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Gaseous State

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Gaseous State. Chapter 9. 9.1 The Behavior of Gases. Characteristics of Gas. Gases consist of Particles that are relatively far apart Gas particles move very rapidly Gas particles have little interaction until they collide. Gases expand to fill the available space. - PowerPoint PPT Presentation
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Gaseous State Chapter 9
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Page 1: Gaseous State

Gaseous State

Chapter 9

Page 2: Gaseous State

9.1 The Behavior of Gases

Page 3: Gaseous State

Characteristics of Gas• Gases consist of Particles that are

relatively far apart• Gas particles move very rapidly• Gas particles have little interaction

until they collide.• Gases expand to fill the available

space.

Page 4: Gaseous State

Description of Gases• Gases can be described in various physical

properties.– Pressure– Temperature– Density– Volume– Number of Particles

• Changing one physical parameter will change one or more others.

Page 5: Gaseous State

Pressure• Pressure (P) = Force/area• There are several units for Pressure.– Pounds/Sq. Inch (psi)– 1 Atmosphere (atm) = 760 mm Hg =

760 torr– 1 atm = 101,325 Pa (pascal)– 1 atm = 14.7 psi

Page 6: Gaseous State

EXAMPLE• Calculate the amount of pressure a 105

lbs. woman exerts by stepping down on a stiletto heel (1/16 sq inch)? Compare this to an Elephant (12,000 lbs., 16 sq. in. foot)?

Page 7: Gaseous State

PROBLEM• The depths of the ocean can exceed

380 atm of pressure. How many pascals is this? How many psi?

Page 8: Gaseous State

9.2 Factors That Affect the Properties of Gases

Page 9: Gaseous State

Boyle’s Law• For a given mass of gas at a constant

temperature, volume varies inversely with pressure.

Page 10: Gaseous State

Implications of Boyle’s Law

Therefore

Page 11: Gaseous State

Ideal Gases• Any gas that behaves according to

the predicted linear relationships.– Pressure/Volume– Volume/Temperature

Page 12: Gaseous State

PROBLEM• Given an ideal gas held at constant mass

and temperature, what would be the volume of the gas if it was originally 125 ml, and its pressure is dropped from 1.40 atm to 0.500 atm?

Page 13: Gaseous State

Charles’s Law• For a given mass of a gas at constant

pressure, volume is directly proportional to temperature on an absolute (Kelvin) scale.

Page 14: Gaseous State

Implications of Charles’s Law

Therefore

Page 15: Gaseous State

Kelvin Scale• So far we have measured

temperature in degrees Celsius, a relative scale.

• Absolute temperature is measure in Kelvin (K, note no degree sign is used), this scale is related to the absolute motion of atoms.

0 K = -273.15 °CTherefore Temp °C +273.15 = Temp K

Page 16: Gaseous State

PROBLEM• Calculate the following temperatures

in Kelvin.

– Boiling Point of Water

– Freezing Point of Water

Page 17: Gaseous State

PROBLEM• Given an ideal gas held at constant mass

and pressure, what would be the temperature of the gas if it was originally at 125 °C, and its volume is dropped from 1.00 L to 0.500 L?

Page 18: Gaseous State

Combined Gas Law• Combining Boyle’s and Charles’s Law

results in the following equation.

Page 19: Gaseous State

PROBLEM• A sample of Hydrogen gas occupies

1.25 L at 80.0 °C and 2.75 atm. What would its volume be at 185 °C and 5.00 atm?

Page 20: Gaseous State

Guy-Lussac and Avagadro• Guy-Lussac’s Law stated that

combined gases always reacted in small whole number ratios (sound familiar?)

• Avagadro hypothesized that the volume occupied by a gas is proportional to the number of gas particles and hence the moles of gas.

Page 21: Gaseous State

Avagadro’s Hypothesis• At a given pressure and temperature,

equal volumes of gas contain equal numbers of moles.

• Standard Temperature and Pressure (STP) are defined as 273.15 K and 1 atm, at which 1.00 mole of gas occupies 22.414 L, defined as molar volume

Page 22: Gaseous State

PROBLEM• What volume would 1.00 mole of gas

occupy at 37°C and 1.00 atm?

Page 23: Gaseous State

9.3 The Ideal Gas Law

Page 24: Gaseous State

Review of the Relationships• Boyle’s Law: (C is a constant)

at constant n, T

• Charles’s Law: at constant n, P

• Avagadro’s Hypothesis: at constant P, T

Page 25: Gaseous State

Combine the Equations• Assume the constants combined

equal another constant we will call the Ideal Gas Constant, R

• Rearrange this into the Ideal Gas Law

Page 26: Gaseous State

So What is the Value for R?• Assuming a standard gas you can

calculate the value of R becomes

For a Standard gas 1.000 mole at 273.15 K and 1.000 atm has a volume of 22.414 L

= 0.08206

Page 27: Gaseous State

PROBLEM• Calculate the Ideal Gas Constant if

pressure is measured in torr

Page 28: Gaseous State

PROBLEMThe volume of an oxygen cylinder is 2.025 L. At a temperature of 32 °C the cylinder has a pressure of 945 torr. How many moles of Oxygen gas are in the cylinder?

Page 29: Gaseous State

PROBLEM• Given the amount of oxygen in the

previous question, what is its mass?

• What is its density?

Page 30: Gaseous State

Partial Pressures• Dalton’s Law of Partial Pressure:

Gases in a mixture behave independently and exert they same pressure as they would alone.

+ +…

Page 31: Gaseous State

PROBLEMGiven a 2.500 L container at 45.00°C, what would be the total pressure in the container from a mixture of 2.100 moles gaseous sulfur dioxide and 1.800 moles hydrogen sulfide?

Page 32: Gaseous State

9.5 Gases and Chemical Reactions

Page 33: Gaseous State

The return of Stoichiometry• You can use the gas laws to solve

stoichiometry problems by converting values between states of matter.

Page 34: Gaseous State

Example• A sample of hydrogen gas has a volume of 8.00 L

at a pressure of 5.00 atm and a temperature of 25 °C. What volume of gaseous water is produced in the following reaction at 150.0 °C and 0.947 atm, if all the hydrogen gas reacts with copper (II) oxide

CuO(s) + H2(g) Cu(s) + H2O(g)ALGORITHM• mol of Hydrogen (PV=nRT)• mol of Water (formula)• V of Water (PV=nRT)

Page 35: Gaseous State

PROBLEMHow many grams of calcium carbonate is formed if 3.45 L of carbon dioxide, measured at 45.0 C and 1.37 atm, react with excess CaO?

CaO(s) + CO2(g) CaCO3(S)


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