A horse starts to chase a dog that has left the stable two hours earlier. The horse runs at an average speed of 2km/hr.  (It crosses a 10-metre road, two small ponds 3 metres deep, and finally runs along two small streets of 200 metres long=irrelavent data). After traveling 6 hrs, 2hrs after sunset, it catches the dog. Compute the speed of the dog in Km/hr?Ans:starting of the question is given to waste our time.its useless   

  horse's average speed =2kmphhorse catches the dog after 6 hours.sototal distance travelled by horse=>>distance=velocity*time   =2kmph*6                                                  =12kmbut the dog started 2 hours before(read the question)so total time taken to travel 12 km by dog is=6+2=8 hours.By using basicdistance=velocity*time formula we can get the velocity of dog                            12=velocity*8velocity=12/8=1.5kmph

.  A sheet of paper has statements numbered from 1 to 70. For all values of n from 1 to 70, Statement n says \' At least n of the statements on this sheet are false. �Which statements are true and which are false?For this kind of questions the logic is simple , you have to remember 3 things .

when the question says : 

atleast - half of the statements are true and half are false exactly -- (n-1)th statement is true and remaining are false atmost -- then all are true .. 

now according to the above asked question , atmost : then all the statements are true .. 

therefore, none of these (option d ) is the solution

A and B play a game of dice between them. The dice consist of colors on their faces (instead of numbers). When the dice are thrown, A wins if both show the same color; otherwise B wins. One die has 4 red face and 2 blue faces. How many red and blue faces should the other die have if the both players have the same chances of winning?

P(A wins) = P(Die 1 lands red) * P(Die 2 lands red) + P(Die 1 lands blue) * P(Die 2 lands blue)

So if r represents the number of red faces on the 2nd die and we want P(A wins) to be 0.50 (50%), then0.50 = 4/6 * r/6 + 2/6 * (6-r)/60.50 = 4r/36 + (12-2r)/3618/36 = (12-2r)/36

18/36 = 12/36 - 2r/366/36 = 2r/366 = 2r3 = r

Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the present age of Peter?

For these type of questions, use the formula 1) 7x/4 =[sum of ages] where x is the age of elder.2)7x/3 = [sum of ages] whr x is the age of younger. Here peter is elder so 7x/4=35. Solve you get x= 20

In planet OZ planet there are 8 days in a week - Sunday to Saturday and another day called OZ day. There is 36 hours in a day and each hour has 90 minutes while each minute has 60 seconds. As on earth, the hour hand covers the dial twice every day. What is the approximate angle between the hands of the clock on Oz when the time is 12:40 a.m.?

For hour hand:18hr = 360deg1hr = 20deg12hr = 240deg90min = 20deg1min = (2/9)deg40min = (2*40/9) = 9deg approxtotal= 240+9 = 249deg

For minute hand,90min = 360deg1min = 4deg40min = 160deg

So, difference = 249-160 = 89deg (Answer)

20h+_934/9)m

  Entry ticket to an exhibition ranges from 1p to 31p. You need to provide exact change at the counter. You have 31p coin. In how many parts will you divide 31p so that you will provide the exact change required and carry as less coins as possible?

Look at the highest price its 31p. Now think of a power of 2 closest to 31. Its 2^5. Now the power is the answer. So ans =5. For your information, the coins to take will be 2^0,2^1,2^2,2^3,2^4 = 1,2,4,8,16.

A hare and a tortoise have a race along a circle of 100 yards diameter. The tortoise goes in one direction and the hare I the other. The hare starts after the tortoise had coveredc 1/7 of its distance and that tooo leisurely. The hare and tortoise meet when the hare has covered only 1/8 of the distance. By what factor shoul the hare increase its speed so as to ties the reace?841.00567Ans: 1/7, 1/87*8=5656-7=4949-8=4149*41/7^2=41.00

Mr bean visited a magic shop and bought some magical marbles of different colours along with other magical items. While returning home whenever he saw a coloured light he took out marbles of similar colours and counted them. So he counted the pink coloured marbles and found that he has bought 25 of them . then he counted 10 green marbles and then 32 yellow marbles. He later counted 30 purple coloured marbles with him. But when he reached a crossing, he looked at a red light and started counting red marbles and found that he had bought 34 red marbles. As soon as he finished counting, it started raining heavily and by the time he reached home he was drenched. After reaching home he found that the red, green, and yellow marbles had magically changed colours and became white, while other marbles were unchanged . it will take 1 day to regain its colo9urs, but he needs to give atleast one pair of marbles to his wife so as to ensure that there is atleast one pair of red, yellow and green marbles?70426840

Ans: 34+32+2=68

45 people {a1, a2, …, a12} meet and shake hands in a circular fashion. In the pairs, {a1, a2}, {a2, a3}, …, {a11, a12}, {a12, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is

(a) 12

(b) 10(c) 18(d) 15Ans. d hint: ceiling[N/3]

Alok and Bhanu play the following min-max game. Given the expression N = 15 + X*(Y – Z) Where X, Y and Z are variables representing single digits (0 to 9), Alok would like to maximize N while Bhanu would like to minimize it. Towards this end, Alok chooses a single digit number and Bhanu substitutes this for a variable of her choice (X, Y or Z). Alok then chooses the next value and Bhanu, the variable to substitute the value. Finally Alok proposes the value for the remaining variable. Assuming both play to their optimal strategies, the value of N at the end of the game would be?Ans. 15+18 =33Note: For this type of questions:x+y-z=11x-y-z=2x*(y+z)=18

How many four digit numbers can be formed using the digits 1, 2, 3, 4, 5 (but with repetition) that are divisible by 4? Can you help Alok find the answer?

(a) 100(b) 125(c) 75(d) 85

Ans:. 5^n-1= 5^4-1=125, n= no of digits

The citizens of planet nigiet are 8 fingered and have thus developed their decimal system in base 8. A certain street in nigiet contains 1000 (in base 8) buildings numbered 1 to 1000. How many 3s are used in numbering these buildings?a) 54 b) 64 c) 265 d) 192 in unit's place, the 3's are:3, 13, 23 ... 73103, 113, 123 ... 173...703, 713, .... 773=> total number of 3's in unit's place is 8*8 = 64in 10's place (that's 8 in decimal), the 3's are:30, 31, 32... 37130, 131, ... 137...

730, 731, .... 737=> total number of 3's in 10's place is 8*8 = 64in 100's place (that's 64 in decimal), the 3's are:300, 301, ... 307310, 311 ... 317...370, 371 .... 377=> total number of 3's in 100's place is 8*8 = 64thus, the total number of 3's in total is 64 + 64 + 64 = 192

8. 36 people {a1, a2, ., a36} meet and shake hands in a circular fashion. Inother words, there are totally 36 handshakes involving the pairs, {a1, a2}, {a2, a3},...., {a35, a36}, {a36, a1}. Then size of the smallest set of people such that the rest have shaken hands with at least one person in the set is

12131811

Solution: for at least one person & for exactly one person =36/3for at least two person & for exactly two person =36/2

A boy wants to make cuboids of dimension 5m, 6m and 7m from small cubes of .03 m3. Later he realized he can make same cuboids by making it hollow. Then it takes some cubes less. What is the number of the cubes to be removed?a) 2000 b) 5000 c) 3000 d) 7000 total number of cubes=5*6*7=210given volume of each cube =0.03m3so no of cubes can be formed is 210/0.03no of hollow cubes=(5-2)*(6-2)*(7-2)/0.03=2000so no of cubes to be removed is 7000-2000=5000.

Leena cut small cubes of 10 cm dimension each. She joined it to make a cuboid of length 100 cm, width 50 cm and depth 50 cm. How many more cubes does she need to make a perfect cube?a)500 b)250 c)750 d)650Solution

volume of given cube = 100*50*50 = 250000required volume = 100*100*100 = 1000000

so extra volume required = 750000so cubes required = 750000/10*10*10 = 750

A lady builds 9cm length,10cm width,3cm height box using 3cubic cm cubes. What is the minimum number of cubes required to build the box? volume of box 9*10*3=270volume of cube is 3so min cubes r 270/3=90

Simple question bt big one on average age.sth like a,b,c weigheted separately 1st a,b,c ,then a& b,then b&c ,then c&a at last abc,the last weight was 167,then what will be the avg weight of the 7 weight? the following are being weighed:a,b,c,a+b,b+c,c+a,a+b+clast weight = a+b+c=167the average weight of 7 will be= [a+b+c+(a+b)+(b+c)+(c+a)+(a+b+c)]/7=4(a+b+c)/7=4(167)/7=95.428which is approximately equal to 95.43

A lady has fine gloves and hats in her closet- 18 blue, 32 red, and 25 yellow. The lights are out and it is totally dark. In spite of the darkness, she can make out the difference between a hat and a glove. She takes out an item out of the closet only if she is sure that if it is a glove. How many gloves must she take out to make sure she has a pair of each color?

A game is played between 2 players and one player is declared as winner. All the winners from first round are played in second round.

All the winners from second round are played in third round and so on. If 8 rounds are played to declare only one player as winner, how many players are played in first round?ans: a (256)Start from final round. For every round players double in a knockout game. So 8th round(final round)=2 players. Now 7th round double it=4 players. In that way calculate until 1st round. you get 256. or simply 2^n , n= no. of rounds. 2^8=256

Middle- earth is a fictional land inhabited by hobbits, elves, dwarves and men. The hobbits and elves are peaceful creatures that prefer slow, silent lives and appreciate nature and art. The dwarves and the men engage in physical games. The game is as follows. A tournament is one where out of the two teams that play a match, the one that loses get eliminated. The matches are played in different rounds, where in every round; half of the teams get eliminated from the tournament. If there are 8 rounds played in knock out tournament, how many matches were played?ans is d)2551+2+4+8+16+32+64+128=255at final round play only one match.prev round play two matcheslike wise at 8th round the play 128 matches.so finally add all we got the answer

Peter and Paul are two friends. The sum of their ages is 35 years. Peter is twice as old as Paul was when Peter was as old as Paul is now. What is the present age of Peter?We have a + e = 35………………….. (1)

Now when Peter was Paul’s age which means (e - a) years ago

Peter would have been e - (e - a) = a which is Paul’s age now

Paul would have been a - (e - a) = 2a - e

We have been given that Peter’s age is twice what Pauls was,

so e = 2(2a - e) = 4a - 2e which gives 3e = 4a………………….. (2)

For ease of use if a + e = 35; then 3a + 3e = 105 = 3a + 4a from (2) above

Thus 7a = 105

a = 15; e = 20

peter and paul are two friends.the sum of their age is 35 years.peter is twice as old as paul was when peter was as old as paul is now.what is the present age of peter? For these type of questions, use the formula 1) 7x/4 =[sum of ages] where x is the age of elder.2)7x/3 = [sum of ages] whr x is the age of younger. Here peter is elder so 7x/4=35. Solve you get x= 20

A person run from A to B.He took ¼ of the time less to reach B when compare to run at normal Speed.Then how many percentage he has increased his speed?nitialy---speed-s1 ,distance -d ,time -t1s1=d1/t1now speed-s2 ,distance - d, time- t2=(1-1/4)=3/4s1

so, s1/s2=3/4.s2= 4/3s1 = 1.33s1% increase = (1.33s1 - s1)/s1 *100 =33.3%

An athlete decides to run the same distance in 1/4th less time that she usually took. By how much percent will she have to increase her average speed?let initial velocity = u and time taken = tsince athlete decides to run the same distance in 1/4th less time,then new time taken will be t-(t/4) = 3t/4let the new volocity = vthen for the same distance u*t = v*(3t/4) on solving we get v = 4u/3so increment = 4u/3 - u = u/3so % increment in speed = 33.33%

There are 100 can out of of them one is poisoned .if a person tastes very little of this he will die within 14 hours so they decided to test with a mice .given that a mouse dies in 24 hours and you have 24 hours in all to find out the poisoned can , how many mice are required to find the poisoned can? it will be 7 micewe have a formula for this which is 2^m > b, where m=mice,b=bottleso according to this 2^7=128 immediaately greater than 100.reason is that to find the poisoned bottle we'll definitely need combinations of mice coz we dont hv the EXACT time of death do we??? like if 10 ppl go to a party and 1 has limca,2 hv pepsi, 3 have coke nd 4 hv dew, the one who had limca also had coke and one person from pepsi group also had dew.now the group of 4 plus the one frm pepsi group who had dew fall sick, then we'll easily know that dew was the reason of sickness and its identifier will be the GROUP, or rather the COMBINATION of ppl who had it.... now see frm the above xample, that only ONE particular group was the identifier for ONE particular drink... draw the analogy from here for this case too that we'll need to have a unique grup of mice fr each bottle which will b the identifier for it... so the total no. of grups of mice will be nothing but the total no. of bottles..we'll get the grups simply by combination of mice, and the total no. of bottles as said earlier will b equal to the sum of those combinations.now we know, sum of combinations nC0+nC1+...+nCn=2^nwe said total no of combinations, ie sum of combinations=no. of bottles(B)so nC0+nC1+...+nCn=2^n=Band we cant take nC0 as it wud mean combi of n MICE taking 0 at a time whch is impossible. so 2^n will always have to be greater than B and that too the immediate next greater. now fr 

this prob, its 100 bottles so immediate higher power of 2 is 128=2^7 so the no of mice=27...plss dont consider combination of bottles as v r determining the poisoned BOTTLE and NOT the poisoned mouse.... :Phope this helps... the xplanation is fr undrstanding..jus remember the formula.

In a hotel we can order two types of varities,but we can make 6 more variteis in home.One can choosethe four varities with two from hotel as must.Find how many ways one can order.a)14 b)15 c)56 d)28No. of ways=2c2*6c2=15

There was a grand mother in a village who had a grand child.Upon asking her grand childs age she told that she is as older as many days old as her daughters age in weeks and as many days as her own age in years.The sum of the three is 130.then how old is the child.?Let the ages of grandmother, her daughter and the grandchild be x, y and z respectively in years. 

z in days = y in weeksz * 365 = y * 52 ... (i)

Similarly, z in days = x in yearsz*365 = x ... (ii)

Also, x + y + z = 130 ... (iii)

Substituting the values of x, y and z in equation (iii) we get,

365*z + (365/52)*z + z = 130

Solving this we get z = 0.3485 in years = 127 days

So the child is 127 days old.

The pacelength P is the distance between the rear of two consecutive footprints. For men, the formula, n/P = 144 gives an approximate relationship between n and P where, n = number of steps per minute and P = pacelength in meters. Bernard knows his pacelength is 164cm. The formula applies to Bernard's walking. Calculate Bernard's walking speed in kmph.• • 236.16 • • 23.62• • 8.78• • 11.39n/P = 144n = 144 * PP = 1.64n = 144 * 1.64 = 236.16 approx 236 steps per minute we are taking n in integer for it represents no. of stepsnow v = d / tv = 1.64 * 236 meter/minutev = 387.04 meter / minuteor v = (387.04/1000)/(1/60)or v = 387.04*60/1000 = 23.2224

A hollow cube of size 5 cm is taken. with a thickness of 1 cm. it is made of smaller cubes of size 1 cm. if 4 faces of the outer surface of the cube are painted, totally how many faces of the smaller cubes remain unpainted?

900

500

488

800

The big cube is completely hollow.. But, the thickness ofits side is 1cm & this is made up of smaller cubes.

Just like the walls of a room. The room is hollow, but, itsthickness is due to smaller bricks. The 4 walls of this roomis painted from the outside. And, you are asked totally howmany sides of all the bricks are now unpainted.

First, you need to know how many bricks (small cubes) are there.

Size of big cube = 5cmTotal volume of the big cube = 5*5*5 = 125cm^3

Size of the hollow cube inside the big cube = 3cmVolume of the hollow space inside the big cube = 3*3*3 = 27cm^3

Therefore, volume occupied by small cubes (or volume ofthickness) = 125 - 27 = 98cm^3

Size of each small cube = 1cmVolume of each small cube = 1*1*1 = 1cm^3Total number of small cubes in wall = 98 / 1 = 98

In short, 98 small cubes make up the wall of the big cube.Each cube has 6 faces, so 98 cubes have = 98*6 faces = 588

The four sides of the big cube have 100 painted faces.Because each big side has 25 faces of the small cubes.

Therefore, total unpainted faces = 588 - 100 = 488

A Police car starts chasing a fugitive in a BMW 2 hours after the BMW escapes from the scene of crime at 10AM . The BMW drives for 10km through the crowded roads of Shanghai and then drives into a highway, where the traffic allows vehicles to move twice as fast. After a while, the police car finally catches up with the BMW after a chase that lasted 5 hours. By this time the moon was up in the sky for 4 hours . if the average speed of the police car is 94 kmph then the average speed of the BMW is______ kmph13.43

67.14

26.86

68.14police's car distance traveled in 5 hour = 5*94= 470 kmaverage speed of BMW is=470/7=67.17 kmh

A farm in Chennai has around 200 trees each separated by about 20m . tthese trees are home to many birds. There are 19 birds that weigh up to 15g, 46 that weigh from 15 to 50 g, and 28 that weigh greater thatn 50g, in the month of June, around 2 hours after sunset, after all birds have returned to their nests, a cunning fox finds its way into the farm. The fox takes a bird out of its nest at random. How many sparrows must the fox take out ot make sure that it has two of each weight rang?76.00

56.00

65.00

54.0076. taking worst case scenario. so we get 46+28+2.

9 years ago i was five times as old as my eldest son. Today i am 3 times his age. How oldam i now?18.0020.0055.0054.00 54 is the anslet present age of person is x and his son is ygiven 9 yeaars ago implies x-9=5(y-9)now,,x=3ysolving we get x=54 years

A lady has fine gloves and hats in her closet- 18 blue- 32 red and 25 yellow. The lights are out and itis totally dark inspite of the darkness. She can make out the difference between a hat and a glove. Shetakes out an item out of the closet only if she is sure that if it is a glove. How many gloves must shetake out to make sure she has a pair of each colour? 32+25+2=59

Susan made a block with small cubes of 5 cubic cm volume to make a block 7 small cubeslong, 7 small cubes wide and 6 small cubes deep. She realise that she has used more smallcubes than she really needed. She realised that she could have glued a fewer number ofcubes together ot look like a block with same dimensions, if it were made hollow. What is theminimum number of cubes that she needs to make the block?114.00194.00294.00100.00 INITIAL DEMENTION 7*7*6=294;NOW 5*5*4=100; THESE CUBES ARE INTERNAL CUBES AND THESE SHOULD BE REMOVED 

FROM THE TOTAL NO OF CUBES WE WILL GET OUTER SURFACE CUBES.HENCE 294-100=194;

In how many ways can 5 letters be posted in 3 post boxes, if any number of letters can be posted in all of the three post boxes?

A. 5 C 3

B. 5 P 3

C. 53

D. 35

E. 25

The correct choice is (D) and the correct answer is 35.

The first letter can be posted in any of the 3 post boxes. Therefore, it has 3 choices.

Similarly, the second, the third, the fourth and the fifth letter can each be posted in any of the 3 post boxes.

Therefore, the total number of ways the 5 letters can be posted in 3 boxes is 3*3*3*3*3= 35

A group of friends Tom, Teena, Dick, Tiana and Harry and Harriot, go out to a fair 300 meters from the Mc Donalds which is 5 Km away. They see a weighing machine and decide to have some fun. However, the girl refused to step on the weighing machine. So Tom, Dick and Harry way themselves in a particular order. First Tom, Dick and Harry wheigh themselves individually and then Tom and Dick, Dick and Harry, Tom and Harry and then Tom, Dick and Harry together respectively. The recorded weight for the last measure is 197 Kgs. The average of all the 7 measures is.

1. 253.292. 112.573. 140.714. 65.67112.57197*4/7=112.57

Earl can stuff advertising circulars into envelopes at the rate of 36 envelopes per minutes and Ellen requires a minutes and half to stuff the same number of envelops.Working together,how long will it take Earl and Ellen to stuff 360 envelopesa)6 minutesb)5 minutesc)7 minutesd)3 minutes earl takes 1 min. for 36 envelopes.ellen takes 3/2 mins for the same. so ellen can stuff ((36)/(2/3)) in 1 min. i.e., 24 envlpes a min.so both of them when work together can stuff 36+24=60 envelopes in 1 min.for 360 envelopes they will take 360/60 mins. i.e., 6 mins.

The chairman of Tata Motors, Ratan Tata, had 300 engineers work for 5 years designing the world's lowest-cost car,convinced that cost-conscious Indian drivers could live without air-conditioning and cup holders.However, after the booking started they found that only 23 percent of initial 253850 orders for the car-the nano-were for the no frills $2600 model.How much time(in days) would it have taken if there were 500 employees working for double the time?Let The Completeion Of Work Be "X" Working"x" Hrs A Day...So(300*5*x)/X=(500*Z*2*x)/X=>Z=1.5 Year...If Any One Of The Year Is Leap Year Days Will Be 365+182=547 dAYS...If Both Are Ordinary Years 365+181=546 Days...

Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is4310 Solution

4 is the correct answerthe first point equidistant to all the three lines will be incentre, the other 3 will be excentres of the triangle, formed on outside the 3 sides

9years ago, Andromeda’s age was twice Achillie’s age .9 years hence, Andromeda’s age will be 4/3 times the ageof Achilles’. Find Andromeda’s present age in binary numbers.Options 1)  11011 2)  11000 3)  1001

 4)  1010Let Andromeda's present age be x and Achille's present age be ySo, according to the first condition,x-9 = 2(y-9)........(A)According to the second condition,x+9 = 1.33(y+9).....(B)Solving A and B, we get x = 27 and y = 1827 in binary form = 11011Hence, option 1 

Elephant competitions are of great entertainment in south india.In one such competition held in cochin,200 elephants participated.Each elephant eas given equal amount of milk to drink for a certain time period.Whichever elephant could drink the maximum would be the winner.One of the elephants named Garru could drink 1/3 of the amount of milk offered.Another elephant named Marta could drink only 1/20 of the amount of milk offered,but it was better than Thorny which could drink 2/45 of the amount of milk offered.Amazingly Darru could drink 6 litres more than 1/4 of the amount of milk offered,where as Malar could drink 2/15 of the amount of milk offered.If the amount of milk left over by the elephants GARRU and Darru were same,then calculate the total amount of milk offered to each elephant.a)73.00 litresb)71.00 litresc)12.00 litresd)72.00 litres

amount of milk left by Darru= x-(6+x/4)amount of milk left by Garru=x-x/3these 2 equations are equal accornding to question. therefore solving we get the answer is 72.00 litres. so option D is correct

there are a dozen eggs in a basket.which of the option can't be possible for the ratio of broken eggs to unbroken eggs...?

OPTIONS:(a)1:4(b)1:3(c)1:5(d)1:1

the option a can,t be possible ratio as its sum i.e. 5 is not a factor of 12..

a multiple choice question has 4 options.choosing the correct option earns the student 3 marks and wrong option incurs negative marks, so that if a student chooses randomly his score is 0.suppose a student has eliminated 2 incorrect options.His score is if he chooses randomly among the remaining options -a)1 b)1.5 c)0 d)3

  There are two possibilities only -> Correct Answer or Wrong AnswerLet E be the expectation of the outome. There are four options. Probability of selecting any one = 1/4 = 0.25Then, E =  0.25*3 + 0.75*x = 0 (given)where x is the negative marks given to a wrong option selectedSolving, we get x = -1Now, two incorrect options have been eliminated.So, E = 0.5*3 + 0.5*(-1) = 1Hence, option 1 

19 people(a1,a2,….,a19)are invited to a party. The host and the hostess shake hands with each invitee and also with each other. The invitee shake hands in a circular fashion, i.e. the pairs(a1,a1),(a2,a3),….(a18,a19),(a19,a1)shake hands. So in all three are 58 handshakes. Let S be a set of people such that every pair in S shake hands. The size of S is at mosta.2b.3c.1d.4

here answer is 4. the set comprises host,hostress,any two other guests