6.002 CIRCUITS ANDELECTRONICS
Incremental Analysis
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Nonlinear AnalysisAnalytical methodGraphical method
TodayIncremental analysis
Reading: Section 4.5
Review
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Method 3: Incremental Analysis Motivation: music over a light beam
Can we pull this off?
LED: Light Emitting expoDweep ☺
Dv+-
)(tvI+–
Di
LEDRi
AMP
light intensity IRin photoreceiver
RR Ii ∝
lightintensity
DD iI ∝
Iv
t
music signal
)(tvI light sound)(tiR)(tiD
nonlinearlinear
problem! will result in distortion
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Problem:The LED is nonlinear distortion
ID vv =Dv
Div
D
t
tDi vD
Di
t
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Insight:
Dv
Di
DI
DV
DC offsetor DC bias
Trick:
dDD iIi +=
IVDv
+-
)(tvi+–
LED+–
Iv
dDD vVv +=
IV iv
small regionlooks linear(about VD , ID)
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Result
vdvery small
Di
Dv
di
DI
DV
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Result
t
DvDV
ID vv =
tDI
Di~linear!
Demo
dv
diDi
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totalvariable
DCoffset
smallsuperimposed
signal
The incremental method:(or small signal method)
1. Operate at some DC offsetor bias point VD, ID .
2. Superimpose small signal vd(music) on top of VD .
3. Response id to small signal vdis approximately linear.
Notation:dDD iIi +=
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( )DD vfi =
What does this meanmathematically?Or, why is the small signal responselinear?
We replacedDDD vVv Δ+=
using Taylor’s Expansion to expandf(vD) near vD=VD :
( ) DVvD
DDD v
dvvdfVfi
DD
Δ⋅+==
)(
+Δ⋅+=
22
2 )(!21
DVvD
D vdv
vfd
DD
large DC
incrementabout VD
nonlinear
dv
neglect higher order termsbecause is smallDvΔ
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( ) DVvD
DDD v
vdvfdVfi
DD
Δ⋅+≈=
)(
equating DC and time-varying parts,
DVvD
DD v
vdvfdi
DD
Δ⋅=Δ=
)(
constantw.r.t. ΔvD
constant w.r.t. ΔvDslope at VD, ID
( )DD VfI = operating point
constant w.r.t. ΔvD
X :
We can write
( ) DVvD
DDDD v
vdvfdVfiI
DD
Δ⋅+≈Δ+=
)(
so, DD vi Δ∝Δ By notation,dD ii =ΔdD vv =Δ
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Equate DC and incremental terms,
DbvD eai =
In our example,
From X : dbVbV
dD vbeaeaiI DD ⋅⋅
constant
+≈+
DbVD eaI =
dbV
d vbeai D ⋅⋅=
operating point
dDd vbIi ⋅⋅= small signalbehaviorlinear!
aka bias pt.aka DC offset
DbVD eaI = operating point
dDd vbIi ⋅⋅=
Dv
Di
DI
DV
slope atVD, ID
operatingpoint
we areapproximatingA with B
A
B
dv
di
Graphical interpretation
We saw the small signal
DI
IVDV
+-
+– LED DbVD eaI =
Large signal circuit:
Small signal reponse: dDd vbIi =
graphicallymathematicallynow, circuit
small signal circuit:
Linear!
di
iv dv+- bID
1+–
behaves like:dv+ -
di
bI1RD
=