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Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 —...

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Complex numbers
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Page 1: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42

Complex numbers

Page 2: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42

Cartesian complex numbers There are several applications of complex numbers in science and engineering, in particular in electrical alternating current theory and in mechanical vector analysis. There are two main forms of complex number –Cartesian form and polar form . If we can add, subtract, multiply and divide complex numbers in both forms and represent the numbers on an Argand diagram then a.c. theory and vector analysis become considerably easier. (i) If the quadratic equation x2 +2x +5 =0 is solved using the quadratic formula then,

Page 3: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42
Page 4: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42
Page 5: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42
Page 6: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42
Page 7: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42
Page 8: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42
Page 9: Complex numbers · 2018. 1. 19. · If and Problem 7. j4, determine in a + Jib form: (c) —2 — j215 = (—2+15) + j (5 +6), since j — 13 +jll 1—j3 1—j3 —3 j212 32 + 42

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