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SECTION 6-2 Parallelograms Tuesday, April 10, 2012
Transcript
Page 1: Geometry Section 6-2 1112

SECTION 6-2Parallelograms

Tuesday, April 10, 2012

Page 2: Geometry Section 6-2 1112

Essential Questions

How do you recognize and apply properties of the sides and angles of parallelograms?

How do you recognize and apply properties of the diagonals of parallelograms?

Tuesday, April 10, 2012

Page 3: Geometry Section 6-2 1112

Vocabulary

1. Parallelogram:

Tuesday, April 10, 2012

Page 4: Geometry Section 6-2 1112

Vocabulary

1. Parallelogram: A quadrilateral that has two pairs of parallel sides

Tuesday, April 10, 2012

Page 5: Geometry Section 6-2 1112

Properties and Theorems6.3 - Opposite Sides:

6.4 - Opposite Angles:

6.5 - Consecutive Angles:

6.6 - Right Angles:

Tuesday, April 10, 2012

Page 6: Geometry Section 6-2 1112

Properties and Theorems6.3 - Opposite Sides: If a quadrilateral is a parallelogram, then its

opposite sides are congruent

6.4 - Opposite Angles:

6.5 - Consecutive Angles:

6.6 - Right Angles:

Tuesday, April 10, 2012

Page 7: Geometry Section 6-2 1112

Properties and Theorems6.3 - Opposite Sides: If a quadrilateral is a parallelogram, then its

opposite sides are congruent

6.4 - Opposite Angles: If a quadrilateral is a parallelogram, then its opposite angles are congruent

6.5 - Consecutive Angles:

6.6 - Right Angles:

Tuesday, April 10, 2012

Page 8: Geometry Section 6-2 1112

Properties and Theorems6.3 - Opposite Sides: If a quadrilateral is a parallelogram, then its

opposite sides are congruent

6.4 - Opposite Angles: If a quadrilateral is a parallelogram, then its opposite angles are congruent

6.5 - Consecutive Angles: If a quadrilateral is a parallelogram, then its consecutive angles are supplementary

6.6 - Right Angles:

Tuesday, April 10, 2012

Page 9: Geometry Section 6-2 1112

Properties and Theorems6.3 - Opposite Sides: If a quadrilateral is a parallelogram, then its

opposite sides are congruent

6.4 - Opposite Angles: If a quadrilateral is a parallelogram, then its opposite angles are congruent

6.5 - Consecutive Angles: If a quadrilateral is a parallelogram, then its consecutive angles are supplementary

6.6 - Right Angles: If a quadrilateral has one right angle, then it has four right angles

Tuesday, April 10, 2012

Page 10: Geometry Section 6-2 1112

Properties and Theorems6.7 - Bisecting Diagonals:

6.8 - Triangles from Diagonals:

Tuesday, April 10, 2012

Page 11: Geometry Section 6-2 1112

Properties and Theorems6.7 - Bisecting Diagonals: If a quadrilateral is a parallelogram, then its

diagonals bisect each other

6.8 - Triangles from Diagonals:

Tuesday, April 10, 2012

Page 12: Geometry Section 6-2 1112

Properties and Theorems6.7 - Bisecting Diagonals: If a quadrilateral is a parallelogram, then its

diagonals bisect each other

6.8 - Triangles from Diagonals: If a quadrilateral is a parallelogram, then each diagonal separates the parallelogram into two congruent triangles

Tuesday, April 10, 2012

Page 13: Geometry Section 6-2 1112

Example 1In ▱ABCD, suppose m∠B = 32°, CD = 80 inches, and BC = 15 inches.

Find each measure.

a. AD

b. m∠C

c. m∠D

Tuesday, April 10, 2012

Page 14: Geometry Section 6-2 1112

Example 1In ▱ABCD, suppose m∠B = 32°, CD = 80 inches, and BC = 15 inches.

Find each measure.

a. AD 15 inches

b. m∠C

c. m∠D

Tuesday, April 10, 2012

Page 15: Geometry Section 6-2 1112

Example 1In ▱ABCD, suppose m∠B = 32°, CD = 80 inches, and BC = 15 inches.

Find each measure.

a. AD 15 inches

b. m∠C = 180 − 32

c. m∠D

Tuesday, April 10, 2012

Page 16: Geometry Section 6-2 1112

Example 1In ▱ABCD, suppose m∠B = 32°, CD = 80 inches, and BC = 15 inches.

Find each measure.

a. AD 15 inches

b. m∠C = 180 − 32 = 148°

c. m∠D

Tuesday, April 10, 2012

Page 17: Geometry Section 6-2 1112

Example 1In ▱ABCD, suppose m∠B = 32°, CD = 80 inches, and BC = 15 inches.

Find each measure.

a. AD 15 inches

b. m∠C = 180 − 32 = 148°

c. m∠D = 32°

Tuesday, April 10, 2012

Page 18: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r b. s

c. t

Tuesday, April 10, 2012

Page 19: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

b. s

c. t

Tuesday, April 10, 2012

Page 20: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

b. s

c. t

Tuesday, April 10, 2012

Page 21: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

c. t

Tuesday, April 10, 2012

Page 22: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

ZV = VX c. t

Tuesday, April 10, 2012

Page 23: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

ZV = VX

8s = 7s + 3

c. t

Tuesday, April 10, 2012

Page 24: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

ZV = VX

8s = 7s + 3

s = 3

c. t

Tuesday, April 10, 2012

Page 25: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

ZV = VX

8s = 7s + 3

s = 3

c. t

m∠VWX = m∠VYZ

Tuesday, April 10, 2012

Page 26: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

ZV = VX

8s = 7s + 3

s = 3

c. t

m∠VWX = m∠VYZ

2t = 18

Tuesday, April 10, 2012

Page 27: Geometry Section 6-2 1112

Example 2If WXYZ is a parallelogram, find the value of the indicated variable.

m∠VWX = (2t)°, m∠VYX = 40°, m∠VYZ =18°,

WX = 4r, ZV = 8s, VX = 7s + 3, ZY =18

a. r

WX = ZY

4r = 18

r = 4.5

b. s

ZV = VX

8s = 7s + 3

s = 3

c. t

m∠VWX = m∠VYZ

2t = 18 t = 9

Tuesday, April 10, 2012

Page 28: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

Tuesday, April 10, 2012

Page 29: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

M(MP ) =

−3+ 52

,0 + 4

2

⎛⎝⎜

⎞⎠⎟

Tuesday, April 10, 2012

Page 30: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

M(MP ) =

−3+ 52

,0 + 4

2

⎛⎝⎜

⎞⎠⎟ =

22

,42

⎛⎝⎜

⎞⎠⎟

Tuesday, April 10, 2012

Page 31: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

M(MP ) =

−3+ 52

,0 + 4

2

⎛⎝⎜

⎞⎠⎟ =

22

,42

⎛⎝⎜

⎞⎠⎟ = 1, 2( )

Tuesday, April 10, 2012

Page 32: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

M(MP ) =

−3+ 52

,0 + 4

2

⎛⎝⎜

⎞⎠⎟ =

22

,42

⎛⎝⎜

⎞⎠⎟ = 1, 2( )

M(NR) =

−1+ 32

,3+1

2

⎛⎝⎜

⎞⎠⎟

Tuesday, April 10, 2012

Page 33: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

M(MP ) =

−3+ 52

,0 + 4

2

⎛⎝⎜

⎞⎠⎟ =

22

,42

⎛⎝⎜

⎞⎠⎟ = 1, 2( )

M(NR) =

−1+ 32

,3+1

2

⎛⎝⎜

⎞⎠⎟

=22

,42

⎛⎝⎜

⎞⎠⎟

Tuesday, April 10, 2012

Page 34: Geometry Section 6-2 1112

Example 3What are the coordinates of the intersection of the diagonals of

parallelogram MNPR with vertices M(−3, 0), N(−1, 3), P(5, 4) , and R(3, 1)?

M =

x1+ x

2

2,y

1+ y

2

2

⎝⎜⎞

⎠⎟

M(MP ) =

−3+ 52

,0 + 4

2

⎛⎝⎜

⎞⎠⎟ =

22

,42

⎛⎝⎜

⎞⎠⎟ = 1, 2( )

M(NR) =

−1+ 32

,3+1

2

⎛⎝⎜

⎞⎠⎟

=22

,42

⎛⎝⎜

⎞⎠⎟ = 1, 2( )

Tuesday, April 10, 2012

Page 35: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

Tuesday, April 10, 2012

Page 36: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD

Tuesday, April 10, 2012

Page 37: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

Tuesday, April 10, 2012

Page 38: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

2. AB is parallel to CD

Tuesday, April 10, 2012

Page 39: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

2. Definition of parallelogram2. AB is parallel to CD

Tuesday, April 10, 2012

Page 40: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

2. Definition of parallelogram

3. ∠BAC ≅ ∠ACD, ∠BDC ≅ ∠DBA

2. AB is parallel to CD

Tuesday, April 10, 2012

Page 41: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

2. Definition of parallelogram

3. ∠BAC ≅ ∠ACD, ∠BDC ≅ ∠DBA

2. AB is parallel to CD

3. Alt. int. ∠’s of parallel lines ≅

Tuesday, April 10, 2012

Page 42: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

2. Definition of parallelogram

3. ∠BAC ≅ ∠ACD, ∠BDC ≅ ∠DBA

2. AB is parallel to CD

3. Alt. int. ∠’s of parallel lines ≅

4. AB ≅ DC

Tuesday, April 10, 2012

Page 43: Geometry Section 6-2 1112

Example 4Given ▱ABCD, AC and BD are diagonals, P is the intersection of AC

and BD, prove that AC and BD bisect each other.

1. ABCD is a parallelogram, AC and BD are diagonals,

P is the intersection of AC and BD1. Given

2. Definition of parallelogram

3. ∠BAC ≅ ∠ACD, ∠BDC ≅ ∠DBA

2. AB is parallel to CD

3. Alt. int. ∠’s of parallel lines ≅

4. AB ≅ DC 4. Opposite sides of parallelograms ≅

Tuesday, April 10, 2012

Page 44: Geometry Section 6-2 1112

Example 4

Tuesday, April 10, 2012

Page 45: Geometry Section 6-2 1112

Example 4

5. ∆APB ≅ ∆CPD

Tuesday, April 10, 2012

Page 46: Geometry Section 6-2 1112

Example 4

5. ∆APB ≅ ∆CPD 5. ASA

Tuesday, April 10, 2012

Page 47: Geometry Section 6-2 1112

Example 4

5. ∆APB ≅ ∆CPD 5. ASA

6. AP ≅ CP, DP ≅ BP

Tuesday, April 10, 2012

Page 48: Geometry Section 6-2 1112

Example 4

5. ∆APB ≅ ∆CPD 5. ASA

6. AP ≅ CP, DP ≅ BP 6. CPCTC

Tuesday, April 10, 2012

Page 49: Geometry Section 6-2 1112

Example 4

5. ∆APB ≅ ∆CPD 5. ASA

6. AP ≅ CP, DP ≅ BP 6. CPCTC

7. AC and BD bisect each other

Tuesday, April 10, 2012

Page 50: Geometry Section 6-2 1112

Example 4

5. ∆APB ≅ ∆CPD 5. ASA

6. AP ≅ CP, DP ≅ BP 6. CPCTC

7. AC and BD bisect each other 7. Def. of bisect

Tuesday, April 10, 2012

Page 51: Geometry Section 6-2 1112

Check Your Understanding

Review #1-8 on p. 403

Tuesday, April 10, 2012

Page 52: Geometry Section 6-2 1112

Problem Set

Tuesday, April 10, 2012

Page 53: Geometry Section 6-2 1112

Problem Set

p. 403 #9-23 odd, 27-35 odd, 43, 51, 57

“The best way to predict the future is to invent it.” - Alan Kay

Tuesday, April 10, 2012


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