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Content• Section 1
– Single Phase Theory (Phase-Diagrams)
– Vapor Pressure (Antoine and Clapyeron Eqn)
– Gibbs Phase Rule
• Section 2
– Gas-Liquid Systems (1 condensable)
• Evaporation, Drying, Humidity
– Gas-Liquid Systems (multi-condensable)
• Raoult Law, Henry Law
• Dew/Bubble points
• Txy & Pxy Diagrams
• Section 3
– Solid-Liquid Systems• Crystallization
– Solubility and Saturation
– Hydrated Salts
– Liquid-Liquid Systems• Miscibility and Extraction
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Application in MB• Many processes include multiple-phase
equilibriums– Humidity in air– Absorption– Distillation
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Section 1
• Single Phase Theory (Phase-Diagrams)– Phase Diagram
– Phase Change
– Boiling point (T,P); Sublimation point (T,P); Freezing point (T,P)
– L-S, L-G, G-S Equilibrium lines
• Vapor Pressure (Antoine and Clapyeron Eqn)– Vapor pressure definition
– Volatility
– Latent heat of vaporization
– Vapor Pressure estimation/calculation
• Gibbs Phase Rule– DOF for systems (intensive properties)
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Phase Diagrams
• Diagram of a pure substance
– It’s a Plot containing one system variable (P,T,V,etc.) vs. other one.
– It shows conditions at which the substance exists in different phases (sol., liq., gas typically)
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Phase Diagrams
• P-T Diagram shows the next information:
– Pressure of substance (y-axis)
– Temperature of substance (x-axis)
– Phase Equilibrium Lines
– Critical Point
– Triple Point
– Phases
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Special Data
• Phase Equilibrium Lines– Phase equilibrium @ P,T
• Critical Point– Point where no phase boundaries exist
• Triple Point:– Point which the three equilibrium
lines meet
– Solid-Liquid-Gas coexist
• Boiling point– Normal BP (P=1atm)
• Freezing point– Normal FP (P=1atm)
• Sublimation point– Normal SP (P=1atm)
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Phase Diagrams
A phase diagram for a binary system displaying a eutectic point.
The iron–iron carbide (Fe–Fe3C) phase diagram
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Volatility and Vapor Pressure
• Volatility
– degree to which the species trends to transfer from the liquid (or even solid) state to the vapor state
• Vapor pressure Pº
– Measure of volatility
– Function of Temperature
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Vapor Pressure
• Pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases (solid or liquid) at a given temperature in a closed system
Pvapor
Pcond
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Vapor Pressure
• Given (T boiling)
• The Vapor Pressure “line” is shown in the Graphic
• For any Tb, there is a Vapor Pressure
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Estimation of Vapor Pressures
• Three types of estimation
– Clasius-Clapeyron Equation
– Antoine Equation
– Cox Diagrams
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Clasius-Clapeyron Equation
• This approach supposes “straight” equilibrium lines
Review Equilibrium Thermodynamics Course for Extra information in this topic
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Clasius-Clapeyron Equation
• This approach supposes “straight” equilibrium lines
Review Equilibrium Thermodynamics Course for Extra information in this topic
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Clasius-Clapeyron Equation
• This approach supposes “straight” equilibrium lines
“Straight line in intervals”
Review Equilibrium Thermodynamics Course for Extra information in this topic
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Clasius-Clapeyron Equation
• This approach supposes “straight” equilibrium lines
• dp/dT = slope of line
Review Equilibrium Thermodynamics Course for Extra information in this topic
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Clasius-Clapeyron Equation
• Vg-Vl = V^
• Substituting Ideal Gas Law
• Inverting Temperature axis (T 1/T)
• Logarithm of P-axis
• Suppose ΔH^v = cte.
Review Equilibrium Thermodynamics Course for Extra information in this topic
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Clasius-Clapeyron Equation
• Ln P* vs. 1/T graphs
• Straight line
• Slope = ΔH^v/R
• Y-Intersect = B
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Clasius-Clapeyron Equation
• P* = Vapor Pressure [mm Hg]
• ΔH^v = Heat of Vaporization [J/gmol]
• R = Ideal gas constant
• T = (K)
• B= Intersection of Y-Axis constant
• You now just need 2 points to get parameters: B, ΔHv
• 2 vapor pressure points (Pº, T)
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Clasius-Clapeyron Equation
• What is latent heat of vaporization?
– Required energy to transform a mol of “liquid” to a mol of “Vapor”
• ΔH^v = Heat of Vaporization [J/gmol]
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Clasius-Clapeyron EquationExercise 1
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Clasius-Clapeyron EquationExercise 1
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Antoine Equation
• Empirical equation
• Similar to Clasius-Clapeyron Eqn.
• A,B,C values can be found in tables!
• p* must be expressed in mm Hg
• T must be expressed in ºC NOT K!
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Antoine EquationExercise
• Calculate Pº of Acetone – @ T = 20 ºC
– @ T = 240 ºCLow Temp
High Temp
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Cox Diagrams
• Set of lines ending in Critical Points
• Y-axis typically Vapor pressure
• X-Axis typically Temperature of gas
• Recommended if using those set of substances
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Cox Diagrams
• Set of lines ending in Critical Points
• Y-axis typically Vapor pressure
• X-Axis typically Temperature of gas
• Recommended if using those set of substances
• Procedure:– Choose a Substance
– Specify either P or T… Cross a horizontal line if P, vertical if T.
– Cross it with the line of the substance
– Make a Vertical line (if you started with P) or a horizontal line (if you started with T).
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Cox DiagramsThis line marks the 14.7 psi (atmospheric) “Normal” Boiling Point of Substances
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• Go to www.ChemicalEngineeringGuy.com
• Section: Courses
– Mass Balance Course
• Problems Section
• You will find a problem index there…
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Gibbs Phase Rule
• The number of intensive variables that can be specified independently for a system at equilibrium:
• Π = Number of phases in the system
• c = Number of chemical Species
• DOF= Degrees of Freedom
• A system is completely stated if there are 0 DOF
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Gibbs Phase RuleExercise
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Gibbs Phase RuleExercise
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Gibbs Phase Rule Conclusion• Gibss Phase Rules is helpful to determine the variables in a
system
• In mixture systems, sometimes you need to “set” some variables
We “fixed” P = 1 atm We “fixed” C = 1 substance
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Gibbs Phase Rule Conclusion
• “Fixing” a property… P,V or T will reduce the 3-D chart to a 2-D chart (easier to read)
• Limitation only that Value of fixed variable (E.g. P= 1 atm, 1 m3)
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End of Section 1
• We´ve seen– Single Phase Theory (Phase-Diagrams)
• Pressure of substance (y-axis)
• Temperature of substance (x-axis)
• Phase Equilibrium Lines
• Critical Point
• Triple Point
• Phases
– Vapor Pressure
• Cox Diagrams
• Antoine Empirical Equation
• Clapyeron Theoretical Equation
– Gibbs Phase Rule
• Intensive Variables in a system
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Section 2
• Gas-Liquid Systems (1 condensable)– Only one substance condenses
– Evaporation, Drying, Humidity
– Examples: Air-Humidity
• Gas-Liquid Systems (multi-condensable)– Raoult Law
– Henry Law
– Dew/Bubble points
– Txy & Pxy Diagrams
– Examples: Ethanol-Water
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Gas-Liquid Systems: One Condensable
• Typical Example: Air+Humidity
• Air is non-condensable gas
• Humidity is a condensable vapor
• Typical operations:
– Evaporation
– Drying
– Humidification/dehumidification
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Gas-Liquid Systems: One Condensable
• Liquid Water + Dry Air @ 75ºC and 1 atm
– Initially Dry Air has no water (yw = 0)
– Then, water evaporates to Dry Air (yw =/ 0)
– There is a partial pressure of water in the system
• Pw = yw·P
– At one point, water stops to evaporate
– At this point, the Air-Water mixture is “Saturated”
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Gas-Liquid Systems: One Condensable
• Saturated system (DA+W):
– It contains all the water that system can hold at that temperature and pressure
• Saturated vapor (W):
– Water evaporated contained in this type of system
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Gas-Liquid Systems: One Condensable
• Apply Gibbs Phase Rule:– DOF= 2 + c - π = 2+2-2 = 2
– We need to set 2 variables!
• T, P and yw 3 variables
• If we set P (1 atm) and T (temperture) you will always be able to calculate yw
• If we set P (1 atm) and (yw) you will always have the same temperature for the desired system
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Raoult Law (Single Component)
• If only one component will condense with Temperature decrease…
• We may apply Raoult Law (for single component!)
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Raoult Law (Single ComponentExercise 1
From Raoult’s law:yw·P = P*yw = P* / P
From tables/data bases
yw = 289 mm Hg / 760 mm Hg = 0.38 gmol W / gmol mixyw = 0.38 gmol W / gmol mix
1 = yw + yda yda = 1- yw = 1- 0.38 = 0.62 gmol DA / gmol mix
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Dew/Bubble Point
• Dew Temperature: temperature at which a vapor becomes saturated (@ P = cte)
– The point at which the mix will start condensing
• Bubble Temperature: temperature at which a liquid becomes saturated (@ P = cte)
– The point at which the mix will start evaporating
• NOTE Dew Temp. = Bubble Temp. (#)
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Dew/Bubble Point
• Bubble you reach from liquid to vapor (blue)
• Dew you go from vapor to liquid (red)
@ P =cte = 1 atm
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Raoult Law (Single Component) MBExercise
1) DP = 90ºC … 100-90 = 10ºC
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Raoult Law (Single Component) MBExercise
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Raoult Law (Single Component) MBExercise
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Humidity Theory
• Types of Humidity/Saturation
– Relative
– Molal
– Absolute
• Psychometric Charts!
– Air and Humidity charts @ 1 atm
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Relative Saturation
• Compares Partial Pressure of Water vs. Vapor pressure of Water at that Temperature
• Typical for weather reports
• 40 % humidity; 80% humidity
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Molal Saturation (Humidity)
• Moles of Vapor per Moles of Dry-Air
• Example:
– Moles of W = 2 gmol of Water
– Moles of Air = 180 gmol of Dry Air
– 2/180 = 0.01 gmol of W / gmol of DA
• This is NOT mole Fraction
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Absolute Saturation (Humidity)
• Similar to Molal Saturation, compares mass of vapor to mass of Dry gas
• Example:– 0.05 kg of vapor
– 2 kg of dry air
– 0.05/2 = 0.025 kg of W / kg of DA
• This is NOT mass fraction of vapor in mixture!
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Humidity Theory
• Eventually, you should find either:
– Partial Pressure of Vapor
– Mole fraction of Vapor in mixture
• With these data you could start MB
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Saturation/HumidityExercise
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Saturation/HumidityExercise
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Saturation/HumidityExercise
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Psychometric Chart
• As seen before, the system of Dry Air and Humidity have 2 DOF
• T,P, yw Variables
• If we set P = 1 atm we would only need to define either T or yw
• A graph already exists! Its called Psychometric Chart and relates humidity and temperature of air
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Psychometric Chart
• We found the next variables
– Specific volume of dry air [m3/kg DA]
– Dry bulb temperature [ºC]
– Wet bulb temperature [ºC]
– Relative humidity [%]
– Absolute humidity [kg w / kg DA]
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How to read a Psychometric Chart
• We need:
– Set a Temperature (any)
• Dry
• Wet
– Set a Humidity (any)
• Relative
• Absolute
NOTE: Setting Specific Volume of DA indirectly sets a Temperature… WHY?
We need at least two:- 1 temp + 1 humid- 2 temp- 2 humid
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How to read a Psychometric ChartExercise
• What is the Relative humidity of a stream of air @ 30ºC and 0.007 kg of moisture per kg of DA
• Locate Temperature (x axis)
• Locate Absolute Humidity (y axis)
• Locate Relative Humidity (probably between two lines)
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How to read a Psychometric ChartExercise
• Between 20% and 30%
• Relative Humidity is Approx. 28%
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Dry Bulb Temperature
• Temperature of air measured by a thermometer freely exposed to the air but shielded from radiation and moisture
• Generally known as “THE” temperature of air.
• It is the true thermodynamic temperature
• Does not indicate the amount of moisture in the air
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Wet Bulb Temperature
• Temperature that air would have if it were cooled to saturation (100% relative humidity)– By evaporation of water
– Latent heat being supplied by air
• The lowest temperature that can be reached under current ambient conditions by the evaporation of water only
• Its determined by – Actual air temperature (dry-bulb temperature)
– Amount of moisture in the air (humidity).
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Dry/Wet Bulb Temperature
• Dry Bulb Thermometer has no add-ons
• Wet Bulb Thermometer has a “wet” coat so water may vaporize
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• Go to www.ChemicalEngineeringGuy.com
• Section: Courses
– Mass Balance Course
• Problems Section
• You will find a problem index there…
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Gas-Liquid: Multicomponent
• Processes which involve 2+ components in at least 2+ phases
• Typical processes
– Vapor-Liquid Distillation & Absorption
– Solid-Liquid Solutions (Crystallization)
– Liquid-Liquid Immiscible liquids (Extraction)
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Vapor-Liquid Equilibrium
• Best way to evaluate equilibriums Data
• If we got no data estimate
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Vapor-Liquid EquilibriumExercise 1
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Vapor-Liquid EquilibriumExercise 1
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Vapor-Liquid EquilibriumExercise 1
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Vapor-Liquid EquilibriumExercise 1
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Vapor-Liquid EquilibriumExercise 1
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Vapor-Liquid Equilibrium
• What if we got NO data?
• We need to apply some Laws– Raoult Law
– Henry Law
• These law help relate vapor pressures with concentrations (mole fractions) and constants
• Using Gibbs Rule– DF = 2 – c – π = 2 – 2 -2 = 2
– We need two variables!
2 phases2 substances
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Raoult Law
• If ideal solution (one that follows Roult Law)
– Xa 1 (A is almost pure)
• Then we can relate liquid phase with vapor phase:
• Note, if we set A, then B is fixed too WHY?
ya = mole fraction of A in vaporP = Total pressure of systemxa = mole fraction of A in liquidPaº(T) = Vapor Pressure of A
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Raoult Law
• Remember Raoult law for 1 condensable?
• This equation
• Reduces to
Xa = 1Ya = 1
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Henry Law
• Ha(T): Henry Constant
• Valid when Xa 0 (when it is dilute)
– Suppose no dissociation, ionization, reaction
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Raoult and Henry LawExercise
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Raoult and Henry LawExercise
Xb = Xt(equimolar)
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Raoult and Henry LawExercise
• Continue to solve for yb and P
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Raoult and Henry LawExercise
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Raoult and Henry LawExercise
• Substitute yb in P equation… you get P
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Dew/Bubble Point
• We’ve seen Dew and Bubble Temperatures
– Typical for Equilibrium Thermodynamics
– Calculating Temperature of the Dew Point
– Calculating Temperature of the Bubble Point
• Visit www.ChemicalEngineeringGuy.com/Courses
– Click on Courses Equilibrium Thermodynamics
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Graphical Representation:Vapor-Liquid Equilibrium
• We use diagrams to condense data:
– T x-y Diagrams: Temperature vs. compositions
– P x-y Diagrams: Pressure vs. compositions
• We use this on Binary Systems (A+B)
• If Txy fix P (generally 1 atm)
• If Pxy fix T (Temperature may vary)
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T x-y Diagrams
• Simplest form of T x-y Diagrams
• Y-axis: Temperature
• X-Axis: Mole Composition of A
• Vapor Region
• Liquid Region
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P x-y Diagrams
• Simplest form of P x-y Diagrams
• Y-axis: Pressure
• X-Axis: Mole Composition of A
• Vapor Region
• Liquid Region
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P x-y Diagrams
More Information of P xy and T xy Diagrams in Equilibrium Thermodynamics Course
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T x-y and P x-y DiagramsExercise 1
We don’t need P xy (WHY?)
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T x-y and P x-y DiagramsExercise 1
a) Temperature when boiling…
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T x-y and P x-y DiagramsExercise 1
T boiling approx= 86ºC
a) Temperature when boiling…
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T x-y and P x-y DiagramsExercise 1
Boiling @ T constant (WHY)
b) Final Composition?
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T x-y and P x-y DiagramsExercise 1
Boiling @ T constant (WHY)
b) Final Composition?
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T x-y and P x-y DiagramsExercise 1
Boiling @ T constant (WHY)
YB = 0.87
b) Final Composition?
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Need more Exercises & Problems?
• Go to www.ChemicalEngineeringGuy.com
• Section: Courses
– Mass Balance Course
• Problems Section
• You will find a problem index there…
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End of Section 2
• Section 2– Gas-Liquid Systems (1 condensable)
• Evaporation, Drying, Humidity• Theory of Humidity (absolute, molal, relative)• Raoult Law for 1 condensable specie• Psychometric Charts• MB with G-L (1) data
– Gas-Liquid Systems (multi-condensable)• Vapor-Liquid Equilibrium• Raoult Law• Henry Law• Txy & Pxy Diagrams• MB with G-L (2+) data
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Section 3
• Section 3
– Solid-Liquid Systems• Crystallization
– Solubility and Saturation
– Hydrated Salts
– Liquid-Liquid Systems• Miscibility and Extraction
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Solid-Liquid Systems
• MB processes Crystallization
– Solution, Solvent, Solute
– Solubility and Saturation
– Saturated and Supersaturated concepts
– Hydrated Salts
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Solubility
• Solubility of a solid in a liquid is the maximum amount of that substance that can be solved in a specific amount of liquid (in equilibrium)
• Varies for each type of substance
• Is Temperature Dependent
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Unsaturated Solution
• Unsaturated solution:
– is a chemical solution in which the solute concentration is lower than its equilibrium solubility.
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Saturated Solution
• Saturated solution:
– is the point at which a solution of a substance can dissolve no more of that substance and additional amounts of it will appear as a separate phase
Any more solute will stay as a solid
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Supersaturated Solution
• Supersaturated solution
– is a state of a solution that contains more of the dissolved material than could be dissolved by the solvent under normal circumstances.
Crystals form in a supersaturated solution
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Crystallization MBexercise 1
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Hydrated Salts
• Anhydrous salts: Water free salts
• Hydrated Salts: Salts + Hydrate
– Water molecules bon to the salt
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Hydrated SaltsExercise
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Hydrated SaltsExercise
60 kg K per 100 kg W
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Hydrated SaltsExercise
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Hydrated SaltsExercise
• See next diagram for solution
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Hydrated SaltsExercise
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Hydrated SaltsExercise
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Hydrated SaltsExercise
About 75ºC (Saturation Temp.)
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Need more Exercises & Problems?
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• Section: Courses
– Mass Balance Course
• Problems Section
• You will find a problem index there…
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Colligative Properties
• This topic is covered in
– Basic Chemistry Course
– Equilibrium Thermodynamics
• The scope of our course does not includes such material
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Liquid-Liquid Systems
• Miscibility and Immiscibility
• Partially miscible
• Liquid Extraction
• Distribution Coefficient
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Liquid-Liquid SystemsExtraction
• Miscibility
– property of substances to mix in all proportions, forming a homogeneous solution
– Miscible
– Partially Miscible
– Not Miscible
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Liquid-Liquid SystemsExtraction
• LLE consists in transferring one (or more) solute(s) contained in a feed solution to another immiscible liquid (solvent).
• The solvent that is enriched in solute(s) is called extract.
• The feed solution that is depleted in solute(s) is called raffinate.
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Liquid-Liquid SystemsExtraction
• Extraction
• Distribution Coefficient/Partition ratio
– Ralates transfer
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Liquid-Liquid SystemsExtraction
• In practice, extraction is often carried out in several consecutive stages.
• The solution leaves each stage and then goes to another additional solvent in the next stage
• Enough stages should be used to achieve almost a complete transfer of solute
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Liquid-Liquid SystemsExercise 1
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Liquid-Liquid SystemsExercise 1
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Liquid-Liquid SystemsExercise 1
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Liquid-Liquid SystemsExercise 1
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Liquid-Liquid SystemsExercise 1
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Liquid-Liquid SystemsExercise 1
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• Section: Courses
– Mass Balance Course
• Problems Section
• You will find a problem index there…
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End of Section 3
• Section 3
– Solid-Liquid Systems• Crystallization
– Solubility and Saturation
– Hydrated Salts
– Liquid-Liquid Systems• Miscibility and Extraction
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Problems & Exercises
• All pair problems of Elementary Principles in Chemical Processes. Felder, R; Rousseau, R. 3rd edition are solved in the next videos. (Chapter 6)
• Remember: practice makes the master
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Elementary Principles in Chemical Processes
What topics did we covered from the book?
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End of MB3: Multiple-Phase MB• You should be now able to perform MB with multiple phases
• Hopefully you are now able to:– Understand phases
– Calculate Vapor pressure and apply them in MB• Clasisus Clapeyron
• Antoine Equation
– Get to know the Vapor-Liquid equilibrium systems
– Use Raoult Law and Henry Law
– Understand the Solid-Liquid system
– Solve Liquid Liquid systems
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MORE INFORMATION
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