University of Bath
PHD
A Regularity Theory for Fractional Harmonic Maps
Roberts, James
Award date:2017
Awarding institution:University of Bath
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A Regularity Theory for
Fractional Harmonic Maps
submitted by
James Edward Roberts
for the degree of Doctor of Philosophy
of the
University of Bath
Department of Mathematical Sciences
September 2016
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0
Summary
Our purpose is to define, and develop a regularity theory for, Intrinsic Minimising
Fractional Harmonic Maps from Euclidean space into smooth compact Rieman-
nian manifolds for fractional powers strictly between zero and one. Our aims are
motivated by the theory for Intrinsic Semi-Harmonic Maps, corresponding to the
power one-half, developed by Moser [34].
Our definition and methodology are based on an extension method used for
the analysis of real valued fractional harmonic functions. We define and derive
regularity properties of Fractional Harmonic Maps by regarding their domain as
part of the boundary of a half-space, equipped with a Riemannian metric which
degenerates or becomes singular on the boundary, and considering the regularity
of their extensions to this half-space.
We show that Fractional Harmonic Maps, and their first order derivatives, are
locally Holder continuous away from a set with Hausdorff dimension depending on
the dimension of the domain and the fractional power in question. We achieve this
by establishing the corresponding partial regularity of extensions of Fractional
Harmonic Maps which minimise the Dirichlet energy on the half-space.
To prove local Holder continuity, we develop several results in the spirit of
the regularity theory for harmonic maps. We combine a monotonicity formula
with the construction of comparison maps, scaling in the Poincare inequality and
results from the theory of harmonic maps, to prove energy decay sufficient for
the application of a modified decay lemma of Morrey.
Using the Holder continuity of minimisers, we prove a bound for the essen-
tial supremum of their gradient. Then we consider the derivatives in directions
tangential to the boundary of the half-space; we establish the existence of their
gradients using difference quotients. A Caccioppoli-type inequality and scaling in
the Poincare inequality then imply decay estimates sufficient for the application
of the modified decay lemma to these derivatives.
i
Acknowledgements
To Roger Moser. You have been an outstanding supervisor throughout my
PhD. Thank you for your endless support, knowledge and patience and for the
opportunity and inspiration to work on this project. I would also like to thank
you for always taking the time to answer my questions and for the many helpful
discussions we have had; you have taught me a great deal about research and
mathematics.
To Katy. Since the day we met your encouragement and support of my PhD
have been invaluable. You have made me truly happy, through both the fun
and the hard times. Words cannot express how thankful I am that I met you.
To my office mates, Sam, William, Nathan, Jesus, James, Marcus, Xavier,
Pablo and Leonard. Thank you for making the office and department a fun
place to work and for many interesting discussions about mathematics. I wish
you all the best.
To my parents, Jane and Dave, and my brother Matt. I would like to thank you
for your constant love and support, even when I’ve bored you rigid talking
about my work.
To the EPSRC. Thank you for the financial support enabling me to study for a
PhD in mathematics.
To the members of Mathematics department at the University of Bath. Thank
you for providing an engaging, welcoming environment in which to study.
ii
Contents
1 Introduction 1
2 Weighted Sobolev Spaces and Degenerate Elliptic Equations 8
2.1 Weighted Sobolev Spaces . . . . . . . . . . . . . . . . . . . . . . . 9
2.2 Weighted Homogeneous Sobolev Spaces . . . . . . . . . . . . . . . 12
2.2.1 Relationship of W 1,2β (Rm+1
+ ;Rn) to Weighted and Unweighted
Sobolev Spaces . . . . . . . . . . . . . . . . . . . . . . . . 13
2.3 Analytical Properties of Weighted Sobolev Spaces . . . . . . . . . 17
2.3.1 Behaviour of Integrals Over Balls and Cubes Under Bi-
Lipschitz Maps . . . . . . . . . . . . . . . . . . . . . . . . 18
2.3.2 Traces of Sobolev Functions . . . . . . . . . . . . . . . . . 21
2.3.3 Poincare Inequality for W 1,2β . . . . . . . . . . . . . . . . . 22
2.3.4 Pointwise Bounds for Functions in Terms of Their Integrals
on an Interval . . . . . . . . . . . . . . . . . . . . . . . . . 32
2.3.5 Compactness of the Embedding W 1,2β → L2
β . . . . . . . . 33
2.4 Properties of Solutions of div(xβm+1∇v) = 0 . . . . . . . . . . . . . 38
2.4.1 Spaces of Smooth and Continuous Functions . . . . . . . . 39
2.4.2 Solutions of div(xβm+1∇v) = 0 with Neumann-type Bound-
ary Data . . . . . . . . . . . . . . . . . . . . . . . . . . . . 40
2.4.3 Continuity Properties of Solutions of div(|xm+1|β∇v) = 0
on Sets Overlapping ∂Rm+1+ . . . . . . . . . . . . . . . . . 46
3 Holder Continuity of Energy Minimisers 49
3.1 Critical Points of Eβ . . . . . . . . . . . . . . . . . . . . . . . . . 50
3.1.1 The Euler-Lagrange Equations . . . . . . . . . . . . . . . . 50
3.1.2 The Stationary Equations . . . . . . . . . . . . . . . . . . 53
3.2 Background Theory and Discussion of the Problem . . . . . . . . 57
3.3 Energy Monotonicity . . . . . . . . . . . . . . . . . . . . . . . . . 63
3.3.1 Boundary Energy Monotonicity . . . . . . . . . . . . . . . 63
iii
3.3.2 Interior Energy Monotonicity . . . . . . . . . . . . . . . . 68
3.4 Motivating Observations Concerning the Energy . . . . . . . . . . 70
3.5 A Modified Lemma of Morrey . . . . . . . . . . . . . . . . . . . . 76
3.5.1 From Decay Estimates to Holder continuity . . . . . . . . 80
3.6 Interior Estimates for Holder continuity . . . . . . . . . . . . . . . 81
3.7 An Overview of the Boundary Estimates for Holder Continuity . . 91
3.8 A Modified Lemma of Luckhaus . . . . . . . . . . . . . . . . . . . 92
3.8.1 Homogeneous Degree Zero Extension . . . . . . . . . . . . 93
3.8.2 Absolute Continuity Properties of Functions in W 1,2β . . . . 98
3.8.3 Embeddings of Absolutely Continuous Functions on Line
Segments . . . . . . . . . . . . . . . . . . . . . . . . . . . 98
3.8.4 Proof of Lemma 3.8.0.1 . . . . . . . . . . . . . . . . . . . . 101
3.9 Corollary to the Luckhaus Lemma . . . . . . . . . . . . . . . . . . 113
3.9.1 Radial Slicing for Functions in W 1,2β . . . . . . . . . . . . . 113
3.9.2 Luckhaus Corollary . . . . . . . . . . . . . . . . . . . . . . 114
3.10 Improved Control in the Poincare Inequality . . . . . . . . . . . . 119
3.11 Energy Decay Lemma . . . . . . . . . . . . . . . . . . . . . . . . 122
3.12 Holder Continuity of Energy Minimisers . . . . . . . . . . . . . . 125
3.12.1 ε-regularity Theorem . . . . . . . . . . . . . . . . . . . . . 125
3.12.2 Partial Regularity for Energy Minimisers . . . . . . . . . . 128
4 Preliminaries for Regularity of First Order Derivatives 131
4.1 Monotonicity Formula for Even Solutions of the Linear Degenerate
Equation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 139
4.2 Solutions of the Linear Degenerate Dirichlet Problem . . . . . . . 156
5 Holder Continuity of First Derivatives of Minimisers 160
5.1 An L∞ Bound for the Gradient of an Energy Minimiser . . . . . . 161
5.2 Existence of second order derivatives . . . . . . . . . . . . . . . . 168
5.3 Caccioppoli-Type Inequality . . . . . . . . . . . . . . . . . . . . . 171
5.4 Improved Control in the Poincare Inequality for First Derivatives
on the Boundary . . . . . . . . . . . . . . . . . . . . . . . . . . . 173
5.5 Improved Control in the Poincare Inequality for First Derivatives
in the Interior . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 181
5.6 Holder Continuity of First Order Derivatives . . . . . . . . . . . . 188
6 Fractional Harmonic Maps 196
7 Further Work 211
iv
Chapter 1
Introduction
The aim of this thesis is to define and analyse the regularity properties of frac-
tional harmonic maps between Riemannian manifolds. To motivate this objective
and outline our approach we begin with a discussion of fractional harmonic func-
tions.
Fractional harmonic functions appear in a wide range of contexts; quantum
mechanics, optimisation and mathematical finance, minimal surfaces and crystal
dislocations to name a few [14], and have been extensively studied in the liter-
ature. There are several equivalent ways to define the fractional laplacian of a
function u : Rm → R. Provided u is sufficiently regular we have, for example,
(−∆)su(x) = C(m, s) limε→0+
∫Rm\Bε(x)
u(x)− u(y)
|x− y|2s+mdy,
where s ∈ (0, 1), m ∈ N ε > 0 and Bε(x) is the ball in Rm with radius ε and
centre x. These operators are naturally associated to the Sobolev spaces Hs(Rm),
see [14], whose norm consists of the L2 norm of u plus a suitable semi-norm. The
square of the semi-norm serves as an energy for u ∈ Hs(Rm) and this energy may
be expressed as a constant multiple of
||(−∆)s2u||2L2(Rm).
In contrast to the Laplace operator, fractional Laplace operators are non-
local; the value of (−∆)su(x) depends upon the behaviour of u on the whole
of its domain, not just in a neighbourhood of x. One might therefore expect
that techniques, such as localisation or comparison principles, used to study so-
lutions of Laplace’s equation ∆u = 0, may not be applicable in the study of
solutions to the fractional counterpart of this equation, namely (−∆)su = 0.
1
Such an equation arises, for instance, as the Euler-Lagrange equation for the
energy ||(−∆)s2u||2L2(Rm). However, using a result of Caffarelli and Silvestre [5],
one may recast this, seemingly non-local, problem as a variant of the problem for
Laplace’s equation by considering the extension of u to a half-space with Rm as
the boundary.
Let Rm+1+ = Rm×(0,∞) and β ∈ (−1, 1). The result of Caffarelli and Silvestre
[5] states that, for given boundary data u : Rm → R, solutions v : Rm+1+ → R of
the Dirichlet problem:
div(xβm+1∇v) = 0 in Rm+1+ and Tv = u (1.0.1)
satisfy (−∆)1−β
2 u = ∂βm+1v := − limxm+1→0+ xβm+1∂m+1v, where T is a suitable
trace operator with respect to ∂Rm+1+ . We observe that div(xβm+1∇v) = 0 is the
Euler-Lagrange equation for the Dirichlet energy Eβ(v) = 12
∫Rm+1
+xβm+1|∇v|2dx,
defined, for example, on W 1,2β (Rm+1
+ ;Rn), the homogeneous Sobolev space with
(Eβ)12 as the norm. Hence, if v is a critical point of Eβ with Tv = u, then v
is a solution of (1.0.1). If we wish to study fractional harmonic functions, that
is, maps with (−∆)su = 0, then the aforementioned theory suggests that we
consider minimisers of Eβ with Tv = u such that ∂βm+1v = 0.
There are two possible approaches which lead to a generalisation of the notion
of fractional harmonic functions to fractional harmonic maps between Rieman-
nian manifolds. To facilitate their comparison, we give a reformulation of the
above variational problem so as to remove any explicit mention of the fractional
Laplace operators. One method of proof for Caffarelli and Silvestre’s result [5] is
to show that C||(−∆)s2u||2L2(Rm) = Eβ(v) where s = 1−β
2, v is an extension of u
satisfying (1.0.1) and C depends on m and s. Consequently, the semi-norm on
Hs satisfies
C||(−∆)s2u||2L2(Rm) = infEβ(v) : Tv = u, v ∈ W 1,2
β (Rm+1+ ;Rn).
Furthermore, the discussion above yields Dirichlet to Neumann map u 7→ ∂βm+1v
which is identified with the fractional Laplace operator of order 1−β2
. If instead
we consider (1.0.1) for u : O → R where O ( Rm is open, then we still obtain a
Dirichlet to Neumann map for the problem (1.0.1), but we may no longer identify
this with a fractional Laplace operator. We can thus express the conclusions of
Caffarelli and Silvestre in the following way: the first variation of the energy, given
by infEβ(v) : Tv = u on Hs, is the Dirichlet to Neumann map u 7→ ∂βm+1v. As
a result, we may study fractional harmonic functions u by considering v which
2
minimise Eβ, satisfy Tv = u and send u 7→ 0 via the aforementioned Dirichlet to
Neumann map.
This observation is key; it provides one of the foundational ideas for the work
conducted in this thesis. Using the aforementioned Dirichlet to Neumann map,
we can obtain regularity results for solutions of (−∆)1−β
2 u = 0 by examining
the corresponding properties of an extension v : Rm+1+ → R, as described above,
near the boundary ∂Rm+1+ . In particular, we may use many of the methods from
the theory of second order elliptic partial differential equations to analyse this
extension. If v has a continuous, or even smooth (with respect to the variables
x1, . . . , xm) extension to Rm × 0, then u is continuous or smooth respectively.
As a consequence of the results of [7], a map u : O → R, whose extension v
satisfies div(xβm+1∇v) = 0 in Rm+1+ and ∂βm+1v = 0 in O, is indeed smooth.
With this formulation in mind, we now discuss the definition of fractional
harmonic maps between manifolds. We first consider the situation corresponding
to the equation (−∆)12u = 0. Da Lio and Riviere [12] first considered 1
2-harmonic
maps into the round unit sphere Sn−1 ⊂ Rn centred at the origin. These are
critical points u of the energy ||(−∆)14u||2L2(Rm) in H
12 under the constraint that
u takes values in Sn−1 almost everywhere. In other words, they considered critical
points of the functional
L(u) = infE0(v) : Tv = u, v ∈ W 1,2(Rm+1+ ;Rn), u(x) ∈ Sn−1 for a.e x ∈ Rm,
where Rm is identified with ∂Rm+1+ , which are defined as 1
2-harmonic maps into
Sn−1. The motivation for studying critical points of this functional comes from
the physical relevence of 12-harmonic maps. As noted in [12], they appear, for
instance, in the asymptotic limit of equations in phase-field theory for reaction-
diffusion. There is also a geometric reason for studying such a functional; when
m = 1 the functional is invariant under the trace of conformal transformations
of R2+.
Moser [34] observed that the definition of L is not intrinsic, meaning that it
depends on the choice of embedding of Sn−1 into an ambient space. He proposed
a modification of L which removes such dependence, and also considers general,
compact target manifolds. Suppose N is a smooth compact manifold which, due
to the embedding theorem of Nash [36], we may assume is isometrically embedded
in Rn for some n. Define
I(u) = infE0(v) : Tv = u, v ∈ W 1,2(Rm+1+ ;Rn), v(x) ∈ N for a.e x ∈ Rm+1
+ .(1.0.2)
3
The critical points of I are called intrinsic semi-harmonic maps. When m = 1,
this functional is conformally invariant in the same sense as L is, so the geometric
motivation for 12-harmonic maps also serves as a reason to study intrinsic semi-
harmonic maps in this case. Moser, also considered the functional I when the
domain of u is restricted to open O ( Rm.
There are two potential methods for calculating the Euler Lagrange equation
for L. It is possible to directly calculate the equation, owing to the fact that the
energy in question is defined in terms of a differential operator, by considering
variations of the energy in Hs which respect the constraint u ∈ Sn−1. This
is the approach taken by Da Lio and Riviere [12]. Alternatively, we could try
to connect the Dirichlet to Neumann map, similar to that obtained from the
Dirichlet problem (1.0.1), to the first variation of L. If successful, we would then
obtain an identification of this map with the differential operator obtained in the
explicit calculation. We note that any v for which L(u) = E0(v) satisfies ∆v = 0
in Rm+1+ and is thus smooth in Rm+1
+ .
In contrast, as there is not an obvious a-priori choice of differential operator
corresponding to I, Moser [34] used the latter interpretation of the first variation
of I as a Dirichlet to Neumann map. Thus intrinsic semi-harmonic maps u have
an extension v ∈ W 1,2(Rm+1+ ;Rn) with v(x) ∈ N for almost every x. The map v
minimises E0 among all maps with values in N and trace equal to u and satisfies
v 7→ 0 under the Dirichlet to Neumann map. In this case, any v for which
I(u) = E0(v) is a critical point of the energy. However, the constraint v ∈ N
must now be taken into account when calculating the Euler-Lagrange equation
for E0. To facilitate subsequent discussions of these equations we now recall the
definition of a harmonic map between Riemannian manifolds.
Let M be a Riemannian manifold, of dimension m+ 1, with metric g and let
N be a smooth, compact Riemannian manifold isometrically embedded in Rn for
some n ∈ N. We are interested in defining the energy of maps in
W 1,2(M ;N) := v ∈ W 1,2(M ;N) : v(x) ∈ N for almost every x ∈M.
The energy density of v ∈ W 1,2(M ;N) is given by e(v) =∑
i,j gij⟨∂v∂xi, ∂v∂xj
⟩where gij are the components of the matrix representing g in coordinates and gij
are the components of its inverse. The energy of v is defined as
Eg(v) =
∫M
e(v)dvolM . (1.0.3)
4
If x1, . . . , xm+1 are coordinates on M then
Eg(v) =
∫M
∑i,j
gij⟨∂v
∂xi,∂v
∂xj
⟩√det(g)dx
where det(g) is the determinant of the matrix representing g in the given coordi-
nates. The Euler-Lagrange equations for Eg are
∆gv +∑i,j
gijA(v)
(∂v
∂xi,∂v
∂xj
)= 0 (1.0.4)
where A is the second fundamental form of N , a section of T ∗N ⊗T ∗N ⊗ (TN)⊥,
and ∆gv is the Laplace-Beltrami operator. For the sake of consistency with the
usual Laplace operator, we use the convention that, in coordinates, this operator
is given by ∆gv =∑
i,j1√
det(g)
∂∂xi
(gij√
det(g) ∂∂xjv)
. Critical points of Eg with
respect to the dependent variable (weakly) satisfy (1.0.4) and are called (weakly)
harmonic maps with respect to g. If the choice of g is implicit from the context
or we are talking about harmonic maps corresponding to different metrics, we
simply refer to (weakly) harmonic maps.
With the above notion of harmonic map in mind, we may formulate the
discussion of intrinsic semi-harmonic maps as follows. Any v with E0(v) = I(u)
for some u satisfies
∆v + A(v)(∇v,∇v) = 0 (1.0.5)
in Rm+1+ , where A(v)(∇v,∇v) =
∑iA(v)
(∂v∂xi, ∂v∂xi
)and ∆ is the usual Laplace
operator on Euclidean space. Intrinsic semi-harmonic maps may thus be regarded
as maps u which have a harmonic extension v to Rm+1+ satisfying (1.0.5), which
minimise E0 among all maps with trace u and which are sent to 0 by the Dirichlet
to Neumann map that arises as the first variation of I.
Da Lio and Riviere considered the regularity of 12-harmonic maps when m = 1
and showed that such maps are smooth. They consider the Euler Lagrange equa-
tions for L explicitly, the underlying idea being to re-formulate these equations
in such a way as to take advantage of compensation phenomena: in this case
these are gains in regularity after re-writing the equations using the geometric
structure of the sphere. They succeed in writing the equations in a form which
is sufficient to deduce decay estimates for the energy which imply continuity of
solutions, from which they deduce their smoothness. They extended these meth-
ods to 12-harmonic maps u into general C2 target manifolds N [11]. The idea
is still to take advantage of gains in regularity observed via a re-writing of the
5
Euler-Lagrange equation; the application of a well chosen rotation along u gives
the desired structure and it is then possible to prove suitable decay of the energy
to conclude continuity and higher regularity.
Moser [34] instead examined the regularity of the extension to Rm+1+ of in-
trinsic semi-harmonic maps. In particular, he considered the regularity of the
extensions of maps u which are critical points of I with respect to both the de-
pendent and independent variable. He showed that if u is such a critical point and
v its extension, then v is a critical point of E0 with respect to variations of the
dependent and independent variable; in other words, v is a stationary harmonic
map. The fact that u is sent to 0 by the first variation of I may be regarded as a
0 Neumann boundary condition for v. Consequently, the even reflection of v in
∂Rm+1+ gives a stationary harmonic map from Rm+1 into N . The regularity the-
ory for such maps is known; a stationary harmonic map v : Rm+1 → N is smooth
away from a set of points of vanishing m−1 dimensional Hausdorff measure when
m ≥ 2 [3] and when m = 1 such a v is smooth [26]. The map u then inherits
its regularity from an extension v. Moser also showed that if the domain of u is
Rm then u must be constant. He furthermore examined critical points of I with
the following constraint: let Γ be a smooth closed submanifold of N and suppose
u(x) ∈ Γ for almost every x. Once such critical points are defined appropriately,
their regularity is the same as for the unconstrained problem. Moreover, the
results may essentially be regarded as generalisations of the theory of Da Lio and
Riviere.
So far, we have only discussed fractional harmonic maps corresponding to the
power 12. However, Da Lio and Schikkora [10, 42, 13, 43] have also considered the
regularity properties of extrinsic fractional harmonic maps for other powers as well
as on domains of dimension m > 1 which are not necessarily the whole of Rm. The
idea in each case is still to take advantage of compensation phenomena to obtain
the resulting regularity. Da Lio [10] proved full regularity of m2
harmonic maps
u : Rm → N whenever m is odd and N is smooth and compact without boundary.
Schikkora [42] proved that m2
harmonic maps from a domain into Sn−1 are Holder
continuous. Da Lio and Schikkora [13] showed that mp
harmonic maps into Sn−1
or, more explicitly, critical points of∫Rm |(−∆)
α2 u|pdx where p = m
α∈ (1,∞), are
Holder continuous. Schikkora has also considered the techniques used to obtain
regularity for fractional harmonic maps in generality [43].
To our knowledge, there are currently no results regarding the regularity of
intrinsic fractional harmonic maps for powers other than 12. In this thesis we
generalise Moser’s approach to a regularity theory for fractional harmonic maps
6
to powers strictly between 0 and 1.
7
Chapter 2
Weighted Sobolev Spaces and
Degenerate Elliptic Equations
We intend to define and study two related families of variational problems, one
involving a family of Dirichlet energies and the other, a family of related func-
tionals, both parametrised by β ∈ (−1, 1). One set of problems will be posed for
maps defined on the half space Rm+1+ = Rm× (0,∞) for m ∈ N and the other will
be posed for maps defined on open subsets of the boundary of Rm+1+ . In order
to observe the connection we expect between these problems, we must work with
function spaces where the boundary values of functions and their derivatives need
not vanish. Appropriate choices are homogeneous Sobolev spaces defined with
respect to the energies that we will consider later.
The Euler-Lagrange equations for the Dirichlet energies are in the form of de-
generate elliptic semi-linear equations. To facilitate the study of such equations,
we will need to examine their linear parts in more detail. These have the form
div(xβm+1∇v) = 0 (2.0.1)
on open subsets of Rm+1+ , together with either Dirichlet or Neumann-type bound-
ary data depending on the context. When β ∈ (−1, 1)\0, the equations are
degenerate elliptic; there are no uniform bounds, either away from zero when
β ∈ (0, 1) or away from infinity when β ∈ (−1, 0), for the coefficients of the
highest order terms.
Degenerate elliptic equations with certain classes of coefficients may be anal-
ysed in a canonically associated weighted Sobolev space. The homogeneous
Sobolev spaces we will use to study the aforementioned variational problems are
connected, locally, to the weighted Sobolev spaces corresponding to (2.0.1). We
8
will first introduce these Sobolev Spaces and describe the connections between
them. Then we discuss relevant properties of solutions to (2.0.1).
2.1 Weighted Sobolev Spaces
Certain classes of degenerate elliptic equations may be studied using weighted
Sobolev and Lebesgue spaces. Our purpose here is to introduce the function
spaces relevant to the study of (2.0.1). Rather than give a complete overview
of these spaces, we present the machinery necessary for our subsequent analysis.
When dealing with solutions of (2.0.1) in domains overlapping ∂Rm+1+ = Rm×0
it will often be helpful to reflect the solutions in this hyperplane, to this end we
consider function spaces for maps with open domain Ω ⊂ Rm+1. Furthermore,
the maps we consider will be vector-valued with image contained in Rn for some
n ∈ N.
Let dx denote the Lebesgue measure on Rm+1 for m ∈ N. Any non-negative,
locally integrable function w defines a weighted measure, dµw(x), with respect
to dx via dµw(x) = w(x)dx wherever the function is defined. The function w is
said to be a weight and is the Radon-Nikodym derivative of dµw(x) with respect
to dx.
The class of weights relevant to the problems we consider are Muckenhoupt’s
Ap weights with respect to the Lebesgue measure on Rm+1 for p ∈ [1,∞) [35].
Muckenhoupt states the condition to be in Ap in terms of cubes but we may
equivalently state it in terms of balls: a weighting w of dx is said to be in
Ap(dx), or Ap for short, if
supB⊂Rm+1
(1∫B
dx
∫B
wdx
)(1∫B
dx
∫B
w−1p−1 dx
)p−1
≤ C
for a positive constant C. The significance of this condition is that it is both nec-
essary and sufficient to ensure the boundedness of the Hardy-Littlewood maximal
function, defined with respect to dx, from the Lebesgue space Lp(µw) into itself.
This was first proved for weightings of the Lebesgue measure in Rm+1 by Muck-
enhoupt [35] and has been extended to a more general setting by Calderon [8].
Our interest in the Ap condition is motivated by the consequences of the theory
of these weights with regard to Sobolev spaces and degenerate elliptic equations;
there are a number of similarities to the theory of elliptic equations studied in
the usual Sobolev spaces which we will take advantage of.
The Lebesgue and Sobolev spaces best suited to the study of (2.0.1) are
9
those defined with respect to the weights xβm+1 where β ∈ (−1, 1). Whenever
we consider (2.0.1) in a domain in Rm+1+ whose boundary intersects ∂Rm+1
+ , the
boundary conditions we attach to the equation will allow us to reflect solutions
in this hyperplane, giving rise to the weights |xm+1|β. Hence we consider these
weights on subsets of Rm+1.
A calculation verifies that |xm+1|β is an A2 weight on Rm+1. Consequently
|xm+1|β is an Aq weight for all q ≥ 2 by part 3 of remark 1.2.4 in [47]. We define
the β-measures
dµβ(x) = |xm+1|βdx (2.1.1)
for β ∈ (−1, 1). It is implicit in the definition of dµβ(x) that these measures are
defined on the same sigma-algebra as the Lebesgue measure and hence define the
same collection of measurable functions as dx. Thus we may refer to measurable
functions without ambiguity.
Let p ∈ [1,∞) and Ω be an arbitrary subset of Rm+1. Define the weighted
Lebesgue spaces corresponding to dµβ as
Lpβ(Ω;Rn) = f : Ω→ Rn : f is measurable,
∫Ω
|f |p dµβ <∞ (2.1.2)
and for p =∞ we recall the Lebesgue space
L∞(Ω;Rn) = f : Ω→ Rn : f is measurable, ess supΩ(f) <∞. (2.1.3)
As stated in [9] Theorem 3.4.1, these are Banach spaces with respect to the norm
||f ||Lpβ(Ω;Rn) =(∫
Ω|f |p dµβ
) 1p . Furthermore, when p = 2, this norm is induced by
the inner product 〈f, g〉L2β(Ω;Rn) =
∫Ω〈f, g〉 dµβ for f, g ∈ L2
β(Ω;Rn) where 〈f, g〉is the inner product of f and g in Rn. Thus each L2
β(Ω;Rn) is a Hilbert space. If
β = 0 then we omit the subscript and let Lp(Ω;Rn) denote the Lebesgue space
of p-integrable functions on Ω with values in Rn.
There are two possible ways to define Sobolev spaces on an open Ω ⊂ Rm+1.
One method is to take the completion of the set of smooth functions from Ω to
Rn with finite Sobolev norm. The other is to equip the collection of Lpβ functions,
with first order weak derivatives also in Lpβ, with a Sobolev norm. The question
is then to what extent do the two definitions agree; if they give rise to different
function spaces, we must make a choice as to which is better suited to the study
of the equations we consider.
10
Let p ∈ [2,∞) and define
W 1,pβ (Ω;Rn) = v : Ω→ Rn : v,
∂v
∂xi∈ Lpβ(Ω;Rn) for i = 1, . . . ,m+ 1 (2.1.4)
where ∂v∂xi
denotes the weak (distributional) partial derivative of v with respect
to xi. Proposition 2.1.2 of [47] guarantees that W 1,pβ (Ω;Rn) is a Banach space
with respect to the norm
||v||W 1,pβ (Ω;Rn) =
(∫Ω
|v|pdµβ +
∫Ω
|∇v|pdµβ) 1
p
where ∇v is the weak derivative of v : Ω → Rn and |∇v|2 =∑m+1
i=1
∣∣∣ ∂v∂xi ∣∣∣2.
Let C∞(Ω;Rn) denote the space of smooth functions from Ω to Rn. It follows
from corollary 2.1.6 [47] that the collection of maps in C∞(Ω;Rn) which satisfy
||v||W 1,pβ (Ω;Rn) <∞ is dense in W 1,2
β (Ω;Rn). Hence, for p ∈ [2,∞), the space W 1,pβ
coincides with the completion of the set of smooth functions with ||v||W 1,pβ (Ω;Rn) <
∞ and the two approaches we could have used to define W 1,pβ give the same
function space. This conclusion also holds for all p ∈ (q,∞) where q = q(β) ∈(1, 2) using Corollary 1.2.17 of [47], but not necessarily all p ∈ [1,∞). However,
throughout this thesis we only consider W 1,pβ when β 6= 0 for p ≥ 2. The norm
on W 1,2β (Ω;Rn) is induced by the inner product 〈v, w〉W 1,2
β (Ω;Rn) =∫
Ω〈v, w〉 dµβ +∫
Ω〈∇u,∇v〉 dµβ for v, w ∈ L2
β(Ω;Rn) where we use the notation 〈∇v,∇w〉 =∑m+1i=1
⟨∂v∂xi, ∂w∂xi
⟩to denote the inner product of ∇v and ∇w in R(m+1)×n. Hence
W 1,2β (Ω;Rn) is a Hilbert space and thus reflexive. When β = 0 we omit the
subscript 0 and write W 1,p(Ω;Rn) for the Sobolev space of p-integrable functions
with p-integrable weak first derivatives.
It is worth noting that, for every β ∈ (−1, 1)\0, approximation by smooth
functions in Lpβ(Ω;Rn) and W 1,pβ (Ω;Rn) works in the same way as for the un-
weighted spaces Lp(Ω;Rn) and W 1,p(Ω;Rn) whenever p ≥ 2. The details of this
process are given in Theorem 2.1.4 and Corollary 2.1.5 in [47].
In order to find solutions to the Dirichlet problem for (2.0.1) we will need
subspaces of the weighted Sobolev and Lebesgue spaces with vanishing boundary
values. Define W 1,pβ,0(Ω;Rn) as the closure of C∞0 (Ω;Rn) in W 1,p
β (Ω;Rn) with
respect to || · ||W 1,pβ (Ω;Rn). If p = 2 then, as closed subspaces of Hilbert spaces, the
W 1,2β,0(Ω;Rn) are also Hilbert spaces.
11
2.2 Weighted Homogeneous Sobolev Spaces
The Dirichlet energies we intend to study, introduced in detail in the beginning
of Chapter 3, are of the form
Eβ(v) =1
2
∫Rm+1
+
|∇v|2dµβ (2.2.1)
where β ∈ (−1, 1), dµβ(x) = |xm+1|βdx is the measure defined by (2.1.1), Rm+1+ =
Rm× (0,∞) and v is in a function space to be defined here. As stated previously,
in order to link the variational problem for the Eβ to the related problems for
functions defined on open subsets of ∂Rm+1+ , we intend to analyse the energies in
function spaces where their values and the values of their derivatives on ∂Rm+1+
may be non-zero. An appropriate choice are homogeneous Sobolev spaces defined
with respect to the energy; we have control of the energy in these spaces and no
extraneous information is contained in the norm.
To construct a suitable Sobolev space for the energies Eβ, we consider the
completion of a space of smooth functions with respect to norms defined via
the energies. Let m,n ∈ N and observe that the restriction of functions in
C∞0 (Rm+1;Rn) to Rm+1+ need not vanish near the boundary of Rm+1
+ . Define
D+(Rm+1+ ;Rn) = φ | φ = f |Rm+1
+for some f ∈ C∞0 (Rm+1;Rn).
We define a family of norms on D+(Rm+1+ ;Rn). We write ∂
∂xito denote the partial
derivative with respect to the ith variable and ∇ to denote the gradient of a map
from Rm+1+ to Rn. Let β ∈ (−1, 1) and consider the functional
νβ : D+(Rm+1+ ;Rn)→ R : φ 7→
(1
2
∫Rm+1
+
|∇φ|2 dµβ
) 12
. (2.2.2)
We now show that νβ is a norm on D+(Rm+1+ ;Rn).
Lemma 2.2.0.1. Let β ∈ (−1, 1). The function νβ is a norm on D+(Rm+1+ ;Rn).
Proof. If φ ≡ 0 then νβ(0) = 0. Conversely, if νβ(φ) = 0 then |∇φ|2 = 0 in Rm+1+
and thus φ is constant. Since the only constant function in D+(Rm+1+ ;Rn) is the
zero function, φ must be zero. The fact that νβ(cφ) = |c|νβ(φ) for all c ∈ R follows
from the definition of νβ. Lastly, the fact that the triangle inequality holds for νβ
is a consequence of Minkowski’s inequality for the space L2β(Rm+1
+ ;Rn×(m+1)).
We are now in a position to define the Sobolev spaces we will use to study
12
the Dirichlet energies.
Definition 2.2.0.1. Let β ∈ (−1, 1). The Weighted Homogeneous Sobolev Space
W 1,2β (Rm+1
+ ;Rn) is the completion of D+(Rm+1+ ;Rn) with respect to the metric
induced by νβ.
By construction, W 1,2β (Rm+1
+ ;Rn) is a Banach space. However, we can show
more; the map 〈·, ·〉D+(Rm+1+ ;Rn) : D+(Rm+1
+ ;Rn)×D+(Rm+1+ ;Rn)→ R given by
〈φ, ψ〉D+(Rm+1+ ;Rn) =
∫Rm+1
〈∇φ,∇ψ〉dµβ
for φ, ψ ∈ D+(Rm+1+ ;Rn) is well defined as a consequence of Holder’s inequality for
maps in L2β(Rm+1
+ ;R(m+1)×n). Furthermore, this map is an inner product which
induces the norm νβ on D+(Rm+1+ ;Rn) making it an inner product space. Thus
〈·, ·〉D+(Rm+1+ ;Rn) extends to an inner product on W 1,2
β (Rm+1+ ;Rn). Since this space
is complete by definition it is thus a Hilbert Space and hence reflexive.
2.2.1 Relationship of W 1,2β (Rm+1
+ ;Rn) to Weighted and Un-
weighted Sobolev Spaces
The elements of W 1,2β (Rm+1
+ ;Rn) are, strictly speaking, equivalence classes of
Cauchy sequences and it will be necessary to have more tangible characterisations
of these classes in order to solve the partial differential equations we consider.
The β ∈ (−1, 1) which parametrise the Dirichlet energies come from the
definition of Rm+1+ as a Riemannian manifold as we will see later in the beginning
of section 3. When m = 1, as we will discuss further in section 3.2, the Dirichlet
energies all reduce to E0, the energy for the Lebesgue measure. Thus the problems
we consider will be posed for m ≥ 2. We will show that it is possible to relate
W 1,2β (Rm+1
+ ;Rn) to W 1,2β (Ω;Rn) for Ω ⊂ Rm+1
+ using the Sobolev Embedding
Theorem for W 1,2 when m ≥ 3 and β ∈ (−1, 1). We can obtain the same relation
when m = 2 for β ∈ (−13, 1) using a different method of proof, but we currently
do not know if this can be extended to all β ∈ (−1, 1) when m = 2.
Lemma 2.2.1.1. Let m ∈ N with m ≥ 2 and Ω be an open bounded subset of
Rm+1+ . If m = 2 let β ∈ (−1
3, 1) and if m ≥ 3 let β ∈ (−1, 1). Then there
is a bounded linear operator I : W 1,2β (Rm+1
+ ;Rn) → W 1,2β (Ω;Rn) which satisfies
If = f |Ω for every f ∈ D+(Rm+1+ ;Rn). Moreover,
||Iv||W 1,2β (Ω;Rn) ≤ C||v||W 1,2
β (Rm+1+ ;Rn) (2.2.3)
13
for every v ∈ W 1,2β (Rm+1
+ ;Rn) where C is a positive constant depending on m and
the diameter of Ω.
Proof. First, suppose that (2.2.3) is true for all φ ∈ D+(Rm+1+ ;Rn), the dense
subset of smooth functions in W 1,2β (Rm+1
+ ;Rn). The operator D+(Rm+1+ ;Rn) →
W 1,2β (Ω;Rn) : f 7→ f |Ω may be uniquely extended to the operator I described in
the statement of the Lemma by taking limits on both sides of (2.2.3) and using
the completeness of W 1,2β (Ω;Rn). Hence we only need show that (2.2.3) holds for
all φ ∈ D+(Rm+1+ ;Rn).
We may bound the gradient term in the W 1,2β (Ω;Rn)-norm of φ using the
W 1,2β (Rm+1
+ ;Rn)-norm of φ. To conclude the proof we must show that∫Ω
|φ|2dµβ ≤ C
∫Rm+1
+
|∇φ|2dµβ (2.2.4)
for a constant C as specified in the statement of the lemma. In order to show
(2.2.4) we will apply the Sobolev Embedding Theorem (with respect to the
Lebesgue measure) on the intersection of hyperplanes which are orthogonal to
the m+ 1 axis, with Ω.
For the remainder of the proof, C ′ denotes a positive constant that only
depends on m. Observe that for every xm+1 ∈ [0,∞) we have φ(·, xm+1) ∈L2(Rm;Rn) and∇′φ(·, xm+1) ∈ L2(Rm;Rmn), where∇′ denotes the derivative of φ
with respect to x′ for (x′, xm+1) ∈ Rm× [0,∞). Hence φ(·, xm+1) ∈ W 1,2(Rm;Rn)
for every xm+1 ∈ [0,∞) and we may apply the Sobolev inequality for this space
to φ(·, xm+1). The Sobolev exponent in this case is 2mm−2
which satisfies 2mm−2≥ 2
for every m ≥ 3. Thus, for every xm+1 ∈ [0,∞),
(∫Rm|φ(x′, xm+1)|
2mm−2 dx′
)m−22m
≤ C ′(∫
Rm|∇′φ(x′, xm+1)|2dx′
) 12
(2.2.5)
for a constant C ′.
To see that (2.2.4) holds we will show something stronger: ||φ||2L2β(Ω;Rm)
is
bounded in terms of ||∇′φ||2L2β(Rm+1
+ ;Rmn). Define l(xm+1) = Ω∩ (Rm×xm+1) for
xm+1 ∈ [0,∞) and let a = infΩ(xm+1) and b = supΩ(xm+1). Notice that l(xm+1) is
contained in an m dimensional cube with side length 2diam(Ω) for every xm+1 ∈[0,∞). Hence
∫l(xm+1)
dx′ ≤ 2mdiam(Ω)m. An application of Fubini’s Theorem,
followed by an application of Holder’s inequality, with conjugate exponents mm−2
14
and m2
, yields∫Ω
xβm+1|φ|2dx
=
∫ b
a
xβm+1
∫l(xm+1)
|φ(x′, xm+1)|2dx′dxm+1
≤ C ′ (diam(Ω))2
∫ b
a
xβm+1
(∫l(xm+1)
|φ(x′, xm+1)|2mm−2 dx′
)m−2m
dxm+1. (2.2.6)
Combining (2.2.6) with (2.2.5) and using Fubini’s Theorem once more, we see
that∫Ω
xβm+1|φ|2dx ≤ C ′ (diam(Ω))2
∫ b
a
xβm+1
(∫l(xm+1)
|φ(x′, xm+1)|2mm−2 dx′
)m−2m
dxm+1
≤ C ′ (diam(Ω))2
∫ b
a
xβm+1
∫Rm|∇′φ(x′, xm+1)|2dx′dxm+1
≤ C ′ (diam(Ω))2
∫Rm+1
+
xβm+1|∇′φ|2dx. (2.2.7)
Hence, using the fact that∫
Ωxβm+1|∇φ|2dx ≤
∫Rm+1
+xβm+1|∇φ|2dx, together with
(2.2.6), yields (2.2.4) for φ ∈ D+(Rm+1+ ;Rn) which concludes the proof for m ≥ 3.
When m = 2 the preceding method used to establish (2.2.4) is no longer
viable; we are working in R3+ and are therefore no longer permitted to apply
the same Sobolev Embedding Theorem along hyperplanes orthogonal to the 3rd
coordinate axis. We have found a substitute for this method which holds when
m = 2 provided β > −13. In this case, Corollary 2 in Section 2.1.7 of [30] implies
that for every φ ∈ C∞0 (R3;Rn) we have
(∫R3
|x3|3β|φ|6dx
) 13
≤ C
∫R3
|x3|β|∇φ|2dx.
By approximation this holds for φ ∈ W 1,2β (R3;Rn). The even reflection of a
φ ∈ D+(R3+;Rn) in ∂Rm+1
+ , which we denote φ, is in W 1,2β (R3;Rn). Hence, we
deduce the preceding inequality holds for φ. Furthermore, Holder’s inequality
yields
∫Ω
xβ3 |φ|2dx ≤ |Ω|23
(∫R3
|x3|3β|φ|6dx
) 13
≤ C|Ω|23
∫R3
|x3|β|∇φ|2dx = 2C|Ω|23
∫R3
+
xβ3 |∇φ|2dx,
15
for every φ ∈ D+(R3+;Rn). An approximation argument then yields the statement
of the lemma, as in the case m ≥ 3.
Remark 2.2.1.1. Henceforth, when stating results for the space W 1,2β (Rm+1
+ ;Rn)
we will always assume m ≥ 2. If m ≥ 3 then we allow β ∈ (−1, 1) and if m = 2
we allow β ∈ (−13, 1). In the forthcoming chapters, Chapter 3, Chapter 5 and
Chapter 6, we always make these assumptions for m and β. However, we will
only usually state the results for β ∈ (−1, 1); if m = 2 then we are assuming
β ∈ (−13, 1).
Corollary 2.2.1.1. Let m ∈ N with m ≥ 3 and Ω be an open bounded subset of
Rm+1+ . Furthermore, let v ∈ W 1,2
β (Rm+1+ ;Rn). Then∫
Ω
xβm+1|v|2dx ≤ C ′ (diam(Ω))2
∫Rm+1
+
xβm+1|∇′v|2dx.
Proof. The inequality holds for all φ ∈ D+(Rm+1+ ;Rn) as this is (2.2.7) from the
proof of Lemma 2.2.1.1. By approximation we deduce the result for a general
v ∈ W 1,2β (Rm+1
+ ;Rn).
We can further connect W 1,2β (Rm+1
+ ;Rn) withW 1,p(Ω;Rn) by examining the re-
lationship between the weighted Sobolev space W 1,2β (Ω;Rn) and the usual Sobolev
spaces W 1,p(Ω;Rn) for p ∈ [1,∞). The proximity of Ω to ∂Rm+1+ is the crucial
factor in determining the nature of the connection between these spaces.
Lemma 2.2.1.2. Let β ∈ (−1, 1) and suppose Ω ⊂ Rm+1+ is open, bounded and
satisfies Ω ⊂ Rm+1+ . Then W 1,2
β (Ω;Rn) = W 1,2(Ω;Rn).
Proof. For such Ω, the norms || · ||W 1,2β (Ω;Rn) and || · ||W 1,2(Ω;Rn) are equivalent and
the statement of the Lemma follows for every β ∈ (−1, 1).
If ∂Ω intersects ∂Rm+1+ the situation is different depending on the sign of β.
The following two Lemmata summarise the relationship between the weighted
and usual Sobolev spaces in this situation.
Lemma 2.2.1.3. Let β ∈ (−1, 0] and suppose Ω ⊂ Rm+1+ is open and bounded.
Then W 1,2β (Ω;Rn) ⊂ W 1,2(Ω;Rn).
Proof. The norm || · ||W 1,2(Ω;Rn) is dominated by a constant (depending on Ω and
β) multiple of the norm || · ||W 1,2β (Ω;Rn) on such Ω. Thus the Lemma is proved.
Lemma 2.2.1.4. Let β ∈ (0, 1) and suppose Ω ⊂ Rm+1+ is open and bounded.
Then W 1,2β (Ω;Rn) ⊂ W 1,p(Ω;Rn) for every 1 ≤ p < 2
1+β.
16
Proof. Let 1 > β > 0 and 1 ≤ p < 2. Then for every measurable f ∈ L2β(Ω;Rn)
we have ∫Ω
|f |pdx =
∫Ω
x− pβ
2m+1x
pβ2m+1|f |pdx
≤(∫
Ω
(x− pβ
2m+1)qdx
) 1q(∫
Ω
xβm+1|f |2dx
) p2
(2.2.8)
where q = 22−p is the conjugate exponent of 2
p. The right hand side of (2.2.8) is
finite whenever
(∫Ω
(x− pβ
2m+1)qdx
) 1q
< ∞. Since Ω is bounded, we calculate that
this is the case as long as
1− βp
2− p> 0
and rearranging gives the condition p < 21+β
. It follows from (2.2.8) that if
β ∈ (0, 1) and v ∈ W 1,2β (Ω;Rn) then
||v||W 1,p(Ω;Rn) ≤ C||v||W 1,2β (Ω;Rn)
for every p < 21+β
where C is a positive constant that depends on Ω and p and
hence on β.
Consequently, in view of Lemmata 2.2.1.1, 2.2.1.2, 2.2.1.3 and 2.2.1.4 we have
shown that, provided m ≥ 3, the restrictions of elements of W 1,2β (Rm+1
+ ;Rn) to
open, bounded Ω ⊂ Rm+1+ are elements of W 1,2
β (Ω;Rn) and hence of W 1,p(Ω;Rn)
for some 1 ≤ p ≤ 2 depending on Ω and β.
2.3 Analytical Properties of Weighted Sobolev
Spaces
There is general theory of weighted Sobolev Spaces defined via measures satis-
fying Muckenhoupt’s, and even more general, weight conditions. For instance,
an axiomatic approach to this theory, tailored to the study of degenerate elliptic
equations, is described in Chapter 1 of [25]. A more comprehensive account is
provided in Chapter 2 of [47].
Shortly we will prove results required to study the variational problems related
to the energies Eβ. It is possible, due to the nature of the weight functions
xβm+1, to obtain the necessary results using only the theory of the Sobolev spaces
W 1,2, and not the theory of weighted Sobolev spaces. This approach has the
17
advantage that, for some of the inequalities, we are able to prove estimates with
constants independent of β ∈ (−1, 1). When considering results on a domain
whose boundary intersects ∂Rm+1+ , it will suffice to assume the domain is either
a half-cube or half-ball with centre in ∂Rm+1+ .
2.3.1 Behaviour of Integrals Over Balls and Cubes Under
Bi-Lipschitz Maps
Most of the integral estimates we will use are given over balls contained in Rm+1+
or half-balls with centres in Rm × 0 where m ∈ N. However, sometimes it
may be necessary, or more convenient, to consider integrals over cubes, half-
cubes, rectangles or other simple domains instead. We need a means to compare
estimates over such domains, to this end we now discuss how integrals with respect
to the measures dµβ transform under bi-Lipschitz mappings between subsets of
Rm+1.
Let Ω, Ω ⊂ Rm+1 be open. Suppose Φ : Ω→ Φ(Ω) = Ω is a bi-Lipschitz map
with inverse Φ−1 : Ω → Ω. The classical derivatives ∇Φ and ∇Φ−1 exist almost
everywhere in their respective domains by Rademacher’s Theorem. Let f be a
non-negative, integrable function. A change of variables gives∫Φ(Ω)
xβm+1fdx =
∫Ω
(Φ(x))βm+1f(Φ(x))|det(∇Φ(x))|dx
and ∫Φ−1(Ω)
xβm+1fdx =
∫Ω
(Φ−1(x))βm+1f(Φ−1(x))|det(∇Φ−1(x))|dx.
In order for such integrals to be sufficiently preserved when mapping between Ω
and Ω we stipulate further that Φ satisfies∫Φ(Ω)
xβm+1fdx =
∫Ω
(Φ(x))βm+1f(Φ(x))|det(∇Φ(x))|dx ≤ C
∫Ω
xβm+1f(Φ(x))dx
(2.3.1)
and ∫Φ−1(Ω)
xβm+1fdx =
∫Ω
(Φ−1(x))βm+1f(Φ−1(x))|det(∇Φ−1(x))|dx
≤ C
∫Ω
xβm+1f(Φ−1(x))dx (2.3.2)
for a positive constant C. Any bi-Lipschitz map that satisfies (2.3.1) and (2.3.2)
will be called a dµβ-equivalence from Ω to Ω if C = C(m,β) and a uniform
18
dµβ-equivalence from Ω to Ω if C = C(m).
A necessary and sufficient condition for Φ to satisfy (2.3.1) and (2.3.2) is that
it must preserve the weight function xβm+1 in the following sense. We introduce
some further terminology to make this notion precise; if Φ : Ω→ Ω satisfies
(Φ(x))βm+1 ≤ Cxβm+1 for x ∈ Ω (2.3.3)
and
(Φ−1(x))βm+1 ≤ Cxβm+1 for x ∈ Ω (2.3.4)
for a positive C = C(m,β) then we say Φ is an xβm+1-equivalence from Ω to Ω
and if C = C(m) then we say Φ is a uniform xβm+1-equivalence from Ω to Ω.
We discuss in detail the bi-Lipschitz, piecewise C1 with piecewise C1 inverse
maps which allow us to transform between cubes and balls and half-cubes and
half-balls. The purpose of our calculations is to show that such a map is a
uniform dµβ and xβm+1-equivalence between half-balls and half-cubes with the
same centres. All other bi-Lipschitz maps we use will be discussed at their time
of use and the required calculations are similar or less tedious than those given
below.
First, let us introduce some notation for the sets we consider. Let y ∈ Rm+1,
m ∈ N and r > 0. Typically we will work in m+ 1 dimensional Euclidean space.
Consider the m+ 1-dimensional open cubes
Qm+1r (y) = x ∈ Rm+1 : xi ∈ (yi − r, yi + r) for i = 1, . . . ,m+ 1
and the m+ 1-dimensional open balls
Bm+1r (y) = x ∈ Rm+1 : |x− y| < r.
For y ∈ ∂Rm+1+ and r > 0 we define the m + 1-dimensional half-cubes and half-
balls
Q+,m+1r (y) = Qm+1
r (y) ∩ Rm+1+
and
B+,m+1r (y) = Bm+1
r (y) ∩ Rm+1+
respectively. In contexts where we do not need to distinguish the dimension, we
supress the superscript and use the notation Qm+1r (y) = Qr(y), Bm+1
r (y) = Br(y),
Q+r (y) = Q+,m+1
r (y) and B+r (y) = B+,m+1
r (y).
Henceforth we work in m + 1 dimensions for m ∈ N. Let y ∈ Rm+1 and
19
consider the cones
Cy,k = x ∈ Rm+1\y : |xk − yk| = maxj∈1,...,m+1|zj − yj|
and define
Φy,k : Cy,k → Cy,k : x 7→ |xk − yk|(x− y)
|x− y|+ y.
Then each Φy,k is Lipschitz continuous in Cy,k and C1 in the interior of Cy,k.
Furthermore, each Φy,k has inverse
Φ−1y,k : Cy,k → Cy,k : x 7→ |x− y| (x− y)
|xk − yk|+ y,
which is Lipschitz continuous in Cy,k and C1 in the interior of Cy,k. Now we may
define a bi-Lipschitz piecewise C1 map Φy : Rm+1 → Rm+1 with piecewise C1
inverse; let Φy|Cy,k = Φy,k for k = 1, . . . ,m + 1, let Φy|Cy,k = Φy,k for one such
k whenever the Cy,k overlap and define Φy(y) = y. Then Φy is well defined and
bi-Lipschitz but fails to be C1 on the intersections of the Cy,k and at y.
Next we show how transformations between Q+r (y) and B+
r (y), where y ∈∂Rm+1
+ , under Φy and Φ−1y , affect integrals over these regions. Note that the defi-
nition of Φy implies Φy(Q+r (y)) = B+
r (y). Recall the equivalence of the Euclidean
and maximum distance functions on Rm+1, in particular note that
maxj∈1,...,m+1
|xj − yj| ≤ |x− y| ≤ (m+ 1)12 maxj∈1,...,m+1
|xj − yj|.
Let x ∈ Rm+1+ and suppose further that x ∈ C l
y,k for some k ∈ 1, . . . ,m + 1 so
that maxj∈1,...,m+1 |xj − yj| = |xk − yk|. Then
1
(m+ 1)12
xm+1 ≤ (Φy(x))m+1 = |xk − yk|xm+1
|x− y|≤ xm+1 (2.3.5)
and
xm+1 ≤(Φ−1y (x)
)m+1
= |x− y| xm+1
|xk − yk|≤ (m+ 1)
12xm+1. (2.3.6)
We also calculate
(∇Φy,k(x))ij = sgn(xk − yk)δjkxi − yi|x− y|
+ |xk − yk|δij|x− y|
− |xk − yk|(xi − yi)(xj − yj)
|x− y|3,
20
where δij = 1 if i = j and δij = 0 otherwise. We obtain a similar expression for
(∇Φ−1y )ij and hence deduce there is a positive constant c = c(m) such that
|∇Φy(x)|, |det(∇Φy(x))|, |∇Φ−1y (x)| and |det(∇Φ−1
y (x))| ≤ c. (2.3.7)
Suppose f : Q+r (y) → [0,∞] and g : B+
r (y) → [0,∞] are dµβ integrable. We
combine (2.3.5), (2.3.6) and (2.3.7) with (2.3.1) and (2.3.2) to deduce that∫Q+r (y)
xβm+1fdx ≤ ccβ1
∫B+r (y)
xβm+1f(Φ−1y (x))dx (2.3.8)
and ∫B+r (y)
xβm+1fdx ≤ ccβ2
∫Q+r (y)
xβm+1f(Φy(x))dx, (2.3.9)
for two constants c1 = c1(m) and c2 = c2(m) which arise from (2.3.5) and (2.3.6)
respectively. Since β ∈ (−1, 1), we can choose another constant C = C(m) such
that ccβ1 ≤ C and ccβ2 ≤ C. Hence the map Φy is both a uniform dµβ-equivalence
and a uniform xβm+1-equivalence from Q+r (y) to B+
r (y).
2.3.2 Traces of Sobolev Functions
The boundary values of Sobolev functions defined on open Ω ⊂ Rm+1+ will play
an important role in the variational problems we will consider.
Henceforth we will assume that we are working on domains Ω ⊂ Rm+1+ such
that a continuous linear trace operator T : W 1,p(Ω;Rn) → Lp(∂Ω;Rn) exists for
some p ∈ (1, 2] with Tv = v|∂Ω whenever additionally v ∈ C(Ω;Rn). This is
the case, for instance, on open, bounded Ω ⊂ Rm+1+ with Lipschitz boundary,
as illustrated in [18] Section 4.3 Theorem 1. In view of Lemmata 2.2.1.3 and
2.2.1.4, we therefore have a continuous linear trace operator T : W 1,2β (Ω;Rn) →
Lp(∂Ω;Rn) with Tv = v|∂Ω whenever additionally v ∈ C(Ω;Rn). Here we may
choose p ∈ (1, 2] if Ω ⊂ Rm+1+ , p ∈ (1, 2] if ∂Ω ∩ ∂Rm+1
+ 6= ∅ and β ∈ (−1, 0] and
p ∈ (1, 21+β
) if ∂Ω ∩ ∂Rm+1+ 6= ∅ and β ∈ (0, 1).
The values of functions in W 1,2β (Rm+1
+ ;Rn) on open O ⊂ Rm × 0 will be
of particular importance. We will assume that O ⊂ ∂Ω for an Ω such that the
trace operators mentioned previously exist, this way we have an interpretation
for traces of elements of the homogeneous Sobolev spaces, given by composing
the trace operators described previously with the embedding given in Lemma
2.2.1.1.
21
2.3.3 Poincare Inequality for W 1,2β
Poincare inequalities are a fundamental aspect of both the theory of Sobolev
spaces and the analysis of partial differential equations. We will require inequal-
ities regarding the L2β distance between a function and its average in terms of its
energy.
Before proceeding any further with a discussion of the relevant Poincare
inequalities, we observe a related property of the minimisation of the integral∫Ω|v − λ|2dµβ over all constant vectors λ ∈ Rn. Let vΩ,β = 1∫
Ω dµβ
∫Ωvdµβ and
vΩ,0 = vΩ = 1∫Ω dx
∫Ωvdx where Ω ⊂ Rm+1 is open and bounded and v is integrable
on Ω.
Lemma 2.3.3.1. Suppose Ω ⊂ Rm+1 is open and bounded and let v ∈ W 1,2β (Ω;Rn).
Then
infλ∈Rn
∫Ω
|v − λ|2dµβ =
∫Ω
|v − vΩ,β|2dµβ.
Proof. To prove the Lemma we calculate the first and second order partial deriva-
tives of the function
f : Rn → R : λ→ f(λ) =
∫Ω
|v − λ|2dµβ
with respect to the components λi, for i = 1, . . . , n, of λ and use calculus to find
and determine the nature of any critical points of f .
If λ is a critical point f then ∇f(λ) = 0. Hence,
∂f
∂λi(λ) = 2
∫Ω
(λi − vi)dµβ = 0
for i = 1, . . . , n. Thus λi = (vi)Ω,β and hence λ = vΩ,β. To see that vΩ,β minimises
f we calculate the second derivatives of f . We have ∂2f∂λiλj
= 0 for i 6= j and∂2f∂λ2
i= 2
∫Ω
dµβ. Hence the determinant of the Hessian of f is 2n(∫
Ωdµβ
)n> 0
for every λ in Rn. This implies that f has a local minimum at λ = vΩ,β and,
furthermore, that f is convex. Thus f attains a global minimum at λ = vΩ,β.
This property allows us to readily deduce a Poincare inequality for W 1,2β func-
tions on any Br(y) or Qr(y) with closure contained in Rm+1+ .
Lemma 2.3.3.2. Let β ∈ (−1, 1), y ∈ Rm+1+ , r > 0 and suppose Br(y) and Qr(y)
have closures contained in Rm+1+ . Let Ω denote either Br(y) or Qr(y). Then
∫Ω
|v − vΩ,β|2dµβ ≤ Cr2 supΩ(xβm+1)
infΩ(xβm+1)
∫Ω
|∇v|2dµβ
22
for a positive constant C = C(m).
Proof. We combine the fact that the weights xβm+1 are bounded on Ω with Lemma
2.3.3.1 and apply the Poincare inequality for W 1,2. First, notice that Lemma
2.3.3.1 gives ∫Ω
|v − vΩ,β|2dµβ ≤∫
Ω
|v − vΩ|2dµβ.
Since the weights xβm+1 are bounded on Ω we have∫Ω
|v − vΩ|2dµβ ≤ supΩ
(xβm+1)
∫Ω
|v − vΩ|2dx.
The Poincare inequality for W 1,2(Ω;Rn) yields∫Ω
|v − vΩ|2dx ≤ Cr2
∫Ω
|∇v|2dx
and using the boundedness of the weights again gives∫Ω
|∇v|2dx ≤ 1
infΩ(xβm+1)
∫Ω
|∇v|2dµβ.
Combining the above yields the statement of the Lemma.
The factorsupΩ(xβm+1)
infΩ(xβm+1)in Lemma 2.3.3.2 is inconvenient in general, depending
on the domain and the sign of β, it may blow up or degenerate on domains
close to or far from ∂Rm+1+ . However, on a particular class of balls in Rm+1
+ , as
discussed subsequently in section 3.4, this term can actually be bounded above by
a constant depending only on m. These inequalities, combined with a Poincare
inequality with respect to the measures dµβ on open half-cubes and half-balls
with centres on ∂Rm+1+ , will be sufficient for our purposes.
To prove some of our Lemmata regarding inequalities for functions hereafter,
we will reduce the proofs to the case of maps defined on the easiest domain to work
with. This will involve the use of bi-Lipschitz maps which are dµβ-equivalences
between the domains as discussed in section 2.3.1. Furthermore we will make use
of scale and translation invariance to rescale the domain to unit size and centre it
at the origin. The idea is to prove the Lemma on such a domain and then apply
this version of the Lemma to a suitably rescaled map to deduce the Lemma for
other domains. In the next two Lemmata, we give the details of this process,
discussing the use of bi-Lipschitz transformations in Lemma 2.3.3.3 and rescaling
in Lemma 2.3.5.2.
23
There is a general Poincare inequality for A2 weights in which the constant
may depend on the weight. Next we prove a Poincare inequality for the weights
xβm+1 such that the constant is uniform in β and thus independent of these weights.
Lemma 2.3.3.3. Let v ∈ W 1,2β (Ω;Rn) where Ω is either a half-ball B+
r (y) or
half-cube Q+r (y) for y ∈ ∂Rm+1
+ and r > 0. Then∫Ω
|v − vΩ,β|2dµβ ≤ Cr2
∫Ω
|∇v|2dµβ (2.3.10)
for a constant C which only depends on m.
Proof. Throughout, C denotes a postive constant that depends only on m. First
we reduce the inequality for half-balls to the case of half-cubes. To this end,
suppose that (2.3.10) holds for a half-cube Q+r (y) and let Φy : Q+
r (y) → B+r (y)
denote the bi-Lipschitz map described in section 2.3.1. An application of Lemma
2.3.3.1 gives∫B+r (y)
|v − vB+r (y),β|
2dµβ ≤∫B+r (y)
|v − (v Φy)Q+r (y),β|
2dµβ. (2.3.11)
Since Φy is a uniform dµβ-equivalence from Q+r (y) to B+
r (y), as described in
section 2.3.1, there is a constant c = c(m) such that∫B+r (y)
|v − (v Φy)Q+r (y),β|
2dµβ ≤ c
∫Q+r (y)
|v Φy(x)− (v Φy)Q+r (y),β|
2dµβ.
(2.3.12)
The Poincare inequality for half-cubes, which we have assumed holds for now,
gives∫Q+r (y)
|v Φy(x)− (v Φy)Q+r (y),β|
2dµβ ≤ Cr2
∫Q+r (y)
|∇(v Φy)|2dµβ, (2.3.13)
and since Φy has bounded gradient in terms of a constant depending only on m,
as in (2.3.7), we have∫Q+r (y)
|∇(v Φy)|2dµβ ≤ C
∫Q+r (y)
|∇v(Φy(x))|2dµβ. (2.3.14)
The map Φ−1y also satisfies (2.3.7), hence∫
Q+r (y)
|∇v(Φy(x))|2dµβ ≤ C
∫B+r (y)
|∇v|2dµβ. (2.3.15)
24
Combining (2.3.11), (2.3.12), (2.3.13), (2.3.14) and (2.3.15) yields (2.3.10). Hence
we may assume Ω = Q+r (y).
If β = 0 then (2.3.10) is the Poincare inequality in W 1,2(Q+r (y);Rn). The
approach we use to prove the Lemma for other β requires us to distinguish the
cases β ∈ (−1, 0) and β ∈ (0, 1); however, the underlying idea in each case is the
same. We will take advantage of Lemma 2.3.3.1 and prove that∫Q+r (y)
xβm+1|v − λ|2dx ≤ Cr2
∫Q+r (y)
xβm+1|∇v|2dx (2.3.16)
for a λ ∈ Rn depending on β. Combined with Lemma 2.3.3.1 this yields (2.3.10).
Observe that (2.3.16) is invariant under re-scaling and translation in the vari-
ables x1, . . . , xm in the sense that if (2.3.16) holds on Q+1 (0), then we can obtain
(2.3.16) on any Q+r (y) for r > 0, y ∈ ∂Rm+1
+ , with the same constant C, by ap-
plying the inequality on Q+1 (0) to the rescaled function vr(x) = v(rx+ y). Hence
we may assume r = 1 and y = 0.
In order to find λ ∈ Rn as in (2.3.16) we consider the cases β ∈ (−1, 0) and
β ∈ (0, 1) separately. However, in either case we consider∫Q+
1 (0)
h(xm+1)|v − λ|2dx (2.3.17)
for a function h : (0, 1) → (0,∞) closely related to the weights xβm+1. The
idea is to re-write (2.3.17), using Fubini’s Theorem, in terms of the integral of
the derivative of h multiplied by a term to which we may apply the Poincare
inequality for W 1,2 functions, provided λ is chosen accordingly. We use a second
application of Fubini’s Theorem to write the integrals in terms of h again which
will conclude the proofs.
The case β ∈ (0, 1)
We will show that for β ∈ (0, 1), a sufficient choice of λ ∈ Rn to ensure that v
satisfies (2.3.16) on Q+1 (0) is λ = vΩ, where Ω = (−1, 1)m×(1
2, 1). For convenience
we denote (−1, 1)m by Q′ so that Q+1 (0) = Q′ × (0, 1) and Ω = Q′ × (1
2, 1).
Furthermore, dx′ denotes the m-dimensional Lebesgue measure.
Define the function
h(t) =
tβ for t ∈ [0, 12]
12β
for t ∈ (12, 1].
25
Note h′(t) = 0 for t ∈ (12, 1] and consider (2.3.17) with this choice of h. We have∫
Q+1 (0)
h(xm+1)|v − vΩ|2dx =
∫Q′
∫ 1
0
∫ xm+1
0
h′(s)ds|v − vΩ|2dxm+1dx′. (2.3.18)
An application of Fubini’s Theorem yields∫Q′
∫ 1
0
∫ xm+1
0
h′(s)ds|v − vΩ|2dxm+1dx′ =
∫Q′
∫ 1
0
∫ 1
s
h′(s)|v − vΩ|2dxm+1dsdx′
=
∫ 12
0
h′(s)
∫Q′
∫ 1
s
|v − vΩ|2dxm+1dx′ds.
(2.3.19)
Now we use the Poincare inequality for W 1,2 functions. It follows from [21]
Chapter 7 equation 7.45 that for all s ∈ (0, 12] we have∫
Q′
∫ 1
s
|v − vΩ|2dxm+1dx′
≤(C
|Ω|
) 2mm+1
diam(Q′ × [s, 1])2(m+1)
∫Q′
∫ 1
s
|∇u|2dxm+1dx′
≤ C
∫Q′
∫ 1
s
|∇u|2dxm+1dx′. (2.3.20)
Combining (2.3.18), (2.3.19) and (2.3.20) gives
∫Q+
1 (0)
h(xm+1)|v − vΩ|2dx ≤ C
∫ 12
0
h′(s)
∫Q′
∫ 1
s
|∇v|2dxm+1dx′ds. (2.3.21)
26
Now we change the order of integration again using Fubini’s Theorem. We have∫ 12
0
h′(s)
∫Q′
∫ 1
s
|∇v|2dxm+1dx′ds =
∫Q′
∫ 12
0
h′(s)
∫ 1
s
|∇v|2dxm+1dsdx′
=
∫Q′
∫ 12
0
∫ xm+1
0
h′(s)ds|∇v|2dxm+1dx′
+
∫Q′
∫ 1
12
∫ 12
0
h′(s)ds|∇v|2dxm+1dx′
=
∫Q′
∫ 12
0
h(xm+1)|∇v|2dxm+1dx′
+1
2β
∫Q′
∫ 1
12
|∇v|2dxm+1dx′
=
∫Q+
1 (0)
h(xm+1)|∇v|2dx. (2.3.22)
We combine (2.3.22) with (2.3.21) to see that∫Q+
1 (0)
h(xm+1)|v − vΩ|2dx ≤ C
∫Q+
1 (0)
h(xm+1)|∇v|2dx. (2.3.23)
This estimate holds independently of β ∈ (0, 1). Lastly notice that∫Q+
1 (0)
h(xm+1)|f |dx ≤∫Q+
1 (0)
xβm+1|f |dx ≤ C
∫Q+
1 (0)
h(xm+1)|f |dx (2.3.24)
for any integrable f and a constant C that can be chosen independently of β ∈(0, 1). Thus, combining (2.3.23) and (2.3.24) shows that (2.3.16) holds with
λ = vΩ and hence we apply Lemma 2.3.3.1 to conclude the proof for β ∈ (0, 1).
The case β ∈ (−1, 0)
Let β ∈ (−1, 0). Then v ∈ W 1,2(Q+1 (0);Rn) by Lemma 2.2.1.3. Thus we may
apply the trace operator T : W 1,2(Q+1 (0);Rn) → L2(Q′ × 0;Rn) to v. We will
show that a sufficient choice of λ ∈ Rn to ensure v satisfies (2.3.16) on Q+1 (0) is
λ = (Tv)Q′ .
Define
h(t) = tβ − 1
27
for t ∈ (0, 1] and consider (2.3.17) again. We have∫Q+
1 (0)
h(xm+1)|v − (Tv)Q′|2dx = −
∫Q′
∫ 1
0
∫ 1
xm+1
h′(s)ds|v − (Tv)Q′ |2dx′dxm+1.
(2.3.25)
We apply Fubini’s Theorem to see that∫Q′
∫ 1
0
∫ 1
xm+1
h′(s)ds|v − (Tv)Q′ |2dxm+1dx′
=
∫Q′
∫ 1
0
∫ s
0
h′(s)|v − (Tv)Q′ |2dxm+1dsdx′
=
∫ 1
0
h′(s)
∫Q′
∫ s
0
|v − (Tv)Q′|2dxm+1dx′ds. (2.3.26)
To conclude, we need to use a variant of the Poincare inequality for W 1,2 func-
tions, namely∫Q′
∫ s
0
|v − (Tv)Q′|2dxm+1dx′ ≤ C
∫Q′
∫ s
0
|∇v|2dxm+1dx′ (2.3.27)
where s ∈ (0, 1] and C is a positive constant independent of s. We digress to
prove this assertion.
A Poincare Inequality Involving Traces
First we show that it suffices to prove (2.3.27) for s = 1. To this end, suppose
the inequality is true for s = 1. That is, assume that∫Q′
∫ 1
0
|v − (Tv)Q′|2dxm+1dx′ ≤ C
∫Q′
∫ 1
0
|∇v|2dxm+1dx′.
28
Define vs(x) = v(x′, sxm+1) for s ∈ (0, 1]. Then Tv = Tvs for every such s. Using
the change of variables xm+1 7→ sxm+1 we calculate∫Q′
∫ s
0
|v − (Tv)Q′|2dxm+1dx′ = s
∫Q′
∫ 1
0
|vs − (Tvs)Q′ |2dxm+1dx′
≤ sC
∫Q′
∫ 1
0
|∇(vs)|2dxm+1dx′
≤ sC
∫Q′
∫ 1
0
|∇v(x′, sxm+1)|2dxm+1dx′
= C
∫Q′
∫ s
0
|∇v|2dxm+1dx′.
It follows that∫Q′
∫ s
0
|v − (Tv)Q′|2dxm+1dx′ ≤ C
∫Q′
∫ s
0
|∇v|2dxm+1dx′
for s ∈ (0, 1] where C is a positive constant independent of s. Hence to show
(2.3.27) holds independently of s ∈ (0, 1] we only need prove the inequality for
s = 1.
To proceed, we adapt one of the many proofs of the Poincare inequality for
W 1,2 functions, see for example, [46] section 1.3, Lemma 2. Suppose, for a con-
tradiction, that for every C = C(m) there is a v ∈ W 1,2(Q+1 (0),Rn) such that
C
∫Q+
1 (0)
|∇v|2dxm+1dx′ <
∫Q′
∫ 1
0
|v − (Tv)Q′|2dx.
In particular, we choose a sequence (vk)k∈N of vk ∈ W 1,2(Q+1 (0),Rn) satisfying∫
Q+1 (0)
|∇vk|2dx <1
k
∫Q+
1 (0)
|vk − (Tvk)Q′|2dx. (2.3.28)
Define,
wk(x) =vk(x)− (Tvk)Q′(∫
Q+1 (0)|vk − (Tvk)Q′|2dx
) 12
.
Then∫Q+
1 (0)|wk|2dx = 1,
∫Q′Twkdx
′ = 0 and
∇wk =∇vk(∫
Q+1 (0)|v − (Tvk)Q′ |2dx
) 12
29
for all k. We substitute this expression for ∇wk into (2.3.28) to see that∫Q+
1 (0)
|∇wk|2dx <1
k. (2.3.29)
Thus wk is a bounded sequence inW 1,2(Q+1 (0);Rn) and so the Rellich-Kondrachov
compactness Theorem yields a subsequence (wkj)j∈N which converges strongly
in L2(Q+1 (0);Rn) to a limit w ∈ W 1,2(Q+
1 (0);Rn). Extracting a subsequence
again, if necessary, we may assume that wkj → w almost everywhere as j →∞.
Furthermore, ∇wkj → ∇w weakly in L2 since the unit ball in a Hilbert spaces
is weakly compact. Hence, in view of (2.3.29) and the lower semicontinuity of
the L2 norm it follows that ∇w = 0 almost everywhere in Q+1 (0). Therefore w
is constant. Since wkj → w in L2 it follows that w 6= 0 because∫Q+
1 (0)|w|2dx =
limj→∞∫Q+
1 (0)|wkj |2dx = 1. However, (2.3.29) implies
∫Q+
1 (0)|∇wk|2dx → 0 =∫
Q+1 (0)|∇w|2dx and since ∇wk to ∇w weakly in L2, we deduce ∇wk converges to
∇w strongly in L2. Moreover,∫Q′Twkjdx
′ = 0 for all j and the continuity of the
trace operator thus implies∫Q′Twdx′ = 0. As w is constant, its trace is constant
and we must have Tw = 0. The only constant function with zero trace is the zero
function but we have already shown that w is non-zero which is a contradiction.
Thus (2.3.27) holds.
Return to the proof of the Poincare Inequality for β ∈ (−1, 0).
Recall (2.3.26). In view of (2.3.27), noting that h′(t) ≤ 0, we see that
−∫ 1
0
h′(s)
∫Q′
∫ s
0
|v − (Tv)Q′ |2dxm+1dx′ds
≤ −C∫ 1
0
h′(s)
∫Q′
∫ s
0
|∇v|2dxm+1dx′ds. (2.3.30)
Hence, combining (2.3.25), (2.3.26) and (2.3.30) and applying Fubini’s Theorem
once more we have∫Q+
1 (0)
h(xm+1)|v − (Tv)Q′ |2dx ≤ −C
∫ 1
0
h′(s)
∫Q′
∫ s
0
|∇v|2dxm+1dx′ds
= C
∫Q+
1 (0)
h(xm+1)|∇v|2dx.
30
We rearrange the above, noting that 1 ≤ xβm+1 on Q+1 (0), and apply (2.3.27) with
s = 1 to see that∫Q+
1 (0)
xβm+1|v − (Tv)Q′|2dx ≤
∫Q+
1 (0)
|v − (Tv)Q′ |2dx
+ C
∫Q+
1 (0)
h(xm+1)|∇v|2dx
≤ C
∫Q+
1 (0)
xβm+1|∇v|2dx.
Hence (2.3.16) holds with λ = TvQ′ and we apply Lemma 2.3.3.1 to conclude the
proof for β ∈ (−1, 0).
It will be useful to have a version of the Poincare inequality on B+r (y), with
ym+1 = 0 but with vB+r (y),β replaced by vB+
θr(y),β for θ ∈ (0, 1). Such a statement
is proved using the Poincare inequality, Lemma 2.3.3.3.
Lemma 2.3.3.4. Let v ∈ W 1,2β (Ωr;Rn) where Ωr is either a half-ball B+
r (y) or
half-cube Q+r (y) with y ∈ ∂Rm+1
+ and r > 0. Let θ ∈ (0, 1). Then∫Ωr
|v − vΩθr,β|2dµβ ≤ Cθ−(1+m+β)r2
∫Ωr
|∇v|2dµβ (2.3.31)
for a constant C = C(m).
Proof. We have∫Ωr
|v − vΩθr,β|2dµβ ≤ 2
∫Ωr
|vΩr,β − vΩθr,β|2dµβ + 2
∫Ωr
|v − vΩr,β|2dµβ
= 2r1+m+β
∫Ω1
dµβ|vΩr,β − vΩθr,β|2 + 2
∫Ωr
|v − vΩr,β|2dµβ.
(2.3.32)
The Poincare inequality, Lemma 2.3.3.3, yields∫Ωr
|v − vΩr,β|2dµβ ≤ Cr2
∫Ωr
|∇v|2dµβ (2.3.33)
so to conclude, we must consider the remaining term in (2.3.32). An application
31
of Holder’s inequality gives
|vΩr,β − vΩθr,β|2 ≤(∫
Ωθr
dµβ
)−1 ∫Ωθr
|v − vΩr,β|2dµβ
≤ (θr)−(1+m+β)
(∫Ω1
dµβ
)−1 ∫Ωr
|v − vΩr,β|2dµβ.
Thus, using Lemma 2.3.3.3 again, we find
|vΩr,β − vΩθr,β|2 ≤ (θr)−(1+m+β)
(∫Ω1
dµβ
)−1
Cr2
∫Ωr
|∇v|2dµβ. (2.3.34)
Combining (2.3.32), (2.3.33) and (2.3.34) concludes the proof.
2.3.4 Pointwise Bounds for Functions in Terms of Their
Integrals on an Interval
We discuss bounding a measurable function, defined on an interval, in terms of
the integral of the function over the interval. Let (a, b) ⊂ R with a < b and
consider the measure dµ1β = |x|βdx on (a, b). Suppose f : (a, b) → [0,∞] is
a dµ1β-integrable function and let θ ∈ (0, 1). Then for all x ∈ (a, b), with the
exception of a set of dµ1β-measure θ
∫ ba
dµ1β, we have
f(x) ≤ 1
θ∫ ba
dµ1β
∫ b
a
fdµ1β. (2.3.35)
Otherwise the reverse inequality would hold on a set P of measure greater than
θ∫ ba
dµ1β and integrating over P would yield
∫ b
a
fdµ1β <
∫P
dµ1β
θ∫ ba
dµ1β
∫ b
a
fdµ1β <
∫P
fdµ1β
which is a contradiction.
Similary, we deduce an analogous weaker statement. There always exists an
x ∈ (a, b) such that
f(x) ≤ 1∫ ba
dµ1β
∫ b
a
fdµ1β (2.3.36)
otherwise the reverse inequality would hold for every x ∈ (a, b) and integrating
32
over (a, b) would give the contradiction∫ b
a
fdµ1β <
∫ b
a
fdµ1β.
2.3.5 Compactness of the Embedding W 1,2β → L2
β
Compact embeddings provide a means to analyse bounded sequences of solutions
to partial differential equations. We will, for instance, need to consider sequences
of solutions to (2.0.1).
Compactness of the Embedding on Domains with Closure in Rm+1+
When Ω ⊂ Rm+1+ is bounded, open and satisfies Ω ⊂ Rm+1
+ we may directly take
advantage of the Rellich Kondrachov Compactness Theorem to deduce that the
embedding W 1,2β (Ω;Rn) → L2
β(Ω;Rn) is compact. We summarise this fact in a
Lemma, which follows directly from [46] Section 1.3, Lemma 1, along with some
additional properties of bounded sequences in W 1,2β (Ω;Rn).
Lemma 2.3.5.1. Let β ∈ (−1, 1) and suppose Ω ⊂ Rm+1+ is bounded and open
with Ω ⊂ Rm+1+ . Suppose that (vj)j∈N is a sequence in W 1,2
β (Ω;Rn) which satisfies
supj ||vj||W 1,2β (Ω;Rn) < ∞. Then there exists a subsequence (vjk)k∈N and a v ∈
W 1,2β (Ω;Rn) such that
1. vjk v in W 1,2β (Ω;Rn)
2. vjk → v in L2β(Ω;Rn)
3.∫
Ωxβm+1|∇v|2dx ≤ lim infk→∞
∫Ωxβm+1|∇vjk |2dx.
Proof. The statement of the Lemma for β = 0 is Lemma 1 of Section 1.3 in [46].
For β 6= 0, statement 1 is a consequence of the weak compactness of the unit ball
in the Hilbert spaces W 1,2β (Ω;Rn). Recall that W 1,2
β (Ω;Rn) = W 1,2(Ω;Rn) by
Lemma 2.2.1.2 and similarly L2β(Ω;Rn) = L2(Ω;Rn) on the Ω in consideration.
Since the two norms ||·||W 1,2β (Ω;Rn) and ||·||W 1,2(Ω;Rn) and the two norms ||·||L2
β(Ω;Rn)
and || · ||L2(Ω;Rn) are equivalent, we conclude that statement 2 for sequences in
W 1,2β (Ω;Rn) follows from the case for W 1,2(Ω;Rn). Statement 2 combined with
the lower semi-continuity of the Hilbert space norm ||·||W 1,2β (Ω;Rn) yields statement
3.
33
Compactness of the Embedding on Half-Cubes and Half-Balls
We require a counterpart to Lemma 2.3.5.1 concerning the compactness of the
embedding W 1,2β (Ω;Rn) → L2
β(Ω;Rn) when Ω is a half-cube or half-ball.
Lemma 2.3.5.2. Let r > 0, y ∈ ∂Rm+1+ and suppose (vj)j∈N is a sequence in
W 1,2β (Ω;Rn) with supj ||vj||W 1,2
β (Ω;Rn) < ∞ where Ω is either Q+r (y) or B+
r (y).
Then there exists a subsequence (vjk)k∈N and a v ∈ W 1,2β (Ω;Rn) such that
1. vjk v in W 1,2β (Ω;Rn)
2. vjk → v in L2β(Ω;Rn)
3.∫
Ωxβm+1|∇v|2dx ≤ lim infk→∞
∫Ωxβm+1|∇vjk |2dx.
Proof. For β = 0 the proof is the same as for Lemma 2.3.5.1, a statement and
proof of which can be found in [46] section 1.3 Lemma 1. Henceforth we suppose
β ∈ (−1, 1)\0.Statement 1 follows from the weak sequential compactness of the unit ball
in a Hilbert space. Furthermore, statement 3 follows from statement 2 and the
lower semi-continuity of a Hilbert space norm. Hence, the main task is to prove
statement 2.
We may assume that Ω is a half-cube which we justify as follows. If the Lemma
is true on a Q+r (y) then statement 1 for sequences of maps with domain B+
r (y)
follows in the same way as for the domains Q+r (y). For any sequence (vk)k∈N with
vk ∈ W 1,2β (B+
r (y);Rn), we can apply the Lemma to the sequence (vk Φy)k∈N,
where Φy : Q+r (y) → B+
r (y) is the bi-Lipschitz map defined in section 2.3.1, to
deduce statement 2 for (vk)k∈N. Statement 3 then also follows as described for
the domains Q+r (y).
Now we show that statement 2 is invariant under rescaling and translations
with respect to xi for i = 1, . . . ,m. Suppose that the statement is true for
any sequence (vj)j∈N of vj ∈ W 1,2β (Q+
1 (0);Rn) satisfying the assumptions of
the Lemma. Then we can obtain the statement for any sequence (vj)j∈N of
vj ∈ W 1,2β (Q+
r (y);Rn) which satisfies the assumptions of the Lemma, by applying
statement 2 on Q+1 (0) to the sequence vj(x) = vj(rx+ y) defined for x ∈ Q+
1 (0).
A change of variables shows that
||vj||2L2β(Q+
1 (0);Rn)= r−(1+m+β)||vj||2L2
β(Q+r (y);Rn)
(2.3.37)
and
||∇vj||L2β(Q+
1 (0);Rn) = r1−m−β||∇vj||L2β(Q+
r (y);Rn). (2.3.38)
34
Hence the sequence (vj)j∈N satisfies the assumptions of the Lemma on Q+1 (0)
and there is a v ∈ W 1,2β (Q+
1 (0);Rn) such that a subsequence (vjk)k∈Rn converges
to v in L2β(Q+
1 (0);Rn). We define v(x) = v(x−yr
) for x ∈ Q+r (y). Both (2.3.37)
and (2.3.38) hold with vj replaced by v and vj replaced by v; we conclude that
v ∈ W 1,2β (Q+
r (y);Rn) and (vjk)k∈Rn converges to v in L2β(Q+
r (y);Rn). Hence we
only need show statement 2 holds on Q+1 (0).
Suppose (vj)j∈N is a sequence with vj ∈ W 1,2β (Q+
1 (0);Rn) for every j, which
satisfies
supj∈N||vj||W 1,2
β (Q+1 (0);Rn) ≤M (2.3.39)
for some positive constant M . Without relabelling the index, suppose (vj)j∈N
is also the subsequence which satisfies vj v for v ∈ W 1,2β (Q+
1 (0);Rn). Since
W 1,2β (Q+
1 (0);Rn) is a Hilbert space, the norm on this space is weakly lower semi-
continuous and hence we have
||v||W 1,2β (Q+
1 (0);Rn) ≤M. (2.3.40)
Let Q′ = (−1, 1)m so that Q+1 (0) = Q′ × (0, 1) and define
Qi =
(x′, xm+1) ∈ Q+
1 (0) :1
i+ 1< xm+1 ≤ 1
for i ∈ N. We will take advantage of the compactness of the embeddings
W 1,2β (Qi;Rn) → L2
β(Qi;Rn) provided by Lemma 2.3.5.1 in order to construct
a subsequence of (vj)j∈N which converges to v in L2β(Q+
1 (0);Rn).
Notice that in view of (2.3.39), for each i ∈ N we have
supj∈N||vj||W 1,2
β (Qi;Rn) ≤M. (2.3.41)
Hence, applying Lemma 2.3.5.1 on Q1, we find a v ∈ W 1,2β (Q1;Rn) and a sub-
sequence, which we denote (vj)j∈Λ1 for an infinite set Λ1 ⊂ N, which satisfies
vj v in W 1,2β (Q1;Rn), vj → v in L2
β(Q1;Rn) and almost everywhere as j →∞with j ∈ Λ1. Notice that (vj)j∈Λ1 converges weakly to v in W 1,2
β (Q1;Rn) because
(vj)j∈N does and so, by the uniqueness of weak limits, we deduce v = v in Q1.
Hence vj → v in L2β(Q1;Rn) and almost everywhere as j →∞ as well.
Similarly, we observe that the sequence (vj)j∈Λ1 is a bounded sequence in
W 1,2β (Q2;Rn) in view of (2.3.41) and so we apply Lemma 2.3.5.1 to this sequence.
We obtain a subsequence (vj)j∈Λ2 , where Λ2 ⊂ Λ1 is an infinite set, of (vj)j∈Λ1
which satisfies all the properties of this sequence and, in addition, converges to
35
v in L2β(Q2;Rn) and almost everywhere in Q2. Inductively, for every i ∈ N, we
obtain sequences (vj)j∈Λi with Λi+1 ⊂ Λi such that (vj)j∈Λi converges to v in
L2β(Qi;Rn) and almost everywhere in Qi.
Now we extract a diagonal-type subsequence from the collection of sequences
(vj)j∈Λi : i ∈ N with additional bounds on the L2β(Qi;Rn) distance from the
terms in the sequence to v for each i. Since (vj)j∈Λi converges to v in L2β(Qi;Rn)
and Λi+1 ⊂ Λi for each i ∈ N, we can choose an increasing sequence of numbers
(ki)i∈N with ki ∈ Λi such that
∫Qi
|vk − v|2dµβ <
∫ 1i1i+1
xβm+1dx
2i≤ 1
i2+β2i(2.3.42)
for k ≥ ki. Then the sequence (vki)i∈N converges to v almost everywhere in
Q+1 (0) and in L2
β(Qk;Rn) for all k ∈ N as i → ∞. We claim that vki → v in
L2β(Q+
1 (0);Rn) as i→∞.
We write the L2β distance from vki to v as an integral over two regions in
Q+1 (0), depending on i; fix i ∈ N and consider∫
Q+1 (0)
|vki − v|2dµβ =
∫Q′×(0, 1
i+1)|vki − v|2dµβ +
∫Qi
|vki − v|2dµβ. (2.3.43)
By (2.3.42) we have∫Qi|vki − v|dµβ < 1
i2+β2i. We will show a similar bound, in
terms of i, for the quantity∫Q′×(0, 1
i+1) |vki − v|dµβ.
It follows from the discussion in section 2.3.4, applied to the functions xm+1 7→∫Q′|vki(x′, xm+1)−v(x′, xm+1)|2dx′ and combined with Fubini’s Theorem, that we
may choose ci ∈(
11+i, 1i
)such that
∫Q′|vki(x′, ci)− v(x′, ci)|2dx′ ≤ 1(∫ 1
i1i+1
xβm+1dxm+1
) ∫ 1i
1i+1
∫Q′|vki − v|2dµβ.
(2.3.44)
Now for each i ∈ N, we calculate∫ 1i+1
0
∫Q′|vki − v|2dµβ ≤ 4
∫ 1i+1
0
∫Q′|vki − vki(x′, ci)|2dµβ
+ 4
∫ 1i+1
0
∫Q′|v − v(x′, ci)|2dµβ
+ 4
∫ 1i+1
0
∫Q′|vki(x′, ci)− v(x′, ci)|2dµβ. (2.3.45)
36
To complete the proof we bound each of the terms on the right hand side of
(2.3.45) in terms of i. We proceed with the term
∫ 1i+1
0
∫Q′|v − v(x′, ci)|2dµβ,
noting that the bound for the same integral with v replaced by vki is identical.
We write this integral in terms of the derivative of v with respect to the m+ 1th
variable and apply Holder’s inequality to see that∫ 1i+1
0
∫Q′|v(x′, xm+1)− v(x′, ci)|2dµβ
≤∫ 1
i+1
0
∫Q′
(∫ ci
xm+1
∂v
∂xm+1
(x′, s)ds
)2
dµβ
=
∫ 1i+1
0
xβm+1
∫Q′
(∫ ci
xm+1
s−β2 s
β2
∂v
∂xm+1
(x′, s)ds
)2
dx′dxm+1
≤ c1−βi
1− β
∫ 1i+1
0
xβm+1
∫Q′
∫ ci
0
sβ∣∣∣∣ ∂v
∂xm+1
∣∣∣∣2 (x′, s)dsdx′dxm+1
≤ c1−βi
1− β2c1+βi
∫ ci
0
∫Q′
∣∣∣∣ ∂v
∂xm+1
∣∣∣∣2 dµβ
≤ 1
1− β2
1
i2M2. (2.3.46)
We apply (2.3.44) followed by (2.3.42) to see that
∫ 1i+1
0
∫Q′|vki(x′, ci)− v(x′, ci)|2dµβ ≤
∫ 1i+1
0 xβm+1dxm+1∫ 1i1i+1
xβm+1dx
∫ 1i
1i+1
∫Q′|vki − v|2dµβ
≤∫ 1i+1
0 xβm+1dxm+1
2i
<1
(1 + β)i1+β2i. (2.3.47)
Finally we combine (2.3.42), (2.3.43),(2.3.45), (2.3.46) and (2.3.47) to see that∫Q+
1 (0)
|vki − v|2dµβ ≤1
i2+β2i+
4
(1 + β)i1+β2i+
8
1− β2
1
i2M2 → 0 as i→∞
which concludes the proof.
37
2.4 Properties of Solutions of div(xβm+1∇v) = 0
The properties of harmonic functions with respect to the Euclidean metric, so-
lutions to Laplace’s equation, play an important role in the theory of some ge-
ometric semi-linear partial differential equations where the Laplace operator is
the highest order term. The variational problem for Eβ that we will consider
gives rise to a highest order term of the form div(xβm+1∇v). We therefore expect
solutions of (2.0.1), accompanied with Dirichlet or Neumann boundary data, to
be useful for our analysis.
At various points in this section, we will want to apply results for single partial
differential equations to a system of equations. In the situations we consider, this
is permitted because we are considering solutions of a system where the equations
for each component are the same. This means that the systems de-couple and
we could consider the theory for each of the components of the solution instead.
We do not remark on this any further.
Whenever we consider (2.0.1) on a domain Ω whose boundary intersects
∂Rm+1+ , we will prescribe zero Neumann type data on ∂Ω ∩ ∂Rm+1
+ . As we will
see shortly, this permits the even reflection of a solution in ∂Rm+1+ . Thus we may
either consider (2.0.1) with prescribed Neumann-type data or we could consider
solutions of
div(|xm+1|β∇v) =m+1∑i=1
∂
∂xi
(|xm+1|β
∂v
∂xi
)= 0 (2.4.1)
in open Ω ⊂ Rm+1. Generally we will be dealing with weak solutions of (2.4.1):
for Ω ⊂ Rm+1 open, we say that v ∈ W 1,2β (Ω;Rn) is a weak solution of (2.4.1) if
∫Ω
|xm+1|β 〈∇v,∇φ〉 dx =m+1∑i=1
∫Ω
|xm+1|β⟨∂v
∂xi,∂φ
∂xi
⟩dx = 0 (2.4.2)
for every φ ∈ C∞0 (Ω;Rn). We have expanded the expression for the measure
dµβ into its constituent parts to emphasise the fact that the weight |xm+1|β is
the coefficient of the partial differential equation. This notation will be common
throughout.
Remark 2.4.0.1. The functional φ 7→∫
Ω|xm+1|β 〈∇v,∇φ〉 dx is continuous on
C∞0 (Ω;Rn) which is dense in W 1,2β,0(Ω;Rn) and hence, by approximation,∫
Ω
|xm+1|β 〈∇v,∇φ〉 dx = 0 (2.4.3)
38
for every φ ∈ W 1,2β,0(Ω;Rn) if v is a weak solution of (2.4.1).
If Ω satisfies Ω ⊂ Rm+1\(Rm×0) then (2.4.1) is a uniformly elliptic second
order partial differential equation and hence any weak solution is smooth by the
regularity theory in Chapter 8 of [21]. Furthermore every weak solution of (2.4.1)
is smooth on any open Ω with Ω ⊂ Rm+1+ or Ω ⊂ Rm+1
− = Rm × (−∞, 0), since
such an Ω can be written as a union of bounded domains with closure contained
in Rm+1+ or Rm+1
− . This reduces regularity questions about solutions of (2.4.1)
to domains overlapping Rm × 0. Next we introduce some function spaces and
notation to facilitate further discussion of the solutions to (2.4.1) in such domains.
2.4.1 Spaces of Smooth and Continuous Functions
We have already encountered the space C∞(Ω;Rn) of smooth, Rn-valued func-
tions on open Ω ⊂ Rm+1, and the subset C∞0 (Ω;Rn) of C∞(Ω;Rn), comprised
of smooth functions with compact support in Ω. In order to discuss solutions
and their derivatives, we will also require spaces of continuous and differentiable
functions.
Let Ω ⊂ Rm+1 be open, k ∈ N, γ ∈ (0, 1] and α = (α1, . . . , αm+1) ∈ Nm+1∪0denote a multi-index. We denote the αth partial derivative, weak or classical, of
a map v : Ω→ Rn, by
Dαv =∂|α|v
∂α1x1 . . . ∂αm+1xm+1
where |α| = α1 + . . .+ αm+1.
The following function spaces are introduced in section 4.1 of [21] and, as
stated there, the spaces we can equip with a norm are all Banach spaces. The
space of continuous functions v : Ω → Rn is denoted C(Ω;Rn). The space of
bounded, uniformly continuous functions on Ω is C(Ω;Rn) which, if Ω is bounded,
may be given the norm ||v||C(Ω;Rn) = supΩ |v|. We write Ck(Ω;Rn) for the space of
k times continuously differentiable v : Ω→ Rn. The space of k times differentiable
functions whose first k derivatives all have continuous extensions to Ω is denoted
Ck(Ω;Rn). If Ω is bounded, this space may be given the norm ||v||Ck(Ω;Rn) =∑kj=0 sup|α|=j ||Dαv||C(Ω;Rn). Let C0,γ(Ω;Rn) denote the space of locally Holder
continuous, if γ ∈ (0, 1), or locally Lipschitz continuous, if γ = 1, functions
v : Ω → Rn. The space of Holder or Lipschitz continuous functions on Ω is
denoted C0,γ(Ω;R) for γ ∈ (0, 1) and γ = 1 respectively. When Ω is bounded,
39
this space may be given the norm ||v||C0,γ(Ω;Rn) = ||v||C(Ω;Rn) + [v]C0,γ(Ω;Rn), where
[v]C0,γ(Ω;Rn) = supx,y∈Ωx 6=y
|v(x)− v(y)||x− y|γ
(2.4.4)
is a semi-norm on C0,γ(Ω;Rn).
2.4.2 Solutions of div(xβm+1∇v) = 0 with Neumann-type
Boundary Data
When we consider a solution v of (2.0.1) on an open Ω ⊂ Rm+1+ with ∂Ω∩∂Rm+1
+ 6=∅, we will usually stipulate that it satisfies a Neumann-type boundary condition
on this part of the boundary. This defines a Neumann-type problem where,
explicitly, we require
div(xβm+1∇v) = 0 in Ω
limxm+1→0+
xβm+1
∂v
∂xm+1
= 0 in ∂0Ω(2.4.5)
where ∂0Ω is defined as the interior, with respect to ∂Rm+1+ , of ∂Ω∩ ∂Rm+1
+ . The
weak formulation of this problem is as follows; we say that v ∈ W 1,2β (Ω;Rn) is a
weak solution of the Neumann problem (2.4.5) in Ω if
∫Ω
xβm+1 〈∇v,∇φ〉 dx =m+1∑i=1
∫Ω
xβm+1
⟨∂v
∂xi,∂φ
∂xi
⟩dx = 0 (2.4.6)
for every φ ∈ D+(Ω;Rn) = φ = ψ|Ω : ψ ∈ C∞0 (Ω;Rn) where Ω = x =
(x′, xm+1) ∈ Rm+1 : (x′, |xm+1|) ∈ Ω ∪ ∂0Ω is the union of Ω, its reflection in
∂Rm+1+ and ∂0Ω.
Remark 2.4.2.1. The functional φ 7→∫
Ω|xm+1|β 〈∇v,∇φ〉 dx is continuous on
D+(Ω;Rn) which is dense in its completion, denoted H1,+β (Ω;Rn), with respect
to the W 1,2β (Ω;Rn) norm. This completion is a closed subspace of W 1,2
β (Ω;Rn),
since the dense subspace in H1,+β (Ω;Rn) is contained in the dense subspace in
W 1,2β (Ω;Rn), and thus a reflexive Banach space in its own right. Hence, by
approximation, ∫Ω
|xm+1|β 〈∇v,∇φ〉 dx = 0 (2.4.7)
for every φ ∈ H1,+β (Ω;Rn).
We will now show that a weak solution of (2.4.5) in a domain Ω ⊂ Rm+1+ ,
40
where ∂0Ω 6= ∅, can be evenly reflected in Rm × 0 to give a weak solution
of (2.4.1) in Ω. The next Lemma shows that the even reflection of a Sobolev
function, defined on Ω, in Rm × 0 gives a Sobolev function in the reflected
domain Ω and, furthermore, a symmetric function on this domain restricts to a
Sobolev function on Ω.
Lemma 2.4.2.1. Suppose Ω ⊂ Rm+1+ with ∂0Ω 6= ∅. If v ∈ W 1,2
β (Ω;Rn) or v ∈H1,+β (Ω;Rn) then the even reflection v(x′, xm+1) = v(x′, |xm+1|), for (x′, xm+1) ∈
Ω, is in W 1,2β (Ω;Rn) or W 1,2
β,0(Ω;Rn) respectively. Conversely, if v ∈ W 1,2β (Ω;Rn)
or v ∈ W 1,2β,0(Ω;Rn) satisfies v(x′, xm+1) = v(x′,−xm+1) for every (x′, xm+1) ∈ Ω,
then v = v|Ω ∈ W 1,2β (Ω;Rn) or v ∈ H1,+
β (Ω;Rn) respectively. The relationship
between the weak derivatives of v and v is given by
∂v
∂xi(x′, xm+1) =
∂v
∂xi(x′, |xm+1|) (2.4.8)
for i = 1, . . . ,m and
∂v
∂xm+1
(x′, xm+1) = sgn(xm+1)∂v
∂xm+1
(x′, |xm+1|). (2.4.9)
Proof. We prove the Lemma by constructing appropriate approximating sequences
of smooth functions. Our calculations are essentially independent of the Sobolev
spaces under consideration so we assume that we are working with elements of
W 1,2β (Ω;Rn) and W 1,2
β (Ω;Rn). The calculations for elements of H1,+β (Ω;Rn) and
W 1,2β,0(Ω;Rn) are almost identical.
Suppose that v ∈ W 1,2β (Ω;Rn) and let (φk)k∈N, with each φk contained in
the dense subspace of smooth functions in W 1,2β (Ω;Rn), be an approximating
sequence such that ||v− φk||W 1,2β (Ω;Rn) → 0 as k →∞. Since ||v− φk||W 1,2
β (Ω;Rn) ≤||v − φk||W 1,2
β (Ω;Rn) we deduce that (φk)|Ω → v as k → ∞ in W 1,2β (Ω;Rn) and
hence v ∈ W 1,2β (Ω;Rn).
Now we assume v ∈ W 1,2β (Ω;Rn) and consider the even reflection v(x′, xm+1) =
v(x′, |xm+1|) defined for (x′, xm+1) ∈ Ω. To construct an approximating sequence
of smooth functions for v, we first consider the reflection of a smooth approx-
imating sequence for v. Choose (φk)k∈N, with φk contained in the dense sub-
space of smooth elements in W 1,2β (Ω;Rn), such that ||v − φk||W 1,2
β (Ω;Rn) → 0 as
k → ∞. Define φk(x′, xm+1) = φk(x
′, |xm+1|) for (x′, xm+1) ∈ Ω. We show that
φk(x′, xm+1) ∈ W 1,2
β (Ω;Rn).
We calculate∂φk∂xi
(x′, xm+1) =∂φk∂xi
(x′, |xm+1|) (2.4.10)
41
and∂φk∂xm+1
(x′, xm+1) = sgn(xm+1)∂φk∂xm+1
(x′, |xm+1|) (2.4.11)
for xm+1 6= 0 using the chain rule. Next we verify that this relationship defines
the weak derivatives of φk in Ω.
First suppose i = 1, . . . ,m, let Ω− = Ω\Ω and let ψ ∈ C∞0 (Ω;Rn). We have,
using the change of variables xm+1 7→ −xm+1,∫Ω
∂φk∂xi
ψdx =
∫Ω
∂φk∂xi
ψdx+
∫Ω−
∂φk∂xi
ψdx
=
∫Ω
∂φk∂xi
ψdx+
∫Ω
∂φk∂xi
ψ(x′,−xm+1)dx. (2.4.12)
Since φk is smooth on Ω and ψ is smooth on Ω and vanishes on a compact subset
of Ω we may integrate by parts with respect to xi. This gives∫Ω
∂φk∂xi
ψdx = −∫
Ω
φk∂ψ
∂xidx
= −∫
Ω
φk∂ψ
∂xidx (2.4.13)
and, combining the integration by parts with the change of variable xm+1 7→−xm+1 again, ∫
Ω
∂φk∂xi
ψ(x′,−xm+1)dx = −∫
Ω
φk∂ψ
∂xi(x′,−xm+1)dx
= −∫
Ω−
φk∂ψ
∂xidx. (2.4.14)
Combining (2.4.12), (2.4.13) and (2.4.14) shows that the weak partial derivatives∂φk∂xi
are defined by (2.4.10). Now suppose i = m+1. Observe that φk is continuous
in Ω and smooth in Ω\∂0Ω. We calculate∫Ω
∂φk∂xm+1
ψdx =
∫Ω
∂φk∂xm+1
ψdx−∫
Ω−
∂φk∂xm+1
(x′,−xm+1)ψdx. (2.4.15)
An integration by parts yields∫Ω
∂φk∂xm+1
ψdx = −∫∂0Ω
φkψdx′ −∫
Ω
φk∂ψ
∂xm+1
dx. (2.4.16)
Moreover, a change of variables, via the map xm+1 7→ −xm+1, and an integration
42
by parts gives
−∫
Ω−
∂φk∂xm+1
(x′,−xm+1)ψdx = −∫
Ω
∂φk∂xm+1
ψ(x′,−xm+1)dx
=
∫∂0Ω
φkψdx′ −∫
Ω
φk∂ψ
∂xm+1
(x′,−xm+1)dx
=
∫∂0Ω
φkψdx′ −∫
Ω−
φk∂ψ
∂xm+1
dx. (2.4.17)
Combining (2.4.15), (2.4.16) and (2.4.17) we see that the weak derivative ∂φk∂xm+1
is defined by (2.4.11). Furthermore, we have∫Ω
|xm+1|β|∇φk|2dx = 2
∫Ω
xβm+1|∇φk|2dx <∞ (2.4.18)
and ∫Ω
|xm+1|β|φk|2dx = 2
∫Ω
xβm+1|φk|2dx <∞ (2.4.19)
and so φk ∈ W 1,2β (Ω;Rn) for every k.
Now we construct an approximating sequence of smooth functions inW 1,2β (Ω;Rn)
for v. We deduce, using the inequalities (2.4.18) and (2.4.19), that
||v − φk||W 1,2β (Ω;Rn) = 2
12 ||v − φk||W 1,2
β (Ω;Rn) → 0 as k →∞.
Furthermore, since each φk ∈ W 1,2β (Ω;Rn), each φk has an approximating se-
quence of smooth functions and we may choose an increasing sequence of numbers
(jk)k∈N and smooth functions φjk in the dense set in W 1,2β (Ω;Rn) such that
||φk − φjk ||W 1,2β (Ω;Rn) ≤
1
k.
It follows that
||v − φjk ||W 1,2β (Ω;Rn) ≤ ||v − φk||W 1,2
β (Ω;Rn) + ||φjk − φk||W 1,2β (Ω;Rn) → 0 as k →∞
and hence (φjk)k∈N is the required approximating sequence for v.
The equalities (2.4.8) and (2.4.9) hold since they hold for φk and φk → v
in W 1,2β (Ω;Rn) and so, extracting subsequences if necessary, we conclude that
φk → v and ∂φk∂xi→ ∂v
∂xi, for i = 1, . . . ,m+ 1, almost everywhere.
Lemma 2.4.2.2. Let Ω ⊂ Rm+1+ with ∂Ω ∩ ∂Rm+1
+ 6= ∅ and let Ω = x =
(x′, xm+1) ∈ Rm+1 : (x′, |xm+1|) ∈ Ω ∪ ∂0Ω. The even reflection, with respect to
43
Rm×0, of a weak solution of (2.4.5) in Ω ⊂ Rm+1+ is a weak solution of (2.4.1)
in Ω. Conversely, a weak solution of (2.4.1), which is symmetric with respect to
Rm × 0, in Ω is a weak solution of (2.4.5) in Ω.
Proof. Suppose that two measurable functions v : Ω → Rn and v : Ω → Rn are
related via
v(x′, xm+1) =
v(x′, xm+1) (x′, xm+1) ∈ Ω
v(x′,−xm+1) (x′, xm+1) ∈ Ω− = Ω\Ω
It follows from Lemma 2.4.2.1 that v ∈ W 1,2β (Ω;Rn) if, and only if, v ∈ W 1,2
β (Ω;Rn).
Henceforth, we assume v and v are related as above. We have∫Ω
|xm+1|β 〈∇v,∇φ〉 dx =
∫Ω
xβm+1 〈∇v,∇φ〉 dx
+
∫Ω−
(−xm+1)β 〈∇v,∇φ〉 dx. (2.4.20)
Furthermore, we write the integral over Ω− as∫Ω−
(−xm+1)β 〈∇v,∇φ〉 dx =
∫Ω−
(−xm+1)β 〈∇′v,∇′φ〉 dx
+
∫Ω−
(−xm+1)β⟨
∂v
∂xm+1
,∂φ
∂xm+1
⟩dx (2.4.21)
where∇′ is the gradient with respect to x1, . . . , xm and, for any functions f, h such
that ∇′f,∇′h exist, 〈∇′f,∇′h〉 =∑m
i=1
⟨∂f∂xi, ∂h∂xi
⟩. Combining the expressions
for the weak derivatives for v and v given by Lemma 2.4.2.1 with the change of
variables xm+1 7→ −xm+1 we calculate∫Ω−
(−xm+1)β 〈∇′v,∇′φ〉 dx =
∫Ω
xβm+1 〈∇′v,∇′φ(x′,−xm+1)〉 dx (2.4.22)
and ∫Ω−
(−xm+1)β⟨
∂v
∂xm+1
,∂φ
∂xm+1
⟩dx
= −∫
Ω−
(−xm+1)β⟨
∂v
∂xm+1
(x′,−xm+1),∂φ
∂xm+1
⟩dx
= −∫
Ω
xβm+1
⟨∂v
∂xm+1
,∂φ
∂xm+1
(x′,−xm+1)
⟩dx. (2.4.23)
44
Together, (2.4.20), (2.4.21), (2.4.22) and (2.4.23) give∫Ω
|xm+1|β 〈∇v,∇φ〉 dx =
∫Ω
xβm+1 〈∇v,∇φ〉 dx
+
∫Ω
xβm+1 〈∇′v,∇′φ(x′,−xm+1)〉 dx
−∫
Ω
xβm+1
⟨∂v
∂xm+1
,∂φ
∂xm+1
(x′,−xm+1)
⟩dx. (2.4.24)
Now we show that if v is a weak solution of (2.4.1), that is div(|xm+1|β∇v) = 0
in Ω in the weak sense, then v is a weak solution of (2.4.5), or in other words
div(xβm+1∇v) = 0 in Ω and xβm+1∂v
∂xm+1= 0 in ∂0Ω in the weak sense, and vice
versa.
Suppose v is a weak solution of (2.4.5). Then v satisfies∫Ω
xβm+1 〈∇v,∇φ〉 dx = 0
for every φ ∈ D+(Ω;Rn). We want to show that v satisfies (2.4.2) for every
φ ∈ C∞0 (Ω;Rn). Choose such a φ and define ψ(x′, xm+1) = φ(x′,−xm+1). It
follows that φ|Ω and ψ|Ω are in D+(Ω;Rn). Furthermore, their derivatives are
related by∂φ
∂xi(x′, xm+1) =
∂ψ
∂xi(x′,−xm+1) (2.4.25)
for i = 1, . . . ,m and
∂φ
∂xm+1
(x′, xm+1) = − ∂ψ
∂xm+1
(x′,−xm+1). (2.4.26)
Hence, using (2.4.24), (2.4.25) and (2.4.26), we have∫Ω
|xm+1|β 〈∇v,∇φ〉 dx =
∫Ω
xβm+1 〈∇v,∇φ〉 dx
+
∫Ω
xβm+1 〈∇′v,∇′φ(x′,−xm+1)〉 dx
−∫
Ω
xβm+1
⟨∂v
∂xm+1
,∂φ
∂xm+1
(x′,−xm+1)
⟩dx
=
∫Ω
xβm+1 〈∇v,∇φ〉 dx
+
∫Ω
xβm+1 〈∇v,∇ψ〉 dx
= 0 (2.4.27)
45
since v is a weak solution of (2.4.5) and φ|Ω and ψ|Ω are in D+(Ω;Rn). This
shows that v is a weak solution of (2.4.1) since φ ∈ C∞0 (Ω;Rn) was arbitrary.
Conversely, suppose that v is a weak solution of (2.4.1). Then for every
φ ∈ C∞0 (Ω;Rn) we have ∫Ω
|xm+1|β 〈∇v,∇φ〉 dx = 0.
By approximation, as in remark 2.4.0.1, this holds for every φ ∈ W 1,2β,0(Ω;Rn).
Suppose that φ ∈ D+(Ω;Rn). It follows from Lemma 2.4.2.1 that the even
reflection φ of φ in Rm × 0 is in W 1,2β,0(Ω;Rn). Moreover, using the relationship
between the derivatives of φ and φ given by (2.4.8) and (2.4.9) from Lemma
2.4.2.1, combined with (2.4.24), we see that
0 =
∫Ω
xβm+1
⟨∇v,∇φ
⟩dx
=
∫Ω
xβm+1 〈∇v,∇φ〉 dx
+
∫Ω
xβm+1
⟨∇′v,∇′φ(x′,−xm+1)
⟩dx
−∫
Ω
xβm+1
⟨∂v
∂xm+1
,∂φ
∂xm+1
(x′,−xm+1)
⟩dx
= 2
∫Ω
xβm+1 〈∇v,∇φ〉 dx. (2.4.28)
Since this holds for every φ ∈ D+(Ω;Rn) we conclude that v is a weak solution
of (2.4.5). This concludes the proof.
2.4.3 Continuity Properties of Solutions of div(|xm+1|β∇v) =
0 on Sets Overlapping ∂Rm+1+
On any Ω ⊂ Rm+1 with Ω ∩ ∂Rm+1+ 6= ∅, as mentioned previously, it follows
from the regularity theory for second order linear elliptic equations in Chapter
8 of [21] that a solution of (2.4.1) is smooth in Ω\∂Rm+1+ . When the ellipticity
degenerates, arguments from the theory of degenerate elliptic equations must
instead be used to conclude continuity and higher regularity of solutions.
In order to conclude the Holder continuity of solutions to the variational
problems considered later we will need to use a consequence of the continuity
of solutions to (2.4.1); a result of Fabes et al [19] shows that a weak solution of
(2.4.1) in an Ω ⊂ Rm+1 with ∂0Ω 6= ∅ is locally Holder continuous in Ω. We state
46
their result in the context considered here and do not quote the whole result,
merely the part that we need.
Lemma 2.4.3.1 ([19] Part of Theorem 2.3.12). Suppose v is a weak solution of
div(|xm+1|β∇v) = 0 in Ω ⊂ Rm+1. Then v is locally Holder continuous in Ω.
Corollary 2.4.3.1. Let v be a weak solution of div(|xm+1|β∇v) = 0 in BR(x0) ⊂Rm+1. There exists a positive constant C and a γ = γ(m,β) ∈ (0, 1) such that
|v(x)− v(y)| ≤ C|x− y|γ
for x, y ∈ BR2(x0).
Since the equation div(|xm+1|β∇v) = 0 is linear we deduce the following
reverse Poincare inequality, analogously to the case of linear uniformly elliptic
equations.
Lemma 2.4.3.2. Let v be a weak solution of (2.4.1) in a ball BR(x0) ⊂ Rm+1
and let r ≤ R. Then∫B r
2(x0)
|∇v|2dµβ ≤C
r2
∫Br(x0)
|v − λ|2dµβ (2.4.29)
for any λ ∈ Rn and a positive constant C.
Proof. Let η ∈ C∞0 (Br(x0);Rn) be a cutoff function with η ≡ 1 in B r2(x0) and
0 ≤ η ≤ 1. Furthermore, suppose that |∇η| ≤ Cr
for a fixed positive C > 2.
Although we are discussing PDEs here, since the weight |xm+1|β does not play
a significant role we use the notation dµβ in place of |xm+1|βdx. We want to
test (2.4.2) against φ = η2(v − λ). This is an admissible test function by remark
2.4.0.1 since η is smooth with compact support in Br(x0) and v−λ ∈ W 1,2β (Ω;Rn).
Hence, we find ∫Br(x0)
⟨∇v,∇(η2(v − λ))
⟩dµβ = 0.
We expand this expression to see that∫Br(x0)
η2|∇v|2dµβ = −2
∫Br(x0)
η 〈∇v,∇η · (v − λ)〉 dµβ. (2.4.30)
47
Using Young’s inequality, ab ≤ δ a2
2+ b2
2δfor a, b ≥ 0 and δ > 0, we see that
2
∫Br(x0)
η 〈∇v,∇η · (v − λ)〉 dµβ ≤ δ
∫Br(x0)
η2|∇v|2dµβ
+C
δ
∫Br(x0)
|∇η|2|v − λ|2dµβ. (2.4.31)
Choosing δ = 12
and combining (2.4.30) and (2.4.31) we see that∫Br(x0)
η2|∇v|2dµβ ≤ C
∫Br(x0)
|∇η|2|v − λ|2dµβ
and since |∇η| ≤ Cr
this yields (2.4.29) as required.
Combining Corollary 2.4.3.1 and Lemma 2.4.3.2 we deduce the following result
which we will require in our regularity theory later on.
Corollary 2.4.3.2. Let v be a weak solution of (2.4.5) in a half-ball B+R(x0) with
x0 ∈ Rm × 0. There exists a γ = γ(m,β) ∈ (0, 1) and a positive constant C
such that (r2
)1−m−β∫B+r2
(x0)
xβm+1|∇v|2dx ≤ Cr2γ (2.4.32)
for every r ≤ R2
.
Proof. The even reflection v of v in ∂Rm+1+ is a weak solution of div(|xm+1|β∇v) =
0 in BR(x0) by Lemma 2.4.2.2. Therefore we may apply Lemma 2.4.3.2 to v. We
do so, choosing λ = v(x0) in the lemma, to see that∫B r
2(x0)
|xm+1|β|∇v|2dx ≤ C
r2
∫Br(x0)
|xm+1|β|v − v(x0)|2dx (2.4.33)
for every r ≤ R2
. Moreover, corollary 2.4.3.1 gives a γ ∈ (0, 1) such that
|v − v(x0)| ≤ Crγ (2.4.34)
for a constant C and, since 2∫B+r2
(x0)xβm+1|∇v|2dx =
∫B r
2(x0)|xm+1|β|∇v|2dx, we
deduce the claim of the corollary by combining (2.4.33) and (2.4.34).
48
Chapter 3
Holder Continuity of Energy
Minimisers
First we set the scene. Let Rm+1+ = Rm × (0,∞) and consider the Riemannian
metric g on Rm+1+ defined in Euclidean coordinates by
g(x)(·, ·) = xαm+1
m+1∑i,j=1
δijdxidxj, (3.0.1)
where α ∈ R is fixed and δij = 1 if i = j and δij = 0 if i 6= j. The matrix
representing g has elements gij(x) = xαm+1δij and the elements of the inverse are
given by
gij(x) = x−αm+1δij.
We also calculate
det(g(x)) = x(m+1)αm+1 .
If we try to extend g by continuity to take values on Rm × 0 then the metric
would become degenerate or singular depending on the sign of α. If α > 0 then
the extension would be identically 0 along Rm × 0 and if α < 0 then the
extension would be infinite.
We define the Dirichlet energy, or simply energy, of a map v ∈ W 1,2β (Rm+1
+ ;Rn)
by
Eβ(v) =1
2
∫Rm+1
+
|∇v|2g√
det(g)dx
=1
2
∫Rm+1
+
xβm+1|∇v|2dx (3.0.2)
49
where β = α(m+12− 1) = α(m−1)
2and
|∇v|2g =m+1∑i,j=1
gij⟨∂v
∂xi,∂v
∂xi
⟩= x−αm+1
m+1∑i=1
⟨∂v
∂xi,∂v
∂xi
⟩.
Recall the assumptions on m,β as discussed in Remark 2.2.1.1. We will study
maps with image in a smooth, compact Riemannian manifold N . The Nash
embedding theorem [36] guarantees that we may isometrically embed N in Rn
for some n ∈ N and we assume this is the case henceforth. For technical reasons
we also assume, translating N if necessary, that 0 ∈ N .
Define
W 1,2β (Rm+1
+ ;N) = v ∈ W 1,2β (Rm+1
+ ;Rn) : v(x) ∈ N for almost every x ∈ Rm+1+ .(3.0.3)
This space of functions is non-empty since 0 ∈ N . The regularity properties
of a particular class of critical points v ∈ W 1,2β (Rm+1
+ ;N) of Eβ with respect to
smooth variations, both of the dependent variable v ∈ N and of the independent
variable x ∈ Rm+1+ , are our primary concern. Before discussing our main ques-
tions regarding these critical points, we will first derive two systems of partial
differential equations which they necessarily solve.
3.1 Critical Points of Eβ
We formulate all the results in this section in anticipation of a connection to a
family of variational problems, corresponding to those we will consider for the
Eβ, for the boundary values of functions in W 1,2β (Rm+1
+ ;N) on open O ⊂ ∂Rm+1+ .
The classes of admissible variations of Eβ will be chosen accordingly. Henceforth
O denotes an open subset of ∂Rm+1+ .
3.1.1 The Euler-Lagrange Equations
Here we consider critical points v ∈ W 1,2β (Rm+1
+ ;N) of Eβ with respect to smooth
variations of the dependent variable which leave the boundary values of v un-
changed outside O. To construct such a variation we will compactly perturb the
map v by adding a small multiple of a smooth function ψ ∈ D+(Rm+1+ ;Rn) with
ψ(·, 0) ∈ C∞0 (O;Rn) to v. In general, for any s > 0 the sum v + sψ will not
have values in N . In order to define a variation which does have values in N we
make use of the nearest point projection onto N , defined as follows. Since N is
50
compact, theorem 1 in section 2.12.3 of [46] gives a tubular neighbourhood of N ,
which has the form Uδ(N) = x ∈ Rn : dist(x,N) < δ for a δ = δ(N) > 0, and
a smooth map πN : Uδ(N) → N such that |πN(y) − y| = dist(y,N) for every
y ∈ Uδ(N). For sufficiently small s we define a variation of v by
vs = πN(v + sψ) ∈ N.
We say v is a critical point of Eβ with respect to smooth variations of the depen-
dent variable relative to O if
d
ds
∣∣∣∣s=0
Eβ(vs) = 0
for every variation of the form vs. In order to calculate dds
∣∣s=0
Eβ(vs) explicitly
we follow [33] section 3.2. Observe that
|∇vs|2 =m+1∑i=1
⟨DπN(v + sψ)
(∂v
∂xi+ s
∂ψ
∂xi
), DπN(v + sψ)
(∂v
∂xi+ s
∂ψ
∂xi
)⟩(3.1.1)
where DπN is the derivative of the nearest point projection. Differentiating both
sides of (3.1.1) with respect to s yields
d
ds
(xβm+1|∇vs|2
)=2xβm+1
m+1∑i=1
⟨DπN(v + sψ)
(∂v
∂xi+ s
∂ψ
∂xi
),HessπN(v + sψ)
(∂v
∂xi+ s
∂ψ
∂xi, ψ
)⟩
+ 2xβm+1
m+1∑i=1
⟨DπN(v + sψ)
(∂v
∂xi+ s
∂ψ
∂xi
), DπN(v + sψ)
(∂ψ
∂xi
)⟩.
(3.1.2)
Lemma 3.1 of [33] shows that DπN(y) is the orthogonal projection onto TyN and
hence, using the fact that ∂v∂xi
is tangential to N , we evaluate (3.1.2) at s = 0 to
51
see that
d
ds
∣∣∣∣s=0
(xβm+1|∇vs|2
)=2xβm+1
m+1∑i=1
⟨DπN(v)
(∂v
∂xi
),HessπN(v)
(∂v
∂xi, ψ
)⟩
+ 2xβm+1
m+1∑i=1
⟨DπN(v)
(∂v
∂xi
), DπN(v)
(∂ψ
∂xi
)⟩
= 2xβm+1
m+1∑i=1
⟨∂v
∂xi,HessπN(v)
(∂v
∂xi, ψ
)+∂ψ
∂xi
⟩. (3.1.3)
We split the vector ψ into its normal part ψ⊥ and tangential part ψ> with respect
to TvN , so that ψ = ψ⊥ + ψ>. It follows from lemma 3.2 in [33] that
m+1∑i=1
⟨∂v
∂xi,HessπN(v)
(∂v
∂xi, ψ
)⟩=
m+1∑i=1
⟨∂v
∂xi,HessπN(v)
(∂v
∂xi, ψ> + ψ⊥
)⟩
= −m+1∑i=1
⟨ψ⊥, A(v)
(∂v
∂xi,∂v
∂xi
)⟩
where A, a section of T ∗N ⊗ T ∗N ⊗ (TN)⊥, is the second fundamental form of
N . Since A(v(x)) is a normal vector for almost every x we find
m+1∑i=1
⟨∂v
∂xi,HessπN(v)
(∂v
∂xi, ψ
)⟩= −
m+1∑i=1
⟨ψ,A(v)
(∂v
∂xi,∂v
∂xi
)⟩. (3.1.4)
We combine (3.1.3) and (3.1.4) to see that
d
ds
∣∣∣∣s=0
Eβ(vs) =m+1∑i=1
∫Rm+1
+
xβm+1
(⟨∂v
∂xi,∂ψ
∂xi
⟩−⟨ψ,A(v)
(∂v
∂xi,∂v
∂xi
)⟩)dx.
(3.1.5)
If v ∈ W 1,2β (Rm+1
+ ;N) is a critical point of Eβ with respect to smooth variations
of the dependent variable relative to O then, in view of (3.1.5), v satisfies
m+1∑i=1
∫Rm+1
+
xβm+1
(⟨∂v
∂xi,∂ψ
∂xi
⟩−⟨ψ,A(v)
(∂v
∂xi,∂v
∂xi
)⟩)dx = 0 (3.1.6)
for every ψ ∈ D+(Rm+1+ ;Rn) with ψ(·, 0) ∈ C∞0 (O;Rn). We abbreviate (3.1.6) to∫
Rm+1+
xβm+1 (〈∇v,∇ψ〉 − 〈ψ,A(v) (∇v,∇v)〉) dx = 0 (3.1.7)
52
where
〈∇v,∇ψ〉 =m+1∑i=1
⟨∂v
∂xi,∂ψ
∂xi
⟩and A(v) (∇v,∇v) =
m+1∑i=1
A(v)
(∂v
∂xi,∂v
∂xi
).
It is important to note that the Euler Lagrange equations (3.1.6) contain
Neumann type boundary condition for v on O. We interpret this as follows:
assuming v is as smooth as necessary, we integrate by parts in (3.1.6) to obtain
m+1∑i=1
∫Rm+1
+
⟨∂
∂xi
(xβm+1
∂v
∂xi
)+ xβm+1A(v)
(∂v
∂xi,∂v
∂xi
), ψ
⟩dx
= −∫O
⟨(xβm+1
∂v
∂xm+1
)∣∣∣∣xm+1=0
, ψ(x′, 0)
⟩dx′ (3.1.8)
which holds for every ψ ∈ D+(Rm+1+ ;Rn) with ψ(·, 0) ∈ C∞0 (O;Rn). If ψ ∈
C∞0 (Rm+1+ ;Rn) we deduce
m+1∑i=1
(∂
∂xi
(xβm+1
∂v
∂xi
)+ xβm+1A(v)
(∂v
∂xi,∂v
∂xi
))= 0 in Rm+1
+ . (3.1.9)
We abbreviate (3.1.9) to
div(xβm+1∇v) + xβm+1A(v) (∇v,∇v) = 0 in Rm+1+ . (3.1.10)
Furthermore, if v is sufficiently smooth in Rm+1+ ∪O, the Neumann type boundary
condition in (3.1.8) becomes
limxm+1→0+
xβm+1
∂v
∂xm+1
= 0 in O. (3.1.11)
A map satisfying (3.1.9) is said to be harmonic. Furthermore, a harmonic map
satisfying (3.1.11) is said to be harmonic with respect to the Neumann type bound-
ary condition (3.1.11). A map satisfying (3.1.6) for every ψ ∈ C∞0 (Rm+1+ ;Rn) is
weakly harmonic and a map satisfying (3.1.6) for every ψ ∈ D+(Rm+1+ ;Rn) with
ψ(·, 0) ∈ C∞0 (O;Rn) is weakly harmonic with respect to the Neumann type bound-
ary condition (3.1.11).
3.1.2 The Stationary Equations
A weakly harmonic map may be discontinuous in general. In [38] Riviere estab-
lishes the existence of everywhere discontinuous weakly harmonic maps from the
53
unit ball Bn ⊂ Rn to the unit sphere Sp ⊂ Rp+1 for n ≥ 3 and p ≥ 2. However,
there are various regularity theories, which we will discuss shortly, for weakly
harmonic maps satisfying additional conditions. The least stringent of these is
that a weakly harmonic map must also be a critical point of the energy with
respect to smooth variations of the independent variable x ∈ Rm+1+ .
Weakly harmonic maps with respect to the Neumann-type boundary condition
(3.1.11) are weakly harmonic by definition and so may also be discontinuous in
Rm+1+ . Such maps may also have discontinuities on O, at least if β = 0 [23], as
discussed subsequently in Section 3.2. Thus we stipulate that such a map must
also be a critical point of Eβ with respect to smooth variations of the independent
variable which leave its boundary values unchanged outside O. Such critical
points are solutions of another system of PDEs in addition to (3.1.10) and we
derive these presently.
Recall that a φ ∈ D+(Rm+1+ ;Rm+1) is the restriction to Rm+1
+ of a smooth,
compactly supported function ψ defined on Rm+1. Without relabelling, we also
write φ to mean ψ|Rm+1+
.
Define
Φs(x) = x+ sφ(x)
for x ∈ Rm+1+ , where φ ∈ D+(Rm+1
+ ;Rm+1) is such that
φ(·, 0) ∈ C∞0 (O; ∂Rm+1+ )
and |s| is small enough to make Φs into a diffeomorphism of Rm+1+ with Φs(O) ⊂
O. Then, for v ∈ W 1,2β (Rm+1
+ ;N) we define a variation of v given by vs = v Φs
which is also a map in W 1,2β (Rm+1
+ ;N).
A v ∈ W 1,2β (Rm+1
+ ;N) is said to be a critical point of Eβ with respect to
smooth variations of the independent variable relative to O if dds
∣∣s=0
Eβ(vs) = 0
for any vs defined as above. We proceed to calculate dds
∣∣s=0
Eβ(vs). Observe that
Eβ(vs) =1
2
∫Rm+1
+
xβm+1
m+1∑i=1
⟨∂v
∂xi(Φs),
∂v
∂xi(Φs)
⟩dx
+ s
∫Rm+1
+
xβm+1
m+1∑i=1
⟨∂v
∂xi(Φs),
m+1∑k=1
∂v
∂xk(Φs)
∂φk∂xi
⟩dx
+1
2s2
∫Rm+1
+
xβm+1
m+1∑i=1
⟨m+1∑k=1
∂v
∂xk(Φs)
∂φk∂xi
,m+1∑j=1
∂v
∂xj(Φs)
∂φj∂xi
⟩dx.
(3.1.12)
54
To further our calculation we exploit the fact that Φs is a diffeomorphism, with
inverse Φ−1s , and transform
∫Rm+1
+
xβm+1
m+1∑i=1
⟨∂v(Φs)
∂xi,∂v(Φs)
∂xi
⟩dx
in (3.1.12). We see that
∫Rm+1
+
xβm+1
m+1∑i=1
⟨∂v(Φs)
∂xi,∂v(Φs)
∂xi
⟩dx
=
∫Rm+1
+
(Φ−1s )βm+1
m+1∑i=1
⟨∂v(x)
∂xi,∂v(x)
∂xi
⟩|detDΦ−1
s |dx
=
∫Rm+1
+
(Φ−1s )βm+1
m+1∑i=1
⟨∂v(x)
∂xi,∂v(x)
∂xi
⟩(1− sdivφ(x) +O(s2))dx (3.1.13)
where D means derivative, we have used the series expansion for detDΦ−1s and
the absolute value sign has been omitted since detDΦ−1s is posivite for sufficiently
small s. We will need to calculate ∂∂s
∣∣s=0
(Φ−1s ) and briefly digress to do this now.
The notation Φs(x) = Φ(s, x) makes the following calculation more transparent.
By definition Φ(s,Φ−1(s, x)) = x for all x ∈ Rm+1+ and for all s sufficiently small.
Furthermore, Φ0 = Φ−10 = IdRm+1
+, the identity map on Rm+1
+ . Let Dx represent
the derivative with respect to x. Then DxΦ(s, x) = Dx(x+sφ) = IdRm+1+
+sDxφ.
Thus we calculate
∂
∂s
∣∣∣∣s=0
Φ(s,Φ−1(s, x)) =∂Φ
∂s(0,Φ−1(0, x)) +DxΦ|(0,Φ−1(0,x))
(∂Φ−1
∂s(0, x)
)=∂Φ
∂s(0, x) +
∂Φ−1
∂s(0, x)
=0.
As a result we have
∂Φ−1
∂s(0, x) = −∂Φ
∂s(0, x) = −φ(x). (3.1.14)
Substituting (3.1.13) into (3.1.12), differentiating with respect to s and using
55
(3.1.14) we see that,
2d
ds
∣∣∣∣s=0
Eβ(vs) =−∫Rm+1
+
βxβ−1m+1φm+1
m+1∑i=1
⟨∂v
∂xi,∂v
∂xi
⟩dx
−∫Rm+1
+
xβm+1
m+1∑i=1
⟨∂v
∂xi,∂v
∂xi
⟩(divφ)dx
+ 2
∫Rm+1
+
xβm+1
m+1∑i=1
⟨∂v
∂xi,
m+1∑k=1
∂v
∂xk
∂φk∂xi
⟩dx. (3.1.15)
Thus a critical point of the Dirichlet energy corresponding to variations of the
independent variable relative to O satisfies
∫Rm+1
+
m+1∑i=1
m+1∑k=1
xβm+1
(2
⟨∂v
∂xi,∂v
∂xk
⟩− δik|∇v|2
)∂φk∂xi
dx
=
∫Rm+1
+
βxβ−1m+1φm+1|∇v|2dx.
(3.1.16)
A weakly harmonic map which satisfies (3.1.16) for every φ ∈ C∞0 (Rm+1+ ;Rm+1)
is said to be weakly stationary harmonic or stationary harmonic. A weakly har-
monic map with respect to the Neumann type boundary condition (3.1.11) which
satisfies (3.1.16) for every φ ∈ D+(Rm+1+ ;Rm+1) with φ(·, 0) ∈ C∞0 (O; ∂Rm+1
+ ) is
called weakly stationary harmonic, or stationary harmonic, with respect to the
Neumann type boundary condition (3.1.11).
If we assume v is smooth we may integrate by parts in (3.1.16) to obtain a
divergence form equation. We consider (3.1.16) for φ ∈ C∞0 (Rm+1+ ;Rm+1) and
analyse the term involving |∇v|2 on the left hand side. We calculate
∫Rm+1
+
m+1∑i=1
m+1∑k=1
xβm+1δik|∇v|2∂φk∂xi
dx =
∫Rm+1
+
m+1∑k=1
∂
∂xk
(xβm+1|∇v|2φk
)dx
−∫Rm+1
+
m+1∑k=1
∂
∂xk
(xβm+1|∇v|2
)φkdx
= −∫Rm+1
+
m+1∑k=1
∂
∂xk
(xβm+1|∇v|2
)φkdx
(3.1.17)
since φ has compact support in Rm+1+ and thus it follows from an application of the
divergence theorem that∫Rm+1
+
∑m+1k=1
∂∂xk
(xβm+1|∇v|2φk
)dx = 0. An integration
by parts in the first term on the left hand side of (3.1.16) combined with (3.1.17)
56
gives
∫Rm+1
+
m+1∑k=1
∂
∂xk
(xβm+1|∇v|2
)φkdx
−∫Rm+1
+
m+1∑i=1
m+1∑k=1
∂
∂xi
(xβm+12
⟨∂v
∂xi,∂v
∂xk
⟩)φkdx
=
∫Rm+1
+
βxβ−1m+1φm+1|∇v|2dx.
Thus, for i = 1, . . . ,m we have
div
(xβm+1|∇v|2ei − 2xβm+1
⟨∂v
∂xi,∇v
⟩)= 0 in Rm+1
+ (3.1.18)
where we have used the notation
div
(xβm+1
⟨∂v
∂xi,∇v
⟩)=
m+1∑k=1
∂
∂xk
(xβm+1
⟨∂v
∂xi,∂v
∂xk
⟩).
Similarly we find
div
(xβm+1|∇v|2em+1 − 2xβm+1
⟨∂v
∂xm+1
,∇v⟩)
= βxβ−1m+1|∇v|2 in Rm+1
+ . (3.1.19)
3.2 Background Theory and Discussion of the
Problem
We are interested in the regularity properties of maps v ∈ W 1,2β (Rm+1
+ ;N) which
minimise Eβ in the following sense:
Definition 3.2.0.1. Let v ∈ W 1,2β (Rm+1
+ ;N). We say that v is Eβ minimising,
or energy minimising, in Rm+1+ relative to O ⊂ ∂Rm+1
+ , if for every compact K ⊂Rm+1 with K ∩ ∂Rm+1
+ ⊂ O and for every w ∈ W 1,2β (Rm+1
+ ;N) with v|Rm+1+ \K =
w|Rm+1+ \K we have Eβ(v) ≤ Eβ(w).
The main question we intend to answer is whether, away from a small set of
points, minimisers of Eβ relative to O have regular extensions to O.
An energy minimiser relative to O is weakly stationary harmonic with re-
spect to the Neumann type boundary condition (3.1.11) and therefore weakly
stationary harmonic in Rm+1+ . Such a map is also energy minimising in Rm+1
+
among maps with the same boundary values and hence stationary harmonic on
57
this domain. There is a rich regularity theory for maps v : M → N , with M,N
Riemannian manifolds of some order of differentiability, which are minimisers of
the Dirichlet energy (1.0.3) or stationary harmonic maps. The regularity of min-
imisers was first addressed by Morrey, see [31] and references therein. He used
them in his solution of the Plateau Problem for manifold valued maps; given a
region bounded by a finite number of closed Jordan curves, find a surface of least
area whose boundary comprises the curves. He showed that such maps are as
smooth as the regularity M and N permit. Later, Schoen and Uhlenbeck consid-
ered the regularity of minimisers v : M → N , with M,N compact Riemannian
manifolds [44]. They showed minimisers are regular away from a set of Hausdorff
dimension at most dimM − 3. Their approach relied heavily on the use of com-
parison functions, maps which agree with a given minimiser on the boundary of
a domain of interest, and allowed them to directly take advantage of the min-
imising property. To obtain regularity, they used comparison functions which are
smooth mollifications of a given minimiser with energy sufficiently small so that
the mollification may be projected (using πN) onto N and modified to agree with
minimisers on the boundary of a small ball. Further constructions of comparison
maps allowed them to study the singular set of minimisers. Their methods were
extended and simplified by Simon [46] in view of a result of Luckhaus [29] which
provided a different method of constructing comparison functions. We will also
construct comparison maps in this section, basing our approach on that of Simon.
The advantage of this approach is that, when β = 0, it provides a more general
compactness result for sequences of minimising harmonic maps, than those ob-
tained by Schoen and Uhlenbeck in [44]. We expect that a similar compactness
result holds for minimisers of Eβ relative to O, but do not prove the result in this
thesis as we are primarily interested in discerning the regularity of such maps.
If one is considering the regularity properties of stationary or even weakly
harmonic maps, it is necessary to use a different approach from that for min-
imisers as it is no longer fruitful to compare the energies of maps in the same
way. Helein proved full regularity for weakly harmonic maps on a 2 dimensional
domain [26]. This corresponds to m = 1 in the situation considered here and in
this case β = αm−12≡ 0 regardless of the choice of α ∈ R in (3.0.1). His method
was to construct an optimal tangent frame on N ; the purpose of this frame is
to allow one to re-write the equation in a form which shows that the Laplacian
of a minimiser is more regular than the a-priori L1 information obtained from
the Euler-Lagrange equation. If the target manifold N has enough symmetry,
it is possible to write the Euler Lagrange equation in a form sufficient for such
58
gains in regularity without an optimal frame. Evans proved partial regularity of
stationary harmonic maps into spheres using this observation to prove the decay
of the energy on concentric balls is sufficient to allow one to conclude continu-
ity, and hence higher regularity [17]. Bethuel, see [3], extended these results
to general smooth target manifolds using an optimal tangent frame based on
the construction of Helein [26]. More recently Riviere observed that the Euler-
Lagrange equation for harmonic maps with two dimensional domain (and more
generally any critical point of any elliptic conformally invariant functional) may
be re-written so that the maps Laplacian is equal to the product of its gradient
with an anti-symmetric factor [39]. This factor may depend on the map and its
gradient. Riviere deduced such maps satisfy a conservation law; the divergence
of a first order quantity along solutions vanishes. In dimensions two he showed
this yields continuity. This method was then extended to maps whose domain
is of any dimension by Riviere and Struwe who noted that the harmonic map
equation may still be written as a product in the aforementioned form [40]. An
application of a well chosen gauge transformation to the gradient then makes the
anti-symmetric factor divergence free and one can again deduce decay estimates
for the energy sufficient to conclude continuity.
The result of Helein, see [26], allows us to conclude that, for maps whose
domain is 2 dimensional, minimisers of Eβ = E0 are smooth since such a map
satisfies (3.1.6). In fact, as shown in the proof of Theorem 1.2 in [34], we can
reflect a minimiser, or stationary critical point, relative to O of E0 evenly in
R × 0 to get a harmonic map defined on R2\((R × 0)\O) which is smooth.
The restriction of such a map is then smooth on O.
If α = 0 in the definition of our metric then β ≡ 0, regardless of m. In this
case we are considering E0 for maps defined on Rm+1+ . Again, we may reflect
a minimiser or stationary harmonic map evenly in Rm × 0, as in the proof
of Theorem 1.3 in [34], to get a harmonic map on Rm+1\((Rm × 0)\O). The
aforementioned regularity theory then applies in this case. Otherwise, the singu-
larity or degeneracy of the metrics we consider along the boundary hyperplane
Rm × 0 prevents us from using the regularity theory directly to show that a
critical point can be extended in the desired way to the boundary hyperplane.
Henceforth we will assume that m ≥ 2 and α 6= 0.
So far we have discussed interior regularity theory for harmonic maps. As
stated previously, we are specifically interested in the regularity of minimisers of
v in O. On this set, minimisers of Eβ weakly satisfy the Neumann type boundary
condition (3.1.11). This condition also arises in the free boundary problem for
59
harmonic maps; if v is a weakly harmonic map in Rm+1+ and we require v(O) ⊂ N
then, at least for β = 0 (see [23] for example), v weakly satisfies the Neumann
type boundary condition (3.1.11). We therefore discuss some results from the
theory of free boundary problems as well.
A number of regularity results for various classes of harmonic maps v : M →N satisfying a free boundary condition, with M,N Riemannian manifolds satis-
fying conditions described below, have been obtained in the literature as part of
an investigation into constrained boundary conditions: v(O) ⊂ Γ for a relatively
open submanifold O ⊂ ∂M and a submanifold Γ ⊂ N . Such a condition im-
plies ∂v∂ν
, with ν the unit normal to ∂M , is orthogonal to Γ on O [23]. Neumann
boundary conditions, analogous to (3.1.11) with β = 0, arise when Γ = N ; in
this case ∂v∂ν
must be both orthogonal and tangential to N hence equal to zero.
Baldes studied the regularity of weakly harmonic maps which satisfy the con-
straint on O ( ∂M with Dirichlet data on the remainder of the boundary [2].
Both M and N are assumed compact with and without boundary respectively.
He required that v(O) ⊂ Γ for a totally geodesic Γ ⊂ N and showed that if the
sectional curvature of N is bounded above and the image of S under the Dirich-
let data is contained in a sufficiently small (depending on the curvature bound)
geodesic ball in N with centre in Γ, then this mixed boundary problem has a
solution which is as smooth as the regularity of M and N permits. In particular,
the singular set of such maps is empty. Gulliver and Jost also considered weakly
harmonic maps v with constrained boundary conditions v(∂M) ⊂ Γ [23]. Their
hypotheses are in terms of a family of convex functions parametrised by points
in Γ; in particular they yield continuity, and higher regularity at free boundary
points. They also construct an example of a weakly harmonic map with a dis-
continuity at the free boundary and illustrate that the second fundamental form,
in N , of Γ plays a role in the regularity of v at free boundary points.
There are also works which address the regularity of harmonic maps at a
free boundary with no geometric assumptions on M,N or Γ; only compactness
and some degree of differentiablity of these manifolds are required. However,
to compensate for the lack of geometric hypotheses one must stipulate that the
maps in question are energy minimising or stationary harmonic and respect the
free boundary condition since, as mentioned previously, there are examples of
weakly harmonic maps with discontinuities at the free boundary. Such examples
imply that weakly harmonic maps satisfying the free boundary condition may
have points of discontinuity at the boundary in general and therefore one can, at
most, expect partial regularity on the boundary. Since we assume N is compact
60
and smooth, with no other geometric conditions, we also only expect a partial
regularity result for minimisers of Eβ relative to O.
Two simultaneous works addressed the regularity of minimising harmonic
maps satisfying the free boundary condition v(O) ⊂ Γ which use different meth-
ods to obtain partial regularity results. Hardt and Lin considered the free bound-
ary problem for energy minimisers v with v(∂M) ⊂ N as well as the constrained
problem v(∂M) ⊂ Γ [24]. Their methods are based on the construction of com-
parison maps analogous to those of Schoen and Uhlenbeck [44]; Hardt and Lin use
these maps, together with a blow up procedure in the domain, to show that near
free boundary points the energy decays sufficiently to conclude continuity. They
prove that minimisers are regular on O away from a set of Hausdorff dimension
at most dimM − 4 for the free boundary case and at most dimM − 3 for the
constrained problem. Moreover, they give examples of minimisers with singular
sets in O which have precisely the stated Hausdorff dimensions, thus showing
that the dimension bounds for the singular set are optimal. Duzaar and Steffen
also obtained partial regularity for the constrained problem for minimisers with
v(O) ⊂ Γ [16]. They combined the methods of Schoen and Uhlenbeck with a
partial reflection of the minimiser across Γ in N to obtain appropriate compar-
ison maps. Using these maps, they showed that minimisers of the constrained
problem are as smooth as allowed by M,N away from a subset of O with van-
ishing dimM − 2 Hausdorff measure. They subsequently improved their results,
see [15], to achieve the same bound as Hardt and Lin, basing their method on
the dimension reducing arguments used by Schoen and Uhlenbeck [44].
Scheven considered the regularity of stationary harmonic maps v with respect
to the constraint v(O) ⊂ Γ [41]. His methods are based on a reflection of v across
Γ in N combined with a number of arguments used by Bethuel [3]. He showed
that stationary harmonic maps satisfying the free boundary condition are smooth
away from a singular set of vanishing dimM − 2 dimensional Hausdorff measure.
A common feature in the aforementioned literature on boundary problems is
an extension of the maps in question by reflection across Γ in N and/or across
O in M . We will not need a reflection in N since we only consider maps with
the free boundary condition v(O) ⊂ N . In this case we have the Neumann
condition (3.1.11) and similarly to [34] we may, if necessary, just consider the
even reflection in ∂Rm+1+ of minimisers of Eβ relative to O. We also note that
in the literature regarding boundary problems with no geometric assumptions
on N , the partial regularity results obtained all give the optimal bound on the
Hausdorff dimension of the singular set on the free boundary. In this thesis, we
61
are only interested in obtaining regularity away from a singular set and do not
consider reducing the maximum dimension of the set we obtain as it turns out to
be small enough for our purposes. However, as mentioned previously, we expect
our method of constructing comparison maps to yield a compactness result for
sequences of minimisers which, in turn, would then permit the analysis of the
singular set of minimisers of Eβ relative to O.
The main theorem of this section is the following.
Theorem 3.2.0.1. Suppose v ∈ W 1,2β (Rm+1
+ ;N) is a minimising harmonic map
relative to O ⊂ ∂Rm+1+ . Then there is a relatively closed set Σ ⊂ Rm+1
+ ∪ Oof vanishing (m + β − 1)-dimensional Hausdorff measure, with respect to the
Euclidean metric, such that v ∈ C0,γ((Rm+1+ ∪ O)\Σ;N) for some γ ∈ (0, 1).
Furthermore, Σ decomposes into Σint = Σ ∩ Rm+1+ which is relatively closed in
Rm+1+ and has Hausdorff dimension m− 2, and Σbdry = Σ∩O which is relatively
closed in O and satisfies Hm+β−1(Σbdry) = 0.
The part of the theorem corresponding to regularity in Rm+1+ is a direct con-
sequence of the regularity theory of Schoen and Uhlenbeck. To elucidate; a
minimising harmonic map v : Rm+1+ → N restricts to a minimising harmonic
map on any (m+ 1)-dimensional compact subset K of the Riemannian manifold
(Rm+1+ , xαm+1δij) with α ∈ R. Since K is compact this means that the restriction
of the metric is smooth and bounded. Let K denote the interior of K. Theorem
II in [44] guarantees that v is smooth in K with the possible exception of a set
which is closed in K and has (m−2)-dimensional Hausdorff measure. We can ex-
press Rm+1+ as a countable union ∪∞i=1Ki where each Ki is an (m+1)-dimensional
compact subset of Rm+1+ and Ki ⊂ Ki+1 for every i ∈ N. Then v is smooth in Ki
with the possible exception of a closed subset Σi of Ki , where Σi has vanishing
m−2+ δ-dimensional Hausdorff measure for every δ > 0. We note that Ki \Σi is
open in Ki and hence open in Rm+1+ . Thus ∪iKi \Σi is open in Rm+1
+ and its com-
plement is therefore closed in Rm+1+ . We conclude that Rm+1
+ \∪i (Ki \Σi) = ∪iΣi
is closed in Rm+1+ and v is smooth in Rm+1
+ \Σint where Σint := ∪∞i=1Σi. Since each
Σi has vanishing m− 2 + δ-dimensional Hausdorff measure (for every δ > 0) we
conclude that Σint has the same property. Hence the Hausdorff dimension of Σint
is at most m − 2. Furthermore, Σint comprises all points x ∈ Rm+1+ such that
v is not continuous in any neighbourhood of x since, by Theorem 8.5.1 in [27],
continuous weakly harmonic maps are smooth.
To show that minimisers of Eβ have the desired extension to O we develop a
regularity theory, analogous to that for harmonic maps, at this boundary. Our
62
proof of Holder continuity contains a number of results which have counterparts
in the theory of harmonic maps.
3.3 Energy Monotonicity
Stationary harmonic maps satisfy a monotonicity formula for an appropriately
scaled version of the energy over balls with closure in Rm+1+ . This property was
proved by Schoen and Uhlenbeck for energy minimisers, see [44] Proposition 2.4,
and Price, see the remark after Theorem 1 in [37], for stationary harmonic maps.
This monotonicity formula is a key ingredient in the proof of Holder continuity
of both stationary and minimising harmonic maps; it contributes to the proof of
energy decay estimates sufficient to conclude the desired continuity.
We show that stationary harmonic maps with respect to the Neumann-type
boundary condition (3.1.11) satisfy a similar monotonicity formula on half-balls
B+ρ (y) = x ∈ Rm+1
+ : |x− y| < ρ
in Rm+1+ with centre y in O and which satisfy ∂0B+
ρ (y) = Bm(y) ⊂ O, where
∂0B+ρ (y) is the interior, with respect to Rm×0, of ∂B+
ρ (y)∩∂Rm+1+ . Moreover,
we will derive a version of the formula for balls with closure contained in Rm+1+ ,
with a view to determining what factors the constants involved depend upon.
Many of the estimates we consider involve integrals over ∂B+ρ (y) ∩Rm+1
+ and
so we use the following notation. Let Ω ⊂ Rm+1 and define
∂+Ω = ∂Ω ∩ Rm+1+ .
We will also use a smooth cutoff function
χ(s) =
0 s ∈ (−∞, 1
2]
0 ≤ χ(s) ≤ 1 s ∈ (12, 1)
1 s ∈ [1,∞)
(3.3.1)
in the following proofs.
3.3.1 Boundary Energy Monotonicity
Lemma 3.3.1.1. Suppose v ∈ W 1,2β (Rm+1
+ ;N) is a weakly stationary harmonic
map with respect to the Neumann-type boundary condition (3.1.11). Suppose y
63
in O and consider B+R(y) with ∂0B+
R(y) ⊂ O. Then
r1−m−β∫B+r (y)
xβm+1 |∇v|2 dx− s1−m−β
∫B+s (y)
xβm+1 |∇v|2 dx
= 2
∫B+r (y)\B+
s (y)
xβm+1
|(x− y) · ∇v|2
|x− y|m+1+βdx (3.3.2)
whenever 0 ≤ s ≤ r ≤ R and therefore
ρ1−m−β∫B+ρ (y)
xβm+1 |∇v|2 dx
is a non-decreasing function of ρ for 0 < ρ ≤ R.
Proof. We follow [46] Section 2.4 and [33] Lemma 3.3. Our strategy is to test the
weak form of the stationary equations (3.1.16) for a map v, which is a stationary
harmonic map with respect to the Neumann type boundary condition (3.1.11),
against a sequence of functions which are the product of the vector x − y and
a smooth, radially symmetric, sequence of real valued functions which converge
pointwise to the indicator function of B+ρ (y). We take the limit of the resulting
integrals to yield the statement of the lemma in terms of the derivatives, with
respect to the radius, of the quantities involved and then integrate to give the
conclusion.
We test (3.1.16) with φ(x) = (x − y)η(x) where η ∈ C∞0 (Bρ(y)), since in
this case φ(x′, 0) = (x′ − y′, 0)η(x) ∈ ∂Rm+1+ for every x = (x′, 0) ∈ O and so
φ(·, 0) ∈ C∞0 (O; ∂Rm+1+ ). This gives
∫Rm+1
+
m+1∑i=1
m+1∑k=1
xβm+1
(2
⟨∂v
∂xi,∂v
∂xk
⟩− δik|∇v|2
)(δikη + (xk − yk)
∂η
∂xi
)dx
=
∫Rm+1
+
βxβm+1η|∇v|2dx (3.3.3)
since ym+1 = 0. In more concise notation, after rearranging, (3.3.3) becomes
(m− 1 + β)
∫Rm+1
+
xβm+1 |∇v|2 ηdx+
∫Rm+1
+
xβm+1(x− y) · ∇η |∇v|2 dx
= 2
∫Rm+1
+
xβm+1 〈(x− y) · ∇v,∇η · ∇v〉 dx. (3.3.4)
Let χ be the cutoff function defined in (3.3.1). The smooth functions defined
by ηj(x) = χ(j(ρ − |x − y|)) are admissible choices for η and the sequence ηj
64
converges pointwise to the indicator function of B+ρ (y) in Rm+1
+ . Furthermore,
∂ηj∂xi
(x) =
−j xi−yi|x−y|χ
′(j(ρ− |x− y|)) if |x− y| ∈(ρ− 1
j, ρ− 1
2j
)0 if |x− y| ≥ ρ− 1
2jor |x− y| ≤ ρ− 1
j.
(3.3.5)
Replacing η with ηj in (3.3.4) we see that
(m− 1 + β)
∫Rm+1
+
xβm+1 |∇v|2 ηjdx
−∫Rm+1
+
xβm+1j|x− y|χ′(j(ρ− |x− y|)) |∇v|2 dx
= −2
∫Rm+1
+
xβm+1
j
|x− y|χ′(j(ρ− |x− y|)) |(x− y) · ∇v|2 dx. (3.3.6)
We want to let j →∞ in (3.3.6) and so we consider each term in turn. Firstly,
an application of Lebesgue’s Dominated Convergence Theorem gives
limj→∞
∫Rm+1
+
xβm+1 |∇v|2 ηjdx =
∫B+ρ (y)
xβm+1 |∇v|2 dx. (3.3.7)
We must now deal with the terms in (3.3.6) involving χ′. Let
f(r) =
∫∂+B+
r (y)
xβm+1 |∇v|2 dσ(x)
for r > 0, where dσ is the measure on ∂+B+r (y), and note that∫
B+ρ (y)
xβm+1 |∇v|2 dx =
∫ ρ
0
f(r)dr.
We calculate∣∣∣∣∣∫ ρ
ρ− 1j
jrχ′(j(ρ− r))f(r)dr − ρf(ρ)
∣∣∣∣∣ =
∣∣∣∣∣∫ ρ
ρ− 1j
jχ′(j(ρ− r))(rf(r)− ρf(ρ))dr
∣∣∣∣∣≤ cj
∫ ρ
ρ− 1j
|rf(r)− ρf(ρ)|dr.
Moreover, for almost every ρ > 0, the right hand side tends to zero as j → ∞by Lebesgue’s differentiation theorem. Hence, since χ′(j(ρ− r)) is supported for
65
r ∈(ρ− 1
j, ρ− 1
2j
), we find
limj→∞
∫Rm+1
+
xβm+1j|x− y|χ′(j(ρ− |x− y|)) |∇v|2 dx
= limj→∞
∫ ρ− 12j
ρ− 1j
jrχ′(j(ρ− r))f(r)dr
= ρf(ρ)
= ρ
∫∂+B+
ρ (y)
xβm+1 |∇v|2 dσ(x) (3.3.8)
for almost every ρ > 0. Similarly, Lebesgue’s differentiation theorem guarantees
that
limj→∞
∫Rm+1
+
xβm+1
j
|x− y|χ′(j(ρ− |x− y|)) |(x− y) · ∇v|2 dx
= ρ−1
∫∂+B+
ρ (y)
xβm+1 |(x− y) · ∇v|2 dσ(x) (3.3.9)
for almost every ρ > 0. Hence, in view of (3.3.7), (3.3.8) and (3.3.9), letting
j →∞ in (3.3.6) yields
(m− 1 + β)
∫B+ρ (y)
xβm+1 |∇v|2 dx− ρ
∫∂B+
ρ (y)
xβm+1 |∇v|2 dσ(x)
= −2
ρ
∫∂+B+
ρ (y)
xβm+1 |(x− y) · ∇v|2 dσ(x).
Multiplying the above by the factor −ρ−(β+m) gives
(1−m− β)ρ−(β+m)
∫B+ρ (y)
xβm+1 |∇v|2 dx+ ρ1−m−β
∫∂+B+
ρ (y)
xβm+1 |∇v|2 dσ(x)
= 2ρ−(1+m+β)
∫∂+B+
ρ (y)
xβm+1 |(x− y) · ∇v|2 dσ(x).
(3.3.10)
Since ddρ
∫B+ρ (y)
xβm+1 |∇v|2 dx = d
dρ
∫ ρ0f(r)dr =
∫∂+B+
ρ (y)xβm+1 |∇v|
2 dσ(x) for al-
most all ρ > 0, in view of (3.3.10) we have
d
dρ
(ρ1−m−β
∫B+ρ (y)
xβm+1 |∇v|2 dx
)= 2
∫∂+B+
ρ (y)
xβm+1
|(x− y) · ∇v|2
|x− y|m+1+βdσ(x)
(3.3.11)
66
for almost every ρ > 0. Choose two positive numbers r and s with 0 < s < r such
that B+s (y) ⊂ B+
r (y). Since the integral of an L1 function over a half-ball of radius
ρ is an absolutely continuous function of ρ we may integrate (3.3.11) between s
and r. This gives (3.3.2) which in turn shows that ρ1−m−β ∫B+ρ (y)
xβm+1 |∇v|2 dx is
a non-decreasing function of ρ.
It follows from Lemma 3.3.1.1 that limρ→0+ ρ1−m−β ∫B+ρ (y)
xβm+1|∇v|2dx is well
defined for y in O whenever v is a weakly stationary harmonic map with respect
to the Neumann type boundary condition (3.1.11). This means we can define the
density function
Θβv (y) = lim
ρ→0+ρ1−m−β
∫B+ρ (y)
xβm+1|∇v|2dx
analogously to Definition 1 in Section 2.5 of [46]. This function will be useful
later in considerations of the singular set of minimisers and satisfies the following
property.
Lemma 3.3.1.2. The density function Θβv is upper semi-continuous in O for
any map v which is weakly stationary harmonic with respect to the Neumann-
type boundary condition (3.1.11).
Proof. We need to show that if (xi)i∈N is a sequence in O converging to x0 ∈ Othen
lim supi→∞
Θβv (xi) ≤ Θβ
v (x0). (3.3.12)
Consider such a sequence (xi)i∈N with xi → x0 as i → ∞ and let δ > 0. We
choose a radius r > 0 such that ∂0B+r (x0) = Bm
r (x0) ⊂ O and
r1−m−β∫B+r (x0)
xβm+1|∇v|2dx ≤ Θβv (x0) + δ.
For large i it follows that xi ∈ Bmr (x0) and so B+
r−|xi−x0|(xi) ⊂ B+r (x0). Thus
(r − |xi − x0|)1−m−β∫B+r−|xi−x0|
(xi)
xβm+1|∇v|2dx
≤(
1− |xi − x0|r
)1−m−β
r1−m−β∫B+r (x0)
xβm+1|∇v|2dx
≤(
1− |xi − x0|r
)1−m−β
(Θβv (x0) + δ). (3.3.13)
67
Using the definition of Θβv and the boundary monotonicity formula, Lemma
3.3.1.1, we deduce that
Θβv (xi) = lim
ρ→0+ρ1−m−β
∫B+ρ (xi)
xβm+1|∇v|2dx
≤ (r − |xi − x0|)1−m−β∫B+r−|xi−x0|
(xi)
xβm+1|∇u|2dx. (3.3.14)
The combination of (3.3.13) and (3.3.14) shows that
Θβv (xi) ≤
(1− |xi − x0|
r
)1−m−β
(Θβv (x0) + δ)
and therefore
lim supi→∞
Θβv (xi) ≤ lim sup
i→∞
(1− |xi − x0|
r
)1−m−β
(Θβv (x0) + δ) = Θβ
v (x0) + δ.
Since δ is arbitrary we conclude (3.3.12) holds as required.
Now we proceed with a derivation of the monotonicity formula for balls with
closure in Rm+1+ .
3.3.2 Interior Energy Monotonicity
The interior version of the energy monotonicity formula presented here is due
to Grosse-Brauckmann, [22] Theorem 1. We present a proof here with a view
to determining explicit dependences of the constants, this will allow a degree of
compatibility of the boundary and interior versions of the lemma.
Lemma 3.3.2.1. Suppose v ∈ W 1,2β (Rm+1
+ ;N) is weakly stationary harmonic.
Fix a ball Bρ0(y) with Bρ0(y) ⊂ Rm+1+ for some ρ0 > 0. Choose two positive
numbers r and s with 0 < s < r < ρ0. Then
erC|β|r1−m∫Br(y)
xβm+1 |∇v|2 dx − esC|β|s1−m
∫Bs(y)
xβm+1 |∇v|2 dx
≥ 2
∫Br(y)\Bs(y)
xβm+1e|x−y|C|β| |(x− y) · ∇v|2
|x− y|m+1dx (3.3.15)
and therefore, for 0 < ρ < ρ0,
eρC|β|ρ1−m∫Bρ(y)
xβm+1 |∇v|2 dx
68
is a non-decreasing function of ρ where C = (ym+1 − ρ0)−1.
Proof. Again we follow [46] Section 2.4 and [33] Lemma 3.3, the method of proof
is analogous to the proof of Lemma 3.3.1.1.
Fix ρ0 and y ∈ Rm+1+ such that Bρ0(y) ⊂ Rm+1
+ and let η ∈ C∞0 (Rm+1+ ). In
order to proceed we test (3.1.16) against the function (x− y)η(x). This gives
(m− 1)
∫Rm+1
+
xβm+1 |∇v|2 ηdx+
∫Rm+1
+
xβm+1(x− y) · ∇η |∇v|2 dx
+
∫Rm+1
+
βxβm+1η|∇v|2dx−∫Rm+1
+
βxβ−1m+1ym+1η|∇v|2dx
=
∫Rm+1
+
xβm+12 〈(x− y) · ∇v,∇η · ∇v〉 dx. (3.3.16)
We consider a sequence of test functions which converge pointwise to the indicator
function of Bρ(y), with ρ < ρ0. Let χ ∈ C∞0 (R; [0, 1]) be the cutoff function given
by (3.3.1). As in the proof of Lemma 3.3.1.1 we define ηj(x) = χ(j(ρ− |x− y|))and, replacing η with ηj in (3.3.16), we take the limit as j →∞ using Lebesgue’s
dominated convergence and differentiation theorems. We find
(m− 1)
∫Bρ(y)
xβm+1 |∇v|2 dx+
∫Bρ(y)
βxβm+1|∇v|2dx
−∫Bρ(y)
βxβ−1m+1ym+1|∇v|2dx− ρ
∫∂Bρ(y)
xβm+1 |∇v|2 dσ(x)
= −2
ρ
∫∂Bρ(y)
xβm+1 |(x− y) · ∇v|2 dσ(x) (3.3.17)
where dσ(x) is the measure on Bρ(y). To proceed we must examine the term∫Bρ(y)
βxβ−1m+1ym+1|∇v|2dx more closely. Observe that
xm+1 − ρ ≤ ym+1 ≤ xm+1 + ρ
and (xm+1)−1 ≤ (ym+1−ρ0)−1 for every x ∈ Bρ(y) and every ρ < ρ0. We therefore
calculate∫Bρ(y)
βxβ−1m+1ym+1|∇v|2dx ≤ ρC|β|
∫Bρ(y)
xβm+1|∇v|2dx+ β
∫Bρ(y)
xβm+1|∇v|2dx
(3.3.18)
69
where C = (ym+1 − ρ0)−1. Substituting (3.3.18) into (3.3.17) we see that
−(1−m+ ρC|β|)∫Bρ(y)
xβm+1 |∇v|2 dx− ρ
∫∂Bρ(y)
xβm+1 |∇v|2 dσ(x)
≤ −2
ρ
∫∂Bρ(y)
xβm+1 |(x− y) · ∇v|2 dσ(x)
and multiplying through by −eρC|β|ρ−m gives
(1−m+ ρC|β|)eρC|β|ρ−m∫Bρ(y)
xβm+1 |∇v|2 dx
+ eρC|β|ρ1−m∫∂Bρ(y)
xβm+1 |∇v|2 dσ(x)
≥ ρ−(1+m)eρC|β|2
∫∂Bρ(y)
xβm+1 |(x− y) · ∇v|2 dσ(x).
Thus for almost all admissible ρ > 0 we have
d
dρ
(eρC|β|ρ1−m
∫Bρ(y)
xβm+1 |∇v|2 dx
)
≥ 2
∫∂Bρ(y)
xβm+1e|x−y|C|β| |(x− y) · ∇v|2
|x− y|(m+1)dσ(x). (3.3.19)
Choose two positive numbers r and s with 0 < s < r < ρ0 such that Bs(y) ⊂Br(y) ⊂ Bρ0(y). Since the integral of an L1 function over a ball of radius ρ is an
absolutely continuous function of ρ we may integrate (3.3.19) with respect to ρ.
This gives (3.3.15) which in turn shows that eρC|β|ρ1−m ∫Bρ(y)
xβm+1 |∇v|2 dx is a
non-decreasing function of ρ whenever ρ ≤ ρ0.
Remark 3.3.2.1. Note that ym+1 − ρ0 = dist(Bρ0(y),Rm × 0). The constant C
from the lemma can thus be written as C = (dist(Bρ0(y),Rm × 0))−1.
3.4 Motivating Observations Concerning the En-
ergy
Here we consider the relationship between Dirichlet energies with respect to the
Riemannian metric g defined by (3.0.1) and the Euclidean metric, taken over half
balls B+R(x0) ⊂ Rm+1
+ with x0 ∈ Rm × 0 and balls Bρ(y) with Bρ(y) ⊂ Rm+1+
respectively. We also investigate the effect of changing between the Lebesgue
measure and dµβ (corresponding to the metrics g for β ∈ (−1, 1)) for balls with
70
closure contained in Rm+1+ . The following discussion provides motivation for the
form of Lemma 3.5.0.2 in Section 3.5 and our overall approach to proving the
Holder continuity of minimising harmonic maps.
First we consider switching between the Lebesgue measure and dµβ, as we
will need our conclusions in order to discuss the Dirichlet energies. We identify a
class of ball in Rm+1+ on which we can immediately obtain results like the Poincare
inequality with respect to the measure dµβ from the corresponding results for the
Lebesgue measure, recall Lemma 2.3.3.2 from Section 2.3.3, the only cost being
a slightly larger constant. Let Bρ(y) be a ball with Bρ(y) ⊂ Rm+1+ . We note that
infBρ(y)
xβm+1 = (ym+1 − sgn(β)ρ)β
and
supBρ(y)
xβm+1 = (ym+1 + sgn(β)ρ)β.
where sgn(β) is the sign of β. Let f, g ∈ L1(Bρ(y);Rn) and suppose∫Bρ(y)
|f |dx ≤∫Bρ(y)
|g|dx.
We have
(ym+1 + sgn(β)ρ)−β∫Bρ(y)
|f |dµβ ≤∫Bρ(y)
|f |dx
≤∫Bρ(y)
|g|dx
≤ (ym+1 − sgn(β)ρ)−β∫Bρ(y)
|g|dµβ.
Hence ∫Bρ(y)
|f |dµβ ≤(ym+1 + sgn(β)ρ)β
(ym+1 − sgn(β)ρ)β
∫Bρ(y)
|g|dµβ
which is equivalent to∫Bρ(y)
|f |dµβ ≤(
1 +2ρ
ym+1 − ρ
)|β| ∫Bρ(y)
|g|dµβ. (3.4.1)
Note that ym+1 − ρ = dist(Bρ(y),Rm × 0). In view of (3.4.1) we will restrict
71
focus to balls where dist(Bρ(y),Rm × 0) ≥ ρ since in this case (3.4.1) implies∫Bρ(y)
|f |dµβ ≤ 3|β|∫Bρ(z)
|g|dµβ.
Furthermore, if β ∈ (−1, 1) we have∫Bρ(y)
|f |dµβ ≤ 3
∫Bρ(z)
|g|dµβ. (3.4.2)
In a similar vein we observe that, on any Bρ(y) ⊂ Rm+1+ with ym+1 − ρ ≥ ρ,
we have ym+1
2≤ ym+1 − ρ ≤ ym+1 ≤ ym+1 + ρ ≤ 3ym+1
2. Thus if x ∈ Bρ(y) and
β ∈ (−1, 1) we have
cyβm+1 ≤ xβm+1 ≤ Cyβm+1 (3.4.3)
for two constants c, C independent of β. It follows that
c0 ≤supBρ(y) x
βm+1
infBρ(y) xβm+1
≤ C0 (3.4.4)
for two constants c0, C0 independent of β ∈ (−1, 1).
We define some notation for the aforementioned class of ball. Let
B = Bρ(y) ⊂ Rm+1+ : ym+1 ≥ 2ρ. (3.4.5)
In addition, define
Bθ = Bρ(y) ⊂ Rm+1+ : ym+1 ≥ θρ (3.4.6)
for θ ≥ 2. Then Bθ ⊂ B and B2 = B. Many of our calculations on balls in Bθ will
be with reference to a half-ball B+R(x0) with x0 ∈ ∂Rm+1
+ and so we also define
Bθ(x0, R, r) = Bρ(y) ⊂ B+R(x0) : ym+1 ≥ θρ, y ∈ B+
r (x0), (3.4.7)
dropping the subscript θ in the case θ = 2. We will also often want to refer to a
class of half-balls related to B+R(x0). Let
B+(x0, R, r) = B+ρ (y) ⊂ B+
R(x0) : ym+1 = 0, |x0 − y| < r, ρ ≤ r. (3.4.8)
For future reference we note that the classes defined in (3.4.8) and (3.4.7) corre-
spond to those considered in (3.5.3) and (3.5.4) respectively in Lemma 3.5.0.2.
When combined with, for example, the Poincare inequality, Lemma 2.3.3.2, for
functions in W 1,2(Bρ(y);Rn) where Bρ(y) ∈ B, (3.4.2) and (3.4.4) are particularly
72
useful. We record the following version of Lemma 2.3.3.2.
Lemma 3.4.0.1. Let Bρ(y) ∈ B and v ∈ W 1,2β (Bρ(y);Rn). Then∫
Bρ(y)
|v − vBρ(y),β|2dµβ ≤ Cρ2
∫Bρ(y)
|∇v|2dµβ (3.4.9)
for a positive constant C = C(m).
Proof. For suchBρ(y), we combine Lemma 2.3.3.2 with (3.4.4) to yield the lemma.
Now we discuss the Dirichlet energies, taken over open Ω ⊂ Rm+1+ . For refer-
ence, we define the energies
EβΩ(v) =
1
2
∫Ω
|∇v|2 dµβ (3.4.10)
for v ∈ W 1,2β (Ω;Rn) and
EΩ(v) = E0Ω(v) =
1
2
∫Ω
|∇v|2 dx
for v ∈ W 1,2(Ω;Rn). We will favour the integral notation in technical compu-
tations involving the weights to make them more transparent. When we change
between dµβ and the Lebesgue measure, or want to emphasise the role xβm+1 has
as a coefficient of a PDE, in addition to a weighting of the Lebesgue measure, we
may expand the expression for dµβ into xβm+1dx.
Consider B ym+12
(y) ∈ B, let y+ = (y1, . . . , ym, 0) and note that B ym+12
(y) ⊂B+
3ym+12
(y+). Using (3.4.3) we have
(ym+1
2
)1−m∫B ym+1
2(y)
|∇v|2 dx ≤ Cy−βm+1
(ym+1
2
)1−m∫B ym+1
2(y)
xβm+1 |∇v|2 dx
≤ C
(3ym+1
2
)1−m−β ∫B+
3ym+12
(y+)
xβm+1 |∇v|2 dx
(3.4.11)
where C = C(m) is a positive constant which is chosen large enough to be inde-
pendent of β ∈ (−1, 1). In fact, we can combine (3.4.11) with the monotonicity
formulas proved in Section 3.3 and replace the left hand side of (3.4.11) with
ρ1−m ∫Bρ(y)
|∇v|2 dx whenever Bρ(y) ∈ B. Using this idea we can connect esti-
73
mates for the energy on balls in Rm+1+ with estimates for the energy on half-balls
centred on O. More precisely, we have the following.
Lemma 3.4.0.2. Suppose β ∈ (−1, 1) and let v ∈ W 1,2β (Rm+1
+ ;N) be a weakly
stationary harmonic map with respect to the Neumann type boundary condition
(3.1.11). Let B+R(x0) be a half-ball with ∂0B+
R(x0) ⊂ O and suppose Bρ(y) ∈B(x0, R,
R3
). Then there is a constant C = C(m) such that
ρ1−m∫Bρ(y)
|∇v|2dx ≤ CR1−m−β∫B+R(x0)
xβm+1|∇v|2dx. (3.4.12)
Proof. To prove the lemma we need to combine the boundary energy mono-
tonicity formula, Lemma 3.3.1.1, with the interior energy monotonicity formula,
Lemma 3.3.2.1, in a suitable manner. It follows from (3.4.3) that
ρ1−m∫Bρ(y)
|∇v|2 dx ≤ Cy−βm+1ρ1−m
∫Bρ(y)
xβm+1 |∇v|2 dx (3.4.13)
for every Bρ(y) ∈ B and a constant C independent of β ∈ (−1, 1). Notice that
any ball Bρ(y) ∈ B satisfies Bρ(y) ⊂ B ym+12
(y) so we can choose the scaling
factor e2|β|ρym+1 in Lemma 3.3.2.1. Furthermore, e
2|β|ρym+1 ≤ e|β| ≤ e since ym+1 ≥ 2ρ
and β ∈ (−1, 1). Hence, applying Lemma 3.3.2.1, we find
y−βm+1ρ1−m
∫Bρ(y)
xβm+1 |∇v|2 dx
≤ y−βm+1e2|β|ρym+1 ρ1−m
∫Bρ(y)
xβm+1 |∇v|2 dx
≤ y−βm+1e2|β|ym+1
2ym+1
(ym+1
2
)1−m∫B ym+1
2(y)
xβm+1 |∇v|2 dx
≤ 2βe(ym+1
2
)1−m−β∫B ym+1
2(y)
xβm+1 |∇v|2 dx
≤ C(ym+1
2
)1−m−β∫B ym+1
2(y)
xβm+1 |∇v|2 dx (3.4.14)
where C is chosen large enough to be independent of β ∈ (−1, 1). Now let
y = (y1, . . . , ym+1) and y+ = (y1, . . . , ym, 0). Since B ym+12
(y) ⊂ B+3ym+1
2
(y+), we
74
have (ym+1
2
)1−m−β∫B ym+1
2(y)
xβm+1 |∇v|2 dx
≤ C
(3ym+1
2
)1−m−β ∫B+
3ym+12
(y+)
xβm+1 |∇v|2 dx (3.4.15)
where C = C(m) is chosen such that C(m) ≥ 3m ≥ 3m+β−1. If Bρ(y) ∈B(x0, R,
R3
), then y ∈ B+
R3
(x0) and B+3ym+1
2
(y+) ⊂ B+R2
(y+) ⊂ B+R(x0). It fol-
lows from Lemma 3.3.1.1 that(3ym+1
2
)1−m−β ∫B+
3ym+12
(y+)
xβm+1 |∇v|2 dx ≤
(R
2
)1−m−β ∫B+R2
(y+)
xβm+1 |∇v|2 dx.
(3.4.16)
Lastly, since B+R2
(y+) ⊂ B+R(x0) for y ∈ B+
R2
(x0), it follows that
(R
2
)1−m−β ∫B+R2
(y+)
xβm+1 |∇v|2 dx ≤ CR1−m−β
∫B+R(x0)
xβm+1 |∇v|2 dx (3.4.17)
where C = C(m) ≥ 2m ≥ 2m+β−1. A combination of (3.4.13), (3.4.14), (3.4.15),
(3.4.16) and (3.4.17) yields (3.4.12).
A consequence of this lemma, vital to our subsequent regularity theory, is as
follows. Suppose R1−m−β ∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε for some ε > 0 and a half-ball
B+R(x0) with ∂0B+
R(x0) ⊂ O. The lemma states that we can control the energy
ρ1−m ∫Bρ(y)
|∇v|2dx, for all Bρ(y) ∈ B(x0, R,R3
), in terms of ε. In particular, if
ε is small then so is ρ1−m ∫Bρ(y)
|∇v|2dx. analogously, Lemma 3.3.1.1 provides
control of the energy ρ1−m−β ∫B+ρ (y)
xβm+1|∇v|2dx in terms of ε for all half-balls
B+ρ (y) ∈ B+(x0, R,
R2
). The details of this process are given in the proof of
Theorem 3.12.1.1.
The preceding two observations motivate the form of the decay lemma in the
next section.
Lastly we explain an assumption we will frequently make in our lemmata;
we assume that any half-ball B+R(x0) appearing henceforth has radius no greater
than 1 and, in general, we will work in the region Rm× (0, 1]. This is a technical
assumption based on the fact that for xm+1 ∈ (0, 1] the weights xβm+1 are ordered
in the following sense; if β2 < β1 are real numbers in (−1, 1) then xβ1
m+1 ≤ xβ2
m+1
75
whenever xm+1 ∈ (0, 1]. If we assume xm+1 ≥ 1 then the converse is true and
the assumption xm+1 ≤ 1 eliminates the need to consider more than one kind of
ordering of the weights. This assumption has no impact on our regularity theory;
the assumption of our main theorem will be
R1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε
for a half-ball B+R(x0) with ∂0B+
R(x0) ⊂ O and an ε > 0 and in view of the
monotonicity formula, Lemma 3.3.1.1,
r1−m−β∫B+r (x0)
xβm+1 |∇v|2 dx ≤ R1−m−β
∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε
for every r ≤ R. Thus we may always assume R ≤ 1.
3.5 A Modified Lemma of Morrey
Since we are considering systems of partial differential equations derived from
energy functionals it is appropriate to try to find an integral characterisation of
Holder continuity in terms of the energy. We modify a decay lemma of Morrey,
[32] Theorem 3.5.2, using the version in [33] Lemma 2.1 for the proof. The form
of the following lemma was suggested to us by the considerations in Section 3.4.
Recall the notation Bθ(x0, R, r) and B+(x0, R, r) defined in Section 3.4. We
will also consider the averages vΩ = 1∫Ω dx
∫Ωvdx and vΩ,β = 1∫
Ω dµβ
∫Ωvdµβ for
bounded Ω ⊂ Rm+1+ and correspondingly integrable v.
We will need the following version of the original decay lemma for the proof
of the modified version.
Lemma 3.5.0.1 ([33] Lemma 2.1). Let γ > 0, v ∈ W 1,p(BR(x0);Rn) for p ≥ 1
and a > 0. There exists a constant C0 = C0(m, γ) such that the following holds.
Suppose
ρp−(1+m)−γ∫Bρ(y)
|∇v|pdx ≤ a (3.5.1)
for every y ∈ BR2(x0) and every ρ ≤ R
2. Then, for almost every x1, x2 ∈ BR
2(x0),
|v(x1)− v(x2)| ≤ C0a1p |x1 − x2|
γp . (3.5.2)
The modified statement is as follows.
76
Lemma 3.5.0.2. Let β ∈ (−1, 1), γ > 0, x0 ∈ Rm × 0, a > 0, θ1 ≥ 2 and
θ2 ≤ 12. Define θ = θ2
2θ1. Then there exists a constant C0 = C0(m, γ, θ1, β) such
that if v ∈ W 1,2β (B+
R(x0);Rn) with
r1−m−β−γ∫B+r (x1)
xβm+1|∇v|2dx ≤ a (3.5.3)
for every B+r (x1) ∈ B+(x0, R, θ2R), and
r1−m−γ∫Br(x2)
|∇v|2dx ≤ a (3.5.4)
for every Br(x2) ∈ Bθ1(x0, R, θ2R), then for almost every x1, x2 ∈ B+θR(x0),
|v(x1)− v(x2)| ≤ C0a12 |x1 − x2|
γ2 . (3.5.5)
Proof. The underlying idea of the proof is to apply Lemma 3.5.0.1 for p = 1. In
order to apply this lemma we consider the even reflection of v, with respect to
∂Rm+1+ , to BR(x0). Due to the nature of this reflection we only need to verify the
assumptions of Lemma 3.5.0.1 hold for balls with centres y satisfying ym+1 ≥ 0.
We conclude the proof by using the assumptions (3.5.3) and (3.5.4) combined
with applications of Holder’s inequality to verify that (3.5.1) is satisfied for all
Br(x1) ⊂ B2θR(x0) with x1 ∈ BθR(x0) and r ≤ θR.
Recall that, by Lemma 2.4.2.1, the even reflection of v in ∂Rm+1+ , which we
do not relabel, is in W 1,2β (BR(x0);Rn). First we show that we may restrict our
attention to the case of balls with centre y satisfying ym+1 ≥ 0. Suppose that
the assumption (3.5.1) from Lemma 3.5.0.1 is satisfied, with p = 1, on every
Bρ(y) ⊂ B2θR(x0) with ym+1 ≥ 0, y ∈ BθR(x0) and ρ ≤ θR. This means
ρ−m∫Bρ(y)
|∇v|dx ≤ aργ (3.5.6)
for an a > 0 and a γ ∈ (0, 1). Consider Bρ(z) ⊂ B2θR(x0) with zm+1 ≤ 0,
z ∈ BθR(x0) and ρ ≤ θR. It follows that z = (y′,−ym+1) for some y = (y′, ym+1)
with ym+1 ≥ 0 and y ∈ BθR(x0). A change of variables gives∫Bρ(z)
|∇v|dx =
∫Bρ(y)
|∇v|dx. (3.5.7)
It follows from (3.5.7) that (3.5.6) is satisfied on every Bρ(z) ⊂ B2θR(x0) with
zm+1 ≤ 0, z ∈ BθR(x0) and ρ ≤ θR provided that (3.5.6) is satisfied on every
77
Bρ(y) ⊂ B2θR(x0) with ym+1 ≥ 0, y ∈ BθR(x0) and ρ ≤ θR.
Our task now is to show that the assumptions of Lemma 3.5.0.1 hold on
B2θR(x0) for θ as specified. In particular, we show that (3.5.6) holds, for a
γ ∈ (0, 1) and an a > 0, on every ball Br(x1) ⊂ B2θR(x0) with (x1)m+1 ≥ 0, x1 ∈BθR(x0) and r ≤ θR. Such a ball must satisfy either Br(x1) ∈ Bθ1(x0, 2θR, θR)
or Br(x1) 6∈ Bθ1(x0, 2θR, θR). We address these cases in turn. Henceforth, C will
denote a constant depending only on m and we will not distinguish such C unless
necessary.
Suppose that Br(x1) ∈ Bθ1(x0, 2θR, θR) with r ≤ θR. We apply Holder’s
inequality to see that
∫Br(x1)
|∇v|dx ≤(∫
Br(x1)
dx
) 12(∫
Br(x1)
|∇v|2dx
) 12
= Crm+1
2
(∫Br(x1)
|∇v|2dx
) 12
. (3.5.8)
Now notice that rm+1
2 = rmr1−m
2 . Furthermore, as θ ≤ θ22θ1≤ θ2, the assumption
Br(x1) ∈ Bθ1(x0, 2θR, θR) implies Br(x1) ∈ Bθ1(x0, R, θ2R). Thus we combine
(3.5.8) with the hypothesis (3.5.4) to give
r−m∫Br(x1)
|∇v|dx ≤ r−mCrmr1−m
2
(∫Br(x1)
|∇v|2dx
) 12
= C
(r1−m
∫Br(x1)
|∇v|2dx
) 12
≤ Ca12 r
γ2 (3.5.9)
which is (3.5.6) with γ = γ2
and a = Ca12 .
We must now consider the case when Br(x1) ⊂ B2θR(x0) with x1 ∈ BθR(x0),
(x1)m+1 ≥ 0 and r ≤ θR but Br(x1) 6∈ Bθ1(x0, 2θR, θR). In this case, since
Br(x1) ⊂ B2θR(x0) and x1 ∈ BθR(x0) by assumption, we must have (x1)m+1 <
θ1r. Expressed slightly differently, we find (x1)m+1 − ζr < r where ζ ≥ 1 is
such that θ1 = ζ + 1. As a consequence, Br(x1) ⊂ B2ζr+r(x+1 ) where x+
1 =
x1 − (0, (x1)m+1). Using the fact that v is even with respect to ∂Rm+1+ and
78
applying Holder’s inequality we find∫Br(x1)
|∇v|dx ≤∫B2ζr+r(x
+1 )
|∇v|dx
= 2
∫B+
2ζr+r(x+1 )
|∇v|dx
≤ 2
(∫B+
2ζr+r(x+1 )
x−βm+1dx
) 12(∫
B+2ζr+r(x
+1 )
xβm+1|∇v|2dx
) 12
.
(3.5.10)
We bound(∫
B+2ζr+r(x
+1 )x−βm+1dx
) 12
above as follows. Let Qρ(y) denote the cube,
with edges parallel to the coordinate axis and of length 2ρ, centred at y ∈ ∂Rm+1+
and let Q+ρ (y) = Qρ(y) ∩ Rm+1
+ . We calculate∫B+
2ζr+r(x+1 )
x−βm+1dx ≤∫Q+
2ζr+r(x+1 )
x−βm+1dx =C
1− β(2ζr + r)1+m−β. (3.5.11)
Combining (3.5.11) with (3.5.10) gives
∫Br(x1)
|∇v|dx ≤ C
(1− β)12
(2ζr + r)1+m−β
2
(∫B+
2ζr+r(x+1 )
xβm+1|∇v|2dx
) 12
.
(3.5.12)
We write (2ζr + r)1+m−β
2 = (2ζ+1)mrm (2ζr + r)1−m−β
2 and use (3.5.12) to deduce
that
r−m∫Br(x1)
|∇v|dx
≤ r−mC(2ζ + 1)m
(1− β)12
rm (2ζr + r)1−m−β
2
(∫B+
2ζr+r(x+1 )
xβm+1|∇v|2dx
) 12
=C(2ζ + 1)m
(1− β)12
((2ζr + r)1−m−β
∫B+
2ζr+r(x+1 )
xβm+1|∇v|2dx
) 12
. (3.5.13)
In order to apply the assumption (3.5.3) on B+2ζr+r(x
+1 ) we must check that
B+2ζr+r(x
+1 ) ∈ B+(x0, R, θ2R). Recall the assumptions θ ≤ θ2
2θ1≤ θ2 ≤ 1
2,
x1 ∈ BθR(x0) and r ≤ θR. It follows that 2ζr+r ≤ 2θ1r ≤ θ2R and x+1 ∈ B+
θ2R(x0)
which, in turn, implies that B+2ζr+r(x
+1 ) ⊂ B+
θ2R(x+
1 ) ⊂ B+2θ2R
(x0) ⊂ B+R(x0) since
79
θ2 ≤ 12. Therefore, we may apply (3.5.3) and thus, in view of (3.5.13),
r−m∫Br(x1)
|∇v|dx ≤ C(2ζ + 1)m+ γ2
(1− β)12
a12 r
γ2 (3.5.14)
which is (3.5.6) with γ = γ2
and a = C(2ζ+1)m+γ2
(1−β)12
a12 . Recalling (3.5.7), we combine
(3.5.9) and (3.5.14) to see that (3.5.6) is satisfied for every Br(x1) ⊂ B2θR(x0)
with x1 ∈ BθR(x0) and r ≤ θR. Thus we may apply Lemma 3.5.0.1 to conclude
the proof.
3.5.1 From Decay Estimates to Holder continuity
We will require a method to pass from estimates which constitute improvements
of the monotonicity formulas given by lemmata 3.3.1.1 and 3.3.2.1, to estimates
of the form (3.5.3) and (3.5.4). Proving such estimates is our primary concern
hereafter. In particular, we will show that on any B+R(x0) with ∂0B+
R(x0) ⊂ O,
provided R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx is sufficiently small, the following holds;
for θ ≥ 2 and σ1, σ2 ∈ (0, 1) to be determined, if Br(y) ∈ Bθ(x0, R,R3
) and ρ ≤ r
we have
e|β|σ1ρym+1−ρ (σ1ρ)1−m
∫Bσρ(y)
|∇v|2dx ≤ 1
2e
|β|ρym+1−ρρ1−m
∫Bρ(y)
|∇v|2dx (3.5.15)
and if B+ρ (y) ∈ B+(x0, R,
R3
) and r ≤ ρ we have
(σ2ρ)1−m−β∫B+σ2ρ
(y)
|∇v|2dx ≤ 1
2ρ1−m−β
∫B+ρ (y)
|∇v|2dx. (3.5.16)
Once we know either of these estimates holds we can apply the following lemma,
possibly combined with a few additional arguments, to deduce that the corre-
sponding hypothesis in Lemma 3.5.0.2 holds.
Lemma 3.5.1.1 (Lemma 8.23 in [21]). Let f, h : (0, R0]→ R be non-decreasing
functions which satisfy
f(σr) ≤ τf(r) + h(r) (3.5.17)
for every r ≤ R0 and some fixed σ, τ ∈ (0, 1). There exists a C = C(σ, τ) > 0
and, for every µ ∈ (0, 1), there exists a γ = γ(σ, τ, µ) > 0 such that
f(r) ≤ C
(r
R0
)γf(R0) + h(rµR1−µ
0 ). (3.5.18)
80
The rest of this section is dedicated to showing minimisers of Eβ satisfy
(3.5.15) and (3.5.16) in any B+R(x0) with ∂0B+
R(x0) ⊂ O whenever the energy
R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx is small.
3.6 Interior Estimates for Holder continuity
Here we show, using the regularity theory of Schoen and Uhlenbeck [44] and
Schoen [45], that minimisers v ∈ W 1,2β (Rm+1
+ ;N) of Eβ relative to O satisfy
(3.5.15) from the preceeding section, and consequently (3.5.4) in Lemma 3.5.0.2,
provided the scaled energy R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx is sufficiently small. In
other words, we show that, given a half-ball B+R(x0) with ∂0B+
R(x0) ⊂ O and a
minimiser v with R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx small, if Br(y) ∈ Bθ(x0, R,
R3
)for
a θ ≥ 2 to be chosen, then we have
ρ1−m∫Bρ(y)
|∇v|2 dx ≤ C(ρr
)γr1−m
∫Br(y)
|∇v|2 dx (3.6.1)
for some γ ∈ (0, 1) and any ρ ≤ r. We recall the relevant theory from [44] and
[45] sections 1, 2 and 3, stating the results in our context with slightly different
notation.
Let Br(y) be the ball of radius r > 0 in Rm+1 centred at y. The Sobolev spaces,
considered in [44] and [45], that we need here are subsets of W 1,2(Br(y);Rn),
defined for maps with compact domain Br(y). It follows from theorem 3.18 in [1]
that W 1,2(Br(y);Rn) coincides with the space W 1,2(Br(y);Rn). Thus, as in [44]
and [45], we consider maps in the Sobolev spaces
W 1,2(Br(y);N) = v ∈ W 1,2(Br(y);Rn) : v(x) ∈ N for almost every x ∈ Br(y).
In order to prove (3.6.1) holds with a constant independent of the balls
Br(y) ∈ Bθ(x0, R,
R3
), we take advantage of the fact that on each Br(y) ∈ B
we may multiply the metric g(x), defined in (3.0.1), whose components are
gij(x) = xαm+1δij, by a constant factor, namely y−αm+1, to get a metric which is close
to the Euclidean metric in a sense which uniform across Br(y) ∈ Bθ(x0, R,
R3
).
The energy functionals corresponding to these metrics on a given Br(y) are mul-
tiples of the energies defined by (3.4.10) in Section 3.4. In particular, they have
the form
2y−βm+1EβBr(y)(v) =
∫Br(y)
(y−1m+1xm+1)β|∇v|2dx
for v ∈ W 1,2(Br(y);N). Critical points of this energy with respect to variations
81
of the independent variable are weakly harmonic maps as defined in Chapter 1.
From this definition we see that they satisfy (3.1.6), multiplied on both sides
by the factor 2y−βm+1, but with φ ∈ C∞0 (Br(y);Rn). In other words, a map v ∈W 1,2(Br(y);N) is weakly harmonic with respect to the metric y−αm+1g on Br(y) if∫
Br(y)
xβm+1 〈∇v,∇φ〉 dx =
∫Br(y)
xβm+1 〈φ,A(v)(∇v,∇v)〉 dx (3.6.2)
for every φ ∈ C∞0 (Br(y);Rn), where A is the second fundamental form of N .
We now discuss minimisers as defined in [44] section 1. Consider the compact
Riemannian manifold B1(0) with metric g. Recall the following notation. The
matrix representing g is gij for i, j = 1, . . . ,m+ 1, which has determinant det(g).
The inverse matrix then has components denoted gij for i, j = 1, . . . ,m + 1.
Furthermore, we write |∇v|g =∑m+1
i,j=1 gij⟨∂v∂xi, ∂v∂xj
⟩. For each g, the energy
functional on B1(0) is given by
Eg(v) =
∫B1(0)
|∇v|2g√
det(g)dx
where v ∈ W 1,2(B1(0);N). The definition of energy minimising corresponding to
Eg is as follows.
Definition 3.6.0.1. [[44] Section 1] Any v ∈ W 1,2(B1(0);N) is an Eg minimising
map if it satisfies Eg(v) ≤ Eg(w) for any w ∈ W 1,2(B1(0);N) with v − w ∈W 1,2
0 (B1(0);Rn).
We assume the metric g is C2 on B1(0). For Λ > 0 denote by EΛ the class of
functionals Eg on B1(0) with metric g such that gij(0) = δij and
∑i,j,k
∣∣∣∣∂gij∂xk(x)
∣∣∣∣ ≤ Λ.
If v is Eg-minimising with Eg ∈ EΛ then we say v ∈HΛ.
Schoen and Uhlenbeck [44] proved their ε-regularity theorem for minimisers of
functionals of the form Eg+F , where F gives rise to terms in the Euler-Lagrange
equations which are lower order than those coming from the energy. We state
the result of their theorem with F = 0.
Lemma 3.6.0.1 (Theorem 3.1 in [44]). There exists ε = ε(m,N) > 0 such that
if v ∈ HΛ, Λ ≤ ε and∫B1(0)|∇v|2 dx ≤ ε, then v is Holder continuous in B 1
2(0)
and
|v(x1)− v(x2)| ≤ C|x1 − x2|γ (3.6.3)
82
for constants C = C(m,N) and γ = γ(m,N) ∈ (0, 1) and every x1, x2 ∈ B 12(0).
Holder continuous weakly harmonic maps are smooth. This is the content of
the following lemma, proved by Schoen in [45].
Lemma 3.6.0.2 (Lemma 3.1 of [45]). Consider a ball Br(y) ⊂ Rm+1+ and suppose
v ∈ W 1,2(Br(y);N) is a weakly harmonic map which is Holder continuous on
Br(y). Then v is smooth on Br(y).
The final lemma we will need is from [45].
Lemma 3.6.0.3 (Theorem 2.2 of [45]). Let v ∈ C2(Br(0);N) and g be a Rie-
mannian metric on Br(0). Suppose v is harmonic with respect to g in Br(0) and
g satisfies ∣∣∣∣∂gij∂xk
∣∣∣∣ ≤ Λr−1 (3.6.4)
for i, j, k = 1, . . . ,m + 1 and Λ−1(δij) ≤ (gij) ≤ Λ(δij) in the sense of tensors,
where δij = 1 when i = j and δij = 0 otherwise. Then there exists an ε =
ε(Λ,m,N) such that if
r1−m∫Br(0)
|∇v|2g (det(g))12 dx ≤ ε
then
supB r
2(0)
|∇v|2g ≤ Cr−(1+m)
∫Br(0)
|∇v|2g (det(g))12 dx (3.6.5)
for a constant C = C(Λ,m,N).
We are now in a position to prove an estimate of the form (3.6.1).
Lemma 3.6.0.4. Let β ∈ (−1, 1) and v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of Eβ
relative to O. Suppose B+R(x0) is a half-ball with R ≤ 1 and ∂0B+
R(x0) ⊂ O. There
exists an ε0 = ε0(m,N) > 0, a θ = θ(m,N) ≥ 2 and a positive C = C(m,N)
such that if
R1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε0,
then
ρ1−m∫Bρ(y)
|∇v|2dx ≤ C(ρr
)γr1−m
∫Br(y)
|∇v|2dx (3.6.6)
on every Br(y) ∈ Bθ(x0, R,R3
) for 0 < ρ ≤ r and a γ = γ(m,N) ∈ (0, 1).
83
Proof. Let v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of Eβ relative to O and fix B+R(x0)
with ∂0B+R(x0) ⊂ O and R ≤ 1. Our strategy for the proof is as follows. We show
that provided the scaled energy R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx is sufficiently small,
v is Holder continuous on every Br(y) ∈ Bθ(x0, R,R3
) for a suitably chosen θ by
using Lemma 3.6.0.1. It then follows from Lemma 3.6.0.2 that on every such ball
v is smooth. Finally we show that we may apply Lemma 3.6.0.3 on every Br(y) ∈Bθ(x0, R,
R3
) if the energy R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx is sufficiently small. This
allows us to deduce decay estimates of the form (3.5.15) for the scaled energy
eρC|β|ρ1−m ∫Bρ(y)
xβm+1 |∇v|2 dx, where C = (ym+1 − ρ0)−1 for an appropriately
chosen ρ0 as in the interior monotonicity formula, Lemma 3.3.2.1, and ρ ≤ r.
Then we may apply Lemma 3.5.1.1 to conclude the statement of the lemma.
Suppose R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx ≤ ε0 for an ε0 > 0 to be chosen small.
First we will show, given this assumption, that the rescaled maps vr,y(x) =
v(rx+y), defined for x ∈ B1(0) and r and y corresponding to Br(y) ∈ Bθ(x0, R,R3
)
where θ is to be chosen, satisfy the assumptions of Lemma 3.6.0.1. In partic-
ular, by defining appropriate metrics on B1(0), we show that vr,y ∈ Hε and∫B1(0)|∇vr,y|2 ≤ ε where ε is the number from Lemma 3.6.0.1.
In order to show that vr,y ∈ Hε we must show that vr,y is a minimiser,
in the sense of 3.6.0.1, of an energy on B1(0). To see this we introduce the
following metrics on B1(0). Recall that the metric g, defined by (3.0.1), is given
in coordinates by gij(x) = xαm+1δij for i, j = 1, . . . ,m + 1. Define g on B1(0),
given in Euclidean coordinates by
gij(x) = δij
(1 +
r
ym+1
xm+1
)α. (3.6.7)
The energy corresponding to g is
Eg(v) =1
2
∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇v|2 dx
for maps v ∈ W 1,2(B1(0);Rn).
First we consider bounds for the metrics g and use these to choose a first
upper bound for θ. Notice that g and g are related as follows; for x ∈ B1(0) we
have
gij(x) = y−αm+1gij(ρx+ y).
We could consider bounds for these metrics, directly applying the fact that 12≤
1 + rym+1
xm+1 ≤ 32
since Br(y) ∈ Bθ(x0, R,R3
) for a θ ≥ 2 implies Br(y) ∈ B,
that is, 2r ≤ ym+1. However, we already have bounds for zβm+1 when z is in such
84
a Br(y), recall (3.4.3) in Section 3.4. Since β = α(m−1
2
)∈ (−1, 1) this yields
bounds for g. In particular, assuming x ∈ B1(0) and z ∈ Br(y) are related by
z = rx+ y, it follows from (3.4.3) that there exist constants c, C depending only
on m such that
c ≤ gij(x)m−1
2 = δij
(1 +
r
ym+1
xm+1
)β= δijy
−βm+1z
βm+1 = y−βm+1gij(z)
m−12 ≤ C
(3.6.8)
and
c ≤ gij(x) = y−αm+1gij(z) ≤ C. (3.6.9)
In addition to the preceding bounds for g, we consider bounds for its derivatives;
this gives a lower bound for θ. We find
∂
∂xi
(1 +
r
ym+1
xm+1
)α= 0
for i = 1, . . . ,m. Moreover, using (3.6.9) and the fact that 12≤ 1+ r
ym+1xm+1 ≤ 3
2,
we have ∣∣∣∣ ∂
∂xm+1
(1 +
r
ym+1
xm+1
)α∣∣∣∣ =r
ym+1
|α|
∣∣∣∣∣(
1 +r
ym+1
xm+1
)α−1∣∣∣∣∣
≤ Cr
ym+1
(3.6.10)
where C is chosen independently of α. Now suppose
r ≤ min
ym+1ε
(m+ 1)C,ym+1
2
(3.6.11)
where C is from (3.6.10) and ε is the constant given by Lemma 3.6.0.1. Then we
have ∑i,j,k
∣∣∣∣∂gij∂xk
∣∣∣∣ =m+1∑i=1
∣∣∣∣ ∂gii∂xm+1
∣∣∣∣ ≤ ε. (3.6.12)
Thus we choose
θ = θ(m,N) ≥ max
2,
(m+ 1)C
ε
(3.6.13)
and assume Br(y) ∈ Bθ(x0, R,R3
) henceforth, this implies (3.6.11) and hence
(3.6.12) holds on any such Br(y).
In order to conclude that vr,y ∈Hε for every Br(y) ∈ Bθ(x0, R,R3
), it remains
to show that if v ∈ W 1,2β (Rm+1
+ ;N) is a minimiser of Eβ in the sense of definition
3.2.0.1, then the map vr,y(x) = v(rx+ y) satisfies vr,y ∈ W 1,2(B1(0);N) and is an
85
energy minimiser of Eg in the sense of definition 3.6.0.1. A change of variables
gives∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇vr,y|2 dx = y−βm+1r
1−m∫Br(y)
xβm+1 |∇v|2 dx (3.6.14)
and∫B1(0)
(1 +
r
ym+1
xm+1
)β|vr,y|2 dx = y−βm+1r
−(1+m)
∫Br(y)
xβm+1 |v|2 dx. (3.6.15)
Thus, noting that as a consequence of Lemma 2.2.1.1 we have W 1,2(Rm+1+ ;N) →
W 1,2(Br(y);N) for every Br(y) with Br(y) ⊂ Rm+1+ , regardless of β ∈ (−1, 1),
using (3.6.8) we conclude from (3.6.14) and (3.6.15) that vr,y ∈ W 1,2(B1(0);N).
Now we show that vr,y is a minimiser of Eg in the sense of 3.6.0.1. Let
w ∈ W 1,2(B1(0);N) be such that vr,y − w ∈ W 1,20 (B1(0);Rn). We will use
this w to define a map in W 1,2β (Rm+1
+ ;N) to which we may apply definition
3.2.0.1. Notice that the map w(z) = w(z−yr
), for z ∈ Br(y), satisfies w ∈
W 1,2(Br(y);N); w can be approximated in W 1,2(B1(0);Rn) by a sequence in
C∞(B1(0);Rn) ∩W 1,2(B1(0);Rn) and composing the elements of this sequence
with the map z → z−yr
, we obtain a sequence in C∞(Br(y);Rn)∩W 1,2(Br(y);Rn)
which approximates w in W 1,2(Br(y);Rn). We extend the function w(z) =
w(z−yr
), for z ∈ Br(y), to Rm+1
+ by requiring w = v outside Br(y). It fol-
lows from the fact that w(z) = w(z−yr
)∈ N for almost every z ∈ Br(y) and
w(z) = v(z) ∈ N for almost every z ∈ Rm+1+ \Br(y), that w(z) ∈ N for almost
every z ∈ Rm+1+ . Thus, to conclude w ∈ W 1,2
β (Rm+1+ ;N), we need to construct a
sequence in D+(Rm+1+ ;Rn) which converges to w in W 1,2
β (Rm+1+ ;Rn). Let (φk)k∈N
be a sequence in C∞0 (Br(y);Rn) such that φk → w − v in W 1,20 (Br(y);Rn).
Without relabelling, we extend the domain of each φk to Rm+1+ by requiring
φk = 0 in Rm+1+ \Br(y). Then every φk ∈ C∞0 (Rm+1
+ ;Rn). Furthermore, let
(ψk)k∈N, with ψk ∈ D+(Rm+1+ ;Rn) for each k, be a sequence such that ψk → v
in W 1,2β (Rm+1
+ ;Rn). It follows that φk + ψk ∈ D+(Rm+1+ ;Rn) for every k. We
calculate∫Rm+1
+
xβm+1|∇(φk + ψk − (w − v + v)|2dx ≤ 2
∫Br(y)
xβm+1|∇φk −∇(w − v)|2dx
+ 2
∫Rm+1
+
xβm+1|∇ψk − v|2dx
and observe that the right hand side of the above tends to 0 as k → ∞. Thus
86
φk +ψk → w in W 1,2β (Rm+1
+ ;N) and w = v outside Br(y) so we may compare the
Eβ energies of w and v.
A change of variables gives∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇w|2 dx
= y−βm+1r1−m
∫Br(y)
zβm+1
∣∣∣∣∇(w(z − yr))∣∣∣∣2 dz (3.6.16)
and∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇(v(rx+ y))|2 dx = y−βm+1r
1−m∫Br(y)
zβm+1 |∇v|2 dz.
(3.6.17)
Since v is an energy minimiser for Eβ relative to O, w = v outside Br(y) and
v, w ∈ W 1,2β (Rm+1
+ ;N) we have∫Rm+1
+
zβm+1 |∇v|2 dz ≤
∫Rm+1
+
zβm+1 |∇w|2 dz. (3.6.18)
Then, as w = v outside Br(y), subtracting∫Rm+1
+ \Br(y)zβm+1 |∇v|
2 dz from (3.6.18)
gives ∫Br(y)
zβm+1 |∇v|2 dz ≤
∫Br(y)
zβm+1 |∇w|2 dz
and thus
y−βm+1r1−m
∫Br(y)
zβm+1 |∇v|2 dz ≤ y−βm+1r
1−m∫Br(y)
zβm+1
∣∣∣∣∇(w(z − yr))∣∣∣∣2 dz.
(3.6.19)
Hence, transforming both sides of (3.6.19) back to integrals over B1(0) using
(3.6.16) and (3.6.17), we find∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇vr,y|2 dx ≤
∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇w|2 dx
which shows that vr,y is a minimiser in the sense of definition 3.6.0.1 on B1(0).
We have shown so far that if Br(y) ∈ Bθ(x0, R,R3
), for θ as in (3.6.13), then
vr,y ∈Hε. Thus, as soon as∫B1(0)|∇vr,y|2 dx ≤ ε, Lemma 3.6.0.1 applies. We can,
however, guarantee this is true by applying Lemma 3.4.0.2. We have, changing
87
variables, ∫B1(0)
|∇vr,y|2 dx = r1−m∫Br(y)
|∇v|2 dx.
Then Lemma 3.4.0.2 yields
r1−m∫Br(y)
|∇v|2 dx ≤ CR1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx (3.6.20)
for a positive constant C = C(m). Hence, if we assume ε0 ≤ εC
where C is the
constant from (3.6.20), then∫B1(0)
|∇vr,y|2 dx ≤ CR1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx ≤ Cε0 = ε (3.6.21)
for every r, y corresponding to a ball Br(y) ∈ Bθ(x0, R,
R3
). Thus we choose
ε0 = ε0(m,N) = εC
. Consequently, vr,y ∈ Hε and satisfies the conditions of
lemma 3.6.0.1 for every such ball. An application of this lemma guarantees the
existence of a C = C(m,N) and a γ = γ(m,N) ∈ (0, 1) such that
|vr,y(x1)− vr,y(x2)| ≤ C|x1 − x2|γ (3.6.22)
for every x1, x2 ∈ B 12(0). Let z1, z2 ∈ Br(y). Then zi = rxi + y for some
x1, x2 ∈ B 12(0) and for i = 1, 2. It follows that
|v(z1)− v(z2)| = |vr,y(x1)− vr,y(x2)| ≤ C|x1 − x2|γ =C
rγ|z1 − z2|γ. (3.6.23)
Hence v is Holder continuous in every B r2(y) ∈ Bθ(x0, R,
R3
). Equivalently, v is
Holder continuous in every Br(y) ∈ B2θ(x0, R,R3
).
Since v is weakly harmonic in Rm+1+ , as defined in Chapter 1 and discussed
in Section 3.1.1, it is weakly harmonic on every Br(y) with Br(y) ⊂ Rm+1+ . Thus
it follows from Lemma 3.6.0.2 that v is smooth in each Br(y) ∈ B2θ(x0, R,R3
),
which holds if and only if each vr,y corresponding to such a Br(y) is smooth in
B1(0).
Our aim is now to apply Lemma 3.6.0.3 to yield decay estimates of the form
(3.5.15) for the energy of vr,y on B1(0). Let Λ = Λ(m) = maxε, c, c−1, C, C−1where c and C are the constants from (3.6.9) and ε is as above. It then follows
from (3.6.9) and (3.6.12) that the metrics g satisfy (3.6.4) and Λ−1(δij) ≤ (gij) ≤Λ(δij) as in Lemma 3.6.0.3 on B1(0) with this choice of Λ. Furthermore, as v is
88
smooth in Br(y), it is a smooth harmonic map with respect to g satisfying (3.6.2)
on this set. An integration by parts in (3.6.2) shows that
div(zβm+1∇v) + zβm+1A(v)(∇v,∇v) = 0 in Br(y).
We multiply this expression by y−βm+1 and apply the chain rule to see that vr,y
satisfies
div
((1 +
r
ym+1
xm+1
)β∇vr,y
)+
(1 +
r
ym+1
xm+1
)βA(vr,y)(∇vr,y,∇vr,y) = 0
in B1(0). This implies vr,y is a smooth harmonic map with respect to g in B1(0)
which satisfies the assumptions of Lemma 3.6.0.3. Thus the lemma gives an
ε1 = ε1(Λ,m,N) = ε1(m,N) such that if∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇vr,y|2dx ≤ ε1
then (3.6.5) applies. We combine (3.6.8) with (3.6.21) to see that∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇vr,y|2dx ≤ C
∫B1(0)
|∇vr,y|2dx ≤ Cε0. (3.6.24)
Thus, assuming ε0 ≤ ε1C
, it follows that we may apply Lemma 3.6.0.3. We do so,
recalling that 12≤ 1 + r
ym+1xm+1 ≤ 3
2and β = αm+1
2− α, and see that
r2 supB r
2(y)
(xm+1
ym+1
)β|∇v|2 = sup
B 12
(0)
(1 +
r
ym+1
xm+1
)β|∇vr,y|2
≤ C supB 1
2(0)
(1 +
r
ym+1
xm+1
)−α|∇vr,y|2
≤ C
∫B1(0)
(1 +
r
ym+1
xm+1
)β|∇vr,y|2dx
= r1−m∫Br(y)
(xm+1
ym+1
)β|∇v|2dx.
89
As a result, for any σ ∈ (0, 12] we have
(σr)1−m∫Bσr(y)
(xm+1
ym+1
)β|∇v|2dx ≤ C(σr)2r−(1+m)
∫Br(y)
(xm+1
ym+1
)β|∇v|2dx
= Cσ2r1−m∫Br(y)
(xm+1
ym+1
)β|∇v|2dx.
Choose σ such that σ2 ≤ 12C
and notice that for ρ ≤ r, the scaling factor e|β|ρ
ym+1−r
in Lemma 3.3.2.1 is increasing in ρ. It follows that
e|β|σr
ym+1−r (σr)1−m∫Bσr(y)
(xm+1
ym+1
)β|∇v|2dx
≤ 1
2e
|β|rym+1−r r1−m
∫Bσr(y)
(xm+1
ym+1
)β|∇v|2dx
on every Br(y) ∈ B2θ(x0, R,R3
). Furthermore, Lemma 3.3.2.1 implies that the
map ρ 7→ e|β|ρ
ym+1−r ρ1−m ∫Bρ(y)
(xm+1
ym+1
)β|∇v|2dx is non-decreasing in ρ for ρ ≤ r.
We may thus apply Lemma 3.5.1.1. We find
e|β|ρ
ym+1−r ρ1−m∫Bρ(y)
(xm+1
ym+1
)β|∇v|2dx
≤ C(ρr
)γe
|β|rym+1−r r1−m
∫Br(y)
(xm+1
ym+1
)β|∇v|2dx (3.6.25)
for every ρ ≤ r on every Br(y) ∈ B2θ(x0, R,R3
). Notice that
e|β|(r−ρ)ym+1−r = e
|β|(r−ym+1+ym+1−ρ)ym+1−r ≤ e
since ym+1 − r ≥ ym+1
2and ym+1 − ρ ≤ ym+1 which follows as Bρ(y) ⊂ Br(y) ∈
B2θ(x0, R,R3
). Using this fact, combined with (3.4.3) and (3.6.25), we deduce that
ρ1−m∫Bρ(y)
|∇v|2dx ≤ C(ρr
)γr1−m
∫Br(y)
|∇v|2dx
on every Br(y) ∈ B2θ(x0, R,R3
) for 0 < ρ ≤ r. This concludes the proof.
This lemma gives us a condition on the energy Eβ such that minimisers es-
sentially satisfy (3.5.4) in Lemma 3.5.0.2 and comprises the first milestone in the
proof of our ε-regularity theorem.
90
3.7 An Overview of the Boundary Estimates for
Holder Continuity
Our strategy to prove that energy minimisers satisfy (3.5.3) in Lemma 3.5.0.2,
which will complete our proof of Holder continuity of minimisers of Eβ relative
to O, consists of proving three main estimates. First we construct a comparison
function w which satisfies
σ1−m−β∫B+σ (y)
xβm+1|∇w|2dx
≤ ερ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx+1
ερ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx
(3.7.1)
where ε ∈ (0, 1), σ ∈(
3ρ4, ρ)
and y ∈ ∂Rm+1+ . This function is constructed in
such a way that we may compare its energy with the energy of a minimiser of
Eβ relative to O. If v is such a minimising harmonic map then we will show that
as a result of the monotonicity formula, Lemma 3.3.1.1, and the assumption of
small energy, we have good control over the first term on the right hand side of
(3.7.1). In order to control the other term we prove an improved version of the
Poincare inequality of the form
(θρ)−(1+m+β)
∫B+θρ(y)
xβm+1|v − vB+ρ (y),β|
2dx ≤ δρ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx,
(3.7.2)
where θ ∈ (0, 1) depends on δ in addition to some other factors.
Combining (3.7.1) and (3.7.2) we prove an energy decay estimate on concentric
half-balls. In particular we show
(θ0ρ)1−m−β∫B+θ0ρ
(y)
xβm+1|∇v|2dx ≤ 1
2ρ1−m−β
∫B+ρ (y)
xβm+1|∇v|2dx (3.7.3)
for a θ0 ∈ (0, 14). This allows us to show that a minimising harmonic map satisfies
(3.5.3) in Lemma 3.5.0.2 as we require. The combination of this fact with Lemma
3.6.0.4 will allow us to conclude that energy minimisers are Holder continuous.
91
3.8 A Modified Lemma of Luckhaus
In order to show that (3.7.1) holds we first prove a modified version of a lemma of
Luckhaus, Lemma 3 in [29], as presented in Lemma 1 Section 2.6 of [46]. This is
the main step in constructing the comparison function w as described in Section
3.7. A consequence of the lemma we prove, and an analogue of Corollary 1 in
Section 2.7 of [46], is an estimate of the form (3.7.1).
Let Sm ⊂ Rm+1 denote the m dimensional unit sphere, centred at the origin
and equipped with the metric induced by the Euclidean metric on Rm+1. Define
Sm+ = Sm ∩ Rm+1+ with the metric induced from Sm. We let ω denote a point in
Sm ⊂ Rm+1 or Sm+ ⊂ Rm+1+ and write dω for the volume element corresponding
to the induced metric. We continue to use the notation ∂+Ω = ∂Ω ∩ Rm+1+ for
Ω ⊂ Rm+1 and Qr(y) = x ∈ Rm+1 : |xi− yi| < r, i = 1, . . . ,m+ 1 for y ∈ Rm+1.
We also write Q+r (y) = Qr(y) ∩ Rm+1
+ for y ∈ Rm × 0.In order to state the modified Luckhaus lemma precisely we introduce the
notion of a Sobolev space for functions whose domain is either Sm or Sm+ . There
are several possible definitions of this space and we have chosen the one most
congruous with our methodology. The role the following Sobolev space plays will
become evident during the proof of the lemma, it is connected with the notion
of homogeneous degree zero extensions of functions which we discuss below in
Section 3.8.1.
Definition 3.8.0.1. Let ε > 0 and ρ > 0. Suppose S = ρSm and Vε =
Bρ+ε(0)\Bρ−ε(0) or S = ρSm+ and Vε = B+ρ+ε(0)\B+
ρ−ε(0). An element v ∈L2β(S;Rn) is said to be in W 1,2
β (S;Rn) if the map v(ρ x|x|) ∈ W 1,2
β (Vε;Rn) for
some ε > 0. An element v ∈ L2β(S × [a, b];Rn), with a < b real numbers, is said
to be in W 1,2β (S × [a, b];Rn) if the map v(ρ x
|x| , s) ∈ W1,2β (Vε × [a, b];Rn) for some
ε > 0. If N ⊂ Rn is compact, we say v is in W 1,2β (S;N) or W 1,2
β (S × [a, b];N) if
v is in W 1,2β (S;Rn) or W 1,2
β (S × [a, b];Rn) respectively and v(x) ∈ N for almost
every x ∈ S.
Lemma 3.8.0.1. Let m + 1 ≥ 3 and β ∈ (−1, 1). Let N be a compact subset
of Rn and suppose u, v ∈ W 1,2β (Sm+ ;N). Then for all ε ∈ (0, 1) there is a w ∈
W 1,2β (Sm+ × [0, ε];Rn) such that w agrees with u on Sm+ × 0 and v on Sm+ × ε
in the sense of traces and which satisfies the following. Let D be the gradient on
92
Sm+ × [0, ε] and D the gradient on Sm+ . Then w = w(ω, s) satisfies∫Sm+×[0,ε]
ωβm+1|Dw|2dωds
≤ C1ε
∫Sm+ωβm+1
(|Du|2 + |Dv|2
)dω +
C1
ε
∫Sm+ωβm+1|u− v|2dω
(3.8.1)
where C1 = C1(m,β). Furthermore, w satisfies
dist2(w(ω, s), N)
≤ C2
εm+β2
+|β|2
(∫Sm+ωβm+1
(|Du|2 + |Dv|2
)dω
) 1q(∫
Sm+ωβm+1|u− v|2dω
)1− 1q
+C2
εm+1+β2
+|β|2
∫Sm+ωβm+1|u− v|2dω
(3.8.2)
for almost every (ω, s) ∈ Sm+ × [0, ε] where C2 = C2(m,β) and q satisfies the
following. If β ∈ (−1, 0] then (3.8.2) holds for q = 2 and if β ∈ (0, 1) then
(3.8.2) holds with either q = 2 or q = p for any fixed p ∈ (1, 21+β
).
Our proof of Lemma 3.8.0.1 follows the proof, given in section 2.12.2 of [46],
of lemma 1 in section 2.6 of [46]. There are several preliminary results we will
need for the proof and we proceed to discuss these.
3.8.1 Homogeneous Degree Zero Extension
We will use homogeneous degree zero extension to define functions on the interior
of sets given their boundary values. Our primary use of this technique will be
to inductively define functions on cubes of dimension 2, . . . ,m+ 2; we start with
a function defined on the l-dimensional boundary of an l + 1 dimensional cube,
for l = 2, . . . ,m + 1, and use homogeneous degree zero extension to define a
function on the whole cube. The benefit of this method of extension is that
certain bounds obtained on boundary of the cubes are preserved when the map
is extended into the interior. Here we discuss properties of maps which are
homogeneous of degree zero with a view to applying the aforementioned method
of homogeneous extension in the proof of Lemma 3.8.0.1.
The distributional derivative of a function v, which is homogeneous of degree
zero with respect to a point y ∈ Rl+1, can be expressed in terms of the derivative
of the restriction of v to the boundaries of balls, half-balls, cubes or half-cubes
centred at y, depending on the circumstances. Let Bρ = Bl+1ρ (y) and Qρ =
93
Ql+1ρ (y). Furthermore, for y ∈ Rl × 0, we write B+
ρ = Bρ ∩ Rl+1+ and Q+
ρ =
Qρ ∩ Rl+1+ and recall the notation ∂+Ω = ∂Ω ∩ Rl+1
+ for Ω ⊂ Rl+1.
We regard Bρ, Qρ, ∂Bρ and ∂Qρ as submanifolds of Rl+1 with metrics induced
by the Euclidean metric on Rl+1. These are then submanifolds of at least Lipschitz
regularity and thus admit gradient operators.
To further facilitate our discussion, we introduce the following notation in
Rl+1. Let r = |x| be the radial variable and suppose ω ∈ Sl, the unit sphere
in Rl+1 centred at 0. Furthermore, let dω denote the volume form on Sl with
respect to the metric induced from Rl+1.
We will perform the following calculations on B1 = B and Q1 = Q, centred
at y = 0, the inequalities on Bρ and Qρ then follow by rescaling. Suppose v is
homogeneous of degree zero with respect to 0. We now discuss the relationship
between the gradient of v on B with the gradient of v|Sl on Sl. We denote
a gradient taken on Sl by ∇ and for simplicity we will also denote v|Sl by v.
Observe that v(x) = v(rω) = v(ω) for ω(x) = xr. It follows that ∂v
∂r≡ 0 and
hence we have the identification
∇v = ∇v (3.8.3)
on Sl. Furthermore, we calculate
∇vi(x) = ∇ (vi (ω(x)))
=1
|x|∇vi(ω(x))− x
|x|2∂vi∂r
(ω(x))
=1
|x|∇vi(ω(x))
=1
|x|∇vi(ω(x)) (3.8.4)
for i = 1, . . . , n and x ∈ Rl+1\0.We observe a similar relationship between the gradient of v on Q and the
gradient of its restriction to ∂Q. Let ζ ∈ ∂Q and define ζ(x) = xmaxj=1,...,l+1|xj |
.
Let x ∈ Rl+1\0 and suppose maxj=1,...,l+1|xj| = |xk|. Since v is homogeneous
of degree zero with respect to 0 we have v(x) = v(ζ(x)). Thus, for i 6= k we
calculate
∂v
∂xi(x) =
∂
∂xi(v(ζ(x)))
=∂v
∂xi(ζ(x))
1
|xk|. (3.8.5)
94
When i = k we find
∂v
∂xk(x) = −sgn(xk)
l+1∑i=1i 6=k
∂v
∂xi(ζ(x))
xi|xk|2
. (3.8.6)
Let ∇ denote the gradient on the faces F of ∂Q. It follows from (3.8.5) and
(3.8.6) that
|∇v| ≤ C|∇v|, (3.8.7)
on every face F of ∂Q, where C = C(l).
Now we show that if v is homogeneous of degree zero with respect to 0 then
integrals of the gradient of v over Qρ or Q+ρ can be expressed in terms of integrals
of the gradient on the respective boundaries. We describe the details of this
relationship on half-cubes Q+ρ and then state the corresponding result for cubes
Qρ.
Henceforth we denote any l dimensional face of Q+ρ which has no edges in
the l + 1 direction by F l. We denote the collection of all such faces, excluding
those which do not intersect Rl+1+ , by F l. Furthermore, we write F l
l+1 for an l
dimensional face of Q+ρ that has edges in the l+1 direction and call the collection
of these faces F ll+1. Then
∂+Q+ρ =
⋃F lF l ∪
⋃F ll+1
F ll+1.
In the proof of Lemma 3.8.0.1 we will regard the half-cubes Q+ρ as subsets
(submanifolds) of Rm+1+ ×R. To facilitate the compatibility of our considerations
in the proof of the lemma with the discussion here, we consider the following
integrals with respect to the l+ 1 dimensional Hausdorff measure dHl+1 on Rl+1.
First we consider Q+ = Q+1 . The general case will follow by rescaling. We
transform the integral of xβl+1|∇v|2 over Q+ into an integral over B+ = B+1 . Recall
the bi-Lipschitz, piecewise C1 map Φy : Rl+1 → Rl+1 with bi-Lipschitz, piecewise
C1 inverse Φ−1y : Rl+1 → Rl+1 defined in section 2.3.1. When y = 0, this map
is given by Φ0(x) = |xk| x|x| if x 6= 0, where |xk| = maxj=1...,l+1 |xj|, and satisfies
Φ0(0) = 0. Hence Φ0(Q+) = B+. Moreover, as shown in Section 2.3.1, Φ0 is a
uniform dµβ-equivalence from Q+ to B+ in the sense of (2.3.1) and (2.3.2). Thus
we have ∫Q+
xβl+1|∇v|2dHl+1 ≤ C
∫B+
xβl+1|∇v(Φ−10 (x))|2dHl+1(x). (3.8.8)
95
Moreover, it follows from (3.8.4) that
|∇v(Φ−10 (x))| = 1
|Φ−10 (x)|
|∇v(ω(Φ−10 (x)))| (3.8.9)
for every x ∈ B+. By definition, |Φ−10 (x)| ≥ C|x| for every x ∈ B+ and a
constant C = C(m). For the remainder of this section C will always denote such
a constant and we do not distinguish different C. Notice that ω(Φ−10 (x)) = ω(x)
and hence, in view of (3.8.9), we deduce
|∇v(Φ−10 (x))| ≤ C
|x||∇v(ω(x))|. (3.8.10)
It follows that∫B+
xβl+1|∇v(Φ−10 (x))|2dHl+1(x) ≤ C
∫B+
1
|x|2xβl+1|∇v(ω(x))|2dHl+1(x).
(3.8.11)
Now we change variables to r and ω. Recall the notation dω, which we now use
for the volume form with respect to the metric on ∂+B+ = Sl+1+ induced from
the Euclidean metric on Rl+1. We calculate∫B+
1
|x|2xβl+1|∇v(ω(x))|2dHl+1(x) =
∫ 1
0
1
r2
∫Sl+rβωβl+1|∇v(ω)|2rldωdr
=
∫ 1
0
rl−2+β
∫Sl+ωβl+1|∇v(ω)|2dωdr
=1
l − 1 + β
∫Sl+ωβl+1|∇v|
2dω. (3.8.12)
Next we transform the right hand side of (3.8.12) into an integral over ∂+Q+, in
terms of the gradient on ∂+Q+, via change of variables using the map Φ0. Notice
that Φ0(x) = ω(x) for all x ∈ ∂+Q+. Hence, in view of (3.8.4) we have
|∇v(Φ0(x))| = |∇v(ω(x))| = |x||∇v(x)| (3.8.13)
for all x ∈ ∂+Q+. For such x we also have |x| ≤ C and thus, using (3.8.13) and
(3.8.7), we see that
|∇v(Φ0(x))| ≤ C|∇v(x)| (3.8.14)
for every x ∈ ∂+Q+, where we have now used ∇ to denote the gradient on ∂+Q+.
Hence, combining (3.8.14) with the fact that Φ0 is a uniform dµβ-equivalence
96
between ∂+Q+ and ∂+B+, we change variables in (3.8.12). This yields∫∂+B+
ωβl+1|∇v(ω)|2dω ≤ C
∫∂+Q+
xβl+1|∇v(Φ0(x))|2dHl(x)
≤ C
∫∂+Q+
xβl+1|∇v|2dHl. (3.8.15)
Combining (3.8.8), (3.8.11), (3.8.12) and (3.8.15) we have∫Q+
xβl+1|∇v|2dHl+1 ≤ C
∫∂+Q+
xβl+1|∇v|2dHl
= C∑F l
∫F lxβl+1|∇v|
2dHl
+ C∑F ll+1
∫F ll+1
xβl+1|∇v|2dHl, (3.8.16)
where C depends on l and β. This is the estimate we seek for Q+. We now rescale
to Q+ρ where Qρ has centre y ∈ ∂Rl+1
+ . Suppose v is homogeneous of degree zero
with respect to such a y. Then v(x) = v(ρx + y) is homogeneous of degree zero
with respect to 0. We apply (3.8.16) to v on Q+ to see that∫Q+ρ
xβl+1|∇v|2dHl+1 ≤ Cρ
∫∂+Q+
ρ
xβl+1|∇v|2dHl
= Cρ∑F l
∫F lxβl+1|∇v|
2dHl
+ Cρ∑F ll+1
∫F ll+1
xβl+1|∇v|2dHl, (3.8.17)
where ∇ is now the gradient on ∂+Q+ρ .
A similar estimate holds on cubes Qρ = Ql+1ρ (y) ⊂ Rl+1 with the Euclidean
metric. In this case, let F denote any l dimensional face of Qρ and write F =
F l ∪ F ll+1 for the collection of all such faces. If v is homogeneous of degree zero
with respect to y then∫Qρ
|∇v|2dHl+1 ≤ Cρ
∫∂Qρ
|∇v|2dHl
= Cρ∑F
∫F
|∇v|2dHl, (3.8.18)
which follows either from arguments analogous to those leading to (3.8.17) or
directly from estimate (13) in the proof of the Luckhaus lemma as given in [46]
97
section 2.12.2 after rescaling and translation.
Next we recall some properties of representations of functions in W 1,p.
3.8.2 Absolute Continuity Properties of Functions in W 1,2β
We recall the discussion in [46] section 2.12.1 pertaining to some absolute conti-
nuity properties of W 1,p functions. Let Hs denote the s-dimensional Hausdorff
measure with respect to the Euclidean metric. Consider a rectangle Q ⊂ Rm+1+ of
the form Q = [a1, b1]× . . .× [am+1, bm+1] where ai < bi. Suppose v ∈ W 1,2β (Q;Rn)
with β ∈ (−1, 1). If am+1 > 0 then Q ⊂ Rm+1+ and v|Q ∈ W 1,2(Q;Rn) by
Lemma 2.2.1.2. If am+1 = 0 then v|Q ∈ W 1,2(Q;Rn) if β < 0 by Lemma
2.2.1.3 and v|Q ∈ W 1,p(Q;Rn) for p ∈ (1, 21+β
) if β > 0 by Lemma 2.2.1.4.
Hence, by lemma 3.1.1 and theorem 3.1.8 in [32], if am+1 ≥ 0, we may infer
the existence of a representative v of v such that, for each i = 1, . . . ,m + 1,
v(x1, . . . , xi−1, xi, xi+1, . . . , xm+1) is an absolutely continuous function of xi for
almost all fixed values of x1, . . . , xi−1, xi+1, . . . , xm+1 with respect to the m di-
mensional Hausdorff measure Hm on [a1, b1]× . . .× [ai−1, bi−1]× [ai+1, bi+1]× . . .×[am+1, bm+1]. The classical partial derivatives ∂v
∂xiagree almost everywhere with
the weak derivatives ∂v∂xi
. Furthermore, for any closed subset N of Rn, if v(x) ∈ Nfor almost every x then it is possible to choose v(x) ∈ N for every x ∈ Rm+1
+ .
3.8.3 Embeddings of Absolutely Continuous Functions on
Line Segments
A crucial aspect of the construction of the function w as described in Lemma
3.8.0.1, are bounds on the supremum of functions which are absolutely continuous
along line segments parallel to the coordinate axis. More specifically, we are
interested in bounds given in terms of the L2 norm of these functions and their
derivatives, either with respect to the Lebesgue measure or the Lebesgue measure
with weight xβm+1.
Let Ej, for j = 1, . . . ,m + 1, denote a 1 dimensional line segment of length
r ≤ 1, which is parallel to the xj coordinate axis and satisfies Ej ⊂ Rm×(0, 1]. Let
v : Rm+1+ → Rn be an absolutely continuous function on Ej and let ∂jv denote the
weak partial derivative of v with respect to the jth variable for j = 1, . . . ,m+ 1.
Suppose v and ∂jv are square integrable on Ej. Integrating over Ej and using
98
Holder’s inequality we have
supEj
|v|2 ≤∫Ej
|∂j|v|2|dxj +1
r
∫Ej
|v|2dxj
≤ 2
(∫Ej
|∂jv|2dxj
) 12(∫
Ej
|v|2dxj
) 12
+1
r
∫Ej
|v|2dxj (3.8.19)
for j = 1, . . . ,m+ 1.
We will require estimates of in terms of xβm+1dxj instead of the Lebesgue
measure, where it is understood that for j = 1, . . . ,m the factor xβm+1 is evaluated
on Ej. When j = m + 1 we consider line segments depending on the sign of β.
Suppose that Em+1 can be identified with [a, b] where 0 ≤ a < b ≤ 1 and
b − a = r. In addition, assume v and ∂jv are square xβm+1dxj-integrable on Ej.
Whenever (inf(xβm+1))−1 is finite, the required estimates follow from (3.8.19) for
every j = 1, . . . ,m + 1; if β ∈ (−1, 0] and 0 ≤ a < b ≤ 1 or if β ∈ (0, 1) and
0 < a < b ≤ 1 then v and ∂jv are square integrable on Ej and, in view of (3.8.19),
we have
supEj
|v|2 ≤ 2
infEj(xβm+1)
(∫Ej
xβm+1|∂jv|2dxj
) 12(∫
Ej
xβm+1|v|2dxj
) 12
+1
infEj(xβm+1)r
∫Ej
xβm+1|v|2dxj. (3.8.20)
Now let β ∈ (0, 1) and consider Em+1 = (0, r]. In this case we can prove a similar
but slightly weaker version of (3.8.20). Suppose that v and ∂m+1v are square
xβm+1dxm+1-integrable. Then they are p-dxm+1-integrable for every p ∈ (1, 21+β
).
We integrate along Em+1 to see that
supEm+1
|v|p ≤∫Em+1
|∂m+1|v|p|dxm+1 +1
r
∫Em+1
|v|pdxm+1. (3.8.21)
We consider the terms on the right hand side separately. It follows that∫Em+1
|∂m+1|v|p|dxm+1 ≤ p
∫Em+1
|∂m+1v||v|p−1dxm+1. (3.8.22)
99
An application of Holder’s inequality yields∫Em+1
|∂m+1v||v|p−1dxm+1
=
∫Em+1
x−β
2m+1x
β2m+1|∂m+1v||v|p−1dxm+1
≤(∫
Em+1
xβm+1|∂m+1v|2dxm+1
) 12(∫
Em+1
x−βm+1|v|2(p−1)dxm+1
) 12
. (3.8.23)
Then, since 1p−1
is greater than 1 (with conjugate exponent q = 12−p), using
Holder’s inequality again we see that∫Em+1
x−βm+1|v|2(p−1)dxm+1
=
∫Em+1
x−βm+1x−β(p−1)m+1 x
β(p−1)m+1 |v|2(p−1)dxm+1
≤(∫
Em+1
x− βp
2−pm+1 dxm+1
)2−p(∫Em+1
xβm+1|v|2dxm+1
)p−1
=
(2− p
2− p− βp
)2−p
r2−p−βp(∫
Em+1
xβm+1|v|2dxm+1
)p−1
(3.8.24)
provided that β < 2p− 1 = 2−p
por equivalently p < 2
1+βwhich is true by assump-
tion. Combining (3.8.22), (3.8.23) and (3.8.24) gives∫Em+1
|∂m+1|v|p|dxm+1
≤ Cr1− p2−βp
2
(∫Em+1
xβm+1|∂m+1v|2dxm+1
) 12(∫
Em+1
xβm+1|v|2dxm+1
) p−12
(3.8.25)
where C = p(
2−p2−p−βp
)1− p2
= C(β) since p is chosen depending on β. Now we
consider the other term in (3.8.21). Note that 2p≥ 1 with conjugate exponent
22−p . Applying Holder’s inequality we see that∫
Em+1
|v|pdxm+1 =
∫Em+1
x−βp
2m+1x
βp2m+1|v|pdxm+1
≤(∫
Em+1
x− βp
2−pm+1 dxm+1
) 2−p2(∫
Em+1
xβm+1|v|2dxm+1
) p2
= Cr1− p2−βp
2
(∫Em+1
xβm+1|v|2dxm+1
) p2
(3.8.26)
100
where C = C(β) =(
2−p2−p−βp
)1− p2. We combine (3.8.21) with (3.8.25) and (3.8.26)
to see that
supEm+1
|v|p
≤ Cr1− p2−βp
2
(∫Em+1
xβm+1|∂m+1v|2dxm+1
) 12(∫
Em+1
xβm+1|v|2dxm+1
) p−12
+ Cr−p2−βp
2
(∫Em+1
xβm+1|v|2dxm+1
) p2
. (3.8.27)
In view of (3.8.27), we calculate
supEm+1
|v|2
=
(supEm+1
|v|p) 2
p
≤ Cr2p−1−β
(∫Em+1
xβm+1|∂m+1v|2dxm+1
) 1p(∫
Em+1
xβm+1|v|2dxm+1
)1− 1p
+ Cr−(1+β)
∫Em+1
xβm+1|v|2dxm+1, (3.8.28)
where C = C(β) = p2p
(2−p
2−p−βp
) 2p−1
.
Remark 3.8.3.1. The estimates (3.8.20) and (3.8.28) are sufficient to prove the
Sobolev embeddings W 1,2β (0, r) → L∞[0, r] for β ∈ (0, 1) and r ≤ 1. Similarly
(3.8.19) corresponds to the Sobolev embedding W 1,2(a, b) → L∞[a, b] for a < b.
3.8.4 Proof of Lemma 3.8.0.1
Proof of Lemma 3.8.0.1. We follow the proof, given in Section 2.12.2 of [46], of
Lemma 1 in Section 2.6 of [46]. Throughout, C denotes a constant only depending
on m and β. First we extend u and v to Rm+1 in such a way that we can
bound certain integrals of the extensions and their gradients on Q+1 (0) in terms
of corresponding integrals involving u, v and their gradients on Sm+ .
Suppose u, v ∈ W 1,2β (Sm+ ;N). We reflect u and v evenly in Rm × 0, without
relabelling, to get u, v ∈ W 1,2β (Sm;N). We choose extensions of u and v to
Rm+1\0 which are homogeneous of degree zero with respect to the origin. Then
we choose representatives of these extensions which satisfy the absolute continuity
properties described in Section 3.8.2 on Q1(0). We will denote the representatives
of the extensions of u and v by u and v respectively. Then u(ρω) = u(ω),
101
v(ρω) = v(ω) for almost every ρ > 0 and ω ∈ Sm. An application of (3.8.8),
(3.8.11), (3.8.12) and (3.8.3) in Section 3.8.1 gives∫Q+
1 (0)
xβm+1
(|∇u|2 + |∇v|2
)dx ≤ C
∫Sm+ωβm+1
(|Du|2 + |Dv|2
)dω, (3.8.29)
where D is the gradient on Sm+ and ∇ is the gradient on Rm+1+ . In a similar way
we find that ∫Q+
1 (0)
xβm+1|u− v|2dx ≤ C
∫Sm+ωβm+1|u− v|2dω. (3.8.30)
To construct w as required in the lemma, we first construct a map on Q+14
(0)×[0, ε] whose gradient and distance from N can be bounded using combinations
of the expressions on the right hand sides of (3.8.29) and (3.8.30). In order to
achieve this we divide Q1(0) into small congruent sub-cubes of side length ε. We
bound the sum, taken over all l-dimensional faces in this collection of cubes, of
the integrals of a non-negative measurable function f over the faces in terms
of the integral of f over Q1(0) for l = 0, . . . ,m + 1. We will then apply these
estimates to the functions |∇u|+ |∇v|2 and |u− v|2.
More precisely, let ε ∈ (0, 18) and define the closed rectangles Qi,ε = [i1ε, (i1 +
1)ε] × . . . × [im+1ε, (im+1 + 1)ε] for i = (i1, . . . , im+1) ∈ Zm+1. Fix ε ∈ (0, 18)
arbitrarily henceforth. Let F l denote any l-dimensional face of a cube with no
edges in the xm+1 direction and F lm+1 any l-dimensional face with edges in the
xm+1 direction. We define
Q = Qi,ε : i ∈ Zm+1, Qi,ε ⊂ Q 12(0),
F li =F l faces of Qi,ε
,
and
F li,m+1 =F lm+1 faces of Qi,ε
.
In addition, we write x + F li to denote the collection of the translations of all
faces in F li by x ∈ Rm+1 and x + F li,m+1 for the collection of the translations of
all faces in F li,m+1 by x ∈ Rm+1.
Consider a non-negative, measurable function f : Q1(0) → R which is even
with respect to the hyperplane Rm × 0. Invoking [46] Section 2.12.2 estimate
(3), which is a consequence of repeated applications of (2.3.35) for the Lebesgue
measure and Fubini’s theorem, we see that for every K ≥ 1 there exists a set
102
P ⊂ Q0,ε of measure |P | ≤ Cεm+1
K, with C = C(m), such that for all y ∈ Q0,ε\P
and l ∈ 0, . . . ,m+ 1 we have
εm+1−l∑
i:Qi,ε∈Q
∑y+F li
∫F lfdHl +
∑y+F li,m+1
∫F lm+1
fdHl
≤ K
∫Q1(0)
fdx
≤ 2K
∫Q+
1 (0)
fdx.
(3.8.31)
Our aim is to eventually construct a function on Sm+ and hence we discard the in-
tegrals in (3.8.31) taken over any faces which do not intersect Rm+1+ . In particular,
since f is non negative, we find
εm+1−l∑
i:Qi,ε∈Qim+1≥−1
∑y+F li
∫F l∩Rm+1
+
fdHl +∑
y+F li,m+1
∫F lm+1∩R
m+1+
fdHl
≤ 2K
∫Q+
1 (0)
fdx. (3.8.32)
We want to apply (3.8.32) to the squared norms of the gradients (on Rm+1)
of, and difference between, u and v. Since we chose u and v with the absolute
continuity properties described in Section 3.8.2 on Q1(0) it follows that for almost
every x ∈ Q0,ε, with respect to the m + 1-dimensional Lebesgue measure, all of
the functions u, v,∇u,∇v are Hl almost everywhere defined on each of the l-
dimensional faces of x + Qi,ε for Qi,ε ∈ Q and l = 1, . . . ,m + 1. Moreover, the
gradients of u and v on any l-dimensional face of x + Qi,ε coincide Hl almost
everywhere with the tangential parts of ∇u and ∇v respectively. Thus we may
choose x = a ∈ Q0,ε such that these properties hold and, provided we choose
K (depending on m) sufficiently large in (3.8.32), such that am+1 ≥ ε2
and such
that we may apply (3.8.32) simultaneously for f(x) = |xm+1|β f(x) with f(x) =
|u(x)− v(x)|2 and f(x) = |∇u(x)|2 + |∇v(x)|2 (where ∇ is the gradient on Rm+1).
103
In particular, we have
εm+1−l∑
i:Qi,ε∈Qim+1≥−1
∑a+F li
∫F l∩Rm+1
+
xβm+1fdHl
+ εm+1−l∑
i:Qi,ε∈Qim+1≥−1
∑
a+F li,m+1
∫F lm+1∩R
m+1+
xβm+1fdHl
≤ C
∫Q+
1 (0)
xβm+1fdx. (3.8.33)
Since am+1 ≥ ε2
we assume hereafter that am+1 = cε for c ∈[
12, 1].
Now we begin the construction of w by defining a map on the one dimensional
faces of every Q×[0, ε] where Q = (a+Qi,ε)∩Rm+1+ with Qi,ε ∈ Q and im+1 ≥ −1.
We show that the map we define satisfies bounds sufficient for us to apply (3.8.33).
Let Ej denote a one dimensional face of Q parallel to the jth coordinate axis
for j = 1, . . . ,m + 1. Define w(x, 0) = u(x) on Q × 0 and w(x, ε) = v(x)
on Q × ε. We extend w to Ej × [0, ε] by linear interpolation. That is, let
w(x, s) = (1− sε)u(x) + s
εv(x) for x ∈ Ej and s ∈ [0, ε].
The distance of w(x, s) fromN can be bounded as follows. Since u(Rm+1+ ) ⊂ N
by definition, it follows that
dist2(w(x, s), N) =
(infy∈N|y −
((1− s
ε)u(x) +
s
εv(x)
)|)2
≤
(inf
z∈Q+1 (0)|u(z)− u(x) +
s
ε(u(x)− v(x))|
)2
≤ |sε
(u(x)− v(x))|2
≤ maxj=1,...,m+1 supEj
|u− v|2 (3.8.34)
for x in the 1-dimensional edges of Q and s ∈ [0, ε]. We give estimates for
supEj |u− v|2 by using the embeddings of absolutely continuous functions along
line segments described in Section 3.8.3 which vary accordingly depending on
whether infEj(xβm+1) is finite or not.
First we determine when infEj(xβm+1) < ∞. We see that this is satisfied on
every Ej, with j = 1, . . . ,m+ 1, of any Q = (a+Qi,ε) ∩Rm+1+ with im+1 ≥ 0. In
this case, since am+1 ≥ ε2, we have ε
2≤ xm+1 ≤ 1 for x in any such Q. Hence,
on any edge Ej, with j = 1, . . . ,m + 1, of a Q with im+1 ≥ 0, if β ∈ (−1, 0]
then infEj(xβm+1) ≥ 1, and if β ∈ (0, 1) then infEj(x
βm+1) ≥ εβ
2β≥ εβ
2. The
104
same bounds hold on any Ej, with j = 1, . . . ,m, in a Q = (a + Qi,ε) ∩ Rm+1+
with im+1 = −1 because such a cube has no edges in Rm × 0 by definition.
Furthermore, if β ∈ (−1, 0] then on any such Q we still have infEm+1(xβm+1) ≥ 1.
Combining the previous considerations we deduce that, with the exception of the
edges Em+1 belonging to a Q with im+1 = −1 when β ∈ (0, 1), infEj(xβm+1) <∞
and satisfies the aforementioned bounds, for j = 1, . . . ,m+ 1, on any edge Ej of
any Q with im+1 ≥ −1. Hence it follows from (3.8.20), applied to the absolutely
continuous function u − v, that on any edge Ej, with j = 1, . . . ,m + 1, of any
Q = (a+Qi,ε) ∩ Rm+1+ with im+1 ≥ −1, if infEj(x
βm+1) <∞ then
supEj
|u− v|2
≤ C
εβ2
+|β|2
(∫Ej
xβm+1
(|∂ju|2 + |∂j v|2
)dxj
) 12(∫
Ej
xβm+1|u− v|2dxj
) 12
+C
ε1+β2
+|β|2
∫Ej
xβm+1|u− v|2dxj. (3.8.35)
The remaining case we must consider occurs when im+1 = −1 and β ∈ (0, 1).
Any Q which satisfies this assumption is of the form Q = Qmε2
(y)×(0, cε] for some
y ∈ Rm × 0. This means that every Em+1 in Q has the form x′ × (0, cε] for
appropriate x′ ∈ Qmε2
(y). We apply (3.8.28) to u − v with a fixed p ∈ (1, 21+β
),
noting that this assumption on p implies (cε)2p−1−β ≤ 1 and recalling that c ≥ 2−1,
to see that
supEm+1
|u− v|2
≤ C
(∫Em+1
xβm+1|∂m+1(u− v)|2dxm+1
) 1p(∫
Em+1
xβm+1|u− v|2dxm+1
)1− 1p
+ Cε−(1+β)
∫Em+1
xβm+1|u− v|2dxm+1. (3.8.36)
The combination of (3.8.35) and (3.8.36) with (3.8.33), applied with l = 1, yields
the following for any edge Ej of any Q = a + Qi,ε ∩ Rm+1+ with Qi,ε ∈ Q and
105
im+1 ≥ −1. We see that
supEj
|u− v|2
≤ C
εm+β2
+|β|2
(∫Q+
1 (0)
xβm+1
(|∇u|2 + |∇v|2
)dx
) 1q(∫
Q+1 (0)
xβm+1|u− v|2dx
)1− 1q
+C
εm+1+β2
+|β|2
∫Q+
1 (0)
xβm+1|u− v|2dx (3.8.37)
where q ∈ p, 2, for p fixed as above, depends on β.
We obtain a bound on dist2(w(x, s), N), with (x, s) ∈ Ej × [0, ε] for any Ej
of any Q = a+Qi,ε ∩Rm+1+ with Qi,ε ∈ Q and im+1 ≥ −1, by combining (3.8.34)
and (3.8.37). In particular we find
dist2(w(x, s), N)
≤ C
εm+β2
+|β|2
(∫Q+
1 (0)
xβm+1
(|∇u|2 + |∇v|2
)dx
) 1q(∫
Q+1 (0)
xβm+1|u− v|2dx
)1− 1q
+C
εm+1+β2
+|β|2
∫Q+
1 (0)
xβm+1|u− v|2dx (3.8.38)
where q is as specified in (3.8.37).
Next we bound the gradient of w on the product of the 1-dimensional edges of
Q with [0, ε]. Let ∇ denote the gradient on Ej × [0, ε] and ∇ be the gradient on
Ej for j = 1, . . . ,m+ 1. Recall that u, v are defined so that the tangential parts
of their gradients ∇u,∇v on Rm+1+ coincide H1 almost everywhere with their
gradients ∇u, ∇v on the edges Ej. Whenever (x, s) ∈ Ej × [0, ε] we calculate
∇w(x, s) = (1− s
ε)∇u(x) +
s
ε∇v(x)
= (1− s
ε)∂ju(x) +
s
ε∂j v(x)
and∂
∂sw(x, s) =
1
ε(v(x)− u(x)).
It follows that
sups∈[0,ε]
|∇w(x, s)|2 ≤ 8(|∇u(x)|2 + |∇v(x)|2
)+
2
ε2
(|u(x)− v(x)|2
), (3.8.39)
for x in any edge Ej, j = 1, . . . ,m + 1, of Q and s ∈ [0, ε]. We integrate |∇w|2
over Ej × [0, ε] with respect to xβm+1dxjds for j = 1, . . . ,m+ 1, evaluating xβm+1
106
at the fixed value of xm+1 which defines Ej as an edge in Q ⊂ Rm+1+ for j 6= m+1.
In view of (3.8.39) we find∫Ej×[0,ε]
xβm+1|∇w|2dxjds ≤ 8ε
∫Ej
xβm+1(|∇u|2 + |∇v|2)dxj
+2
ε
∫Ej
xβm+1|u− v|2dxj. (3.8.40)
We now want to extend w to any l + 1-dimensional (l ≥ 2) face F l × [0, ε]
or F lm+1 × [0, ε] of Q × [0, ε] in such a way as to preserve the estimate (3.8.38),
regarding the distance of w from N , and so that we may apply (3.8.33) to obtain
analogues of (3.8.40) with Ej replaced by F l and F lm+1. The method for the
extension of w is slightly different depending on whether Q = (a+Qi,ε)∩Rm+1+ is
such that im+1 ≥ 0 or im+1 = −1 but overall the idea is the same. In either case
we proceed by induction; we assume w is defined on the l-dimensional faces of
Q× [0, ε] and extend w homogeneously, of degree zero, into the l+ 1-dimensional
faces.
Consider Q × [0, ε] for Q = (a + Qi,ε) ∩ Rm+1+ with Qi,ε ∈ Q and im+1 ≥
−1. Suppose that l ≥ 2 and w is already defined with L2 gradient on every
F l−1 × [0, ε] and square xβm+1dHl−1ds-integrable gradient on every F l−1m+1 × [0, ε].
In addition suppose that w(x, 0) = u(x) and w(x, ε) = v(x) for x ∈ F l or
x ∈ F lm+1. These assumptions imply that w is defined Hl almost everywhere on
all the l-dimensional faces of Q for l ≥ 2. Since ∂(F l× [0, ε]) and ∂+(F lm+1× [0, ε])
are the union of such l-dimensional faces, w is defined Hl almost everywhere on
these sets. If Q is such that im+1 ≥ 0 then we extend w to each F l × [0, ε] and
F lm+1 × [0, ε] by homogeneous extension of degree zero with respect to (y, ε
2),
where y is the centre point of F l or F lm+1. If im+1 = −1 then we can extend w
into F l × [0, ε] using the same method. In this case we extend w homogeneously
of degree 0 from ∂+(F lm+1 × [0, ε]) into F l
m+1 × [0, ε] with respect to the point(y+, ε
2
), where y is the centre point of F l
m+1 and y+ = y − (0, ym+1).
Now we check that this inductive construction of w preserves (3.8.38) and gives
a bound analogous to (3.8.40) but with the Ej replaced by F l and F lm+1. In what
follows, ∇ denotes the gradient on the product spaces of the form F j × [0, ε] and
F jm+1×[0, ε] and ∇ denotes the gradient on the faces F j and F j
m+1 for j = 2, . . . , l.
Furthermore, unless stated otherwise, in the following inequalities ∇ and ∇ are
the gradients on the set over which they are integrated. We consider the cases
im+1 ≥ 0 and im+1 = −1 separately.
Suppose im+1 ≥ 0. Let F denote an l-dimensional face F l or F lm+1 of Q, let
107
y be the centre of F and let y =(y, ε
2
). Recall that u and v are chosen such
that the tangential parts of the gradients ∇u,∇v on Rm+1 coincide with ∇u, ∇vfor Hl almost every x ∈ F . We regard F × [0, ε] as an l + 1 dimensional cube
and combine the fact that supQ(xβm+1)(
infQ(xβm+1))−1
≤ C, a positive number
independent of Q, ε and β ∈ (−1, 1), with the estimate (3.8.18) from Section
3.8.1 to see that∫F×[0,ε]
xβm+1|∇w|2dHlds ≤ Cε
∫F
xβm+1(|∇u|2 + |∇v|2)dHl
+ Cε∑
a+F l−1i
∫F l−1×[0,ε]
xβm+1|∇w|2dHl−1ds
+ Cε∑
a+F l−1i,m+1
∫F l−1m+1×[0,ε]
xβm+1|∇w|2dHl−1ds.
(3.8.41)
From (3.8.41), we inductively deduce that for any l ∈ 2, . . . ,m + 1 we can
extend w to each F l × [0, ε] and F lm+1 × [0, ε] in Q × [0, ε] (with im+1 ≥ 0) so
that w has an L2 gradient ∇w on these faces. Moreover, for any β ∈ (−1, 1), ∇wsatisfies ∫
F×[0,ε]
xβm+1|∇w|2dHlds
≤ Cεl−1∑a+F1
i
∫F 1×[0,ε]
xβm+1|∇w|2dH1ds
+ Cl∑
j=1
εl−j+1∑a+Fji
∫F jxβm+1(|∇u|2 + |∇v|2)dHj
+ Cεl−1∑
a+F1i,m+1
∫F 1m+1×[0,ε]
xβm+1|∇w|2dH1ds
+ C
l∑j=1
εl−j+1∑
a+Fji,m+1
∫F jm+1
xβm+1(|∇u|2 + |∇v|2)dHj. (3.8.42)
Now we consider cubes Q = (a+Qi,ε)∩Rm+1+ with im+1 = −1. We note that on
any face F l×[0, ε] ofQ×[0, ε] we still have (3.8.42) because dist(F l,Rm×0) ≥ ε2,
therefore we only consider the faces F lm+1 × [0, ε].
Recall that we have assumed w is defined on ∂+(F lm+1× [0, ε]) and extended w
homogeneously of degree zero into F lm+1× [0, ε] with respect to the point (y+, ε
2),
where y = (y′, ym+1) is the centre of F lm+1 and y+ = (y′, 0). We want to derive
108
an estimate, analogous to (3.8.42), on these faces of Q. We do so by reducing
the situation for F lm+1 × [0, ε] to that of an l+ 1 dimensional half-cube and then
applying (3.8.17) in Section 3.8.1.
Let z = (z′, zm+1) ∈ Rm × (0,∞) denote the centre of Q. We note that
Q = Qmε2
(z+) × (0, cε] where Qmε2
(z+) ⊂ Rm × 0, z+ = (z′, 0) and c ∈[
12, 1]
is
such that am+1 = cε. Define
Ψc : Rm+1+ → Rm+1
+ : x = (x′, xm+1) 7→(x′,
xm+1
2c
). (3.8.43)
This is Lipschitz and C1 with Lipschitz, C1 inverse
Ψ−1c : Rm+1
+ → Rm+1+ : x = (x′, xm+1) 7→ (x′, 2cxm+1) . (3.8.44)
Furthermore, we observe that Ψc(Q) = Q+ε2(z+) ∩ Rm+1
+ , a half-cube centred at
z+. We can write every l-dimensional face of Ψc(Q) with edges parallel to the
m+1-axis as Glm+1 = Ψc(F
lm+1) for appropriately corresponding faces F l
m+1 of Q.
Notice that Ψc(y+) = y+, where y+ = (y′, 0) and y = (y′, ym+1) is the centre of
F lm+1. This will allow us to use w and Ψc to define a function w on Gl
m+1× [0, ε],
which is homogeneous of degree zero with respect to (y+, ε2), and then apply
(3.8.17).
Let w(x, s) = w(Ψ−1c (x), s) with domain Ψc(Q) × [0, ε]. It follows that w is
defined Hl almost everywhere on the l-dimensional faces of Ψc(Q) × [0, ε] since
w is defined thus on the l-dimensional faces of Q× [0, ε]. Furthermore, since w is
homogeneous of degree zero in F lm+1× [0, ε] with respect to y =
(y+, ε
2
), it follows
that w is homogeneous of degree 0 with respect to y in Glm+1 × [0, ε].
A calculation shows that Ψc is a uniform dµβ and xβm+1-equivalence from
Q to Ψc(Q) = Q ε2(p+) ∩ Rm+1
+ , as defined in Section 2.3.1. Since Ψc and Ψ−1c
also have bounded derivatives, independently of c ∈ [12, 1], using (2.3.2) from the
aforementioned section, we calculate∫F lm+1×[0,ε]
xβm+1|∇w(x, s)|2dHlds
≤ C
∫Glm+1×[0,ε]
xβm+1|∇w(Ψ−1c (x), s)|2dHlds
≤ C
∫Glm+1×[0,ε]
xβm+1|∇w(x, s)|2dHlds. (3.8.45)
We identify Glm+1 × [0, ε] with a half-cube Q+,l+1
ε2
(p) ∩ Rl+1+ in such a way that
xm+1 7→ xl+1. This allows us to take advantage of the fact that w is homogeneous
109
of degree zero with respect to (y+, ε2); we may apply (3.8.17) from Section 3.8.1
to see that∫Glm+1×[0,ε]
xβm+1|∇w|2dHlds ≤ Cε
∫∂+(Glm+1×[0,ε])
xβm+1|∇w|2dHl, (3.8.46)
where ∂+(Ω× [0, ε]) = ∂(Ω× [0, ε])∩ (Rm+1+ × [0, ε]) for Ω ⊂ Rm+1. We transform
the right hand side of (3.8.46) into an integral over ∂+(F lm+1 × [0, ε]) using Ψc
and (2.3.1) from Section 2.3.1. We have∫∂+(Glm+1×[0,ε])
xβm+1|∇w(x, s)|2dHl ≤ C
∫∂+(F lm+1×[0,ε])
xβm+1|∇w(Ψc(x), s)|2dHl
≤ C
∫∂+(F lm+1×[0,ε])
xβm+1|∇w(x, s)|2dHl.
(3.8.47)
We combine (3.8.45), (3.8.46) and (3.8.47) to deduce that∫F lm+1×[0,ε]
xβm+1|∇w|2dHlds
≤ Cε
∫F lm+1
xβm+1(|∇u|2 + |∇v|2)dHl
+ Cε∑
a+F l−1i
∫F l−1×[0,ε]
xβm+1|∇w|2dHl−1ds
+ Cε∑
a+F l−1i,m+1
∫F l−1m+1×[0,ε]
xβm+1|∇w|2dHl−1ds. (3.8.48)
Thus, on any Q with im+1 = −1, using (3.8.48) and (3.8.41), we inductively
deduce that for any l ∈ 2, . . . ,m + 1, we can extend w to each F l × [0, ε] and
F lm+1 × [0, ε] in Q × [0, ε] so that w has an L2 gradient ∇w on F l × [0, ε], and
110
square xβm+1dHlds-integrable gradient∇w on F lm+1×[0, ε]. Furthermore, we have∫
F lm+1×[0,ε]
xβm+1|∇w|2dHlds
≤ Cεl−1∑a+F1
i
∫F 1×[0,ε]
xβm+1|∇w|2dH1ds
+ Cl∑
j=1
εl−j+1∑a+Fji
∫F jxβm+1(|∇u|2 + |∇v|2)dHj
+ Cεl−1∑
a+F1i,m+1
∫F 1m+1×[0,ε]
xβm+1|∇w|2dH1ds
+ Cl∑
j=1
εl−j+1∑
a+Fji,m+1
∫F jm+1
xβm+1(|∇u|2 + |∇v|2)dHj. (3.8.49)
So far, we have constructed a map w = wi,ε on each cube and rectangle
Q = (a+Qi,ε)∩Rm+1+ such that Qi,ε ∈ Q with im+1 ≥ −1. These maps satisfy the
bound (3.8.38) on the distance from w to N on the products of one dimensional
edges of Q with [0, ε]. Furthermore, for 1 ≤ l ≤ m + 1, (3.8.40) combined with
(3.8.42) and (3.8.49) provide bounds for integrals of the norm of the gradients
on the products of the l-dimensional faces of Q with [0, ε], in terms of integrals
of the norm of the gradients on the lower dimensional faces of Q. In particular,
wi,ε ∈ W 1,2β where it is defined. We now combine the definitions of wi,ε on each
of the cubes Q with the aforementioned estimates in order to define the w as in
the statement of the lemma.
It follows from the construction that w(i,ε) = w(j,ε) Hl+1-almost everywhere on
common faces F l×[0, ε] and F lm+1×[0, ε] of (a+Qi,ε)∩Rm+1
+ and (a+Qj,ε)∩Rm+1+ .
Furthermore, for 0 < ε < 18
it follows that
Q+14
(0) ⊂⋃
i:Qi,ε∈Qim+1≥−1
a+Qi,ε.
We may therefore define w ∈ W 1,2β (Q+
14
(0) × [0, ε];Rn) by w|(a+Qi,ε)∩Rm+1+
(x, s) =
w(i,ε)(x, s) for s ∈ [0, ε].
Notice that since w is homogeneous of degree 0 on any l-dimensional face
of any Q × [0, ε] with l ≥ 3, our inductive procedure preserves (3.8.38) for all
(x, s) in Q+14
(0) × [0, ε], with the possible exception of a set P of m-dimensional
Hausdorff measure 0. It follows from (3.8.38) that for (x, s) ∈ (Q+14
(0)× [0, ε])\P
111
we have
dist2(w(x, s), N)
≤ C
εm+β2
+|β|2
(∫Q+
1 (0)
xβm+1
(|∇u|2 + |∇v|2
)dx
) 1q(∫
Q+1 (0)
xβm+1|u− v|2dx
)1− 1q
+C
εm+1+β2
+|β|2
∫Q+
1 (0)
xβm+1|u− v|2dx (3.8.50)
where q is as specified in (3.8.37). Moreover, we combine (3.8.40) with (3.8.42)
and (3.8.49), which we apply with l = m+1, and apply (3.8.33) for l = 1, . . . ,m+
1, to see that∫Q+
14
(0)×[0,ε]
xβm+1|∇w|2dxds ≤ Cε
∫Q+
1 (0)
xβm+1
(|∇u|2 + |∇v|2
)dx
+C
ε
∫Q+
1 (0)
xβm+1|u− v|2dx. (3.8.51)
The definition of w as required now follows from combining (3.8.50) and
(3.8.51) with (3.8.29) and (3.8.30). The absolute continuity properties, described
in Section 3.8.2, of w, viewed as a function defined on a rectangle in polar co-
ordinates, guarantee that for almost every ρ ∈ [18, 1
4], w has square xβm+1dHmds-
integrable gradient ∂+B+ρ (0) × [0, ε] which coincides Hmds almost everywhere
with the tangential part of ∇w. Using Fubini’s theorem and (2.3.35) from Sec-
tion 2.3.4, applied to the map ρ 7→∫∂+B+
ρ (0)×[0,ε]xβm+1|∇w|2dHmds, we may there-
fore choose ρ ∈ [18, 1
4] such that w has square xβm+1dHmds-integrable gradient on
∂+B+ρ (0)× [0, ε] and satisfies∫∂+B+
ρ (0)×[0,ε]
xβm+1|∇w|2dHmds ≤ C
∫B+
14
(0)×[0,ε]
xβm+1|∇w|2dHm+1ds. (3.8.52)
We define w on Sm+ × [0, ε] by w(ω, s) = w(ρω, s). It follows that w(ω, 0) = u(ω)
almost everywhere on Sm+×0 and w(ω, ε) = v(ω) almost everywhere on Sm×εbecause the corresponding properties hold for w on ∂+B+
ρ (0)×[0, ε]. Furthermore,
since ρ ∈ [18, 1
4], the map ω → ρω is a uniform dµβ and xβm+1-equivalence as
described in Section 2.3.1 and thus∫Sm+×[0,ε]
xβm+1|Dw|2dωds ≤ C
∫∂+B+
ρ (0)×[0,ε]
xβm+1|∇w|2dHmds (3.8.53)
where D is the gradient on Sm+ × [0, ε]. We combine (3.8.51), (3.8.52) and (3.8.53)
112
with (3.8.29) and (3.8.30) to give (3.8.1). Moreover, w(ω, s) = w(ρω, s) for Hmds
almost every (ω, s) ∈ Sm+ × [0, ε] and therefore w satisfies (3.8.50), since the set
of points P for which this statement fails for w has vanishing m-dimensional
Hausdorff measure. Together, (3.8.50), (3.8.29) and (3.8.30) yield (3.8.2). This
concludes the proof.
3.9 Corollary to the Luckhaus Lemma
3.9.1 Radial Slicing for Functions in W 1,2β
Before stating the corollary to Lemma 3.8.0.1 we discuss the relationship between
integrals of a W 1,2β function on B+
ρ (y) and integrals of its restriction to ∂+B+σ (y)
for σ ≤ ρ, similarly to the discussion in section 2.7 of [46].
For v ∈ W 1,2β (B+
ρ (y);N) and σ ∈ (ρ2, ρ) we consider v(ω) := v(y + σω) where
ω ∈ Sm+ . Let D denote the gradient on Sm+ and ∇ the gradient on Rm+1+ . Using
(2.3.35) from the discussion in Section 2.3.4, if θ ∈ (0, 1) then for all σ ∈ (ρ2, ρ)
with the exception of a set of 1-dimensional Lebesgue measure θρ2
, we find∫Sm+ωβm+1|Dv|2dω =
∫Sm+ωβm+1|D(v(y + σω))|2dω
≤ Cσ2−m−β∫Sm+
(σωm+1)β|∇v(y + σω)|2σmdω
= Cσ2−m−β∫∂+B+
σ (y)
xβm+1|∇v|2dS(x)
≤ C
θρ1−m−β
∫B+ρ (y)\B+
ρ2
(y)
xβm+1|∇v|2dx (3.9.1)
where dS(x) is the Euclidean volume element on ∂+B+σ (y). Similarly, for all
σ ∈ (ρ2, ρ) with the exception of a set of 1-dimensional Lebesgue measure θρ
2we
have∫Sm+ωβm+1|v − vB+
ρ (y),β|2dω ≤σ−m−β
∫∂+B+
σ (y)
xβm+1|v − vB+ρ (y),β|
2dS(x)
≤ C
θρ−(1+m+β)
∫B+ρ (y)\B+
ρ2
(y)
xβm+1|v − vB+ρ (y),β|
2dx.
(3.9.2)
Hence if we choose θ ∈ (0, 1) small enough, depending on at most m,β, in (3.9.1)
and (3.9.2) we may choose a σ ∈ (3ρ4, ρ) such that they hold simultaneously and
113
so that v ∈ W 1,2β (Sm+ ;N).
Now we state a corollary to Lemma 3.8.0.1 which gives the estimate (3.7.1).
The following corollary is an analogue of Corollary 1 in Section 2.7.
3.9.2 Luckhaus Corollary
Corollary 3.9.2.1. There exists a δ0 = δ0(m,N, β) > 0 such that the following
holds. Let ε ∈ (0, 1) and v ∈ W 1,2β (B+
ρ (y);N) with ρ1−m−β ∫B+ρ (y)
xβm+1|∇v|2dx ≤
δ20εm+1+β
2+|β|2 . Then there is a σ ∈ (3ρ
4, ρ) such that we can find a map wε ∈
W 1,2β (B+
ρ (y);N) which agrees with v in B+ρ (y)\B+
σ (y) and such that
σ1−m−β∫B+σ (y)
xβm+1|∇w|2dx
≤ Cερ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx+C
ερ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx
(3.9.3)
for a constant C = C(m,β).
Proof. We follow the proof of Corollary 1 in Section 2.7 of [46]. Our strategy is
the following. We find a λ ∈ N which can be chosen close to vB+ρ (y),β, provided
the energy of v on B+ρ (y) is sufficiently small. Then we choose a σ ∈ (3ρ
4, ρ) which
allows us to control certain integrals involving v|∂+B+σ (y) in terms of the energy
of v on B+ρ (y). Using Lemma 3.8.0.1 we obtain a w0 agreeing with v|∂+B+
σ (y) on
Sm+ × 0 and λ on Sm+ × ε in the sense of traces. We then show that we can
make the distance from w0 to N small enough so that we may project w0 onto
N using the nearest point projection. Using the resulting map we interpolate
between v and λ to define a map which satisfies the statement of the lemma.
Throughout, C denotes a constant which depends on m and possibly β and
we only distinguish different C when necessary. We will also assume that ε ≤ 12.
This is a technical assumption and we obtain the lemma for ε ∈ (12, 1) by applying
the lemma for ε = 12, after shrinking the δ0 we obtained for ε ≤ 1
2by a factor
depending only on m,β if necessary.
Let δ0 > 0 to be chosen as required and suppose the assumptions of the lemma
hold for δ0. First, we bound the distance of vB+ρ (y),β from N in terms of δ0 and ε.
114
An application of the Poincare Inequality, Lemma 2.3.3.3, gives
ρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx ≤ Cρ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx
≤ Cδ20εm+1+β
2+|β|2 . (3.9.4)
As discussed in Section 3.8.2, we may work with a representative of v, which we
don’t relabel, such that v(B+ρ (y)) ⊂ N . It follows that
dist2(vB+ρ (y),β, N) ≤ |v(x)− vB+
ρ (y),β|2 (3.9.5)
for every x ∈ B+ρ (y). Now notice that we can choose a constant C such that
Cρ−(1+m+β2
+|β|2
) ≥(∫
B+ρ (y)
xβ2
+|β|2
m+1 dx
)−1
. Therefore, integrating (3.9.5) overB+ρ (y)
with respect to xβ2
+|β|2
m+1 dx and dividing by∫B+ρ (y)
xβ2
+|β|2
m+1 dx gives
dist2(vB+ρ (y),β, N) ≤ Cρ−(1+m+β
2+|β|2
)
∫B+ρ (y)
xβ2
+|β|2
m+1 |v − vB+ρ (y),β|
2dx. (3.9.6)
If β ∈ (−1, 0) we note additionally that ρβ ≤ infB+ρ (y) x
βm+1 and thus, in view of
(3.9.6), we conclude that
dist2(vB+ρ (y),β, N) ≤ Cρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx (3.9.7)
for any β ∈ (−1, 1). Combining (3.9.7) with (3.9.4) we find
dist2(vB+ρ (y),β, N) ≤ Cρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx ≤ Cδ20εm+1+β
2+|β|2 .
(3.9.8)
As a consequence, we may choose λ ∈ N such that
|λ− vB+ρ (y),β|
2 ≤ Cρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx ≤ Cδ20εm+1+β
2+|β|2 .
(3.9.9)
We want to apply Lemma 3.8.0.1 to v and λ. Since λ ∈ N is constant and
v ∈ N by construction, we are permitted to do this provided we can use v to define
a function in W 1,2β (Sm+ ;N). Let ω ∈ Sm+ . The combination of (3.9.4) with (3.9.1)
and (3.9.2) from Section 3.9.1 yields a σ ∈ (3ρ4, ρ) such that v ∈ W 1,2
β (Sm+ ;N),
115
where v(ω) = v(σω + y) and, moreover, such that∫Sm+ωβm+1|Dv|2dω ≤ Cρ1−m−β
∫B+ρ (y)\B+
ρ2
(y)
xβm+1|∇v|2dx
≤ Cδ20εm+1+β
2+|β|2 , (3.9.10)
where D is the gradient on Sm+ , and∫Sm+ωβm+1|v − vB+
ρ (y),β|2dω ≤ Cρ−(1+m+β)
∫B+ρ (y)\B+
ρ2
(y)
xβm+1|v − vB+ρ (y),β|
2dx
≤ Cδ20εm+1+β
2+|β|2 . (3.9.11)
Thus we may apply Lemma 3.8.0.1 to v ∈ W 1,2β (Sm+ ;N) and λ. This yields a
w0 : Sm+ × [0, ε] → Rn with w0 = v on Sm+ × 0 and w0 = λ on Sm+ × ε in the
sense of traces. Furthermore, in view of (3.8.1) we have∫Sm+×[0,ε]
ωβm+1|Dw0|2dωds ≤ Cε
∫Sm+ωβm+1|Dv|2dω +
C
ε
∫Sm+ωβm+1|v − λ|2dω,
(3.9.12)
where D is the gradient on Sm+ × [0, ε] and D is the gradient on Sm+ . In addition,
it follows from (3.8.2) that
dist2(w0(ω, s), N) ≤ C
εm+β2
+|β|2
(∫Sm+ωβm+1|Dv|2dω
) 1q(∫
Sm+ωβm+1|v − λ|2dω
)1− 1q
+C
εm+1+β2
+|β|2
∫Sm+ωβm+1|v − λ|2dω (3.9.13)
for every (ω, s) ∈ Sm+× [0, ε], where q ∈ (1, 2] depends on β. We proceed to bound
dist(w0(ω, s), N) in terms of δ0. Henceforth we assume that δ0 ≤ 1. Using (3.9.9)
and (3.9.11) we deduce that∫Sm+ωβm+1|v − λ|2dω ≤ 2
∫Sm+ωβm+1|v − vB+
ρ (y),β|2dω
+ 2
∫Sm+ωβm+1|vB+
ρ (y),β − λ|2dω
≤ 2
∫Sm+ωβm+1|v − vB+
ρ (y),β|2dω + C|vB+
ρ (y),β − λ|2
≤ Cδ20εm+1+β
2+|β|2 + Cδ2
0εm+1+β
2+|β|2
≤ Cδ20εm+1+β
2+|β|2 . (3.9.14)
116
The combination of (3.9.13) with (3.9.10) and (3.9.14) yields
dist2(w0(ω, s), N) ≤ C
εm+β2
+|β|2
(Cδ2
0εm+1+β
2+|β|2
) 1q(Cδ2
0εm+1+β
2+|β|2
)1− 1q
+C
εm+1+β2
+|β|2
Cδ20εm+1+β
2+|β|2 (3.9.15)
for every (ω, s) ∈ Sm+ × [0, ε] and for q ∈ (1, 2] depending on β. Hence, using
(3.9.15), we find
dist(w0(x, s), N) ≤ Cδ0. (3.9.16)
In order to construct w as required we choose δ0 small enough to allow us
to apply the nearest point projection of N to w0. In particular, we choose δ0,
depending on N,m, β, such that Cδ0 ≤ α where C is the constant in (3.9.16) and
α > 0 is sufficiently small to guarantee that the nearest point projection onto
N , which we denote πN , exists and has bounded derivatives in Nα = x ∈ Rn :
dist(x,N) ≤ α. It then follows from (3.9.16) that we may apply πN to w0. Let
ω ∈ Sm+ satisfy ω = ω(x) = x−y|x−y| , r = |x− y| and define w ∈ W 1,2
β (B+ρ (y);N) by
w(x) = w(y + rω(x)) =
v(y + rω(x)) r ∈ (σ, ρ)
πN(w0(ω(x), (1− rσ))) r ∈ [(1− ε)σ, σ]
λ r ∈ (0, (1− ε)σ).
Note that w agrees with v in B+ρ (y)\B+
σ (y). To complete the proof we check that
w satisfies (3.9.3). By definition, ∇w = 0 in B+(1−ε)σ(y) which implies
σ1−m−β∫B+σ (y)
xβm+1|∇w|2dx = σ1−m−β∫B+σ (y)\B+
(1−ε)σ(y)
xβm+1|∇w|2dx. (3.9.17)
Observe that∇w(x) = ∇(πN(w0(ω(x), 1−σ−1r(x)))) in B+σ (y)\B+
(1−ε)σ(y). Using
the chain rule we deduce that
|∇(πN(w0(ω, 1− σ−1r)))|
≤ C|∇πN(w0(ω, 1− σ−1r))||Dw0(ω, 1− σ−1r)||∇(ω, 1− σ−1r)|,
where D is the gradient on Sm+ × [0, ε]. The boundedness of the derivatives of
πN on Nα implies |∇πN(w0(ω, 1− σ−1r))| ≤ C. Recall the technical assumption
ε ≤ 12, together with the fact that r ∈ [(1−ε)σ, σ], ω(x) = x−y
|x−y| and r(x) = |x−y|.Using the preceding facts we calculate |∇ω| ≤ Cr−1 ≤ C((1 − ε)σ)−1 ≤ Cσ−1
117
and |∇(1− σ−1r)| ≤ Cσ−1 which yields |∇(ω, 1− σ−1r)| ≤ Cσ−1. It follows that
|∇(πN(w0(ω, 1− σ−1r)))| ≤ C
σ|Dw0(ω, 1− σ−1r)|. (3.9.18)
Hence, as a consequence of (3.9.17) and (3.9.18), we have
σ1−m−β∫B+σ (y)
xβm+1|∇w|2dx
≤ Cσ−(1+m+β)
∫B+σ (y)\B+
(1−ε)σ(y)
xβm+1|Dw0(ω, 1− σ−1r)|2dx. (3.9.19)
We paramatrise ω ∈ Sm+ by spherical coordinates and let r = |x − y|. Using the
change of variables x = rω + y we calculate∫B+σ (y)\B+
(1−ε)σ(y)
xβm+1|Dw0(ω, 1− σ−1r)|2dx
=
∫ σ
(1−ε)σrm+β
∫Sm+ωβm+1|Dw0(ω, 1− σ−1r)|2dωdr
≤ σm+β
∫ σ
(1−ε)σ
∫Sm+ωβm+1|Dw0(ω, 1− σ−1r)|2dωdr. (3.9.20)
The change of variables s = 1− rσ
yields∫ σ
(1−ε)σ
∫Sm+ωβm+1|Dw0(ω, 1− σ−1r)|2dωdr = σ
∫Sm+×[0,ε]
ωβm+1|Dw0(ω, s)|2dωds.
(3.9.21)
Thus, we combine (3.9.19), (3.9.20) and (3.9.21) with (3.9.12) to see that
σ1−m−β∫B+σ (y)
xβm+1|∇w|2dx ≤ Cε
∫Sm+ωβm+1|Dv|2dω +
C
ε
∫Sm+ωβm+1|v − λ|2dω.
This inequality, together with (3.9.10) and the combination of (3.9.9), (3.9.11)
and (3.9.14), implies (3.9.3) as required.
Remark 3.9.2.1. We note that the function w constructed in Lemma 3.9.2.1 is
defined in such a way as to permit the direct comparison of its energy with that
of a map v, which minimises Eβ relative to O. In particular, we may replace the
energy of w with the energy of such a v on the left hand side of (3.9.3). Such a
w is often called a comparison function.
118
3.10 Improved Control in the Poincare Inequal-
ity
The purpose of constructing the comparison function w in Section 3.9 is so we
may compare the energy of w to the energy of a v which is a minimising harmonic
map relative to O. The end goal is to prove a decay estimate of the form (3.7.3)
assuming that the energy of v is small. In order to achieve this we must show that
under the same smallness assumption on the energy of v, we also have sufficient
control of Cερ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|2dx in (3.9.3). In Section 3.7 we
stated that an estimate of the form (3.7.2) would suffice and we prove such an
estimate here.
Lemma 3.10.0.1. For every δ > 0 and every c0 > 0 there exist two constants
ε = ε(m,n, δ, c0) > 0 and θ = θ(m,n, δ, c0) ∈ (0, 14] such that the following
holds. Let B+R(x0) ⊂ Rm+1
+ be a half-ball with R ≤ 1 and (x0)m+1 = 0. Suppose
v ∈ W 1,2β (B+
R(x0);Rn) satisfies∣∣∣∣∣∫B+R(x0)
xβm+1 〈∇v,∇φ〉 dx
∣∣∣∣∣ ≤ c0
∫B+R(x0)
xβm+1 |φ| |∇v|2 dx
for every φ ∈ C∞0 (BR(x0);Rn). If
R1−m−β∫B+R(x0)
xβm+1|∇v|2dx ≤ ε
then
(θR)−(1+m+β)
∫B+θR(x0)
xβm+1
∣∣∣v − vB+θR(x0),β
∣∣∣2 dx ≤ δR1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx.
Proof. First we observe that the statement of the lemma is invariant under rescal-
ing and translation by any point in ∂Rm+1+ ; if the lemma is true on B+
1 (0) then
we may obtain the lemma on any B+R(x0) ⊂ Rm+1
+ with R ≤ 1 and (x0)m+1 = 0
by rescaling using the map x 7→ Rx + x0, defined for x ∈ B+1 (0), and applying
the lemma on B+1 (0). Thus we will assume R = 1 and x0 = 0.
We argue by contradiction. In particular, we will show that if the lemma
were false, then we may construct a weak solution of 2.4.5, that is a weak so-
lution of div(xβm+1∇w) = 0 in B+1 (0) with xβm+1
∂w∂xm+1
= 0 on ∂0B+1 (0), whose
L2β(B+
1 (0);Rn) norm is bounded below and strictly above by the same number, a
contradiction.
119
Now suppose, for a contradiction, that there exist δ > 0 and c0 > 0 such that
the claim is false. Then for any θ ∈ (0, 14] there is a sequence of maps (vk)k∈N,
with vk ∈ W 1,2β (B+
1 (0);Rn) for every k, such that∣∣∣∣∣∫B+
1 (0)
xβm+1 〈∇vk,∇φ〉 dx
∣∣∣∣∣ ≤ c0
∫B+
1 (0)
xβm+1|φ||∇vk|2dx (3.10.1)
for every φ ∈ C∞0 (B1(0);Rn) and∫B+
1 (0)
xβm+1|∇vk|2dx := εk → 0 as k →∞
but
θ−(1+m+β)
∫B+θ (0)
xβm+1|vk − (vk)B+θ (0),β|
2dx > δ
∫B+
1 (0)
xβm+1|∇vk|2dx
= δεk. (3.10.2)
In order to construct a weak solution of the Neumann type problem (2.4.5)
with the desired properties, we define the normalised sequence (wk)k∈N by
wk = ε− 1
2k (vk − (vk)B+
θ (0),β)
and analyse the limit as k →∞. We calculate
∇wk = ε− 1
2k ∇vk.
Hence ∫B+
1 (0)
xβm+1|∇wk|2dx = 1 (3.10.3)
and
(wk)B+θ (0),β =
1∫B+θ (0)
xβm+1dx
∫B+θ (0)
xβm+1wkdx = 0. (3.10.4)
Furthermore, we deduce from (3.10.2) that
θ−(1+m+β)
∫B+θ (0)
xβm+1 |wk|2 dx > δ. (3.10.5)
Using (3.10.4) we write wk = wk − (wk)B+θ (0),β and an application of lemma
120
(2.3.3.4) shows that∫B+
1 (0)
xβm+1|wk|2dx =
∫B+
1 (0)
xβm+1|wk − (wk)B+θ (0),β|
2dx
≤ Cθ−(1+m+β)
∫B+
1 (0)
xβm+1 |∇wk|2 dx. (3.10.6)
Together, (3.10.3) and (3.10.6) show that (wk)k∈N is bounded W 1,2β (B+
1 (0);Rn).
Hence, the Compactness lemma, Lemma 2.3.5.2, yields a subsequence (wkj)j∈N
which converges weakly in W 1,2β (B+
1 (0);Rn) and strongly in L2β(B+
1 (0);Rn) to
some w ∈ W 1,2β (B+
1 (0);Rn).
To see that w is a weak solution of the Neumann-type problem 2.4.5 in B+1 (0)
we use (3.10.1). Let φ ∈ C∞0 (B1(0);Rn). In view of (3.10.3) we find∣∣∣∣∣∫B+
1 (0)
xβm+1 〈∇wk,∇φ〉 dx
∣∣∣∣∣ = ε− 1
2k
∣∣∣∣∣∫B+
1 (0)
xβm+1 〈∇vk,∇φ〉 dx
∣∣∣∣∣≤ c0||φ||L∞(B+
1 (0);Rn)ε− 1
2k
∫B+
1 (0)
xβm+1 |∇vk|2 dx
= c0||φ||L∞(B+1 (0);Rn)ε
− 12
k εk
∫B+
1 (0)
xβm+1 |∇wk|2 dx
= c0||φ||L∞(B+1 (0);Rn)ε
12k .
Since wkj w in W 1,2β (B+
1 (0);Rn), it follows that∣∣∣∣∣∫B+
1 (0)
xβm+1〈∇w,∇φ〉dx
∣∣∣∣∣ = limj→∞
∣∣∣∣∣∫B+
1 (0)
xβm+1〈∇wkj ,∇φ〉dx
∣∣∣∣∣≤ c0||φ||L∞(B+
1 (0);Rn) limj→∞
ε12kj
= 0
for every φ ∈ C∞0 (B1(0);Rn). Hence w is a weak solution of (2.4.5) in B+1 (0).
We also conclude, using the Compactness Lemma, Lemma 2.3.5.2, to take
limits in (3.10.3), (3.10.4) and (3.10.5), that∫B+
1 (0)
xβm+1 |∇w|2 dx ≤ 1, (3.10.7)
wB+θ (0),β =
1∫B+θ (0)
xβm+1dx
∫B+θ (0)
xβm+1wdx = 0 (3.10.8)
and
θ−(1+m+β)
∫B+θ (0)
xβm+1 |w|2 dx ≥ δ (3.10.9)
121
respectively. Now, in view of (3.10.8), the Poincare inequality, Lemma 2.3.3.3,
yields
θ−(1+m+β)
∫B+θ (0)
xβm+1|w|2dx ≤ Cθ1−m−β∫B+θ (0)
xβm+1|∇w|2dx. (3.10.10)
Lastly, since w is a weak solution of 2.4.5 we may apply Corollary 2.4.3.2 to w
with θ ≤ 14
(so that 2θ ≤ 12). This gives a positive constant C (independent of θ)
and a γ ∈ (0, 1) such that
θ1−m−β∫B+θ (0)
xβm+1|∇w|2dx ≤ C(2θ)2γ. (3.10.11)
Combining (3.10.10) and (3.10.11) we see that
θ−(1+m+β)
∫B+θ (0)
xβm+1|w|2dx ≤ C(2θ)2γ. (3.10.12)
This holds for all fixed θ ∈ (0, 14] and we choose θ < 1
2
(δC
) 12γ so that (3.10.12)
contradicts (3.10.9). Hence the lemma is proved.
3.11 Energy Decay Lemma
If the energy of a minimising harmonic map relative to O is sufficiently small on
a half-ball B+R(x0) with ∂0B+
R(x0) ⊂ O then we can show that the decay of the
energy on smaller, concentric half-balls is slightly better than the decay we obtain
from the monotonicity formula, Lemma 3.3.1.1. The subsequent lemma encap-
sulates this fact and is the final precursor to an ε-regularity result for minimisers
of Eβ relative to O. The lemma corresponds to (3.7.3) in Section 3.7.
Lemma 3.11.0.1. Let β ∈ (−1, 1) and v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of
Eβ relative to O. Suppose B+R(x0) is a half-ball with R ≤ 1 and ∂0B+
R(x0) ⊂ O.
There exist ε0 = ε0(m,N, β) > 0 and θ0 = θ0(m,N, β) ∈ (0, 14) such that if
R1−m−β∫B+R(x0)
xβm+1|∇v|2dx ≤ ε0,
then
(θ0r)1−m−β
∫B+θ0r
(y)
xβm+1|∇v|2dx ≤ 1
2r1−m−β
∫B+r (y)
xβm+1|∇v|2dx,
122
for every B+r (y) ∈ B+(x0, R,
R2
).
Proof. To prove the lemma we combine Corollary 3.9.2.1 and Lemma 3.10.0.1 in
an appropriate way. Our strategy is as follows. We show that if the energy on
B+R(x0) is small then it remains proportionally small on any half-ball B+
r (y) ∈B+(x0, R,
R2
). Therefore, using the monotonicity formula, Lemma 3.3.1.1, we
deduce that if we can apply Corollary 3.9.2.1 on B+r (y) then we can apply it on
B+ρ (y) for ρ ≤ r. We do so for ρ ≤ r arbitrary and then choose ε small in the
corollary. With this choice in mind, we then choose a δ and a c0 for which to apply
Lemma 3.10.0.1 and finally conclude the proof by using our findings to choose
ρ accordingly in terms of r. Throughout the proof we will assume that, unless
stated otherwise, all constants depend only on m,N and β and only distinguish
them when necessary.
Let B+ρ (y) ⊂ B+
r (y) ∈ B+(x0, R,R2
). Then ρ ≤ r ≤ R2
, y ∈ ∂Rm+1+ and
|x0 − y| < R2
. Furthermore, as ∂0B+R(x0) ⊂ O we have y ∈ O. First we note how
the energy scales with the radius ρ. Suppose v ∈ W 1,2β (Rm+1
+ ;N) minimises Eβ
relative to O and satisfies R1−m−β ∫B+R(x0)
|∇v|2dx ≤ ε0 for ε0 > 0 to be chosen
as required. Then for any ρ ∈ (0, r] the monotonicity formula, Lemma 3.3.1.1,
yields
ρ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx ≤ r1−m−β∫B+r (y)
xβm+1|∇v|2dx
≤(R
2
)1−m−β ∫B+R2
(y)
xβm+1|∇v|2dx
≤ CR1−m−β∫B+R(x0)
xβm+1|∇v|2dx
≤ Cε0. (3.11.1)
We apply Corollary 3.9.2.1 on B+ρ (y) ⊂ B+
r (y), with ρ ≤ r to be chosen later.
This gives a δ0 such that for any ε ∈ (0, 1), if
ρ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx ≤ δ20ε
1+m+β2
+|β|2 (3.11.2)
then there is a σ ∈ (3ρ4, ρ) such that we can find a wε ∈ W 1,2
β (B+ρ (y);N) which
123
agrees with v in B+ρ (y)\B+
σ (y) and such that
σ1−m−β∫B+σ (y)
xβm+1|∇w|2dx
≤ Cερ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx+1
εCρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx.
(3.11.3)
Assuming (3.11.2) and consequently (3.11.3) hold, we make use of the comparison
property of w. Since v = w in B+ρ (y)\B+
σ (y) we may extend w to an element
of W 1,2β (Rm+1
+ ;N) by requiring w = v on Rm+1+ \B+
ρ (y). Therefore, as v is a
minimiser of Eβ relative to O, we deduce that∫B+σ (y)
xβm+1|∇v|2dx ≤∫B+σ (y)
xβm+1|∇w|2dx.
Combining this fact with the monotonicity formula, Lemma 3.3.1.1, and (3.11.3)
gives (3ρ
4
)1−m−β ∫B+
3ρ4
(y)
xβm+1|∇v|2dx
≤ Cερ1−m−β∫B+ρ (y)
xβm+1|∇v|2dx+1
εCρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx.
(3.11.4)
Fix ε = min14, 1
4C, where C is the constant in (3.11.4). We assume hence-
forth that ε0 ≤ 1Cδ2
0ε1+m+β
2+|β|2 where C is the constant from (3.11.1). It follows
from (3.11.1) that (3.11.2) is satisfied and hence, substituting this ε into (3.11.4),
we have (3ρ
4
)1−m−β ∫B+
3ρ4
(y)
xβm+1|∇v|2dx
≤ 1
4ρ1−m−β
∫B+ρ (y)
xβm+1|∇v|2dx+ Cρ−(1+m+β)
∫B+ρ (y)
xβm+1|v − vB+ρ (y),β|
2dx
(3.11.5)
for a constant C and any ρ ≤ r ≤ R2
. Now we apply Lemma 3.10.0.1 with
124
δ = min14, 1
4C fixed, depending on m,N and β. Observe that∣∣∣∣∫
B+r (y)
xβm+1 〈∇v,∇φ〉 dx∣∣∣∣ =
∣∣∣∣∫B+r (y)
xβm+1 〈φ,A(v)(∇v,∇v)〉 dx∣∣∣∣
≤ c0
∫B+r (y)
xβm+1|φ||∇v|2dx, (3.11.6)
for every φ ∈ C∞0 (Br(y);Rn) on every B+r (y) ⊂ B+
R(x0) where c0 = c0(m,N).
Hence, we may apply the lemma for δ, c0 as above to obtain a corresponding
ε1 > 0 and θ1 ∈ (0, 14] such that if r1−m−β ∫
B+r (y)
xβm+1|∇v|2dx ≤ ε1 then
(θ1r)−(1+m+β)
∫B+θ1r
(y)
xβm+1|v − vB+θ1r
(y),β|2dx ≤ 1
4Cr1−m−β
∫B+r (y)
xβm+1|∇v|2dx.
(3.11.7)
Now choose ε0 = 1C
minδ20ε
1+m+β2
+|β|2 , ε1 where C is the constant from (3.11.1).
It follows that (3.11.5) and (3.11.7) hold on any B+ρ (y) ⊂ B+
r (y) ∈ B+(x0, R,R2
).
Thus we may apply (3.11.5) with ρ = θ1r. In turn, assuming this choice of ρ, we
combine (3.11.5) with the monotonicity formula and (3.11.7) to see that(3θ1r
4
)1−m−β ∫B+
3θ1r4
(y)
xβm+1|∇v|2dx ≤ 1
2r1−m−β
∫B+r (y)
xβm+1|∇v|2dx.
Hence the lemma is proved with the above choice of ε0 and θ0 = 3θ14
.
3.12 Holder Continuity of Energy Minimisers
Here we present an ε-regularity theorem for minimisers of Eβ relative to O which
is a culmination of all our preceding results. That is, we show that if the energy of
a minimiser is sufficiently small in a given half-ball then the minimiser is Holder
continuous in a smaller concentric half-ball. The following lemma is an analogue
of the regularity estimate, Theorem 3.1 in [44], due to Schoen and Uhlenbeck for
harmonic maps between Riemannian manifolds. Since we have not prescribed
boundary data, the theorem has the form of an interior regularity result.
3.12.1 ε-regularity Theorem
Theorem 3.12.1.1. Let β ∈ (−1, 1) and v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of
Eβ relative to O. Suppose B+R(x0) is a half-ball with R ≤ 1 and ∂0B+
R(x0) ⊂ O.
125
There exists an ε = ε(m,N, β) > 0 and a θ = θ(m,N, β) ∈ (0, 1) such that if
R1−m−β∫B+R(x0)
xβm+1|∇v|2dx ≤ ε,
then v ∈ C0,γ(B+θR(x0);N) for some γ = γ(m,N, β) ∈ (0, 1). In particular,
|v(x1)− v(x2)| ≤ C
(R1−m−β
∫B+R(x0)
xβm+1|∇v|2dx
) 12 ( |x1 − x2|
R
)γ(3.12.1)
for every x1, x2 ∈ B+θR(x0) and a constant C = C(m,N, β).
Proof. To prove the theorem, we show that minimisers of Eβ relative to O satisfy
(3.5.3) and (3.5.4) and apply Lemma 3.5.0.2. To achieve this we choose ε small
enough so we may apply Lemma 3.6.0.4 and Lemma 3.11.0.1. We conclude min-
imisers satisfy (3.5.3) by applying Lemma 3.11.0.1 and Lemma 3.5.1.1. This fact,
together with an application of Lemma 3.6.0.4 shows minimisers satisfy (3.5.4).
Throughout the proof we adopt the convention that all constants depend only
on m,N and β unless stated otherwise. We reinforce this dependence where
appropriate.
Let v be a minimiser of Eβ relative toO with R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx ≤ ε
for ε = minε0, ε1, where ε0 is the number from Lemma 3.11.0.1 and ε1 is the
number from lemma 3.6.0.4. We now proceed to investigate the implications of
this choice of ε in terms of the application of the aforementioned lemmata.
The choice of ε allows us to apply Lemma 3.11.0.1. This yields a θ0 ∈ (0, 14]
such that on every B+r (z) ∈ B+(x0, R,
R2
) we have
(θ0r)1−m−β
∫B+θ0r
(z)
xβm+1|∇v|2dx ≤ 1
2r1−m−β
∫B+r (z)
xβm+1|∇v|2dx. (3.12.2)
Hence, since the function f(r) = r1−m−β ∫B+r (z)
xβm+1|∇v|2dx is non-decreasing on
(0, R2
] by the monotonicity formula, Lemma 3.3.1.1, we may apply Lemma 3.5.1.1
(with h = 0) to this f . We deduce that for any B+r (z) ∈ B+(x0, R,
R2
) we have
r1−m−β∫B+r (z)
xβm+1|∇v|2dx ≤ C
(2r
R
)γ0(R
2
)1−m−β ∫B+R2
(z)
xβm+1|∇v|2dx
≤ C
(r
R
)γ0
R1−m−β∫B+R(x0)
xβm+1|∇v|2dx (3.12.3)
for a constant C and a γ0 ∈ (0, 1) which depend on m,N, β and θ0, and hence
126
only on m,N, β. Thus, v satisfies (3.5.3) in Lemma 3.5.0.2 for all B+r (z) ∈
B+(x0, R,R2
).
We now focus on a proof of (3.5.4). It follows from our choice of ε that we
may apply Lemma 3.6.0.4. Hence, for any Br(y) ∈ Bθ1(x0, R,R3
), with θ1 ≥ 2
given by the lemma, and any 0 < ρ ≤ r we have
ρ1−m∫Bρ(y)
|∇v|2 dx ≤ C(ρr
)γ1
r1−m∫Br(y)
|∇v|2 dx (3.12.4)
for some γ1 ∈ (0, 1). In order to verify that (3.5.4) is satisfied we combine (3.12.4)
for r = ym+1
θ1, with (3.12.3) applied on a suitable choice of half-ball B+
r (z). Since
θ1 ≥ 2, for any Br(y) ∈ Bθ1(x0, R,R3
) we have the inclusions
Br(y) ⊂ B ym+1θ1
(y) ⊂ B+(θ1+1θ1
)ym+1
(y+) ⊂ B+3ym+1
2
(y+) ∈ B+
(x0, R,
R
2
).
(3.12.5)
These inclusions, together with (3.4.3) from Section 3.4, yield(ym+1
θ1
)1−m ∫B ym+1
θ1
(y)
|∇v|2 dx
≤ C
(ym+1
θ1
)1−m−β ∫B+
( θ1+1θ1
)ym+1
(y+)
xβm+1|∇v|2dx
≤ C
((θ1 + 1)ym+1
θ1
)1−m−β ∫B+
( θ1+1θ1
)ym+1
(y+)
xβm+1|∇v|2dx, (3.12.6)
where C depends on m,N, β and θ1 and thus only on m,N, β. In view of (3.12.5)
and (3.12.6) we note that B+r (z), with r =
(θ1+1θ1
)ym+1 and z = y+, is a sufficient
choice of half-ball on which to apply (3.12.3). Let γ = minγ0, γ1. We combine
(3.12.3), applied on B+(θ1+1θ1
)ym+1
(y+), with (3.12.4), applied on B ym+1θ1
(y), and
127
(3.12.6) to see that
ρ1−m∫Bρ(y)
|∇v|2 dx
≤ C
(θ1ρ
ym+1
)γ (ym+1
θ1
)1−m ∫B ym+1
θ1
(y)
|∇v|2 dx
≤ C
(ρ
ym+1
)γ ((θ1 + 1)ym+1
θ1
)1−m−β ∫B+
( θ1+1θ1
)ym+1
(y+)
xβm+1|∇v|2dx
≤ C
(ρ
ym+1
)γ (ym+1
R
)γR1−m−β
∫B+R(x0)
xβm+1|∇v|2dx
≤ C( ρR
)γR1−m−β
∫B+R(x0)
xβm+1|∇v|2dx. (3.12.7)
This holds for any Bρ(y) ∈ Bθ1(x0, R,R3
) and since (3.12.3) holds on B+(x0, R,R2
),
it holds on B+(x0, R,R3
). Thus we have satisfied the assumptions (3.5.3) and
(3.5.4) of Lemma 3.5.0.2. Applying this lemma concludes the proof.
3.12.2 Partial Regularity for Energy Minimisers
We now provide an estimate for the Hausdorff dimension, with respect to the
Euclidean metric, of the set of points in O where a minimiser of Eβ relative to
O fails to be Holder continuous. Combined with Theorem 3.12.1.1 this yields
a partial regularity result for minimisers of Eβ relative to O which constitutes
Theorem 3.2.0.1 in Section 3.2.
Lemma 3.12.2.1. Suppose v ∈ W 1,2β (Rm+1
+ ;N) is a minimiser of Eβ relative to
O. Let Σint ⊂ Rm+1+ denote the set of points, discussed in Section 3.2, which
is relatively closed in Rm+1+ and has Hausdorff dimension m − 2, such that v
is smooth in Rm+1+ \Σint. Then there exist γ ∈ (0, 1) and a relatively closed set
Σbdry ⊂ O of vanishing m+β−1-dimensional Hausdorff measure, with respect to
the Euclidean metric, such that v ∈ C0,γ((Rm+1+ ∪O)\Σ;N) where Σ = Σint∪Σbdry.
Furthermore Σ is relatively closed in Rm+1+ ∪ O and Hm+β−1(Σ) = 0.
Proof. The proof closely follows the proof of Theorem 3.2 in [33]; Theorem
3.12.1.1 indicates a choice for Σbdry and we use a covering argument to estimate
the Hausdorff dimension of this set.
The ε-regularity result, Theorem 3.12.1.1, gives us a candidate for Σbdry;
define
Σbdry = y ∈ O : Θβv (y) ≥ ε
128
where ε is the number given by the theorem and
Θβv (y) = lim
r→0+r1−m−β
∫B+r (y)
xβm+1|∇v|2dx
is the density function defined in Section 3.3.1. It follows from Lemma 3.12.1.1
that every point in O\Σbdry is contained in a neighbourhood where v is Holder
continuous. Moreover, in view of Lemma 3.3.1.2, Θβv is upper semi-continuous
which, when combined with the definition of Σbdry, shows that Σbdry is relatively
closed in O.
We want to show that the m+ β − 1 dimensional Hausdorff measure of Σbdry
vanishes. We may write Σbdry as a countable union of compact sets of the form
K ∩ Σbdry where K ⊂ O is compact. Let Σ′ ⊂ Σbdry be such a set. Fix δ > 0
and cover Σ′ by a collection of balls Bmri
(xi) ⊂ O with Bmri
(xi) ⊂ O with xi ∈ Σ′
and 0 < ri ≤ δ. The compactness of Σ′, combined with Vitali’s covering theorem
yields a finite subcollection of balls, Bmr1
(x1), . . . , BmrI
(xI) for some I ∈ N, of any
such cover of Σ′, which satisfies
Bri(xi) ∩Brj(xj) = ∅ for i 6= j, 1 ≤ i, j ≤ I
and
Σ′ ⊂I⋃i=1
B5ri(xi).
For each i, the boundary energy monotonicitly formula, Lemma 3.3.1.1, implies
ε ≤ r1−m−βi
∫B+ri
(xi)
xβm+1|∇v|2dx.
Hence,
I∑i=1
(10ri)m+β−1 ≤ 10m+β−1
ε
I∑i=1
∫B+ri
(xi)
xβm+1|∇v|2dx
≤ 10m+β−1
ε
∫O×[0,δ]
xβm+1|∇v|2dx. (3.12.8)
Using Lebesgue’s Dominated Convergence Theorem we send δ → 0+ in (3.12.8).
This shows that Hm−1+β(Σ′) = 0 and hence Hm−1+β(Σbdry) = 0.
Now we show that Σ = Σint ∪ Σbdry is relatively closed in Rm+1+ ∪ O. Let
x0 ∈ (Rm+1+ ∪ O)\Σ. If x0 ∈ Rm+1
+ then x0 ∈ Rm+1+ \Σint and the discussion in
Section 3.2 after Theorem 3.2.0.1 implies that v is smooth in an open ball centred
129
at x0 and contained in Rm+1+ \Σint ⊂ (Rm+1
+ ∪O)\Σ. If x0 ∈ O then x0 ∈ O\Σbdry
and Θβv (x0) < ε which, combined with the fact that O\Σbdry is open in O,
implies there exists an R > 0 such that R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx ≤ ε, R ≤ 1
and ∂0B+R(x0) ⊂ O\Σbdry. Consequently, Theorem 3.12.1.1 implies that there
are θ, γ ∈ (0, 1) such that v ∈ C0,γ(B+θR(x0);N). Furthermore, we deduce from
(3.12.3) in the proof of Theorem 3.12.1.1 that
r1−m−β∫B+r (z)
xβm+1|∇v|2dx ≤ C( rR
)γε
on every B+r (z) ∈ B+(x0, R,
R2
) which shows that Θβv (z) = 0 for every z ∈
∂0B+R2
(x0). Now setting σ = minθ, 12 we see that Θβ
v (z) = 0 for z ∈ ∂0B+σR(x0)
which implies ∂0B+σR(x0) ⊂ O\Σbdry. Furthermore, v is a Holder continuous
weakly harmonic map in any Br(y) with Br(y) ⊂ B+σR(x0). We apply Lemma
3.6.0.2 to see that v is smooth inB+σR(x0) and conclude thatB+
σR(x0) ⊂ Rm+1+ \Σint.
Consequently, we have B+σR(x0) ∪ ∂0B+
σR(x0) ⊂ (Rm+1+ ∪ O)\Σ and note that
B+σR(x0) ∪ ∂0B+
σR(x0) is an open ball centred at x0 in the (Euclidean) topol-
ogy of Rm+1+ ∪ O. Hence Σ is relatively closed in Rm+1
+ ∪ O. We also conclude
v ∈ C0,γ((Rm+1+ ∪ O)\Σ;N).
Finally, as the Hausdorff dimension of Σint is m − 2 < m − 1 + β and
Hm−1+β(Σbdry) = 0, we deduce that Hm+β−1(Σ) = 0.
Remark 3.12.2.1. We define Σbdry := y ∈ O : Θβv (y) ≥ ε henceforth.
130
Chapter 4
Preliminaries for Regularity of
First Order Derivatives
Monotonicity formulas and related properties of solutions of second order linear
PDEs are a vital component in the regularity theory for semi-linear second order
PDEs, where the highest order term is linear. The main topic of discussion
here will be the validity of certain monotonicity formula for the average energy
of weak solutions, and their derivatives, of div(|xm+1|β∇v) = 0, particularly in
the context of the Neumann type problem (2.4.5) or the Dirichlet problem as
described below in Section 4.2.
The following monotonicity formula is asserted in [6] for balls with centre
(0′, xm+1) ∈ Rm+1; we state the theorem on B1(0) ⊂ Rm+1 which is a particular
case of their result.
Lemma 4.0.0.1 (Particular Case of Theorem 2.6 of [6]). Suppose v is a weak
solution of div(|xm+1|β∇v) = 0 in B1(0) with v ∈ W 1,2β (B1(0);Rn) and v ∈
L2(B+1 (0);Rn). Then for every 0 < r ≤ R < 1 it follows that
r−(1+m+β)
∫Br(0)
|xm+1|β |∇v|2 dx ≤ R−(1+m+β)
∫BR(0)
|xm+1|β |∇v|2 dx. (4.0.1)
We claim that this is actually not true if β ∈ (0, 1) unless the solution v is
also symmetric with respect to the hyperplane Rm × 0, that is v(x′, xm+1) =
v(x′,−xm+1) for every x = (x′, xm+1) in B1(0). We will show that the formula
holds for all β ∈ (−1, 1) given the aforementioned symmetry and provide a
counter example for general v below.
131
Lemma 4.0.0.2. The function
v(x′, xm+1) =
1
1−βx1−βm+1 if xm+1 ≥ 0
− 11−β (−xm+1)1−β if xm+1 < 0
is a weak solution of div(|xm+1|β∇v) = 0 in B1(0) and satisfies the assumptions
of Lemma 4.0.0.1 for every β ∈ (−1, 1). When β ∈ (0, 1) the map v does not
satisfy the conclusion of Lemma 4.0.0.1.
The function v defined in the preceding lemma is the odd reflection of the
function 11−βx
1−βm+1 in the hyperplane Rm × 0 which, as we will show later, is
a solution of div(xβm+1∇v) = 0 in bounded domains in Rm+1+ . To establish that
div(|xm+1|β∇v) = 0 in B1(0), we prove the following, more general fact which we
will also use in the proof of the monotonicity formula.
Lemma 4.0.0.3. Let R > 0, x0 ∈ ∂Rm+1+ and suppose v ∈ W 1,2
β (B+R(x0);Rn)
is a weak solution of (2.4.1) in B+R(x0). Let Tv = 0 on ∂0B+
R(x0) where T is a
bounded linear trace operator with the properties described in Section 2.3.2. Then
the odd reflection of v in Rm × 0, that is, the function
v(x′, xm+1) =
v(x′, xm+1) if xm+1 ≥ 0
−v(x′,−xm+1) if xm+1 < 0
is in W 1,2β (BR(x0);Rn) and is a weak solution of (2.4.1) in BR(x0). Moreover,
the weak derivatives of v are given by the formula
∂v
∂xi(x′, xm+1) = sgn(xm+1)
∂v
∂xi(x′, |xm+1|) (4.0.2)
for i = 1, . . . ,m and
∂v
∂xm+1
(x′, xm+1) =∂v
∂xm+1
(x′, |xm+1|). (4.0.3)
Proof. To prove the lemma we need to show that v ∈ W 1,2β (BR(x0);Rn) and that
v is a weak solution of div(|xm+1|β∇v) = 0 in BR(x0).
First we show that the weak partial derivatives of v are defined by (4.0.2)
and (4.0.3). Let B−R(x0) = Rm+1− ∩ BR(x0) and φ ∈ C∞0 (BR(x0);Rn). Then for
132
i = 1, . . . ,m we calculate∫BR(x0)
⟨sgn(xm+1)
∂v
∂xi(x′, |xm+1|), φ
⟩dx =
∫B+R(x0)
⟨∂v
∂xi(x′, xm+1), φ
⟩dx
−∫B−R (x0)
⟨∂v
∂xi(x′,−xm+1), φ
⟩dx.
(4.0.4)
We consider the integrals over the regions B+R(x0) and B−R(x0) separately. Since
φ vanishes on ∂+B+R(x0), an integration by parts yields∫B+R(x0)
⟨∂v
∂xi, φ
⟩dx = −
∫B+R(x0)
⟨v,∂φ
∂xi
⟩dx. (4.0.5)
Similarly, the change of variables xm+1 7→ −xm+1, followed by an integration by
parts and the same change of variables again, gives
−∫B−R (x0)
⟨∂v
∂xi(x′,−xm+1), φ
⟩dx = −
∫B+R(x0)
⟨∂v
∂xi, φ(x′,−xm+1)
⟩dx
=
∫B+R(x0)
⟨v,∂φ
∂xi(x′,−xm+1)
⟩dx
= −∫B−R (x0)
⟨v,∂φ
∂xi
⟩dx. (4.0.6)
Together, (4.0.4), (4.0.5) and (4.0.6) show that the weak partial derivatives ∂v∂xi
are defined by (4.0.2) for i = 1, . . . ,m.
Now we show that ∂v∂xm+1
is defined by (4.0.3). We have
∫BR(x0)
⟨∂v
∂xm+1
(x′, |xm+1|), φ⟩
dx =
∫B+R(x0)
⟨∂v
∂xm+1
(x′, xm+1), φ
⟩dx
+
∫B−R (x0)
⟨∂v
∂xm+1
(x′,−xm+1), φ
⟩dx.
(4.0.7)
Since φ vanishes on ∂+B+R(x0) and Tv(x′) = 0 for x′ ∈ Bm
r (x0), we integrate by
parts to see that∫B+R(x0)
⟨∂v
∂xm+1
, φ
⟩dx = −
∫B+R(x0)
⟨v,
∂φ
∂xm+1
⟩dx. (4.0.8)
Similarly, also using the change of variables xm+1 7→ −xm+1, followed by an
133
integration by parts and the same change of variables again, we find∫B−R (x0)
⟨∂v
∂xm+1
(x′,−xm+1), φ
⟩dx =
∫B+R(x0)
⟨∂v
∂xm+1
, φ(x′,−xm+1)
⟩dx
=
∫B+R(x0)
⟨v,
∂φ
∂xm+1
(x′,−xm+1)
⟩dx
= −∫B−R (x0)
⟨v,
∂φ
∂xm+1
⟩dx. (4.0.9)
The combination of (4.0.7), (4.0.8) and (4.0.9) shows that the weak partial deriva-
tive ∂v∂xm+1
is defined by (4.0.3). Thus, since∫BR(x0)
|xm+1|β|∇v|2dx = 2
∫B+R(x0)
xβm+1|∇v|2dx (4.0.10)
and ∫BR(x0)
|xm+1|β|v|2dx = 2
∫B+R(x0)
xβm+1|v|2dx, (4.0.11)
we deduce that v ∈ W 1,2β (BR(x0);Rn).
Now we show that v is a weak solution of (2.4.1) in BR(x0). Let φ ∈C∞0 (BR(x0);Rn). We need to show that∫
BR(x0)
|xm+1|β 〈∇v,∇φ〉 dx = 0.
To this end, consider χ ∈ C∞(R; [0, 1]) with
χ(s) =
0 s ∈ (−∞, 1
2]
0 ≤ χ(s) ≤ 1 s ∈ (12, 1)
1 s ∈ [1,∞)
Then, for δ > 0, consider the symmetric functions χδ(xm+1) = χ( |xm+1|δ
) ∈C∞(R; [0, 1]). The pointwise limit as δ → 0+ of these functions is
χ0(s) =
0 xm+1 = 0
1 xm+1 ∈ R\0.
Differentiating with respect to xm+1 we see that
(χδ)′(xm+1) = 0
134
outside the set [−δ,− δ2] ∪ [ δ
2, δ] and furthermore,
(χδ)′(xm+1) =
1
δsgn(xm+1)χ′
(|xm+1|δ
)(4.0.12)
on this set.
Consider∫BR(x0)
|xm+1|β⟨∇v,∇(χ 1
kφ)⟩
dx =
∫BR(x0)
χ 1k|xm+1|β 〈∇v,∇φ〉 dx
+
∫BR(x0)
(χ 1k)′|xm+1|β
⟨∂v
∂xm+1
, φ
⟩dx,
(4.0.13)
for k ∈ N. We examine each of the terms in (4.0.13) in turn, with a view to
taking the limit as k →∞.
First, we write∫BR(x0)
|xm+1|β⟨∇v,∇(χ 1
kφ)⟩
dx =
∫B+R(x0)
xβm+1
⟨∇v,∇(χ 1
kφ)⟩
dx
+
∫B−R (x0)
(−xm+1)β⟨∇v,∇(χ 1
kφ)⟩
dx.
(4.0.14)
As v is a weak solution of div(xβm+1∇v) = 0 inB+R(x0) and χ 1
kφ ∈ C∞0 (B+
R(x0);Rn)
for every k, it follows that∫B+R(x0)
xβm+1
⟨∇v,∇(χ 1
kφ)⟩
dx = 0. (4.0.15)
Furthermore, we calculate∫B−R (x0)
(−xm+1)β⟨∇v,∇(χ 1
kφ)⟩
dx
= −∫B−R (x0)
χ 1k(−xm+1)β 〈∇′v(x′,−xm+1),∇′φ〉 dx
+
∫B−R (x0)
χ 1k(−xm+1)β
⟨∂v
∂xm+1
(x′,−xm+1),∂φ
∂xm+1
⟩dx
−∫B−R (x0)
kχ′(−kxm+1)(−xm+1)β⟨
∂v
∂xm+1
(x′,−xm+1), φ
⟩dx. (4.0.16)
135
Using the change of variables xm+1 7→ −xm+1 combined with (4.0.12) we see that∫B−R (x0)
χ 1k(−xm+1)β 〈∇′v(x′,−xm+1),∇′φ〉 dx
=
∫B
+R (x0)
χ 1kxβm+1 〈∇′v,∇′φ(x′,−xm+1)〉 dx, (4.0.17)
∫B−R (x0)
χ 1k(−xm+1)β
⟨∂v
∂xm+1
(x′,−xm+1),∂φ
∂xm+1
⟩dx
= −∫B+R(x0)
χ 1kxβm+1
⟨∂v
∂xm+1
,∂
∂xm+1
(φ(x′,−xm+1))
⟩dx (4.0.18)
and
−∫B−R (x0)
kχ′(−kxm+1)(−xm+1)β⟨
∂v
∂xm+1
(x′,−xm+1), φ
⟩dx
= −∫B+R(x0)
kχ′(kxm+1)xβm+1
⟨∂v
∂xm+1
, φ(x′,−xm+1)
⟩dx. (4.0.19)
Hence, combining (4.0.16), (4.0.17), (4.0.18) and (4.0.19) we see that∫B−R (x0)
(−xm+1)β⟨∇v,∇(χ 1
kφ)⟩
dx
= −∫B+R(x0)
xβm+1
⟨∇v,∇(χ 1
kφ(x′,−xm+1))
⟩dx. (4.0.20)
Now observe that the map x 7→ φ(x′,−xm+1) ∈ C∞(BR(x0);Rn) because φ ∈C∞(BR(x0);Rn). Thus, since v is a weak solution of div(xβm+1∇v) = 0 in B+
R(x0)
and x 7→ χ 1kφ(x′,−xm+1) ∈ C∞0 (B+
R(x0);Rn), for every k we have∫B+R(x0)
xβm+1
⟨∇v,∇(χ 1
kφ(x′,−xm+1))
⟩dx = 0. (4.0.21)
Together, (4.0.14), (4.0.15), (4.0.20) and (4.0.21) show that∫BR(x0)
|xm+1|β⟨∇v,∇(χ 1
kφ)⟩
dx = 0 (4.0.22)
for every k ∈ N.
Now we consider the other terms in (4.0.13). Since v, φ ∈ W 1,2β (BR(x0);Rn),
we have |χ 1k|xm+1|β 〈∇v,∇φ〉 | ≤ C|xm+1|β|∇v||∇φ| ∈ L1(BR(x0);Rn). Thus,
136
Lebesgue’s Dominated Convergence Theorem implies that
limk→∞
∫BR(x0)
χ 1k|xm+1|β 〈∇v,∇φ〉 dx =
∫BR(x0)
|xm+1|β 〈∇v,∇φ〉 dx. (4.0.23)
Lastly we consider the term∫BR(x0)
(χ 1k)′|xm+1|β
⟨∂v
∂xm+1, φ⟩
dx. Let fk(x′) =
min 1k, f(x′) where f(x′) = (R2 − |x′ − x0|2)
12 for x′ ∈ Bm
R (x0). Then, recalling
(4.0.12) and the fact that (χ 1k)′(xm+1) = 0 when xm+1 /∈ [− 1
k,− 1
2k] ∪ [ 1
2k, 1k], we
have ∫BR(x0)
(χ 1k)′|xm+1|β
⟨∂v
∂xm+1
, φ
⟩dx
=
∫BmR (x0)
∫ fk
0
kχ′(kxm+1)xβm+1
⟨∂v
∂xm+1
, φ
⟩dx
−∫BmR (x0)
∫ 0
−fkkχ′(−kxm+1)(−xm+1)β
⟨∂v
∂xm+1
(x′,−xm+1), φ
⟩dx.
Using the change of variables xm+1 7→ −xm+1 we see that∫BR(x0)
(χ 1k)′|xm+1|β
⟨∂v
∂xm+1
, φ
⟩dx
=
∫BmR (x0)
∫ fk
0
kχ′(kxm+1)xβm+1
⟨∂v
∂xm+1
, φ(x′, xm+1)− φ(x′,−xm+1)
⟩dx.
(4.0.24)
Furthermore, we have |φ(x′, xm+1)− φ(x′,−xm+1)| ≤ 2k||∇φ||L∞(BR(x0);R(m+1)n) for
every xm+1 ∈ (0, fk(x′)) and every x′ ∈ Bm
R (x0) as a result of the Mean Value
Theorem. This fact, together with (4.0.24) yields∣∣∣∣∫BR(x0)
(χ 1k)′|xm+1|β
⟨∂v
∂xm+1
, φ
⟩dx
∣∣∣∣≤ C||∇φ||L∞(BR(x0);R(m+1)n)
∫BmR (x0)
∫ fk
0
xβm+1
∣∣∣∣ ∂v
∂xm+1
∣∣∣∣ dx. (4.0.25)
Since v ∈ W 1,2β (B+
R(x0);Rn), we may apply Lebesgue’s Dominated Convergence
Theorem to see that∫BmR (x0)
∫ fk
0
xβm+1
∣∣∣∣ ∂v
∂xm+1
∣∣∣∣ dx→ 0 as k →∞. (4.0.26)
137
Consequently, in view of (4.0.25) and (4.0.26), we have
limk→∞
∫BR(x0)
(χ 1k)′|xm+1|β
⟨∂v
∂xm+1
, φ
⟩dx = 0. (4.0.27)
Finally, we combine (4.0.13) with (4.0.22), (4.0.23) and (4.0.27) to see that∫BR(x0)
|xm+1|β 〈∇v,∇φ〉 dx = limk→∞
∫BR(x0)
|xm+1|β⟨∇v,∇(χ 1
kφ)⟩
dx = 0
as required.
Proof of Lemma 4.0.0.2. First we show that v(x) = 11−βx
1−βm+1 is in C0(B+
1 (0);R)∩W 1,2β (B+
1 (0);R) and is a weak solution of div(xβm+1∇v) = 0 in B+1 (0) with
v(x′, 0) = 0 for every x′ ∈ Rm.
Observe that v is smooth in Rm+1+ and continuous in B+
1 (0) by definition with
v(x′, 0) = 0 for all x′ ∈ Rm. Notice that
∂v
∂xi= 0 for i = 1, . . . ,m and
∂v
∂xm+1
= x−βm+1 and∂2v
∂x2m+1
= −βx−β−1m+1
(4.0.28)
classically in Rm+1+ . It follows that
∫B+
1 (0)
xβm+1 |∇v|2 dx =
∫B+
1 (0)
xβm+1
∣∣∣∣ ∂v
∂xm+1
∣∣∣∣2 dx =
∫B+
1 (0)
x−βm+1dx = C
where C = C(m,β). Hence, since v is continous, and therefore bounded, in B+1 (0)
and continuously differentiable in B+1 (0), it follows that v ∈ W 1,2
β (B+1 (0);R).
Moreover, the continuity of v in B+1 (0), together with the fact that v(x′, 0) = 0
for all x′ ∈ ∂0B+1 (0), yields Tv = 0 on ∂0B+
1 (0) for the trace operator T defined
in Section 2.3.2. Lastly, we calculate that
div(xβm+1∇v) = xβm+1
∂2v
∂x2m+1
+ βxβ−1m+1
∂v
∂xm+1
= − β
xm+1
+β
xm+1
= 0
classically in B+1 (0) and hence v is a weak solution of div(xβm+1∇v) = 0 on this
domain.
We now apply Lemma 4.0.0.3 to see that the odd reflection
v(x′, xm+1) =
1
1−βx1−βm+1 if xm+1 ≥ 0
− 11−β (−xm+1)1−β if xm+1 < 0
138
weakly solves div(|xm+1|β∇v) = 0 in B1(0) and satisfies v ∈ W 1,2β (B1(0);R). The
lemma also tells us that all weak partial derivatives of v with respect to xi with
i = 1, . . . ,m are zero and that ∂v∂xm+1
= |xm+1|−β ∈ L2β(B1(0);R). We proceed to
show that the monotonicity formula (4.0.1) is not valid for v.
For 0 < ρ < 1 we calculate∫Bρ(0)
|xm+1|β|∇v|2dx =
∫Bρ(0)
|xm+1|β||xm+1|−β|2dx
=
∫Bρ(0)
|xm+1|−βdx
=
∫ ρ
0
rm−β∫Sm|ωm+1|−βdωdr
= ρ1+m−β∫Sm |ωm+1|−βdω
1 +m− β(4.0.29)
since∫Sm |ωm+1|−βdω <∞. Thus we deduce that
r−(1+m+β)
∫Br(0)
|xm+1|β|∇v|2dx ≤ R−(1+m+β)
∫BR(0)
|xm+1|β|∇v|2dx (4.0.30)
if, and only if,
r−(1+m+β)r1+m−β∫Sm |ωm+1|−βdω
1 +m− β≤ R−(1+m+β)R1+m−β
∫Sm |ωm+1|−βdω
1 +m− β(4.0.31)
if, and only if,
r−2β ≤ R−2β, (4.0.32)
which is false if 0 < r < R < 1 and β ∈ (0, 1).
4.1 Monotonicity Formula for Even Solutions of
the Linear Degenerate Equation
This section is dedicated to proving the following monotonicity formula.
Theorem 4.1.0.1. Let BR(x0) ⊂ Rm+1 with (x0)m+1 = 0 and R ≤ 1 and suppose
v ∈ W 1,2β (BR(x0);Rn) is a weak solution of div(|xm+1|β∇v) = 0 in BR(x0). If v
is symmetric with respect to ∂Rm+1+ in BR(x0) then
s−(1+m+β)
∫Bs(x0)
|xm+1|β|∇v|2dx ≤ r−(1+m+β)
∫Br(x0)
|xm+1|β|∇v|2dx
139
for every 0 < s ≤ r ≤ R.
Remark 4.1.0.1. Recall that a weak solution of div(|xm+1|β∇v) = 0 in BR(x0)
is symmetric with respect to ∂Rm+1+ if, and only if, it is a weak solution of the
Neumann-type problem (2.4.5) in B+R(x0) by Lemma 2.4.2.2. Hence the above
theorem applies to solutions of this problem as well.
We will use the notation ∂ki v = ∂kv∂xki
for i = 1, . . . ,m + 1 and k ∈ N. Fur-
thermore, we define v∗ := |xm+1|β∂m+1v. This function is significant and will
be integral to our proof of Theorem 4.1.0.1 because, as we will see in more de-
tail later, it satisfies div(|xm+1|−β∇v∗) = 0 when div(|xm+1|β∇v) = 0 and v is
symmetric with respect to ∂Rm+1+ .
We proceed by proving the required monotonicity holds for the derivatives ∂iv,
where i = 1, . . . ,m, of a solution to div(|xm+1|β∇v) = 0 in BR(x0). Treatment of
the derivatives ∂m+1v requires a slightly different approach depending on whether
β < 0 or β > 0.
First, we consider the differentiability of solutions of div(|xm+1|β∇v) = 0
in general. We will describe results on differentiability in the directions xi for
i = 1, . . . ,m. In turn, these results will provide the information we need about
the derivatives in the xm+1 direction when the solutions are symmetric with
respect to ∂Rm+1+ .
Let i = 1, . . . ,m and let h ∈ R. Define the difference quotient of a map
v : Ω → Rn by ∆hi v(x) = h−1(v(x + hei) − v(x)) where ei denotes the i-th basis
vector in Rm+1 and dist(x, ∂Ω) < |h|.
Lemma 4.1.0.1. Let Ω ⊂ Rm+1 be open and v ∈ W 1,2β (Ω;Rn). Then for any
i = 1, . . . ,m we have ∆hi v ∈ L2
β(K;Rn) for any compact K ⊂ Ω, provided |h| <dist(K, ∂Ω). In particular,∫
K
|xm+1|β|∆hi v|2dx ≤
∫Ω
|xm+1|β |∂iv|2 dx.
Proof. This proof follows the proof of Lemma 7.23 in [21]. We assume that h ≥ 0,
the argument for negative h is analogous. Let v ∈ C1(Ω;Rn)∩W 1,2β (Ω;Rn). Then
for any i = 1, . . . ,m we have
∆hi v(x) =
1
h
∫ h
0
∂iv(x+ tei)dt.
140
Hence
|∆hi v(x)|2 =
∣∣∣∣1h∫ h
0
∂iv(x+ tei)dt
∣∣∣∣2 ≤ 1
h
∫ h
0
|∂iv(x+ tei)|2 dt.
Thus, using the notation Kh = x ∈ Rm+1 : dist(x,K) ≤ h and noting Kh ⊂ Ω,
by Fubini’s Theorem and the compactness of K, for h with |h| < dist(K, ∂Ω) we
have ∫K
|xm+1|β|∆hi v|2dx ≤
∫K
|xm+1|β1
h
∫ h
0
|∂iv(x+ tei)|2 dtdx
≤ 1
h
∫ h
0
∫Kh
|xm+1|β |∂iv|2 dxdt
≤∫
Ω
|xm+1|β |∂iv|2 dx.
We deduce the result for v ∈ W 1,2β (Ω;Rn) by approximation.
Next we prove (essentially) the reverse implication. Let Ω ⊂ Rm+1 be a
domain.
Lemma 4.1.0.2. Suppose Ω ⊂ Rm+1 is open and bounded and let v ∈ L2β(Ω;Rn).
For any i = 1, . . . ,m, suppose there exist constants M > 0 and h > 0 such that∫K
|xm+1|β|∆hi v|2dx ≤M
for every h 6= 0 with |h| < h and compact K ⊂ Ω with dist(K, ∂Ω) > |h|. Then
the weak derivative ∂iv exists in Ω and satisfies∫Ω
|xm+1|β |∂iv|2 dx ≤M.
Proof. First choose a sequence (hk)k∈N with hk → 0, discard hk with |hk| ≥ h, re-
index to k ∈ N and define vhki (x) = ∆hki v(x) when x ∈ Ω and dist(x, ∂Ω) ≥ 2|hk|
and vhki = 0 otherwise. As a consequence of the assumptions in the lemma,
vhki k∈N is a bounded sequence in the Hilbert space L2β(Ω;Rn). Hence there
is a subsequence, which we do not relabel, such that hk → 0 and vhki → vi
weakly in L2β(Ω;Rn). Furthermore, this convergence, together with the weak
lower semi-continuity of a Hilbert space norm, guarantees that∫
Ωxβm+1 |vi|
2 dx ≤M . Analogous calculations to those in the proof of Lemmata 2.2.1.2, 2.2.1.3 and
2.2.1.4 imply that L2β(Ω;Rn) ⊂ Lp(Ω;Rn) for some p ∈ (1, 2] depending on β.
Hence, since every linear functional on Lp(Ω;Rn) restricts to a linear functional
141
on L2β(Ω;Rn), we also have that vhki converges to vi weakly in Lp(Ω;Rn). Thus
we deduce, as in the proof of Lemma 7.24 in [21], that vi is the weak derivative
∂iv.
Now we consider the derivatives ∂iv of solutions to div(|xm+1|β∇v) = 0 for
i = 1, . . . ,m.
Lemma 4.1.0.3. Let v ∈ W 1,2β (BR(x0);Rn) and suppose v is a weak solution
of div(|xm+1|β∇v) = 0 in BR(x0). Then for every r < R and i = 1, . . . ,m,
∂iv ∈ W 1,2β (Br(x0);Rn) and ∂iv is a weak solution of div(|xm+1|β∇v) = 0 in
Br(x0).
Proof. Recall that v satisfies∫BR(x0)
|xm+1|β 〈∇v,∇φ〉 dx (4.1.1)
for every φ ∈ W 1,2β,0(BR(x0);Rn) by Remark 2.4.0.1. Let r < R and choose
η ∈ C∞0 (BR(x0)) with η ≡ 1 in Br(x0), η ≡ 0 in BR(x0)\Br+R−r2
(x0), 0 ≤ η ≤ 1
and |∇η| ≤ CR−r . Let ∆h
i v be the difference quotient of v for some i = 1, . . . ,m
and suppose |h| < R−r4
. Then φ = −∆−hi (η2∆hi v) ∈ W 1,2
β,0(BR(x0);Rn). We
substitute this φ into (4.1.1) and integrate by parts to see that∫BR(x0)
η2|xm+1|β|∇∆hi v|2dx = −
∫BR(x0)
2η|xm+1|β⟨∇∆h
i v · ∇η,∆hi v⟩
dx.
Since |∇η| ≤ CR−r we have∫
BR(x0)
η2|xm+1|β|∇∆hi v|2dx ≤ C
R− r
∫BR(x0)
η|xm+1|β|∇∆hi v||∆h
i v|dx.
An application of Young’s inequality, ab ≤ δ a2
2+ δ−1 a2
2for a, b ≥ 0 and δ > 0,
and Lemma 4.1.0.1 yields∫BR(x0)
η2|xm+1|β|∇∆hi v|2dx ≤ C
R− rδ
∫BR(x0)
η2|xm+1|β|∇∆hi v|2dx
+C
R− rδ−1
∫BR(x0)
|xm+1|β|∂iv|2dx.
142
Choosing δ = R−r2C
we deduce that∫Br(x0)
|xm+1|β|∇∆hi v|2dx ≤
∫BR(x0)
η2|xm+1|β|∇∆hi v|2dx
≤ C
(R− r)2
∫BR(x0)
|xm+1|β|∂iv|2dx.
The right hand side above is independent of h and so by Lemma 4.1.0.2
the weak derivative ∇∂iv exists and is in L2β(Br(x0);R(m+1)n). Hence ∂iv ∈
W 1,2β (Br(x0);Rn) for every r < R. Finally, we integrate by parts in (4.1.1) to see
that
0 =
∫Br(x0)
|xm+1|β 〈∇v,∇∂iφ〉 dx = −∫Br(x0)
|xm+1|β 〈∇∂iv,∇φ〉 dx.
Hence ∂iv is a weak solution of div(|xm+1|β∇v) = 0 in Br(x0) for every r < R.
We will need to consider the higher regularity of solutions of div(|xm+1|β∇v) =
0 in balls centred on ∂Rm+1+ . Solutions of this equation are smooth in such a ball
away from ∂Rm+1+ and we require results dealing explicitly with regularity on
∂Rm+1+ . Estimates for the Holder norms of all derivatives Dαv, where α is a
multi-index with (α)m+1 = 0, are given in Proposition 2.1, Corollary 2.5 and
Proposition 2.6 of [7], for example. These estimates can be derived directly, or
by applying known theory for equations of the type we consider, see for instance
Theorem 6.6 of [25]. We only need the property of continuity, rather than the
explicit bounds obtained in the aforementioned literature. For the most part,
this follows from the theory already described in this chapter.
Lemma 4.1.0.4. Suppose v ∈ W 1,2β (BR(x0);Rn) and assume v weakly satisifes
div(|xm+1|β∇v) = 0 in BR(x0). Then the derivatives Dαv, where α is a multi-
index with (α)m+1 = 0, are continuous in BR(x0). If v is symmetric with respect
to ∂Rm+1+ then so is Dαv whenever α is a multi-index with (α)m+1 = 0.
Proof. We know that v is smooth in BR(x0)\∂Rm+1+ by linear elliptic regularity
theory. Lemma 4.1.0.3 implies that ∂iv is a weak solution of div(|xm+1|β∇v) = 0
in Br(x0) for every r < R. Hence, using Lemma 2.4.3.1, we deduce that ∂iv is
locally Holder continuous, and therefore continuous, inBr(x0) for every r < R. As
a result ∂iv is continuous in BR(x0). Applying this process now to the derivatives
∂i∂jv for i, j = 1, . . . ,m, we see that these derivatives are weak solutions of
div(|xm+1|β∇v) = 0 in Br(x0) for every r < R and are therefore continuous in
BR(x0). We can inductively repeat this process for Dαv where α is a multi-index
143
with (α)m+1 = 0. Symmetry of Dαv with respect to ∂Rm+1+ follows from the
corresponding symmetry of v.
Now we need to discuss regularity in the xm+1 direction. First, we record a
consequence of a result of [4].
Lemma 4.1.0.5 (Consequence of [4] Lemma 4.5). Let β ∈ (−1, 1) and let v ∈L∞(B+
2r(x0))∩W 1,2β (B+
2r(x0)) be a weak solution the Neumann-type problem 2.4.5
in B+2r(x0). Then there is a γ ∈ (0, 1) depending on m,β such that v, xβm+1
∂v∂xm+1
∈C0,γ(B+
r (x0)).
Together with our previous theory, this result implies the following.
Lemma 4.1.0.6. Suppose v ∈ W 1,2β (BR(x0);Rn) and assume v is a weak solution
of div(|xm+1|β∇v) = 0 in BR(x0) which is symmetric with respect to ∂Rm+1+ . Then
v∗ := |xm+1|β∂m+1v is continuous in BR(x0), v∗|∂0B+R(x0) = 0 and v∗ is odd with
respect to ∂Rm+1+ , that is v∗(x′, xm+1) = −v∗(x′,−xm+1) for every (x′, xm+1) ∈
BR(x0). Furthermore, v∗ ∈ W 1,2−β (Br(x0);Rn) and satisfies
div(|xm+1|−β∇v∗) = 0
weakly in Br(x0) for every r < R.
Proof. If v is as stated in the assumptions of the lemma then elliptic regularity
theory shows that v∗ is smooth in BR(x0)\∂Rm+1+ [21]. Fix y ∈ BR(x0) with
ym+1 = 0 and choose s > 0 such that Bs(y) ⊂ BR(x0). Lemma 2.4.3.1 implies
that v is continuous, and hence bounded, in Br(x0) for every r < R. Hence
choosing r < R with Bs(y) ⊂ Br(x0) we see that v is continuous and bounded in
Bs(y). Furthermore, since v is symmetric with respect to ∂Rm+1+ , it follows from
Lemma 2.4.2.2 that v is a weak solution of the Neumann type problem (2.4.5) in
B+R(x0) and hence in B+
s (y). Thus we may apply Lemma 4.1.0.5 to see that v∗ is
continuous in B+s2(y). This holds for every y ∈ BR(x0) with ym+1 = 0 and so v∗
is continuous in B+R(x0) ∪ ∂0B+
R(x0). As a result, using the fact that v is a weak
solution of the Neumann type problem (2.4.5) we see that v∗(x′, 0) = 0 for every
(x′, 0) ∈ ∂0B+R(x0).
For every x = (x′, xm+1) ∈ BR(x0)\∂Rm+1+ , using the symmetry of v with
respect to ∂Rm+1+ , we calculate ∂m+1v(x′, xm+1) = −∂m+1v(x′,−xm+1). Conse-
quently, v∗(x′, xm+1) = −v∗(x′,−xm+1) for every (x′, xm+1) ∈ BR(x0)\∂Rm+1+ .
It follows that limxm+1→0− v∗(x′, xm+1) = − limxm+1→0+ v∗(x′, xm+1) = 0 for ev-
ery (x′, 0) ∈ ∂0B+R(x0). Thus we deduce that v∗ is continuous in BR(x0) and
v∗|∂0B+R(x0) = 0.
144
Next we show that v∗ ∈ W 1,2−β (Br(x0);Rn) for every r < R. To see this
observe that Lemma 4.1.0.3 implies ∂iv ∈ W 1,2β (Br(x0);Rn) for every r < R and
i = 1, . . . ,m. It follows that∫Br(x0)
|xm+1|−β|∂iv∗|2dx =
∫Br(x0)
|xm+1|β|∂i∂m+1|2dx <∞ (4.1.2)
for i = 1, . . . ,m. We also note that ∆′v ∈ W 1,2β (Br(x0);Rn) by Lemma 4.1.0.3,
where ∆′ is the Laplace operator with respect to the variables x1, . . . , xm. Fur-
thermore, as v solves div(|xm+1|β∇v) = 0 classically in BR(x0)\∂Rm+1+ , we have
|xm+1|−β∂m+1v∗ = −∆′v ∈ W 1,2
β (Br(x0);Rn) for every r < R. Hence∫Br(x0)
|xm+1|−β|∂m+1v∗|2dx =
∫Br(x0)
|xm+1|β||xm+1|−β∂m+1v∗|2dx
=
∫Br(x0)
|xm+1|β|∆′v|2dx <∞. (4.1.3)
The combination of (4.1.2) and (4.1.3) implies∫Br(x0)
|xm+1|−β|∇v∗|2dx <∞ for
every r < R and since∫Br(x0)
|xm+1|−β|v∗|2dx =
∫Br(x0)
|xm+1|β|∂m+1v|2dx <∞, (4.1.4)
we deduce that v∗ ∈ W 1,2−β (Br(x0);Rn).
Finally we show that v∗ is a weak solution of div(|xm+1|−β∇v∗) = 0 in Br(x0)
for every r < R. In analogy with the calculations in [5] we calculate
div(x−βm+1∇v∗) = x−βm+1∂m+1(div(xβm+1∇v)) = 0 (4.1.5)
in B+R(x0) classically. Hence, v∗ is continuous in B+
r (x0) for every r < R
and weakly satisfies div(x−βm+1∇(v∗|B+r (x0)
)) = 0 on these sets. Furthermore,
v∗|∂0B+r (x0) = 0 so Lemma 4.0.0.3 thus implies that the odd reflection of v∗ in
∂Rm+1+ is a weak solution of div(|xm+1|−β∇v∗) = 0 in Br(x0). However, the odd
reflection of v∗|B+r (x0)
coincides with the way v∗ is already defined. This holds for
all r < R which concludes the proof.
With the preceding regularity theory in hand, we are ready to commence the
proof of Theorem 4.1.0.1. As mentioned previously, we treat the derivatives xi
for i = 1, . . . ,m first and then consider those with respect to xm+1. We begin
with the following preliminary lemma.
145
Lemma 4.1.0.7. Suppose that v ∈ W 1,2β (BR(x0)) and that∫
∂Bρ(x0)
ν · |xm+1|β∇vdσ(x) ≥ 0
for almost every ρ ∈ (0, R), where ν is the outward pointing unit normal on
∂Bρ(x0), then
s−(1+m+β)
∫Bs(x0)
|xm+1|βvdx ≤ r−(1+m+β)
∫Br(x0)
|xm+1|βvdx (4.1.6)
for every 0 < s ≤ r ≤ R.
Proof. This proof follows the proof of Theorem 2.1 in Section 2 of [21] and the
proof of Proposition 2.2 in Section III of [20]. Suppose v satisfies the assumptions
of the lemma. For almost every 0 < s ≤ r < R the following holds. Using Fubini’s
Theorem, we calculate
r−(m+β)
∫∂Br(x0)
|xm+1|βvdσ(x)− s−(m+β)
∫∂Bs(x0)
|xm+1|βvdσ(x)
=
∫∂B1(0)
|ωm+1|β(v(rω + x0)− v(sω + x0))dω
=
∫∂B1(0)
|ωm+1|β∫ r
s
∂
∂tv(tω + x0)dtdω
=
∫ r
s
∫∂B1(0)
|ωm+1|βω · ∇v(tω + x0)dωdt
=
∫ r
s
t−(m+β)
∫∂Bt(x0)
|xm+1|βν · ∇vdσ(x)dt
≥ 0. (4.1.7)
Define the function f(r) =∫Br(x0)
|xm+1|βvdx for 0 < r ≤ R and observe that
f(r) is an absolutely continuous function of r with f ′(r) =∫∂Br(x0)
|xm+1|βvdσ(x).
Using (4.1.7) we calculate
f(r) =
∫ r
0
f ′(ρ)dρ =
∫ r
0
ρm+βρ−(m+β)f ′(ρ)dρ
≤∫ r
0
ρm+βr−(m+β)f ′(r)dρ
=r
1 +m+ βf ′(r) (4.1.8)
for 0 < r < R. Multiplying the above inequality by r−(1+m+β) and rearranging
146
yields
0 ≤ r−(1+m+β)f ′(r)− (1 +m+ β)r−(2+m+β)f(r). (4.1.9)
As a result, we calculate
d
dr(r−(1+m+β)f(r)) = r−(1+m+β)f ′(r)− (1 +m+ β)r−(2+m+β)f(r) ≥ 0. (4.1.10)
Integrating between s ≤ r ≤ R completes the proof.
Now we consider the monotonicity formula for derivatives with respect to the
variables xi for i = 1, . . . ,m.
Lemma 4.1.0.8. Let v ∈ W 1,2β (BR(x0);Rn) and suppose that v is a weak solution
of div(|xm+1|β∇v) = 0 in BR(x0) which is symmetric with respect to ∂Rm+1+ . Let
α be a multi-index with αm+1 = 0. Then for every 0 < s ≤ r < R we have
s−(1+m+β)
∫Bs(x0)
|xm+1|β|Dαv|2dx ≤ r−(1+m+β)
∫Br(x0)
|xm+1|β|Dαv|2dx.
Proof. First note that v is smooth in BR(x0)\∂Rm+1+ and div(|xm+1|β∇Dαv) = 0
classically in this set for any multi-index with αm+1 = 0. Fix R > r > ε > 0.
Define Bεr(x0) = Br(x0) ∩ x ∈ Rm+1 : |xm+1| > ε. Observe that in Bε
r(x0) we
have
div(|xm+1|β∇|Dαv|2) = 2|xm+1|β|∇Dαv|2 + 2〈Dαv, div(|xm+1|β∇Dαv)〉 ≥ 0
classically. Furthermore, notice that for any r > ε > 0 the domain Bεr(x0)
is Lipschitz. Hence the Divergence Theorem may be applied on this set. We
calculate
0 ≤∫Bεr(x0)
div(|xm+1|β∇|Dαv|2)dx
=
∫∂Br(x0)
1Bεr(x0)|xm+1|βν · ∇|Dαv|2dσ(x)
−∫Bm√
r2−ε2(x0)
εβem+1 · ∇(|Dαv|2(x′, ε)− |Dαv|2(x′,−ε))dx′ (4.1.11)
where 1Bεr(x0) is the indicator function of Bεr(x0) and ν is the outward unit normal
on ∂Br(x0). We consider the terms on the right hand side above separately with
a view to taking the limit as ε→ 0+.
147
To facilitate this we recall the necessary regularity results for v. For every r <
R, each Dαv ∈ W 1,2β (Br(x0);Rn) and is a weak solution of div(|xm+1|β∇Dαv) = 0
in Br(x0) by Lemma 4.1.0.3. Moreover, each Dαv is continuous in BR(x0) and
symmetric with respect to ∂Rm+1+ by Lemma 4.1.0.4. Hence, Lemma 4.1.0.6 thus
implies (Dαv)∗ = |xm+1|β∂m+1Dαv is continuous inBR(x0) with (Dαv)∗|∂0B+
R(x0) =
0. Since (Dαv)∗ = |xm+1|β∂m+1Dαv and ∂iD
αv, where i = 1, . . . ,m, are continu-
ous, they are bounded in Br(x0) for every r < R. Consequently we calculate
||xm+1|βν · ∇|Dαv|2| ≤ 2∣∣|xm+1|β
⟨νm+1∂m+1D
αv,Dαv⟩∣∣
+ 2
∣∣∣∣∣m∑i=1
|xm+1|β⟨νi∂iD
αv,Dαv⟩∣∣∣∣∣
≤ C(1 + |xm+1|β).
It follows that
|1Bεr(x0)|xm+1|βν · ∇|Dαv|2| ≤ C(1 + |xm+1|β)
for every ε > 0. Therefore, applying Lebesgue’s Dominated Convergence Theo-
rem, we see that
limε→0+
∫∂Br(x0)
1Bεr(x0)|xm+1|βν · ∇|Dαv|2dσ(x) =
∫∂Br(x0)
|xm+1|βν · ∇|Dαv|2dσ(x).
(4.1.12)
Now we deal with the other term on the right hand side of (4.1.11). Since
∂m+1Dαv(x′, ε) = −∂m+1D
αv(x′,−ε) and Dαv(x′, ε) = Dαv(x′,−ε), we calculate
em+1 · ∇(|Dαv|2(x′, ε)− |Dαv|2(x′,−ε))
= 2⟨∂m+1D
αv(x′, ε), Dαv(x′, ε)⟩− 2
⟨∂m+1D
αv(x′,−ε), Dαv(x′,−ε)⟩
= 4⟨∂m+1D
αv(x′, ε), Dαv(x′, ε)⟩.
Moreover, we note that for any r < R, Dαv is uniformly bounded on Br(x0)
and 1Bm√r2−ε2
(x0)εβ∂m+1D
αv(x′, ε) = 1Bm√r2−ε2
(x0)(Dαv)∗(x′, ε) → 0 uniformly in
Bmr (x0) as ε→ 0+. We deduce that 1Bm√
r2−ε2(x0)ε
β⟨∂m+1D
αv(x′, ε), Dαv(x′, ε)⟩→
148
0 uniformly as ε→ 0+. Hence
limε→0+
∫Bm√
r2−ε2(x0)
εβem+1 · ∇(|Dαv|2(x′, ε)− |Dαv|2(x′,−ε))dx′
= 4 limε→0+
∫Bmr (x0)
1Bm√r2−ε2
(x0)εβ⟨∂m+1D
αv(x′, ε), Dαv(x′, ε)⟩
dx′ = 0. (4.1.13)
We combine (4.1.11), (4.1.12) and (4.1.13) to see that
0 ≤ limε→0+
∫Bεr(x0)
div(|xm+1|β∇|Dαv|2)dx =
∫∂Br(x0)
|xm+1|βν · ∇|Dαv|2dσ(x).
(4.1.14)
This holds for every r < R. Applying Lemma 4.1.0.7 concludes the proof.
Now we consider the monotonicity of derivatives with respect to xm+1. The
following lemma holds for all β ∈ (−1, 1) but, as we will see shortly, only yields
sufficient information to prove Theorem 4.1.0.1 (when combined with the preced-
ing Lemma) when β ∈ (−1, 0).
Lemma 4.1.0.9. Suppose v is a weak solution of div(|xm+1|β∇v) = 0 in BR(x0)
which is symmetric with respect to ∂Rm+1+ . Let α be a multi-index with αm+1 = 0.
Then for every 0 < s ≤ r < R we have
s−(1+m−β)
∫Bs(x0)
|xm+1|β|∂m+1Dαv|2dx ≤ r−(1+m−β)
∫Br(x0)
|xm+1|β|∂m+1Dαv|2dx.
Proof. The proof of this lemma is similar to the proof of Lemma 4.1.0.8. Recall
that v is smooth in BR(x0)\∂Rm+1+ . It follows that div(|xm+1|−β∇(Dαv)∗) = 0
classically in BR(x0)\∂Rm+1+ . Fix R > r > ε > 0. Define Bε
r(x0) = Br(x0)∩x ∈Rm+1 : |xm+1| > ε. Observe that in Bε
r(x0) we have
div(|xm+1|−β∇|(Dαv)∗|2) = 2|xm+1|β|∇(Dαv)∗|2
+ 2〈(Dαv)∗, div(|xm+1|−β∇(Dαv)∗)〉 ≥ 0
classically. Furthermore, notice that for any r > ε > 0 the domain Bεr(x0)
is Lipschitz. Hence the Divergence Theorem may be applied on this set. We
149
calculate
0 ≤∫Bεr(x0)
div(|xm+1|−β∇|(Dαv)∗|2)dx
=
∫∂Br(x0)
1Bεr(x0)|xm+1|−βν · ∇|(Dαv)∗|2dσ(x)
−∫Bm√
r2−ε2(x0)
ε−βem+1 · ∇(|(Dαv)∗|2(x′, ε)− |(Dαv)∗|2(x′,−ε))dx′ (4.1.15)
where 1Bεr(x0) is the indicator function of Bεr(x0) and ν is the outward unit normal
on ∂Br(x0). We consider the terms on the right hand side above separately with
a view to taking the limit as ε→ 0+.
We recall the regularity theory, for v and its derivatives, which is required
to facilitate this procedure. For every r < R, each Dαv ∈ W 1,2β (Br(x0);Rn)
and is a weak solution of div(|xm+1|β∇Dαv) = 0 in Br(x0) by Lemma 4.1.0.3.
Furthermore, each Dαv is continuous in BR(x0) and symmetric with respect to
∂Rm+1+ by Lemma 4.1.0.4. We conclude, using Lemma 4.1.0.6, that (Dαv)∗ =
|xm+1|β∂m+1Dαv is continuous in BR(x0) with (Dαv)∗|∂0B+
R(x0) = 0. We fur-
ther note that Lemma 4.1.0.6 implies that for every r < R, we have (Dαv)∗ ∈W 1,2−β (Br(x0);Rn) and (Dαv)∗ is a weak solution of div(|xm+1|−β∇(Dαv)∗) = 0 in
Br(x0). Another application of Lemma 4.1.0.4 implies that for every r < R and
i = 1, . . . ,m, the derivatives ∂i(Dαv)∗ are continuous in Br(x0).
Using the preceding observations we see that |xm+1|−β∂m+1(Dαv)∗ = −∆′Dαv
is continuous in BR(x0) and bounded in Br(x0) for every r < R. Furthermore,
the continuity of (Dαv)∗ = |xm+1|β∂m+1Dαv and ∂i(D
αv)∗, where i = 1, . . . ,m,
yields their boundedness in Br(x0). Hence, we have
||xm+1|−βν · ∇|(Dαv)∗|2| ≤ 2∣∣|xm+1|−β
⟨νm+1∂m+1(Dαv)∗, (Dαv)∗
⟩∣∣+ 2
∣∣∣∣∣m∑i=1
|xm+1|−β⟨νi∂i(D
αv)∗, (Dαv)∗⟩∣∣∣∣∣
≤ C(1 + |xm+1|−β).
It follows that
|1Bεr(x0)|xm+1|−βν · ∇|(Dαv)∗|2| ≤ C(1 + |xm+1|−β)
for every ε ∈ (0, r). Therefore, applying Lebesgue’s Dominated Convergence
150
Theorem, we see that
limε→0+
∫∂Br(x0)
1Bεr(x0)|xm+1|−βν · ∇|(Dαv)∗|2dσ(x)
=
∫∂Br(x0)
|xm+1|−βν · ∇|(Dαv)∗|2dσ(x). (4.1.16)
Now we deal with the other term on the right hand side of (4.1.15). We have
∂m+1(Dαv)∗(x′, ε) = ∂m+1(Dαv)∗(x′,−ε) and (Dαv)∗(x′, ε) = −(Dαv)∗(x′,−ε).Thus
em+1 · ∇(|(Dαv)∗|2(x′, ε)− |(Dαv)∗|2(x′,−ε))
= 2⟨∂m+1(Dαv)∗(x′, ε), (Dαv)∗(x′, ε)
⟩− 2
⟨∂m+1(Dαv)∗(x′,−ε), (Dαv)∗(x′,−ε)
⟩= 4
⟨∂m+1(Dαv)∗(x′, ε), (Dαv)∗(x′, ε)
⟩.
We observe that 1Bm√r2−ε2
(x0)εβ∂m+1D
αv(x′, ε) = 1Bm√r2−ε2
(x0)(Dαv)∗(x′, ε)→ 0
uniformly in Bmr (x0) as ε→ 0+ and |xm+1|−β∂m+1(Dαv)∗ = −∆′Dαv is uniformly
bounded Br(x0). Thus 1Bm√r2−ε2
(x0)ε−β ⟨∂m+1(Dαv)∗(x′, ε), (Dαv)∗(x′, ε)
⟩→ 0
uniformly as ε→ 0+. Hence
limε→0+
∫Bm√
r2−ε2(x0)
ε−βem+1 · ∇(|(Dαv)∗|2(x′, ε)− |(Dαv)∗|2(x′,−ε))dx′
= 4 limε→0+
∫Bm√
r2−ε2(x0)
ε−β⟨∂m+1(Dαv)∗(x′, ε), (Dαv)∗(x′, ε)
⟩dx′ = 0. (4.1.17)
We combine (4.1.15), (4.1.16) and (4.1.17) to see that
0 ≤ limε→0+
∫Bεr(x0)
div(|xm+1|−β∇|(Dαv)∗|2)dx
=
∫∂Br(x0)
|xm+1|−βν · ∇|(Dαv)∗|2dσ(x).
This holds for every r < R. We apply Lemma 4.1.0.7, noting that∫Br(x0)
|xm+1|−β|(Dαv)∗|2dx =
∫Br(x0)
|xm+1|β|∂m+1Dαv|2dx,
to conclude the proof.
Remark 4.1.0.2. This lemma indicates the derivatives (Dαv)∗ corresponding to
solutions of the Neumann problem (2.4.5) satisfy a stronger monotonicity prop-
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erty than stated in Theorem 4.1.0.1 if β ∈ (−1, 0) and a weaker such property if
β ∈ (0, 1). We will make use of this fact to prove the theorem for β ∈ (−1, 0) in
the following lemma.
Lemma 4.1.0.10. Let BR(x0) ⊂ Rm+1 with (x0)m+1 = 0 and R ≤ 1 and suppose
v ∈ W 1,2β (BR(x0);Rn) is a weak solution of div(|xm+1|β∇v) = 0 in BR(x0). If v
is symmetric with respect to ∂Rm+1+ in BR(x0) and β ∈ (−1, 0) then
s−(1+m+β)
∫Bs(x0)
|xm+1|β|∇v|2dx ≤ r−(1+m+β)
∫Br(x0)
|xm+1|β|∇v|2dx
for every 0 < s ≤ r ≤ R.
Proof. Lemma 4.1.0.8 implies that
s−(1+m+β)
∫Bs(x0)
|xm+1|β|∇′v|2dx ≤ r−(1+m+β)
∫Br(x0)
|xm+1|β|∇′v|2dx (4.1.18)
for every 0 < s ≤ r < R. Moreover, Lemma 4.1.0.9 implies that
s−(1+m−β)
∫Bs(x0)
|xm+1|β|∂m+1v|2dx ≤ r−(1+m−β)
∫Br(x0)
|xm+1|β|∂m+1v|2dx
for every 0 < s ≤ r < R. However, if β < 0 then s−(1+m+β) = s−2βs−(1+m−β) and
hence
s−(1+m+β)
∫Bs(x0)
|xm+1|β|∂m+1v|2dx
= s−2βs−(1+m−β)
∫Bs(x0)
|xm+1|β|∂m+1v|2dx
≤ s−2βr−(1+m−β)
∫Br(x0)
|xm+1|β|∂m+1v|2dx
=(sr
)−2β
r−(1+m+β)
∫Br(x0)
|xm+1|β|∂m+1v|2dx
≤ r−(1+m+β)
∫Br(x0)
|xm+1|β|∂m+1v|2dx. (4.1.19)
Adding together (4.1.18) and (4.1.19) concludes the proof of the lemma for all
0 < s ≤ r < R. As v ∈ W 1,2β (BR(x0);Rn), we conclude the statement for r = R
using Lebesgue’s Dominated Convergence Theorem.
Remark 4.1.0.3. This lemma proves Theorem 4.1.0.1 when β ∈ (−1, 0).
It remains to show that Theorem 4.1.0.1 is satisfied when β ∈ (0, 1). Our
152
method is similar to the proof of Lemma 4.1.0.9, but instead of considering the
quantity div(|xm+1|−β∇|v∗|2) we consider div(|xm+1|β∇|∂m+1v|2) .
Lemma 4.1.0.11. Let β ∈ (0, 1) and suppose v ∈ W 1,2β (BR(x0);Rn) is a weak
solution of div(|xm+1|β∇v) = 0 in BR(x0) which is symmetric with respect to
∂Rm+1+ . Let α be a multi-index with αm+1 = 0. Then for every 0 < s ≤ r < R
we have
s−(1+m+β)
∫Bs(x0)
|xm+1|β|∂m+1Dαv|2dx ≤ r−(1+m+β)
∫Br(x0)
|xm+1|β|∂m+1Dαv|2dx.
Proof. Recall that v is smooth in BR(x0)\∂Rm+1+ . Fix R > r > ε > 0. Define
Bεr(x0) = Br(x0) ∩ x ∈ Rm+1 : |xm+1| > ε. We calculate
div(|xm+1|β∇|∂m+1Dαv|2) = 2|xm+1|β|∇∂m+1D
αv|2
+ 2〈∂m+1Dαv, div(|xm+1|β∇∂m+1D
αv)〉 (4.1.20)
classically in Bεr(x0). In contrast to the considerations of analogous terms in the
proof of Lemmata 4.1.0.8 and 4.1.0.9, the term div(|xm+1|β∇∂m+1Dαv) need not
vanish. We can, however, still show that the right hand side above is positive
when β ∈ (0, 1). As div(|xm+1|β∇Dαv) = 0 in Bεr(x0) we find
0 = ∂m+1div(|xm+1|β∇Dαv) = |xm+1|β∆∂m+1Dαv
+ sgn(xm+1)β|xm+1|β−1∆Dαv
+ sgn(xm+1)β|xm+1|β−1∂2m+1D
αv
+ β(β − 1)|xm+1|β−2∂m+1Dαv
= div(|xm+1|β∇∂m+1Dαv)
+ sgn(xm+1)β
|xm+1|div(|xm+1|β∇Dαv)
− β|xm+1|β−2∂m+1Dαv
= div(|xm+1|β∇∂m+1Dαv)
− β|xm+1|β−2∂m+1Dαv.
Hence
div(|xm+1|β∇∂m+1Dαv) = β|xm+1|β−2∂m+1D
αv (4.1.21)
153
in Bεr(x0). We conclude from (4.1.20) and (4.1.21) that
div(|xm+1|β∇|∂m+1Dαv|2) = 2|xm+1|β|∇∂m+1D
αv|2
+ 2β|xm+1|β−2|∂m+1Dαv|2 ≥ 0.
An application of the Divergence Theorem on Bεr(x0) yields
0 ≤∫Bεr(x0)
div(|xm+1|β∇|∂m+1Dαv|2)dx
=
∫∂Br(x0)
1Bεr(x0)|xm+1|βν · ∇|∂m+1Dαv|2dσ(x)
−∫Bm√
r2−ε2(x0)
εβem+1 · ∇(|∂m+1Dαv|2(x′, ε)− |∂m+1D
αv|2(x′,−ε))dx′
(4.1.22)
where 1Bεr(x0) is the indicator function of Bεr(x0) and ν is the outward unit normal
on ∂Br(x0). We consider the terms on the right hand side above separately with
a view to taking the limit as ε→ 0+.
We recall the required regularity results for v. Observe that each Dαv is
continuous in BR(x0) and symmetric with respect to ∂Rm+1+ by Lemma 4.1.0.4.
For every r < R, each Dαv ∈ W 1,2β (Br(x0);Rn) and is a weak solution of
div(|xm+1|β∇Dαv) = 0 in Br(x0) by Lemma 4.1.0.3. Lemma 4.1.0.6 implies
that (Dαv)∗ = |xm+1|β∂m+1Dαv is continuous in BR(x0) with (Dαv)∗|∂0B+
R(x0) =
0. Hence (Dαv)∗ is bounded in Br(x0) for every r < R. We also note that
|xm+1|−β∂m+1(Dαv)∗ = −∆′Dαv is continuous in BR(x0) and thus also bounded
in Br(x0) for every r < R. The same is true for ∂m+1(Dαv)∗ = −|xm+1|β∆′Dαv
and we see additionally that ∂m+1(Dαv)∗|∂0B+R(x0) = 0. An application of Lemma
4.1.0.4 implies that for every r < R and i = 1, . . . ,m, the derivatives ∂i(Dαv)∗
are continuous in Br(x0). The preceding statements hold for every multi-index α
with αm+1 = 0.
Now we show that the derivative ∂m+1Dαv(x′, 0) exists and is equal to 0 for
(x′, 0) ∈ ∂0B+R(x0). Fix such an (x′, 0), note that (x′, 0) ∈ Br(x0) for some r < R
and choose h with |h| sufficiently small as to ensure (x′, h) ∈ Br(x0). Using the
154
aforementioned properties of v, together with the Mean Value Theorem, we find
|h|−1|Dαv(x′, h)−Dαv(x′, 0)| = |∂m+1Dαv(x′, xm+1)|
= |xm+1|−β|(Dαv)∗(x′, xm+1)− 0|
= |xm+1|−β|∂m+1(Dαv)∗(x′, ξ)||xm+1|
≤ |xm+1|||ξ|−β∂m+1(Dαv)∗(x′, ξ)|
≤ C|h| → 0 as h→ 0, (4.1.23)
where xm+1 with |xm+1| ∈ (0, |h|) and ξ with |ξ| ∈ (0, |xm+1|) are chosen such
that the Mean Value Theorem holds. Notice that (4.1.23) holds for every (x′, 0) ∈∂0B+
R(x0) and thus we see that ∂m+1Dαv exists and is equal to zero on ∂0B+
R(x0).
Similar calculations to those on the right hand side of (4.1.23) show that ∂m+1Dαv
is continuous at every point in ∂0B+R(x0). Noting that ∂m+1D
αv is smooth in
BR(x0)\∂Rm+1+ , we conclude it is continuous in BR(x0).
Next we show |xm+1|β∂2m+1D
αv is bounded in Br(x0)\∂Rm+1+ for every r < R;
we already know it is continuous in BR(x0)\∂Rm+1+ . We calculate
|xm+1|β∂2m+1D
αv = ∂m+1(Dαv)∗ − βx−1m+1(Dαv)∗. (4.1.24)
Recall that (Dαv)∗ = 0 on ∂0B+R(x0) and (Dαv)∗, ∂m+1(Dαv)∗ are continuous in
BR(x0) and hence bounded in Br(x0) for every r < R. We therefore deduce, using
the Mean Value Theorem, that for every r < R and every point in Br(x0)\∂Rm+1+
we have
||xm+1|β∂2m+1D
αv| ≤ |∂m+1(Dαv)∗|+ β|x−1m+1(Dαv)∗|
= |∂m+1(Dαv)∗|+ β|∂m+1(Dαv)∗(x′, ξ)|
≤ C,
where ξ is chosen with |ξ| ∈ (0, |xm+1|) such that the Mean Value Theorem holds.
We now return to (4.1.22). We have shown above that Dα∂m+1v is continuous
in BR(x0) and |xm+1|β∇Dα∂m+1v is bounded in Br(x0)\∂Rm+1+ for every r < R.
It follows that |xm+1|βν · ∇|Dα∂m+1v|2 is bounded on Br(x0)\∂Rm+1+ for every
r < R. Applying Lebesgue’s Dominated Convergence Theorem, we see that
limε→0+
∫∂Br(x0)
1Bεr(x0)|xm+1|βν · ∇|Dα∂m+1v|2dσ(x)
=
∫∂Br(x0)
|xm+1|βν · ∇|Dα∂m+1v|2dσ(x). (4.1.25)
155
Now we deal with the other term on the right hand side of (4.1.22). We observe
that ∂2m+1D
αv(x′, ε) = ∂2m+1D
αv(x′,−ε) and ∂m+1Dαv(x′, ε) = −∂m+1D
αv(x′,−ε).Thus
em+1 · ∇(|∂m+1Dαv|2(x′, ε)− |∂m+1D
αv|2(x′,−ε))
= 2⟨∂2m+1D
αv(x′, ε), ∂m+1Dαv(x′, ε)
⟩− 2
⟨∂2m+1D
αv(x′,−ε), ∂m+1Dαv(x′,−ε)
⟩= 4
⟨∂2m+1D
αv(x′, ε), ∂m+1Dαv(x′, ε)
⟩.
Notice that 1Bm√r2−ε2
(x0)∂m+1Dαv(x′, ε) converges uniformly, for x′ ∈ Bm
r (x0), to
0 as ε → 0+. Furthermore, Dα∂m+1v and |xm+1|β∂2m+1D
α∂m+1v are uniformly
bounded in Br(x0). Thus 1Bm√r2−ε2
(x0)εβ⟨∂2m+1D
αv(x′, ε), ∂m+1Dαv(x′, ε)
⟩→ 0
uniformly as ε→ 0+. We may therefore infer that
limε→0+
∫Bm√
r2−ε2(x0)
εβem+1 · ∇(|∂m+1Dαv|2(x′, ε)− |∂m+1D
αv|2(x′,−ε))dx′
= 4 limε→0+
∫Bm√
r2−ε2(x0)
εβ⟨∂2m+1D
αv(x′, ε), ∂m+1Dαv(x′, ε)
⟩dx′ = 0. (4.1.26)
We combine (4.1.22), (4.1.25) and (4.1.26) to see that
0 ≤ limε→0+
∫Bεr(x0)
div(|xm+1|β∇|∂m+1Dαv|2)dx
=
∫∂Br(x0)
|xm+1|βν · ∇|∂m+1Dαv|2dσ(x). (4.1.27)
This holds on every Br(x0) with r < R and we apply Lemma 4.1.0.7 to conclude
the proof.
Proof of Theorem 4.1.0.1. The conclusion of Lemma 4.1.0.8 combined with the
conclusion of Lemma 4.1.0.11 prove Theorem 4.1.0.1 when β ∈ (0, 1). Since the
theorem is also proved for β ∈ (−1, 0) in Lemma 4.1.0.10 and is well known for
β = 0, we conclude the theorem holds for every β ∈ (−1, 1).
4.2 Solutions of the Linear Degenerate Dirichlet
Problem
Here we discuss solutions of the Dirichlet problem
div(|xm+1|β∇v) = 0 in BR(x0) and v = φ on ∂BR(x0) (4.2.1)
156
for a given φ. This type of problem has been considered extensively in the
literature. An exposition of some of the theory is given in [25] and we record
the results we need in the following lemma.
Lemma 4.2.0.1. Suppose φ ∈ W 1,2β (BR(x0);Rn). Then there exists a v ∈
W 1,2β (BR(x0);Rn) which is a weak solution of the Dirichlet problem (4.2.1). In
other words, v is a weak solution of div(|xm+1|β∇v) = 0 in BR(x0) with v − φ ∈W 1,2β,0(BR(x0);Rn). Moreover, the following holds. Any weak solution is unique
and continuous in BR(x0), if φ ∈ C(BR(x0);Rn) then v(x)→ φ(z) as x→ z for
z ∈ ∂BR(x0) and the weak maximum principle
maxBR(x0)
v = max∂BR(x0)
v = max∂BR(x0)
φ
and weak minimum principle
minBR(x0)
v = min∂BR(x0)
v = min∂BR(x0)
φ
both hold, where we take the maximum and minimum component-wise. For any
φ ∈ W 1,2β (BR(x0);Rn), if v is a weak solution of the Dirichlet problem (4.2.1) and
w ∈ W 1,2β (BR(x0);Rn) also satisfies w − φ ∈ W 1,2
β,0(BR(x0);Rn) then∫BR(x0)
|xm+1|β|∇v|2dx ≤∫BR(x0)
|xm+1|β|∇w|2dx.
Proof. Recall that |xm+1|β is of Muckenhoupt class A2. Thus according to 1.6 of
[25], |xm+1|β is a 2-admissible weight which, in particular, means we may apply
the results there. For complete details see 1.1 of [25]. Theorem 3.70 in [25]
asserts that any weak solution of div(|xm+1|β∇v) = 0 in BR(x0) is continuous.
Moreover, if v ∈ W 1,2β (BR(x0);Rn) is a weak solution of div(|xm+1|β∇v) = 0 in
BR(x0), φ ∈ C(BR(x0);Rn) ∩W 1,2β (BR(x0);Rn) and v − φ ∈ W 1,2
β,0(BR(x0);Rn) it
follows from corollary 6.32 in [25] that v(x) → φ(z) as x → z for z ∈ ∂BR(x0).
Furthermore, the strong maximum principle, 6.5 in [25], then immediately implies
the weak maximum principle and weak minimum principle as stated in the lemma.
The Dirichlet problem is uniquely solvable according to 3.17 in [25]. Lastly
we show that solutions of (4.2.1) are energy minimising. Consider a weak so-
lution v ∈ W 1,2β (BR(x0);Rn) of div(|xm+1|β∇v) = 0 in BR(x0) with v − φ ∈
W 1,2β,0(BR(x0);Rn) and let w ∈ W 1,2
β (BR(x0);Rn) with w− φ ∈ W 1,2β,0(BR(x0);Rn).
157
It follows that w − v ∈ W 1,2β,0(BR(x0);Rn). We calculate∫
BR(x0)
|xm+1|β|∇w|2dx =
∫BR(x0)
|xm+1|β|∇v +∇(w − v)|2dx
=
∫BR(x0)
|xm+1|β|∇v|2dx+
∫BR(x0)
|xm+1|β|∇(w − v)|2dx
+ 2
∫BR(x0)
|xm+1|β〈∇v,∇(w − v)〉dx.
However, since v is a weak solution of div(|xm+1|β∇v) = 0 in BR(x0) and w−v ∈W 1,2β,0(BR(x0);Rn), it follows from Remark 2.4.0.1 that∫
BR(x0)
|xm+1|β〈∇v,∇(w − v)〉dx = 0.
Hence∫BR(x0)
|xm+1|β|∇w|2dx =
∫BR(x0)
|xm+1|β|∇v|2dx+
∫BR(x0)
|xm+1|β|∇(w − v)|2dx
which concludes the proof.
We now consider solutions to the Dirichlet problem (4.2.1) with boundary
data which is symmetric with respect to ∂Rm+1+ .
Lemma 4.2.0.2. Suppose v, φ ∈ W 1,2β (BR(x0);Rn) and v is a weak solution of
the Dirichlet problem (4.2.1) with φ as boundary data. Let φ ∈ C(BR(x0);Rn)
and suppose φ(x′, xm+1) = φ(x′,−xm+1) for every (x′, xm+1) ∈ BR(x0). Then
v(x′, xm+1) = v(x′,−xm+1) for every (x′, xm+1) ∈ BR(x0).
Proof. Our goal is to show that v(x′, xm+1) := v(x′,−xm+1) is a continuous weak
solution of the same Dirichlet problem (4.2.1) as v. Since solutions to this problem
are unique as a consequence of Lemma 4.2.0.1, we then have v = v, which implies
v is symmetric with respect to ∂Rm+1+ as required.
Since φ is continuous in BR(x0), Lemma 4.2.0.1 implies that v is continu-
ous in BR(x0). Hence, so is the function v(x′, xm+1) := v(x′,−xm+1). Further-
more, v|∂BR(x0) = φ|∂BR(x0) since φ(x′, xm+1) = φ(x′,−xm+1) for every (x, xm+1) ∈BR(x0). We also note v ∈ W 1,2
β (BR(x0);Rn). Hence v − φ ∈ W 1,2β,0(BR(x0);Rn).
Finally we will show that v weakly satisfies div(|xm+1|β∇v) = 0 in BR(x0). Let
158
ψ ∈ C∞0 (BR(x0);Rn). We have∫BR(x0)
|xm+1|β 〈∇v,∇ψ〉 dx =
∫BR(x0)
|xm+1|β 〈∇′v,∇′ψ〉 dx
+
∫BR(x0)
|xm+1|β 〈∂m+1v, ∂m+1ψ〉 dx. (4.2.2)
We consider the right hand side of (4.2.2). Define ψ(x′, xm+1) = ψ(x′,−xm+1) and
observe that ψ ∈ C∞0 (BR(x0);Rn). Using the change of variables xm+1 7→ −xm+1
we calculate∫BR(x0)
|xm+1|β 〈∇′v,∇′ψ〉 dx =
∫BR(x0)
|xm+1|β⟨∇′v,∇′ψ
⟩dx (4.2.3)
and ∫BR(x0)
|xm+1|β 〈∂m+1v, ∂m+1ψ〉 dx =
∫BR(x0)
|xm+1|β⟨∂m+1v, ∂m+1ψ
⟩dx.
(4.2.4)
Together, (4.2.2), (4.2.3) and (4.2.4) imply∫BR(x0)
|xm+1|β 〈∇v,∇ψ〉 dx =
∫BR(x0)
|xm+1|β⟨∇v,∇ψ
⟩dx = 0. (4.2.5)
Hence v and v solve the same Dirichlet problem and therefore Lemma 4.2.0.1
implies v = v which concludes the proof.
159
Chapter 5
Holder Continuity of First
Derivatives of Minimisers
In Chapter 3 we established the Holder continuity of a minimiser v of Eβ relative
to O. In doing so, we took advantage of the fact that v is a harmonic map in Rm+1+
and the restriction of the metric g, defined by (3.0.1) in Chapter 3, is smooth
and bounded on compact sets in Rm+1+ ; in this case if v is continuous, then it is
smooth. The higher regularity of continuous harmonic maps was known when
the first partial regularity theories for harmonic maps were developed and there
are several ways to prove that continuity implies higher regularity. We proceed
to highlight the theory upon which the methods in this chapter are based.
Jost, see Chapter 8 of [27], gives an exposition of one possible way to prove
continuous harmonic maps are smooth. The approach is based on the theory, de-
veloped by Ladyzhenskaya, for linear and quasilinear uniformly elliptic equations
[28]. The application of difference quotients to establish the existence and inte-
grability of higher order derivatives is one of the main constituents of the method.
This technique is also widely used throughout the literature on elliptic equations
and, in order to adapt the technique to the theory of harmonic maps, the con-
tinuity assumption must be exploited due to the nature of the Euler-Lagrange
equations these maps satisfy.
If a harmonic map is Holder continuous, it is possible to bypass some of
the technicalities in the approach described by Jost. The average energy of a
harmonic map is comparable to that of a solution to the associated linear equation
with the same boundary data. In conjunction with the scaling and minimising
properties of such a solution, the Holder continuity of a harmonic map can be
used to derive a bound for the essential supremum of its gradient as described by
Schoen [45].
160
Once sufficient integrability of the higher order derivatives, or a bound for
the supremum of the gradient, of a harmonic map is known, higher regularity fol-
lows from repeated differentiation of the Euler-Lagrange equations coupled with
applications of the Sobolev embedding theorem. If we view the Euler-Lagrange
equations for Eβ, recall (3.1.10), as elliptic equations, we see that the ellipticity
degenerates at the boundary ∂Rm+1+ . Furthermore, the derivatives of the coef-
ficient xβm+1 become increasingly singular if we formally repeatedly differentiate
the Euler-Lagrange equations for Eβ with respect to xm+1. Therefore, we do
not necessarly expect to be able to establish higher regularity of all higher or-
der derivatives of a minimiser of Eβ up to ∂Rm+1+ using the Sobolev embedding
theorem and methods from the regularity theory for harmonic maps directly.
Ultimately, as will be discussed in Chapter 6, we are interested in a variational
problem for maps defined on O ⊂ ∂Rm+1+ . We therefore focus on establishing
higher regularity of a minimiser of Eβ relative to O in the directions xi, for
i = 1, . . . ,m, up to the boundary. We observed in Chapter 4 that for solutions
of the linear equation div(|xm+1|β∇v) = 0, the regularity for the derivatives
with respect to xi, for i = 1, . . . ,m, can be established without considering the
derivatives with respect to xm+1. In this chapter we show that the same is
essentially true for the derivatives ∂iv, where i = 1, . . . ,m .
We have a substitute for the general Sobolev embedding theorem on balls
with centre in ∂Rm+1+ , namely the modified lemma of Morrey, Lemma 3.5.0.2,
which we used to establish the continuity of minimisers v of Eβ relative to O.
The goal of the method presented here is to again show decay estimates, this
time for the scaled energy of derivatives of v with respect to xi for i = 1, . . . ,m,
which allow us do deduce (3.5.3) and (3.5.4) in Lemma 3.5.0.2. We observe that
the aforementioned derivatives of a minimiser of Eβ relative to O satisfy a second
order equation with better structural conditions than those of the Euler-Lagrange
equations for Eβ. Consequently, we prove a Cacciopoli-type inequality which is
instrumental in the proof of the decay estimates.
Recall the assumptions on m,β stated in Remark 2.2.1.1. We make the same
assumptions throughout this chapter.
5.1 An L∞ Bound for the Gradient of an Energy
Minimiser
We show that the combination of Holder continuity and sufficiently small energy
of minimiser of Eβ relative to O implies a bound for the essential supremum of
161
its gradient. The following lemma is an analogue of Lemma 3.1 in [45] and the
proof given here is based on the proof in [45].
Lemma 5.1.0.1. Suppose v ∈ W 1,2β (Rm+1
+ ;N) is a minimiser of Eβ relative to
O. Let ε > 0 be the number from Theorem 3.12.1.1 and let B+R(x0) be a half-ball
with R ≤ 1 and ∂0B+R(x0) ⊂ O. Suppose R1−m−β ∫
B+R(x0)
xβm+1|∇v|2dx ≤ ε. Then
there is a θ = θ(m,N, β) ∈ (0, 1) such that ∇v ∈ L∞(B+θR(x0);R(m+1)n). In
particular, we have
||∇v||2L∞(B+
θR(x0);R(m+1)n)≤ C
1
|B+3θR(x0)|β
∫B+
3θR(x0)
xβm+1|∇v|2dx
where C = C(m,N, β).
Proof. It follows from Theorem 3.12.1.1 that there is a θ0 ∈ (0, 1) such that v is
Holder continuous in B+θ0R
(x0). That is, there is a γ = γ(m,N, β) ∈ (0, 1) such
that
|v(x)− v(y)| ≤ C
Rγ|x− y|γ (5.1.1)
for every x, y ∈ B+θ0R
(x0). Recall from the proof of Theorem 3.12.1.1 and (3.6.24)
in the proof of Lemma 3.6.0.4, that ε is also chosen sufficiently small to imply
Lemma 3.6.0.3 holds, that is, we have
||∇v||2L∞(B ρ2
(y);R(m+1)n) ≤ C1
|Bρ(y)|
∫Bρ(y)
|∇v|2dx, (5.1.2)
on every Bρ(y) ∈ Bθ1(x0, R,R3
) where θ1 = θ1(m,N) ≥ 2. We intend to show a
uniform bound for ||∇v||2L∞(B ym+1
2θ1
(y);R(m+1)n)where B ym+1
θ1
(y) ∈ Bθ1(x0, θ0R,θ0R
3);
on this class of ball we have
B ym+1θ1
(y) ⊂ B+θ1+1θ1
ym+1(y+) ⊂ B+
θ0R2
(y+) ⊂ B+θ0R
(x0) (5.1.3)
so we may take advantage of the Holder continuity of v on B+θ0R
(x0).
To obtain the required bound, in view of (5.1.3) we examine the decay of
the average energy on concentric balls Bρ(y) with B+ρ (y) ∈ B+(x0, θ0R,
θ0R2
).
Without relabelling, we reflect v evenly across the hyperplane Rm × 0. Then
v ∈ C0,γ(Bθ0R(x0);N)∩W 1,2β (BR(x0);N) is a weak solution of div(|xm+1|β∇v) +
|xm+1|βA(v)(∇v,∇v) = 0 in BR(x0). Let B+ρ (y) ∈ B+(x0, θ0R,
θ0R2
). We focus
initially on an estimate for the average energy on B ρ2(y) in terms of that on Bρ(y).
162
An application of Minkowski’s inequality, for maps in L2β(B ρ
2(y);Rn(m+1)), yields
(∫B ρ
2(y)
|xm+1|β|∇v|2dx
) 12
≤
(∫B ρ
2(y)
|xm+1|β |∇w|2 dx
) 12
+
(∫Bρ(y)
|xm+1|β 〈∇(v − w),∇(v − w)〉 dx
) 12
(5.1.4)
for any w ∈ W 1,2β (Bρ(y);Rn). Now suppose w ∈ W 1,2
β (Bρ(y);Rn) is the weak
solution of div(|xm+1|β∇w) = 0 in Bρ(y) with w = v on ∂Bρ(y), given by Lemma
4.2.0.1. Then w is smooth in Bρ(y)\(Rm × 0) and continuous in Bρ(y) by
Lemma 4.2.0.1. Furthermore, since v is symmetric with respect to ∂Rm+1+ , it
follows from Lemma 4.2.0.2 that w is symmetric with respect to ∂Rm+1+ and,
crucially, we are now free to apply Theorem 4.1.0.1 on any Bρ(y) with B+ρ (y) ∈
B+(x0, θ0R,θ0R
2).
Recall w − v ∈ C(Bρ(y);Rn) ∩W 1,2β,0(Bρ(y);Rn), v satisfies div(|xm+1|β∇v) +
|xm+1|βA(v)(∇v,∇v) = 0 weakly in Bρ(y) and w weakly solves div(|xm+1|β∇w) =
0 in Bρ(y). We may therefore expand the second term in the right hand side of
(5.1.4) to see that ∫Bρ(y)
|xm+1|β 〈∇(v − w),∇(v − w)〉 dx
=
∫Bρ(y)
|xm+1|β 〈∇v,∇(v − w)〉 dx
−∫Bρ(y)
|xm+1|β 〈∇w,∇(v − w)〉 dx
=
∫Bρ(y)
|xm+1|β 〈∇v,∇(v − w)〉 dx
=
∫Bρ(y)
|xm+1|β 〈v − w,A(v)(∇v,∇v)〉 dx
≤ C supBρ(y)
|v − w|∫Bρ(y)
|xm+1|β|∇v|2dx.
163
Hence, substituting this bound into (5.1.4), we have
(∫B ρ
2(y)
|xm+1|β|∇v|2dx
) 12
≤
(∫B ρ
2(y)
|xm+1|β|∇w|2dx
) 12
+
(C sup
Bρ(y)
|v − w|∫Bρ(y)
|xm+1|β|∇v|2dx
) 12
.
Now we divide by |B ρ2(y)|
12β , this gives
(1
|B ρ2(y)|β
∫B ρ
2(y)
|xm+1|β|∇v|2dx
) 12
≤
(1
|B ρ2(y)|β
∫B ρ
2(y)
|xm+1|β|∇w|2dx
) 12
+
(C sup
Bρ(y)
|v − w| 1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇v|2dx
) 12
. (5.1.5)
We consider the terms on the right hand side above.
Fix z ∈ ∂Bρ(y). Then v(z) = w(z) and it follows that
supBρ(y)
|v(x)− w(x)| ≤ supBρ(y)
|v(x)− v(z)|+ supBρ(y)
|v(z)− w(x)|
= supBρ(y)
|v(x)− v(z)|+ supBρ(y)
|w(z)− w(x)|.
The Holder continuity of v, together with (5.1.1), yields
supBρ(y)
|v(x)− v(z)| ≤ Cργ
Rγ.
We also note that w satisfies the weak maximum and minimum principle compo-
nentwise by lemma 4.2.0.1. It follows that, for k = 1, . . . , n, we have
supBρ(y)
|wk(x)− wk(z)| ≤ sup∂Bρ(y)
|wk(x)− wk(z)| = sup∂Bρ(y)
|vk(x)− vk(z)| ≤ Cργ
Rγ.
We thus conclude that
supBρ(y)
|v(x)− w(x)| ≤ Cργ
Rγ. (5.1.6)
164
Next we use the monotonicity and minimising properties of w to scale its averaged
energy in (5.1.5). It follows from an application of Theorem 4.1.0.1, followed by
an application of Lemma 4.2.0.1, that
1
|B ρ2(y)|β
∫B ρ
2(y)
|xm+1|β|∇w|2dx ≤ 1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇w|2dx
≤ 1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇v|2dx. (5.1.7)
Hence, combining (5.1.5), (5.1.6) and (5.1.7), we have
(1
|B ρ2(y)|β
∫B ρ
2(y)
|xm+1|β|∇v|2dx
) 12
≤
(1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇v|2dx
) 12
+
(Cργ
Rγ
1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇v|2dx
) 12
.
We square both sides of this inequality to see that
1
|B ρ2(y)|β
∫B ρ
2(y)
|xm+1|β|∇v|2dx
≤(
1 + Cργ2
Rγ2
+ Cργ
Rγ
)1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇v|2dx
≤(
1 + Cργ2
Rγ2
)1
|Bρ(y)|β
∫Bρ(y)
|xm+1|β|∇v|2dx (5.1.8)
This holds on every Bρ(y) with B+ρ (y) ∈ B+(x0, θ0R,
θ0R2
).
Now we iterate this estimate on concentric balls. Consider B θ0R2
(y) with
B+θ0R
2
(y) ∈ B+(x0, θ0R,θ0R
2). Let ρk = 2−k θ0R
2for k ∈ N0. It follows from (5.1.8)
that, for every k ≥ 1, we have
1
|Bρk(y)|β
∫Bρk (y)
|xm+1|β|∇v|2dx
≤
(1 + C
ργ2k−1
Rγ2
)1
|Bρk−1(y)|β
∫Bρk−1
(y)
|xm+1|β|∇v|2dx.
165
Hence, applying this repeatedly gives
1
|Bρk(y)|β
∫Bρk (y)
|xm+1|β|∇v|2dx
≤k−1∏j=0
(1 + C
ργ2j
Rγ2
)1
|B θ0R2
(y)|β
∫B θ0R
2
(y)
|xm+1|β|∇v|2dx
≤∞∏j=0
(1 + C
ργ2j
Rγ2
)1
|B θ0R2
(y)|β
∫B θ0R
2
(y)
|xm+1|β|∇v|2dx. (5.1.9)
We consider the infinite product in (5.1.9). Observe thatργ2j
Rγ2≤ 2−
jγ2 . Hence
∞∏j=0
(1 + C
ργ2j
Rγ2
)≤∞∏j=0
(1 + C2−
jγ2
)≤ C <∞
where C depends only on m,N, β. Thus it follows from (5.1.9) that, for every
k ∈ N0, we have
1
|Bρk(y)|β
∫Bρk (y)
|xm+1|β|∇v|2dx ≤ C1
|B θ0R2
(y)|β
∫B θ0R
2
(y)
|xm+1|β|∇v|2dx.
(5.1.10)
Furthermore, since B θ0R2
(y) ⊂ Bθ0R(x0), we deduce that
1
|B θ0R2
(y)|β
∫B θ0R
2
(y)
|xm+1|β|∇v|2dx ≤ C1
|Bθ0R(x0)|β
∫Bθ0R(x0)
|xm+1|β|∇v|2dx.
(5.1.11)
The combination of (5.1.10) and (5.1.11) implies
1
|Bρk(y)|β
∫Bρk (y)
|xm+1|β|∇v|2dx ≤ C1
|Bθ0R(x0)|β
∫Bθ0R(x0)
|xm+1|β|∇v|2dx
= C1
|B+θ0R
(x0)|β
∫B+θ0R
(x0)
xβm+1|∇v|2dx
(5.1.12)
for every k ∈ N0.
To conclude we show that we can use (5.1.12) to obtain a uniform bound for
||∇v||2L∞(B ym+1
2θ1
(y);R(m+1)n)where B ym+1
θ1
(y) ∈ Bθ1(x0, θ0R,θ0R
3). Recall the inclu-
166
sions given in (5.1.3). Using (5.1.2) and recalling the notation y+ = y−(0, ym+1),
we calculate
||∇v||2L∞(B ym+12θ1
(y);R(m+1)n) ≤ C1
|B ym+1θ1
(y)|
∫B ym+1
θ1
(y)
|∇v|2dx
≤ C1
|B+(θ1+1)ym+1
θ1
(y+)|β
∫B+
(θ1+1)ym+1θ1
(y+)
xβm+1|∇v|2dx.
(5.1.13)
Now observe that
1
|B+(θ1+1)ym+1
θ1(y+)|β
∫B+
(θ1+1)ym+1θ1
(y+)
xβm+1|∇v|2dx
≤ C1
|B+ρk
(y+)|β
∫B+ρk
(y+)
xβm+1|∇v|2dx
≤ C1
|Bρk(y+)|β
∫Bρk (y+)
|xm+1|β|∇v|2dx (5.1.14)
where ρk = θ0R2
2−k for some k ∈ N0. Together, (5.1.12), (5.1.13) and (5.1.14)
yield
||∇v||2L∞(B ym+12θ1
(y);R(m+1)n) ≤ C1
|B+θ0R
(x0)|β
∫B+θ0R
(x0)
xβm+1|∇v|2dx. (5.1.15)
This holds for every B ym+1θ1
(y) ∈ Bθ1(x0, θ0R,θ0R
3). Finally we deduce that for
almost every y ∈ B+θ0R
3
(x0) we have
|∇v|2(y) ≤ C1
|B+θ0R
(x0)|β
∫B+θ0R
(x0)
xβm+1|∇v|2dx (5.1.16)
so that
||∇v||2L∞(B+
θ0R3
(x0);R(m+1)n)≤ C
1
|B+θ0R
(x0)|β
∫B+θ0R
(x0)
xβm+1|∇v|2dx. (5.1.17)
Remark 5.1.0.1. The choice of θ in the preceding lemma is θ03
where θ0 is the
number from Theorem 3.12.1.1 such that if R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx ≤ ε
then v ∈ C0,γ(B+θ0R
(x0);N).
We readily deduce from this lemma that v is Lipschitz continuous on B+θR(x0).
167
Corollary 5.1.0.1. Suppose the assumptions of Lemma 5.1.0.1 hold. Then v is
Lipschitz continuous in B+θR(x0). Furthermore, v satisfies
|v(x)− v(y)| ≤ C
((3θR)1−m−β
∫B+
(3θR)(x0)
xβm+1|∇v|2dx
) 12 |x− y|
θR(5.1.18)
for every x, y ∈ B+θR(x0).
Proof. Assuming the hypotheses in Lemma 5.1.0.1 hold, we have
||∇v||2L∞(B+
θR(x0);R(m+1)n)≤ C
1
|B+3θR(x0)|β
∫B+
3θR(x0)
xβm+1|∇v|2dx
=C
θ2R2(3θR)1−m−β
∫B+
3θR(x0)
xβm+1|∇v|2dx
for θ and C depending on m,N and β. Now, using the Mean Value Theorem, we
see that
|v(x)− v(y)| ≤ C||∇v||L∞(B+θR(x0);R(m+1)n)|x− y|
for x, y ∈ B+θR(x0). The combination of the two preceding inequalities implies
(5.1.18).
5.2 Existence of second order derivatives
The difference quotient method is an effective tool for establishing the existence
of higher order derivatives in the theory of elliptic partial differential equations.
It can be used to show that a continuous harmonic map is smooth [27]. We
use difference quotients to show that the derivatives ∂iv, with i = 1, . . . ,m, of a
minimiser v of Eβ relative to O are in W 1,2β , taking advantage of the bound for
the essential supremum of the gradient of v described in Section 5.1. We could
however still obtain existence of these derivatives only using the Holder continuity
of v.
Lemma 5.2.0.1. Let v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of Eβ relative to Oand let B+
R(x0) be a half-ball with ∂0B+R(x0) ⊂ O. Suppose v ∈ C0(B+
R(x0);N) ∩W 1,2β (B+
R(x0);N) and ∇v ∈ L∞(B+R(x0);R(m+1)n). Then, for i = 1, . . . ,m, the
weak derivative ∇∂iv exists and satisfies
∇∂iv ∈ L2β(B+
R2
(x0);R(m+1)n).
168
Proof. First we recall (3.1.6); for any φ ∈ C∞0 (BR(x0);Rn) we have∫B+R(x0)
xβm+1〈∇v,∇φ〉dx =
∫B+R(x0)
xβm+1〈φ,A(v)(∇v,∇v)〉dx. (5.2.1)
Let η ∈ C∞0 (B 3R4
(x0)) be a smooth cutoff function such that η ≡ 1 in BR2(x0),
1 ≥ η ≥ 0 in B 3R4
(x0)\BR2(x0) and |∇η| ≤ C
R. Furthermore, let ∆h
i v = h−1(v(x+
hei)− v(x)) be the difference quotient of v and assume |h| < R4
. It follows, using
approximation, that w = −∆−hi (η2∆hi v) is an admissible test function for (5.2.1);
substituting w into (5.2.1) yields∫B+R(x0)
xβm+1〈∇v,∇w〉dx =
∫B+R(x0)
xβm+1〈w,A(v)(∇v,∇v)〉dx. (5.2.2)
We consider each term in (5.2.2) separately. We have∫B+R(x0)
xβm+1〈∇v,∇w〉dx =
∫B+R(x0)
xβm+1〈∇v,∇(−∆−hi (η2∆hi v))〉dx
=
∫B+R(x0)
xβm+1〈∇v,−∆−hi ∇(η2∆hi v)〉dx
=
∫B+R(x0)
xβm+1〈∆hi∇v,∇(η2∆h
i v)〉dx
=
∫B+R(x0)
2ηxβm+1〈∆hi∇v · ∇η,∆h
i v)〉dx
+
∫B+R(x0)
η2xβm+1|∆hi∇v|2dx. (5.2.3)
Furthermore, an integration by parts in the term involving A gives∫B+R(x0)
xβm+1〈w,A(v)(∇v,∇v)〉dx =
∫B+R(x0)
xβm+1〈η2∆hi v,∆
hi (A(v)(∇v,∇v))〉dx.
(5.2.4)
Recalling that the support of η is contained in B 3R4
(x0), we combine (5.2.2),
(5.2.3) and (5.2.4) to see that∫B+R(x0)
η2xβm+1|∆hi∇v|2dx =
∫B+
3R4
(x0)
η2xβm+1〈∆hi v,∆
hi (A(v)(∇v,∇v))〉dx
−∫B+
3R4
(x0)
2ηxβm+1〈∆hi∇v · ∇η,∆h
i v〉dx. (5.2.5)
We now use Young’s inequality, ab ≤ a2
δ2+ δ b
2
2for a, b ≥ 0 and δ > 0, to move all
169
of the terms involving ∆hi∇v on the right hand side of (5.2.5) to the left hand
side. We calculate
−∫B+
3R4
(x0)
2ηxβm+1〈∆hi∇v · ∇η,∆h
i v〉dx ≤ Cδ
∫B+R(x0)
η2xβm+1|∆hi∇v|2dx
+C
δ
∫B+R(x0)
xβm+1|∇η|2|∆hi v|2dx.
(5.2.6)
We need to estimate the term involving ∆hi (A(v)(∇v,∇v)) in a similar fashion.
To this end, without relabelling we extend A to a section of T ∗Rn⊗T ∗Rn⊗TRn
and write xh = x+ hei. The integrals in (5.2.5) all vanish outside B+3R4
(x0) so we
assume x ∈ B+3R4
(x0). Notice that the Mean Value Theorem yields
|∆hi v(x)| ≤ ||∇v||L∞(B+
R(x0);R(m+1)n). (5.2.7)
Now we calculate
∆hi (A(v)(∇v,∇v))(x)
= h−1(A(v(xh))(∇v(xh),∇v(xh))− A(v(x))(∇v(xh),∇v(xh)))
+ A(v(x))(∆hi∇v,∇v(xh)) + A(v(x))(∇v,∆h
i∇v).
Consequently, an application of the Mean Value Theorem and (5.2.7) gives
∣∣∆hi (A(v)(∇v,∇v))(x)
∣∣ ≤ C|∆hi∇v|||∇v||L∞(B+
R(x0);R(m+1)n)
+ C||∇v||3L∞(B+
R(x0);R(m+1)n). (5.2.8)
Together, (5.2.7) and (5.2.8) imply∫B+
3R4
(x0)
η2xβm+1〈∆hi v,∆
hi (A(v)(∇v,∇v))〉dx
≤ C
∫B+
3R4
(x0)
η2xβm+1|∆hi∇v|||∇v||2L∞(B+
R(x0);R(m+1)n)dx
+ C||∇v||4L∞(B+
R(x0);R(m+1)n)
∫B+
3R4
(x0)
xβm+1dx. (5.2.9)
170
An application of Young’s inequality gives∫B+
3R4
(x0)
η2xβm+1|∆hi∇v|||∇v||2L∞(B+
R(x0);R(m+1)n)dx
≤ Cδ
∫B+
3R4
(x0)
η2xβm+1|∆hi∇v|2dx
+C
δ
∫B+
3R4
(x0)
η2xβm+1||∇v||4L∞(B+R(x0);R(m+1)n)
dx. (5.2.10)
Choosing δ sufficiently small in (5.2.6) and (5.2.10) we combine these inequalities
with (5.2.5) and (5.2.9). This yields∫B+R(x0)
η2xβm+1|∆hi∇v|2dx
≤ C||∇v||4L∞(B+
R(x0);R(m+1)n)
∫B+R(x0)
xβm+1dx+ C
∫B+R(x0)
xβm+1|∇η|2|∆hi v|2dx.
(5.2.11)
Since |∇η| ≤ CR
and η ≡ 1 in B+R2
(x0), using (5.2.7) we have
∫B+R2
(x0)
xβm+1|∆hi∇v|2dx
≤ C||∇v||2L∞(B+
R(x0);R(m+1)n)(R−2 + ||∇v||2
L∞(B+R(x0);R(m+1)n)
)
∫B+R(x0)
xβm+1dx.
We observe that this bound is independent of h with |h| < R4
. Hence by Lemma
4.1.0.2 we conclude that the weak derivative ∇∂iv exists and satisfies the above
inequality with ∇∂iv in place of ∆hi∇v. This concludes the proof.
5.3 Caccioppoli-Type Inequality
Here we show a Caccioppoli-type estimate for the derivatives ∂iv, with i =
1, . . . ,m, of a minimiser v of Eβ relative to O. Such inequalities are widely
used in the theory of elliptic partial differential equations; they capitalise on the
ellipticity in order to obtain control of higher order derivatives in terms of lower
order derivatives.
Lemma 5.3.0.1. Let v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of Eβ relative to
O and let B+R(x0) be a half-ball with R ≤ 1 and ∂0B+
R(x0) ⊂ O. Suppose
171
v ∈ C0(B+R(x0);N), ∇v ∈ L∞(B+
R(x0);R(m+1)n) and ∂iv ∈ W 1,2β (B+
R(x0);Rn)
for some i = 1, . . . ,m. Let Bρ(y) ⊂ BR(x0) with ym+1 ≥ 0. Then there is a
constant C = C(m,N, β) such that∫B ρ
2(y)∩Rm+1
+
xβm+1 |∇∂iv|2 dx
≤ C
(||∇v||2
L∞(Bρ(y)∩Rm+1+ ;R(m+1)n)
+1
ρ2
)∫Bρ(y)∩Rm+1
+
xβm+1 |∂iv − λ|2 dx
+ C||∇v||6L∞(Bρ(y)∩Rm+1
+ ;R(m+1)n)
∫Bρ(y)∩Rm+1
+
xβm+1dx (5.3.1)
for any λ ∈ Rn.
Proof. Integrating by parts with respect to xi in (3.1.6) shows that for every
ψ ∈ W 1,2β,0(BR(x0);Rn), we have∫
B+R(x0)
xβm+1 〈∇∂iv,∇ψ〉 dx
=
∫B+R(x0)
xβm+1 〈ψ, 2A(v) (∇∂iv,∇v) +DA(v) (∇v,∇v, ∂iv)〉 dx
where DA represents the derivative of A(y)(·, ·) with respect to y. Now, choose
ψ = η2 (∂iv − λ) where λ ∈ Rn is a constant vector and η ∈ C∞0 (Bρ(y)) is a cutoff
function with η ≡ 1 in B ρ2(y), 0 ≤ η ≤ 1, and |∇η| ≤ C
ρ. We calculate∫
Bρ(y)∩Rm+1+
xβm+1η2 |∇∂iv|2 dx ≤ C
∫Bρ(y)∩Rm+1
+
xβm+1η2 |∂iv − λ| |∇∂iv| |∇v| dx
+ C
∫Bρ(y)∩Rm+1
+
xβm+1η2 |∂iv − λ| |∂iv| |∇v|2 dx
+ C
∫Bρ(y)∩Rm+1
+
xβm+1η|∇η| |∂iv − λ| |∇∂iv| dx.
(5.3.2)
We consider each term on the right hand side of (5.3.2) separately, applying
Young’s inequalitiy, ab ≤ δa2
2+ b2
δ2for a, b ≥ 0 and δ > 0, to each in turn. Since
172
||∇v||L∞(B+R(x0);R(m+1)n) <∞, we calculate∫Bρ(y)∩Rm+1
+
xβm+1η2 |∂iv − λ| |∇∂iv| |∇v| dx
≤ C
δ||∇v||2
L∞(Bρ(y)∩Rm+1+ ;R(m+1)n)
∫Bρ(y)∩Rm+1
+
xβm+1η2 |∂iv − λ|2 dx
+ Cδ
∫Bρ(y)∩Rm+1
+
xβm+1η2 |∇∂iv|2 dx, (5.3.3)
∫Bρ(y)∩Rm+1
+
xβm+1η2 |∂iv − λ| |∂iv| |∇v|2 dx
≤ C
∫Bρ(y)∩Rm+1
+
xβm+1 |∂iv − λ|2 dx
+ C||∇v||6L∞(Bρ(y)∩Rm+1
+ ;R(m+1)n)
∫Bρ(y)∩Rm+1
+
xβm+1dx (5.3.4)
and, using additionally the fact that |∇η| ≤ Cρ
,∫Bρ(y)∩Rm+1
+
xβm+1η|∇η| |∂iv − λ| |∇∂iv| dx
≤ 1
δ
C
ρ2
∫Bρ(y)∩Rm+1
+
xβm+1 |∂iv − λ|2 dx
Cδ
∫Bρ(y)∩Rm+1
+
xβm+1η2 |∇∂iv|2 dx. (5.3.5)
The combination of (5.3.2) with (5.3.3), (5.3.4) and (5.3.5) yield (5.3.1) provided
δ is chosen sufficiently small in (5.3.3) and (5.3.5).
5.4 Improved Control in the Poincare Inequal-
ity for First Derivatives on the Boundary
In Section 3.10 we showed that if the energy of a minimiser of Eβ relative to Ois sufficiently small, then we obtain improved control in the Poincare inequality,
provided the integrals are multiplied by factors making them scaling invariant.
We can obtain a similar improvement in the Poincare inequality for the derivatives
∂iv, where i = 1, . . . ,m, of a minimiser v of Eβ relative to O, still only assum-
ing the energy of v is sufficiently small, by taking advantage of the Caccioppoli
inequality, Lemma 5.3.0.1.
173
Lemma 5.4.0.1. Let i = 1, . . . ,m. For every δ > 0 there exist numbers ε > 0,
τ ∈ (0, 1) and θ ∈ (0, 14] such that the following holds. Suppose v ∈ W 1,2
β (Rm+1+ ;N)
is a minimiser of Eβ relative to O . Let B+R(x0) ⊂ Rm+1
+ be a half-ball with R ≤ 1
and ∂0B+R(x0) ⊂ O. If
R1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε2,
then, for every B+r (y) ∈ B+(x0, R, τR), either
r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx ≤ δ
1
R2
( rR
)2
(5.4.1)
or
(θr)−(1+m+β)
∫B+θr(y)
xβm+1
∣∣∣∂iv − ∂ivB+θr(y),β
∣∣∣2 dx ≤ δr1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx.
(5.4.2)
Proof. First we observe that the statement of the lemma is invariant under rescal-
ing and translation by any point in ∂Rm+1+ . We will show that if the lemma is
true on B+1 (0) for minimisers of Eβ relative to O whenever ∂0B+
1 (0) ⊂ O, then we
may obtain the lemma on B+R(x0) for a minimiser of Eβ relative to O whenever
∂0B+R(x0) ⊂ O and R ≤ 1. To achieve this we will use rescaling via the map
x 7→ Rx+ x0, defined for x ∈ B+1 (0), and apply the lemma on B+
1 (0) to the map
vR(x) = v(Rx+ x0).
Suppose the lemma holds on B+1 (0) for a minimiser of Eβ relative to O when-
ever ∂0B+1 (0) ⊂ O. Let v ∈ W 1,2
β (Rm+1+ ;N) be a minimising harmonic map
relative to O, let B+R(x0) satisfy ∂0B+
R(x0) ⊂ O and suppose
R1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε2.
Define vR(·) = v(R · +x0) ∈ W 1,2β (Rm+1
+ ;N). Using the change of variables
x 7→ Rx+ x0 we see that∫B+
1 (0)
xβm+1 |∇vR|2 dx = R1−m−β
∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε2.
Now we show vR is a minimiser relative to O := x−x0
R: x ∈ O. Since B+
R(x0)
satisfies ∂0B+R(x0) ⊂ O, it follows from the definition of O that B+
1 (0) satisfies
∂0B+1 (0) ⊂ O. Let w ∈ W 1,2
β (Rm+1+ ;N) with w|Rm+1
+ \K = vR|Rm+1+ \K for a compact
K ⊂ Rm+1 with K ∩ ∂Rm+1+ ⊂ O. Then w(·) = w
( ·−x0
R
)∈ W 1,2
β (Rm+1+ ;N) and
174
w|Rm+1+ \K = v|Rm+1
+ \K where K is the image of K under the change of variables
x 7→ Rx+ x0. Since v is a minimiser, we calculate∫Rm+1
+
xβm+1 |∇vR|2 dx = R1−m−β
∫Rm+1
+
xβm+1 |∇v|2 dx
≤ R1−m−β∫Rm+1
+
xβm+1 |∇w|2 dx
= R−(1+m+β)
∫Rm+1
+
xβm+1
∣∣∣∣∇w(x− x0
R
)∣∣∣∣2 dx
=
∫Rm+1
+
xβm+1 |∇w|2 dx.
Hence vR is a minimiser of Eβ relative to O. Thus the conclusions of the lemma
hold for vR on B+1 (0) by assumption. This implies that for every B+
s (z) ∈B+(0, 1, τ) either
s1−m−β∫B+s (z)
xβm+1 |∇∂i(vR)|2 dx ≤ δs2 (5.4.3)
or
(θs)−(1+m+β)
∫B+θs(z)
xβm+1
∣∣∣∂i(vR)− ∂i(vR)B+θs(z),β
∣∣∣2 dx
≤ δs1−m−β∫B+s (z)
xβm+1 |∇∂i(vR)|2 dx. (5.4.4)
We want to show (5.4.1) and (5.4.2) hold for v. Notice thatB+r (y) ∈ B+(x0, R, τR)
if, and only if, B+s (z) ∈ B+(0, 1, τ) where s and r are related by s = r
Rand y and
z are related by z = y−x0
R. Furthermore, Bs(z) is the image of Br(y) under the
change of variables x 7→ x−x0
R.
First we show (5.4.3) implies (5.4.1). Suppose r, s, y and z are related as
described previously. We calculate
s1−m−β∫B+s (z)
xβm+1 |∇∂i(vR)|2 dx
= R4s1−m−β∫B+s (z)
xβm+1 |∇∂iv(Rx+ x0)|2 dx
= R2(Rs)1−m−β∫B+s (z)
xβm+1 |∇∂iv(Rx+ x0)|2R1+m+βdx
= R2r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx. (5.4.5)
175
Hence, if (5.4.3) holds, we deduce from (5.4.5) that
R2r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx ≤ δ
( rR
)2
which implies (5.4.1).
Now we show (5.4.2) follows from (5.4.4). Using the change of variables
x 7→ Rx + x0 we see that ∂i(vR)B+θs(z),β
= R∂ivB+θr(y),β. Hence, using the same
change of variables again, we have
(θs)−(1+m+β)
∫B+θs(z)
xβm+1
∣∣∣∂i(vR)− ∂i(vR)B+θs(z),β
∣∣∣2 dx
= R2(θs)−(1+m+β)
∫B+θs(z)
xβm+1
∣∣∣∂iv(Rx+ x0)− ∂ivB+θr(y),β
∣∣∣2 dx
= R1−m−β(θs)−(1+m+β)
∫B+θs(z)
xβm+1
∣∣∣∂iv(Rx+ x0)− ∂ivB+θr(y),β
∣∣∣2R(1+m+β)dx
= R2(θr)−(1+m+β)
∫B+θr(y)
xβm+1
∣∣∣∂iv − ∂ivB+θr(y),β
∣∣∣2 dx. (5.4.6)
The combination of (5.4.5) and (5.4.6) yields (5.4.2). Thus if the lemma holds
on B+1 (0) and the hypothesis of the lemma hold on B+
R(x0) then the conclusion
also holds on B+R(x0).
Henceforth we will assume R = 1, x0 = 0 and v is a minimiser of Eβ relative
to O and ∂0B+1 (0) ⊂ O. We argue by contradiction. In particular, we will show
that if the lemma were false, then we may construct a weak solution of (2.4.5),
that is a weak solution of div(xβm+1∇w) = 0 in B+1 (0) with xβm+1
∂w∂xm+1
= 0 on
∂0B+1 (0), whose L2
β(B+1 (0);Rn) norm is bounded below and strictly above by the
same number, a contradiction.
Suppose the statement is false. Then there exists a δ > 0 such that, for any
fixed θ ∈ (0, 14] we may find a sequence (vk)k∈N of minimising harmonic maps,
relative to O, with vk ∈ W 1,2β (B+
1 (0);N) such that∫B+
1 (0)
xβm+1 |∇vk|2 dx := ε2
k → 0,
and, furthermore, a sequence of numbers 0 < τk → 0+, half-balls B+rk
(yk) ∈B+(0, 1, τk), and numbers 0 < rk ≤ τk → 0+ such that
r1−m−βk
∫B+rk
(yk)
xβm+1 |∇∂ivk|2 dx > δr2
k (5.4.7)
176
and
(θrk)−(1+m+β)
∫B+θrk
(yk)
xβm+1
∣∣∣∂ivk − (∂ivk)B+θrk
(yk),β
∣∣∣2 dx
> δr1−m−βk
∫B+rk
(yk)
xβm+1 |∇∂ivk|2 dx. (5.4.8)
We show that r1−m−βk
∫B+rk
(yk)xβm+1 |∇∂ivk|
2 dx → 0. Discarding as many vk
as necessary and re-indexing the resulting sequence, we may suppose that ε2k ≤ ε
for every k, where ε is the number from Theorem 3.12.1.1. Furthermore we may
choose this sequence such that 2τk ≤ θ012
, where θ0 is the number given by Theorem
3.12.1.1, so that B+rk
(yk) ⊂ B+2rk
(yk) ⊂ B+2τk
(yk) ∈ B+(0, θ06, θ0
12) and, in particular,
B+2τk
(yk) ⊂ B+θ06
(0). Applying Theorem 5.1.0.1 we see that each vk satisfies
||∇vk||2L∞(B+θ03
(0);R(m+1)n)≤ C
θ20
θ1−m−β0
∫B+θ0
(0)
xβm+1|∇vk|2dx.
Furthermore, the boundary monotonicity formula, Lemma 3.3.1.1, implies that
θ1−m−β0
∫B+θ0
(0)
xβm+1|∇vk|2dx ≤∫B+
1 (0)
xβm+1 |∇vk|2 dx = ε2
k.
Thus,
||∇vk||2L∞(B+θ03
(0);R(m+1)n)≤ C
θ20
ε2k → 0. (5.4.9)
Now we make use of the Caccioppoli-type inequality, Lemma 5.3.0.1, with λ = 0,
noting that by Lemma 5.2.0.1 we have ∇∂ivk ∈ L2β(B+
θ06
(0);R(m+1)n) for i =
1, . . . ,m. We apply Lemma 5.3.0.1 on B+2τk
(yk) ⊂ B+θ06
(0). This yields
∫B+rk
(yk)
xβm+1 |∇∂ivk|2 dx
≤ C
(||∇vk||2L∞(B+
2rk(yk);R(m+1)n)
+1
r2k
)∫B+
2rk(yk)
xβm+1 |∂ivk|2 dx
+ C||∇vk||6L∞(B+2rk
(yk);R(m+1)n)
∫B+
2rk(yk)
xβm+1dx (5.4.10)
Since ||∇vk||L∞(B+2rk
(yk);R(m+1)n) ≤ ||∇vk||L∞(B+θ03
(0);R(m+1)n) we may combine (5.4.9)
177
with (5.4.10), multiplying the latter by r1−m−βk , to see that
r1−m−βk
∫B+rk
(yk)
xβm+1 |∇∂ivk|2 dx
≤ Cr2k||∇vk||4L∞(B+
θ03
(0);R(m+1)n)+ C||∇vk||2L∞(B+
θ03
(0);R(m+1)n)
+ Cr2k||∇vk||6L∞(B+
θ03
(0);R(m+1)n)
≤ C(r2kε
4k + ε2
k + r2kε
6k)→ 0, (5.4.11)
where C depends on m,N, β and θ0 and hence only on m,N, β. From (5.4.11),
we conclude that
r1−m−βk
∫B+rk
(yk)
xβm+1 |∇∂ivk|2 dx := ε2
k → 0. (5.4.12)
We see from (5.4.7) and (5.4.8) that
ε2k > δr2
k (5.4.13)
and
(θrk)−(1+m+β)
∫B+θrk
(yk)
xβm+1
∣∣∣∂ivk − (∂ivk)B+θrk
(yk),β
∣∣∣2 dx > δε2k. (5.4.14)
In order to construct a weak solution of the Neumann type problem (2.4.5)
with the desired properties, we define the normalised sequence
wk =∂ivk(rkx+ yk)− (∂ivk)B+
θrk(yk),β
εk
and analyse the limit as k →∞. We calculate
∇wk(x) =rkεk∇∂ivk(rkx+ yk). (5.4.15)
Hence, using the change of variables x 7→ rkx+ yk, we find∫B+
1 (0)
xβm+1 |∇wk|2 dx = 1 (5.4.16)
and
(wk)B+θ (0),β =
1∫B+θ (0)
xβm+1dx
∫B+θ (0)
xβm+1wkdx = 0. (5.4.17)
178
Furthermore, after changing variables again, we deduce from (5.4.14) that
θ−(1+m+β)
∫B+θ (0)
xβm+1 |wk|2 dx > δ. (5.4.18)
Using (5.4.17) we write wk = wk − (wk)B+θ (0),β and an application of Lemma
2.3.3.4 shows that∫B+
1 (0)
xβm+1|wk|2dx =
∫B+
1 (0)
xβm+1|wk − (wk)B+θ (0),β|
2dx
≤ Cθ−(1+m+β)
∫B+
1 (0)
xβm+1 |∇wk|2 dx. (5.4.19)
Together, (5.4.16) and (5.4.19) show that (wk)k∈N is bounded W 1,2β (B+
1 (0);Rn).
Hence, the the Rellich Compactness lemma, Lemma 2.3.5.2, yields a subse-
quence (wkj)j∈N which converges weakly in W 1,2β (B+
1 (0);Rn) and strongly in
L2β(B+
1 (0);Rn) to some w ∈ W 1,2β (B+
1 (0);Rn).
Now we show that w is a weak solution of the Neumann-type problem 2.4.5
in B+1 (0). Let φ ∈ C∞0 (B1(0);Rn) and define φ ∈ C∞0 (Brk(yk);Rn) by φ(z) =
φ(z−ykrk
). We observe that
∇φ(z) = ∇(φ
(z − ykrk
))=
1
rk∇φ(z − ykrk
)=
1
rk∇φ(x) (5.4.20)
where x ∈ B1(0) and z ∈ Brk(yk) satisfy z = rkx + yk. Using the change of
variables x 7→ rkx+ yk, combined with (5.4.15) and (5.4.20), we find∫B+
1 (0)
xβm+1 〈∇wk,∇φ〉 dx =rkεk
∫B+
1 (0)
xβm+1 〈∇∂ivk(rkx+ yk),∇φ(x)〉 dx
=r−m−βk
εk
∫B+rk
(yk)
zβm+1
⟨∇∂ivk,∇φ
(z − ykrk
)⟩dz
=r1−m−βk
εk
∫B+rk
(yk)
zβm+1
⟨∇∂ivk,∇φ
⟩dz. (5.4.21)
179
As φ ∈ C∞0 (Brk(yk);Rn) and vk is a minimiser of Eβ relative to O, we have∣∣∣∣∣∫B+rk
(yk)
zβm+1
⟨∇∂ivk,∇φ
⟩dz
∣∣∣∣∣=
∣∣∣∣∣∫B+rk
(yk)
zβm+1
⟨φ, 2A(vk)(∇∂ivk,∇vk) +DA(vk)(∇vk,∇vk, ∂ivk)
⟩dz
∣∣∣∣∣≤ ||φ||L∞(B+
rk(yk);Rn)C
∫B+rk
(yk)
zβm+1(|∇∂ivk|+ 1)dz. (5.4.22)
It follows from (5.4.13) thatr2k
ε2k< 1
δ. Using this fact, changing variables and using
(5.4.15) again, we find∫B+rk
(yk)
zβm+1(|∇∂ivk|+ 1)dz = r1+m+βk
∫B+
1 (0)
xβm+1(|∇∂ivk(rkx+ yk)|+ 1)dx
= εkrm+βk
∫B+
1 (0)
xβm+1(|∇wk|+rkεk
)dx
≤ εkrm+βk
∫B+
1 (0)
xβm+1(|∇wk|+ δ−12 )dx. (5.4.23)
We combine (5.4.21), (5.4.22) and (5.4.23) with the fact that ||φ||L∞(B+rk
(yk);Rn) =
||φ||L∞(B+1 (0);Rn) to see that∣∣∣∣∣
∫B+
1 (0)
xβm+1 〈∇wk,∇φ〉 dx
∣∣∣∣∣ ≤ C||φ||L∞(B+1 (0);Rn)rk
∫B+
1 (0)
xβm+1(|∇wk|+ δ−12 )dx.
(5.4.24)
Now note that for any φ ∈ C∞0 (B1(0);Rn), the weak convergence of wkj to w in
W 1,2β (B+
1 (0);Rn), combined with (5.4.24) and (5.4.16) yields∣∣∣∣∣∫B+
1 (0)
xβm+1〈∇w,∇φ〉dx
∣∣∣∣∣ = limj→∞
∣∣∣∣∣∫B+
1 (0)
xβm+1〈∇wkj ,∇φ〉dx
∣∣∣∣∣≤ C||φ||L∞ lim
j→∞rkj
∫B+
1 (0)
xβm+1(|∇wkj |+ δ−12 )dx
= 0
since rkj → 0. Hence w is a weak solution of (2.4.5) in B+1 (0).
We also conclude, by taking limits in (5.4.16), (5.4.17) and (5.4.18), that∫B+
1 (0)
xβm+1 |∇w|2 dx ≤ 1, (5.4.25)
180
wB+θ (0),β =
1∫B+θ (0)
xβm+1dx
∫B+θ (0)
xβm+1wdx = 0 (5.4.26)
and
θ−(1+m+β)
∫B+θ (0)
xβm+1 |w|2 dx ≥ δ (5.4.27)
respectively, where we have used the Rellich Compactness Lemma, Lemma 2.3.5.2,
to take the limit in (5.4.25) and (5.4.27). Now, in view of (5.4.26), the Poincare
inequality, Lemma 2.3.3.3, yields
θ−(1+m+β)
∫B+θ (0)
xβm+1|w|2dx ≤ Cθ1−m−β∫B+θ (0)
xβm+1|∇w|2dx. (5.4.28)
Lastly, since w is a weak solution of (2.4.5) we may apply Corollary 2.4.3.2 to w
with θ ≤ 14
(so that 2θ ≤ 12). This gives a positive constant C (independent of θ)
and a γ ∈ (0, 1) such that
θ1−m−β∫B+θ (0)
xβm+1|∇w|2dx ≤ C(2θ)2γ. (5.4.29)
Combining (5.4.28) and (5.4.29) we see that
θ−(1+m+β)
∫B+θ (0)
xβm+1|w|2dx ≤ C(2θ)2γ. (5.4.30)
This holds for all fixed θ ∈ (0, 14] and we choose θ < 2−1
(δC
) 12γ so that (5.4.30)
contradicts (5.4.27). Hence the lemma is proved.
5.5 Improved Control in the Poincare Inequal-
ity for First Derivatives in the Interior
We need a counterpart to Lemma 5.4.0.1 which holds on a class of balls with
closure contained in the interior of Rm+1+ .
Lemma 5.5.0.1. Let i = 1, . . . ,m. For every δ > 0 there exist numbers ε > 0,
τ ∈ (0, 1) and θ ∈ (0, 14] such that the following holds. Suppose v is a minimiser of
Eβ relative to O. Let B+R(x0) ⊂ Rm+1
+ be a half-ball with R ≤ 1 and ∂0B+R(x0) ⊂
O. If
R1−m−β∫B+R(x0)
xβm+1 |∇v|2 dx ≤ ε2,
181
then, for every Br(y) ∈ B4(x0, R, τR), either
r1−m∫Br(y)
|∇∂iv|2 dx ≤ δ1
R2
( rR
)2
or
(θr)−(1+m)
∫Bθr(y)
∣∣∂iv − ∂ivBθr(y)
∣∣2 dx ≤ δr1−m∫Br(y)
|∇∂iv|2 dx.
Proof. The method of proof is similar to the proof of Lemma 5.4.0.1. We observe
that the lemma is invariant under scaling and translation with respect to x0 in
∂Rm+1+ in an analogous way to the proof of Lemma 5.4.0.1. Hence we assume
R = 1, x0 = 0, v is a minimiser of Eβ relative to O and ∂0B+1 (0) ⊂ O. We
argue by contradiction. We will show that if the lemma were false, then we may
construct a weak solution of div((1 + axm+1)β∇w) = 0 in B1(0), for a carefully
chosen a ∈ (0, 14], whose L2(B1(0);Rn) norm is bounded below and strictly above
by the same number, a contradiction.
Suppose the statement is false. Then there exists a δ > 0 such that, for any
fixed θ ∈ (0, 14] we may find a sequence (vk)k∈N of minimising harmonic maps,
relative to O, with vk ∈ W 1,2β (B+
1 (0);N) such that∫B+
1 (0)
xβm+1 |∇vk|2 dx := ε2
k → 0,
and, furthermore, a sequence of numbers 0 < τk → 0, balls Brk(yk) ∈ B4(0, 1, τk),
and numbers 0 < rk ≤ τk → 0 such that
r1−mk
∫Brk (yk)
|∇∂ivk|2 dx > δr2k (5.5.1)
and
(θrk)−(1+m)
∫Bθrk (yk)
∣∣∣∂ivk − (∂ivk)Bθrk (yk)
∣∣∣2 dx
> δr1−mk
∫Brk (yk)
|∇∂ivk|2 dx. (5.5.2)
We show that r1−mk
∫Brk (yk)
|∇∂ivk|2 dx→ 0. Discarding as many vk as neces-
sary and re-indexing the resulting sequence, we may suppose that ε2k ≤ ε for every
k, where ε is the number from Theorem 3.12.1.1. Furthermore we may choose this
sequence such that 2τk ≤ θ012
, where θ0 is the number given by Theorem 3.12.1.1,
so that Brk(yk) ⊂ B2rk(yk) ∈ B(0, θ06, θ0
24). It follows that B2rk(yk) ⊂ B+
θ06
(0).
182
Applying Theorem 5.1.0.1, we see that each vk satisfies
||∇vk||2L∞(B+θ03
(0);R(m+1)n)≤ C
θ20
θ1−m−β0
∫B+θ0
(0)
xβm+1|∇vk|2dx.
Furthermore, the boundary monotonicity formula, Lemma 3.3.1.1, implies that
θ1−m−β0
∫B+θ0
(0)
xβm+1|∇vk|2dx ≤∫B+
1 (0)
xβm+1 |∇vk|2 dx = ε2
k.
Thus,
||∇vk||2L∞(B+θ03
(0);R(m+1)n)≤ C
θ20
ε2k → 0. (5.5.3)
Now we make use of the Caccioppoli-type inequality, Lemma 5.3.0.1, with λ = 0,
noting that by Lemma 5.2.0.1 we have ∇∂ivk ∈ L2β(B+
θ06
(0);R(m+1)n) for i =
1, . . . ,m. We apply the lemma on B2rk(yk) ⊂ B+θ06
(0). This yields
∫Brk (yk)
xβm+1 |∇∂ivk|2 dx
≤ C
(||∇vk||2L∞(B2rk
(yk);R(m+1)n) +1
r2k
)∫B2rk
(yk)
xβm+1 |∂ivk|2 dx
+ C||∇vk||6L∞(B2rk(yk);R(m+1)n)
∫B2rk
(yk)
xβm+1dx. (5.5.4)
Since ||∇vk||L∞(B2rk(yk);R(m+1)n) ≤ ||∇vk||L∞(B+
θ03
(0);R(m+1)n) we may combine (5.5.3)
with (5.5.4), multiplying the latter by (yk)−βm+1r
1−mk and using (3.4.4) in Section
3.4, to see that
r1−mk
∫Brk (yk)
|∇∂ivk|2 dx
≤ Cr2k||∇vk||4L∞(B+
θ03
(0);R(m+1)n)+ C||∇vk||2L∞(B+
θ03
(0);R(m+1)n)
+ Cr2k||∇vk||6L∞(B+
θ03
(0);R(m+1)n)
≤ C(r2kε
4k + ε2
k + r2kε
6k)→ 0, (5.5.5)
where C depends on m,N, β and θ0 and hence only on m,N, β. From (5.5.5), we
conclude that
r1−mk
∫Brk (yk)
|∇∂ivk|2 dx := ε2k → 0. (5.5.6)
183
It follows from (5.5.1) and (5.5.2) that
ε2k > δr2
k (5.5.7)
and
(θrk)−(1+m)
∫Bθrk (yk)
∣∣∣∂ivk − (∂ivk)Bθrk (yk)
∣∣∣2 dx > δε2k. (5.5.8)
To find a weak solution of div((1 + axm+1)β∇w) = 0 in B1(0) for some a ∈ (0, 12],
we consider the normalised sequence
wk(x) =∂ivk(rkx+ yk)− (∂ivk)Bθrk (yk)
εk.
We calcuate
∇wk(x) =rkεk∇∂ivk (rkx+ yk) . (5.5.9)
Using the change of variables x 7→ rkx+ yk we thus find∫B1(0)
|∇wk|2 dx = 1, (5.5.10)
(wk)Bθ(0) =1∫
Bθ(0)dx
∫Bθ(0)
wkdx = 0 (5.5.11)
and, also using (5.5.8),
θ−(1+m)
∫Bθ(0)
|wk|2 dx > δ. (5.5.12)
As a result of (5.5.11), we may write wk = wk − (wk)Bθ(0). Hence we can apply
the Poincare inequality, as given in estimate 7.45 of [21], to see that∫B1(0)
|wk|2dx =
∫B1(0)
|wk − (wk)Bθ(0)|2dx ≤ Cθ−(1+m)
∫B1(0)
|∇wk|2 dx.
(5.5.13)
Together, (5.5.10) and (5.5.13) guarantee that (wk)k∈N is a bounded sequence in
W 1,2(B1(0);Rn). The Rellich Compactness lemma, [46] Section 1.3 Lemma 1,
thus yields a subsequence (wkj)j∈N which converges weakly in W 1,2(B1(0);Rn)
and strongly in L2(B1(0);Rn) to some w ∈ W 1,2(B1(0);Rn).
In order to derive the required contradiction, we will show that w is a solution
184
of some PDE which satisfies a mean value inequality, similarly to Euclidean har-
monic functions. To this end, we examine the sequence of maps (fkj)j∈N where
fk is defined by
fk(x) =
(1 +
rk(yk)m+1
xm+1
)βfor each k ∈ N. Note that the sequence of numbers akj =
rkj(ykj )m+1
satisfies
0 ≤ akj ≤ 14
for every j, since each Brk(yk) ∈ B4(0, 1, τk), and thus there is a
subsequence, which we also index with kj which converges to a number a with
0 ≤ a ≤ 14
as j → ∞. Furthermore, the sequence fkj is uniformly bounded and
equicontinuous so, by the Arzela-Ascoli theorem, there is a uniformly convergent
subsequence which we again index by kj. Since fkj(x) converges pointwise to
f(x) = (1 + axm+1)β this must also be the uniform limit of fkj .
We will now show that w is a weak solution of div((1 + axm+1)β∇w) = 0
in B1(0). Let φ ∈ C∞0 (B1(0);Rn) and define φ ∈ C∞0 (Brk(yk);Rn) by φ(z) =
φ(z−ykrk
). We observe that
∇φ(z) = ∇(φ
(z − ykrk
))=
1
rk∇φ(z − ykrk
)=
1
rk∇φ(x) (5.5.14)
where x ∈ B1(0) and z ∈ Brk(yk) satisfy z = rkx + yk. Using the change of
variables x 7→ rkx+ yk, combined with (5.5.9) and (5.5.14), we find∫B1(0)
fk(x) 〈∇wk,∇φ〉 dx
=rkεk
∫B1(0)
fk(x) 〈∇∂ivk(rkx+ yk),∇φ(x)〉 dx
= (yk)−βm+1
r−mkεk
∫Brk (yk)
zβm+1
⟨∇∂ivk,∇φ
(z − ykrk
)⟩dz
= (yk)−βm+1
r1−mk
εk
∫Brk (yk)
zβm+1
⟨∇∂ivk,∇φ
⟩dz. (5.5.15)
As φ ∈ C∞0 (Brk(yk);Rn) and vk is a minimiser we have∣∣∣∣∣∫Brk (yk)
zβm+1
⟨∇∂ivk,∇φ
⟩dz
∣∣∣∣∣=
∣∣∣∣∣∫Brk (yk)
zβm+1
⟨φ, 2A(vk)(∇∂ivk,∇vk) +DA(vk)(∇vk,∇vk, ∂ivk)
⟩dz
∣∣∣∣∣≤ ||φ||L∞(Brk (yk);Rn)C
∫Brk (yk)
zβm+1(|∇∂ivk|+ 1)dz. (5.5.16)
185
It follows from (5.5.7) thatr2k
ε2k≤ δ−1. Using this fact, changing variables and
using (5.5.9) again, we find∫Brk (yk)
zβm+1(|∇∂ivk|+ 1)dz
= (yk)βm+1r
1+mk
∫B1(0)
fk(x)(|∇∂ivk(rkx+ yk)|+ 1)dx
= (yk)βm+1εkr
mk
∫B1(0)
fk(x)(|∇wk|+rkεk
)dx
≤ (yk)βm+1εkr
mk
∫B1(0)
fk(x)(|∇wk|+ δ−12 )dx. (5.5.17)
We combine (5.5.15), (5.5.16) and (5.5.17) with the fact that ||φ||L∞(Brk (yk);Rn) =
||φ||L∞(B1(0);Rn) and supB1(0) |fk| is uniformly bounded in k to see that∣∣∣∣∫B1(0)
fk(x) 〈∇wk,∇φ〉 dx∣∣∣∣ ≤ C||φ||L∞(B1(0);Rn)rk
∫B1(0)
(|∇wk|+ δ−12 )dx.
(5.5.18)
Next we show that∫B1(0)
f(x)〈∇w,∇φ〉dx = limj→∞
∫B1(0)
fkj(x)〈∇wkj ,∇φ〉dx.
To see this, note that∫B1(0)
f(x)〈∇w,∇φ〉dx−∫B1(0)
fkj(x)〈∇wkj ,∇φ〉dx
=
∫B1(0)
f(x)〈∇w −∇wkj ,∇φ〉dx+
∫B1(0)
(f(x)− fkj(x))〈∇wkj ,∇φ〉dx.
The weak convergence of wkj to w in W 1,2(B1(0);Rn) guarantees that
limj→∞
∫B1(0)
f(x)〈∇w −∇wkj ,∇φ〉dx = 0.
Furthermore, we apply Holder’s inequality to see that∣∣∣∣∫B1(0)
(f(x)− fkj(x))〈∇wkj ,∇φ〉dx∣∣∣∣
≤ C||∇φ||L∞(B1(0);R(m+1)n) supB1(0)
|f − fkj |(∫
B1(0)
|∇wkj |2dx
) 12
.
186
Since ∇wkj is bounded in L2 by (5.5.10) we have∣∣∣∣∫B1(0)
(f(x)− fkj(x))〈∇wkj ,∇φ〉dx∣∣∣∣ ≤ C||∇φ||L∞(B1(0);R(m+1)n) sup
B1(0)
|f − fkj |
→ 0 as j →∞,
since fkj → f uniformly. Thus∫B1(0)
f(x)〈∇w,∇φ〉dx = limj→∞
∫B1(0)
fkj(x)〈∇wkj ,∇φ〉dx. (5.5.19)
Using (5.5.10), (5.5.18) and (5.5.19) we conclude that for every φ ∈ C∞0 (B1(0);Rn)
we have∣∣∣∣∫B1(0)
f(x)〈∇w,∇φ〉dx∣∣∣∣ = lim
j→∞
∣∣∣∣∫B1(0)
fkj(x)〈∇wkj ,∇φ〉dx∣∣∣∣
≤ C||φ||L∞(B1(0);Rn) limj→∞
rkj
∫B1(0)
(|∇wkj |+ δ−
12
)dx
= 0.
Hence w is a weak solution of div((1 + axm+1)β∇w) = 0 in B1(0). By linear
elliptic regularity theory, w is smooth in B1(0). We also conclude by taking
limits in (5.5.10), (5.5.11) and (5.5.12) that∫B1(0)
|∇w|2 dx ≤ 1, (5.5.20)
wBθ(0) =1∫
Bθ(0)dx
∫Bθ(0)
wdx = 0 (5.5.21)
and
θ−(1+m)
∫Bθ(0)
|w|2 dx ≥ δ (5.5.22)
respectively using the Rellich compactness lemma for (5.5.20) and (5.5.22). Now,
in view of (5.5.21) the Poincare inequality yields
θ−(1+m)
∫Bθ(0)
|w|2dx ≤ Cθ1−m∫Bθ(0)
|∇w|2dx. (5.5.23)
We recall that ∇w satisfies a mean value inequality, namely supBθ(0) |∇w|2 ≤
187
C(m,β)∫B1(0)|∇w|2dx as shown in theorem 2.1 in section III of [20]. Hence
θ1−m∫Bθ(0)
|∇w|2dx ≤ Cθ2
∫B1(0)
|∇w|2dx. (5.5.24)
Combining (5.5.20) with (5.5.23) and (5.5.24) we see that
θ−(1+m)
∫Bθ(0)
|w|2dx ≤ Cθ2. (5.5.25)
This holds for all fixed θ ∈ (0, 12] and we choose θ <
(δC
) 12 then (5.5.25) contradicts
(5.5.22). Hence the lemma is proved.
5.6 Holder Continuity of First Order Deriva-
tives
The culmination of all of our theory so far is the following ε-regularity theorem
for minimisers of Eβ relative to O.
Theorem 5.6.0.1. Let v ∈ W 1,2β (Rm+1
+ ;N) be a minimiser of Eβ relative to
O, let ε > 0 be the number from Theorem 3.12.1.1 and let B+R(x0) be a half-
ball with R ≤ 1 and ∂0B+R(x0) ⊂ O. Suppose R1−m−β ∫
B+R(x0)
xβm+1|∇v|2dx ≤ ε.
Then there is a θ = θ(m,N, β) ∈ (0, 1) and a γ = γ(m,N, β) ∈ (0, 1) such that
∂iv ∈ C0,γ(B+θR(x0);Rn) for i = 1, . . . ,m.
Proof. First we observe that the statement of the lemma is invariant under rescal-
ing and translation by any point in ∂Rm+1+ . If the lemma is true on B+
1 (0) for
minimisers of Eβ relative to O whenever ∂0B+1 (0) ⊂ O, then we may obtain the
lemma on B+R(x0) for a minimiser of Eβ relative to O whenever ∂0B+
R(x0) ⊂ Oand R ≤ 1. This follows from rescaling using the map x 7→ Rx + x0, defined for
x ∈ B+1 (0), and applying the lemma on B+
1 (0) to the map vR(x) = v(Rx + x0).
Thus we will assume R = 1 and ∂0B+1 (0) ⊂ O.
First we observe that the combination of Theorem 3.12.1.1, Lemma 5.1.0.1
and Lemma 5.2.0.1 yield a θ = θ(m,N, β) ≤ 12
and a γ ∈ (0, 1) such that
v ∈ C0,γ(B+
θ(0);N) with ∇v ∈ L∞(B+
θ(0);R(m+1)n), ∂iv ∈ W 1,2
β (B+
θ(0);Rn) for
i = 1, . . . ,m. Applying Lemma 5.3.0.1, re-formulating the statement slightly, we
188
see that ∫B ρ
2(y)∩Rm+1
+
xβm+1 |∇∂iv|2 dx
≤ C
ρ2
∫Bρ(y)∩Rm+1
+
xβm+1 |∂iv − λ|2 dx
+ C|λ|2||∇v||2L∞(Bρ(y)∩Rm+1
+ ;R(m+1)n)
∫Bρ(y)∩Rm+1
+
xβm+1dx
+ C||∇v||4L∞(Bρ(y)∩Rm+1
+ ;R(m+1)n)
∫Bρ(y)∩Rm+1
+
xβm+1dx
+ C||∇v||6L∞(Bρ(y)∩Rm+1
+ ;R(m+1)n)
∫Bρ(y)∩Rm+1
+
xβm+1dx (5.6.1)
for any Bρ(y) ⊂ Bθ(0) with ym+1 ≥ 0. We apply Lemmata 5.4.0.1 and 5.5.0.1
with δ = 12
12m+2C
where C is the constant from (5.6.1). The powers of 2 appear
in the choice of δ as we will later need to multiply (5.6.1) by 2m+1 or 2m+1+β,
depending on the context, and the given δ ensures the factor outside the integral
involving ∂iv − λ remains less than a half. An application of the lemmata gives
numbers ε1 > 0, τ1 ∈ (0, 1) and θ1 ∈ (0, 14] and ε2 > 0, τ2 ∈ (0, 1) and θ2 ∈ (0, 1
4]
respectively such that the following holds. Let R1, R2 ∈ (0, 1]. If
R1−m−β1
∫B+R1
(0)
xβm+1|∇v|2dx ≤ ε21 (5.6.2)
then for every B+r1
(y) ∈ B+(0, R1, τ1R1) either
r1−m−β1
∫B+r1
(y)
xβm+1 |∇∂iv|2 dx ≤ δ
1
R21
(r1
R1
)2
(5.6.3)
or
(θ1r1)−(1+m+β)
∫B+θ1r1
(y)
xβm+1
∣∣∣∂iv − ∂ivB+θ1r1
(y),β
∣∣∣2 dx
≤ δr11−m−β
∫B+r1
(y)
xβm+1 |∇∂iv|2 dx. (5.6.4)
Furthermore, if
R1−m−β2
∫B+R2
(0)
xβm+1|∇v|2dx ≤ ε22 (5.6.5)
189
then for every Br2(y) ∈ B4(0, R2, τ2R2) either
r21−m
∫Br2 (y)
|∇∂iv|2 dx ≤ δ1
R22
(r2
R2
)2
(5.6.6)
or
(θ2r2)−(1+m)
∫Bθ2r2 (y)
∣∣∣∂iv − ∂ivBθ2r2 (y)
∣∣∣2 dx ≤ δr21−m
∫Br2 (y)
|∇∂iv|2 dx. (5.6.7)
We now show that (5.6.2) and (5.6.5) hold simultaneously for some R = R1 =
R2. It follows from the proof of Theorem 3.12.1.1, bearing in mind R = 1, that
for every B+r (y) ∈ B+(0, 1, 1
2) we have
r1−m−β∫B+r (y)
xβm+1|∇v|2dx ≤ Crγ
for some γ ∈ (0, 1) and some constant C. In particular, this holds for y = 0
and r ≤ 12. Hence if R = R(m,N, β) = (min ε
21
C,ε22C,(θ2
)γ)
1γ then (5.6.2) and
(5.6.5) hold on B+
R(0), that is, with R1 = R2 = R. We have assumed R ≤ θ
2so
that we may later apply (5.6.1) with impunity on any ball or half-ball in B+
R(0).
Consequently, either (5.6.3) or (5.6.4) and either (5.6.6) or (5.6.7) hold for some
τ1, θ1, τ2, θ2 depending on δ and thus only on m,N, β. We claim this is sufficient
for us to deduce the hypothesis of Lemma 3.5.0.2 hold.
First we show that (3.5.3) holds on every B+r1
(y) ∈ B+(0, R, τ1R). To see
this we use an iterative procedure. Consider r11−m−β ∫
B+r1
(y)xβm+1|∇∂iv|2dx. We
know that (5.6.3) or (5.6.4) holds on B+r1
(y) with R1 = R. We apply 5.6.1 with
λ = ∂ivB+θ1r1
(y),β, noting that |λ| ≤ ||∇v||L∞(B+θ1r1
(y);R(m+1)n). We deduce that
(θ1r1
2
)1−m−β ∫B+θ1r1
2
(y)
xβm+1 |∇∂iv|2 dx
≤ C2m+β−1(θ1r1)−(1+m+β)
∫B+θ1r1
(y)
xβm+1
∣∣∣∂iv − ∂ivB+θ1r1
(y),β
∣∣∣2 dx
+ C(||∇v||4L∞(B+
θ(0);R(m+1)n)
+ ||∇v||6L∞(B+
θ(0);R(m+1)n)
)r21. (5.6.8)
Hence, regardless of which of (5.6.3) or (5.6.4) holds (bearing in mind our choice
190
of δ above), we have
(σ1r1)1−m−β∫B+σ1r1
(y)
xβm+1 |∇∂iv|2 dx
≤ 1
2r1
1−m−β∫B+r1
(y)
xβm+1|∇∂iv|2dx+ Cr21, (5.6.9)
where σ1 = θ12
and C may depend on positive powers of ||∇v||L∞(B+
θ(0);Rn) and,
moreover, on R, θ1,m,N and β and hence only on m,N, β as R = R(m,N, β)
and θ1 = θ1(m,N, β). This holds for any B+r1
(y) ∈ B+(0, R, τ1R). In particular,
we may apply (5.6.9) with r1 replaced by σk1r1 for every k ∈ N. This gives
(σk1r1
)1−m−β∫B+
σk1 r1(y)
xβm+1 |∇∂iv|2 dx
≤ 1
2(σk−1
1 r1)1−m−β
∫B+
σk−11 r1
(y)
xβm+1|∇∂iv|2dx+ C(σk−11 r1)2. (5.6.10)
We iteratively deduce that
(σk1r1
)1−m−β∫B+
σk1 r1(y)
xβm+1 |∇∂iv|2 dx
≤ 1
2kr1
1−m−β∫B+r1
(y)
xβm+1|∇∂iv|2dx+ Ck−1∑j=0
2−j(σk−1−j1 r1)2. (5.6.11)
Consider the sum on the right hand side above. Recall that σ1 = θ12∈ (0, 1
8].
Hence,
C
k−1∑j=0
2−j(σk−1−j1 r1)2 =
Cr21
2k
k−1∑j=0
2k−jσk−1−j1 σk−1−j
1
≤ Cr21
2kσ−2
1
k−1∑j=0
2k−jσk−j1 σk−j1
≤ Cr21
2k
∞∑j=0
σj1
≤ Cr21
2k. (5.6.12)
191
Substituting (5.6.12) into (5.6.11) yields
(σk1r1
)1−m−β∫B+
σk1 r1(y)
xβm+1 |∇∂iv|2 dx
≤ 1
2k
(r1
1−m−β∫B+r1
(y)
xβm+1|∇∂iv|2dx+ Cr21
). (5.6.13)
Let γ1 = − ln 2lnσ1∈ (0, 1). Then (σk1)γ1 = 2−k and so
(σk1r1
)1−m−β∫B+
σk1 r1(y)
xβm+1 |∇∂iv|2 dx
≤ (σk1r1)γ1
rγ1
1
(r1
1−m−β∫B+r1
(y)
xβm+1|∇∂iv|2dx+ Cr21
).
Now note that for any r ≤ r1 we have r ∈ [σk+11 r1, σ
k1r1] for some k ∈ N0. Thus
there is a number c1 ∈ [1, σ−11 ] so that c1r = σk1r1. Hence we deduce that
r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx
≤ σ1−m−β−γ1
1
(r
r1
)γ1(r1
1−m−β∫B+r1
(y)
xβm+1|∇∂iv|2dx+ Cr21
)(5.6.14)
for any r ≤ r1. This holds for any B+r1
(y) ∈ B+(0, R, τ1R).
We want a similar estimate for r21−m ∫
Br2 (y)|∇∂iv|2 dx on balls Br2(y) ∈
B4(0, R, τ2R). A similar argument which lead to (5.6.14) yields the existence
of a γ2 = γ2(m,N, β) ∈ (0, 1) such that for any Br2(y) ∈ B4(0, R, τ2R) and any
r ≤ r2 we have
r1−m∫Br(y)
|∇∂iv|2 dx ≤ σ1−m−γ2
2
(r
r2
)γ2(r2
1−m∫Br2 (y)
|∇∂iv|2dx+ Cr22
),
(5.6.15)
where σ2 = θ22
. Together, (5.6.14) and (5.6.15) essentially constitute (3.5.3) and
(3.5.4) from Lemma 3.5.0.2. We now show that these hypothesis are actually
satisfied.
Let τ = min2τ13, τ2,
12, γ = minγ1, γ2. We apply (5.6.14) with r1 = τR.
192
Then for every B+r (y) ∈ B+(0, R, τ R) we have B+
τR(y) ∈ B+(0, R, τ1R) and hence
r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx
≤ C
(r
τR
)γ ((τR)1−m−β
∫B+
τR(y)
xβm+1|∇∂iv|2dx+ C(τR)2
). (5.6.16)
Furthermore, applying (5.6.1) with λ = 0 implies that
r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx ≤ C(1 + (τR)2) ≤ C, (5.6.17)
for every r ≤ τR, where C may depend on positive powers of ||∇v||L∞(B+
θ(0);R(m+1)n)
and m,N, β. We combine (5.6.16) and (5.6.17) to see that for every B+r (y) ∈
B+(0, R, τ R) we have
r1−m−β∫B+r (y)
xβm+1 |∇∂iv|2 dx ≤ C
(r
τR
)γ≤ C1r
γ, (5.6.18)
where C1 depends on m,N, β, R and τ and hence only on m,N and β, which is
(3.5.3) in Lemma 3.5.0.2. To see that (3.5.4) holds, we proceed as follows. Let
Br(y) ∈ B4(0, R, 2τ3R). Then
Br(y) ⊂ B ym+14
(y) ⊂ B+3ym+1
2
(y+) ⊂ B+
τR(y+) ∈ B+(0, R, τ R). (5.6.19)
Recalling (3.4.4) from Section 3.4, we note that(ym+1
4
)1−m∫B ym+1
4(y)
|∇∂iv|2 dx
≤ C
(3ym+1
2
)1−m−β ∫B+
3ym+12
(y+)
xβm+1 |∇∂iv|2 dx. (5.6.20)
Since ym+1 ≤ τR ≤ 1, applying (5.6.15) on B ym+14
(y) ∈ B4(0, R, τ2R), using
193
(5.6.20), and then applying (5.6.18) gives
r1−m∫Br(y)
|∇∂iv|2 dx
≤ C
(4r
ym+1
)γ(ym+1
4
)1−m∫B ym+1
4(y)
|∇∂iv|2 dx+ Cy2m+1
≤ C
(r
ym+1
)γC (3ym+1
2
)1−m−β ∫B+
3ym+12
(y+)
xβm+1 |∇∂iv|2 dx+ Cy2
m+1
≤ C
(r
ym+1
)γ (ym+1
τR
)γ+ Crγy2−γ
m+1
≤ C2rγ (5.6.21)
where C2 depends on m,N, β, R and τ and hence only on m,N and β, which is
(3.5.4). Choosing C = maxC1, C2 to be the largest constant from (5.6.18) and
(5.6.21) we deduce that both hypothesis of Lemma 3.5.0.2 hold simlutaneously
for B+r (y) ∈ B+(0, R, 2τ
3R) and Br(y) ∈ B4(0, R, 2τ
3R). Applying this lemma
concludes the proof.
Theorem 5.6.0.1 yields an improvement to the partial regularity theorem for
minimisers of Eβ relative to O, Theorem 3.12.2.1, stated in Section 3.12.2. We
have the following.
Lemma 5.6.0.1. Suppose v ∈ W 1,2β (Rm+1
+ ;N) is a minimiser of Eβ relative to
O. Let Σint ⊂ Rm+1+ denote the set of points, discussed in Section 3.2, which is
relatively closed in Rm+1+ and has Hausdorff dimension m−2, such that v is smooth
in Rm+1+ \Σint. Then there exist γ ∈ (0, 1) and a relatively closed set Σbdry ⊂ O of
vanishing m+β−1-dimensional Hausdorff measure, with respect to the Euclidean
metric, such that v ∈ C0,γ((Rm+1+ ∪O)\Σ;N) and ∂iv ∈ C0,γ((Rm+1
+ ∪O)\Σ;Rn)
for i = 1, . . . ,m, where Σ = Σint ∪ Σbdry. Furthermore Σ is relatively closed in
Rm+1+ ∪ O and Hm+β−1(Σ) = 0.
Proof. As in the proof of Lemma 3.12.2.1, define
Σbdry = y ∈ O : Θβv (y) ≥ ε
where ε is the number given by Theorem 3.12.1.1 and
Θβv (y) = lim
r→0+r1−m−β
∫B+r (y)
xβm+1|∇v|2dx
194
is the density function defined in Section 3.3.1. Let Σ = Σint ∪ Σbdry. We have
already proved every claim of this lemma for this choice of Σ, with the exception
of ∂iv ∈ C0,γ((Rm+1+ ∪O)\Σ;Rn) for i = 1, . . . ,m, in the proof of Lemma 3.12.2.1.
We proceed to prove the remaining claim.
Let x0 ∈ (Rm+1+ ∪O)\Σ. If x0 ∈ Rm+1
+ then x0 ∈ Rm+1+ \Σint and the discussion
in Section 3.2 after Theorem 3.2.0.1 implies that v is smooth in an open ball
centred at x0 and contained in Rm+1+ \Σint ⊂ (Rm+1
+ ∪O)\Σ. If x0 ∈ O then x0 ∈O\Σbdry and Θβ
v (x0) < ε which, combined with the fact thatO\Σbdry is open inO,
implies there exists an R > 0 such that R1−m−β ∫B+R(x0)
xβm+1|∇v|2dx ≤ ε, R ≤ 1
and ∂0B+R(x0) ⊂ O\Σbdry. Consequently, Theorem 5.6.0.1 implies that there are
θ, γ ∈ (0, 1) such that ∂iv ∈ C0,γ(B+θR(x0);Rn) for i = 1, . . . ,m. However, we also
know that (Rm+1+ ∪ O)\Σ is open in Rm+1
+ ∪ O. Hence there exists R > 0 such
that B+
R(x0) ∪ ∂0B+
R(x0) ⊂ (Rm+1
+ ∪ O)\Σ. Setting r = minθR, R we conclude
∂iv ∈ C0,γ(B+r (x0);Rn) and B+
r (x0)∪∂0B+r (x0) ⊂ (Rm+1
+ ∪O)\Σ which completes
the proof.
195
Chapter 6
Fractional Harmonic Maps
We define and analyse a family of functionals whose critical points are Fractional
Harmonic Maps. Our goal is to connect the variational problem for the function-
als defined in this section to the variational problem for the energies Eβ defined
in Chapter 3. This will permit us to apply our regularity theory for minimisers of
the energy to minimising Fractional Harmonic Maps. We assume the conditions
on m,β specified in Remark 2.2.1.1 hold throughout this chapter.
Let O ⊂ ∂Rm+1+ be open and such that a continuous linear trace operator
T : W 1,2β (Rm+1
+ ;Rn) → Lp(O;Rn) exists as in the discussion in Section 2.3.2,
where p = p(β). Define
Iβ(u) = infEβ(v) : v ∈ W 1,2β (Rm+1
+ ;N), T v = u (6.0.1)
for u ∈ T (W 1,2β (Rm+1
+ ;N)). The functional Iβ serves as an intrinsic energy for
u in its domain, as described in Chapter 1. We note that I0 coincides with the
functional I defined by (1.0.2). Minimisers of Iβ are defined as follows.
Definition 6.0.0.1. Let u ∈ T (W 1,2β (Rm+1
+ ;N)). We say that u minimises Iβ if
for every compact K ⊂ O and every u ∈ T (W 1,2β (Rm+1
+ ;N)) with u|O\K = u|O\Kwe have Iβ(u) ≤ Iβ(u). A minimiser of Iβ will be called an intrinsic minimising1−β
2-harmonic map. For convenience, as we consider no other kind of fractional
harmonic map, we drop the prefixes intrinsic and minimising. Any 1−β2
-harmonic
map will also be broadly referred to as a fractional harmonic map.
First we show that for every u ∈ T (W 1,2β (Rm+1
+ ;N)), the intrinsic energy
Iβ(u) is attained by some v ∈ W 1,2β (Rm+1
+ ;N). To this end we make the following
definition.
Definition 6.0.0.2. Let v ∈ W 1,2β (Rm+1
+ ;N). We say that v is a minimal har-
monic map if Eβ(v) ≤ Eβ(w) for all w ∈ W 1,2β (Rm+1
+ ;N) with Tw = Tv.
196
Lemma 6.0.0.1. Suppose O is open and bounded. Let u ∈ T (W 1,2β (Rm+1
+ ;N)).
Then there exists a minimal harmonic map v with Tv = u.
Proof. We recall, see Section 2.2, that W 1,2β (Rm+1
+ ;Rn) is a Hilbert space and
thus a reflexive Banach space. Furthermore, Eβ is weakly lower semi-continuous
because it is the square of a norm on a Hilbert space, and it is coercive by
definition. Consider the set
S = v ∈ W 1,2β (Rm+1
+ ;N) : Tv = u
which is non-empty by definition. If we can show this set is sequentially weakly
closed then the direct method applies and Eβ attains a minimum in S; that is,
we can find a minimal harmonic map v ∈ W 1,2β (Rm+1
+ ;N) with Tv = u. Hence
suppose (vk)k∈N is a sequence in S with vk v in W 1,2β (Rm+1
+ ;Rn). We want to
show v ∈ S, that is, v(x) ∈ N for almost every x ∈ Rm+1+ and Tv = u.
First we show that we must have v(x) ∈ N for almost every x ∈ Rm+1+ . Note
that weakly convergent sequences are bounded in W 1,2β (Rm+1
+ ;Rn). Now observe
that in view of Lemmata 2.2.1.1, 2.3.5.1 and 2.3.5.2, for every bounded open
Ω ⊂ Rm+1+ we have a compact embedding W 1,2
β (Rm+1+ ;Rn) → W 1,2
β (Ω;Rn) →L2β(Ω;Rn). We write Rm+1
+ as a countable union of sets Ωn and deduce that there
exist subsequences (vk)k∈Λn of (vk)k∈N such that for every n ∈ N, Λn is an infinite
set, Λn+1 ⊂ Λn and (vk)k∈Λn converges to v pointwise almost everywhere in Ωn.
Hence, we may choose a strictly increasing sequence (kn)n∈N with kn ∈ Λn for
every n. It follows that vkn → v pointwise almost everywhere in Rm+1+ and since
each vkn satisfies vkn(x) ∈ N for almost every x ∈ Rm+1+ , we find v(x) ∈ N for
almost every x ∈ Rm+1+ .
To conclude, we must show that Tv = u. As T is continuous, linear and
its domain and codomain are Banach spaces, we have Tvk Tv. However,
Tvkk∈N is a constant sequence with Tvk = u for every k. Hence Tvk converges
strongly and thus weakly to u. The uniqueness of weak limits therefore yields
Tv = u. It follows that S is sequentially weakly closed and the direct method
applies so the lemma is proved.
An identical calculation to the derivation of the Euler-Lagrange equations for
Eβ, see Section 3.1.1, shows that any minimal harmonic map v satisfies∫Rm+1
+
xβm+1 (〈∇v,∇ψ〉 − 〈ψ,A(v)(∇v,∇v)〉) dx = 0 (6.0.2)
for every ψ ∈ C∞0 (Rm+1+ ;Rn). Here we may not allow ψ with non-zero boundary
197
values in view of the boundary condition Tv = u. In other words, v is a weak
solution of
div(xβm+1∇v) + xβm+1A(v)(∇v,∇v) = 0 in Rm+1+ .
In order to analyse variations of Iβ we must consider the left hand side of (6.0.2)
for ψ with non-zero boundary values, in which case this integral is no longer
necessarily zero for a given minimal harmonic map v. We observe the following.
Lemma 6.0.0.2. Let u ∈ T (W 1,2β (Rm+1
+ ;N)), v ∈ W 1,2β (Rm+1
+ ;N) be a minimial
harmonic map with Tv = u and ψ ∈ D+(Rm+1+ ;Rn) with ψ(x′, 0) = φ(x′) for
φ ∈ C∞0 (O;Rn). Then the integral∫Rm+1
+
xβm+1 (〈∇v,∇ψ〉 − 〈ψ,A(v)(∇v,∇v)〉) dx (6.0.3)
only depends on φ.
In order to prove this lemma, we will consider the integral (6.0.3) for ψ ∈D+(Rm+1
+ ;Rn) with ψ(x′, 0) = φ(x′) = 0. In particular, we will show that any
such ψ may be approximated by a sequence of C∞0 (Rm+1+ ;Rn) functions in a
suitable sense. To this end, recall the cutoff function χ ∈ C∞0 (R; [0, 1]) defined
by (3.3.1) in Section 3.3.1:
χ(s) =
0 s ∈ (−∞, 1
2)
0 ≤ χ(s) ≤ 1 s ∈ [12, 1)
1 s ∈ [1,∞).
For δ > 0 define χδ(xm+1) = χ(xm+1
δ). The pointwise limit as δ 0 is
χ(s) =
0 xm+1 ∈ (−∞, 0)
1 xm+1 ∈ [0,∞)
and (χδ)′(xm+1) = 1
δχ′(xm+1
δ) = 0 outside the interval [ δ
2, δ].
Lemma 6.0.0.3. Let ψ ∈ D+(Rm+1+ ;Rn) with ψ(x′, 0) = 0. Then the se-
quence (ψk)k∈N defined by ψk = χ 1kψ ∈ C∞0 (Rm+1
+ ;Rn) satisfies ψk → ψ in
W 1,2β (Rm+1
+ ;Rn) and uniformly in Rm+1+ .
Proof. Consider the sequence (ψk)k∈N = (χ 1kψ)k∈N. By definition we have ψk ∈
198
C∞0 (Rm+1+ ;Rn) for every k. First we show ψk → ψ in W 1,2
β (Rm+1+ ;Rn). We have∫
Rm+1+
xβm+1|∇(χ 1kψ)−∇ψ|2dx ≤ 2
∫Rm+1
+
xβm+1(1− χ 1k)2|∇ψ|2dx
+ 2
∫Rm+1
+
xβm+1(χ′1k)2|ψ|2dx. (6.0.4)
We consider the terms on the right hand side of (6.0.4). Observe that (1−χ 1k)2 →
0 pointwise and xβm+1(1 − χ 1k)2|∇ψ|2 ≤ xβm+1|∇ψ|2 ∈ L1(Rm+1
+ ;Rn). Hence,
Lebesgue’s Dominated Convergence Theorem implies that∫Rm+1
+
xβm+1(1− χ 1k)2|∇ψ|2dx→ 0 as k →∞. (6.0.5)
Now we consider the remaining term in (6.0.4). We integrate with respect to
xm+1, using the fact that ψ(x′, 0) = 0 for every x′ ∈ Rm, to see that
∫Rm+1
+
xβm+1(χ′1k)2|ψ|2dx ≤
∫Rm
∫ 1k
0
xβm+1(χ′1k)2
∣∣∣∣∫ xm+1
0
∂ψ
∂xm+1
ds
∣∣∣∣2 dxm+1dx′.
(6.0.6)
Using Holder’s inequality followed by Fubini’s theorem we find∫Rm
∫ 1k
0
xβm+1(χ′1k)2
∣∣∣∣∫ xm+1
0
∂ψ
∂xm+1
ds
∣∣∣∣2 dxm+1dx′
=
∫Rm
∫ 1k
0
xβm+1(χ′1k)2
∣∣∣∣∫ xm+1
0
s−β2 s
β2
∂ψ
∂xm+1
ds
∣∣∣∣2 dxm+1dx′
≤ C
∫Rm
∫ 1k
0
xm+1(χ′1k)2
∫ xm+1
0
sβ∣∣∣∣ ∂ψ
∂xm+1
∣∣∣∣2 dsdxm+1dx′
≤ C
∫Rm
∫ 1k
0
|χ′1k|dxm+1
∫ 1k
0
sβ∣∣∣∣ ∂ψ
∂xm+1
∣∣∣∣2 dsdx′
≤ C
∫Rm
∫ 1k
0
sβ∣∣∣∣ ∂ψ
∂xm+1
∣∣∣∣2 dsdx′. (6.0.7)
Since sβ∣∣∣ ∂ψ∂xm+1
∣∣∣2 1Rm×[0, 1k
] ≤ sβ∣∣∣ ∂ψ∂xm+1
∣∣∣2 ∈ L1(Rm+1+ ;Rn) we may use Lebesgue’s
Dominated Convergence Theorem to see that∫Rm
∫ 1k
0
sβ∣∣∣∣ ∂ψ
∂xm+1
∣∣∣∣2 dsdx′ → 0 as k →∞. (6.0.8)
199
Hence, combining (6.0.4), (6.0.5), (6.0.6), (6.0.7) and (6.0.8) we see that∫Rm+1
+
xβm+1|∇(χ 1kψ)−∇ψ|2dx→ 0 as k →∞
as required.
Now we will show that ψk → ψ uniformly on Rm+1+ . To see this, observe that
ψk = ψ on Rm × [ 1k,∞) and hence
supx∈Rm+1
+
|ψk(x)− ψ(x)| = supx∈Rm×[0, 1
k]
|ψk(x)− ψ(x)| ≤ supx∈Rm×[0, 1
k]
|ψ(x)|. (6.0.9)
Since ψ ∈ D+(Rm+1+ ;Rn) it follows that ∇ψ is bounded in Rm+1
+ . We combine
this fact with the assumption ψ(x′, 0) = 0 for every x′ ∈ Rm to see that
|ψ(x)| ≤∫ xm+1
0
∣∣∣∣ ∂ψ
∂xm+1
∣∣∣∣ ds ≤ ∫ 1k
0
∣∣∣∣ ∂ψ
∂xm+1
∣∣∣∣ ds ≤ 1
k||∇ψ||L∞(Rm+1
+ ;R(m+1)n)
(6.0.10)
for every x ∈ Rm × [0, 1k]. Together (6.0.9) and (6.0.10) imply
supx∈Rm+1
+
|ψk(x)− ψ(x)| → 0 as k →∞
which concludes the proof.
Proof of Lemma 6.0.0.2. Let v be minimal harmonic map with Tv = u. Then
for every ψ ∈ D+(Rm+1+ ;Rn) we calculate∣∣∣∣∣
∫Rm+1
+
xβm+1 (〈∇v,∇ψ〉 − 〈ψ,A(v)(∇v,∇v)〉) dx
∣∣∣∣∣≤ ||v||W 1,2
β (Rm+1+ ;Rn)||ψ||W 1,2
β (Rm+1+ ;Rn) + C||ψ||L∞(Rm+1
+ ;Rn)||v||2W 1,2β (Rm+1
+ ;Rn)
(6.0.11)
for a constant C depending on N . Now let φ ∈ C∞0 (O;Rn) and suppose ψ, ψ ∈D+(Rm+1
+ ;Rn) satisfy ψ(x′, 0) = ψ(x′, 0) = φ(x′) for every x′ ∈ Rn. Define ψ =
ψ − ψ. Then ψ ∈ D+(Rm+1+ ;Rn) and ψ(x′, 0) = 0 for every x′ ∈ Rm. Let (ψk)k∈N
be the approximating sequence given by Lemma 6.0.0.3 with ψk ∈ C∞0 (Rm+1+ ;Rn)
for every k. Then∫Rm+1
+
xβm+1 (〈∇v,∇ψk〉 − 〈ψk, A(v)(∇v,∇v)〉) dx = 0
200
for every k by (6.0.2). Furthermore, since ψk → ψ both in W 1,2β (Rm+1
+ ;Rn) and
uniformly on Rm+1+ , using (6.0.11) we see that∣∣∣∣∣
∫Rm+1
+
xβm+1 (〈∇v,∇(ψk − ψ)〉 − 〈(ψk − ψ), A(v)(∇v,∇v)〉) dx
∣∣∣∣∣≤ ||v||W 1,2
β (Rm+1+ ;Rn)||ψk − ψ||W 1,2
β (Rm+1+ ;Rn) + C||ψk − ψ||L∞(Rm+1
+ ;Rn)||v||2W 1,2β (Rm+1
+ ;Rn)
→ 0 as k →∞. (6.0.12)
Hence, ∫Rm+1
+
xβm+1 (〈∇v,∇ψ〉 − 〈ψ,A(v)(∇v,∇v)〉) dx = 0
and ∫Rm+1
+
xβm+1 (〈∇v,∇ψ1〉 − 〈ψ1, A(v)(∇v,∇v)〉) dx
=
∫Rm+1
+
xβm+1 (〈∇v,∇ψ2〉 − 〈ψ2, A(v)(∇v,∇v)〉) dx.
It follows that the integral (6.0.3) only depends on φ as required.
A formal calculation suggests that if ψ ∈ D+(Rm+1+ ;Rn) with ψ(x′, 0) = φ(x′)
for φ ∈ C∞0 (O;Rn), then for any minimal harmonic map v we have∫Rm+1
+
xβm+1 (〈ψ,A(v)(∇v,∇v)〉 − 〈∇v,∇ψ〉) dx
=
∫O
⟨lim
xm+1→0+xβm+1
∂v
∂xm+1
(x′, xm+1), φ(x′)
⟩dx′.
This will only be the case if v has sufficient regularity in Rm+1+ ∪ O. However,
as a consequence of Lemma 6.0.0.2 we see that the integral (6.0.3) defines a
distribution on O. We write
∂βm+1v(φ) =
∫Rm+1
+
xβm+1 (〈ψ,A(v)(∇v,∇v)〉 − 〈∇v,∇ψ〉) dx (6.0.13)
for every φ ∈ C∞0 (O;Rn). This observation allows us, analogously to [34] Propo-
sition 1.1, to identify a superdifferential for Iβ. Recall that πN denotes the nearest
point projection onto N .
Proposition 6.0.0.1. Let u ∈ T (W 1,2β (Rm+1
+ ;N)) and v ∈ W 1,2β (Rm+1
+ ;N) be a
201
minimal harmonic map with Tv = u. Then for φ ∈ C∞0 (O;Rn),
Iβ(πN(u+ tφ)) ≤ Iβ(u)− t∂βm+1v(φ) + o(|t|) (6.0.14)
for t→ 0.
Proof. Let ut = πN(u + tφ) and vt = πN(v + tψ) for sufficiently small t and
some ψ ∈ D+(Rm+1+ ;Rn) with ψ(x′, 0) = φ(x′). We have Tvt = ut. Thus
Iβ(ut) ≤ Eβ(vt) and, by assumption, Iβ(u) = Eβ(v). Our calculation of the
Euler-Lagrange equations for Eβ in Section 3.1.1 shows that
∂
∂t
∣∣∣∣t=0
Eβ(vt) = −∂βm+1v(φ).
We combine this fact with the definition of the derivative to see that
Iβ(πN(u+ tφ)) ≤ Eβ(vt)
= Eβ(v)− t∂βm+1v(φ) + o(|t|)
= Iβ(u)− t∂βm+1v(φ) + o(|t|)
as required.
Remark 6.0.0.1. Suppose the derivative ∂∂t
∣∣t=0
Iβ(πN(u+ tφ)) exists. When t > 0
the preceding proposition implies that
limt→0+
Iβ(πN(u+ tφ))− Iβ(u)
t≤ −∂βm+1v(φ).
If t < 0 then
limt→0−
Iβ(πN(u+ tφ))− Iβ(u)
t≥ −∂βm+1v(φ).
Hence, whenever ∂∂t
∣∣t=0
Iβ(πN(u+ tφ)) exists we have
∂
∂t
∣∣∣∣t=0
Iβ(πN(u+ tφ)) = −∂βm+1v(φ)
for any minimal harmonic map v with Tv = u.
The above considerations suggest that we may now be able to calculate the
Euler-Lagrange equation for Iβ. To this end we make the following definition.
Definition 6.0.0.3. Let β ∈ (−1, 1). Define Dβ as the collection of all u ∈T (W 1,2
β (Rm+1+ ;N)) such that there exists a distribution λβ ∈ (C∞0 (O;Rn))∗ with
202
λβ = −∂βm+1v for every minimal harmonic map v ∈ W 1,2β (Rm+1
+ ;N) with Tv = u.
Then we may define a map Λβ : Dβ → (C∞0 (O;Rn))∗ : u 7→ λβ = Λβu.
The map Λβ is a Dirichlet to Neumann map for the harmonic map problem:
fix u ∈ T (W 1,2β (Rm+1
+ ;N)) and minimise Eβ in W 1,2β (Rm+1
+ ;N) among all maps
with trace u. In other words, it sends the Dirichlet data u to the Neumann data
−∂βm+1v. In [34] Theorem 1.1 Moser showed that for β = 0, this map is actually
the first variation of I0. In an almost identical way, we can prove the following.
Theorem 6.0.0.1. Let u ∈ T (W 1,2β (Rm+1
+ ;N)). If u ∈ Dβ, then
∂
∂t
∣∣∣∣t=0
Iβ(πN(u+ tφ)) = Λβu(φ)
for all φ ∈ C∞0 (O;Rn). If u 6∈ Dβ, then there exists φ ∈ C∞0 (O;Rn) such that the
function t 7→ Iβ(πN(u+ tφ)) is not differentiable at 0.
We give the proof for completeness, as an explanation of ideas involved and
verification that the method of proof in [34] is valid in the context considered
here.
Proof. The fact that t 7→ Iβ(πN(u+ tφ)) is not differentiable at 0 when u 6∈ Dβ is
a consequence of Proposition 6.0.0.1, in particular it follows from remark 6.0.0.1.
This proposition also shows that
Iβ(ut) ≤ Iβ(u) + tΛβu+ o(|t|) (6.0.15)
where ut = πN(u + tφ) and t is small. To complete the proof of the theorem we
will construct a minimal harmonic map w ∈ W 1,2β (Rm+1
+ ;N) which we will use to
show the reverse inequality to (6.0.14) in Proposition 6.0.0.1 is satisfied; that is
Iβ(ut) ≥ Iβ(u) + tΛβu+ o(|t|). (6.0.16)
It then follows from (6.0.15) that (6.0.16)
tΛβu+ o(|t|) ≤ Iβ(ut)− Iβ(u) ≤ tΛβu+ o(|t|)
which shows that ∂∂t
∣∣0Iβ(ut) = Λβu.
Let u ∈ Dβ, then for every minimal harmonic map v ∈ W 1,2β (Rm+1
+ ;N) with
Tv = u we have Λβu = −∂βm+1v. Fix such a v and consider the variations of
u and v, respectively given by ut = πN(u + tφ) and vt = πN(v + tψ) for some
203
ψ ∈ D+(Rm+1+ ;Rn) and φ ∈ C∞0 (O;Rn) with ψ(x′, 0) = φ(x′). We may assume
t ∈ [−1, 1] since we are only interested in the variations vt and ut for t near
0. Let wt be a minimal harmonic map with Twt = Tvt = ut, which exists in
view of Lemma 6.0.0.1. We have Twt = ut, Iβ(ut) = Eβ(wt) ≤ Eβ(vt) and
Iβ(u) = Eβ(v). Bearing these facts in mind, our goal is now to show that as
t→ 0, wt converges (in an appropriate sense) to a minimal harmonic map w with
Tw = u and which we can use to show (6.0.16) holds.
To further motivate this aim and outline the strategy for the proof, we observe
the following. For small t, the variations ut = πN(u + tφ) and u−t = πN(u− tφ)
are approximately inverse to each other; that is, πN(ut − tφ) and πN(u−t + tφ)
are approximately equal to u (they are equal to u when t = 0). We also have
Twt = ut and TπN(wt − tψ) = TπN(ut − tψ). If wt was both minimal harmonic
and of the form wt = πN(w + tψ) for a minimal harmonic map w with Tw = u,
then by the definition of the derivative, using the same method as in the proof
of Proposition 6.0.0.1, we would have
Iβ(ut) = Eβ(wt) = Eβ(w)− t∂βm+1w + o(|t|) = Iβ(u) + tΛβu+ o(|t|)
as required. Unfortunately, wt need not have this form. However, as we intend
to show that wt converges to a minimal harmonic map w with Tw = u, we still
expect πN(wt − tφ) to approximate such a w. By considering the error in the
aforementioned approximation, we will show that (6.0.16) holds.
We examine the map y 7→ πN(y + η), where y ∈ N and η ∈ Rn is fixed
with |η| sufficiently small (depending on N) so that the map is well defined, in
more detail. As suggested above, for such η, the inverse in the y variable is
approximately y 7→ πN(y− η); the following facts about this approximation have
been proven already in [34] section 2. Define the map
Ξη : N → N : y → πN(πN(y + η)− η).
For sufficiently small η the inverse, with respect to y, exists and we write
Θη = Ξ−1η .
Furthermore, as stated in [34] section 2, there exists a constant C = C(N) such
that
|Ξη(y)− y| ≤ C|η|2 and |DηΞη(y)| ≤ C|η| (6.0.17)
204
and
|Θη(y)− y| ≤ C|η|2 and |DηΘη(y)| ≤ C|η|. (6.0.18)
and, for a tangent vector Y ∈ TyN ,
|DyΞη(y)Y − Y | ≤ C|η|2|Y | and |DyΘη(y)Y − Y | ≤ C|η|2|Y |. (6.0.19)
Now we proceed with our calculations. First we show that the family of maps
wtt∈[−1,1] is bounded, independently of t, in W 1,2β (Rm+1
+ ;N). As a consequence
of the Mean Value Theorem, we have
Eβ(vt) ≤ Eβ(v) + |t|∣∣∣∣ ∂∂t∣∣∣∣t=τ
Eβ(vt)
∣∣∣∣ (6.0.20)
for some τ ∈ (−t, t). Furthermore, it follows from (3.1.2) in Section 3.1.1 that∣∣∣∣ ∂∂t(xβm+1|∇vt|2)
∣∣∣∣≤ 2xβm+1
∣∣∣∣∣m+1∑i=1
⟨dπN(v + tψ)
(∂v
∂xi+ t
∂ψ
∂xi
),HessπN(v + tψ)
(∂v
∂xi+ t
∂ψ
∂xi, ψ
)⟩∣∣∣∣∣+ 2xβm+1
∣∣∣∣∣m+1∑i=1
⟨dπN(v + tψ)
(∂v
∂xi+ t
∂ψ
∂xi
), dπN(v + tψ)
(∂ψ
∂xi
)⟩∣∣∣∣∣≤ Cxβm+1 |∇v + t∇ψ|2 |ψ|L∞(Rm+1
+ ;Rn) + Cxβm+1 |∇v + t∇ψ| |∇ψ|. (6.0.21)
Henceforth we allow the constants in subsequent inequalities to depend on posi-
tive powers of |ψ|L∞(Rm+1+ ;Rn). We combine (6.0.21) with an application of Young’s
inequality to see that∣∣∣∣ ∂∂t(xβm+1|∇vt|2)
∣∣∣∣ ≤ Cxβm+1
(|∇v + t∇ψ|2 + |∇ψ|2
)≤ Cxβm+1(|∇v|2 + |∇ψ|2).
(6.0.22)
We now allow C to depend on Eβ(ψ) as well. Then together, (6.0.20) and (6.0.22)
imply
Eβ(wt) ≤ Eβ(vt) ≤ Eβ(v) + |t|C(Eβ(v) + 1) = Iβ(u) + |t|C(Iβ(u) + 1),
(6.0.23)
which shows that wtt∈[−1,1] is bounded, independently of t, in W 1,2β (Rm+1
+ ;N).
205
Now we consider the energy of wt = πN(wt − tψ). We will bound |∇wt|2
above in terms of the gradient of wt and terms which, upon integration, constitute
∂βm+1wt. Furthermore, we will use the maps Ξη and Θη and the corresponding
estimates above to construct a family of maps wtt∈[−1,1], all with trace equal to
u, such that the difference between the energy of wt and wt is o(|t|). Define
ut = πN(ut − tφ) = Ξtφ(u)
and notice that Twt = ut. Then Θtφ(ut) = u and the maps
wt = Θtψ(wt)
all satisfy
Twt = ΘT (tψ)(Twt) = Θtφ(ut) = Θtφ Ξtφ(u) = u.
We proceed to calculate the gradients and bound the energies of wt and wt. In
what follows we use D to denote differentiation in Rn. Lemma 3.1 of [33] states
that DπN(wt) is the orthogonal projection onto TwtN since wt ∈ N . Hence we
calculate
∇wt = DπN(wt − tψ)(∇wt − t∇ψ)
= ∇wt + (DπN(wt − tψ)−DπN(wt))∇wt − tDπN(wt − tψ)∇ψ. (6.0.24)
We add and subtract tD2πN(wt)(∇wt, ψ) and tDπN(wt)∇ψ from (6.0.24) and
observe that
|∇wt|2 = |∇wt|2 − 2t〈∇wt, D2πN(wt)(∇wt, ψ)〉 − 2t〈∇wt, DπN(wt)∇ψ〉
− 2t〈∇wt, (DπN(wt − tψ)−DπN(wt))∇ψ〉
+ 2〈∇wt, (DπN(wt − tψ)−DπN(wt))∇wt + tD2πN(wt)(∇wt, ψ)〉
+ |(DπN(wt − tψ)−DπN(wt))∇wt − tDπN(wt − tφ)∇ψ|2. (6.0.25)
We now expand this expression into |∇wt|2 plus terms constituting the integrand
of ∂βm+1wt and a remainder of o(|t|). For almost every x ∈ Rm+1+ , the second
fundamental form A(wt) ∈ (TwtN)⊥ and ∂wt∂xi∈ TwtN , where i = 1, . . . ,m + 1.
Hence we deduce from lemma 3.2 in [33] that
〈∇wt, D2πN(wt)(∇wt, ψ)〉 = −〈A(wt)(∇wt,∇wt), ψ〉. (6.0.26)
206
Similarly, as ∂wt∂xi∈ TwtN , where i = 1, . . . ,m+ 1, and DπN(wt) is the projection
onto TwtN , we have
〈∇wt, DπN(wt)∇ψ〉 = 〈∇wt,∇ψ〉. (6.0.27)
Added together, (6.0.26) and (6.0.27) comprise the integrand of ∂βm+1wt.
The Mean Value Theorem guarantees that
|(DπN(wt − tψ)−DπN(wt))∇ψ| ≤ C|t||∇ψ| (6.0.28)
and
|(DπN(wt − tψ)−DπN(wt))∇wt| ≤ C|t||∇wt|. (6.0.29)
It also follows from two applications of the Mean Value Theorem and the bound-
edness of the derivatives of πN , that there is a constant C such that
|(DπN(wt − tψ)−DπN(wt))∇wt + tD2πN(wt)(∇wt, ψ)| ≤ Ct2|∇wt|. (6.0.30)
We combine (6.0.26), (6.0.27), (6.0.28), (6.0.29) and (6.0.30) with (6.0.25) to
see that
|∇wt|2 ≤ |∇wt|2 + 2t〈A(wt)(∇wt,∇wt), ψ〉 − 2t〈∇wt,∇ψ〉
+ Ct2(|∇wt|2 + |∇ψ|2).
Multiplying by xβm+1 and integrating over Rm+1+ gives
Eβ(wt) ≤ Eβ(wt) + t∂βm+1wt(φ) + Ct2(Eβ(wt) + 1)
= Iβ(ut) + t∂βm+1wt(φ) + Ct2(Iβ(ut) + 1). (6.0.31)
To permit the comparison of the energy of wt and wt we calculate
∇wt = DyΘtψ(wt)∇wt + tDηΘtψ(wt)∇ψ.
Applying (6.0.18) and (6.0.19) we see that
|∇wt −∇wt| = |DyΘtψ(wt)∇wt −∇wt + tDηΘtψ(wt(x))∇ψ|
≤ |DyΘtψ(wt)∇wt −∇wt|+ |t||DηΘtψ(wt)∇ψ|
= Ct2(|∇wt|+ |∇ψ|). (6.0.32)
207
Observe that
Eβ(wt) = Eβ(wt) + 2
∫Rm+1
+
xβm+1 〈∇wt −∇wt,∇wt〉 dx+ Eβ(wt − wt).
An application of Young’s inequality combined with (6.0.32) gives∫Rm+1
+
xβm+1 〈∇wt −∇wt,∇wt〉 dx ≤∫Rm+1
+
xβm+1 |∇wt −∇wt| |∇wt| dx
≤ Ct2∫Rm+1
+
xβm+1 |∇wt|2 + |∇wt| |∇ψ| dx
≤ Ct2(Eβ(wt) + 1). (6.0.33)
In a similar way we deduce that
Eβ(wt − wt) ≤ Ct2(Eβ(wt) + 1). (6.0.34)
Hence, in view of (6.0.33) and (6.0.34), we have
Eβ(wt) ≤ Eβ(wt) + Ct2(Eβ(wt) + 1). (6.0.35)
Combining (6.0.31) and (6.0.35) we see that
Iβ(u) ≤ Eβ(wt) ≤ Iβ(ut) + t∂βm+1wt(φ) + t2C(Iβ(ut) + 1).
We combine this fact with the observation Eβ(wt) = Iβ(ut) and (6.0.23) to see
that
Iβ(u) ≤ Iβ(ut) + t∂βm+1wt(φ) + Ct2(Iβ(u) + 1)
≤ Iβ(ut) + t∂βm+1wt(φ) + o(|t|). (6.0.36)
If we can replace t∂βm+1wt(φ) with −Λβu(φ) in (6.0.36), whilst only changing
the inequality by terms of the form o(|t|), then we have proved (6.0.16). Choose a
sequence (tk)k∈N with tk → 0 as k →∞. Then (wtk)k∈N is a bounded sequence in
W 1,2β (Rm+1
+ ;N) in view of (6.0.23) and so we may extract a subsequence (tkl)l∈N
such that wtkl w ∈ W 1,2β (Rm+1
+ ;N) weakly. The continuity of the trace operator
implies Tw = u. However, v is a minimal harmonic map and so in view of (6.0.23),
lim supl→∞
Eβ(wtkl ) ≤ Eβ(v) ≤ Eβ(w).
208
Thus wtkl → w stongly in W 1,2β (Rm+1
+ ;N) and so w is also a minimal harmonic
map with Tw = u. Moreover, ∂βm+1w is well defined and
∂βm+1w(φ) = liml→∞
∂βm+1wtkl (φ).
Since u ∈ Dβ we have ∂βm+1w(φ) = −Λβu(φ) which means that the preceding
limit does not depend on the choice of subsequence (tkl)l∈N. Hence
Λβu(φ) = − limt→0
∂βm+1wt(φ).
It follows from (6.0.36) that as t→ 0 we have
Iβ(u) + tΛβu+ o(|t|) ≤ Iβ(ut)
which is (6.0.16). This concludes the proof.
Corollary 6.0.0.1. Suppose u ∈ T (W 1,2β (Rm+1
+ ;N)) is a critical point of Iβ in
the sense that ∂∂t
∣∣0Iβ(ut) = 0 where ut = πN(u + tφ) for φ ∈ C∞0 (O;Rn). Then
u ∈ Dβ and Λβu = 0.
Now we consider the regularity of 1−β2
-harmonic maps. To this end, we estab-
lish a link between minimisers of Iβ and minimisers of Eβ relative to O.
Lemma 6.0.0.4. Suppose u ∈ T (W 1,2β (Rm+1
+ ;N)) minimises Iβ and fix a minimal
harmonic map v ∈ W 1,2β (Rm+1
+ ;N) with Tv = u. Then v is a minimiser of Eβ
relative to O.
Proof. Let K ⊂ Rm+1 be compact such that K ∩ ∂Rm+1+ ⊂ O and suppose
that w ∈ W 1,2β (Rm+1
+ ;N) satisfies v|Rm+1+ \K = w|Rm+1
+ \K . We need to show that
Eβ(v) ≤ Eβ(w). Define u = Tw and let v be a minimal harmonic map with
T v = u, the existence of which follows from Lemma 6.0.0.1. We will show that
for some compact set K ⊂ O, we have u|O\K = u|O\K . Then, since v and v are
minimal harmonic maps and u minimises Iβ in the sense of definition 6.0.0.1, we
have
Eβ(v) = Iβ(u) ≤ Iβ(u) = Eβ(v) ≤ Eβ(w) (6.0.37)
as required. Thus we proceed to prove the assertion u|O\K = u|O\K .
By assumption O is open in ∂Rm+1+ and Km := K∩∂Rm+1
+ ⊂ O. Furthermore,
Km ⊂ O is compact. Hence distm(Km; ∂O) > 0 where distm is the distance in
Rm × 0. Consequently we can choose an open set O ⊂ O with Km ⊂ O ⊂O ⊂ O. Since Km is closed and O is open we have distm(Km; ∂O) > 0 as well.
209
Hence, since Km ⊂ O by assumption, we have dist(O\O;K) := κ > 0 where dist
is the distance in Rm+1+ . Observe that, on O\O, T coincides with T I2 I1 where
I1 : W 1,2β (Rm+1
+ ;Rn)→ W 1,2β (O\O× (0, κ);Rn) is the imbedding given by Lemma
2.2.1.1, I2 : W 1,2β (O\O × (0, κ);Rn) → W 1,p(O\O × (0, κ);Rn) is the imbedding
given by either Lemma 2.2.1.3 or Lemma 2.2.1.4, for p depending on β, and T is
the trace operator T : W 1,p(O\O × (0, κ);Rn)→ Lp(O\O;Rn). It follows that∫O\O|u− u|pdx =
∫O\O|T (v − w)|pdx ≤ C||v − w||p
W 1,p((O\O)×(0,κ);Rn)= 0
since v = w in O\O × (0, κ). Hence (6.0.37) holds, with K = O and the proof is
complete.
As a consequence of the preceding lemma, we can use the partial regularity
theory, developed in Chapters 3 and 5, for minimisers of Eβ relative to O to
conclude corresponding partial regularity for minimisers of Iβ.
Theorem 6.0.0.2. Suppose u ∈ T (W 1,2β (Rm+1
+ ;N)) minimises Iβ. Then there
exists a γ ∈ (0, 1) and a relatively closed set Σ ⊂ O with Hm+β−1(Σ) = 0 such
that u ∈ C1,γ(O\Σ;N).
Proof. Lemma 6.0.0.1 yields a minimal harmonic map v ∈ W 1,2β (Rm+1
+ ;N) with
Tv = u. As u is a minimiser of Iβ, Lemma 6.0.0.4 implies v is a minimiser of Eβ
relative to O. Thus we may apply Theorem 5.6.0.1 to conclude the result.
210
Chapter 7
Further Work
Our main results are a partial regularity theorem for minimisers v of Eβ relative to
O, see Chapter 5 Theorem 5.6.0.1, and a partial regularity theorem for fractional
harmonic maps u, see Chapter 6 Theorem 6.0.0.2. In particular, these theorems
show that v and its derivatives ∂iv, for i = 1, . . . ,m, are in C0,γ and u ∈ C1,γ
away from their respective singular sets. In analogy with the theory of harmonic
maps, we would like to show that fractional harmonic maps are smooth away
from their singular set, or to extend our theory to hold for derivatives Dαu,
where α is a multi-index with αm+1 = 0, of as higher order as possible. This will
require extensions of the theory in Chapter 5. One such modification would be
a substitute for the application of Lemma 3.6.0.3, which itself comes from the
theory of harmonic maps [45], in establishing the L∞ bound for the gradient of a
minimiser. We would also need counterparts to the other lemmata in Chapter 5,
with assumptions which encompass a general structure of the equations satisfied
by the derivatives Dαv when αm+1 = 0.
We have not, so far, considered the regularity of the derivatives of a minimiser
v of Eβ relative to O with respect to xm+1, other than proving a bound for the
gradient of v assuming its energy is sufficiently small. The theory, described in
Chapter 4, for solutions to the linear Neumann type problem (2.4.5) suggests
that it may be prudent to consider the quantity xβm+1∂m+1v as well as ∂m+1v.
Moreover, information regarding higher order derivatives with respect to xi, for
i = 1, . . . ,m, may yield information about the derivatives with respect to xm+1.
Indeed, if we can, say, establish the boundedness of ∆′v in addition to ∇v then
an analysis of the Euler-Lagrange equations for v together with the modified
lemma of Morrey, Lemma 3.5.0.2, may yield information about the regularity of
xβm+1∂m+1v.
We have seen in Chapter 3, Lemma 3.12.2.1, that the singular set of minimis-
211
ing fractional harmonic maps can be characterised very similarly to the singular
set of harmonic maps. We may consider arguments to reduce the Hausdorff di-
mension of the singular set, analogous to Simon’s refinement of the dimension
reducing arguments of Federer, see [46] Chapter 3. The main difference between
the situation considered in [46] and our own is that the bound for Hausdorff
dimension of the singular set of minimising fractional harmonic maps depends
on the parameter β ∈ (−1, 1) and is non-integer when β 6= 0. There are also
geometric conditions in the theory of harmonic maps which reduce the potential
dimension of the singular set. For instance, if the sectional curvature of N is
non-positive then the singular set is always empty [44]. It would be interesting
to investigate the possibility of such conditions lowering the dimension of the
singular set of fractional harmonic maps.
Sometimes in regularity theories for harmonic maps, see [3] for example, the
domain manifold is replaced (provided the metric is bounded and sufficiently reg-
ular) with Euclidean space and conclusions about regularity are established in
this situation. The arguments are then modified accordingly for more general
domain manifolds. The regularity theory we have developed for minimising frac-
tional harmonic maps holds for open subsets of Euclidean space. It would be
interesting to establish conditions which would allow the definition and analysis
of fractional harmonic maps on more general Riemannian manifolds. For exam-
ple, if (M, g) is a manifold contained in the boundary of another manifold (M, g)
and if, in coordinates centred on p ∈M , we have cg ≤ g ≤ Cg as tensors, where
g is the metric defined by (3.0.1) in Chapter 3, then it may be possible to modify
our theory to define and yield partial regularity for fractional harmonic maps on
M .
A key milestone in proving the Holder continuity of minimisers of Eβ relative
to O was the construction of comparison maps in Section 3.8. The remaining
steps in our theory were not specific to minimising v. It may, therefore, be
possible to consider the regularity of other critical points of Iβ using some of
the theory we have developed, provided we can find substitutes for the use of
comparison maps and a connection with critical points of Eβ. For instance, we
could impose a stationarity condition, similar to the condition defining stationary
harmonic maps, on critical points of Iβ. As in [34], for the case β = 0, we may
then hope that stationary critical points of Iβ are linked with weakly stationary
harmonic maps with respect to the Neumann type boundary condition (3.1.11).
These maps would also be interesting to consider in their own right. It may be
possible to adapt techniques used in the regularity theory for stationary harmonic
212
maps, such as the moving frame method used by Helein [26] and Bethuel [3], to
stationary critical points of Eβ. We may also try to extend Riviere and Struwe’s
approach to the regularity of stationary harmonic maps, investigating possible
gains in regularity due to compensation phenomena [40].
We mentioned in Section 2.2.1 that when m = 2 we do not know if the
embedding W 1,2β (Rm+1
+ ;Rn) → W 1,2β (Ω;Rn), where Ω ⊂ Rm+1
+ is open, holds if
β ∈ (−1,−13]. This prevents us from applying any of the theory for weighted
Sobolev spaces or degenerate elliptic equations to solutions of div(xβm+1∇v) = 0
and, as a result, our theory for Fractional Harmonic Maps does not hold in this
case. It would be interesting to know if this is a consequence of our methodology
or whether there is some other underlying reason that prevents our theory from
holding in this situation.
213
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