Optics Course
(Phys 311)
Wave Optics
The Superposition of Waves (1 of 2)
Lecturer: Dr Zeina Hashim
Phys
311
1. The Principle of Superposition.
2. The Addition of Waves of the Same Frequency Along the Same Direction:
a. algebraic method:
- The resultant wave equation, its new (amplitude, phase, and flux density).
- The Phase difference between two superimposed waves.
- The resultant wave equation in the case where two identical waves are following each
other by π«π .
- The special cases of constructive and destructive interferences.
- The superposition of many waves. b. complex method. c. phasors method.
Objectives covered in this lesson :
Lesson 1 of 2
Slide 1 Wave Optics: The Superposition of Waves
Why study this process? Because it underlies
the three phenomena we will soon study:
Interference Diffraction Polarization
The Principle:
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The Principle of Superposition :
Lesson 1 of 2
Slide 2 Wave Optics: The Superposition of Waves
The resultant disturbance at any point in a medium is
the algebraic sum of the separate constituent waves
π πππππ= π1π1 + π2π2 +β―
How did we know this?
From the 3D differential equation:
All solutions of this equation are linear (i.e. to the first power).
This implies that any linear combination of these solutions is also a solution.
Therefore:
Phys
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The Principle of Superposition :
Lesson 1 of 2
Slide 3 Wave Optics: The Superposition of Waves
Are all EM waves linear ??
No ! We have βnon-linear wavesβ, which we will not study.
They are solutions to non-linear partial differential wave equations.
These waves do not satisfy the Principle of Superposition.
A nonlinear wave is caused by a VERY LARGE force.
An example is: A focused beam of a high-intensity laser (Electric field = 1010 V/cm).
So, our differential equation should be called:
βlinear partial differential wave equationβ
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Lesson 1 of 2
Slide 4 Wave Optics: The Superposition of Waves
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Lesson 1 of 2
Slide 5
Addition of Waves (travelling along the x-axis, with the same π):
Algebraic Method Complex Method Graphical Method (Phasors)
Wave Optics: The Superposition of Waves
Phys
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Lesson 1 of 2
Slide 6
Algebraic Method
πΈ = πΈπ1 sin ππ‘ + πΌ1 + πΈπ1 sin(ππ‘ + πΌ2)
sin π₯ + π¦ = sin π₯ cos π¦ + cos π₯ sin π¦
Let:
Wave Optics: The Superposition of Waves
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Lesson 1 of 2
Slide 7
Algebraic Method
Using: sin π₯ + π¦ = sin π₯ cos π¦ + cos π₯ sin π¦
This is the new wave equation which resulted from the superposition of the two waves.
It: is harmonic
and has: the same frequency as its constituents,
but it has: a new π¬π and a new πΆ.
πΈ = πΈπ sin(ππ‘ + πΌ)
Wave Optics: The Superposition of Waves
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Lesson 1 of 2
Slide 8
What is its new amplitude (π¬π)?
Square each equation, and add them together
πΈπ2 sin2 πΌ = πΈπ1
2 sin2 πΌ1 + πΈπ22 sin2 πΌ2 + 2πΈπ1πΈπ2 sin πΌ1 sin πΌ2
,
πΈπ2 cos2 πΌ = πΈπ1
2 cos2 πΌ1 + πΈπ22 cos2 πΌ2 + 2πΈπ1πΈπ2 cos πΌ1 cos πΌ2
sin2 π + sin2 π = 1
πΈπ2 = πΈπ1
2 + πΈπ22 + 2πΈπ1πΈπ2 (cos πΌ1 cos πΌ2 + sinπΌ1 sin πΌ2)
Algebraic Method
π¬ππ = π¬ππ
π + π¬πππ + ππ¬πππ¬ππ ππ¨π¬(πΆπ β πΆπ) its new amplitude.
Ψ£Ω Ψ§ΩΨΉΩΨ³ Ψ 2ΩΨ§ΩΨ΅ Ψ£ΩΩΨ§ 1ΩΩ ΨͺΩΨ±Ω Ψ₯Ψ°Ψ§ ΨΨ·ΩΩΨ§ Ψ£ΩΩΨ§
The resultantβs amplitude depends on what? πΆπ β πΆπ is called βthe phase difference πΉβ
Wave Optics: The Superposition of Waves
ππ¨π¬(πΆπ β πΆπ)
When the two wave equations are:
In-phase πΉ = π , Β±ππ ,Β±ππ ,β¦
Out-of-phase πΉ = Β±π ,Β±ππ ,β¦
Phys
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Lesson 1 of 2
Slide 9
Homework: Q1:
Show that when the two wave equations
πΈ1 = πΈπ1 sin(ππ‘ + πΌ1) and
πΈ2 = πΈπ2 sin(ππ‘ + πΌ2) are in-phase, the resulting
amplitude squared is a maximum (and equals
(πΈπ1 + πΈπ2)2), and when they are out-of-phase it is
a minimum (and equals (πΈπ1 β πΈπ2)2).
Algebraic Method The Phase Difference:
Wave Optics: The Superposition of Waves
πΉ = πΆπ β πΆπ but
So, πΉ = πππ + πΊπ β πππ + πΊπ
πΉ = π( ππ + πΊπ β ππ + πΊπ )
πΉ =ππ
π ππ β ππ + πΊπ β πΊπ
πΉ =ππ
πππ ππ β ππ + πΊπ β πΊπ
Phys
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Lesson 1 of 2
Slide 10
Distances
from
sources
Initial
phases
π =πππ
If π1 β π2 = ππππ π‘πππ‘ the waves are coherent
Algebraic Method The Phase Difference:
Wave Optics: The Superposition of Waves
If the two waves were initially in phase (example: they came from the same source):
πΊπ = πΊπ πΉ =ππ
ππ π ππ β ππ
πΉ = πππ²
Q: How can two waves from the same source have different distances from the
source?
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Lesson 1 of 2
Slide 11
Optical Path:
β= ππ
d here is x
Optical path
difference (π²)
Algebraic Method The Phase Difference:
Wave Optics: The Superposition of Waves
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Lesson 1 of 2
Slide 12
Algebraic Method Now, what is its new phase (πΆ) ?
Divide the second equation by the first equation:
,
its new phase.
Q: When does πΆ β πΆπ and when does πΆ β πΆπ ?
Wave Optics: The Superposition of Waves
Now⦠if I gave you the amplitudes and phases of two waves, can you write down
the wave equation of their resultant superposition ?
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Lesson 1 of 2
Slide 13
Homework: Q2:
Determine the resultant of the superposition of the parallel waves:
πΈ1 = πΈπ1 sin(ππ‘ + π1) and πΈ2 = πΈπ2 sin(ππ‘ + π2)
when π = 120π , πΈπ1 = 6 , πΈπ2 = 8 , π1 = 0 , and π2 =π
2 .
Algebraic Method
Wave Optics: The Superposition of Waves
What is the flux density of the resultant wave?
The flux density has an extra term.
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Lesson 1 of 2
Slide 14
β΄ πΌ =πππ2(π¬ππ
π + π¬πππ + ππ¬πππ¬ππ ππ¨π¬ πΆπ β πΆπ )
= πππ
2π¬πππ +πππ
2π¬πππ +πππ
2ππ¬πππ¬ππ ππ¨π¬ πΆπ β πΆπ
= πΌ1 + πΌ2 +πππ2ππ¬πππ¬ππ ππ¨π¬ πΆπ β πΆπ
ππ¬πππ¬ππ ππ¨π¬ πΆπ β πΆπ is called: βInterference Termβ
Algebraic Method
Wave Optics: The Superposition of Waves
If we have two waves which have the same frequency & same amplitude & same initial
phase, but one is following the other by
Then,
And the resultant wave equation can be written as:
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Lesson 1 of 2
Slide 15
Algebraic Method
Wave Optics: The Superposition of Waves
The special case of
Constructive Interference Destructive Interference
Phys
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Lesson 1 of 2
Slide 16
Algebraic Method
Wave Optics: The Superposition of Waves
The special case of
Constructive Interference Destructive Interference
Phys
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Lesson 1 of 2
Slide 17
Algebraic Method π¬ππ = π¬ππ
π + π¬πππ + ππ¬πππ¬ππ ππ¨π¬(πΆπ β πΆπ) the new amplitude.
The peaks occur at the same time.
The resultantβs amplitude becomes
(πΈπ = πΈπ1 + πΈπ2). This happens when πΌ1 β πΌ2 = 0 , 2π , β¦
Two waves with the same frequencies,
amplitudes, initial phases, and follow
each other by Ξπ₯ will interfere
constructively if
The peak and trough occur at the same time.
The resultantβs amplitude becomes
(πΈπ = πΈπ1 β πΈπ2). This happens when πΌ1 β πΌ2 = π , 3π , β¦
Two waves with the same frequencies,
amplitudes, initial phases, and follow each
other by Ξπ₯ will interfere destructively if
πΈπ = 2πΈπ1 πΈπ = 0
Wave Optics: The Superposition of Waves
Phys
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Lesson 1 of 2
Slide 18
Algebraic Method
Wave Optics: The Superposition of Waves
The Superposition of Many waves
The superposition of N number of:
a. coherent
b. harmonic waves
c. having a given frequency (i.e. the same π)
d. travelling in the same direction
Its wave equation will be:
with a new amplitude: and a new phase:
Phys
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Lesson 1 of 2
Slide 19
Algebraic Method
Leads to a harmonic wave of
that same frequency.
= πΈππ cos(πΌπ Β± ππ‘)
π
π=1
Wave Optics: The Superposition of Waves
Phys
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Lesson 1 of 2
Slide 20
Addition of Waves (travelling along the x-axis, with the same π):
Algebraic Method Complex Method Graphical Method (Phasors)
Wave Optics: The Superposition of Waves
If we have N waves with the same frequency, travelling in the positive x-direction,
each having a wave equation of:
πΈπ = πΈππππ(πΌ1+ππ‘)
The resultant wave of their superposition will be:
with a new complex amplitude:
and a new phase: Not given here
Phys
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Lesson 1 of 2
Slide 21
Complex Method
πΈ = πΈπππ(Ξ±+ππ‘)
πΈπ2πππΌ = πΈπππ
ππΌπ
π
π=1
Wave Optics: The Superposition of Waves
Phys
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Lesson 1 of 2
Slide 22
Addition of Waves (travelling along the x-axis, with the same π):
Algebraic Method Complex Method Graphical Method (Phasors)
Wave Optics: The Superposition of Waves
Phys
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Lesson 1 of 2
Slide 23
Link to: Phasors and waves Graphical Method (Phasors)
Wave Optics: The Superposition of Waves
It is a graphical method to obtain the new amplitude and new phase.
It is useful when we have more than two waves which we need to combine.
Each wave is described by a vector: its length = amplitude of wave.
its direction from the positive x-axis = its πΆ.
Steps: a. Draw each vector.
b. Shift them so that they are head-to-tail, head-to tail.
c. Draw the resultant wave vector (from tail of first wave to head of last wave.
d. Resultant vector length = its amplitude. Its angle from + x-direction = its phase.
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Lesson 1 of 2
Slide 24
Graphical Method (Phasors)
Phasors can be represented by:
Wave Optics: The Superposition of Waves
Example:
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Lesson 1 of 2
Slide 25
Graphical Method (Phasors)
Wave Optics: The Superposition of Waves
The resultant wave leads or lags the constituent waves ?
wave 1 leads wave 2 means: peak of 1 occurs at an earlier location than peak of 2.
wave 1 lags wave 2 means: peak of 1 occurs at a later location than peak of 2.
If it leads its phase is positive
(counter-clockwise from x-axis)
If it lags its phase is negative (clockwise)
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Lesson 1 of 2
Slide 26
Graphical Method (Phasors)
Wave Optics: The Superposition of Waves
Q3:
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Lesson 1 of 2
Slide 27
Homework :
Wave Optics: The Superposition of Waves
Q4:
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Lesson 1 of 2
Slide 28
Homework :
Wave Optics: The Superposition of Waves
1. The Principle of Superposition.
2. The Addition of Waves of the Same Frequency Along the Same Direction:
a. algebraic method:
- The resultant wave equation, its new (amplitude, phase, and flux density).
- The Phase Difference between two superimposed waves.
- The resultant wave equation in the case where two identical waves are following each other
by ππ .
- The special cases of constructive and destructive interferences.
- The superposition of many waves. b. complex method. c. phasors method.
Phys
311
Lesson 1 of 2
Slide 29 (last)
Summary: Any Questions? Next lesson will cover:
Superposition of waves (2)
Wave Optics: The Superposition of Waves