8/18/2019 Updated Case Study on Spc-sqc

1/13

  ASE STUDY ON

ASE STUDY ON

SP / SQP / SQ

TE HNIQUES

E HNIQUES

8/18/2019 Updated Case Study on Spc-sqc

2/13

STORE:PRIMER NO.12STORE:PRIMER NO.12 MULTI DECO CNC M/C NO.MULTI DECO CNC M/C NO.1036410364

COMPONENT:BODYCOMPONENT:BODY USL=16.027USL=16.027LSL=15.926LSL=15.926

OPERATION:COMPLETEOPERATION:COMPLETE PARAMETER:TOTALPARAMETER:TOTALLENGTLENGT

!RE"UENCY:60 MIN!RE"UENCY:60 MIN

8/18/2019 Updated Case Study on Spc-sqc

3/13

ONLINE DATA FOR SP BY

NLINE DATA FOR SP BY

ONTROL HARTS

  ONTROL HARTS

SLNOSLNO #1#1 #2#2 #3#3 #4#4 #5#5 # BAR# BAR RR

11 15.9615.96 15.9$15.9$ 15.9615.96 15.9$15.9$ 15.9615.96 15.96$15.96$ 0.020.02

22 15.9415.94 15.9715.97 15.9715.97 15.9615.96 15.9415.94 15.95615.956 0.030.03

33 15.9615.96 15.9$15.9$ 15.9715.97 15.9$15.9$ 15.9$15.9$ 15.97415.974 0.020.02

44 15.9615.96 15.9715.97 15.9615.96 15.9715.97 15.9715.97 15.96615.966 0.010.01

55 15.9$15.9$ 15.9$15.9$ 15.9615.96 15.9715.97 15.9615.96 15.97215.972 0.020.02

66 15.9615.96 15.9715.97 15.9615.96 15.9715.97 15.9715.97 15.96615.966 0.010.01

8/18/2019 Updated Case Study on Spc-sqc

4/13

STEPS FOR X BAR HART

TEPS FOR X BAR HART

AND R HART

ND R HART

 # = 15.967

R = 0.01$3

CALCULATE UPPER CONTROL LIMIT %UCL& AND

LO'ER CONTROL LIMIT %LCL& !OR # BAR CAR AND R CART

  # CART R( CART

UCL = # )A2 R D4 # R

 

LCL = # * A2 R D3 # R

%A2+ D3 , D4 ARE STANDARD -ALUE&

COMPUTE # AND R

8/18/2019 Updated Case Study on Spc-sqc

5/13

  OMPUTE U L &L L

OMPUTE U L &L L

  FOR X BAR CHARTFOR X BAR CHART

UCL = 15.967 ) 0.577 0.01$3 = 15.977UCL = 15.967 ) 0.577 0.01$3 = 15.977

LCL = 15.967 * 0.577 0.01$3 = 15.956LCL = 15.967 * 0.577 0.01$3 = 15.956

FOR R CHARTFOR R CHART

UCL = 2.115 0.01$3 = 0.03$7UCL = 2.115 0.01$3 = 0.03$7

LCL = 0 0.0.01$3 = 0LCL = 0 0.0.01$3 = 0

8/18/2019 Updated Case Study on Spc-sqc

6/13

USL

LSL

X BAR CHARTX BAR CHART

8/18/2019 Updated Case Study on Spc-sqc

7/13

R CHARTR CHART

8/18/2019 Updated Case Study on Spc-sqc

8/13

INTERPRETATION OF X BAR

HART AND R HART

  TE PROCESS IS IN CONTROL ASTE PROCESS IS IN CONTROL ASBOT TE CART SO'S A STATEBOT TE CART SO'S A STATE

O! CONTROL.O! CONTROL.

8/18/2019 Updated Case Study on Spc-sqc

9/13

PRO ESS APABILITY

RO ESS APABILITY

INDEXNDEX

C=TOLERANCE / 6 SIGMAC=TOLERANCE / 6 SIGMA

  = USL(LSL / 6 SIGMA= USL(LSL / 6 SIGMA

SIGMA= R BAR / 2 %2 8&SIGMA= R BAR / 2 %2 8&

  = 0.01$3 / 2.326 = 0.007$= 0.01$3 / 2.326 = 0.007$

8/18/2019 Updated Case Study on Spc-sqc

10/13

  OMPUTE p & pk

OMPUTE p & pk

C=16.027 * 15.926 / 6 SIGMAC=16.027 * 15.926 / 6 SIGMA

  == 2.1582.158

C=M;C=M;

8/18/2019 Updated Case Study on Spc-sqc

11/13

  OMPARISON OF SIGMA

OMPARISON OF SIGMA

QUALITY LEVELS

UALITY LEVELS

Quality LevelQuality Level CpCp Defective PPDefective PP

2 S;>?2 S;>? 0.170.17 30$53$30$53$

3 S;>?3 S;>? 0.500.50 66$0766$07

4 S;>?4 S;>? 0.$30.$3 62106210

5 S;>?5 S;>? 1.171.17 233233

! "i#$a! "i#$a 1.5%1.5% &.'&.'

8/18/2019 Updated Case Study on Spc-sqc

12/13

TE -ALUE O! C = 2.15$TE -ALUE O! C = 2.15$

TE -ALUE O! C= 1.752TE -ALUE O! C= 1.752

TIS INDICATE TAT PROCESSTIS INDICATE TAT PROCESS"UALITY LE-EL IS ABO-E 6 SIGMA"UALITY LE-EL IS ABO-E 6 SIGMALE-EL.LE-EL.

INTERPRETATION OF p

AND pk INDEX

8/18/2019 Updated Case Study on Spc-sqc

13/13