National Institute of Technology Durgapur
DEPARTMENT OF MANAGEMENT STUDIES2012-2014
PROJECT By
Group 5(44-54)
Exercise 10(I) Integration
Q1. Define Integration as inverse process of differentiation. Give three illustrations.
Ans1. Integration ,the inverse process of differentiation .
If f(x) be a given function of x and if another function F(x) be obtained such that its differential coefficient with respect to x is equal to f(x),then F(x) is defined as an integral ,or more properly an indefinite integral of f(x) with respect to x.
The process of finding an integral of a function of x is called and the operation is indicated by
writing the integral sign “ ” before the given function and dx after the given function ,the symbol dx indicating that x is the variable of integration. The function to be integrated,viz f(x) is called the integral.
Symbolically,if F(x)=f(x) then .Where is called an indefinite integral of f(x)
with respect to x.It will be shown later that if is condition the exits.Thus considered as
symbols of operation, and are inverse to each other.
As we can see the example.
Derivatives Integral(Anti derivatives)
Q2.What do you mean by the constant of integration? Is its value fixed?
Ans 2. Constant of Integration
It may be noted that if F(x)=f(x),then we also have
,
Where is an arbitrary constant.Thus ,if ,a general value of the indefinite integral
In other words , in finding the indefinite integral of a function ,an arbitrary constant is to be added to the result to make it general .This is the reason why the integral is referred to as an indefinite integral.
The arbitrary constant is usually referred to as the constant of integration.Addition of constant to the
and not any non constant function is explained below.
We know that if two function is defined on the closed interval [a,b] are such that
,
For all then is constant on [a,b].Thus it is possible to get the indefinite integral of the same function in different forms by different processes,but ultimately these forms can atmost differ from each other by constant quantities only.Hence an arbitrary constant added to the indefinite integral of a given function obtained by any process makes the result perfectly general.
Q3.State for what value of n,the formula ,where is constant ,is not true.
Ans 3. For =-1,the formulae is not true.
As for n=-1, so for this we have
And we write our formulae as
4. (i) To show
We know or
Here
So ,therefore
(ii) To show
(iii)
(iv)
(v)
5.
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
6
(i)
(ii)
(iii)
(iv)
7.
(i)
(ii)
(iii)
(iv)
8
(i)
(ii)
(iii)
(iv)
(v)
9
(i)
(ii)
(iii)
10
(i)
(ii)
(iii)
(iv)
Exercise 10(II)Integration-A
1. Evaluate:
2. Integrate:
3. Evaluate:
4. Evaluate:
6. Evaluate:
7. Integrate:
Integration-B1. Evaluate
2. Evaluate
3. Integrate
4. Evaluate
5. Evaluate
6. Evaluate 7. Evaluate
EXERCISE 10(III)-A
1. EVALUATE:
2. Evaluate
3. EVALUATE
4. EVALUATE
5. EVALUATE
6. Evaluate
Exercise 10(iii) B
Exercise 11(I) Definite Integrals
2.(i) by first principle.
Let f(x ) be a continuous real valued function, defined in a closed interval [a,b]. Then we define.
= h [f (a) +f (a+h) +f (a+2h) +……..+f [a+ (n-1) h]
Where nh=b-a
Let in this case f(x)= and a =0; b=1, nh=b-a =1
= h [f (0) +f (0+h) +f (0+2h) +……..+f [0+ (n-1) h]
= h[0+ ]
= h[2 { }]
Now we know that
=
As h 0 and nh =1
=23 ans.
2.(ii)
, by first principle.
Let and a=0; b=1 nh= b-a=1
From formula;
2.(iii)
Let a=0 b=1 nh=1
5.(i)
5.(ii)
5.(iii)
Taking log both side we get
Differentiating both side w.r.t to x
Also when
5.(iv)
6.(i)
6.(ii)
6.(iii)
6.(iv)
7.(i)
On dividing 1-x by 1+x
7.(ii)
7.(iii)
let
And at
7.(iv)
Let
And at
Question 3(1) ∫a
b
x❑dx
Answer =
∴∫a
b
x❑dx=1/2¿
= 1/n+1[b1+1−a1+1¿
= 1/n+1[b2−a2 ¿
Question no :3(2) ∫1
5
3 x dx
Solution :
= ∫1
5
3 x dx
=) 3∫1
5
xdx
= ) 3∫1
5
¿¿
=) 3/2[52−12¿¿
=) 36
Question no :3(3) ∫2
3
(2x2+5)dx
Solution :
=2∫2
3
2 x2+5∫2
3
dx
=2∫2
3
¿¿
= 2∫2
3
¿¿
= 2/3∫2
3
¿¿
=) 2/3[33−23¿23+5 [31−21 ¿2
3
= 53/3
8.(i)
Let
Also at
8.(ii)
Let
Also at
8.(iii)
For this problem,
Integrating by parts.
Let x be 1st function and exbe 2nd
8.(iv)
Let
Also at
8.(v)
Let logx=1st function
x2 =2nd function
Now integration by part we get
8.(iv)
1st function=logx
2nd function=x
Integration by parts
9.(i)
Put
Also
9.(ii)
let
Also at
By using partial fraction:-
We can write
Let
9.(iii)
Put
Also
9.(iv)
Put
Also
10.(i)
Let
Also at
10.(ii)
Let
Also at
10.(iv)
Let
Also
10.(v)
Solving by partial fraction.
let
10.(vi)
Using partial fraction
Let
11.(i)
11.(ii)
Using partial fraction
Let
11.(iii)
Using partial fraction
Let
12.(i)
Let
Also at
Dividing z3by 1+z we get
Let
Also
Therefore
Question 13(1) ¿ lim ¿n→∞ (1n+m
+ 1n+2m
+ 1n+3m
+…+ 1n+nm
)¿
Answer =
¿ lim ¿n→∞ (1n+m
+ 1n+2m
+ 1n+3m
+…+ 1n+nm
)¿
¿ lim ¿n→∞1n¿¿
= lim ¿n→∞1n∑r=1
n 1
1+m. rn
¿
= lim ¿n→0h∑r=1
n 11+mrh
¿ [where 1n=h] [
= ∫0
1 dx1+mx
= 1m∫0
1 m1+m x
dx = 1
m¿
= 1m¿
Question 13(2) lim ¿n→∞¿¿ )
Solution:
lim ¿n→∞¿¿)
lim ¿n→∞1/n {¿¿
lim ¿n→∞1/n∑r=1
n
¿¿¿
lim ¿n→∞1/n∑r=1
n
¿¿¿
∫0
1
xmdx
=[ xm+1
m+1 ] =
1m+1
Question13(5)
¿ lim ¿n→∞ (1n+1
+ 1n+2
+ 1n+3
+…+ 1n+n
)¿
Evaluate
¿ lim ¿n→∞ (1n+1
+ 1n+2
+ 1n+3
+…+ 1n+n
)¿
¿ lim ¿n→∞ (+(1n )
1+ 2m
+( 1n )
1+ 3m
+…+( 1n )
1+ nn)¿
¿ lim ¿n→∞∑r=1
n 1
1+. rn
¿
¿∑r=1
n 11+rh
¿∫0
1 11+r
dx
=[log(1+x]
=log2 .
14.
15.(i)
Let
Also
Taking exp both side
Also at
Solving by part 1st function =t 2, and 2nd function=e t
Again solving by parts.
15.(ii)
Solving x+1
(x+2)2 by partial fraction
Let
By using the formula
15.(iii)
Solving i.e. dividing then partial fraction
Therefore
Now p.f of
Let
15.(iv)
Let
Also at
Using p.f
Let
15.(v)
Let
Also
Solving by P.F
Let
16.
The given curve is
The given lines are x-axis x=1 and x=3.
The required area between the above curve and area ABCD(the back region) in the fig
17.(i)
If f’(x) =3 x2+2
Now given that,
17.(ii)
If f’(x) =logx
Solving by parts by taking
Given
18.
Evaluating the first integral by parts
Also given that;
Exercise 11(II)
3
3 30
3
3 30
3
3 30 0 0
33
3 30
0
0
4(3)
.................... (1)
....................(2) ( ) ( )
(1) (2)
2
2 1
2
2 0
.2
a
a
a a a
a
a
a
xdxa x x
xdxSol Ia x x
a xdxI f x dx f a x dxx a x
After adding
x a xI dx
a x x
I dx
I x
I a
aI Ans
∫
∫
∫ ∫ ∫
∫
∫
13 2 5
1
3 2 5
3 2 5
13 2 5
1
5(1) (1 )
( ) (1 )
( ) (1 ) ( )
( )
(1 ) 0 . ( ) 0, ( )
n
a
a
x x dx
Sol Here f x x x
Now f x x x f x
f x is anodd f
x x dx Ans f x dx when f x is anodd
∫
∫ ∫
22
2
2
2
22
2
5(2) 4
( ) 4
( ) 4 ( )
( )
4 0 ( ) 0, ( )
n
a
a
x x dx
Sol Here f x x x
f x x x f x
f x is an odd f
x x dx f x dx when f x is an odd
∫
∫ ∫
22 2
2
2 2 22 4 2 4
2 2 2
2 23 5
2 2
6(1) (1 )
( )
1 1(8 8) (32 32)3 5 3 5
112 .15
x x dx
x x dx x dx x dx
x x
Ans
∫
∫ ∫ ∫
1 2
6 61
1 12 2
3 2 3 2 3 3 3 31 1
1 2
3 3 3 3 31
1 12 2
3 3 3 3 31 1
1 13 3 2
31 1
6(2) ( 1)
( ) ( ) ( )( )
1 12 ( ) ( )
12 ( ) ( )
1 1 1 12 3 3 3
16
x dx aa x
x dx x dxa x a x a x
x dxa a x a x
x dx x dxa a x a x
dz dz a x z so x dx dza z z
a
∫
∫ ∫
∫
∫ ∫
∫ ∫
11 ,3 1 1
11 3 3
3 , 3 3 31 1
3
3 3
3
3 3
log( ) log( )
1 1log( ) log6 6
1 12log6 1
1 1log .3 1
z z
z a xa z a a x
aa a
a Ansa a
5
550
5
550
5
5 50
5 5
550
0 0
7(2)
............... 1
........................ 2
1 2
2
2 1
2
a
a
a
a
aa
x dxx a x
x dxSol Ix a x
a x dxAgainwecanwrite I
a x x
After adding
x a x dxI
x a x
I dx x
aI Ans
∫
∫
∫
∫
∫
4
4 4
2
10 102
2 2
5 2 5 2 5 5 5 52 2
2 5
5 5 5 5 52
2 2 25 5 5 5
5 5 5 5 5 5 5 5 5 5 52 2 2
2
52
7(3) 2
( ) ( ) ( )( )
1 12
1 1 12 2 2
1 1 12 5 2
x dx aa x
x dx x dxa x a x a x
x dxa a x a x
x x x dx x dxdxa a x a x a a x a a x
dza z
∫
∫ ∫
∫
∫ ∫ ∫
∫
25 5 4 5 5 ,
5 ,2
2 2, 5 5 5 55 52 2
5 5 5 55
5 55
1 15 5
1 1log( ) log( ) log( ) log( )10 10
1 log( 32) log 32 log( 32) log( 32)10
1 .2 log( 32) log 3210
dz a x z then x dx dz same a x za z
z z a x a xa a
a a a aa
a aa
∫
5
5 5
1 ( 32)log .5 ( 32)
a Ansa a
BS( Assignment-9)Probability distribution(Binomial and poisson )
1. A binomial variable x satisfies the relation 9 P(X=4)= P(X=2) when n=6. Find the value of the parameter p.
2. Five unbiased coins are tossed 3200 times; find the frequencies of the distribution of heads and tails and tabulate the results.
3. Suppose 5% of the inhabitants of Calcutta are cricket fans. Determine the probability that a sample of 100 inhabitants will contain at least 3 cricket fans.
4. A die is rolled 6 times. Find the probability that each of the six faces appears exactly once.5. A department in a works has 10 machines, which may need adjustments from time to time
during the day. Three of these machines are old, each; having a probability of 1/11 of needing adjustment during the day, and 7 are new, having corresponding probabilities of 1/21. Assuming that no machine needs adjustment twice on the same day, determine the probabilities that on a particular day (i) just 2 old and no new machines need adjustment, (ii) if just 2 machines need adjustment, they are of the same type.
6. An irregular six-faced die is thrown and the expectation that in 10 throws it will give five even numbers is twice the expectation that it will give four even numbers. How many times in 10,000 sets of 10 throws would you expect it to give no even numbers?
7. Seven coins are tossed and number of heads noted. The experiment is repeated 128 times and the following distribution is obtained:
No.of heads 0 1 2 3 4 5 6 7 Total
Frequencies 7 6 19 35 30 23 7 1 128
Fit a Binomial distribution assuming (i) the coin is unbiased. (ii) the nature of the coin is not known.
8. A car hire firm has two cars, which it hires out day by day. The number of demands for a car on each day is distributed as poisson variate with mean 1.5. Calculate the proportion of days on which (i) neither car is used, (ii) one car remains idle (assuming that each car is used equally) (iii) no demand is refused nor any car remains idle and (iv) some demands are refused. Also calculate proportion of demands refused.
9. A manufacturer of cotter pins known that 5% of his product is defective. If he sells cotter pins in boxes of 100 and guarantees that not more than 10 pins will be defective, what is the approximate probability that a box will fail to meet the guaranteed quality?
10. If X and Y are independent Poisson variates such that P (X=1) = P (X=2) and P(Y=2) =P(Y=3) . Find the variance of X-2Y.
11. A skilled typist kept a record of mistakes made per day during 300 working days of a year:Mistakes per day (x) : 0 1 2 3 4 5 6
Number of days (frequency fx) : 143 90 42 12 9 3 1
Fit an appropriate Poisson distribution to the above data.
12.A telephone operator receives an average of 3 calls during three days within 11-00 to 11-05 AM. What is the probability that (i) an operator receives no call during that interval?
(ii) receives exactly one call in three days during that interval?
13. If X is a poisson variate such that P (X=2)=9 P(X=4) + 90 P(X=6)
Find mean and variance of Poisson Distribution and calculate P(X>2).
3. Solution
Probability of inhabitant of Calcutta being a cricket fan=
= 0.05
Sample size = 100
Required probability = Atleast 3 are cricket fans.
Let x => Random variable = No. of cricket fans
Then x is the binomial variate where the parameters n = 100, p = 0.05
Its is = P(x=i) =
P (atleast 3 cricket fans) = P(x 3)
= 1-P(x<3)
= 1-[P(x=0) +P(x=1) +P(x=2)]
=1-[0.0059+0.031+0.081]
=0.8821
9. A manufacturer of cotter pins known that 5% of his product is defective. If he sells cotter pins in boxes of 100 and guarantees that not more than 10 pins will be defective, what is the approximate probability that a box will fail to meet the guaranteed quality?
Soln. Let the random variable X denote the number of defectives in the box.
Given: .
And n=100
The probability that a box will fail to meet the guaranteed quality
=P(it contains more than 10 pins defective)
12. A telephone operator receives an average of 3 calls during three days within 11-00 to 11-05 AM. What is the probability that (i) an operator receives no call during that interval? (ii) receives exactly one call in three days during that interval?
13. If X is a poissonvariate such that P (X=2)=9 P(X=4) + 90 P(X=6).Find mean and variance of Poisson Distribution and calculate P(X>2).