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Fluid Properties and Units
Fluid Properties and Units
CVEN 311CVEN 311
ContinuumContinuum
All materials, solid or fluid, are composed of molecules discretely spread and in continuous motion.
However, in dealing with fluid-flow relations on a mathematical basis, it is necessary to replace the actual molecular structure by a hypothetical continuous medium, called the continuum.
All materials, solid or fluid, are composed of molecules discretely spread and in continuous motion.
However, in dealing with fluid-flow relations on a mathematical basis, it is necessary to replace the actual molecular structure by a hypothetical continuous medium, called the continuum.
ContinuumContinuum
In a continuum, the physical variable at a point in space is the averaged value of the variable in a small sphere.
How good is the assumption?
In a continuum, the physical variable at a point in space is the averaged value of the variable in a small sphere.
How good is the assumption?
10-3cm
3x1010 molecules of air
Dimensions and UnitsDimensions and Units
The dimensions have to be the same for each term in an equation
Dimensions of mechanics are length time mass force temperature
The dimensions have to be the same for each term in an equation
Dimensions of mechanics are length time mass force temperature
aF m aF m
L
T
MMLT-2
Dimensions and UnitsDimensions and Units
Quantity SymbolDimensionsVelocity V LT-1
Acceleration a LT-2
Area A L2
Volume L3
Discharge Q L3T-1
Pressure p ML-1T-2
Gravity g LT-2
Temperature T’ Mass concentration C ML-3
Quantity SymbolDimensionsVelocity V LT-1
Acceleration a LT-2
Area A L2
Volume L3
Discharge Q L3T-1
Pressure p ML-1T-2
Gravity g LT-2
Temperature T’ Mass concentration C ML-3
Dimensions and UnitsDimensions and Units
Quantity Symbol DimensionsDensity ML-3
Specific Weight ML-2T-2
Dynamic viscosity ML-1T-1
Kinematic viscosity L2T-1
Surface tension MT-2
Bulk mod of elasticity E ML-1T-2
These are _______ properties!fluid
How many independent properties? _____4
Definition of a FluidDefinition of a Fluid
“a fluid, such as water or air, deforms continuously when acted on by shearing stresses of any magnitude.” - Munson, Young, Okiishi
“a fluid, such as water or air, deforms continuously when acted on by shearing stresses of any magnitude.” - Munson, Young, Okiishi
WaterOilAirWhy isn’t steel a fluid?
WaterOilAirWhy isn’t steel a fluid?
Fluid Deformation between Parallel Plates
Fluid Deformation between Parallel Plates
Side viewSide view
Force F causes the top plate to have velocity U.Force F causes the top plate to have velocity U.What other parameters control how much force is What other parameters control how much force is required to get a desired velocity?required to get a desired velocity?
Distance between plates (b)Distance between plates (b)
Area of plates (A)Area of plates (A)
F
b
U
Viscosity!Viscosity!
Shear StressShear Stress
change in velocity with respect to distancechange in velocity with respect to distance
AFAF
2m
N
2m
N
b
U b
U b
Ub
U
dydu dydu
b
AUF
b
AUF AU
FtAUFt
2m
sN
2m
sNdimension of
s
1
s
1
Tangential force per unit area
Rate of angular deformation
rate of shear
Fluid classification by response to shear stress
Fluid classification by response to shear stress
Newtonian Ideal Fluid Ideal plastic
Newtonian Ideal Fluid Ideal plastic
NewtonianIdeal Fluid
Ideal plastic
Shear stress Shear stress
Rat
e of
def
orm
atio
nR
ate
of d
efor
mat
ion
dydu
dydu dydu
1
Fluid ViscosityFluid Viscosity
Examples of highly viscous fluids ______________________
Fundamental mechanisms Gases - transfer of molecular momentum
Viscosity __________ as temperature increases. Viscosity __________ as pressure increases.
Liquids - cohesion and momentum transfer Viscosity decreases as temperature increases. Relatively independent of pressure (incompressible)
Examples of highly viscous fluids ______________________
Fundamental mechanisms Gases - transfer of molecular momentum
Viscosity __________ as temperature increases. Viscosity __________ as pressure increases.
Liquids - cohesion and momentum transfer Viscosity decreases as temperature increases. Relatively independent of pressure (incompressible)
molasses, tar, 20w-50 oil
increases
_______
increases
Example: Measure the viscosity of water
Example: Measure the viscosity of water
The inner cylinder is 10 cm in diameter and rotates at 10 rpm. The fluid layer is 2 mm thick and 10 cm high. The power required to turn the inner cylinder is 50x10-6 watts. What is the dynamic viscosity of the fluid?
The inner cylinder is 10 cm in diameter and rotates at 10 rpm. The fluid layer is 2 mm thick and 10 cm high. The power required to turn the inner cylinder is 50x10-6 watts. What is the dynamic viscosity of the fluid?
Outer Outer cylindercylinder
Thin layer of waterThin layer of water
Inner Inner cylindercylinder
Solution SchemeSolution Scheme
Restate the goal Identify the given parameters and represent the
parameters using symbols Outline your solution including the equations describing
the physical constraints and any simplifying assumptions
Solve for the unknown symbolically Substitute numerical values with units and do the
arithmetic Check your units! Check the reasonableness of your answer
Restate the goal Identify the given parameters and represent the
parameters using symbols Outline your solution including the equations describing
the physical constraints and any simplifying assumptions
Solve for the unknown symbolically Substitute numerical values with units and do the
arithmetic Check your units! Check the reasonableness of your answer
Solution
Role of ViscosityRole of Viscosity
Statics Fluids at rest have no relative motion between
layers of fluid and thus du/dy = 0 Therefore the shear stress is _____ and is
independent of the fluid viscosity Flows
Fluid viscosity is very important when the fluid is moving
Statics Fluids at rest have no relative motion between
layers of fluid and thus du/dy = 0 Therefore the shear stress is _____ and is
independent of the fluid viscosity Flows
Fluid viscosity is very important when the fluid is moving
zerozero
Dynamic and Kinematic Viscosity
Dynamic and Kinematic Viscosity
Kinematic viscosity (__) is a fluid property obtained by dividing the dynamic viscosity (__) by the fluid density
Kinematic viscosity (__) is a fluid property obtained by dividing the dynamic viscosity (__) by the fluid density
3mkg
smkg
3mkg
smkg
2m
sN
2m
sN
2s
mkgN
2s
mkgN
[m2/s]
Connection to Reynolds number!
mm
nn
ReVDrm
=ReVDrm
=
Density and Specific WeightDensity and Specific Weight
Density (mass/unit volume) density of water: density of air at
atmospheric pressure and 15 C:
Specific Weight (weight per unit volume) __________________
Density (mass/unit volume) density of water: density of air at
atmospheric pressure and 15 C:
Specific Weight (weight per unit volume) __________________
950960970980990
1000
0 50 100Temperature (C)
Den
sity
(kg
/m3 )
997
998
999
1000
0 10 20
Temperature (C)
Den
sity
(kg
/m3 )
1000 kg/m3
1.22 kg/m3
= g = 9806 N/m3
Specific mass
Perfect Gas LawPerfect Gas Law
PV = nRT R is the universal gas constant T is in Kelvin
PV = nRT R is the universal gas constant T is in Kelvin
Note deviation from the text!Note deviation from the text!
R
8 314.N m
mol K
Use absolute pressure for P and absolute temperature for T
Bulk Modulus of ElasticityBulk Modulus of Elasticity
Relates the change in volume to a change in pressure changes in density at
high pressure pressure waves
_________ ______ __________
Relates the change in volume to a change in pressure changes in density at
high pressure pressure waves
_________ ______ __________ 2.00
2.05
2.10
2.15
2.20
2.25
2.30
2.35
0 20 40 60 80 100
Temperature (C)
Bul
k M
odul
us o
f el
asti
city
(G
Pa)
soundsoundwater hammerwater hammer
Edp
dv /
Edp
dV Vv /
Water
-
vE
a
vEa speed of soundspeed of sound
Vapor PressureVapor Pressure
0
1000
2000
3000
4000
5000
6000
7000
8000
0 10 20 30 40
Temperature (C)
Vap
or p
ress
ure
(Pa)
liquid
What is vapor pressure of water at 100°C?101 kPa
Connection forward to cavitation!
CavitationCavitation
Cavitation DamageCavitation Damage
pR2 = 2R
Surface TensionSurface Tension
Pressure increase in a spherical droplet
Pressure increase in a spherical droplet
Rp
2R
p2
pR2
2R
Surface moleculesSurface molecules
0.0500.0550.0600.0650.0700.0750.080
0 20 40 60 80 100
Temperature (C)
Sur
face
tens
ion
(N/m
)
Example: Surface TensionExample: Surface Tension
Estimate the difference in pressure (in Pa) between the inside and outside of a bubble of air in 20ºC water. The air bubble is 0.3 mm in diameter.
Estimate the difference in pressure (in Pa) between the inside and outside of a bubble of air in 20ºC water. The air bubble is 0.3 mm in diameter.
Rp
2R
p2
R = 0.15 x 10-3 mR = 0.15 x 10-3 m
= 0.073 N/m = 0.073 N/m
m1015.0
N/m 073.023
p
m1015.0
N/m 073.023
p
970 Pap =970 Pap =
What is the difference between pressure in a water droplet and in an air bubble?
hp hp waterm 1.0/9806
9743
mN
Paph
waterm 1.0
/9806
9743
mN
Paph
Statics!
Outline the solutionOutline the solution
Restate the goal Identify the given parameters and represent
the parameters using symbols Outline your solution including the
equations describing the physical constraints and any simplifying assumptions
Restate the goal Identify the given parameters and represent
the parameters using symbols Outline your solution including the
equations describing the physical constraints and any simplifying assumptions
23- s/mN 1.16x10
Viscosity Measurement: SolutionViscosity Measurement: Solution
hr
Pt322
hr
Pt322
23-32
6-
s/mN 1.16x10m) (0.1m) (0.05(1.047/s)2
m) (0.002 W)10(50
x 23-32
6-
s/mN 1.16x10m) (0.1m) (0.05(1.047/s)2
m) (0.002 W)10(50
x
tAU
F t
AUF U U A A
thr
F22
thr
F22
P P
thr
P322
thr
P322
Outer Outer cylindercylinder
Thin layer of waterThin layer of water
Inner Inner cylindercylinder
r = 5 cmt = 2 mmh = 10 cmP = 50 x 10-6 W10 rpm
r 2rh
Fr