GUAL BILNI CLASSES SBI PO Pre. 2019 · " CAT " GMAT " GRE " SSC " BANK Manisha Bansal Ma'am...

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SBI PO (PRE) – 2019

Direction (1-5): What approximate value will come in place of the

question mark (?) in the following question? (You are not expected

to calculate the exact value)

funsZ’k ¼1&5½ % fuEu iz’u eas iz’u fpUg ¼\½ ds LFkku ij D;k vuqekfur eku

vk,xk\ ¼vkils lVhd eku dh x.kuk djus dh vis{kk ugha gSa½

1. 8.02 – (? – 9.01) + (10.92)2 = 120

(a) 0 (b) 18 (c) 21 (d) 24 (e) 23

2. 13.96 × 9.09 + 200.02 = ?

(a) 226 (b) 242 (c) 256 (d) 351 (e) 248

3. 6% of [(198.99)+(15.99)2] = ?

(a) 30 (b) 17 (c) 27 (d) 24 (e) 3

4. 1 1 1

14.96 3.94 ?− + = 0

(a) 5 (b) 8 (c) 10 (d) 12 (e) 3

5. ( )2

6.02 120.89 144.06− + = ?

(a) 35 (b) 42 (c) 37 (d) 40 (e) 33

6. Cost price of A is twice the cost price of B. If the selling price of B is

Rs. 3600 and it is sold at the profit of 20%, then find the cost price

of A.

A dk ykxr ewY; B ds ykxr ewY; ls nksxquk gSA ;fn B dk fcØh ewY;

3600 :i;s gS vkSj ml ij 20% ykHk izkIr gksrk gS] rks A dk ykxr ewY;

Kkr djsaaA

(a) Rs.3000 (b) Rs.6000 (c) Rs.8000

(d) Rs.2000 (e) Rs.10000

7. The cost price of the two chairs is same. Difference between their

selling prices is Rs. 90. On selling one chair, a person got a profit of

12% and on selling another he got a profit of 18%. Find the cost

price of each chair.

nks dqflZ;ksa dk ykxr ewY; cjkcj gSA mudh fcØh dh dherksa ds chp dk

varj :- 90 gSA ,d dqlhZ cspus ij ,d O;fDr dks 12% dk ykHk izkIr gksrk

gS ,oa nwljh dqlhZ dks cspus ij mls 18% dk ykHk izkIr gksrk gSA izR;sd

dqlhZ dh ykxr ewY; Kkr dhft,A

(a) Rs. 1200 (b) Rs. 1500 (c) Rs. 1800

(d) Rs. 2400 (e) Rs. 1000

8. 1500 rupees is invested in a scheme A at R% p.a. simple interest.

Another amount (1500 - x) is invested in scheme B at 2R % p.a.

simple interest. After 4 years, interest earned from scheme A is

25% less than that of scheme B. Find x.

1500 :i;s dh jkf’k dks Ldhe A esa R% dk lk/kkj.k C;kt dh nj ij fuos’k

fd;k x;k nwljh jkf’k (1500-x) dks Ldhe esa 2R% dh lk- C;kt dh nj

ij fuos’k fd;k x;k ;fn 4 lky ckn A dk C;kt B ds C;kt ls 25% de

gS rks x dk eku D;k gksxk\

(a) 500 (b) 600 (c) 900 (d) 1000 (e) 1200

9. Ratio of age A after two years to the present age of B is 5: 6 and ratio

of age of A 8 years hence to the age of B 6 year hence is 6: 7. Find

B’s present age.

nks o"kZ ckn A dh vk;q vkSj B dh orZeku vk;q dk vuqikr 5%6 gS vkSj 8

lky ckn A dh vk;q vkSj 6 lky ckn B dh vk;q dk vuqikr 6%7 gSA rks B

dh orZeku vk;q Kkr djsaA

(a) 30 (b) 34 (c) 36 (d) 28 (e) 24

10. 4 years ago, the ratio of ages of A and B was 9 : 11 and 6 years hence,

the ratio of ages of A and B will be 7 : 8. Find the present age of B.

4 lky igys A vkSj B dh vk;q dk vuqikr 9 % 11 vkSj 6 o"kZ ckn] A vkSj

B dh vk;q dk vuqikr 7 % 8 gksxkA orZeku esa B dh vk;q Kkr dhft,A

(a) 22 years (b) 24 years (c) 26 years

(d) 37 years (e) None of these

11. 4 years hence the sum of ages of A and B will be 16 years more than

the sum of the present ages of B and C. 4 years ago the sum of A’s

age and C’s age was 32 years, then what is the present age of C?

4 o"kZ ckn] A vkSj B dh vk;q dk ;ksx B vkSj C dh orZeku vk;q ds ;ksx ls

16 o"kZ vf/kd gksxkA ;fn 4 o"kZ igys A vkSj C dh dqy vk;q 32 o"kZ Fkh] rks

C dh orZeku vk;q D;k gS\

(a) 18 years (b) 14 years (c) 10 years

(d) 16 years (e) 12 years

12. A started business with Rs. 600 and B with Rs. 900. After 5 months

B left and C joined with capital Rs. 600 less than B. If at the end of

year profit of C was Rs 3500, then find the total profit at the end of

year.

A us 600 :i;s vkSj B us 900 :i;s ls ,d O;olk; 'kq: fd;kA 5 eghus

ckn B us bl O;olk; dks NksM+ fn;k vkSj C, B ls de 600 :i;s de ds

lkFk bl O;olk; ls tqM+ x;kA ;fn o"kZ ds var esa C dk ykHk 3500 :i;s

FkkA rks o"kZ ds var esa dqy ykHk Kkr djsaA

(a) Rs. 46000 (b) Rs. 36000 (c) Rs. 28000

(d) Rs. 23000 (e) None of these

13. A container contains a mixture of milk and water in which water is

24%. 50% of the mixture is taken out in which water is 78 litre less

than the milk. Find the initial quantity of water in that container?

,d crZu A esa nw/k vkSj ikuh gS ftlesa ikuh 24% gS 50% feJ.k dks fudky

fy;k tkrk gS ;fn cps feJ.k esa ikuh rFkk nw/k dh ek=k dk vUrj 78 yh-

gS rks crkvks izkjEHk esa ikuh dh ek=k fdruh gS\

(a) 171 lit (b) 152 lit (c) 72 lit (d) 108 lit (e) 114 lit

14. 40 men can complete a work in 48 days. If 64 men started working

and after X days, 32 more men joined the work. If the remaining

work is completed in 2

163

days, then find the value of X.

40 O;fDr ,d dke dks 48 fnuksa esa iwjk dj ldrs gSaA ;fn 64 O;fDr dk;Z

djuk 'kq: djrs gS vkSj X fnuksa ds ckn 32 yksx vkSj dk;Z djus esa 'kkfey

gksrs gSA ;fn 'ks"k dke 2

163fnuksa esa iwjk dj fn;k tkrk gS] rks] X dk eku

Kkr djsa\

(a) 2 (b) 5 (c) 8 (d) 4 (e) 6

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15. Train A crosses a vertical pole at the speed of 15 m/s in 20 seconds.

Speed of train A is 3 m/s less than the speed of train B and length

of train B is 30 meter less than length of train A. Find the time taken

by Train B to cross 270 meter long platform.

Vªsu A 20 lsdaM esa 15 ehVj@lsdaM dh nj ij ,d Å/okZ/kj [kaHks dks ikj

djrh gSA Vªsu A dh xfr Vªsu B dh xfr ls 3 ehVj@lsdaM de gS vkSj Vªsu

B dh yackbZ Vªsu A dh yackbZ ls 30 ehVj de gSA Vªsu B }kjk 270 ehVj yacs

IysVQkeZ dks ikj djus esa yxus okyk le; Kkr djsaA

(a) 20 seconds (b) 15 seconds (c) 30 seconds

(d) 45 seconds (e) 40 seconds

16. The ratio of speed of a boat in still water to speed of the current is

10 : 1. If ratio of the time taken by the boat to travel D km

downstream to the time taken to travel (D – 45) km upstream is 3 :

2. Find the value of D.

fLFkj ikuh esa ,d uko dh xfr ,oa /kkjk dh xfr dk vuqikr 10 % 1 gSA

;fn /kkjk ds cgko ds lkFk D fdeh dh ;k=k djus esa fy, x, le; vkSj

/kkjk ds izokg ds foijhr (D - 45) fdeh ;k=k djus ds chp fy, x, le;

dk vuqikr 3 % 2 gS] rks D dk eku Kkr djsaA

(a) 88 (b) 54 (c) 110 (d) 99 (e) 66

Direction(17-21): In the following question, two equations are

given in variables X and Y. You have to solve these equations and

determine the relation between X and Y.

funsZ’k ¼17&21½% fuEufyf[kr iz’u esa pj X vkSj Y esa nks lehdj.k fn, x;s

gSaA bu lehdj.kksa dks gy dhft;s] ,oe X vkSj Y ds chp lEcU/k Kkr

dhft;sA

17. A) 5x + 2y = 31

B) 3x + 7y = 36

(a) X > Y (b) X ≥ Y (c) X < Y

(d) X ≤ Y (e) X = Y or No relation can be established

18. A) x2 – 7x + 12 = 0

B) y2 – 9y + 20 = 0

(a) X > Y (b) X ≥ Y (c) X < Y


19. A) (x + 1)2 = 122

B) y2 + 2y – 143 = 0

(a) X > Y (b) X ≥ Y (c) X < Y


20. 6x2 + 5x + 1 = 0

4y2 + 4y + 1 = 0

(a) If X > Y (b) If X < Y (c) If X ≥ Y

(d) If X ≤ Y (e) If X = Y or no relation can be established

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21. x2 – 16x + 64 = 0

Y2 = 64

(a) If X > Y (b) If X < Y (c) If X ≥ Y

(d) If X ≤ Y (e) If X=Y or No relation can be established

22. Cost of gardening the circular field C at Rs.10 per meter square is

Rs.3465. Side of the square field S is equals to the diameter of the

circular field C. find the perimeter of square field.

xksykdkj {ks= C dks 10 :i;s izfr ehVj oxZ dh nj ij ckxokuh djus dh

ykxr 3465 :i;s gSA oxkZdkj {ks= S dh Hkqtk] xksykdkj {ks= C ds O;kl ds

cjkcj gSA oxkZdkj {ks= dk ifjeki Kkr djsaA

(a) 108 (b) 84 m (c) 78 m

(d) 112 m (e) None of these

Direction(23-27): Find the missing term in given series.

funsZ’k ¼23&27½% nh xbZ J`a[kyk esa yqIr 'kCn Kkr dhft,A

23. 15, 8, 9, 15, 32, ?

(a) 82.5 (b) 81.5 (c) 84.5 (d) 80.5 (e) 86

24. 18, 24, 36, 56, 86,?

(a) 128 (b) 118 (c) 124 (d) 130 (e) 126

25. 222, 110, 54, 26, ?

(a) 8 (b) 11 (c) 13 (d) 9 (e) 12

26. 2, 1, 1, 1.5, 3, ?

(a) 4.5 (b) 6 (c) 7.5 (d) 8 (e) 7.2

27. 26, 63, 124, 215, ?

(a) 315 (b) 421 (c) 342 (d) 426 (e) 388



Direction(28-32): Study the following pie-chart and table

carefully to answer the questions that follow.

funsZ’k ¼28&32½ % fuEufyf[kr iz’uksa dk mŸkj nsus ds fy, fuEufyf[kr

rkfydk ,oa ikbZ pkVZ dk /;kuiwoZd v/;;u djsaA

Percentage of visitors (male and female) in a museum on the given

3 days-Friday, Saturday and Sunday is depicted in the pie chart

given below.

laxzgky; esa rhu fnuksa&’kqØokj] 'kfuokj vkSj jfookj esa vk, vkxarqdksa ¼iq:"k

vkSj efgyk½ dk izfr’kr uhps fn, x, ikbZ pkVZ esa n’kkZ;k x;k gSA

Total number of visitors on the given three days = 400

fn;s x, rhu fnuksa esa dqy vkxarqdksa dh la[;k 400 gSA

Percentage of visitors

Ratio of male visitors to female visitors on the given three days is

depicted in the table given below:

fuEufyf[kr rkfydk esa rhu fnuksa eas vkus okys iq:"k ,oa efgyk vkxarqdksa ds

e/; dk vuqikr n’kkZ;k x;k gS%

Days Male : Female

Friday 2 : 3

Saturday 7 : 5

Sunday 5 : 4

28. On Tuesday, the number of female visitors was 1/5 more than that

of Saturday. If the respective ratio between the number of male

visitors and that of female visitors on Tuesday is 11 : 6, then what

was the total number of visitors (male and female) on Tuesday?

Ekaxyokj ds fnu efgyk vkxarqdksa dh la[;k 'kfuokj ds fnu efgyk vkxarqdks

dh la[;k ls 1@5 T;knk FkhA ;fn eaxyokj ds fnu iq:"k vkxarqdksa ,oa

efgyk vkxarqdksa dk vuqikr Øe’k% 11 % 6 Fkk] rks eaxyokj ds fnu vkxarqdksa

¼iq:"k ,oa efgyk½ dh la[;k D;k gS\

(a) 208 (b) 170 (c) 182 (d) 130 (e) 156

29. What is the total number of male visitors on the given 3 days

together?

fn;s x;s rhuksa fnuksa esa iq:"k vkxarqdksa dh dqy la[;k D;k gS\

(a) 220 (b) 230 (c) 200 (d) 210 (e) 190

30. Out of the total number of visitors on Saturday, 35% were adults.

The cost for 1 adult’s ticket is double that for one child’s ticket. If

the total amount collected from selling tickets on Saturday was

Rs.8100. What is the cost of 1 adult’s ticket?

'kfuokj dks vk, dqy vkxarqdksa esa ls 35% o;Ld gSA ,d o;Ld ds fVdV

dh dher ,d cPps dh fVdV dh dher ls nksxquh gSA ;fn 'kfuokj dks

csph xbZ fVdVksa ls dqy 8100 :i, izkIr gksrs gSA rks ,d o;Ld ds fVdV

dh dhe fdruh gS\

(a) Rs.200 (b) Rs.160 (c) Rs.120 (d) Rs.100 (e) Rs.50

31. What is the central angle corresponding to the number of visitors

(male and female) on Sunday (in degrees)?

jfookj ¼fMxzh esa½ dks vkxarqdksa ¼iq:"k vkSj efgyk½ dh la[;k ds laca/k esa

dsanzh; dks.k fdruk gS\

(a) 172.8° (b) 165.6° (c) 162° (d) 154° (e) 198°

32. The number of female visitors on Friday was what percentage of

the number of female visitors on Sunday?

'kqØokj dks efgyk vkxarqdksa dh la[;k jfookj dks efgyk vkxarqdksa dh la[;k

dh fdruh izfr’kr Fkh\

(a) 70% (b) 85% (c) 80% (d) 65% (e) 75%

Direction(33-37): The bar graph shows the total number of male

and female lives in four different towns and table shows the

number of males and females whose ages are above 40 years. Read

the data carefully and answer the questions below:

funsZ’k ¼33&37½ % ckj xzkQ pkj vyx&vyx dLcksa esa jgus okys iq:"kksa vkSj

efgykvksa dh dqy la[;k dks n’kkZrk gS vkSj rkfydk esa mu iq:"kksa vkSj

efgykvksa dh la[;k dks n’kkZrh gS ftudh vk;q 40 o"kZ ls vf/kd gSA tkudkjh

dks /;kuiwoZd i<+s vkSj uhps fn, x, iz’uksa ds mŸkj nsa%

Name of the town Number of males and females whose ages are above 40 years

A 50

B 70

C 110 D 120

33. Find the average number of those males and females whose ages

are below and equals to 40 years of town A, C and D.

mu iq:"kksa vkSj efgykvksa dh vkSlr la[;k Kkr djsa ftudh vk;q 'kgj A,

C vkSj D es 40 lky ls de ;k mlds cjkcj gSA

(a) 180 (b) 160 (c) 190 (d) 200 (e) 210

34. Find the ratio of the those number of males and females whose ages

are above 40 years in town A and B to those males and females

whose ages are below and equals to 40 years in town D.

og iq:"k vkSj efgyk,a ftudh vk;q 'kgj A vkSj B esa 40 o"kZ ls vf/kd gS]

vkSj og iq:"k vkSj efgyk,a ftudh vk;q 'kgj D esa 40 o"kZ ls de vkSj

mlds cjkcj gS] dh la[;k dk vuqikr Kkr djsaA

(a) 1: 1 (b) 3: 5 (c) 2: 5 (d) 4: 7 (e) 1: 3

35. If 40% of population in town B whose ages are below and equals to

40 years are male and 40% of population in town D whose ages are

below and equals to 40 years are female. Find the difference

between the females of town B and D whose ages are below and

equals to 40 years.

;fn 'kgj B esa 40% tula[;k ftudh vk;q 40 o"kZ ls de vkSj mlds cjkcj

gS] iq:"k gS vkSj 'kgj D esa 40% tula[;k ftudh vk;q 40 o"kZ ls de vkSj

mlds cjkcj efgyk,¡ gSA 'kgj B vkSj D dh mu efgykvksa ds chp varj Kkr

djs ftudh vk;q 40 o"kZ ls de vkSj mlds cjkcj gSaA

(a) 46 (b) 52 (c) 49 (d) 58 (e) 39

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36. Number of males and females in town A whose ages are below and

equals to 40 years is what percent less than those number of males

and females in town D whose ages are below and equals to 40 years.

'kgj A esa iq:"kksa vkSj efgykvksa dh la[;k ftudh vk;q 40 o"kZ ls de ;k

mlds cjkcj gS] 'kgj D esa mu iq:"kksa vkSj efgykvksa dh la[;k dh rqyuk esa

fdrus izfr’kr de gS ftudh vk;q 40 lky ls de ;k mlds cjkcj gSA

(a) 10% (b) 12% (c) 7% (d) 5% (e) 17%

37. If in another town E, total males and females are 10% more than

the total males and females in town A and those males and females

whose ages are above 40 years is 20% more than those males and

females whose ages are above 40 years in town C. Find the number

of those males and females in town E whose ages are below and

equals to 40 years.

;fn ,d 'kgj E esa] dqy iq:"k vkSj efgyk,a] 'kgj A ds dqy iq:"kksa vkSj

efgykvksa dh rqyuk esa 10% vf/kd gS vkSj os iq:"k vkSj efgyk,a ftudh mez

40 lky ls vf/kd gS] mu iq:"kksa vkSj efgykvksa dh rqyuk essaa 20% vf/kd gS

ftudh vk;q 'kgj C esa 40 ls vf/kd gSA 'kgj E esa mu iq:"kksa vkSj efgykvksa

dh la[;k Kkr djsa ftudh vk;q 40 o"kZ ls de vkSj mlds cjkcj gSaA

(a) 132 (b) 128 (c) 142 (d) 124 (e) 138

Directions (38-42): Study the given information carefully and

answer the question that follow.

3 pizza shops A, B and C sells veg pizza and non veg pizza.

Respective ratio between number of vegetarian and non-

vegetarian pizzas sold by pizza shop A was 9 : 7 and that sold by

pizza shop B was 3 : 4. The no. of pizzas (Veg + non veg) sold by

pizza shop C was 108 and respective ratio between number of

vegetarian and non-vegetarian pizza sold by pizza shop C was 7 : 5

Total number of pizza sold by all three pizza shop was 376. Number

of veg pizza sold by pizza shop A was 20% more than the veg pizza

sold by pizza shop B.

funsZ’k ¼38&42½ % nh xbZ lwpuk dks /;ku ls i<+s vkSj mldk mŸkj nsA

rhu fiTtk nqdku] A, B rFkk C }kjk ost fiTtk rFkk ukWu ost fiTtk csps

tkrs gSA A,B ds }kjk csps x;s ost rFkk ukWu ost fiTtk dk vuqikr Øe’k%

9%7 rFkk 3%4 gSA C ds }kjk dqy 108 fiTtk ¼ost rFkk ukWu ost½ csps tkrs

gS C ds }kjk csps x;s ost rFkk ukWu ostu fiTtk dk vuqikr 7%5 gS rhuks

nqdku }kjk dqy 376 fiTtk csps x;sA A ds }kjk csps x;s ost fiTtk] B ds

}kjk csps x;s ost fiTtk ls 20% T;knk gSA

38. If cost of each veg pizza and each non-veg pizza sold by shop B is Rs

200 and Rs 300 respectively then find the total amount obtained by

shop B (in Rs).

;fn B ds izR;sd ost fiTtk rFkk ukWuost fiTtk dk ewY; Øe’k% 200 vkSj

300 gS rks B ds }kjk csps x;s fiTtk ls fdruk ewY; izkIr gqvkA

(a) 40,000 (b) 36000 (c) 48000

(d) 32000 (e) 44000

39. What is the ratio of veg pizza sold by shop A & C together to the

non-veg pizza sold by shop B & C together.

A vkSj C ds }kjk csps x;s ost fiTtk rFkk B ,oa C ds }kjk csps x;s ukWuost

fiTtk ds lkFk D;k vuqikr gSA

(a) 27 : 25 (b) 27 : 29 (c) 29 : 27

(d) 25 : 27 (e) 23 : 25

40. What is the average of veg pizza sold by all shops?

lHkh nqdku }kjk csps x;s ost fiTtk dk vkSlr D;k gksxk\

(a) 61 (b) 68 (c) 62 (d) 60 (e) 65

41. Total veg pizzas sold by Shop A and C are what percent of total non-

veg pizza sold by shop B & C?

A vkSj C ds }kjk csps x;s ost fiTtk B rFkk C ds }kjk csps x;s ost fiTtk

dk fdruk izfr’kr gS\

(a) 113% (b) 108% (c) 109% (d) 112% (e) 116%

42. If Veg pizza sold by shop B is increased by 1

33 %3

and non-veg

pizza sold by shop A is increased by 75% then what is the sum of

veg pizza sold by B and non-veg pizza sold by A after increment.

;fn B ds }kjk csps x;s ost fiTtk 1

33 %3

rFkk A ds }kjk csps x;s ukWuost

fiTtk 75% c<+ tkrs gS rks B ds ost rFkk A ds ukWuost fiTtk dk dqy ;ksx

fdruk gksxk\

(a) 178 (b) 186 (c) 198 (d) 200 (e) 182



1. (b)

8.02 – (? – 9.01) + (10.92)2 = 120

⇒ 8 – ? + 9 + (11)2 = 120

⇒ 8 – ? + 9 + 121 = 120

⇒ ? = 138 – 120

⇒ ? = 18

2. (b)

? = 14 × 3 + 200

⇒ ? = 42 + 200

⇒ ? = 242

3. (c)

6% of [(198.99)+(15.99)2]= ?

? = 6

10× [199 + (16)2]

? = 6

10× [199 + 256]

? = 6

10× 455

? = 27.30

? ≈ 27

4. (a)

1 1 1

- +14.96 3.94 ?

= 0

1 1 1

= -? 4 15

1 15- 4

=? 60

1 11

=? 60

? = 60

11≈ 5

5. (c)

(6.02)2 - 120.89 144.06+ = ?

? = (6)2 - 121 144+

? = 36 – 11 + 12

? = 37

6. (b)

Given, selling price of B = 1.20 × cost price of B

⇒ Cost price of B = 3600 ÷ 1.20 = Rs.3000

Cost Price of A = 2 × Cost price of B

Hence, the cost price of A = 2 × Rs.3000 = Rs.6000.

7. (b)

Let CP of the Article 100x Rs.

So SP of first Article at 12% gain= 112x Rs.

And SP of second Article at 18% gain = 118x Rs.

118x – 112x= 90

6x = 90

X= 15

So CP of the Article = 100x =1500 Rs.

8. (a)

Interest earned from scheme A = 1500×R ×4

100= 60R

Interest earned from scheme B

= ( ) ( )1500- x ×2R ×4 2R 1500- x

=100 25

60R = ( )2R 1500- x3

×4 25

1500 – x = 1000

X = 500

9. (c)

Let the age of A be x years and age of B be y years,

❖ Neon Approach (Thought Process):

(10.92)2 and 120 is approximately same

Then x = 8 + 9 = 17 ~ 18


Aryan Ratio :

CP of A = 3600

6× 5× 2 = 6000


∴ Option (a) and (d) impossible gS D;ksafd ;g cgqr

de gSA

∴ CP of A 7200 ls de gksxk ,slk dsoy option (b) gSA


Aryan Ratio :

CP of each chair = 90

6× 100 = 1500


Ratio of interest of A and B = 3 : 4

If Rate of interest of B is same then

A : B

3 : 2

500× ×500

1500 1000 x = 1500 – 1000

= 500

Solutions

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A + 2

B=

5

6

6A + 12 = 5B

6A – 5B = - 12 ---------- (i)

A + 8 6

=B + 6 7

7A + 56 = 6B + 36

7A – 6B = - 20 ----------- (ii)

On solving eq. (i) and (ii), we get

A = 28 and B = 36

10. (c)

Let the ages of A and B be 9X and 11X, then

9 10 7

11 10 8

x

x

+=

+

⇒ 72X + 80 = 77X + 70

⇒ X = 2

Hence, the present age of B = 11X + 4 = 22 + 4 = 26 years

11. (d)

Present age of A and C:

A + C = 40 ............(i)

After 4 years, sum of ages of A and B will be 16 years more than

the sum of the present ages of B and C.

A + 4 + B + 4 = B + C + 16

A - C = 8 ............(ii)

On solving eq(i) and eq(ii).

2A = 48

A = 24

Then, the present age of C:

24 + C = 40

C = 16 Years

12. (d)

Ratio of the equivalent capitals of A, B and C for 1 month

= 600 × 12 : 900 × 5 : 300 × 7 = 24 : 15 : 7

7 ≡ Rs. 3500

⇒ 1 ≡ Rs. 500

The total profit at the end of year = 24 + 15 + 7 = 46 ≡ 46 × Rs.

500 = Rs. 23000

13. (e)

Let the quantity of mixture be 100x lit

Quantity of milk= 76x lit

And quantity of water= 24x lit

Quantity of water taken= 12x lit

Quantity of milk taken= 38x lit

26x=78

x=3 lit

required quantity of water = 24×3 = 72 lit

14. (b)

Total work = 48× 40 = 1920 units

Now,

1920 = 64 × X + (64 + 32) × (50/3)

⇒ 1920 = 64X + 1600

⇒ 64X = 320

⇒ X = 5


A (2 year hence) : B (Present)

5 : 6

A (8 year hence) : B (6 year hence)

6 : 7

difference is same

B’s Present Age = 6

1× 6 = 36


B dh Present Age esa 6 tksM+us ij og 7 dk Multiple

gksxh ,slk dsoy option (c) gSA


A : B

-4 +6

9 : 11 A : B 7 : 8 = 1 × 2

14 : 16 = 2

Present age of B =10

5× 11 + 4 = 26 year


B dh present age esa 6 tksM+us ij og 8 dk Multiple

gksxh ,slk dsoy option (c) gSA


Present age of A and B is 8 year more than B and C

A – C = 8

A + C = 32 + 8 = 40

A = 24

C = 16


The ratio of Milk and water = 19 : 6

Aryan Ratio :

Initial quantity of water = 78

6.5× 6 = 72


40 × 48 =( )

64×x 96×50=

y 3 1- y

y =1

6or x = 5 days


40 × 48 = 96 × D

D = 20

Remaining day = 20 - 2 1

16 33 3=

96 × 10

3= 64 × D

D = 5 days



15. (c)

Let the length of Train A be L meters, then According to

question,

L

15= 20

⇒ L = 300 m

∴ Length of train A is 300 m

So, length of train B = 300 – 30 m = 270 meters

Speed of train B = 15 + 3 = 18 m/s

When B crosses a 270 m long platform,

Time = 270 270

18

+seconds = 30 seconds

Hence, the required time = 30 seconds.

16. (d)

Let ratio of speed of a boat in still water to speed of the current

is 10x : x, then

( )

( )

D/ 10+1 x 3=

D- 45/ 10-1 x 2

⇒ 18D = 33D – 33 × 45

⇒ 15D = 33 × 45

⇒ D = 99

17. (a)

A) (5x + 2y = 31) × 3

B) (3x + 7y = 36) × 5

15x + 6y = 93 ..... (i)

15x+35y= 180 .... (ii)

On solving both equations, we get

x = 5 and y = 3

so, X > Y


∴ x days work = (8×48) – 64 = 320

∴ x = 320

64= 5


down stream : upstream

Speed 11 : 9

Time 3 : 2

Distance 33 : 18

D =45

15× 33 = 99 km


5x + 2y = 31 …...(1)

3x + 7y = 36 ……(2)

Subtract equation (2) - equation (1)

5y – 2x = 5

x = 2.5 (y - 1)

y always +ve then

x > y

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18. (d)

A) x2 – 7x + 12 = 0

⇒ x(x – 4) – 3(x – 4) = 0

⇒ (x – 4)(x – 3) = 0

So, x = 3, 4

B) y2 – 9y + 20 = 0

⇒ y(y – 5) – 4(x – 5) = 0

⇒ (y – 5)(y – 4) = 0

So, y= 4, 5

Hence, X ≤ Y

19. (e)

A) (x + 1)2 = 122

⇒ (x + 1)2 – 122 = 0

⇒ (x + 1 – 12)(x + 1 + 12) = 0

⇒ (x – 11)(x + 13) = 0

x = 11, –13

B) y2 + 2y – 143 = 0

⇒ y2 + 13y – 11y – 143 = 0

⇒ y(y + 13) – 11(y + 13) = 0

⇒ (y + 13)(y – 11) = 0

y = 11, – 13

So, no relation can be established.

20. (c)

6x2 + 5x + 1 = 0

⇒ 6x2 + (3 + 2)x + 1 = 0

⇒ 3x(2x + 1) + (2x + 1) = 0

⇒ (3x + 1)(2x + 1) = 0

⇒ x = –1/3, –1/2

4y2 + 4y + 1 = 0

⇒4y2 + (2 + 2)y + 1 = 0

⇒ (2y + 1)2 = 0

⇒ y = –1/2

So, X ≥ Y

21. (c)

x2 – 16x + 64 = 0

⇒ (x – 8)2 =0

⇒ x = 8

Y2 = 64

⇒ Y = ± 8

So, X ≥ Y

22. (b)

Let r meter be the radius of circular field C, then

Area of circular field C × 10 = 3465

⇒ πr2 × 10 = 3465

⇒ r2 = 441

4

⇒ r = 21

2m

Side of square field S = 2 × r = 21m

Perimeter of square field = 4 × 21 = 84 meters

23. (a)

15 × 0.5 + 0.5 = 8

8 × 1 + 1 = 9

9 × 1.5 + 1.5 = 15

15 × 2 + 2 = 32

32 × 2.5 + 2.5 = 82.5

24. (a)

The pattern of the series is:

25. (e)

222 ÷ 2 - 1 = 110

110 ÷ 2 - 1 = 54

54 ÷ 2 - 1 = 26


+ + - -

- - + +

+ - - +

- - + -

x2 – 7y + 12 = 0 y2 – 9y + 20 = 0

x = +4 y = +5 x < y

x = +3 y = +4


+ + - -

- - + +

+ - - +

- - + -

(x+1)2 = 122 y2 + 2y - 143 = 0

x = + y = +

We can find the Answer with the sign

So relation cannot establish.


+ + - -

- - + +

+ - - +

- - + -

6x2 + 5y + 1 = 0 7y2 + 4y + 1 = 0

x = 3

6− y =

2

4− Ans. x > y

x = 2

6− y =

2

4−


+ + - -

- - + +

+ - - +

- - + -

22 – 16x + 64 = 0 y2 = 64

x = 8 y = + 8 Ans. x > y



26 ÷ 2 - 1 = 12

26. (c)

The pattern of the series is:

2 × 0.5 = 1

1 × 1 = 1

1 × 1.5 = 1.5

1.5 × 2 = 3

3 × 2.5 = 7.5

27. (c)

26 = 33 – 1,

63 = 43 – 1,

124 = 53 – 1,

215 = 63 – 1,

342 = 73 – 1

28. (b)

Day Male Female Total

Friday 40 60 100

Saturday 70 50 120

Sunday 100 80 180

Number of female visitors on Tuesday = 50 + 1/5th of 50 = 50

+ 10 = 60

Number of male visitors on Tuesday = (11/6) × 60 = 110

Hence, the total number of visitors on Tuesday = 60 + 110 =

170.


Aryan Ratio :

⇒ 4 × 30 × 5 6 17

12 5 6 = 170


m : f

11 : 6 = 17

Answer will be multiple of 17

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29. (d)


Friday 40 60 100

Saturday 70 50 120

Sunday 100 80 180

The total number of male visitors on the given 3 days together

= 40 + 70 + 100 = 210.

30. (d)


Friday 40 60 100

Saturday 70 50 120

Sunday 100 80 180

Let cost of 1 adult’s ticket = Rs. 2x, then cost of 1 child’s ticket =

Rs. X

(35% of 120)× 2x + (65% of 120) × x = 8100

⇒ 84x + 78x = 8100

⇒ x = 8100/162 = 50

Hence, cost of 1 adult’s ticket = Rs. 2x = 2× Rs. 50 = Rs.100.

31.

32. (e)


Friday 40 60 100

Saturday 70 50 120

Sunday 100 80 180

Required percentage = (60/80) × 100 = 75%.

33. (a)

Required average = (190 + 150 + 200) ÷ 3 = 540 ÷ 3 = 180

34. (b)

Required ratio = 50 + 70: 200 = 120: 200 = 3: 5

35. (a)

Number of females in town B whose ages are below and equals

to 40 years = 210 × 0.60 = 126

Number of females in town D whose ages are below and equals

to 40 years = 200 × 0.40 = 80

Required difference = 126 – 80 = 46

36. (d)

Required percentage = 200 190

200

−× 100 = 5%

37. (a)

Total males and females in town E = 1.10 × 240 = 264

Number of males and females whose ages are above 40 years =

1.20 × 110 = 132

Required answer = 264 – 132 = 132

38. (b)

A B C

Veg 72 60 63

Non-Veg 56 80 45

Required total amount = 60 × 200 + 80 × 300 = 12000 + 24000

= 36000

39. (a)

Required ratio =72+63

80+ 45=

135 27=

125 25


M : F

Friday 2 : 3 = 5

Saturday 7 : 5 = 12 ÷ 2

Sunday 5 : 4 = 9

the percentage of male

[2+3.5+5]×5 = 52.5%

Total male = 4×52.5 = 210


Adult : Children

No. of person 7 : 13 = 20

Price of Ticket 2 : 1 = 3

Total amount 14 : 13 = 27

Total person on Saturday = 30% of 400 = 120

That is 6 time of 20

Aryan Ratio :

Price of Adult = 8100

27×6× 2 = 100


360

100× 45 = 162


Friday : Saturday

Female 3 : 4

⇒ 3

4× 100 = 75%


Total male and female in A, C, D (below or equal to

the 40 year)

= 190 + 150 + 200 total excess (40+50 = 90)

Required Average = 150 + 90

3= 180


210 × 60% - 200 × 40%

= 46 (Apply digit sum) (unit digit)


Number of those male and female in town E whose

ages are below or equal to 40

= 240 ×11

10- 110 ×

6

5

= 132 (Answer will be multiple of 11) only (a) option



40. (e)

Required ratio = 72+60+63

3= 65

41. (b)

Required ratio = 135

125× 100 =

27

25× 100 = 108%

42. (a)

Required sum = 4

3× 60 +

7

4× 56 = 80 + 98 = 178

38-42.

38.

39.

40.

41.

42.


V. Pizza : N.V. Pizza

A 9 : 7 = 16 × 2 = 32 × 4

B 3 : 4 = 7 × 5 = 35 268

C 7 : 5 = 12 ---×9--------108

A : B

Veg Pizza 6 : 5


B V : N

Pizza 3 : 4

Cost 2 : 3

Total 6 : 12 = 18

(Answer will be multiple of a only (b) option)


(A+C) veg Pizza : (B+C) Non Veg Pizza

9×2×4+7×9 : 4×5×4+5×9

135 : 125

27 : 25


Average = 135 + 650 =195

3= 65


Receive Percentage =27

25× 100 = 108%


Total sum = 60 ×4

3+ 56 ×

7

4= 178

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