ECE4058 Digital Communication
Digital Communication
Electronics and Communication EngineeringHanyang University
Haewoon Nam
Lecture 13
(ECE4058)
1
ECE4058 Digital Communication
Binary Amplitude Shift Keying
2
• The ON-OFF signaling variety
• The average transmitted signal energy is ( the two binary symbols must by equiprobable)
)9.7(0 symbolbinary for ,01 symbolbinary for ,
)(
= bEtb
)10.7(0 symbolfor ,0
1 symbolfor ),2cos(2)(
= tfTE
ts cb
b π
)11.7(2av
bEE =
ECE4058 Digital Communication
Binary Phase Shift Keying
3
• Binary Phase-Shift Keying (BPSK)– The special case of double-sideband suppressed-carried (DSB-SC)
modulation– The pair of signals used to represent symbols 1 and 0,
– An antipodal signals• A pair of sinusoidal wave, which differ only in a relative phase-shift of π
radians.– The transmitted energy per bit, Eb is constant, equivalently, the average
transmitted power is constant.– Demodulation of BPSK cannot be performed using envelope detection,
rather, we have to look to coherent detection.
)12.7( 2 toingcorrespond 0 symbolfor ),2cos(2)2cos(2
1 toingcorrespond 1 symbolfor ),2cos(2
)(
=−=+
==
itfTEtf
TE
itfTE
tsc
b
bc
b
b
cb
b
i
πππ
π
ECE4058 Digital Communication
Binary Phase Shift Keying
4
Productmodulator
Non-return to zerolevel encoder
Binarydata
stream
BPSKsignal
2 cos 2(a) BPSK modulator
Productmodulator
2 cos 2BPSKsignal
Low-passfilter
Decision-makingdevice
Threshold
Sample attime
Say 1, if the thresholdis exceeded
Say 0, otherwise
(b) Coherent detector for BPSK, for the sampler, integer 0, 1, 2, ⋯
Antipodal signal
0
1
22 22
−=
),cos(
),cos()(
tfTE
tfTE
ts
cb
b
cb
b
i
π
π
Constellation plot
ECE4058 Digital Communication
Quadrature Phase Shift Keying
5
• Quadrature Phase-Shift Keying (QPSK)– Efficient utilization of channel bandwidth– The phase of the sinusoidal carrier takes on one of the four equally
spaced values, such as π/4, 3π/4, 5π/4, and 7π/4
– Each one of the four equally spaced phase values corresponds to a unique pair of bits called dibit
)13.7(elsewhere ,0
0 ,4
)12(2cos2)(
≤≤
−+= Ttitf
TE
ts ci
ππ
)15.7()2sin(4
)12(sin2)2cos(4
)12(cos2)( tfiTEtfi
TEts cci ππππ
−−
−=
)14.7(2 bTT =
ECE4058 Digital Communication
Quadrature Phase Shift Keying
6
• Quadrature Phase-Shift Keying (QPSK)– A QPSK signal consists of the sum of two BPSK signals– The first binary sinusoidal wave with an amplitude equal to ±√E/2
– The second binary wave also has an amplitude equal to ±√E/2
),2cos(4
)12(cos/2 tfiTE cππ
−
)16.7(3 2for 2/4 1for 2/
4)12(cos
=−=
=
−
,iE,iE
iE π
),2sin(4
)12(sin/2 tfiTE cππ
−−
)17.7(4 3for 2/2 1for 2/
4)12(sin
==−
=
−−
,iE,iE
iE π
cosine and sine carriersare orthogonal
ECE4058 Digital Communication
Quadrature Phase Shift Keying
7
ECE4058 Digital Communication
Quadrature Phase Shift Keying
8
• Constellation plot
BPSK
Bit 1Bit 0
2
2
QPSK
1000
01 11
ECE4058 Digital Communication
Quadrature Phase Shift Keying
9
• QPSK transmitter
ECE4058 Digital Communication
Quadrature Phase Shift Keying
10
• QPSK receiver
ECE4058 Digital Communication
M-ary Phase Shift Keying
11
• Constellation plot
8-PSK
111001
110
000 101
011
010
100
16-PSK
01011001
1100
0001
0000
1010
1111
0010
1000
1011
0011
11101101
0100
0111
0110
ECE4058 Digital Communication
M-ary Phase Shift Keying
12
• How to calculate bit error rate (BER) and symbol error rate (SER)?• For BPSK, QPSK, M-ary PSK?• How to draw a BER vs SNR curve?• For other modulations?
ECE4058 Digital Communication
Frequency Shift Keying
13
• Binary Frequency-Shift Keying (BFSK)– Each symbols are distinguished from each other by transmitting one of
two sinusoidal waves that differ in frequency by a fixed amount
– Sunde’s BFSK– When the frequencies f1 and f2 are chosen in such a way that they
differ from each other by an amount equal to the reciprocal of the bit duration Tb
)18.7( 2 toingcorrespond 0 symbolfor ),2cos(2
1 toingcorrespond 1 symbolfor ),2cos(2
)(2
1
=
==
itfTE
itfTE
ts
b
b
b
b
i
π
π
ECE4058 Digital Communication
Frequency Shift Keying
14
ECE4058 Digital Communication
Frequency Shift Keying
15
• Continuous-phase Frequency-Shift Keying– The modulated wave maintains phase continuity at all transition points,
even though at those points in time the incoming binary data stream switches back and forth
– Sunde’s BFSK, the overall excursion δf in the transmitted frequency from symbol 0 to symbol 1, is equal to the bit rate of the incoming data stream.
– MSK (Minimum Shift Keying)• The special form of CPFSK• Uses a different value for the frequency excursion δf , with the result that this
new modulated wave offers superior spectral properties to Sunde’s BFSK.
ECE4058 Digital Communication
Frequency Shift Keying
16
• Noncoherent Detection of BFSK Signals– The receiver consists of two paths
• Path 1 : uses a band-pass filter of mid-band frequency f1. produce the output v1
• Path 2 : uses a band-pass filter of mid-band frequency f2. produce the output v2
– The output of the two paths are applied to a comparator
ECE4058 Digital Communication
Quadrature Amplitude Modulation
17
• M-ary Quadrature Amplitude Modulation (QAM)– The mathematical description of the new modulated signal
– The level parameter for in-phase component and quadrature component are independent of each other for all I
– M-ary QAM is a hybrid form of M-ary modulation– M-ary amplitude-shift keying (M-ary ASK)
• If bi=0 for all i, the modulated signal si(t) of Eq. (7.40) reduces to
– M-ary PSK• If E0=E and the constraint is satisfied
)40.7( 0
1,...,1,0),2sin(2)2cos(2)( 00
TtMi
tfbTEtfa
TEts cicii ≤≤
−=−= ππ
1,...,1,0)2cos(2)( 0 −== MitfaTEts cii π
iEEbEa ii allfor ,)( 2/122 =+
ECE4058 Digital Communication
Quadrature Amplitude Modulation
18
ECE4058 Digital Communication
Mapping of Modulated Symbols
19
• Mapping of digitally modulated waveforms onto constellation of signal points for BPSK– The signal-space representation of BPSK is simple, involving a single
basis function
)44.7()2cos(2)(1 tfT
t cb
πφ =
ECE4058 Digital Communication
Mapping of Modulated Symbols
20
• Mapping of digitally modulated waveforms onto constellation of signal points for BFSK– Two basis function each with different frequency
)52.7()2cos(2)( 11 tfT
tb
πφ = )53.7()2cos(2)( 22 tfT
tb
πφ =