Date post: | 24-May-2015 |
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Example
ABC Co. Ltd has four production departments P1, P2, P3 and P4 and three service departments S1, S2 and S3.
S1 –stores
S2 –production control section
S3 –maintenance department
Calculate for each production department an appropriate overhead absorption rate per machine hour.
Calculate the total cost of each department.
The annual overheads are as follows:
120Depreciation -Plant
240Depreciation -Building
100Insurance -Plant
160Insurance -Building
80Rent
600Power
200Supervision
2,000Indirect labour
Total (Rs.’000)Cost
Information
Indirect Labour Costs
Cost centres Actual costs
Rs.’000
P1 300
P2 200
P3 500
P4 100
S1 200
S2 300
S3 400
Information
P1 P2 P3 P4 S1 S2 S3 Total
No. of employee 400 400 500 600 30 20 50 2,000
Floor Area (Sq.M) 3,000 9,000 8,000 8,000 1,000 1,000 2,000 32,000
Power (KWHrs) 7,000 5,000 3,000 2,000 1,500 500 1,000 20,000
Pro.Cntrl Hours 4,000 5,000 5,000 3,000 - - 1,000 18,000
Stores Requisitions 600 300 250 150 - 400 300 2,000
Maint. Dept Hours 6,000 8,000 5,000 6,000 - - - 25,000
Plant Hrs (‘000) 120 80 200 100 - - - 500
Book value of plant
(Rs.’000)
300 200 100 80 120 50 150 1,000
Information
498343289.4357.
6
7825696613500Total
18614.49.6122436120Book valueDepreciation
Plant
157.57.5606067.522.5240Floor areaDepreciation
Building
152128102030100Book valueInsurance
Plant
105540404515160Floor areaInsurance
Building
52.52.5202022.57.580Floor areaRent &
Rates
3015456090150210600KWHrPower
52360504040200No. of
employee
Supervision
4003002001005002003002000ActualInd. Labour
S3S2S1P4P3P2P1Total Basis Item
Allocation of costs to Production and Service Departments
CalculationItem Basis Total P1
Ind. Labour Actual 2000 300.0
Supervision No. of
Employee
200 (200/2,000)*400 = 40.0
Power KWHr 600 (600/20,000)*7000 = 210.0
Rent & rates Floor area 80 (80/32,000)*3000 = 7.5
Insurance -B Floor area 160 (160/32,000)*3000 = 15.0
Insurance-P Book value 100 (100/1,000)*300 = 30.0
Depreciation-B Floor area 240 (240/32,000)*3000 = 22.5
Depreciation-P Book value 120 (120/1,000)*300 = 36.0
Total 3500 661.0
Reallocation of Service Department Overheads to
Production Departments
Item Basis Total P1 P2 P3 P4 S1 S2 S3
Total
costs
3500 661.0 569.0 782.0 357.6 289.4 343.0 498.0
S1-
stores
Store
req
- 86.8 43.4 36.2 21.7 -
289.4
57.9 43.4
S2-Pro
Control
Prodn
control
3500 748.8
89.1
612.4
111.35
818.2
111.35
379.3
66.8
-
-
400.9
-400.9
541.4
22.3
S3-
Maint
Main
Hrs
3500 837.9
135.3
723.75
180.4
929.55
112.7
446.1
135.3
-
-
-
-
563.7
-
563.7
Total 3500 973.2 904.15 1042.25 581.4 - - -
S1-
stores
Store
req
- 87.8 43.4 36.2 21.7 (289.4) 57.9 43.4
• S1 P1 (289.4/2000)*600 = 86.82 ≈ 86.8
P2 (289.4/2000)*300 = 43.41 ≈ 43.4
P3 (289.4/2000)*250 = 36.18 ≈ 36.2
P4 (289.4/2000)*150 = 21.71 ≈ 21.7
S2 (289.4/2000)*400 = 57.88 ≈ 57.9
S3 (289.4/2000)*300 = 43.41 ≈ 43.4
Total 289.4
S2-Pro
Control
Prodn
control
3500 748.8
89.1
612.4
111.35
818.2
111.35
379.3
66.8
-
-
400.9
(400.9)
541.4
22.3
• S2 P1 (400.9/18,000)* 4000= 89.08 ≈ 89.1
P2 (400.9/18,000)* 5000=111.35
P3 (400.9/18,000)* 5000=111.35
P4 (400.9/18,000)* 3000=66.81 ≈ 66.8
S3 (400.9/18,000)* 1000=22.27 ≈ 22.3
S3-
Maint
Plant
Hrs
3500 837.9
135.3
723.75
180.4
929.55
112.7
446.1
135.3
-
-
-
-
563.7
(563.7)
S3 P1 (563.7/25,000)*6000 =135.288 ≈ 135.3
P2(563.7/25,000)*8000 =180.384 ≈ 180.4
P3(563.7/25,000)*5000 =112.74 ≈ 112.7
P4 (563.7/25,000)*6000 =135.288 ≈ 135.3
Total 563.7
Calculation of appropriate departmental
overhead rates
• Based on machine hours
P1 = 973.3/120 = 8.11 per M/C hour
P2 = 904.15/80 = 11.30 per M/C hour
P3 =1042.25/200 = 5.21 per M/C hour
P4 = 581.4/100 = 5.81 per M/C hour
Charging Overhead Rates to Products
Overhead costs in each cost centre should be
absorbed by the products, at an absorption rate
of each product.
Pro.Dep. Job1(hours) Job2(hours) Job3(hours)
P1 3 12 1.5
P2 2.5 0 4
P3 0 5 10
P4 5 0 3
• Then, based on the production hours the
overhead costs chargeable are as follows:
• Job 1 = 3*8.11+2.5*11.3+5*5.81 = 81.63
• Job 2 = 12*8.11+5*5.21 = 123.37
• Job 3 = 1.5*8.11+4*11.3+10*5.21+3*5.81 =
Allocation service department costs
Example
A manufacturing firm has three production departments, P1, P2 and P3, and two service departments, S1and S2. the following costs are shown in the overhead distribution sheet.
production dep. P1 = Rs. 5000
production dep. P2 = Rs. 8000
production dep. P3 = Rs. 6000
service dep. S1 = Rs. 1280
service dep. S2 = Rs. 3000
Total = Rs.23,280
• The costs of the two service departments S1 and S2 are to be re-apportioned to production departments using the following basis.
S1 S2
P1 20% 30%
P2 40% 30%
P3 10% 20%
S1 - 20%
S2 30% -
Total 100% 100%
• There are 3 basic methods of allocating
service department costs.
1. Continuous Allotment
2. Simultaneous Equation method
3. Specified order of Re-Allocation
Continuous Allotment
Costs of service departments are re-allocated to other departments repeatedly until the amount remaining is too insignificant.
s1 s2
P1 20% 30%
P2 40% 30%
P3 10% 20%
S1 - 20%
S2 30% -
Total 100% 100%
Total P1 P2 P3 S1 S2
Cost before
re-allocation
Dept S1
Dept. S2
Total
23280
2380
5000
256
1015
135
61
8
3.6
4
6479
8000
512
1015
271
62
16
3.6
4
9880
6000
128
677
68
40
4
2.4
3
6920
1280
(1280)
677
(677)
40
(40)
2.4
-
3000
384
(3384)
203
(203)
12
(12)
-
Simultaneous equation method
X=total cost of S1 after receiving 20% cost of S2
Y=total cost of S2 after receiving 30% cost of S1
X=1280+0.2Y
Y=3000+0.3X
By solving two equation above,
X=2000 and Y=3600
As above Total P1 P2 P3
Cost before
re-allocation
19000 5000 8000 6000
Dept S1 2000 1400* 400* 800* 200*
Dept S2 3600 2880 1080 1080 720
Total 23280 6480 9880 6920
(2000/100)*70
=1400
(1400/70)*20
=400
(1400/70)*40
=800
(1400/70)*10
=200
Specified order of Re-allocation
• Assume that service dept. costs are first allocated to S1 and then to
S2.
S1 S2
P1 20% 37.5%
P2 40% 37.5%
P3 10% 25.0%
S1 - -
S2 30% -
Total 100% 100%
30*(100/80)
30*(100/80)
20*(100/80)
Total P1 P2 P3 S1 S2
Cost before
re-allocation
23280 5000 8000 6000 1280 3000
Dept S1 256 512 128 (1280) 384
Dept. S2 1269 1269 846 - (3384)
Total 2380 6525 9781 6974 - -
(1280/100)*20
=256
(1280/100)*40
=512
(1280/100)*10
=128
(1280) (1280/100)*30
=384