Method of Joints | Analysis of Simple TrussesMethod of JointsThe free-body diagram of any joint is aconcurrent force systemin which the summation of moment will be of no help. Recall that only two equilibrium equations can be written and This means that to solve completely for the forces acting on a joint, we must select a joint with no more than two unknown forces involved. This can be started by selecting a joint acted on by only two members. We can assume any unknown member to be either tension or compression. If negative value is obtained, this means that the force is opposite in action to that of the assumed direction. Once the forces in one joint are determined, their effects on adjacent joints are known. We then continue solving on successive joints until all members have been found.Problem 001-mj | Method of JointsTop of FormProblemFind the force acting in all members of the truss shown in Figure T-01.

SolutionHideClick here to show or hide the solution

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Problem 002-mj | Method of JointsSPONSORED LINKSTop of FormProblem 002-mjThe structure in Fig. T-02 is a truss which is pinned to the floor at point A, and supported by a roller at point D. Determine the force to all members of the truss.

Solution 002-mjHideClick here to show or hide the solution

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FAB= 8.73 kN tensionFAG= 21.82 kN compressionFBC= 15.71 kN tensionFBF= 8.73 kN compressionFBG= 8.73 kN tensionFCD= 5.24 kN tensionFCE= 13.09 kN tensionFCF= 13.09 kN compressionFDE= 13.09 kN compressionFEF= 10.48 kN compressionFFG= 12.22 kN compressionBottom of Form- See more at: http://www.mathalino.com/reviewer/engineering-mechanics/problem-002-mj-method-joints#sthash.nWao6kQ9.dpufProblem 003-mj | Method of JointsSPONSORED LINKSTop of FormProblem 003-mjFind the force in each member of the truss shown in Fig. T-04.

Solution 003-mjHideClick here to show or hide the solutionAt joint C

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Top chordsFDE= 64 kN tensionFEF= 176 kN tensionBottom chordsFAB= 120 kN compressionFBC= 32 kN compressionWeb membersFAF= 140 kN tensionFAE= 150.78 kN compressionFBE= 150.78 kN tensionFBD= 86.16 kN compressionFCD= 86.16 kN tensionBottom of Form- See more at: http://www.mathalino.com/reviewer/engineering-mechanics/problem-003-mj-method-joints#sthash.dDWmMfac.dpufProblem 004-mj | Method of JointsSPONSORED LINKSTop of FormProblem 004-mjThe truss pinned to the floor at D, and supported by a roller at point A is loaded as shown in Fig. T-06. Determine the force in member CG.

Solution 004-mjHideClick here to show or hide the solution

At joint F

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answerAnother Solution to 004-mjHideClick here to show or hide the solution

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answerBottom of FormProblem 005-mj | Method of JointsSPONSORED LINKSTop of FormProblem 005-mjCompute the force in all members of the truss shown in Fig. T-08.

Solution 005-mjHideClick here to show or hide the solution

At joint A

At joint B

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Bottom of FormProblem 404 Roof Truss - Method of JointsSPONSORED LINKSTop of FormProblem 404Determine the forces in the members of the roof truss shown in Fig. P-404.

Solution 404HideClick here to show or hide the solution

At Joint A

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Check!SummaryAB = 450 N compressionAC = 389.71 N tensionBC = 450 N tensionBD = 900 N compressionCD = 389.71 N tensionBottom of Form