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Scientific Measurements
Accuracy vs. Precision
Significant Figures
Scientific Notation
SI Metric units
Density
Dimensional Analysis
2
How good are the measurements?
Scientists use two word to describe how good the measurements are
Accuracy- how close the measurement is to the actual value
Precision- how well can the measurement be repeated
Accuracy vs. Precision• Accuracy - how close a measurement is to
the accepted true value
• Precision - how close a series of measurements are to each other
ACCURATE = CORRECT
PRECISE = CONSISTENT
4
Differences Accuracy can be true of an individual
measurement or the average of several Precision requires several
measurements before anything can be said about it
examples
5
Let’s use a golf anaolgy
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Accurate? No
Precise? Yes
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Accurate? Yes
Precise? Yes
8
Precise? No
Accurate? Maybe?
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Accurate? Yes
Precise? We cant say!
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In terms of measurement A room is exactly 10.3 m
wide Three students measure
the room to be 10.2 m, 10.3 m and 10.4 m across.
Were they precise? Were they accurate?
Accurate and Precise as it relates to Blood Pressure
lets say a person’s blood pressure is truly 124/78.
3 different people measure it and they get the following data
1. 110/62
2. 110/60
3. 112/62
Is this data accurate or precise, both or neither?
Accurate and Precise as it relates to Blood Pressure
lets say a person’s blood pressure is truly 124/78.
3 different people measure it and they get the following data
1. 124/58
2. 146/90
3. 98/64
Is this data accurate or precise, both or neither?
Accurate and Precise as it relates to Blood Pressure
lets say a person’s blood pressure is truly 124/78.
3 different people measure it and they get the following data
1. 126/78
2. 126/80
3. 124/76
Is this data accurate or precise, both or neither?
Types of measurement
• Quantitative- use numbers
• Qualitative- use description
• 4 feet
• extra large
• Hot
• 100ºF
Scientists prefer
• Quantitative- easy check
• Easy to agree upon, no personal bias
• The measuring instruments limit how good a measurement can be
Significant Figures
• Indicate precision of a measurement.
• Recording Sig Figs– Sig figs in a measurement include the known
digits plus a final estimated digit
2.75 cm
Significant Figurescount any # 1-9
– Zeros are tricky 00000000
– Count all numbers EXCEPT:
• Never count Leading zeros -- 0.00471 (? sig figs)
• Count all trapped zeros 12.07 (? sig figs)
• Don’t count Ending zeros unless they have a decimal point -- 7,400 (? sig figs)
• Count zeros that have a decimal point at the end 3500.
1. 32.30
Significant Figures
Counting Sig Fig Examples
2. 4002
3. 3,470
4. 0.090
Significant Figures
• Calculating with Sig Figs– Multiply/Divide - The # with the fewest sig
figs determines the # of sig figs in the answer.
(14.22g/cm3)(21.5cm3) = 305.73g
306 g
4 SF 3 SF3 SF
Significant Figures
• Calculating with Sig Figs– Multiply/Divide - The # with the fewest sig
figs determines the # of sig figs in the answer.
(17.8g/cm3)(11.53cm3) = 205.234g
205 g
3 SF 4 SF3 SF
Significant Figures
• Calculating with Sig Figs – Add/Subtract - The # with the lowest decimal
value determines the place of the last sig fig in the answer.
3.75 mL
+ 4.1 mL
7.85 mL
224 g
+ 130 g
354 g 7.8 mL 350 g
3.75 mL
+ 4.1 mL
7.85 mL
224 g
+ 130 g
354 g
Significant Figures
• Calculating with Sig Figs – Exact Conversions do not limit the # of sig figs in the answer.
• Exact conversions: 1 m = 100 cm
• 1 in = 2.54 cm
• 3 feet = 1 yard
Significant Figures
(15.30 g) ÷ (6.4 mL)
Practice Problems
= 2.390625 g/mL
4 SF 2 SF
2.4 g/mL2 SF
Significant Figures
Practice Problems
18.1 g
18.9 g
- 0.84 g18.06 g
Scientific Notation
• Converting into Sci. Notation:
– Move decimal until there’s 1 digit to its left. Places moved = exponent. (a # 1-10)
– Large # (>1) positive exponentSmall # (<1) negative exponent
– Only include sig figs.
65,000 kg 6.5 × 104 kg
Scientific Notation
7. 2,400,000 g
8. 0.00256 kg
9. 7 10-5 km
10. 6.2 104 mm
Practice Problems
Scientific Notation
7. 2,400,000 g
8. 0.00256 kg
9. 7 10-5 km
10. 6.2 104 mm
Practice Problems
2.4 106 g
2.56 10-3 kg
0.00007 km
62,000 mm
Scientific Notation
• Calculating with Sci. Notation
(5.44 × 107 g) ÷ (8.1 × 104 mol) =
5.442nd 2nd
EEEE÷÷
2nd 2nd
EEEE ENTERENTER7 8.1 4
= 671.6049383 = 670 g/mol = 6.7 × 102 g/mol
Type on your TI-30 x IIS calculator:
Scientific Notation
• Calculating with Sci. Notation
(5.44 × 107 g) ÷ (8.1 × 104 mol) =
5.44 n n x10x10
ENTERENTER7 (8.1 4
= 671.6049383 = 670 g/mol = 6.7 × 102 g/mol
Type on your TI-30XS Multiview calculator:
÷÷enter n n x10x10
30
Measuring Temperature0ºC
31
Measuring Temperature
Celsius scale. water freezes at 0ºC water boils at 100ºC body temperature 37ºC room temperature 20 - 25ºC
0ºC
32
Convert Celsius to Fahrenheit
9/5 C + 32 = F
Ex. Convert 10 C to F
(9/5 x 10) + 32 = 50 F
33
Convert Fahrenheit to Celsius
5/9 (F – 32) = C
Ex. Convert 45 F to C
5/9 (45 – 32) = 7.2 C
34
Measuring Temperature C + 273 = K K -273 = C
Convert 25 C into K
25 C + 273 = 298 K
Convert 303 K into C
303 K – 273 = 30 C
273 K
35
Measuring Temperature Kelvin starts at absolute zero (-273 º C) degrees are the same size C = K -273 K = C + 273 Water freezes at 273 K Water boils at 373 K Kelvin is always bigger. Kelvin can never be negative.
273 K
36
Quantity Base Unit Symbol
Length – meter m Mass - gram g Time – second s Temperature - Kelvin or ºCelsius K or C Energy - Joules J Volume - Liter L Amount of substance - mole mol
Quantity Base Unit Symbol
Length – meter m Mass - gram g Time – second s Temperature - Kelvin or ºCelsius K or C Energy - Joules J Volume - Liter L Amount of substance - mole mol
SI Units
mega- M 106
deci- d 10-1
centi- c 10-2
milli- m 10-3
Prefix Symbol Factor
micro- 10-6
nano- n 10-9
pico- p 10-12
kilo- k 103
BASE UNIT --- 100
Million
1000
1
1/10 = .1
1/100 = .01
1/1000= .001
.000001
SI Units – Standard International
Quantity Base Unit Abbrev.
Length
Mass
Time
Temp
meter
kilogram
second
kelvin
m
kg
s
K
Amount mole mol
Symbol
l
m
t
T
n
Volume and Density
• Combination of base units.
• Volume (cm3) – length length length
D = MV
1 cm3 = 1 mL
• Density = g/cm3
– mass per volume
Density• An object has a volume of 825 cm3 and a
density of 13.6 g/cm3. Find its mass.
GIVEN:
V = 825 cm3
D = 13.6 g/cm3
M = ?
WORK:
M = DV
M = (13.6 g/cm3)(825cm3)
M = 11,220 g
M= 11,200 gV
MD
Density• A liquid has a density of 0.87 g/mL. What
volume is occupied by 25 g of the liquid?
GIVEN:
D = 0.87 g/mL
V = ?
M = 25 g
WORK:
V = M D
V = 25 g =28.736
0.87 g/mL
V = 29 mLV
MD
43
Converting
k h D d c m how far you have to move on this chart,
tells you how far, and which direction to move the decimal place.
The box is the base unit, meters, Liters, grams, etc.
44
Conversions
Change 5.6 m to millimeters
k h D d c m
starts at the base unit and move three to the right.move the decimal point three to the right
56 00
45
Conversions
Change 5.6 km to millimeters
k h D d c m
46
Conversions
Change 5.6 km to millimeters Km to mm is 6 steps
5.6 E6 mm or 5,600,000 mm
k h D d c m
47
Conversions
convert 25 mg to grams convert 0.45 km to mm convert 35 mL to liters
k h D d c m
48
Conversions
convert 25 mg to grams .025 g convert 0.45 km to mm 450,000 mm convert 35 mL to liters .035 L
k h D d c m
100mL graduated cylinder (52.7 mL)10mL graduated cylinder (6.62 mL)
51
STOP
END HERE
52
Volume calculated by multiplying L x W x H Liter the volume of a cube 1 dm (10 cm)
on a side so 1 L = 10 cm x 10 cm x 10 cm 1 L = 1000 cm3 1/1000 L = 1 cm3 1 mL = 1 cm3
53
Volume 1 L about 1/4 of a gallon - a quart 1 mL is about 20 drops of water or 1
sugar cube
54
Mass weight is a force, is the amount of
matter. 1gram is defined as the mass of 1 cm3
of water at 4 ºC. 1000 g = 1000 cm3 of water 1 kg = 1 L of water
55
Mass 1 kg = 2.5 lbs 1 g = 1 paper clip 1 mg = 10 grains of salt or 2 drops of
water.
56
Which is heavier?
it depends
57
Density how heavy something is for its size the ratio of mass to volume for a
substance D = M / V Independent of how much of it you have gold - high density air low density.
58
Calculating The formula tells you how units will be g/mL or g/cm3 A piece of wood has a mass of 11.2 g
and a volume of 23 mL what is the density?
A piece of wood has a density of 0.93 g/mL and a volume of 23 mL what is the mass?
59
Calculating A piece of wood has a density of 0.93 g/mL
and a mass of 23 g what is the volume? The units must always work out. Algebra 1 Get the thing you want by itself, on the top. What ever you do to onside, do to the other
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Floating Lower density floats on higher density. Ice is less dense than water. Most wood is less dense than water Helium is less dense than air. A ship is less dense than water
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Density of water 1 g of water is 1 mL of water. density of water is 1 g/mL at 4ºC otherwise it is less
62
Measuring Temperature
Celsius scale. water freezes at 0ºC water boils at 100ºC body temperature 37ºC room temperature 20 - 25ºC
0ºC
63
Measuring Temperature Kelvin starts at absolute zero (-273 º C) degrees are the same size C = K -273 K = C + 273 Kelvin is always bigger. Kelvin can never be negative.
273 K
Dimensional Analysis• Measurement conversion
– Units cancel out, so as to convert from one unit of measurement to another unit
– but same value– Ex. which is more 36 individual doughnuts or
3 dozen doughnuts
36 doughnuts x = dozen
Dimensional Analysis
• Measurement conversion– Cancel out units and convert to unit you want
36 doughnuts x 1 dozen = dozen
12 doughnuts
Dimensional Analysis
• Measurement conversion– Multiply everything on top– divide by everything on bottom
36 doughnuts x 1 dozen = 3 dozen
12 doughnuts
Dimensional Analysis- is like multiplying by 1
units change but value stays the same
• Conversion factors always equal 1
• 1/1= 1
• 5/5= 1
• 12/dozen= 1
• 2/pair = 1
• 100cm/1meter=1
• 2.54cm/1in= 1
Dimensional Analysis
• Steps:
1. Identify starting & ending units.
2. Line up conversion factors so units cancel.
3. Multiply all top numbers & divide by each bottom number.
4. Check units & answer.
Dimensional Analysis
• Lining up conversion factors:
1 in = 2.54 cm
2.54 cm 2.54 cm
1 in = 2.54 cm
1 in 1 in
= 1
1 =
Dimensional Analysis Your European hairdresser wants to cut your hair 8.0
cm shorter. How many inches will he be cutting off? 1 in. = 2.54 cm
8.0 cm 1 in
2.54 cm= 3.1 in
cm in
Dimensional Analysis• You live 7 Kilometers from school how many
meters do you live from school?
7.00 km 1000 m
1 Km= 7000 m
Km m
Dimensional Analysis• How many milliliters are in 1.00 quart of
milk? (1L = 1.057 qt)
1.00 qt 1 L
1.057 qt= 946 mL
qt mL
1000 mL
1 L
Dimensional Analysis• Convert 445 km/hr to m/s
445 km
Km/hr m/s
hr
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
1 min
60 sec=
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
1 min
60 sec=
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
1 min
60 sec=
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
1 min
60 sec= 123.61
Dimensional Analysis• Convert 445 km/hr to m/s
445 km 1000 m
Km/hr m/s
hr 1 km
1 hr
60 min
1 min
60 sec= 123.61
124 m/s
Dimensional Analysis• You have 1.5 pounds of gold. Find volume in cm3 if the
density of gold is 19.3 g/cm3.• 1 Kg = 2.2 lb
lb cm3
1.5 lb 1 kg
2.2 lb= 35 cm3
1000 g
1 kg
1 cm3
19.3 g
Dimensional Analysis
Kell football needs 550 cm for a 1st down. How many yards is this?
550 cm 1 in
2.54 cm= 6.0 yd
cm yd
1 ft
12 in
1 yd
3 ft
Percent Error• Indicates accuracy of a measurement
• Compared to Accepted Value (literature)
• That is how close your lab findings are to the accepted value
Percent Error• Indicates accuracy of a measurement
100literature
literaturealexperimenterror %
your value
accepted value
Percent Error• A student determines the density of a
substance to be 1.40 g/mL. Find the % error if the accepted value of the density is 1.36 g/mL.
100g/mL 1.36
g/mL 1.36g/mL 1.40error %
% error = 2.94 %
Percent Error• A student determines the density of a
substance to be 2.95 g/mL. Find the % error if the accepted value of the density is 3.17 g/mL.
% error =
100literature
literaturealexperimenterror %
Percent Error• A student determines the density of a
substance to be 2.95 g/mL. Find the % error if the accepted value of the density is 3.17 g/mL.
% error = 6.94 %
% error = [ 2.95 g/ml – 3.17 g/ml ] x 100
3.17 g/ml
E. Proportions
• Direct Proportion
• Inverse Proportion
xy
xy
1
y
x
y
x