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Geometry Section 5-6 1112

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Inequalities in Two Triangles
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Section 5-6 Inequalities in Two Triangles Tuesday, April 15, 14
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Page 1: Geometry Section 5-6 1112

Section 5-6Inequalities in Two Triangles

Tuesday, April 15, 14

Page 2: Geometry Section 5-6 1112

Essential Questions

How do you apply the Hinge Theorem or its converse to make comparisons in two triangles?

How do you prove triangle relationships using the Hinge Theorem or its converse?

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Page 3: Geometry Section 5-6 1112

Hinge Theorem

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Page 4: Geometry Section 5-6 1112

Hinge Theorem

If two sides of a triangle are congruent to two sides of another triangle, and the included angle of the first is larger than the included angle of the second triangle, then the third side of the first triangle is longer than the third side of the second triangle.

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Page 5: Geometry Section 5-6 1112

Converse of the Hinge Theorem

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Page 6: Geometry Section 5-6 1112

Converse of the Hinge Theorem

If two sides of a triangle are congruent to two sides of another triangle, and the third side of the first triangle is longer than the third side of the second triangle, then the included angle measure of the first is larger than the included angle measure of the second triangle.

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Page 7: Geometry Section 5-6 1112

Example 1Compare the given measures.

a. AD and BD

m∠ACD = 70°, m∠BCD = 68°

b. m∠ABD, m∠CDB

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Page 8: Geometry Section 5-6 1112

Example 1Compare the given measures.

a. AD and BD

m∠ACD = 70°, m∠BCD = 68°

AD > BD by theHinge Theorem

b. m∠ABD, m∠CDB

Tuesday, April 15, 14

Page 9: Geometry Section 5-6 1112

Example 1Compare the given measures.

a. AD and BD

m∠ACD = 70°, m∠BCD = 68°

AD > BD by theHinge Theorem

b. m∠ABD, m∠CDB

By the Converse of the Hinge Theorem,

m∠ABD > m∠CDBTuesday, April 15, 14

Page 10: Geometry Section 5-6 1112

Example 2Doctors use a straight-leg-raising test to determine the amount of pain felt in a person’s back. The patient lies flat on the examining table, and the doctor raises each leg until the patient experiences pain in the back area. Matt Mitarnowski can tolerate the doctor

raising his right leg 35° and his left leg 65° from the table. Which leg can Matt raise higher above the table? How do you know?

Tuesday, April 15, 14

Page 11: Geometry Section 5-6 1112

Example 2Doctors use a straight-leg-raising test to determine the amount of pain felt in a person’s back. The patient lies flat on the examining table, and the doctor raises each leg until the patient experiences pain in the back area. Matt Mitarnowski can tolerate the doctor

raising his right leg 35° and his left leg 65° from the table. Which leg can Matt raise higher above the table? How do you know?

As the angle between the table and leg is greater, Matt can lift his left leg higher.

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Page 12: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

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Page 13: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141

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Page 14: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

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Page 15: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126

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Page 16: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9

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Page 17: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

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Page 18: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0

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Page 19: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0 −15 −15

Tuesday, April 15, 14

Page 20: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0 −15 −15 9a >−15

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Page 21: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0 −15 −15 9a >−15 9 9

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Page 22: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0 −15 −15 9a >−15 9 9

a >−

53

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Page 23: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0 −15 −15 9a >−15 9 9

a >−

53

53<a <14

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Page 24: Geometry Section 5-6 1112

Example 3Find the range of possible values for a.

9a +15<141 −15 −15

9a <126 9 9 a <14

9a +15> 0 −15 −15 9a >−15 9 9

a >−

53

53<a <14

If we are looking at the smaller angle, it must be larger than 0°. If we are looking at the larger angle, it must be less than 180°.

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Page 25: Geometry Section 5-6 1112

Example 4Prove the following.

Given: JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Prove: JH < KL

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Page 26: Geometry Section 5-6 1112

Example 4Prove the following.

1. JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Given: JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Prove: JH < KL

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Page 27: Geometry Section 5-6 1112

Example 4Prove the following.

1. Given1. JK = HL; JH || KL;

m∠JKH + m∠HKL < m∠JHK + m∠KHL

Given: JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Prove: JH < KL

Tuesday, April 15, 14

Page 28: Geometry Section 5-6 1112

Example 4Prove the following.

1. Given

2. HK ≅ HK

1. JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Given: JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Prove: JH < KL

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Page 29: Geometry Section 5-6 1112

Example 4Prove the following.

1. Given

2. Reflexive2. HK ≅ HK

1. JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Given: JK = HL; JH || KL;m∠JKH + m∠HKL < m∠JHK + m∠KHL

Prove: JH < KL

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Page 30: Geometry Section 5-6 1112

Example 4

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Page 31: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK

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Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

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Page 33: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

4. m∠HKL = m∠JHK

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Page 34: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

4. m∠HKL = m∠JHK 4. Definition of congruent

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Page 35: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

5. m∠JKH + m∠JHK < m∠JHK + m∠KHL

4. m∠HKL = m∠JHK 4. Definition of congruent

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Page 36: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

5. m∠JKH + m∠JHK < m∠JHK + m∠KHL5. Substitution

4. m∠HKL = m∠JHK 4. Definition of congruent

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Page 37: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

5. m∠JKH + m∠JHK < m∠JHK + m∠KHL5. Substitution

6. m∠JKH < m∠KHL

4. m∠HKL = m∠JHK 4. Definition of congruent

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Page 38: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

5. m∠JKH + m∠JHK < m∠JHK + m∠KHL5. Substitution

6. m∠JKH < m∠KHL 6. Subtraction

4. m∠HKL = m∠JHK 4. Definition of congruent

Tuesday, April 15, 14

Page 39: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

5. m∠JKH + m∠JHK < m∠JHK + m∠KHL5. Substitution

7. JH < KL

6. m∠JKH < m∠KHL 6. Subtraction

4. m∠HKL = m∠JHK 4. Definition of congruent

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Page 40: Geometry Section 5-6 1112

Example 43. ∠HKL ≅ ∠JHK 3. Alt. Int. Angles Thm

5. m∠JKH + m∠JHK < m∠JHK + m∠KHL5. Substitution

7. JH < KL 7. Hinge Theorem

6. m∠JKH < m∠KHL 6. Subtraction

4. m∠HKL = m∠JHK 4. Definition of congruent

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Page 41: Geometry Section 5-6 1112

Problem Set

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Page 42: Geometry Section 5-6 1112

Problem Set

p. 371 #1-29 odd, 39, 47, 51

"Make visible what, without you, might perhaps never have been seen." - Robert Bresson

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