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Problem 15.Problem 15.
Optical Optical TunnellingTunnelling
ProblemProblem
Take two glass prisms separated by a Take two glass prisms separated by a small gap. Investigate under what small gap. Investigate under what conditions light incident at angles conditions light incident at angles greater than the critical angle is not greater than the critical angle is not totally internally reflected.totally internally reflected.
Experiment Experiment • Two measurement ranges:Two measurement ranges:
• Centimeter waves – accurate Centimeter waves – accurate measuringmeasuring
• Visile light – obtaining the effectVisile light – obtaining the effect
• Parameters:Parameters:• Waveelngth of the light usedWaveelngth of the light used• Refraction index of prisms and Refraction index of prisms and
medium in the gapmedium in the gap• Polarization Polarization • Distance between prismsDistance between prisms
1. Centimeter waves 1. Centimeter waves
• Wavelength: 3 cmWavelength: 3 cm• Polarization: linear, electrical field Polarization: linear, electrical field
perpendicular to plane of propagationperpendicular to plane of propagation• Prism refraction index: 1.5 (paraffin)Prism refraction index: 1.5 (paraffin)• Measurements:Measurements:
• Intensity of tunneled wavesIntensity of tunneled waves• Intenzity of reflected wavesIntenzity of reflected waves
in dependence on prism distancein dependence on prism distance
• Measured – voltage in the detectorMeasured – voltage in the detector• Voltage – proportional to field!Voltage – proportional to field!
Centimeter waves Centimeter waves cont.cont.
• Apparatus schematic:Apparatus schematic:
2,78Izvor
Senzor
multimetermultimeter
Translation Translation systemsystem
Radiation Radiation sourcesource
detectordetector
Centimeter waves Centimeter waves cont.cont.
Centimeter waves Centimeter waves cont.cont.
distance [cm]
0 2 4 6 8 10 12
volta
ge [V
]
0,00
0,02
0,04
0,06
0,08
0,10
Tunelled field:Tunelled field:
d
eUU
0
2. Visible light2. Visible light• Wavelenght: 780 nmWavelenght: 780 nm• Polarization: linearPolarization: linear
• electric field perpendicular to plane electric field perpendicular to plane of propagationof propagation
• Prism index of refraction: 1.48 Prism index of refraction: 1.48 (measured)(measured)
• Measurements:Measurements:• Intensity of tunneled wavesIntensity of tunneled waves• Intensity of reflected wavesIntensity of reflected waves
• Intensity measurement: photodiodeIntensity measurement: photodiode
• Voltage – proportional to square of field!Voltage – proportional to square of field!
2. Visible light2. Visible light
• Measurement in timeMeasurement in time• A slow motor (0.5 r/min) moves A slow motor (0.5 r/min) moves
the translatorthe translator• Voltage sampling at the diode Voltage sampling at the diode
every 1/50 of a secondevery 1/50 of a second• The signal grows in timeThe signal grows in time• Change of prism distance:Change of prism distance:
vtd v – translator speed
t – elapsed time
Visible light Visible light cont.cont.
• Apparatus schematic:Apparatus schematic:
3,15
3,15
Slow motor + Slow motor + translationtranslationlaserlaser
prismsprisms
oscilloscopeoscilloscope
Data Data receiving receiving computercomputer
Visible light Visible light cont.cont.
time [s]
0,6 0,7 0,8 0,9 1,0 1,1
inte
nsity
[arb
itrar
y un
its]
0,11
0,12
0,13
0,14
0,15
0,16
0,17
vt
eUU
0
Explanation Explanation
Electromagnetic waves in dielectrics – Electromagnetic waves in dielectrics – the resultant of interference of the the resultant of interference of the initial wave and all scattered wavesinitial wave and all scattered waves
• Huygens principle:Huygens principle:
Every atom ˝through˝ which light Every atom ˝through˝ which light passes is a source of light identical to passes is a source of light identical to the incident lightthe incident light
Explanation Explanation cont.cont.
• At total reflection – the reflected ray is At total reflection – the reflected ray is the only interference maximumthe only interference maximum
• Behind the reflection plane – Behind the reflection plane – destructive interference, but only destructive interference, but only far far awayaway from the plane from the plane
• Close to the plane (distances of the Close to the plane (distances of the order of the wavelength) the waves order of the wavelength) the waves haven’t interfered completely and a haven’t interfered completely and a decaying field existsdecaying field exists
Explanation Explanation cont.cont.
• That field decays fast due to That field decays fast due to interferenceinterference
• If a prism is put into the field – a new If a prism is put into the field – a new interference maximum can be formed interference maximum can be formed in the prismin the prism
• A new, tunnelled wave is formed in A new, tunnelled wave is formed in the prismthe prism
• The energy of the reflected wave The energy of the reflected wave becomes smallerbecomes smaller
Maxwell equations Maxwell equations
PE 0
1
t
B
E
0B
ttc
EP
B0
2 1
E – electric field
B – magnetic field induction
P – polarization
c – speed of light in a vacuum
ε0 – vacuum permittivity
Plane wave solutions Plane wave solutions
Electrical field:Electrical field:
krEE tie 0
E0 – amplitude
ω – frequency
t – time
k – wave vector
r - radiusvector
Magnetic field:Magnetic field:
EkB 1
Geometry of the Geometry of the problem problem
x
y
k1
krkt'
E1
Er Et'
d
φ
φ
Incident waveIncident wave
Reflected Reflected wavewave
Tunnelled Tunnelled wavewave
Prism 1Prism 1 Prism 2Prism 2
nn11nn00 nn00
Boundary conditionsBoundary conditions
• If the electric field is perpendicular If the electric field is perpendicular to the wave vector plane:to the wave vector plane:
0010 tr EEE
00101 ttxrrxx EkEkEk
E10, Er0, Et0– amplitudes of the incident, reflected and transmitted wavesk1x, krx, ktx– x components
of the wave vectors of the incident, reflected and transmitted waves
Boundary conditions Boundary conditions cont.cont.
• For the wave vectors:For the wave vectors:
yty kk 1
21
21
2
0
12ytx kk
n
nk
k1y, kty– y components of the incident and transmitted wave vectors
n0 – prism index of refraction
n1 – medium between prisms index of refraction
Solution Solution
• If the incident angle is greater than If the incident angle is greater than the reflection angle, Snell’s law givesthe reflection angle, Snell’s law gives
• xx – component of the wave vector is a – component of the wave vector is a pure imaginary => the wave pure imaginary => the wave propagates along the planepropagates along the plane
=> the => the amplitude decays amplitude decays exponentiallyexponentially
φ – incident angle1sin22
1
0
0
11
n
n
n
nikktx
Solution Solution cont.cont.
• The field in the second prism:The field in the second prism:
d
n
ndn
t eEeEE
10
1sin2
10
22
1
01
'
d – prism distance
λ – vacuum wavelegth of incident light
Θ – decay coefficient
Comparation – Comparation – decay coefficientdecay coefficient
• Centimeter waves:Centimeter waves:
• Optical range:Optical range:
Experimental 2.5±0.1
Theoretical 2.22
Experimental 1.1±0.1
Theoretical 1.94
ComparationComparation cont.cont.
• Agreement is relatively goodAgreement is relatively good
• Error causes:Error causes:
• Imprecise prism refraction Imprecise prism refraction index valuesindex values
• In optical range: In optical range:
• Prism surface defects and Prism surface defects and dustdust
• Motor precision ...Motor precision ...
Conclusion Conclusion
• We have obtained, measured and We have obtained, measured and modelled optical tunnellingmodelled optical tunnelling
• It may be said:It may be said:
The only condition for light incident on a The only condition for light incident on a prism plane with an angle greater than the prism plane with an angle greater than the critical angle not reflecting completely is to critical angle not reflecting completely is to put another prism plane next to the original put another prism plane next to the original plane to a distance of the order of the plane to a distance of the order of the wavelength usedwavelength used