+ All Categories
Home > Documents > Ppt Phy10 Wk07 Newtons Laws 2

Ppt Phy10 Wk07 Newtons Laws 2

Date post: 11-Jan-2016
Category:
Upload: jed-efraim-espanillo
View: 219 times
Download: 0 times
Share this document with a friend
Description:
newtons law of motion
Popular Tags:
12
FIRST CONDITION OF EQUILIBRIUM FIRST CONDITION OF EQUILIBRIUM STATIC AND DYNAMIC EQUILIBRIUM STATIC AND DYNAMIC EQUILIBRIUM KINDS OF FORCES KINDS OF FORCES FREE-BODY DIAGRAMS FREE-BODY DIAGRAMS SUGGESTED STEPS IN SOLVING PROBLEMS SUGGESTED STEPS IN SOLVING PROBLEMS NEWTON’S LAWS OF MOTION
Transcript
Page 1: Ppt Phy10 Wk07 Newtons Laws 2

• FIRST CONDITION OF EQUILIBRIUMFIRST CONDITION OF EQUILIBRIUM• STATIC AND DYNAMIC EQUILIBRIUM STATIC AND DYNAMIC EQUILIBRIUM • KINDS OF FORCESKINDS OF FORCES• FREE-BODY DIAGRAMS FREE-BODY DIAGRAMS • SUGGESTED STEPS IN SOLVING PROBLEMSSUGGESTED STEPS IN SOLVING PROBLEMS

NEWTON’S LAWS OF MOTION

Page 2: Ppt Phy10 Wk07 Newtons Laws 2

NEWTON’S LAWS OF MOTION

NEWTON’S FIRST LAW An object sitting at rest will remain at rest if the sum of all forces acting on the object is zero. Similarly, if an object is moving and the sum of the forces acting on the object is zero, then the object will continue to move in the same direction with same speed, therefore, in Equilibrium.

ΣF = 0

Page 3: Ppt Phy10 Wk07 Newtons Laws 2

First Condition of EquilibriumThe body or system at this condition remains at rest or moves in a straight line with constant velocity. (Translational Equilibrium)Types:

a)Static Equilibrium – refers to all objects or systems at rest

b)Dynamic Equilibrium - refers to all objects / systems moving at constant velocity

Note: graphically all forces forms a closed polygon

ΣF = 0 ; ΣFX=0 ; ΣFY = 0 : R = 0

Page 4: Ppt Phy10 Wk07 Newtons Laws 2

NEWTON’S LAWS OF MOTIONNEWTON’S SECOND LAW If a net external force acts on a body, the body accelerates. The direction of acceleration is the same as the direction of the net force. The mass of the body times the acceleration of the body equals the net force vector.

In Symbols,

By Components;

Page 5: Ppt Phy10 Wk07 Newtons Laws 2

NEWTON’S LAWS OF MOTIONNEWTON’S THIRD LAW If body A exerts a force on body B ( an “action”), then body B exerts a force on body A ( a “reaction”). These two forces have the same magnitude but are opposite in direction. These two forces act on different bodies.

Page 6: Ppt Phy10 Wk07 Newtons Laws 2

What is a Force?

Page 7: Ppt Phy10 Wk07 Newtons Laws 2

Unit of a Force

*One newton is the amount of net force that gives an acceleration of 1meter per second squared to a body with a mass of 1 kilogram.

Relationship Between Mass & Weight

Page 8: Ppt Phy10 Wk07 Newtons Laws 2

Kinds of Forces1.Weight, W – force due to earth’s gravitational attraction which is always acting from the center of gravity (c.g.) downward.

2. Tension , T – a pulling force exerted on an object by a rope, cord, cables, etc.

Page 9: Ppt Phy10 Wk07 Newtons Laws 2

3.Compression, C – a push applied to a body using a rod, bar, mast, etc. (directed towards the body or point being considered)

4. Normal Force, N– when an object rests or pushes on a surface, the surface exerts a push on it that is directed perpendicular to the surface

Kinds of Forces

Page 10: Ppt Phy10 Wk07 Newtons Laws 2

5. Friction Force, f – force acting between the body and its surface of contact which is parallel but opposite to the direction of motion.

Kinds of Forces

Page 11: Ppt Phy10 Wk07 Newtons Laws 2

Types of Friction:1. Static Friction, fs – exists when the body is at

rest but has the tendency to slide.2. Kinetic Friction, fk – opposing force when

the body is in motion.

where: f- friction force n- normal force μ – coefficient of friction

f α n or f = μ n

Page 12: Ppt Phy10 Wk07 Newtons Laws 2

Steps in Solving Problems:Make a diagram of the whole structure

being considered.Draw a separate force diagram / Free –

Body Diagram, FBD FBD – is one part of the whole

structure on which known and unknown forces act. (Point of concurrency )

Super impose x and y axis on FBD.

Apply ΣF =0 -[for system / body in equilibrium]

ΣF = ma -[for system / body with acceleration]


Recommended