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International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
43 HITESH SHARMA, GOVERDHAN, S.V.DEO
REINFORCED CONCRETE DESIGN
WITH F.R.P COMPOSITES
HITESH SHARMA, GOVERDHAN, S.V.DEO
N.I.T RAIPUR CHHATTIGRAH INDIA
ABSTRACT-: The first two failure mechanisms occur after large deflection of the member and are
synonyms of better structural performance. In the case of FRP rupture the main steel reinforcement is
fast yielding. Moreover, from an economical point of view the rupture of FRP plate seems to be
desirable because it means that all the mechanical resources of FRP (an expensive material) are
utilized. The third and fourth failure mechanisms are brittle and occur at values of the applied load
lower than expected with conventional design equations. In both cases, the stiffening or
strengthening resources of the FRP plate are of little advantage. Anchoring the FRP plate ends, not
applicable to slabs, may attain a higher ultimate load and an increase in ductility.
Keywords-: fiber, reinforced concrete, shear strength, flexural strength
INTRODUCTION
The two main failure modes of reinforced concrete (RC) beams are governed by flexural and shear.
Flexural failure of an RC beam is ductile in nature whereas shear failure has a catastrophic effect
when an RC beam is deficient in shear strength and is over loaded shear failure may occur suddenly
without advance warning of distress because it is brittle in nature. Shear deficiency of the beam may
occur due to many reasons such as insufficient shear reinforcement or reduction in steel area. Due to
corrosion increased service load and construction cross. Nowadays the advanced composite material
such as fiber reinforce plastics (FRP) Composite are widely used in civil engineering structure due to
their high strength to weight ratio, and stiffness to weight ratio, corrosion resistance, and light weight
nonmagnetic chemically inert and potentially high durability. The use of these material are increased
in the RC structure for strengthening repair, and seismic retrofitting of structural component of
building retaining wall dames, Tank, Chimney etc. due to their performance characteristics and ease
of application and low lifecycle cost.
Fiber-reinforce plastic (FRP) are composite material made of a polymer matrix reinforced with
fibers. The fibers are usually fiberglass, Carbon, or aramid while the polymer is usually and epoxy,
vinyl ester or polyester thermosetting plastic. FRP are commonly used in the aerospace automotive
marine and construction industries. A polymer is generally manufactured by Poly condensation,
Polymerization, or Poly addition, when combined with various agents to enhance or in any way alter
the material properties of polymers. The result is referred to as a plastics or composite plastics refer
to those type of plastics that result from bonding two or more homogeneous material with different
material properties to derive a final product with Certain desired material and mechanical properties
fiber reinforced plastic are a category of composite plastics that specifically use fibrous material to
mechanically enhance the strength and elasticity of plastics. The original plastics material without
fiber reinforcement is known as the matrix. The matrix is a tough but relatively weak plastic that is
reinforced by stronger stiffer reinforcing filaments or fibers. The extent that strength and elasticity
are enhanced in a fiber reinforced plastics depends on the mechanical properties of both the fiber and
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
44 HITESH SHARMA, GOVERDHAN, S.V.DEO
matrix their volume relative to one another and the fiber length and orientation within the matrix
reinforcement of the matrix occurs by definition when the FRP material exhibits increased strength
or elasticity relative to the strength and elasticity of the matrix alone.
NECESSITY A large number of civil engineering structure such as bridge, Historical building, Parking garages,
dames, harbors, and off shore structure are deteriorating very fast due to several reasons. The
deterioration of the structure are mainly due to aggressive environment industrial pollution corrosion
use of deicing salt aging of concrete structure, faulty design or construction and due to different
natural disasters. Rebuilding of the infrastructure is a major problem faced by the nation today due to
economic crisis and availability of funds therefore the development of new rehabilitation and
strengthening techniques that are safe efficient and cost effective presents a formidable challenge for
the construction industry. The use of externally applied fiber reinforced plastic as strengthening
technique for reinforced concrete structure is gaining tremendous popularity and interest because of
their high strength to weigh ratio, high corrosion resistance, high durability, non-magnetic, high
resistance to chemical attack, as well as the ease of its installations it may be safety used for the RC
structure such as column, beams. Slabs walls, tunnels, and chimney and can be used to improve the
flexure and shear capacities and also provide confinement and ductility to compression member. In
the recent past several devastating earthquakes around the world have demonstrated the lacunae in
proper detailing of building structures and eventually the poorly detailed structures have become the
victim of distresses of different kinds. During the post disaster mitigation stage a survey is required
to investigate the conditions of the distressed building because of the vast variety of the building
structures. The development of a general rule for retrofitting measure is rather difficult and to a large
extent each structures much be approached as a strengthening problem on its own merits. It is
necessary to take a decision whether to demolish a distressed structure or to restore the same for
effective load carrying system. Many times the level of distress is such that with minimum
restoration measure the building structure can be brought back to its normally and in such situation
restoration or retrofitting is preferred. It is known that certain types of building structures and a few
specific components of these have repeatedly failed in earthquake and are prime candidates for
renovation and strengthening some of these are.
i. Building with irregular configuration such as those with abrupt changes in stiffness large
floor openings very large floor heights etc.
ii. Building or structures on sites prone to liquefaction.
iii. Building with walls of un-reinforced masonry which tend to crack and crumble under several
ground motions.
iv. Building with lack of ties between walls and floor or roofs.
v. Building with non-ductile concrete frames where shear failure at beam column joints and
column failures are common.
vi. Concrete Building in which insufficient lengths of bar anchorage are used.
vii. Concrete buildings with flat-slab framing, which can be severally affected by large story
drifts.
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
45 HITESH SHARMA, GOVERDHAN, S.V.DEO
The largest class of buildings in need of seismic upgrade is un-reinforced masonry buildings these
structures account for the majority of non-residential buildings and have certain problem in common.
These buildings are commonly marred with scars after a sting of powerful ground excitations.
The retrofitting of building structures involves improving its performance in earthquakes through one
or more of.
i. Increasing its strength and / or stiffness
ii. Increasing its ductility
iii. Reducing the input seismic loads.
ENGINEERINGS PROPERTIES OF F.R.P. The properties of the composite materials can be divided into two categories physical and
mechanical properties. Physical properties are properties that can be, or are assumed to be, related to
the structure of the material at the molecular level (i.e. the scale at which the individual constituents
can be identified by their chemical compositions or physiochemical structures) included in the term
physical properties are the mass properties the geometric properties, the chemical properties, the
thermal properties and the transport properties of the material. Mechanical properties are properties
associated with the application of mechanical forces to the material. These properties are usually
defined in term of continuum mechanics concepts and cannot be directly related to the chemical
composition or the physio-chemical structure of the constituents. The mechanical properties are
typically obtained from mechanical tests either on the constituents or on the composite itself. The
relationship between the mechanical properties and the physical properties is not well understood.
Often there is an interaction between the physical and mechanical properties for example the
temperature dependence of the stiffness properties of a material is due to an interaction between the
physical thermal properties of the material and the mechanical stiffness properties. The
prediction of the properties of composite materials from the properties of their constituents has been
the subject of much research. Both physical properties and mechanical properties have been
considered. Although much has been accomplished over the year the mathematical model used to
predict the physical and mechanical properties of materials and especially those of composite
materials are still only capable of prediction of a limited number of properties and with varying
degrees of accuracy a number of the simplified mathematical models that have been developed to
predict composite material properties in past years. Composite materials are comprised of a resin
matrix material, which typically is either a metal polymer or a ceramic matrix. Resins encase the
fibers and provide protection from damage caused by impact and environment. The two basic types
of resins are categorized as thermo set or thermoplastic. The main difference is the way in which
they cure. Thermoplastics are processed at higher temperatures and are able to be shaped after they
have been cured. A thermo set is made of molecular chains which crosslink during their curing
period and are set into a rigid from (Berthelot 1999) Thermosetting resin dominate the FRP
composite marked currently. Due to the wide range of properties which are available in both fiber
and matrices an almost endless range of fiber/polymer combination can be achieved. Fiber can be
produced form a variety of materials (e.g. glass, carbon, aramid) have a wide range of strengths and
stiffness and can be incorporated into a number of forms such as woven fabrics tow‟s or roving‟s.
The percentage of composite volume taken up by the fiber as well as its orientation profoundly
affects the mechanical properties of the resulting materials. The polymer matrix can also be modified
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
46 HITESH SHARMA, GOVERDHAN, S.V.DEO
to obtain a wide range of physical properties. The incorporation of additives such as mineral fillers
plasticizers and other performance/enhancing additives, can affect mechanical performance diffusion
characteristics and hydrothermal resistance of the composite. The quantity of curing agent‟s
promoters and accelerators used also has an impact on the final properties of the matrix phase.
Another issue which cannot be overlooked is the degree of interfacial bonding between the fiber and
matrix which is critical in transferring loads to and between the fibers so that the full strength
potential of the fibers can be developed. Processing variables, such as heating and cooling rates, cure
temperature and cure time, have an effect on the degree of core and hence the chemistry of the
composite material void volume in a composite component is a function of the compaction and
consolidation which took please during cure.
A high degree of compaction serves to eliminate voids and non-wetted fibers in the composite
laminate which could serve as potential stress concentrations for future damage.
The composite lamina is characterized by the following properties-
Fiber volume ratio Vf =
Fiber weight ratio Wf =
Matrix volume ratio Vm =
Matrix weight ratio Wm = 1- Wf
Wm =
Void volume ratio Vv = 1 – Vf - Vm
Vv =
Laminates which are unidirectional reinforced with high performance fibers generally exhibit linear
– elastic behavior to failure depending on the direction of the applied stress with respect to the fiber
direction. Unidirectional reinforced glass/epoxy laminates have tensile strength and modulus greater
than other material like (steel, Concrete, Aluminum etc.) Unidirectional reinforced carbon
fiber/epoxy laminates have specific tensile strength (ratio of tensile strength to material density) and
specific modulus (ratio of modulus to material density). However FRP material also does not possess
& high degree of ductility and exhibits very little yielding prior to failure in terms of fatigue, most
FRP materials do not exhibits a fatigue limit it also has been observed that high frequency stress
cycling can generate internal heat which is not readily dissipated. Because of the viscous elastic
nature of polymeric materials, time dependent effects are present in fiber-reinforcement composites
FRP materials have a greater tendency to undergo creep under sustained long-term loading thus the
apparent stiffness and strength of the FRP will decrease slowly overtime. In addition the stiffness and
strength of on FRP material is dependent on the rate of loading. The extent to which these
phenomena will occur depends on the specifics of the polymer type and stress history, alignment
type/volume fraction of reinforcement environmental temperature and humidity. The time
temperature superposition principle has been successfully utilized in extrapolating short-term creep
data over many decades in time a detailed treatment of this technique can be found in many polymer
science texts. The coefficient of thermal expansion for glass fiber-reinforced composite is higher
than other building material like steel, concrete; the resin matrix component of an FRP does absorb
moisture, as do aramid reinforcing fibers. There is also evidence that glass fiber shave a tendency to
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
47 HITESH SHARMA, GOVERDHAN, S.V.DEO
degrade in the presence of moisture. Some material properties, such as, density specific heat
absorptivity and eminence have no directionality associated with them and are described by one
scalar quantity for both isotropic and anisotropic materials on the other hand properties such as
stiffness, Poisson‟s ratio strength thermal expansion moisture expansion thermal conductivity and
electrical conductivity are associated with direction and are a function of orientation in anisotropic
materials fiber composite materials can exhibits various degree of anisotropy in the various
properties the largest differences occur between properties in the longitudinal (fiber) and transverse
(normal to the fiber) directions ratio of some properties along these two directions for some typical
composite material.
FAILURE MECHANISMS
It is essential to understand the consequences of the design choice in terms of crack propagation and
failure mechanism. As a result of FRP repair the mode of failure of a flexural member may change
from ductile to brittle. For example, changing the thickness of the FRP plate, changing the banded
length or adding shear reinforcement significantly modifies the crack distribution along the beam and
changes the failure mechanism. Possible mechanisms are FRP rupture, concrete crushing, shear
failure, cracking in adhesive-concrete interface. In all cases flexural cracks initiate in the tensile face
at the middle span of the beam producing a non-linear response in the load deflection. With reference
to a simply supported FRP-repaired RC beam loaded at 4-point, four possible failure mechanisms
have been follows. (1)FRP tensile – rupture (R) when the FRP strain exceeds its ultimate value in the
zone of maximum moment.(2)Concrete crushing (C) when the concrete compressive strain exceeds
its ultimate value in the zone of maximum moment.(3) Deboning between FRP and concrete (D) due
to failure at the concrete – adhesive interface. This failure mechanism can initiate at any flexural
crack and propagated from there to the end of the FRP reinforcement.(4)Shear tension failure (S)
resulting from a combination of a shear and normal tensile stress in the concrete in the plane of
longitudinal steel bars. This failure mechanism initiates at the ends of FRP plate, results in the
propagation of a horizontal crack and causes separation of a horizontal crack and causes separation
of concrete cover.
EXPLANATION OF FAILURE MECHANISMS The first two failure mechanisms occur after large deflection of the member and are synonyms of
better structural performance. In the case of FRP rupture the main steel reinforcement is fast
yielding. Moreover, from an economical point of view the rupture of FRP plate seems to be desirable
because it means that all the mechanical resources of FRP (an expensive material) are utilized. The
third and fourth failure mechanisms are brittle and occur at values of the applied load lower than
expected with conventional design equations. In both cases, the stiffening or strengthening resources
of the FRP plate are of little advantage. Anchoring the FRP plate ends, not applicable to slabs, may
attain a higher ultimate load and an increase in ductility.
Working Stress Method
Q.1 A Reinforced concrete beam is supported on two walls 750 mm thick at clear distance of 6
meters. The beam carries a superimposed load of 9.8 KN/m using M15 concrete, design, the beam
take the permissible tensile and shear stress in steel as 140 N/mm2 for mild steel.
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
48 HITESH SHARMA, GOVERDHAN, S.V.DEO
Solution: (1) Calculation of Design constants
For M15 concrete 25 /cbcc N mm
And 219 (mod ) 140 /stm uler ratio N mm
1
1 s
c c
kt
m b
(N.A. Constant)
= 1
0.404140
119 5
J = 13
k = 0.865 (lever arm constant)
Q = 1
. . . 0.8742
c ck j b (M.R. constant)
(2) Calculation B.M.
Let the effective depth of beam = 1
10span =
16000
10
d = 600 mm
Total depth of beam = 600mm (Say)
Let the width of beam = ½d = 300mm (say)
Self load of beam per meter run = (0.6×0.3×1) 25000 = 4500N
External load = 9800 N/m
Total load per meter run = 9800 + 4500 = 14300N
Effective span = L = l + d = 6 + 0.6 = 6.6 m
(6.6 is smaller than distance between support 6.75)
M = 2
8
WL =
214300(6.6)
8 = 77870 N-m = 77.87 × 10
6 N-mm
(3) Design of section
d =
677.87 10545
0.874 300
Mmm
Qb
Let us take d = 545 mm and D = 580 mm
Revised self load of beam = 0.3×0.58×25000 = 4350 N/m W = 9800 + 4350 = 14150 N/m
Effective span = L = l + d = 6 + 0.545 = 6.545 m
M =
2614150(6.545)
75770 75.77 108
N m N mm
d = 675.77 10
5380.874 300
mm
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
49 HITESH SHARMA, GOVERDHAN, S.V.DEO
Assuming that 20 mm bars will use and 25mm clear cover.
Then, D = 538 + 25 + 10 = 573 mm
So keep D = 580mm, so available d
d = 580– 25 –10 = 545mm.
(4) Steel reinforcement
Ast =
675.77 10
140 0.865 545st
M N mm
jd
Ast = 1150 mm2
Provide 20 mm bars
No. of bars 1150
314 = 3.66 Nos.
Hence provide 4 nos. 20 mm Ast = 1256 mm2
C/c distance between bar = 1
3 (300 – 25 × 2 – 4 × 20) = 56.67 mm
(56.67) which much more than diameter of bar.
Min. reinforcement is given by 0.85st
y
A
bd f
Ast = 20.85(300 545)
556250
mm
Since the actual Ast provided (=1256mm2) is much more than. This design is ok.
(5) Check for shear and design of shear reinforcement
The reaction at all the wall supports will be uniformly distributed over the full width. Hence
the shear force will be maximum of the edge of the support.
Max v =
14150 6
42450 .2 2
wlN
Ťv = 242450
0.26 / .300 545
vN mm
bd
Assuming that out of 4 bars of main reinforcement 2 bar will be bent up near the support only
two bar will be available.
100 100
628 0.38%300 545
sA
bd
Hence from table of Ťc for M15 concrete for 0.38% steel 0.26 N/mm2 which is equal to the
nominal shear stress. Hence no shear reinforcement is required.
0.4sv
sv y
A
b f Using 8mm 2 legged stirrups.
Asv = 2 2 22 ( ) 2 (8) 100.5
4 4D mm
Taking yf = 250 N/mm2
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
50 HITESH SHARMA, GOVERDHAN, S.V.DEO
The spacing of stirrups is given by
2.5 2.5 100.5 250
209300
sv y
v
A fs mm
b
However provide the stirrups @ 200mm c/c provide 2 – 12 mm holding bar.
(6) Check for Development length at support
The code stipulates that at the simple supports where the reinforcement is confined by a
compressive reaction that diameter of the reinforcement be such that
11.3 o d
ML L
v
Assuming that 2 bars are bent up and 2 bars are available at the supports.
2 2 2( ) 2 (20) 628
4 4stA D mm
M1 = moment of resistance
= 140×628×0.865×545
= 82.89×106 N-mm
v = 42450 N
Lo = Sum of anchorage value of hooks
Let us provide a support equal to the width of the wall 600 mm. Let the clear side cover x‟ =
40mm for a U hook having anchorage value of 16 we have
= ' 3 162
= ' 132
600 = 40 13 20 520
2
so
s
LL x
Lx
mm
6
1 41.45 101.3 1.3 520 1269 520 1789
42450o
ML mm
v
Development length
20 1401167
4 4 0.6st
d
bd
L mmJ
Alternatively 58 58 20 1160dL mm
Thus
11.3 o d
ML L
v Hence codes are satisfied.
For given beam section.
(1) Depth of N. Axis (Actual)
Let x be the depth of actual N. Axis
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
51 HITESH SHARMA, GOVERDHAN, S.V.DEO
2
2
( )2
30018.67 1256(545 )
2
s
bxm A d x
xx
2150x = –23449.52x + 12779988.4
2150x + 23449.52x – 12779988.4
223449.52 23449.52 4 150 12779988.4
2 150
23449.52 90652.48
300
x = 224mm
Depth of critical N.A. for given stress x = k.d
X = 0.404 × 545 220.18mm
224 220.18 Balanced section.
Moment of Resistance (For balanced section)
6
=
= 140 1256 0.865 545
= 82.89 10
st sMR A j d
MR
MR N mm
Load carrying capacity of beam
Span 6.6 m
B 300 mm
D 580 mm
MR 682.89 10 N mm (82.89 KNM)
Maximum B.M = 2 2(6.6)
8 8
WL W = if W is in N/M
B.M = Moment of resistance.
2
3(6.6)82.89 10
8
WNm
W = 3
2
82.89 10 8
(6.6)
W = 15223.140 N/m.
Self weight of beam per meter = 300 580 25000
1000 1000
= 4350 N/m.
Total superimposed load which is beam can carry excluding self weight.
15223.140 – 4350 10873.14 N/m.
10.87 KN/m.
9.8 10.87 OK.
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
52 HITESH SHARMA, GOVERDHAN, S.V.DEO
INTRODUCING F.R.P.
Span 6.6 m (6600mm)
b 300 mm
D 580 mm
d 545 mm
MR 682.89 10 N mm
ft 0.3 mm
Using two layer of GFRP sheet so along with the tensile force Ts an addition tensile
force Tfrp will also acting
Tfrp = ffrp × Afrp
Tfrp = 334.5 N/mm2 × 180 mm
2
Tfrp = 60210 N 60.21 KN
140 1256 60210 236050st s frpA T N N
So Now New M.R of beam
6 3
= 0.865 545
= 0.865 545
= 236050 0.865 545
= 111.27 10 (111.27 10 )
st s frp
s frp
MR A T
MR T T
MR
MR N mm Nm
Now load carrying capacity of beam
B.M = MR
2
8
WL = 111.27×10
3 (in N/m)
W = 3
2
111.27 10 8
(6.6)
W = 20435.261 N/m
Self weight of beam per meter = 300 580 25000
1000 1000
= 4350 N/m.
Total superimposed load which is beam can carry excluding self weight.
= 20435.261 – 4350 16085.261 N/m.
=> 16.085 KN/m.
Total increment in load carrying capacity of beam after applying GFRP sheet
= 16.085 – 10.87 5.215 KN/m.
Example 2. Design a reinforced concrete beam subjected to a bending moment of 20 KN-m use M20
concrete and Fe415 reinforcement keep the width of the beam equal to half the effective depth.
Solution: For M20 concrete
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
53 HITESH SHARMA, GOVERDHAN, S.V.DEO
cbc = 7 N/mm2
m 13
Fe 415 st = 230 N/mm2 for balanced section.
1
1 st
cbc
k
m
= 1
0.283230
113 7
J = 0.283
1 13 3
k = 0.906
Q = 1 1
. . . 0.283 0.906 7 0.8982 2
cbck j
2
2 3
.
0.898 0.4492
MR Q bd
dMR d d N mm
B.M = M = 20 KN-m = 20×106 N-mm.
0.449d3 = 20×10
6
d =
16 320 10
3540.449
mm
b = ½d 177mm
Area of steel
Ast = 620 10
230 0.906 354st
m
jd
Ast = 271.1 mm2
MR = 0.449d3 19.91 ×10
6 N-mm
Present load carrying capacity of beam.
B.M = MR
2
8
WL = 19.91×10
3 N/m
W = 3
2
19.91 10 8
(5)
W = 6371.2 N/m
Self-weight of beam (per meter) = 25000 177 354
1000 1000
= 1566.45 N/m
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
54 HITESH SHARMA, GOVERDHAN, S.V.DEO
Total superimposed load which beam can carry safely excluding self-weight
6371.2 – 1566.45 4804.75 N/m
4.8 KN/m
In this beam for increasing load carrying capacity introducing FRP
ft = 0.5 mm. (1 layer)
ffrp = 260 N/mm2 (CFRP)
Tfrp = ffrp× Afrp
Tfrp = 260×88.5 23010 N 23.01 KN
Now New moment of Resistance
6 3
=
=
= 271.1 230 23010 0.906 354
= 27.37 10 (27.37 10 )
s frp
st st frp
MR T T j d
MR A T j d
MR
MR N mm Nm
Now new load carrying capacity of beam
B.M = M.R
W = 3
2
27.37 10 8
(5)
W = 7478.4 N/m
Self-weight of beam per meter = 25000 177 354
1566.45 /1000 1000
N m
Total super imposed load which beam can carry safely excluding self-weight
7478.4 – 1566.45 5911.95 N/m
5.911 KN/m
Total increment in load carrying capacity of beam after applying 1 layer of CFRP with 0.5
mm thickness. 5.911 KN/m – 4.8 KN/m = 1.111 KN/m
FINDINGS OF THE STUDY
The composite plate bonded to the tension face of the beam increases
(i) The stiffness
(ii) Yield moment and
(iii) Ultimate moment of the beam and reduces
(iv) The curvature at failure
On the basis of design of reinforced concrete beam with FRP composites. The wrap system are
fully capable to increased
(1) Flexural strength of beam under 100 % increased live load and
(2) Increased the shear strength of R.C.C „T‟ beam
International Journal of Engineering Technology, Management and Applied Sciences
www.ijetmas.com March 2015, Volume 3 Special Issue, ISSN 2349-4476
55 HITESH SHARMA, GOVERDHAN, S.V.DEO
SUGGESTED FUTURE WORK
[1] The failure of reinforced concrete beams strengthened with epoxy-bonded composite
plates should be investigated for the failure of the concrete layer between the plate and the
reinforcing bars to develop a rational approach for predicting the load causing this type of
failure.
[2] Reinforced concrete design with FRP composite according to IS 456
[3] A special code can be made for FRP wrap system
[4] To evaluate the effect of weather and aging in FRP wrap system
[5] FRP wrapping system can be, more easy and more reasonable
[6] To reduce the possibility of failure of FRP wrap system like, Debonding
REFERENCES
Citation from journals:
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Analysis and parametric study “J.of structure engineering ASCE 117 (11)
[2] Hamoush, S.A. and Ahmad , S.H . (1990), “Debonding of steel plate – strengthened Concrete
Beams “J. Structure Engg. ASCE 116 (2) 356-371
[3] Klaiber, F.W. Dunker K.F. and Sanders W.W. (1982) “Strengthening of single span steel
beam Bridges” J. Struct.Engg. ASCE. 108(12) 2766-2780.
[4] MacDonald M.D. and Calder A.J.J. (1982) “Bonded steel plating for strengthening Concrete
Structure” Int. J. Adhes. 2(2) 119-127.
[5] Saadatmanesh. H. Albrecht. P. and Ayyub B. M. (1989a) “Experimental study of Prestressed
Composite beams” J. Struct. Engg. ASCE. 115 (9) 2349-2364
[6] Saadatmanesh. H. Albrecht. P. and Ayyub B. M. (1989b) “ Analytical study of Prestressed
Composite beams” J. Struct. Engg. ASCE. 115 (9) 2365-2382.
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