Full Name: Sample Final April 13, 2016 (1:30 – 4:30 pm) Examination: Basic Physics International College of Manitoba Student ID: PHY100 Examination time: 3 h Examiner: Dr. J. B. Bland ANSWER SHEET: Fill in the corresponding circle with pencil only. Only one re- sponse per question is permitted. Question a b c d e 1 O O O O O 2 O O O O O 3 O O O O O 4 O O O O O 5 O O O O O 6 O O O O O 7 O O O O O 8 O O O O O 9 O O O O O 10 O O O O O 11 O O O O O 12 O O O O O 13 O O O O O 14 O O O O O 15 O O O O O 16 O O O O O 17 O O O O O 18 O O O O O 19 O O O O O 20 O O O O O 21 O O O O O 22 O O O O O 23 O O O O O 24 O O O O O 25 O O O O O
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by shading in the circle that corresponds to your response. Select the answer that
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be counted.
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7. The questions total 25 marks, and the exam will count for 45% of your final grade
in this course.
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PHY100 BASIC PHYSICS SAMPLE FINAL WINTER 201601
Name___________________________________
ICMID___________________________________
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Indicateyour choice by shading the corresponding bubble on the answer sheet.
1) If an operatic aria lasts for 5.75 min, its length expressed in seconds is x s, where x is 1)A) less than 5.75. B) greater than 5.75.
2) What is the result of 1.58 ÷ 3.793 written with the correct number of significant figures? 2)A) 4.17 × 10-1
B) 4.1656 × 10-1
C) 4.166 × 10-1
D) 4.2 × 10-1
E) 4 × 10-1
3) If the acceleration of an object is negative, the object must be slowing down. 3)A) True B) False
4) If the graph of the position as a function of time for an object is a horizontal line, that object cannotbe accelerating.
4)
A) True B) False
5) Jacques and George meet in the middle of a lake while paddling in their canoes. They come to acomplete stop and talk for a while. When they are ready to leave, Jacques pushes George's canoe
with a force F to separate the two canoes. What is correct to say about the final momentum andkinetic energy of the system if we can neglect any resistance due to the water?
5)
A) The final momentum is in the direction opposite of F but the final kinetic energy is zero.
B) The final momentum is in the direction of F but the final kinetic energy is zero.C) The final momentum is zero and the final kinetic energy is zero.
D) The final momentum is in the direction of F and the final kinetic energy is positive.E) The final momentum is zero but the final kinetic energy is positive.
6) A 620-g object traveling at 2.1 m/s collides head-on with a 320-g object traveling in the oppositedirection at 3.8 m/s. If the collision is perfectly elastic, what is the change in the kinetic energy of the620-g object?
6)
A) It loses 1.4 J.B) It gains 0.69 J.C) It loses 0.47 J.D) It loses 0.23 J.E) It doesn't lose any kinetic energy because the collision is elastic.
1
7) A plane flies directly between two cities, A and B, which are separated by 2300 mi. From A to B, theplane flies into a 65 mi/h headwind. On the return trip from B to A, the wind velocity is unchanged.The trip from B to A takes 65 min less than the trip from A to B. What is the airspeed of the plane,assuming it is the same in both directions?
7)
A) 610 mi/h B) 480 mi/h C) 400 mi/h D) 530 mi/h
8) On a smooth horizontal floor, an object slides into a spring which is attached to another mass that isinitially stationary. When the spring is most compressed, both objects are moving at the samespeed. Ignoring friction, what is conserved during this interaction?
8)
A) kinetic energy onlyB) momentum and kinetic energyC) momentum onlyD) momentum and potential energyE) momentum and mechanical energy
9) A 2.0-kg object is moving without friction along the x-axis. The potential energy curve as afunction of position is shown in the figure, and the system is conservative. If the speed of the objectat the origin is 4.0 m/s, what will be its speed at 7.0 m along the +x-axis?
9)
A) 4.4 m/s B) 9.8 m/s C) 4.2 m/s D) 4.0 m/s E) 4.6 m/s
2
10) Point P in the figure indicates the position of an object traveling at constant speed clockwise aroundthe circle. Which arrow best represent the direction the object would travel if the net external forceon it were suddenly reduced to zero?
10)
A)
B)
C)D)
E)
11) A car is being towed at constant velocity on a horizontal road using a horizontal chain. The tensionin the chain must be equal to the weight of the car in order to maintain constant velocity.
11)
A) True B) False
12) A box slides down a frictionless plane inclined at an angle above the horizontal. The gravitationalforce on the box is directed
12)
A) parallel to the plane in the same direction as the movement of the box.B) vertically.C) perpendicular to the plane.D) parallel to the plane in the opposite direction as the movement of the box.E) at an angle below the inclined plane.
13) A 7.0-kg object is acted on by two forces. One of the forces is 10.0 N acting toward the east. Whichof the following forces is the other force if the acceleration of the object is 1.0 m/s2 toward the east?
13)
A) 9.0 N west B) 3.0 N west C) 12 N east D) 6.0 N east E) 7.0 N west
3
14) The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it0.90 s to reach the floor. What is the mass m of the other block? The pulley has no appreciable massor friction.
14)
A) 60 kg B) 54 kg C) 42 kg D) 48 kg
15) A stock person at the local grocery store has a job consisting of the following five segments:(1) picking up boxes of tomatoes from the stockroom floor(2) accelerating to a comfortable speed(3) carrying the boxes to the tomato display at constant speed(4) decelerating to a stop(5) lowering the boxes slowly to the floor.
During which of the five segments of the job does the stock person do positive work on the boxes?
15)
A) (1) onlyB) (1) and (2)C) (1), (2), (4), and (5)D) (2) and (3)E) (1) and (5)
4
16) A box of mass m is pressed against (but is not attached to) an ideal spring of force constant k andnegligible mass, compressing the spring a distance x. After it is released, the box slides up africtionless incline as shown in the figure and eventually stops. If we repeat this experiment with abox of mass 2m
16)
A) both boxes will have the same speed just as they move free of the spring.B) just as it moves free of the spring, the heavier box will have twice as much kinetic energy as
the lighter box.C) both boxes will reach the same maximum height on the incline.D) the lighter box will go twice as high up the incline as the heavier box.E) just as it moves free of the spring, the lighter box will be moving twice as fast as the heavier
box.
17) A graph of the force on an object as a function of its position is shown in the figure. Determine theamount of work done by this force on the object during a displacement from x = -2.00 m to x = 2.00m. (Assume an accuracy of 3 significant figures for the numbers on the graph.)
17)
A) -12.0 J B) 3.00 J C) -3.00 J D) -1.00 J E) 12.0 J
18) A car needs to generate 75.0 hp in order to maintain a constant velocity of 27.3 m/s on a flat road.What is the magnitude of the total resistive force acting on the car (due to friction, air resistance,etc.)? (1 hp = 746 W)
18)
A) 2.87 × 103 N B) 2.05 × 103 N C) 1.03 × 103 N D) 2.75 N
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19) Shown below are the velocity and acceleration vectors for a person in several different types ofmotion. In which case is the person slowing down and turning to his right?
19)
A)
B)
C)
D)
E)
20)^ ^ ^
What is the angle between the vector A = +3i - 2j - 3k and the +y-axis? 20)A) 115° B) 155° C) 65° D) 90° E) 25°
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21) A 4.00-kg block rests between the floor and a 3.00-kg block as shown in the figure. The 3.00-kgblock is tied to a wall by a horizontal rope. If the coefficient of static friction is 0.800 between eachpair of surfaces in contact, what horizontal force F must be applied to the 4.00-kg block to make itmove?
21)
A) 21.1 N B) 54.9 N C) 23.5 N D) 16.2 N E) 78.4 N
22) A string is attached to the rear-view mirror of a car. A ball is hanging from the other end of thestring. The car is driving around in a circle, at a constant speed. Which of the following lists givesall of the forces directly acting on the ball?
22)
A) tension, gravity, the centripetal force, and frictionB) tensionC) tension, gravity, and the centripetal forceD) tension and gravity
23) A wheel rotates through an angle of 13.8 rad as it slows down uniformly from 22.0 rad/s to 13.5rad/s. What is the magnitude of the angular acceleration of the wheel?
23)
A) 10.9 rad/s2
B) 22.5 rad/s2
C) 5.45 rad/s2
D) 0.616 rad/s2
E) 111 rad/s2
24) As you are leaving a building, the door opens outward. If the hinges on the door are on your right,according to the right hand rule, what is the direction of the angular velocity of the door as youopen it?
24)
A) to your leftB) forwardsC) downD) upE) to your right
25) A solid, uniform sphere of mass 2.0 kg and radius 1.7 m rolls from rest without slipping down aninclined plane of height 7.0 m. What is the angular velocity of the sphere at the bottom of theinclined plane? (I = (2/5) MR2)
25)
A) 11 rad/s B) 5.8 rad/s C) 9.9 rad/s D) 7.0 rad/s
7
Formula SheetsApril 13, 2016 (1:30 – 4:30 pm)Final Examination
International College of Manitoba PHY100 Basic PhysicsExamination Time: 3 h
Examiner: Dr. J. B. Bland
Chapter 1 Foundations
n ≡ N
V
ρ ≡ m
V
Chapter 2 Motion in One Dimension
~b = bxi
d = |x1 − x2|
vx,av ≡∆x
∆t=xf − xi
tf − ti~r = xi
∆~r = ~rf − ~ri = (xf − xi) i
~vav =∆~r
∆t=
(xf − xi
tf − ti
)i
vx ≡dx
dt
vx = lim∆t→ 0
∆x
∆t
Chapter 3 Acceleration
ax,av ≡∆vx∆t
=vx,f − vx,itf − ti
ax ≡dvxdt
=d2x
dt2
ax = lim∆t→ 0
∆vx∆t
∆vx =
∫ tf
ti
ax(t)dt
∆vx = area under ax(t) vs t curve
∆x =
∫ tf
ti
vx(t)dt
∆x = area under vx(t) vs t curve
x(t) = xi + vx,it+1
2axt
2
vx(t) = vx,i + axt
vx(t)2 = v2
x,i + 2ax∆x
ax = g sin θ
Chapter 4 Momentum
mu
ms
≡ −∆vsx
∆vux
~p ≡ m~v
~p ≡ ~p1 + ~p1 + · · ·
∆~p = 0 (Isolated system)
~pf = ~pi (Isolated system)
J = ∆~p
Chapter 5 Energy
K =1
2mv2
1 J = 1 kg ·m2/s2
~v12 ≡ ~v2 − ~v1
v12 = |~v2 − ~v1|
px,i = px,f
e =v12f
v12i
= −v2x,f − v1x,f
v2x,i − v1x,i
E = K + Eint (Closed system)
Ef = Ei (Closed system)
Chapter 6 Principle of Relativity
~rcm ≡m1~r1 +m2~r2 + · · ·m1 +m2 + · · ·
~vcm ≡d~rcm
dt= lim
∆t→ 0
∆~rcm
∆t=m1~v1 +m2~v2 + · · ·m1 +m2 + · · ·
~rBe = ~rAe − ~vABte
1
Formula SheetsApril 13, 2016 (1:30 – 4:30 pm)Final Examination
International College of Manitoba PHY100 Basic PhysicsExamination Time: 3 h
Examiner: Dr. J. B. Bland
~vAo = ~vAB + ~vBo
Kcm ≡1
2mv2
cm
Kconv =1
2µv2
12
µ ≡ m1m2
m1 +m2
K = Kcm +Kconv
∆~pA sys = ∆~pB sys
∆KB + ∆EB int = ∆KA + ∆EA int
Chapter 7 Interactions
a1x
a2x
= −m2
m1
U = U(x)
∆UG = mg∆x
Emech = K + U
∆K + ∆U + ∆Es + ∆Eth = 0
∆Emech = ∆K + ∆U = 0
Chapter 8 Force
1 N = 1 kg ·m/s2
~F12 = −~F21
FGEo x = −mg
(Fby spring on load)x = −k (x− x0)
~a =
∑ ~F
m∑
~F = m~a
∑~F ≡ d~p
dt= lim
∆t→ 0
∆~p
∆t
∆~p = ~J =(∑
~F)
∆t
∆~p = ~J =
∫ tf
ti
∑~F (t)dt
∆~p = ~J = area under∑
~F (t) vs t curve
~acm =
∑ ~Fext
m
Chapter 9 Work
W =(∑
Fx
)∆xF
W =∑
n
(Fext nx∆xFn)
∆E = W
∆E = ∆K
∆Kcm =(∑
Fext x
)∆xcm
W =
∫ xf
xi
Fx(x)dx
W = area under∑
Fx(x) vs x curve
∆Uspring =1
2k (x− x0)2
∆Eth = F fsbdpath
P =dE
dt= lim
∆t→ 0
∆E
∆t
P = Fextxvx
Chapter 10 Motion in a Plane
A ≡∣∣∣ ~A∣∣∣ = +
√A2x + A2
y
tan θ =AyAx
Rx = Ax +Bx
Ry = Ay +By
~A · ~B ≡ AB cosφ
~r = xi+ yj
2
Formula SheetsApril 13, 2016 (1:30 – 4:30 pm)Final Examination
International College of Manitoba PHY100 Basic PhysicsExamination Time: 3 h
Examiner: Dr. J. B. Bland
ax = 0
ay = −g
vx,f = vx,i
vy,f = vy,i − g∆t
xf = xi + vx,i∆t
yf = yi + vy,i∆t−1
2g (∆t)2
∆px = ∆p1x + ∆p2x = 0
∆px = m1(v1x,f − v1x,i) +m2(v2x,f − v2x,i)
∆py = ∆p1y + ∆p2y = 0
∆py = m1(v1y,f − v1y,i) +m2(v2y,f − v2y,i)
(F s12)max = µsF
n12
F s12 ≤ µsF
n12
W = ~F ·∆~rF
W =
∫ ~rf
~ri
~F (~r) · d~r
W = area under ~F (~r) · r vs r curve
∆Eth = −∫ ~rf
~ri
~F (~rcm) · d~rcm
∆Eth = area under ~F (~rcm) · rcm vs rcm curve
W = mgh
Chapter 11 Motion in a Circle
θ ≡ s
r
ωθ =dθ
dt
ωθ = lim∆t→ 0
∆θ
∆t
αθ =dω
dt=d2θ
dt2
αθ = lim∆t→ 0
∆ω
∆t
vt = rωθ
vr = 0
ar = −v2
r
ar = −rω2
at = rαθ
a = +√a2r + a2
t
θf = θi + ωθ,i∆t+1
2αθ (∆t)2
ωθ,f = ωθ,i + αθ∆t
I = mr2
I =
∫r2dm
I = area under r2 vs m curve
I = Icm +md2
Krot =1
2Iω2
Lθ = Iωθ
L = r⊥mv
Chapter 12 Torque
τ ≡ rF sin θ = r⊥F = rF⊥
∑τextθ = Iαθ
vcmx = Rωθ
acmx = Rαθ∑
Fextx = macmx
∑τextθ = Iαθ
∆Krot =(∑
τextθ
)∆θ
3
Formula SheetsApril 13, 2016 (1:30 – 4:30 pm)Final Examination
International College of Manitoba PHY100 Basic PhysicsExamination Time: 3 h
Examiner: Dr. J. B. Bland
K = Kcm +Krot =1
2mv2
cm +1
2Iω2
∆K = ∆Kcm + ∆rot
∑τextθ =
dLθdt
∑τextθ = lim
∆t→ 0
∆Lθ∆t
∆Lθ = Jθ
Jθ =(∑
τextθ
)∆t
∑τextθ =
dLθdt
= 0 =⇒ ∆Lθ = 0
∣∣∣ ~A× ~B∣∣∣ = AB sinφ
~τ = ~r × ~F
~L = ~r × ~p
4
Formula SheetsApril 13, 2016 (1:30 – 4:30 pm)Final Examination
International College of Manitoba PHY100 Basic PhysicsExamination Time: 3 h
Examiner: Dr. J. B. Bland
5
Formula SheetsApril 13, 2016 (1:30 – 4:30 pm)Final Examination
International College of Manitoba PHY100 Basic PhysicsExamination Time: 3 h
