Geometric Review and Design (GRAD) 3...Spiral Curves 3 16| Module 3 –Horizontal Alignment ODOT L&D...

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Geometric Review and Design (GRAD)

Horizontal

Alignment

3

32 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Identify the Design Elements of Horizontal Alignments

Understand how to Design Horizontal Alignments to a Given Design Speed

Understand how to design appropriate superelevation design

Learning Objectives

33 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Tangents

Circular Curves

Spiral (Transition) Curves

Superelevation

Elements of Horizontal Alignments

34 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Sect 202

Maximum Deflection without

Horizontal Curve

Angle varies with the design speed of the roadway

Recommended Minimum Distance

between Consecutive Horizontal

Deflections

High speed / Low speed

Horizontal Alignments - Curves

35 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Horizontal Alignments - Curves

36 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Horizontal Alignments - Curves

37 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Types of Curves

Simple Curves

Compound Curves

Reverse Curves

Spiral Curves

Horizontal Alignments - Curves

38 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Key Elements of a Horizontal

Curve

Simple Curves

39 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Degree vs. Radius

Degree of curve is the central angle subtended by a 100-foot arc for a given radius.

Example: Degree of curve for R = 1909 feet

Simple Curves

310 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Degree vs. Radius

Degree of curve is the central angle subtended by a 100-foot arc for a given radius.

Example: Degree of curve for R = 1909 feet

D = 3°

Simple Curves

311 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Degree vs. Radius

Degree of curve is the central angle subtended by a 100-foot arc for a given radius.

Example: Degree of curve for R = 1909 feet

D = 3°

Example: Radius of curve for D = 9.5°

Simple Curves

312 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Degree vs. Radius

Degree of curve is the central angle subtended by a 100-foot arc for a given radius.

Example: Degree of curve for R = 1909 feet

D = 3°

Example: Radius of curve for D = 9.5°

R = 603 feet

Simple Curves

313 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

2 horizontal curves in the same

direction

Utilize a common tangent

From AASHTO: It is preferable that the

ratio of the flatter radius to the

sharper radius not exceed 2:1 *

Should be used with caution!

Compound Curves

* A Policy on Geometric Design of Highways and Streets, 7th

Edition (2018) - Section 3.3.7.3

314 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

2 horizontal curves in opposite directions separated by a tangent with sufficient length to rotate superelevation from one curve to the next.

Superelevation - The cross slope of the pavement used to compensate for the effect of centrifugal force on horizontal curves

Reverse Curves

315 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Combination of high speed and

sharp curvature leads to longer

transition paths, which can result in

shifts in lateral position and

sometimes actual encroachment

into adjacent lanes.

Should be used on new alignments

based on the maximum degree of

curve as shown in Figure 202-11.

Length of spiral should be equal or

greater than superelevation runoff

length for the curve.

Spiral Curves

316 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Spiral Curves

Key Elements of a Spiral

Curve

317 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Sect 202.4

Increasing the cross slope to

keep vehicles on the road

through the horizontal

curve

Implemented by raising the

pavement outer edge with

respect to the inner edge.

Superelevation

318 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Recommended rates

Rural Highways (0.08 max) –

Figure 202-7

Urban Highways (high speed – 0.06

max) – Figure 202-8

Urban Ramps and Interchange

(low speed – 0.06 max) – Figure

202-10

Urban Highways (low speed – 0.04

max) – Figure 202-9; Figure 202-9a

Superelevation

319 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Can be difficult to apply

recommended superelevation rates

on urban roadways because of:

Wide pavements

Adjacent development

Drainage conditions

Frequent access points

In these cases, may use reduced or

no superelevation although Crown

Removal is recommended min.

Superelevation – 0.04 Figure

320 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Required whenever rate specified in Figures 202-7 through 202-10 is not provided.

Not required if a higher superelevation rate than what is specified in Figures 202-7 through 202-10 is provided as long as the rate doesn’t exceed the maximum superelevation rate for that given figure.

Superelevation – Design Exceptions

321 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Maximum curvature (minimum

curve radius) that doesn’t

require superelevation based on

design speed and rural/urban

condition (Figure 202-3)

Can also use Figures 202-7, 202-

8, and 202-9 to determine these

values.

Maximum Curvature without Superelevation

322 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Figures also show maximum

curvature for given design speed

(confirmed in Figure 202-2)

Maximum Curvature without Superelevation

323 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Four methods:

1. Revolve pavement about the

centerline (most commonly used)

2. Revolve pavement about the inner

edge of traveled way

3. Revolve pavement about the outer

edge of traveled way

4. Revolve pavement having a straight

cross slope (no crown) about the

outside edge of traveled way (ramps

typically)

Superelevation Methods

324 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Key Terms:

Normal Crown (Point A)

Adverse Crown Removed (Point B; also known as “half flat”)

Crown Removal (Point C)

PC/PT of curve (Point D) Superelevation rate is 50-70% design rate

Full Super (Point E) Design superelevation rate

Tangent Runout Normal Crown to Adverse Crown Removed

Superelevation Runoff Adverse Crown Removed to Full Super

Superelevation Transitions

325 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

With Spirals

Transition from Adverse Crown

Removed to Full Super shall occur

within the limits of the spiral.

Superelevation Position Spiral Length

326 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

With Spirals

Transition from Adverse Crown

Removed to Full Super shall occur

within the limits of the spiral.

Simple Curves – No Spirals

50%-70% of maximum

superelevation rate is outside the

curve limits; 2/3 of

superelevation rate at PC and PT

Prefer to have full superelevation

rate maintained for 1/3 of curve

length

Superelevation Position

2/3 (e(des) rate)

327 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Determine width of pavement

that is being rotated

Superelevation Transitions

328 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Determine width of pavement

that is being rotated

Identify Adjustment Factor (bw)

“Credit” for rotating more than

one lane

Superelevation Transitions

329 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Determine width of pavement

that is being rotated

Identify Adjustment Factor (bw)

“Credit” for rotating more than

one lane

Identify Equivalent Slope Rate (G)

For the given Design Speed

Superelevation Transitions

330 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Determine width of pavement

that is being rotated

Identify Adjustment Factor (bw)

“Credit” for rotating more than

one lane

Identify Equivalent Slope Rate (G)

For the given Design Speed

Calculate Superelevation Runoff

(Lr)

Superelevation Transitions

331 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Determine width of pavement

that is being rotated

Identify Adjustment Factor (bw)

“Credit” for rotating more than

one lane

Identify Equivalent Slope Rate (G)

For the given Design Speed

Calculate Superelevation Runoff

(Lr)

Calculate Tangent Runout (Lt)

Superelevation Transitions

332 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example - Determine Superelevation

Degree of Curve = 3.0°

Design Speed = 60 mph

Urban Location

Superelevation

333 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example - Determine Superelevation

Degree of Curve = 3.0°

Design Speed = 60 mph

Urban Location

Radius of Curve = 1,910 feet

Superelevation

334 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example - Determine Superelevation

Degree of Curve = 3.0°

Design Speed = 60 mph

Urban Location

Radius of Curve = 1,910 feet

e(des) = 0.055 ft/ft

Superelevation

335 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example - Determine Superelevation

Radius of Curve = 1,550 feet

Design Speed = 50 mph

Urban Location

Superelevation

336 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example - Determine Superelevation

Radius of Curve = 1,550 feet

Design Speed = 50 mph

Urban Location

Degree of Curve = 3°42’

Superelevation

337 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example - Determine Superelevation

Radius of Curve = 1,550 feet

Design Speed = 50 mph

Urban Location

Degree of Curve = 3°42’

e(des) = 0.050 ft/ft

Superelevation

338 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

339 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions or

340 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions or

341 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

342 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

343 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

344 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

345 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

346 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

347 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Each curve has its own superelevation runoff value

New Alignments

PT and PC should be separated enough

for a smooth transition at a rate not

to exceed “G” value in Figure 202-4.

Distance to be not less than 50% nor

greater than 70% of Lr1 + Lr2. 2/3

(67%) is preferred.

Existing Alignments

Conform as closely as possible to New

Alignments criteria.

Superelevation - Reverse Curves

348 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Example – determine

superelevation rotation

placement

Design Speed = 50 mph

Undivided Highway

Rotate 2-12’ lanes

PC Station = 100+73.35

e(des) = 0.050 ft/ft

Superelevation Transitions

349 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

350 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

Y = (enc) X

(rotating pavement width)

351 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

Y = (enc) X

(rotating pavement width)

Y = (FS cross slope) X

(rotating pavement width)

Y = (-FS cross slope) X

(rotating pavement width)

352 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

Y = (enc) X

(rotating pavement width)

Y = (FS cross slope) X

(rotating pavement width)

Y = (-FS cross slope) X

(rotating pavement width)

353 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

Y = (enc) X

(rotating pavement width)

Y = (FS cross slope) X

(rotating pavement width)

Y = (-FS cross slope) X

(rotating pavement width)

PC = 2/3 x Superelevation Rate)

354 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

Y = (enc) X

(rotating pavement width)

Y = (FS cross slope) X

(rotating pavement width)

Y = (-FS cross slope) X

(rotating pavement width)

PC = 2/3 x Superelevation Rate)L = [(ePC/eDES) x Lr]

355 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

Y = (enc) X

(rotating pavement width)

Y = (FS cross slope) X

(rotating pavement width)

Y = (-FS cross slope) X

(rotating pavement width)

PC = 2/3 x Superelevation Rate)L = [(ePC/eDES) x Lr]

L = Lt L = Lt

356 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Superelevation Exaggerated Profiles

357 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Information reviewers

should look for:

Superelevation Rate

Transition Length

Transition Rate

Super Rate at PC

Super Rate at PT

Length of curve/time at full superelevation

Superelevation Review

358 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

For horizontal alignment

design elements that

don’t meet standards

Chevrons

Rumble Strips

Curve Ahead Signage

Curve Widening

Place the wider shoulder on the left (instead of right) side

Safety Countermeasures

359 | Module 3 – Horizontal Alignment

ODOT L&D Vol. 1 – Section 200

Key Terms

Horizontal Alignments

Tangents

Curves

Spirals

Horizontal Curves

Simple Curves

Compound Curves

Reverse Curves

Spiral Curves

Tangent Runout (NC to ACremoved)

Superelevation Runoff (ACremoved to FS)

Module Review