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Good Beam Diagram1

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    9 Structures

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    http://en.wikipedia.org/wiki/Image:Canary.wharf.and.dome.london.arp.jpghttp://www.diedrichsandassociates.com/images/projects/fea/steering.jpghttp://www.surrey.ac.uk/CivEng/pictures/civil/build3.jpghttp://img510.imageshack.us/
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    9.1 Youngs modulus

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    In selecting the materials for a componentit is essential to know how the materialbehaves under various loads.

    The strength of a material depends on its

    ability to sustain a load without unduedeformation or a failure.

    Tensile testing, in which a specimen is

    loaded until destruction, is one of the mostimportant materials property tests.

    http://video.google.com/videoplay?docid=6411397054336552770&q=tacoma+bridge&total=184&start=0&num=10&so=0&type=search&plindex=9

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    9.1 Youngs modulus

    stress and strain

    Used for the description of the elastic properties(STIFFNESS) of structural elements like: Wires

    Rods Columns

    Beams

    being under the influence of forces.

    Young's modulus can be used to predictthe elongation orcompression of an object as long as the stress is less than theyield strength of the material.

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    Definitions Young's Modulus is a ratio of the stress to the

    strain. Symbol E ; Units: [N/m2]

    Stressis force (load) per unit area acting on a body or system

    Symbols; Units: [N/m2]

    Strainis the ratio of a change in dimension to the original

    value of that dimension. Symbol e; Units: [-]

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    An elastic material returns to its original length (or shape) when any load isremoved.

    Aplastic material distorts easily but does not break.

    Youngsmodulusprovidesquantitativedata relating tothe relationshipof strength andstiffness instructures.

    Beyond theyield point, thematerialundergoes

    plasticdeformation

    http://www.esm.psu.edu/courses/emch13d/design/animation/Fnecking.html

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    There are three typical definitions of

    tensile strength

    Yield strength: the stress atwhich material strain changesfrom elastic deformation toplastic deformation, causing itto deform permanently.

    Ultimate strength: themaximum stress a material can

    withstand.

    Breaking (Rupture)strength: the stresscoordinate on the stress-straincurve at the point of rupture.

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    Assignment

    Draw a stress / strain diagram for a brittlematerial

    Draw a stress / strain diagram for a plasticmaterial

    Draw a stress / strain diagram for an elasticmaterial

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    Stress / Strain diagrams by

    categories

    A = Elastic

    B = Yield Point/ Elastic limit

    C = Failure point

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    Examples of Stress Strain diagrams

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    Typical tensile strengths

    MaterialYield strength

    (MPa)Ultimate strength

    (MPa)Density(g/cm)

    Structural steel 250 400 7.8

    Spider silk 1150 1200Kevlar 3620 1.44

    Carbon nanotube 62000 1.34

    Pine wood 40Concrete 3

    Assignment: rewrite the table with SI units

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    HW: Due Tuesday 02/10/2007

    A tensile strength specimen has a diameter of 11.3 mm and a gaugelength of five times the diameter. In a tensile test to destruction,the following results were obtained:

    1. Plot a load extension graph.

    2. Calculate the Youngs modulus for the sample

    Load

    [kN]

    2 4 6 8 10 12 14 16 18 20 22 24

    Extension

    [m]

    1.6 3.3 5.0 6.6 8.0 10.0 11.5 13.5 18.0 25.0 36.0 57.0

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    9.2 Forces

    Force is an action which may cause rotation,deformation, or an increase in pressure for the body itacts upon.

    Forces applied to a component of a structure are calledstructural loads.

    CW: what is the load

    acting upon wrist, arms,

    spinal cord, leg, sole?

    Handout: Defining terms

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    Loads

    Dead

    Live

    Environmental Static

    Dynamic

    Combination

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    External loads

    This involves loads wherephysical contact is made

    This is when an object is

    attached to a lift (ie.Helicopter) and the weightof the object adds to the

    helicopters. This involvesloads where physical contactis made

    http://en.wikipedia.org/wiki/Image:Snow_on_trees.jpg
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    Body load

    Is a load without physical contact, eg a structures own

    weight.

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    Mass and Weight

    Mass is "How much matter is in an object".Weight is a vector force that is the measure of

    Mass in relation to gravity. It is simply the mass

    of an object multiplied by the acceleration ofgravity.

    Mass is measured in SI units, in Kilograms (kg)Weight is measured in Newtons (N). A Newton

    is literally (kilograms * meters)/(seconds2)

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    Relationships of external loads to internal forces and

    the concept of the balance of equilibrium of forces

    within a structure.

    A structure works byinterpreting how externalloads give rise to internal

    forces within the structuralmembers.

    A static structure is inequilibrium, otherwise itwould move, ie the forcesacting upon it are equal insize and opposite in

    direction.

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    Tensile and compressive forces and how

    they affect equilibrium within a structure

    Tensile loads tend toextend or stretch astructural member.

    Compressive loads tendto compress or shorten astructural member.

    Tensile and compressiveforces must balance ifthe structure is to

    maintain equilibrium.

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    Calculate a tensile or compressive

    strain given values of force and area.

    The simple equation that is required with thisgiven information is: Stress = Force/Area.

    The unit of stress is measured in N/m2Assignment CW:

    Find the strain in a tug-o-war rope which resists a

    load of 700N and is 15mm in diameter

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    Calculate a tensile or compressive strain given

    values of the original dimension and the change in

    dimension.

    Strain = Extension/Original Length

    Strain has no unit because it is a ratio between

    two numerical valuesAssignment CW:

    A steel wire 6mm diameter and 8m long extends

    5mm under a pull of 3.6kN. Calculate the strain inthe wire.

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    Evaluate the importance of forces in

    a design context.

    HW Due: 12/11/07

    Write one paragraph

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    The main problem that arises is if the failure to support specific forcewill fail. If we apply forces, will the failure to support the tension,compression, shear, bending, torsion or elastic instability occur?

    As designers, we must remember that the forces have to be distributed

    evenly over the whole area. The limitations of the bending and torsionequations must also be taken into account. In deriving the bendingequation it was assumed that each cross-section of the beam issymmetrical about the plane in which the loads are applied.

    Further complications arise when a component carries two or more

    types of loading simultaneously. This would result in the fracture in thematerials. Among other things, the designer has to specify the material from which

    each component is made. Many materials are not equally strong intension and compression and the designer must therefore consider both

    tensile and compressive stresses. Concrete, for example, has little strength in tension and steel rods offer

    little resistance to compression. But if the steel rods are embedded in aconcrete beam near the tension face, the bending moments are resistedby tension in the steel and compression in the concrete.

    There is a body load and an external load that acts upon buildings thusreinforced concrete is used.

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    Class work: Norman Example 8.1 and Assignment 2 p 402Handout pp 370-375

    1. List the types of equilibrium.

    2. List the types of structures.

    3. Describe a monocoque structure.

    4. Outline the differences between concentrated and

    distributed forces.5. What other terms are used to name dead and live

    loads?

    6. Define a vector.7. Define coplanar forces.

    8. Define concurrent forces.

    9. State the principle of concurrency.

    9 3 Th t th d tiff f

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    9.3 The strength and stiffness of

    structures

    D fl ti l ti

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    Deflection - elasticmovement or sinkingof a loaded structural

    member, particularly ofthe mid-span of abeam.

    Stiffness -The ratio ofa steady force acting ona deformable elasticmedium to the resulting

    displacement.

    Stiffness = Load

    Deflection

    Unit [N/m}

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    External load

    If an external loadis applied to somepart of a structure,

    that part will bedeflected to someextent, depending

    on the size of theload and thestiffness of the

    structure.

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    Beam

    A beamis a bar, body or

    structure, with one dimensionlarge compared with the otherdimensions, whose function isto carry lateral loads

    (perpendicular to the largedimension) and bendingmovements.

    Many beams are horizontaland the loads they carry areweights acting verticallydownwards.

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    Bending moment

    A bendingmoment exists in astructural element

    when a moment isapplied to theelement so that

    the elementbends.

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    Computer model of a beam under load

    Moment about a pivot

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    Moment about a pivot The load distance from the

    pivot is called the moment aboutthe pivot. The distance betweenthe load and the pivot is calledthe moment arm.

    The moment arm is theperpendicular distance FROM the

    force's line of application TO theaxis of rotationMoment = Force * Moment Arm

    Unit [N*m]

    CW:Lift weightsCalculate the moment of a 40 kg wallshelve acting at a distance of 20 cm from

    its fixing to the wall.

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    Class work

    Consider a trap door held by a piece of string,BC.

    Pand Qare forces.

    The trap door is hinged

    about point O.

    Write the formula: Moment ofPabout O

    Moment ofQabout O

    Calculate Q when the door is 20 kg and the angle OBQis 30 degrees.

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    Factor of safety

    It is the designers responsibility to ensure that everycomponent of a structure can withstand the forcesacting on it.

    The first step is to decide on a safe stress for the

    material of the component. This is usually called theworking stress and it is obtained by dividing thefailure stress by a factor called the factor of safety.

    The failure stress is obtained by experiment. If failureis taken to mean the onset of permanent strain thenthe yield point is used. In some circumstances failureis considered to be fracture and the ultimate strength

    is taken as the failure stress.

    Factor of safety

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    Factor of safety

    Factor of safety = Design Load

    Normal maximum load

    The value of the factor of safety will depend upon

    the type of loading to be expected. If the structure

    carries only static loadsa low value such as two

    may be used. If there are suddenly applied orimpact loads a higher value must be taken.

    Factors of safety for steel structures will vary from

    about 3 for static loads to about 15 for impactloads or 20 where fluctuating loads may cause

    fatigue failure.

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    CW: Due Monday 19/11/2007

    Evaluate the importance of strength andstiffness in a design context.

    Write 1 paragraph

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    9.4 Beams Beams are structural

    members that aresubject to loads actingnormallyto theirlongitudinal axis.

    The loads create shear

    stresses and bendingmoments and causethe beam to bend orflex.

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    Cantilever beam

    Cantilever

    beams are rigidlysupported at oneend with theother end free.

    http://www.answers.com/topic/cantileverbeam-png
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    Computer model

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    Single shear stress:Class Work

    23 kN

    23 kN

    Pin in single shear

    Single shear stressA load of 23 kN is attempting to shear a

    12 mm rivet holding a brake pad/backing

    plate assembly together.Calculate

    the shear

    stress

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    Class work

    Describe how beams are designed to transferforces and distribute loads through the beams.

    Finite element analysis

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    Finite element analysis

    Finite element analysis

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    Finite element analysis

    http://upload.wikimedia.org/wikipedia/commons/4/4a/FAE_visualization.jpg
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    HW: Due Tuesday 27/11/06

    Produce a timeline with the historicaldevelopment of the materials used tomanufacture beams. Include examples!

    Format: A4 page with five or more entries.

    Read HANDOUT

    Properties of

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    Properties of

    different sectionsCW

    List the crosssections that arestiff for both loads.List the cross

    sections that areweak for bothloads.Outline the

    benefits of usingthis sectionalshapes.Handout


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