Date post: | 28-Dec-2015 |
Category: |
Documents |
Upload: | kathryn-payne |
View: | 213 times |
Download: | 0 times |
A function will not have a derivative at a point P (a, f(a)) wherethe slopes of the secant lines,
How f (a) Might Fail to Exist
f x f a
x a
fail to approach a limit as x approaches a. Four instanceswhere this occurs:
1. A corner, where the one-sided derivatives differ.
f x xExample:
There is a corner at x = 0
A function will not have a derivative at a point P (a, f(a)) wherethe slopes of the secant lines,
How f (a) Might Fail to Exist
f x f a
x a
fail to approach a limit as x approaches a. Four instanceswhere this occurs:
2. A cusp, where the slopes of the secant lines approachinfinity from one side and negative infinity from the other.
2 3f x xExample:
There is a cusp at x = 0
A function will not have a derivative at a point P (a, f(a)) wherethe slopes of the secant lines,
How f (a) Might Fail to Exist
f x f a
x a
fail to approach a limit as x approaches a. Four instanceswhere this occurs:
3. A vertical tangent, where the slopes of the secant linesapproach either pos. or neg. infinity from both sides.
3f x xExample:
There is a vertical tangent at x = 0
A function will not have a derivative at a point P (a, f(a)) wherethe slopes of the secant lines,
How f (a) Might Fail to Exist
f x f a
x a
fail to approach a limit as x approaches a. Four instanceswhere this occurs:
4. A discontinuity (which will cause one or both of the one-sided derivatives to be nonexistent).
1, 0
1, 0
xU x
x
Example: The Unit Step Function
There is a discontinuity at x = 0
Relating Differentiability and Continuity
Theorem: If has a derivative at x = a, then iscontinuous at x = a.
f f
Intermediate Value Theorem for Derivatives
f fIf a and b are any two points in an interval on which
is differentiable, then takes on every valuebetween and . f a f b
Ex: Does any function have the Unit Step Function as itsderivative?
NO!!! Choose some a < 0 and some b > 0. Then U(a) = –1and U(b) = 1, but U does not take on any value between –1and 1 can we see this graphically?
Differentiability Implies Local Linearity
Locally linear function – a function that isdifferentiable at a closely resembles its own tangentline very close to a.
Differentiable curves will “straighten out” when wezoom in on them at a point of differentiability…
Differentiability Implies Local LinearityIs either of these functions differentiable at x = 0?
2 0.0001 0.99g x x 1f x x 1. We already know that f is not differentiable at x = 0; its graphhas a corner there. Graph f and zoom in at the point (0,1)several times. Does the corner show signs of straightening out?
Continued zooming in at the given point (assuming asquare viewing window) always yields a graph with theexact same shape there is never any “straightening.”
Differentiability Implies Local LinearityIs either of these functions differentiable at x = 0?
2 0.0001 0.99g x x 1f x x
2. Now do the same thing with g. Does the graph of g show signsof straightening out?
Try starting with the window [–0.0625, 0.0625] by[0.959, 1.041], and then zooming in on the point (0,1).Such zooming begins to reveal a smooth turning point!!!
Differentiability Implies Local LinearityIs either of these functions differentiable at x = 0?
2 0.0001 0.99g x x 1f x x
3. How many zooms does it take before the graph of g looksexactly like a horizontal line?
After about 4 or 5 zooms from our previous window, thegraph of g looks just like a horizontal line.
This function has a horizontal tangent at x = 0, meaningthat its derivative is equal to zero at x = 0…
Differentiability Implies Local LinearityIs either of these functions differentiable at x = 0?
2 0.0001 0.99g x x 1f x x
4. Now graph f and g together in a standard square viewingwindow. They appear to be identical until you start zooming in.The differentiable function eventually straightens out, while thenondifferentiable function remains impressively unchanged.
Try the window [–0.03125, 0.03125] by [0.9795, 1.0205]
How does all of this relate toour topic of local linearity???
Guided Practice
2 3f x x
2,3
Find all the points in the domain of wherethe function is not differentiable.
Think about this problem graphically. We have the graph of theabsolute value function, translated right 2 and up 3:
There is a corner at (2,3),so this function is notdifferentiable at x = 2.
Guided Practice
2, 1
2 , 1
xf x
x x
1,2P
For the given function, compare the right-hand and left-handderivatives to show that it is not differentiable at point P.
Graph the function:
0
1 1limh
f h f
h
Left-hand derivative:
0
2 2limh h
0lim 0h
0
0
1 1limh
f h f
h
Right-hand derivative:
0
2 1 2limh
h
h
0lim 2h
2
1,2P
Guided Practice
2, 1
2 , 1
xf x
x x
For the given function, compare the right-hand and left-handderivatives to show that it is not differentiable at point P.
Left-hand derivative: 0
Right-hand derivative: 2
0 2Since , the function isnot differentiable at point P. 1,2P
Graph the function:
1,2P
Guided PracticeThe graph of a function over a closed interval D is given below.At what points does the function appear to be(a) differentiable?
(b) continuous but not differentiable?
(c) neither continuous nor differentiable?
y f x : 2 3D x (a) All points in [–2,3] except x = –1, 0, 2
(b) x = –1
(c) x = 0, x = 2
Guided PracticeThe given function fails to be differentiable at x = 0. Tell whetherthe problem is a corner, a cusp, a vertical tangent, or adiscontinuity. Support your answer analytically.
4 5y x Check the one-sided derivatives!!!
0
0 0limh
y h y
h
4 5
0limh
h
h 1 50
1limh h
0
0 0limh
y h y
h
4 5
0limh
h
h 1 50
1limh h
The problem is a cusp!!!
(support with a graph???)
Guided PracticeThe given function fails to be differentiable at x = 0. Tell whetherthe problem is a corner, a cusp, a vertical tangent, or adiscontinuity. Support your answer analytically.
1 33y x Check the two-sided derivative!!!
0
0 0limh
y h y
h
1 3
0
3 3limh
h
h
1 3
0limh
h
h
2 30
1limh h
The problem is a vertical tangent!!!(support with a graph???)