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• Make sure that students bubble in their answers for the front page (#1-7) and the back page (#8-14). The bubbles allow students to check their answers and results in a more confident student. In addition, it makes it a lot easier for you to do a quick “checking for understanding” when you have the answer key and can compare the bubbles shaded in.

• Make sure that students show their work! Space is given so that students can demonstrate their knowledge of the concept. I do not give students credit if they do not show their work. Also, students need to give a nice reflection (2-3 sentences)!

• You can decide if you want to use the score in the top left.

• If you have any questions or concerns, please email me at mathindemand@hotmail.com.

© 2017 Math in Demand

Volume: Cone, Cylinder, & Sphere

Worksheet Practice

Score (__/__)

Directions: Determine the volume of each cone, cylinder, and sphere. Use 𝜋 = 3.14 and round your answers to the nearest tenths. Show all your work!

2 3 4

5 6 7

6 ft

6 ft

6.3 ft 2 ft 8 ft

2 ft

1

Answers Bubble in your answers below

for problems #1-7.

1440.0 ft3

25.1 ft3

3,050.1 ft3

100.5 ft3

27.2 ft3

167.8 ft3

1,436.0 ft3

167.5 ft3

2,390.1 ft3

25.5 ft3

904.3 ft3

101.0 ft3

2,388.0 ft3

3,052.1 ft3

18 ft

10 ft

10.8 ft

8 ft

18 ft 13 ft 7 ft

Name: ___________________

Date: ________

Period: ___

12 13 14

Reflection: From this activity, I learned…

9 10 11 8

© 2017 Math in Demand

Answers Bubble in your answers below

for problems #8-14.

126.6 ft3

523.3 ft3

395.2 ft3

1,149.8 ft3

128.5 ft3

1,356.5 ft3

520.3 ft3

1,355.5 ft3

1,150 ft3

2,302.7 ft3

1,696.6 ft3

1,695.6 ft3

390.3 ft3

392.5 ft3

22 ft

24.2 ft 10 ft

12 ft 6 ft

13 ft

20 ft

22 ft

18 ft

Determine the volume of a sphere with a diameter of 10ft.

Determine the volume of a cone with a radius of 5.5ft and height of 4ft.

Determine the volume of a cylinder with a diameter of 10ft and height of 5ft.

© 2017 Math in Demand

Volume: Cone, Cylinder, & Sphere

Worksheet Practice

Score (__/__)

Directions: Determine the volume of each cone, cylinder, and sphere. Use 𝜋 = 3.14 and round your answers to the nearest tenths. Show all your work!

2 3 4

5 6 7

6 ft

V = 4

3πr3

V = 4

3π(6ft)3

V = 4

3∙π∙216 = 288π

V = 904.32 ≈ 904.3 ft3

6 ft

6.3 ft 2 ft 8 ft

2 ft

V = πr2h V = π(2ft)2(8ft) V = 32π V = 100.48 ≈ 100.5 ft3

V = 1

3πr2h

V = 1

3π(2ft)2(6ft)

V = 8π V = 25.12 ≈ 25.1 ft3

1

Answers Bubble in your answers below

for problems #1-7.

1440.0 ft3

25.1 ft3

3,050.1 ft3

100.5 ft3

27.2 ft3

167.8 ft3

1,436.0 ft3

167.5 ft3

2,390.1 ft3

25.5 ft3

904.3 ft3

101.0 ft3

2,388.0 ft3

3,052.1 ft3

18 ft

10 ft

10.8 ft

8 ft

18 ft 13 ft 7 ft

V = 4

3πr3

V = 4

3π(9ft)3

V = 4

3∙π∙729 = 972π

V = 3,052.08 ≈ 3,052.1 ft3

V = 4

3πr3

V = 4

3π(7ft)3

V = 4

3∙π∙343 = 457.3̅π

V = 1,436.026̅ ≈ 1,436.0 ft3

V = 1

3πr2h

V = 1

3π(4ft)2(10ft)

V = 53.3̅π V = 167.46̅ ≈ 167.5 ft3

V = πr2h V = π(6.5ft)2(18ft) V = 760.5π V = 2,387.97 ≈ 2,388.0 ft3

12 13 14

Reflection: From this activity, I learned…

Answers will vary!

9 10 11 8

© 2017 Math in Demand

Answers Bubble in your answers below

for problems #8-14.

126.6 ft3

523.3 ft3

395.2 ft3

1,149.8 ft3

128.5 ft3

1,356.5 ft3

520.3 ft3

1,355.5 ft3

1,150 ft3

2,302.7 ft3

1,696.6 ft3

1,695.6 ft3

390.3 ft3

392.5 ft3

22 ft

24.2 ft 10 ft

12 ft 6 ft

13 ft

20 ft

22 ft

18 ft

Determine the volume of a sphere with a diameter of 10ft.

Determine the volume of a cone with a radius of 5.5ft and height of 4ft.

Determine the volume of a cylinder with a diameter of 10ft and height of 5ft.

V = 4

3πr3

V = 4

3π(5ft)3

V = 4

3∙π∙125 = 166.6̅π

V = 523.3̅ ≈ 523.3 ft3

V = 1

3πr2h

V = 1

3π(10ft)2(22ft)

V = 733.3̅π V = 2,302.6̅ ≈ 2,302.7 ft3

V = πr2h V = π(6ft)2(12ft) V = 432π V = 1,356.48 ≈ 1,356.5 ft3

V = 4

3πr3

V = 4

3π(6.5ft)3

V = 4

3∙π∙274.625 = 366.16̅π

V = 1,149.76 ≈ 1,149.8ft3

V = 1

3πr2h

V = 1

3π(9ft)2(20ft)

V = 540π V = 1,695.6 ≈ 1,695.6 ft3

V = 1

3πr2h

V = 1

3π(5.5ft)2(4ft)

V = 40.3̅π V = 126.646̅ ≈ 126.6 ft3

V = πr2h V = π(5ft)2(5ft) V = 125π V = 392.5 ft3

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