EECS 247 Lecture 4: Filters © 2005 H.K. Page 1
EE247 Lecture 4
• Last lecture– Active biquads
• Sallen- Key & Tow-Thomas• Integrator based filters
– Signal flowgraph concept– First order integrator based filter– Second order integrator based filter &
biquads
– High order & high Q filters• Cascaded biquads
– Sensitivity of cascaded biquad
EECS 247 Lecture 4: Filters © 2005 H.K. Page 2
This Lecture
• Ladder Type Filters – For simplicity, will start with all pole ladder type filters
• Convert to integrator based form• Example shown
– Then will attend to high order ladder type filters incorporatingzeros• Implement the same 7th order elliptic filter in the form of ladder
RLC with zeros– Find level of sensitivity to component variations – Compare with cascade of biquads
• Convert to integrator based form utilizing SFG techniques• Example shown
• Effect of Integrator Non-Idealities on Filter Performance
EECS 247 Lecture 4: Filters © 2005 H.K. Page 3
LC Ladder FiltersLow-Pass RLC Filter
• Made of resistors, inductors, and capacitors• Doubly terminated (with Rs) or singly terminated (w/o Rs)
Doubly terminated LC ladder filters _ Lowest sensitivity to component variations when RS=RL
RsC1 C3
L2
C5
L4
inV RL
oV
EECS 247 Lecture 4: Filters © 2005 H.K. Page 4
LC Ladder FiltersLow-Pass RLC Filter
• Design:– CAD tools
• Matlab• Spice
– Filter tables• A. Zverev, Handbook of filter synthesis, Wiley, 1967.• A. B. Williams and F. J. Taylor, Electronic filter design, 3rd
edition, McGraw-Hill, 1995.
RsC1 C3
L2
C5
L4
inV RL
oV
EECS 247 Lecture 4: Filters © 2005 H.K. Page 5
LC Ladder Filter Design Example
Design a LPF with maximally flat passband:f-3dB = 10MHz, fstop = 20MHzRs >27dB
From: Williams and Taylor, p. 2-37
Stopband A
ttenuation dB
Νοrmalized ω
•Maximally flat passband c Butterworth•Determine minimum filter order :
-Use of Matlab-or Tables
•Here tables used
fstop / f-3dB = 2Rs >27dB
Minimum Filter Orderc5th order Butterworth
1
-3dB
2
EECS 247 Lecture 4: Filters © 2005 H.K. Page 6
LC Ladder Filter Design Example
From: Williams and Taylor, p. 11.3
Find values for L & C from Table:Note L &C values normalized to
ω-3dB =1Denormalization:
Multiply all LNorm, CNorm by:Lr = R/ω-3dB
Cr = 1/(RXω-3dB )
R is the value of the source and termination resistor (choose both 1Ω for now)
Then: L= Lr xLNorm
C= Cr xCNorm
EECS 247 Lecture 4: Filters © 2005 H.K. Page 7
LC Ladder Filter Design Example
From: Williams and Taylor, p. 11.3
Find values for L & C from Table:Normalized values:C1Norm =C5Norm =0.618C3Norm = 2.0
L2Norm = L4Norm =1.618
Denormalization:
Since ω-3dB =2πx10MHzLr = R/ω-3dB = 15.9 nH
Cr = 1/(RXω-3dB )= 15.9 nF
R =1
cC1=C5=9.836nF, C3=31.83nF
cL2=L4=25.75nH
EECS 247 Lecture 4: Filters © 2005 H.K. Page 8
Low-Pass RLC FilterMagnitude Response Simulation
Frequency [MHz]
Mag
nitu
de (
dB)
0 10 20 30
-50
-40
-30
-20
-10-50
-6 dB passband attenuationdue to double termination
30dB
Rs=1Ohm
C19.836nF
C331.83nF
L2=25.75nH
C59.836nF
L4=25.75nH
inV RL=1Ohm
oV
SPICE simulation Results
EECS 247 Lecture 4: Filters © 2005 H.K. Page 9
Low-Pass RLC Ladder FilterConversion to Integrator Based Active Filter
1I2V
RsC1 C3
L2
C5
L4
inV RL
4V 6V
3I 5I
2I4I 6I
7I
• Use KCL & KVL to derive equations:
1V+ − 3V+ − 5V+ −oV
1 in 2
1 31 3
25 6
5 74
I2V V V , V , V V V2 3 2 4sC1I I4 6V , V V V , V V V4 5 4 6 6 o 6sC sC3 5
V VI , I I I , I2 1 3Rs sL
V VI I I , I , I I I , I4 3 5 6 5 7sL RL
= − = = −
= = − = =
= = − =
= − = = − =
EECS 247 Lecture 4: Filters © 2005 H.K. Page 10
Low-Pass RLC Ladder FilterSignal Flowgraph
SFG
1Rs 1
1
sC
2I1I
2VinV 1−1
1
1V oV1− 11
3
1
sC 5
1
sC2
1
sL 4
1
sL
1RL
1− 1− 1−1 1
1− 13V 4V 5V 6V
3I 5I4I 6I 7I
1 in 2
1 31 3
25 6
5 74
I2V V V , V , V V V2 3 2 4sC1I I4 6V , V V V , V V V4 5 4 6 6 o 6sC sC3 5
V VI , I I I , I2 1 3Rs sL
V VI I I , I , I I I , I4 3 5 6 5 7sL RL
= − = = −
= = − = =
= = − =
= − = = − =
EECS 247 Lecture 4: Filters © 2005 H.K. Page 11
Low-Pass RLC Ladder FilterSignal Flowgraph
SFG
1Rs 1
1
sC
2I1I
2VinV 1−1
1
1V oV1− 11
3
1
sC 5
1
sC2
1
sL 4
1
sL
1RL
1− 1− 1−1 1
1− 13V 4V 5V 6V
3I 5I4I 6I 7I
1I2V
RsC1 C3
L2
C5
L4
inV RL
4V 6V
3I 5I
2I4I 6I
7I1V+ − 3V+ − 5V+ −
EECS 247 Lecture 4: Filters © 2005 H.K. Page 12
Low-Pass RLC Ladder FilterNormalize
1
1
*RRs
*1
1
sC R
'1V
2VinV 1−1 1V oV1− 1
*
2
R
sL
1− 1− 1−1 1
1− 13V 4V 5V 6V
'3V'
2V '4V '
5V '6V '
7V
*3
1
sC R
*
4
R
sL*
5
1
sC R
*RRL
1Rs 1
1
sC
2I1I
2VinV 1−1
1
1V oV1− 11
3
1
sC 5
1
sC2
1
sL 4
1
sL
1RL
1− 1− 1−1 1
1− 13V 4V 5V 6V
3I 5I4I 6I 7I
EECS 247 Lecture 4: Filters © 2005 H.K. Page 13
Low-Pass RLC Ladder FilterSynthesize
1
1
1
*RRs
*1
1
sC R
'1V
2VinV 1−1 1V oV1− 1
*
2
R
sL
1− 1− 1−1 1
1− 13V 4V 5V 6V
'3V'
2V '4V '
5V '6V '
7V
*3
1
sC R
*
4
R
sL*
5
1
sC R
*RRL
inV
1+ -
-+ -+
+ - + -
*R Rs−
*R RL21
sτ 31
sτ 41
sτ 51
sτ11
sτ
oV2V 4V 6V
'3V '
5V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 14
Low-Pass RLC Ladder FilterIntegrator Based Implementation
* * * * *2* *
L L4C C C C.R , .R , .R , .R , C .R11 2 2 3 3 4 4 5 5R R
τ τ τ τ τ= = = = = = =
Building Block:RC Integrator
V 12V sRC1
= −
inV
1+ -
-+ -+
+ - + -
*R Rs−
*R RL21
sτ 31
sτ 41
sτ 51
sτ11
sτ
oV2V 4V 6V
'3V '
5V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 15
Negative Resistors
V1-
V2-
V2+
V1+
Vo+
Vo-
V1-
V2+Vo+
EECS 247 Lecture 4: Filters © 2005 H.K. Page 16
Synthesize
oV
4V
'3V
'5V
2V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 17
Frequency Response
oV
4V
'3V
'5V
2V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 18
Scale Node Voltages
Scale Vo by factor “s”
oV
4V
'3V
'5V
2V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 19
Maximizing Signal Handling by Node Voltage Scaling
Scale Vo by factor “s”
EECS 247 Lecture 4: Filters © 2005 H.K. Page 20
Filter Noise
Total noise @ the output: 1.4 µV rms(noiseless opamps)
That’s excellent, but the capacitors are very large (and the resistors small à high power dissipation). Not possible to integrate.
Suppose our application allows higher noise in the order of 140 µV rms …
EECS 247 Lecture 4: Filters © 2005 H.K. Page 21
Scale to Meet Noise TargetScale capacitors and resistors to meet noise objective
s = 10-4
Noise: 141 µV rms (noiseless opamps)
EECS 247 Lecture 4: Filters © 2005 H.K. Page 22
Completed Design
5th order ladder filterFinal design utilizing:
-Node scaling -Final R & C scaling based on noise considerations
oV
4V
'3V
'5V
2V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 23
Sensitivity
• C1 made (arbitrarily) 50% (!) larger than its nominal value
• 0.5 dB error at band edge
• 3.5 dB error in stopband
• Looks like very low sensitivity
EECS 247 Lecture 4: Filters © 2005 H.K. Page 24
inVDifferential 5th Order Lowpass Filter
•Since each signal and its inverse readily available, eliminates the need for negative resistors!•Differential design has the advantage of even order harmonic distortion and common mode spurious pickup automatically cancels•Disadvantage: Double resistor and capacitor area!
+
+
--
+
+
--
+
+--+
+--
+
+
--
inV
oV
EECS 247 Lecture 4: Filters © 2005 H.K. Page 25
RLC Ladder FiltersIncluding Transmission Zeros
RsC1 C3
L2
C5
L4
inV RLC7
L6
C2 C4 C6
oV
RsC1 C3
L2
C5
L4
inV RL
oVAll poles
Poles & Zeros
EECS 247 Lecture 4: Filters © 2005 H.K. Page 26
RLC Ladder Filter Design Example
• Design a baseband filter for CDMA IS95 receiver with the following specs.– Filter frequency mask shown on the next page– Allow enough margin for manufacturing variations
• Assume pass-band magnitude variation of 1.8dB• Assume the -3dB frequency can vary by +-8% due to
manufacturing tolerances
– Assume any phase impairment can be compensated in the digital domain
* Note this is the same example as for cascade of biquad while the specifications are given closer to a real industry case
EECS 247 Lecture 4: Filters © 2005 H.K. Page 27
RLC Ladder Filter Design ExampleCDMA IS95 Receive Filter Frequency Mask
+10
-1
Frequency [Hz]
Mag
nit
ud
e (d
B)
-44
-46
600k 700k 900k 1.2M
EECS 247 Lecture 4: Filters © 2005 H.K. Page 28
RLC Ladder Filter DesignExample: CDMA IS95 Receive Filter
• Since phase impairment can be corrected for, use filter type with max. cut-off slope/pole
à Elliptic• Design filter freq. response to fall well within the freq. mask
– Allow margin for component variations• For the passband ripple, allow enough margin for ripple change
due to component & temperature variationsà Passband ripple 0.2dB
• For stopband rejection add a few dB margin 44+4=48dB• Design to spec.:
– fpass = 650 kHz Rpass = 0.2 dB– fstop = 750 kHz Rstop = 48 dB
• Use Matlab or filter tables to decide the min. order for the filter (same as cascaded biquad example)– 7th Order Elliptic
EECS 247 Lecture 4: Filters © 2005 H.K. Page 29
RLC Low-Pass Ladder Filter DesignExample: CDMA IS95 Receive Filter
RsC1 C3
L2
C5
L4
inV RLC7
L6
C2 C4 C6
oV
7th order Elliptic
• Use filter tables to determine LC values
EECS 247 Lecture 4: Filters © 2005 H.K. Page 30
RLC Ladder Filter DesignExample: CDMA IS95 Receive Filter
• Spec.– fpass = 650 kHz Rpass = 0.2 dB– fstop = 750 kHz Rstop = 49 dB
• Use filter tables to determine LC values – Table from: A. Zverev, Handbook of filter synthesis, Wiley,
1967– Elliptic filters tabulated wrt “reflection coeficient ρ”
– Since Rpass=0.2dBà ρ =20%– Use table accordingly
( )2Rpass 10 log 1 ρ= − × −
EECS 247 Lecture 4: Filters © 2005 H.K. Page 31
RLC Ladder Filter DesignExample: CDMA IS95 Receive Filter
• Table from Zverev book page #281 & 282:
• Since our spec. is Amin=44dB add 5dB margin & design for Amin=49dB
EECS 247 Lecture 4: Filters © 2005 H.K. Page 32
• Table from Zverev page #281 & 282:
• Normalized component values:C1=1.17677C2=0.19393L2=1.19467C3=1.51134C4=1.01098L4=0.72398C5=1.27776C6=0.71211L6=0.80165C7=0.83597
EECS 247 Lecture 4: Filters © 2005 H.K. Page 33
-65
-55
-45
-35
-25
-15
-5
200 300 400 500 600 700 800 900 1000 1100 1200
RLC Filter Frequency Response
•Frequency mask superimposed•Frequency response well within spec.
Frequency [kHz]
Mag
nit
ud
e (d
B)
EECS 247 Lecture 4: Filters © 2005 H.K. Page 34
Passband Detail
-7.5
-7
-6.5
-6
-5.5
-5
200 300 400 500 600 700 800
•Passband well within spec.
Frequency [kHz]
Mag
nit
ud
e (d
B)
EECS 247 Lecture 4: Filters © 2005 H.K. Page 35
RLC Ladder Filter Sensitivity
• The design has the same spec.s as the previous example implemented with cascaded biquads
• To compare the sensitivity of RLC ladder versus cascaded-biquads:– Changed all Ls &Cs one by one by 2% in order to
change the pole/zeros by 1% (similar test as for cascaded biquad)
– Found frequency response à most sensitive to L4 variations
– Note that by varying L4 both poles & zeros are varied
EECS 247 Lecture 4: Filters © 2005 H.K. Page 36
RCL Ladder Filter Sensitivity
Component variation in RLC filter:– Increase L4 by 2%– Decrease L4 by 2%
-65
-55
-45
-35
-25
-15
-5
200 300 400 500 600 700 800 900 1000 1100 1200
Frequency [kHz]
Mag
nit
ud
e (d
B)
L4 nomL4 lowL4 high
EECS 247 Lecture 4: Filters © 2005 H.K. Page 37
RCL Ladder Filter Sensitivity
-6.5
-6.3
-6.1
-5.9
-5.7
200 300 400 500 600 700
-65
-60
-55
-50
600 700 800 900 1000 1100 1200
Frequency [kHz]
Mag
nitu
de (
dB)
1.7dB
0.2dB
-65
-55
-45
-35
-25
-15
-5
200 300 400 500 600 700 800 900 1000 1100 1200
EECS 247 Lecture 4: Filters © 2005 H.K. Page 38
-10
Cascade of Biquads SensitivityComponent variation in Biquad 4 (highest Q pole):
– Increase ωp4 by 1%
– Decrease ωz4 by 1%
High Q poles à High sensitivityin Biquad realizations
Frequency [Hz]1MHz
Mag
nitu
de (
dB)
-30
-40
-20
0
200kHz
3dB
600kHz
-50
2.2dB
EECS 247 Lecture 4: Filters © 2005 H.K. Page 39
Sensitivity Comparison for Cascaded-Biquads versus RLC Ladder
• 7th Order elliptic filter – 1% change in pole & zero pair
1.7dB(21%)
3dB(40%)
Stopband deviation
0.2dB(2%)
2.2dB (29%)
Passband deviation
RLC LadderCascadedBiquad
Doubly terminated LC ladder filters _ Significantly lower sensitivity compared to cascaded-biquads particularly within the passband
EECS 247 Lecture 4: Filters © 2005 H.K. Page 40
RLC Ladder Filter DesignExample: CDMA IS95 Receive Filter
RsC1 C3
L2
C5
L4
inV RLC7
L6
C2 C4 C6
oV
7th order Elliptic
• Previously designed integrator based ladder filters without transmission zerosàQuestion:
How do we implement the transmission zeros in the integrator-based version?
EECS 247 Lecture 4: Filters © 2005 H.K. Page 41
Integrator Based Ladder FiltersHow Do We Implement Transmission zeros?
• Use KCL & KVL to derive :
1I 2V
RsC1 C3
L2
inV RL
4V
3I5I
2I4I
1V+ − 3V+ −
Ca
oV
( )
( )
CI I1 3 aV V2 4C Cs C C1 1a a
CI I3 5 aV V4 2C Cs C C3 a 3 a
−= +
+ +
−= +
+ +
Voltage Controlled Voltage Source!
EECS 247 Lecture 4: Filters © 2005 H.K. Page 42
Integrator Based Ladder FiltersTransmission zeros
1I 2V
( )
( )
CI I1 3 aV V2 4C Cs C C1 1a aCI I3 5 aV V4 2C Cs C C3 a 3 a
−= +
+ +
−= +
+ +
Rs L2
inV RL
4V
3I5I
2I 4I
1V+ − 3V+ −
Ca
• Replace shunt capacitor with voltage controlled voltage sources:
+-
( )C C1 a+ ( )C C3 a+
CaV4 C C1 a+CaV2 C C3 a+
+-
EECS 247 Lecture 4: Filters © 2005 H.K. Page 43
LC Ladder FiltersTransmission zeros
1I 2V
Rs L2
inVRL
4V
3I5I
2I 4I
1V+ − 3V+ −
( )C C1 a+ ( )C C3 a+
CaV4 C C1 a+CaV2 C C3 a+
1Rs ( )1 aC C
1
s +
2I1I
2VinV 1−1
1
1V oV1− 11
( )3 a
1
s C C+2
1
sL1
RL
1− 1−1
3V 4V
3I 4I
oV
CaC C1 a+
CaC C3 a+
+- +-
EECS 247 Lecture 4: Filters © 2005 H.K. Page 44
Integrator Based Ladder FiltersHigher Order Transmission zeros
C1
2V 4V
C3
Ca6VCb
2V 4V
+- +-
( )C C1 a+ ( )C C C3 a b+ +
CaV4 C C1 a+
CaV2 C C3 a+
6V
+-
( )C C5 b+
CbV4 C C3 b++-CbV6 C C3 b+
C5Convert zero generating Cs in C loops to voltage-controlled voltage sources
EECS 247 Lecture 4: Filters © 2005 H.K. Page 45
Higher Order Transmission zeros
*RRs ( )1 aC C
1*s R+
2VinV 1−1
1
1V oV1− 11
( )3 a b
1*s C C CR + +
*
2
R
sL
*RRL
1− 1−1
3V 4V
CaC C1 a+
CaC C3 a+
1−*
4
R
sL
1
5V 6V
RL1I
2V
Rs L2
inV
4V
3I5I
2I
4I1V+ − 3V+ −
+-
+-( )C C1 a+ ( )C C C3 a b+ +
CaV4 C C1 a+
CaV2 C C3 a+
oVL4
6V 7I
6I
5V+ −
+-
( )C C5 b+
CbV4 C C5 b++- CbV6 C C3 b+
( )5 bC C
1*sR +
CbC C3 b+ Cb
C C5 b+
1
1−'1V '
3V'2V '
4V'
5V '6V '
7V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 46
Example:5th Order Chebyshev II Filter
• 5th order Chebyshev II
• Table from: Williams & Taylor book, p. 11.112
• 50dB stopband attenuation
• f-3dB =10MHz
EECS 247 Lecture 4: Filters © 2005 H.K. Page 47
Realization with Integrator
( )i 1 a2
1 3*s a 1a 1
V V CV1V VR C Cs C C R− = − + ++
EECS 247 Lecture 4: Filters © 2005 H.K. Page 48
5th Order Butterworth Filter
From:Lecture 4page 22
oV
4V
'3V
'5V
2V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 49
Opamp-RC Simulation
oV
4V
'3V
'5V
2V
EECS 247 Lecture 4: Filters © 2005 H.K. Page 50
Seventh Order Differential Low-Pass Filter Including Transmission Zeros
+
+
--
+
+
--
+
+--
+
+
--
+
+--
+
+
--
+
+--
inV
oV
Transmission zeros implemented with coupling capacitors
EECS 247 Lecture 4: Filters © 2005 H.K. Page 51
Effect of Integrator Non-Idealities on Filter Performance
Ideal Intg.
opamp DC gain
oH( s )s
1/ RCo
ω
ω
=−
=
=
∞
oV
C
inV
-
+R
EECS 247 Lecture 4: Filters © 2005 H.K. Page 52
Ideal Integrator Quality Factor
o oH( s )s j
ω ω
ω
− −= =
( ) ( ) ( )( )( )
1H jR jX
XQ
R
ωω ω
ωω
=+
=
Ideal Intg.
Since Q is defined as:
Then: int g.Qideal =∞
EECS 247 Lecture 4: Filters © 2005 H.K. Page 53
Effect of Integrator Non-Idealities on Filter PerformanceIdeal Intg. Real Intg.
a
( )( )( )o
os sa
p2 p3
aH( s ) H( s )
1 11 ss . . .ω
ω− −= ≈
+ ++
EECS 247 Lecture 4: Filters © 2005 H.K. Page 54
Effect of Integrator Finite DC Gain on Q
-90
-89.5
ωoω
o( i n r a d i a n )
P1
P1 o
Arctan2 o
Phase lead @ω
π
ω
ω− +
→
∠
Example: P1/ ω0 =1/100
0P1 aω=
0ω
a
-90o
( )log H s
ψ
EECS 247 Lecture 4: Filters © 2005 H.K. Page 55
Effect of Integrator Finite DC Gain on Q
• Phase lead @ ω0
àDroop in the passband
Normalized Frequency
Mag
nitu
de (
dB)
1
Droop in the passband
EECS 247 Lecture 4: Filters © 2005 H.K. Page 56
Effect of Integrator Non-Dominant Poles
-90
-90.5
ωoω
oi
oi
pi 2
opi 2( in rad ian )
Arctan2
Phase lag @
ω
ω
π
ω
∞
=
∞
=
− −
→
∑
∑
∠
Example: ω0 /P2 =1/100
0ω
-90o
( )log H s
ψ
P2P3
EECS 247 Lecture 4: Filters © 2005 H.K. Page 57
Effect of Integrator Non-Dominant Poles
Normalized Frequency
Mag
nitu
de (
dB)
1
• Phase lag @ ω0
àPeaking in the passbandIn extreme cases could result in oscillation!
Peaking in the passband
EECS 247 Lecture 4: Filters © 2005 H.K. Page 58
Effect of Integrator Non-Dominant Poles & Finite DC Gain on Q
-90
ωoω
P1Arctan2 o
oArctan pii 2
πω
ω
∠ − +
∞− ∑
=
0ω
a
-90o
( )log H s
ψ
P2P30P1 a
ω=
-90o
( )log H s
ψ
Note that the two terms have different signs à Can cancel each other’s effect
EECS 247 Lecture 4: Filters © 2005 H.K. Page 59
Integrator Quality Factor
( )( )( )os sa
p2 p3
aH( s )
1 11 s . . .ω
−≈
+ ++Real Intg.
o 1 & a 1p2,3,. . . . .
int g. 1Qreal1 1
oa pii 2
ω
ω
<< >>
≈ ∞− ∑
=
Based on the definition of Q and assuming that:
It can be shown that in the vicinity of unity-gain-frequency:
Phase lead @ ω0 Phase lag @ ω0
EECS 247 Lecture 4: Filters © 2005 H.K. Page 60
Example:Effect of Integrator Finite Q on Bandpass Filter Behavior
Integrator DC gain=100 Integrator P2 @ 100.ωo
IdealIdeal
EECS 247 Lecture 4: Filters © 2005 H.K. Page 61
Example:Effect of Integrator Finite Q on Filter Behavior
Integrator DC gain=100 & P2 @ 100. ωο
Ideal
EECS 247 Lecture 4: Filters © 2005 H.K. Page 62
SummaryEffect of Integrator Non-Idealities on Q
• Amplifier DC gain reduces the overall Q in the same manner as series/parallel resistance associated with passive elements
• Amplifier poles located above integrator unity-gain frequency enhance the Q! – If non-dominant poles close to unity-gain freq. à Oscillation
• Depending on the location of unity-gain-frequency, the two terms can cancel each other out!
i1 1o pi 2
int g.ideal
int g. 1real
Q
Q
a ω∞
=
=
≈−
∞
∑