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MECH 5312 – Solid Mechanics IIme.utep.edu/cmstewart/documents/ME5312/Lecture 5...Principal Strain...

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MECH 5312 – Solid Mechanics II Dr. Calvin M. Stewart Department of Mechanical Engineering The University of Texas at El Paso
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  • MECH 5312 – Solid Mechanics IIDr. Calvin M. Stewart

    Department of Mechanical Engineering

    The University of Texas at El Paso

  • Table of Contents

    • Principal Strains

    • Strain Invariants

    • Volume Changes and Dilatation

    • Strain Deviator

  • Principal Strains

    • Principal stresses exists on an Arbitrary plane, n in a body where only normal stresses appear. Find two complementary planes that are orthogonal to n. We arrive at the principal stress tensor.

    • What form does the corresponding principal strain tensor take?

    1

    2

    3

    0 0

    0 0

    0 0

    σ

    1

    2

    3

    n

    n

    n

    1 2 3n n n

  • Principal Strain Tensor

    • Since, the principal stress tensor contains only normal stresses, the principal strain tensor will contain only normal strains.

    • Our procedure for finding the principal strains follows

    1

    2

    3

    0 0

    0 0

    0 0

    ε

    1

    2

    3

    n

    n

    n

    1 2 3n n n

  • Principal Strain

    • The principal directions coincide with Arbitrary plane, n through the body where the normal strain, εn is maximized and shear strain disappears, γ =0

    0

    0

    0

    xx n xy xz x

    yx yy n yz y

    zzx zy zz n

    n

    n

    n

    n ε I n 0

    2 2 2 1x y zn n n

  • Strain Invariants

    • The exact solution to the determinant

    • resolves into a quadratic equation

    • where J1, J2, and J3 are the strain Invariants.

    det 0n ε I

    3 2

    1 2 3 0n n nJ J J

    1

    2 2 2

    2

    3 det

    xx yy zz

    xx yy yy zz zz xx xy xz yz

    J tr

    J

    J

    ε

    ε

  • ExampleMathCAD

  • Volume Change and Dilatation

    • A differential element is subject to normal strain in the x direction

    • The length of the side increases by

    • The new length is now

    xx

    xxdx

    1 xx dx

    Example, for dx

    dx dx xxdx

    1 xx dx

  • Volume Change and Dilatation

    • If the differential element is subject to normal strains

    • The lengths of the sides increase by

    • The new lengths are now

    , , xx yy zz

    , , xx yy zzdx dy dz

    1 , 1 , 1xx yy zzdx dy dz

    dx

    1 1 1def xx yy zzV dxdydz

    The Deformed Volume, Vdef

    V dxdydz

    The Initial Volume, V

    dy

    dz

  • Volume Change and Dilatation

    • Assuming finite displacement, the change in volume becomes

    • The change in volume per unit volume is

    • where is the dilatation and

    0def xx yy zzV V V dxdydz

    xx yy zz

    V

    V

    1J

    V dxdydz

    Second order terms are neglected!

  • Strain Deviator

    • Strain can be decomposed into volumetric and deviatoric parts

    • The deviatoric strain can be found by rearranging

    1

    3d

    ε I ε

    1

    3d

    ε ε I

  • ExampleMathCAD

  • Calvin M. StewartAssistant ProfessorDepartment of Mechanical EngineeringThe University of Texas at El Paso500 W. University Blvd.Suite A126El Paso, Texas 79968-0717

    Email: [email protected]: http://me.utep.edu/cmstewart/Phone: 915-747-6179Fax: 915-747-5019

    Contact Information

    mailto:[email protected]://me.utep.edu/cmstewart/

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