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GH 1. Three numbers are such that the first number is 30% of third number and second number is 40% of the third number. First number is what percent of the second number? a) 133.33% b) 25% c) 33.33% d) 75% Sol: Let the third number be x. Then, 3 First number = 30% of x = x 10 4 and second number = 40% of x = x 10 First number ∴Percentage value = × 100 Second number 3 x 10 3 = × 100 = × 100 = 75%. 4 4 x 10 Ans: d 2. What is the percentage increase in the area of a rectangle if its length is increased by 20%? 2 a) 44% b) 40% c) 20% d) 16 % 3 Sol: Area of rectangle = L × B New length = 1.2 L; New area = 1.2 L × B Increase in area = 20%. Ans: c 3. After spending 20% on clothes, 10% on books, 9% on purchasing gift for girl friend and 7% on others, Chandra has a balance of Rs. 2,700. How much money was there with him initially? a) Rs.5,000 b) Rs.5,400 c) Rs.2,500 d) Rs.2,700 Sol: Let the initial money that Chandra had be x. Balance left with Chandra = x - 20% of x - 10% of x - 9% of x - 7% of x = 2,700 ⇒ 0.54 x = 2700; ⇒ x = Rs. 5,000. Ans: a 4. In an election contested by two, the loser loses by a margin of 20% of the total votes polled, which is equivalent to 20,000 votes. If only 50% of the total eligible people cast their votes, then how many total people were eligible for casting their votes? a) 1,00,000 b) 50,000 c) 4,00,000 d) 2,00,000 Sol: 20% of total votes = 20,000 votes ⇒ Total votes = 2,00,000. Ans: d 5. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets? 6 5 a) 50% b) 54 % c) 45 % d) 48% 11 11 Sol: Runs by boundaries and sixes = (3 × 4) + (8 × 6) = 60 Total number of runs scored = 110 ∴ Runs scored by running between the wickets = 110 - 60 = 50 Percentage of runs scored by running 50 5 between the wickets × 100 = 45 %. 110 11 Ans: c 6. If the numerator of a fraction be increased by 15% and its denominator be diminished by 15 8%, then the new value of the fraction is . 16 Find the original fraction. 4 10 6 3 a) b) c) d) 5 13 7 4 x Sol: Let the fraction be . y x + 15% of x 15 Then, = y - 8% of y 16 1.15x 15 x 15 0.92 3 ⇒ = ⇒ = × = . 0.92 16 y 16 1.15 4 Ans: d 7. In an examination consisting of 4 subjects, the marks obtained by Shyam in 3 of them are 90%, 95% and 95% respectively. Each subject is of equal marks. Under the given circumstances his average percentage marks for the examination cannot be a) 94% b) 90% c) 93% d) 96% Sol: Let 100 be the maximum marks for each subject. Then, from option (d), 90 + 95 + 95 + x = 96 ⇒ x = 104 4 which is notpossible. Hence, his average % marks cannot be 96%. Ans: d 8. If X = 37.5% of 20% of 48 and Y = 14.28% of 27.27% of 77, then a) X >Y b) X = Y c) X < Y d) X - Y = 1.4 Sol: X = 37.5% of 20% of 48 3 1 = × × 48 = 3.6 8 5 Y = 14.28% of 27.27% of 77 1 3 = × × 77 = 3 ∴ X > Y. Ans: a 7 11 9. A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12 marks more than the passing marks. Find the maximum marks. a) 50 b) 100 c) 150 d) None Sol: Let maximum marks be x. 20 42 Then, x + 10 = x - 12 100 100 ⇒ x = 100. Ans: b 10. In a town of population 1,20,000, 55% are males and rest are females. If 48% of males and 60% of females can vote, then what is the total number of voters in the town? a) 64,320 b) 64,080 c) 70,000 d) None of these Sol: Male population = 1,20,000 × 0.55 = 66,000 ∴ Female population = 1,20,000 - 66,000 = 54,000. Number of male voters = 66,000 × 0.48 = 31,680 Number of female voters = 54,000 × 0.60 = 32,400 ∴ Total number of voters = 32,400 + 31,680 = 64,080. Ans: b 11. In an election, there were three candidates. Out of total 1200 cast votes, Ram received 30%, Balu received 720 votes and Kapil received the rest of the votes. Find out per- cent of votes which the winner got in com- parison to his closest rival? a) 100% b) 200% c) 180% d) 90% Sol: Total votes = 1200 Ram received = 0.30 × 1200 = 360 Balu received = 720 Kapil received = 1200 - (360 + 720) = 120 Percentages of votes which the winner got in comparison to his closest rival is given by 720 = × 100 = 200%. Ans: b 360 12. The incomes of X, Y and Z are in the ratio 2 : 3 : 5 respectively. If the income of Y is Rs.9,000, then by what percent is income of Z more than that of X? a) 50% b) 60% c) 150% d) 25% Sol: Let X = 2x, Y = 3x and Z = 5x. Then, 3x = 9000 ⇒ x = Rs.3,000 ∴ X = Rs.6,000 and Z = Rs.15,000 9000 ∴ Percentage value = × 100 = 150%. 6000 Ans: c 13. The income of a property dealer remains unchanged though the rate of commission is increased from 8% to 10%. The percent- age change in the value of the business is a) 2% b) 20% c) 28% d) 15% Sol: Take initial value of business = Rs.100 So, commission of dealer = 8% of 100 = Rs.8 For next case also, commission for dealer = Rs.8 Take final value of business = a a × 10% = 8 ⇒ a = Rs.80 Percentage change in value of business 20 = × 100 = 20%. Ans: b 100 14. The value of a machine depreciates at the rate of 10% per annum. If its present value is Rs.1,62,000, then what was the value of the machine 2 years ago? a) Rs.1,00,000 b) Rs.2,00,000 c) Rs.2,50,000 d) Rs.1,80,000 Sol: Let the value of the machine two years ago be x. Then, value of machine after one year = x - 10% of x = 0.9x Further value of machine after two years, i.e., present value = 0.9x - 10% of 0.9x = 0.81x ∴ Present value = 0.81x = 1,62,000 ⇒ x = Rs.2,00,000. Ans: b 15. The radius of a sphere is 14 cm. The cost of painting the surface of sphere is Rs.25 per square cm. If the radius of sphere is increased by 10%, then the cost of painting is increased by 20%. What is the percent- age increase in the total cost of painting per square cm? a) 54.27% b) 20.3% c) 2.58% d) 45.2% Sol: Total cost of painting = Rate × Surface area of sphere As the radius increases by 10%. Surface area will change by 21% a + b + (a × b) [ using formula ] 100 Total change in cost of painting 20 × 21 = 21 + 20 + = 45.2%. 100 Ans: d 16. A student multiplies a number by 5 instead of dividing it by 5. What is the percentage change in the result due to this mistake? a) 2500% b) 98% c) 100% d) 2400% Sol: Let the number be x. x Correct answer = .; Wrong answer = 5x 5 x ( 5x - ) 5 Percentage error = × 100 = 2400%. x 5 Ans: d 17. A candidate who gets 30% of the total marks fails by 14 marks but another candi- date who gets 45% of the total marks gets 16 marks more than the passing marks. Find the passing marks. a) 200 b) 74 c) 60 d) 84 Sol: Let maximum marks be x. 30 45 x + 14 = x - 16 ⇒ x = 200 100 100 30 Hence, passing marks = × 200 + 14 = 74 100 Ans: b 18. Sandeep saves 30% of his salary and spends remaining. Out of his total savings, he invests 40% in LIC policy, 35% in HDFC and the remaining on other. If the difference between the amount invested in LIC and others is Rs.135. What is his salary? a) Rs.3,000 b) Rs.2,000 c) Rs.2,800 d) Rs.1,500 Sol: Let x be the salary of Sandeep. Then, savings = 30% of x Expenses = 70% of x LIC = 40% of 30% of x Others = 25% of 30% of x Difference = 40% of 30% of x - 25% of 30% of x ⇒ 135 = 15% of 30% of x ⇒ x = Rs.3,000. Ans: a 19. Number of students who passed in a class is 20% greater than those who failed. Find by what percent, failure are lesser than those who passed? a) 54.27% b) 20.3% c) 2.58% d) 16.66% Sol: Let number of students failed = 100 Number of students who passed = 120 Percentages by which number of students failed is less than who have passed is given by 100 = ( 1 - ) × 100 = 16.66%. 120 Ans: d Percentage SSC Exams Special Quantitative Aptitude Number of voters in the town are... These model questions were prepared by Subject experts of Career Launcher, Hyderabad ÎCî¦ô¢Ù áì÷J 24, 2021 n e-mail: [email protected] 17 1. Ú¨ÙC-î¦-æ¨ö˺ ú£·ôjì î¦Ú¥uõª ÔN? i. N-å-Nª-ûÂõª ÍêŸuÙêŸ Î÷-øŒu-ÚÛ-i-ìN. ÏN @÷±õ šíô¢ª-Þœª-ë]õ, Eô¢y--éìª ví£òÅ°- NêŸÙ ඛú ÚÛô¢(ì ú£î¶ªt-üŒ-û¦õª.- ii. N-å-Nªû Íû¶ í£ë¯Eo îµ³ë]-åÞ¥ Ñí£- óµ«-TÙ-#ì ø‹ú£Y-êŸh íÆ£ÙÚÂ.- iii. N-å-Nª-ûÂõ ö˺ð§õª þ§ëů-ô¢-éÙÞ¥ Ú•Eo î¦uëÅ]ª-õÚÛª Ú¥ô¢é÷ª÷±ê¦ô³.- iv. 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C iv.- E 1) i, ii, iii 2) ii, iii, iv 3) i, iii, iv 4) i, ii, iii, iv N-å-Nª-ûÂõª n- õ÷-é°õª áì-ô¢öËÀ šújûÂq n ñóŸ«õ@ ÎôÂÎôÂH, ÏêŸô¢ ð¼æ©¨ í£K¤Ûõ ví£ê¶uÚÛÙ ô¢àŸô³êŸ Ú•ô¦xÙ þ§ô³î¡µÙÚÛç˶ùà Íú‡šúdÙæÀ vð»šíÆú£ô ú£-÷«-ëů-û¦õª 1-4 2-3 3-1 4-2 5-3 6-3 7-4 8-4 9-2 10-2 11-4 12-1 13-1 14-1 15-3 16-1 17-3 18-3 19-2 20-4 21-3 22-4 23-2 24-3 25-3 26-1 27-2 28-1 29-2 30-3 31-4 32-1 33-2 34-2 35-4 36-4 37-2 38-1 39-2 40-4 34.- Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛ ÚÛé-â°-ö°ö˺x ›íô¢ª-ÚÛª-ð¼-÷è[Ù ÷õx ú£ÙòÅ¡-NÙචú‡–A? 1) šïj°ð¼ Nå-Nª-ûÁ-ú‡úà 2) šïj°í£ô Nå-Nª-ûÁ-ú‡úà 3) šïj°í£ô óŸ«Ú¨dîË Íi-ö˶-ù£û 4) šïj°í£--è…-óŸªîª 35.- Ú¨ÙC-î¦-æ¨ö˺ ú£·ôjì î¦Ú¥uõª ÔN? i) Nå-Nª-ûÂõª øŒÚ¨hE ÑêŸpAh à¶ú£«h ë¶ï£° vë]÷u-ô¦-P šíÙð»Ù-ë]-è¯-EÚ¨ ú£ï£°-ÚÛ-J-þ§hô³.- ii) õ÷-é°õª ·Úö˺-J-íƇÚ Nõª-÷ìª ÚÛLT ÑÙè˶ ÚÛô¢(ì ú£î¶ªt-üŒ-û¦õª iii) Nå-Nª-ûÂõª ÍCÅ-ÚÛÙÞ¥ Bú£ª-ÚÛª-ìo-í£±è[ª ÍN øŒK-ô¢Ùö˺ Ú•÷±y ô¢«í£Ùö˺ Eõy ÑÙæ°ô³.- 1) i, ii 2) ii, iii 3) i, ii, iii 4) iii ÷«vêŸî¶ª 36. - Ú¨ÙC-î¦-æ¨ö˺ þ¼è…óŸªÙ NëÅ]ªõª ÔNªæ¨? i) ÚÛÙè[ô¢ ú£ÙÚÁàŸÙ ii) øŒK-ô¢Ùö˺ sÓõ-vÚÁd-ö˵jæÀ ) õ÷é ú£÷ª-ê½-õuêŸ iii) ô¢ÚÛh-íˆ-è[ì EóŸªÙ-vêŸé 1) i, ii 2) ii, iii 3) i, iii 4) i, ii, iii 37.- ›úyà¦aÄ vð§A-í£-C-ÚÛõª svíƈô¦-è…-ÚÛ-öËÀqzìª êŸT_ÙචÓûÂâ˵j-îª-õìª v›í¸ô-í‡Ùචú£«¤Ût ÷´õÚÛÙ ÔC? 1) Uo-ù‡óŸªÙ 2) ÷«ÙÞœ-Fúà 3) >ÙÚ 4) ÷«L-G“ìÙ 38. - Ú¨ÙC-î¦-æ¨ö˺ ú£·ôjì î¦Ú¥uõª ÔN? i) ðƧú£pÄ-ô¢úÃ, Ú¥L{-óŸªÙêÁ ÚÛLú‡ Ó÷³-ÚÛõª, ë]Ùê¦õ ë]”èÅ[-ê¦y-EÚ¨ Ú¥ô¢-é-÷ª-÷±-꟪ÙC.- ii) ðƧú£pÄ-ô¢úÃ, Lí‡-èÂ-õêÁ ÚÛLú‡ ðƧþ¼pÄ-L-í‡-èÂ- õìª Ôô¦påª à¶ú‡ ÚÛé-êŸyàŸÙ ú£÷ª-vÞœ- êŸÚÛª Ú¥ô¢-é-÷ª-÷±-꟪ÙC.- iii) ðƧþ§pÄ-J-ö˶-ù£û àŸô¢u ë¯yô¦ ÓûÂâ˵j-îªõ àŸô¢u-Q-õ-êŸìª ðƧú£pÄ-ô¢úà ví£òÅ°-NêŸÙ à¶ú£ªhÙC.- 1) i, ii, iii 2) i, ii 3) ii, iii 4) i, iii 39. - Ú¨ÙC-î¦-æ¨ö˺ Ô Nå-Nªû ö˺í£Ù ÷õx ÚÛÙè[-ô¦õ ñõ--ìêŸ, ÷ÙëÅ]uêŸyÙ, Þœô¢(Ä- vþ§÷Ù ÚÛõª-Þœªê¦ô³? 1) Nå-Nªû K 2) Nå-Nªû E 3) Nå-Nªû B 4) Nå-Nªû C 40. - ú‡våúà íÆ£ö°õª, v믤Û, â°÷ª, ò˹ð§pô³ ö°Ùæ¨ î¦æ¨ö˺ ÍCÅ-ÚÛÙÞ¥ õGÅÙචNå- Nªû ÔC? 1) ·ôæ¨-û¦öËÀ 2) ëÇ]óŸ«-Nªû 3) ·ôjò˺-ðƧxNû 4) Îþ§\-J(Ú óŸ«ú‡è íÆ£ÙÚ 1. If base of a triangle increases by 14.28%, then what should be change in height if the area remains constant? a) - 5.5% b) - 7.14% c) - 9.09% d) - 12.5% 2. In an election there were only two candi- dates A and B, B got 50% of the votes that A got. Had A got 200 votes less, there would have been a tie. How many people cast their votes in all? (All votes were valid.) a) 800 b) 1000 c) 1200 d) 1600 Key: 1- d 2-c Try These Questions Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A? Nå-Nª-ûÂõª ú£JÞ¥ @ô¢gÙ Ú¥ÚÛð¼ê¶ øŒKô¢Ùö˺ ú£ÙòÅ¡NÙචú‡–A?
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