4/30/16, 7:15 AMPrint Test
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PRINTABLE VERSIONQuiz 24
You scored 0 out of 100Question 1
You did not answer the question.Express the curve by an equation in and given .
a)
b)
c)
d)
e)
Question 2
You did not answer the question.Express the curve by an equation in and given .
a)
b)
c)
d)
e)
Question 3
You did not answer the question.
x y x(t) = and y(t) = 2 + 4t 2 t 4
x = 4 + 5, y ≥ 0y2
x = 4 + 3, y ≥ 0y2
y = 2 + 3, x ≥ 0x2
y = + 4, x ≥ 0x2
y = 2 + 4, x ≥ 0x2
x y x(t) = cos(t) and y(t) = 5 sin(t)
− 25 = 25x2 y2
25 + = 25x2 y2
25 + = 5x2 y2
+ 25 = 25x2 y2
25 − = 5x2 y2
x(t) = (t) + 2 and y(t) = 5 + tan(t)2
4/30/16, 7:15 AMPrint Test
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Express the curve by an equation in and given .
a)
b)
c)
d)
e)
Question 4
You did not answer the question.Express the curve by an equation in and given .
a)
b)
c)
d)
e)
Question 5
You did not answer the question.Express the curve by an equation in and given .
a)
b)
c)
d)
x y x(t) = (t) + 2 and y(t) = 5 + tan(t)sec2
x = + 2(y − 5)2
y = + 3(x − 5)2
x = + 3(y − 5)2
y = + 2(x − 5)2
x = + 1(y + 5)2
x y x(t) = sin(t) and y(t) = 9 + (t)cos2
− + y = 10, −9 ≤ x ≤ 9x2
+ x = 10, 0 ≤ x ≤ 1y2
+ y = 9, −1 ≤ x ≤ 1x2
+ y = 10, −1 ≤ x ≤ 1x2
− + x = 9, −9 ≤ x ≤ 9y2
x y x(t) = and y(t) = 5 −et e3 t
+ y = 5, x > 0x3
− + y = 6, 0 ≤ x ≤ 5x4
+ x = 5, x > 0y3
− + y = 5, x ≥ 1x3
4/30/16, 7:15 AMPrint Test
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e)
Question 6
You did not answer the question.
Express the curve by an equation in and given and identify the correct
sketch of the curve.
a) ;
− + x = 5, 0 ≤ x ≤ 1y3
x y ( , ), t ∈ (0, 1]1t
2t 2
y = 2 x2
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b) ;
c) ;
y = 2 x−2
y = 2 x−1
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d) ;
e) ;
y = 2 x2
y = −2 x2
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Question 7
You did not answer the question.
Give a parameterization for the ellipse that begins at the point (3,0) and traversesonce in a counterclockwise manner.
a)
b)
c)
d)
e)
Question 8
You did not answer the question.Find a parametrization for the line segment from .
a)
b)
c)
d)
e)
Question 9
You did not answer the question.Find a parametrization for the line segment from .
a)
b)
16 + 9 = 144x2 y2
x(t) = 4 cos(t), y(t) = 3 sin(t), t ∈ [0, 2π]
x(t) = 16 cos(t), y(t) = 9 sin(t), t ∈ [0, 2π]
x(t) = 9 sin(t), y(t) = 16 cos(t), t ∈ [0, 2π]
x(t) = 3 cos(t), y(t) = 4 sin(t), t ∈ [0, 2π]
x(t) = 4 sin(t), y(t) = 3 cos(t), t ∈ [0, 2π]
x = x(t), y = y(t), t ∈ [0, 1] (−8, −2) to (5, 8)
x(t) = 13 t − 8, y(t) = 10 t − 2
x(t) = 13 t − 8, y(t) = −2 + 11 t
x(t) = −8 − 14 t, y(t) = 10 t − 2
x(t) = −10 t − 8, y(t) = −13 t − 2
x(t) = −13 t − 8, y(t) = −10 t − 2
x = x(t), y = y(t), t ∈ [0, 1] (−5, −3) to (−7, −3)
x(t) = −5, y(t) = 2 t − 3
x(t) = −2 t − 5, y(t) = −3
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c)
d)
e)
Question 10
You did not answer the question.Find a parametrization for from .
a)
b)
c)
d)
e)
x(t) = 2 t − 5, y(t) = 0
x(t) = −5 + t, y(t) = −3
x(t) = −2 t − 5, y(t) = −3 + t
x = x(t), y = y(t) f (x) = − 8 − 9x8 x2 (9, −10) to (10, −8)
x(t) = − 8 − 9, y(t) = t, t ∈ [9, 10]t 8 t 2
x(t) = − 8 , y(t) = −9, t ∈ [9, 10]t 8 t 2
x(t) = , y(t) = − 8 t − 9, t ∈ [81, 100]t 2 t 4
x(t) = t, y(t) = − 8 − 9, t ∈ [9, 10]t 8 t 2
x(t) = − 8 − 9, y(t) = t, t ∈ [−10, −8]t 8 t 2