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Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf ·...

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Engineering Analysis Presentation Presentation ME 4182 ME 4182 Team: 5 Guys Engineering + 1 Nathan Bessette, Rahul Bhatia, Andrew Cass, Zeeshan Saiyed Zeeshan Saiyed, Glen Stewart YJ Chok
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Page 1: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Engineering Analysis PresentationPresentation

ME 4182ME 4182Team: 5 Guys Engineering + 1

Nathan Bessette, Rahul Bhatia, Andrew Cass,

Zeeshan SaiyedZeeshan Saiyed, Glen Stewart

YJ ChokJ C o

Page 2: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Automatic Whiteboard WiperAutomatic Whiteboard Wiper

• Last TimeLast Time– Layout Drawings

• Layout or assembly drawings– How individual parts or subsystems fit together as a whole

• Encouraged to use computer modeling software• Drawings for actual design, not prototype

• This Time– Present a critical analysis of the design– Determine the areas that are most likely to fail – Potential engineering and/or manufacturing problems

Page 3: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

CalculationsCalculations

Using the situation with the heavy writing

5”

2”

For 9.6 erasers to span the height of the board

For 4 8 erasers to span half the height of the boardFor 4.8 erasers to span half the height of the board

Page 4: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Material AnalysisMaterial AnalysisWeight Density

Mass Density

Yield Stress

Ultimate Stress

Modulus of

ElasticityApproximate

DeflectionDensity [lb/ft3]

Density [slugs/ft3]

Stress [ksi]

Stress [ksi]

Elasticity E

[ksi]

Deflection [in]

D =L3 •W

Aluminum 170 5.3 40 45 10000 0.0032D

48• E • I

High Strength Steel 490 15.2 100 130 29000 0.0011

Deflection Analysis For Vertical Slider BarA Ci l

Stainless Steel 490 15.2 70 105 29000 0.0011-Assume Circular cross section-5 ft. longHalf the normal force

Polyethylene 75 2.35 N/A 2.5 150 0.2101-Half the normal force from the board acts at the center of the rod (5.5 lbs)

Page 5: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Eraser sub-assembly Weight Calculation

Page 6: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Eraser Subassembly Weight CalculationEraser Subassembly Weight Calculation

• Density: ρ = 0.5097 lbs. / Ft. of bar• Quantity of bar

2 x 60” bars = 120”4 x 5” supports = 20”4 x 5 supports 201 x (2” x 24”) eraser backing = 48”TOTAL = 15⅔ ft

Al i W i h 15⅔ f 0 5097 lb / F 8 lb• Aluminum Weight = 15⅔ ft · 0.5097 lbs. / Ft. ≈ 8 lbs.• Motor Assembly

Motor ≈ 2.3 lbRack & Pinion ≈ 1 lbExtras ≈ 0.5 lb

• Motor Assembly Weight ≈ 3 8 lbs• Motor Assembly Weight ≈ 3.8 lbs.• TOTAL WEIGHT, W ≈ 11.8 lbs.

Page 7: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Statics Analysis (Eraser at bottom)Statics Analysis (Eraser at bottom)• Forces on A and B are reactions on Sliding Assembly

from sliding railsfrom sliding rails.– Total of two sliding rails attached together

• Weight acts at the center of gravity (3.85 inches from the wall, 2.75 feet from the bottom of the assembly)

• Normal force from board N is 11 lbs and acts at the• Normal force from board, Nx is 11 lbs and acts at the center of the eraser (1.5 feet from the bottom of the assembly)

• Reactions calculated by summing forces and summing moments about a fixed pointmoments about a fixed point

∑MB = 0 = (Ax × 5 ft) − (Nx ×1.5 ft) − (W ×3.8512

ft)

∑Fx = 0 = Nx − Ax − Bx∑Fy = 0 = Ay + By −W

B x x 12

Reaction Value (lbs)

Ax 2.03

B 3 47Bx 3.47

Ay 2.95

By 2.95

Page 8: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Statics Analysis (Eraser at Top)Statics Analysis (Eraser at Top)• Forces on A and B are reactions on Sliding Assembly

from sliding railsfrom sliding rails.– Total of two sliding rails attached together

• Weight acts at the center of gravity (3.85 inches from the wall, 1.90 feet from the bottom of the assembly)

• Normal force from board N is 11 lbs and acts at the• Normal force from board, Nx is 11 lbs and acts at the center of the eraser (3.5 feet from the bottom of the assembly)

• Reactions calculated by summing forces and summing moments about a fixed pointmoments about a fixed point

∑Fy = 0 = Ay + By −W∑Fx = 0 = Nx − Ax − Bx∑MB = 0 = (Ax × 5 ft) − (Nx ×1.5 ft) − (W ×

3.8512

ft)

Reaction Value (lbs)

Ax 4.23

B 1 27

12

Bx 1.27

Ay 2.95

By 2.95

Page 9: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Possible points of failurePossible points of failure

Page 10: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Shear Analysis on the wheelsFront View Side View

Wheels

Track

Wheel SupportSupport Attachment

Top View Area of the wheels under shear

Page 11: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Shear stress on the wheels due to weight

Area of one wheel under shear, Aw = 0.1266 in2

Total Area under shear, A T,w = 0.5063 in2

Sh t d t N l f F / A 5 825 iShear stress due to Normal force, τN = Fs,W / A T,w = 5.825 psi Shear strength of Nylatron, Sy = 10,500 psi

Factor of safety for the wheels, n = 1803

Fs,N = 2.950 lb

Area of the wheels under shear

Page 12: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Shear stress on the wheels due to Normal Force

Area of one wheel under shear, As = 0.0765 in2

Total Area under shear, A T,s = 0.3061 in2

Sh t d t N l f F / A 13 816 i

F 4 229 lb

Shear stress due to Normal force, τN = Fs,N/ A T,s = 13.816 psi Shear strength of Nylatron, Sy = 10,500 psi

Factor of safety for the wheels, n = 760

Fs,N = 4.229 lb

Area of the wheels under shear

Page 13: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Horizontal Torque RequirementsHorizontal Torque Requirements

• Required Torque calculation:Required Torque calculation:T = Fmax tension due to friction·rpulley

( lb )(2 2 i )

4.5” ID Pulley

= (7 lbs.)(2.25 in.)= 15.75 lb-in

T = 2 6 lb ft

= 1.3 lb-ftTreq = 2.6 lb‐ft

Motor

Treq = 1.3 lb-ft minimumFmax, tension = 7 lbs.

Page 14: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Vertical Torque RequirementsVertical Torque Requirements

• Required Torque calculation:Required Torque calculation:T = Fmax(friction+weight)·rgear

(12 lb )(1 8 i )= (12 lbs.)(1.875 in.)= 22.5 lb-in

Ffriction = 7 lbs.

= 1.875 lb-ftMotor3.75” ID Gear

Treq = 1.875 lb-ft minimumFweight = 5 lbs.

F Weight of MotorFweight = Weight of Motor Assembly (3 lb est.) plus Eraser Backing (2 lb est.)

Page 15: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Motor Analysis

MotorRef. Volt Gear

Stall Torque

Free Speed

Free Speed

Torque at Peak

Power, 10.5 V Supply

Speed at Peak Power, 10 5 V Supply

Motor Analysis

SupplierMotor

Number Motor Name DescriptionVoltage

Gear Ratio

Torque (lb-ft)

Speed (rpm)

Speed (rad/s)

V Supply (lb-ft)

10.5 V Supply (rad/s)

Fisher-Price

74550-0642

Power Wheels

Motor only 12 0.477 24000 2513 0.209 1100

CIM FR801-001 (Chiaphua, Atwood)

Keyed output shaft ccw 12 1 81 5342 559 0 789 244Atwood) shaft, ccw 12 1.81 5342 559 0.789 244

Fisher-Price

74550-0642

Power Wheels

Motor and gearbox 12 181 56.8 133 13.9 25.1 6.1

Globe 409A586 2WD/4WD transfer mtr.

Motor only 12 0.182 9390 983 0.0811 429

Taigene 16638628 Sliding (van) door

Worm Gearmotor 10.5 22.1 75 7.9 9.59 3.4

Globe 409A587 2WD/4WD transfer mtr.

Planetary Gearmotor 12 117 9.59 80 8.4 4.79 3.7

Nippon E6DF Window Lift WormNippon-Denso

E6DF-14A365-BB

Window Lift Worm Gearmotor 12.6 6.79 92 9.6 2.95 4.1

Minimum Torque Requirements:Horizontal Sliding = 1.3 lb-ftVertical Sliding = 1.875 lb-ft

Page 16: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Motor Analysis

MotorRef. Volt Gear

Stall Torque

Free Speed

Free Speed

Torque at Peak

Power, 10.5 V Supply

Speed at Peak Power, 10 5 V Supply

Motor Analysis

SupplierMotor

Number Motor Name DescriptionVoltage

Gear Ratio

Torque (lb-ft)

Speed (rpm)

Speed (rad/s)

V Supply (lb-ft)

10.5 V Supply (rad/s)

Fisher-Price

74550-0642

Power Wheels

Motor only 12 0.477 24000 2513 0.209 1100

CIM FR801-001 (Chiaphua, Atwood)

Keyed output shaft ccw 12 1 81 5342 559 0 789 244MINIMUM TORQUE NOT MET

MINIMUM TORQUE NOT MET

Atwood) shaft, ccw 12 1.81 5342 559 0.789 244

Fisher-Price

74550-0642

Power Wheels

Motor and gearbox 12 181 56.8 133 13.9 25.1 6.1

Globe 409A586 2WD/4WD transfer mtr.

Motor only 12 0.182 9390 983 0.0811 429MINIMUM TORQUE NOT MET

MINIMUM TORQUE NOT MET

Taigene 16638628 Sliding (van) door

Worm Gearmotor 10.5 22.1 75 7.9 9.59 3.4

Globe 409A587 2WD/4WD transfer mtr.

Planetary Gearmotor 12 117 9.59 80 8.4 4.79 3.7

Nippon E6DF Window Lift Worm

BULKY COMPARED TO GLOBE MOTOR

Nippon-Denso

E6DF-14A365-BB

Window Lift Worm Gearmotor 12.6 6.79 92 9.6 2.95 4.1

Horizontal Sliding: speed high torqueMinimum Torque Requirements:

FACTOR OF SAFETY TOO SMALL

Horizontal Sliding: speed, high torqueVertical Sliding: small, light weight

Horizontal Sliding = 1.3 lb-ftVertical Sliding = 1.875 lb-ft

Page 17: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Motor Analysis

SupplierMotor

Number Motor Name Description

Ref. Voltage

Gear Ratio

Stall Torque (lb-ft)

Free Speed (rpm)

Free Speed (rad/s)

Torque at Peak Power,

10.5 V Supply (lb-ft)

Speed at Peak Power, 10.5 V Supply (rad/s)

Motor Analysis

Supplier Number Motor Name Description age Ratio (lb ft) (rpm) (rad/s) Supply (lb ft) Supply (rad/s)

Fisher-Price

74550-0642 Power Wheels Motor and gearbox 12 181 56.8 133 13.9 25.1 6.1

Globe 409A587 2WD/4WD transfer mtr.

Planetary Gearmotor 12 117 9.59 80 8.4 4.79 3.7

Free Speed Calculations:Across the board

secin.7.13

rev1in.5.4

rad2rev1

secrad1.6

=⋅

⋅⋅π

πFisher‐Price:

secin.9.6

rev1in.75.3

rad2rev1

secrad7.3

=⋅

⋅⋅π

πGlobe:

Up/down board

secevdsec π

Page 18: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Can the cable subassembly overcome frictional forces without breaking?

P d t i lProposed materials:Bicycle brake cable (steel)Rubberized Nylon cable

Here, we will analyze the 5 mm cable with the lowest tensile strength to ensure a sufficiently high factor of safety for the stationary board. Weight considerations are largely ignored for this analysis as they not pertinent to the direction of motion.

A distributed load of 7 lbf is applied against the direction of motion of the cable due to the board friction present. Thus the motor force must overcome the friction force. Since there are boa d ct o p ese t us t e oto o ce ust o e co e t e ct o o ce S ce t e e a e2 pulleys (top and bottom) aiding the path of motion of the eraser, the stress on the cables is halved indicating that the cable tension in summation must overcome eraser assembly friction, pulley/bearing friction, and applied motor stress.

FF

With the chosen motor (maximum torque of 34 N-m = 25.077 ft-lb.) at a distance of 2 ft, the lb 7

022

0

=>

>−+∴>∑fm

fmm

x

FF

FFFF

cable has a F of S of at least 20 which is ample to ensure that the cable, even with the smallest tensile strength, will not stretch or deform and will definitely not snap. This means that cost can largely dictate the cable material that is chosen.

Page 19: Engineering Analysis Presentation - Georgia Institute of ...mefach12/engineeringanalysis.pdf · Engineering Analysis Presentation ME 4182ME 4182 Team: 5 Guys Engineering + 1 Nathan

Automatic Whiteboard WiperAutomatic Whiteboard Wiper

• Next TimeNext Time– Part Drawings

• Prepare a complete set of part drawings• Prepare a complete set of part drawings– Must contain enough information so the part can be fabricated

• Drawings are for the actual design, not for the prototype


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