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Structural Analysis Method of Joints / Method of Pins Twenty.pdf · Structural Analysis Method of...

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1 Structural Analysis Method of Joints / Method of Pins In the air duct installers union they have lots of opportunity to vent. Wednesday, October 21, 2009 Method of Joints 2 Trusses Trusses are common means of transferring loads from their points of application to the supports They vary in design but their analysis always follows the same pattern Wednesday, October 21, 2009 Method of Joints 3 Tools Equations of equilibrium Free Body Diagrams Trig and algebra Visualization
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Page 1: Structural Analysis Method of Joints / Method of Pins Twenty.pdf · Structural Analysis Method of Joints / Method of Pins In#the#air#ductinstallers#union## they#have#lots#of#opportunity#to#vent.!

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Structural Analysis Method of Joints / Method of Pins

In  the  air  duct  installers  union    they  have  lots  of  opportunity  to  vent.  

Wednesday, October 21, 2009 Method of Joints 2

Trusses

 Trusses are common means of transferring loads from their points of application to the supports

 They vary in design but their analysis always follows the same pattern

Wednesday, October 21, 2009 Method of Joints 3

Tools

 Equations of equilibrium  Free Body Diagrams  Trig and algebra  Visualization

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Wednesday, October 21, 2009 Method of Joints 4

Trusses

 A simple truss analysis, which we will do in this class, does not consider the weight of the members which make up the truss

 A simple truss analysis considers that all loading is made at connections

 A simple truss analysis considers that all truss members are two-force members

Wednesday, October 21, 2009 Method of Joints 5

Trusses

 This means that we can break a truss down into a collection of elements for analysis

Wednesday, October 21, 2009 Method of Joints 6

Trusses

 An example truss

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Wednesday, October 21, 2009 Method of Joints 7

Trusses

 The red arrows are the loads (applied externally)

Wednesday, October 21, 2009 Method of Joints 8

Trusses

 The dark black lines are the members

Wednesday, October 21, 2009 Method of Joints 9

Trusses

 Each member goes from connection to connection

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Wednesday, October 21, 2009 Method of Joints 10

Trusses

 The black line along the bottom of the truss represents three separate members

Wednesday, October 21, 2009 Method of Joints 11

Trusses

 The support conditions are the pin at the left and the roller at the right

Wednesday, October 21, 2009 Method of Joints 12

Trusses

 At each intersection of two or more members, we consider that the members are pinned together

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Wednesday, October 21, 2009 Method of Joints 13

Trusses  For example, at the point labeled G on the

diagram, we have four members coming to a point connected by a single pin

Wednesday, October 21, 2009 Method of Joints 14

Trusses

 To simplify our analysis, we assign each connection point with a letter

Wednesday, October 21, 2009 Method of Joints 15

Trusses   I avoid using F and I as connection point

assignments but your text does not

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Wednesday, October 21, 2009 Method of Joints 16

Trusses  Pick a starting point and label each connection, I

chose to start at the lower left and move across the top and then across the bottom

Wednesday, October 21, 2009 Method of Joints 17

Trusses  Each of the members can now be labeled using

the points of connection

Wednesday, October 21, 2009 Method of Joints 18

Trusses   In this truss we have the following members: AB,

BC, CD, DE, CE, CG, EG, BG, and AG

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Wednesday, October 21, 2009 Method of Joints 19

Trusses  The order of the letters is not important, I choose

to put them in the order they appear in the alphabet

Wednesday, October 21, 2009 Method of Joints 20

Method of Joints  To begin the analysis of the truss using this

method, we start by identifying all external forces acting on the truss

Wednesday, October 21, 2009 Method of Joints 21

Method of Joints   In this case it would be the forces represented by

the red lines  The forces (loads) must always be applied at the

connections (joints)

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Wednesday, October 21, 2009 Method of Joints 22

Method of Joints

 This is usually given in the problem

Wednesday, October 21, 2009 Method of Joints 23

Method of Joints  Then we remove any supports and replace them

with reactions provided by the supports

Wednesday, October 21, 2009 Method of Joints 24

Method of Joints  We have a pin at the left so we will have an x

and a y reaction

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Wednesday, October 21, 2009 Method of Joints 25

Method of Joints  And we have a roller at the right so we only have

a y reaction

Wednesday, October 21, 2009 Method of Joints 26

Method of Joints  We are also usually given the dimensions and

geometry of the truss in the given

Wednesday, October 21, 2009 Method of Joints 27

Method of Joints  Now we can solve for the reactions at the

supports using the methods developed previously

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Wednesday, October 21, 2009 Method of Joints 28

Method of Joints  We will use the entire truss as the FBD and

ignore the internal members (for the moment)

Wednesday, October 21, 2009 Method of Joints 29

Method of Joints  Summing forces in the x-direction

Wednesday, October 21, 2009 Method of Joints 30

Method of Joints  Summing moments about D

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Wednesday, October 21, 2009 Method of Joints 31

Method of Joints  Summing forces in the y-direction

Wednesday, October 21, 2009 Method of Joints 32

Method of Joints

 Redrawing our system with the known reactions, we have

Wednesday, October 21, 2009 Method of Joints 33

Method of Joints  Now for the problems that we had done earlier,

we would be finished

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Wednesday, October 21, 2009 Method of Joints 34

Method of Joints   In a truss analysis, we want to know what force

is being carried in each of the members

Wednesday, October 21, 2009 Method of Joints 35

Method of Joints

 Each member of the truss can be in one of three conditions:   It can be in COMPRESSION, that means that it

will be pushing on each end where it is connected

  It can be in TENSION, that means that it will be pulling on each end where it is connected

  It can have no force in the member

Wednesday, October 21, 2009 Method of Joints 36

Method of Joints

  In the method of joints, we are going to assume the condition of each of the members,

  draw a free body diagram of the connection points, and

  apply two of our three equilibrium conditions to solve for the force actually in the members

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Wednesday, October 21, 2009 Method of Joints 37

Method of Joints

 When we used a pin connection previously, we used an x and a y reaction to show what was being provided by the pin

 Here we are actually drawing a FBD of the pin itself and showing the forces from the members onto the pin itself

Wednesday, October 21, 2009 Method of Joints 38

Method of Joints

 You can assume any condition that you want for the members, I usually choose to assume that they are all in either tension or compression and then let the signs of the solutions dictate their actual condition

Wednesday, October 21, 2009 Method of Joints 39

Method of Joints

 Since we can only use two of the equations of equilibrium, the sum of the forces in the x and the sum of the forces in the y direction, our analysis pattern will be dictated by the makeup of the truss itself

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Wednesday, October 21, 2009 Method of Joints 40

Method of Joints

 First, we can look at all the forces acting on each pin of the truss

  It is critical to the analysis that you do not exclude either external forces or support reactions at each pin

Wednesday, October 21, 2009 Method of Joints 41

Method of Joints

  If a member is pushing on a pin at one end, it is always pushing on the pin at its other end

Wednesday, October 21, 2009 Method of Joints 42

Method of Joints

 Conversely, if a member is pulling at a pin on one end, it is pulling on the pin at its other end

 Never push pull!

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Wednesday, October 21, 2009 Method of Joints 43

Method of Joints

 At any joint, you can only solve for two unknowns!!!!

Wednesday, October 21, 2009 Method of Joints 44

Method of Joints

 Now to decide where to start the analysis, we need to find a joint where there are only two unknowns

Wednesday, October 21, 2009 Method of Joints 45

Method of Joints

  In our case, the pins at A and at D both only have two unknowns, so we can start at either point

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Wednesday, October 21, 2009 Method of Joints 46

Method of Joints

  If you thought that there were three unknowns at A and D because of ABx and ABy, remember that the force in the member has a line of action along the member

Wednesday, October 21, 2009 Method of Joints 47

Method of Joints

 We choose A to start our analysis  We now draw a FBD of the pin at A

Wednesday, October 21, 2009 Method of Joints 48

Method of Joints

  I always assume that the members are in compression so our FBD would look like

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Wednesday, October 21, 2009 Method of Joints 49

Method of Joints

 Since I assume compression, the forces in the members are pushing on the connection (pin)

Wednesday, October 21, 2009 Method of Joints 50

Method of Joints

 Now we can use our two equilibrium conditions to solve for the forces in the members

Wednesday, October 21, 2009 Method of Joints 51

Method of Joints

 We report all the magnitudes of the forces as positive numbers and the forces themselves as either compression or tension

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Wednesday, October 21, 2009 Method of Joints 52

Method of Joints

 Solving for AG

Wednesday, October 21, 2009 Method of Joints 53

Method of Joints

 Now that AB and AB are known forces, we can revisit the FBD of the complete truss and find another joint/pin that has only two unknowns

Wednesday, October 21, 2009 Method of Joints 54

Method of Joints

 Usually this will be adjoining the pin that we just solved for

 For this truss it could be either pin B or G

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Wednesday, October 21, 2009 Method of Joints 55

Method of Joints

 At G, we have BG, CG, and EG as unknowns  Three unknowns, so this pin won’t work

Wednesday, October 21, 2009 Method of Joints 56

Method of Joints

 At B, we have two unknowns, BC, and BG  We can proceed to work at BG

Wednesday, October 21, 2009 Method of Joints 57

Method of Joints

 We draw a FBD of the pin at B

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Wednesday, October 21, 2009 Method of Joints 58

Method of Joints

 We know that AB is in compression, so we are not making an assumption about AB

Wednesday, October 21, 2009 Method of Joints 59

Method of Joints

 We are assuming that BC and BG are in compression for this FBD

Wednesday, October 21, 2009 Method of Joints 60

Method of Joints

 Now we use our conditions of equilibrium to solve for BC and BG

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Wednesday, October 21, 2009 Method of Joints 61

Method of Joints

 Now we use our conditions of equilibrium to solve for BC and BG

Wednesday, October 21, 2009 Method of Joints 62

Method of Joints

 You might be asking yourself why BG is even included in the truss

 This is a very preliminary analysis of one loading condition, there is actually much more to truss design than this

Wednesday, October 21, 2009 Method of Joints 63

Method of Joints

 Now we could go to either joint C or joint G  At C, we have CG, CE, and CD as unknowns  At G, we have CG and EG  Our next point is G

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Wednesday, October 21, 2009 Method of Joints 64

Method of Joints

 The FBD at G  Notice that we have drawn AG as a tension

member, we know that from our earlier solution, it is no longer an assumption

Wednesday, October 21, 2009 Method of Joints 65

Method of Joints

 We also have no longer included the force from BG, we know that it carries no force under there loading conditions

Wednesday, October 21, 2009 Method of Joints 66

Method of Joints

 Using our equilibrium conditions

Page 23: Structural Analysis Method of Joints / Method of Pins Twenty.pdf · Structural Analysis Method of Joints / Method of Pins In#the#air#ductinstallers#union## they#have#lots#of#opportunity#to#vent.!

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Wednesday, October 21, 2009 Method of Joints 67

Method of Joints

 Using our equilibrium conditions

Wednesday, October 21, 2009 Method of Joints 68

Method of Joints

  You can continue on with the pattern until all the members in the truss are solved for

  You will always have one extra pin/joint available after all the members in the truss have been solved

  Check the sum of the forces in the x and y direction at that point to see if the truss closes


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