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Soalan 1 (a)

Type of fruit juices Volume of fruit juicesrequired to decolorize1 ml 0.1% DCPIPsolution (ml)

Lime 1.2

Pineapple

2.2

Orange 3.6

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P1= MV (type of fruit juices)P2= RV ( volume of fruit juices required to

decolorized 1 ml 0.1% DCPIP solution.

1. When the type of fruit juice is lime,the volume of fruit juices required todecolorized 1 ml 0.1% DCPIP solution is

1.2 ml.2. When the type of fruit juice is orange,

the volume of fruit juices required to

decolorized 1 ml 0.1% DCPIP solution is 3.6ml.

Soalan 2 (b)(i) Able to state two different

observation

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1. The volume of DCPIP to decolorised lime

juice is less because the concentration ofvitamin C in lime is high.

2. The volume of DCPIP to decolorised

orange juice is higher because Theconcentration of vitamin C in orange islow.

Soalan 2 (b)(i) Able to state two

inferences

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Soalan 1 (c)

Variable Method to handle thevariable

Manipulated variable

1) Type of fruit juices 1) Use differenttype of fruitjuices

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Responding

variable

1) Volume of fruit

juices required to

decolorized 1 ml

0.1% DCPIP

solution//2) Concentration

of vitamin C

1) measure and recordvolume of fruit

juices required to decolorized 1 ml

0.1% DCPIP solution using syringe

Calculate and recordtheconcentration of vitamin Cby using

formula :

Con. Vit C

= Volume of 1.0% ascorbic acid

Volume of fruit juices required to

decolorized 1 ml 0.1% DCPIP Solution

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Constantvariable

Volume /concentrationof DCPIPsolution

1. Fixor Use the samevolume/concentration of DCPIPsolution at 1 ml/0.1 %

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Able to draw the graph correctly

1. Axes = uniform scale on both horizontaland verticle

2. Points= All point plotted correctly

3. Curve= Able to joint all the points to formsmooth graph

P= X axis = 2cm : 0.1M Y axis= 2 cm : 2%

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@

1. Potato strip become turgid, when

immersed in low cocentration ofsucrose

solution

2. Potato strip become flaccid,when

immersed in high cocentration of

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1 (c) i- observation

1. In 0.1M sucrose solution ,

the final lengthof potato

strip is 42mm.

2. In 0.5M sucrose solution ,the final lengthof potato

strip is 34mm.

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1(c) ii-Inference

1.In o.1M the solution is hypotonic tocell sap of potato strip and water diffuseinto potato strip through osmosis/causecondition of potato strip turgid

2.In o.5M the solution is hypertonic tocell sap of potato strip and water diffuseout potato strip through osmosis/causecondition of potato strip flaccid

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Constant variable

1)Time immersed

2)Volume of sucrosesolution

3)SurroundingTemperature

4) Initial length of potato

1) Fixtime, 30min

2)Use the same volume ofsucrose solution,5ml

3)Fixthe temperature of

water bath,37

C4)Use samelength,38mm

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Soalan 1(d)ii

Variable Apparatus

Material

Manipulated

Test tube Sucrosesolution

Responding Ruler Potato

controlled Cork borer Distilled

water

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P1: manipulated variable (cocentration of sucrosesolution)

P2: responding variable ( percentage change in

length/ thefinal length of potato strip)

P3: relationship

The concentration of sucrose solution is

isotonic to concentration of the cell sap if the

solution does not change any percentage

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Soalan 1 (b)i

T=table D= data P= %

Concentrat

ion of

sucrosesolution

(M)

initial length

of potato

strip(mm)

final length of

potato

strip(mm)

Percentage change in

length(%)

0.1 38 42 (4/38)x100%=110.2 38 40 (2/38)x100%=5

0.3 38 39 (1/38)x100%=3

0.4 38 37 (-1/38)x100%=-3

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P1= isotonic solution

P2=Percentage change in length

P3=value from graph

The concentration of the cell sap isisotonic to the sucrose solutionwhere there is no percentagechange in length of potato strip.Hence, the value can be read from

the graph, at the point where the-

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P1= correct prediction

The length of potato strip/decreasebelow ____mm

P2=effect

The percentage change in length/

below -___

P3= Reason

concentration of sucrose solution is

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P1= time

P2= percentage change in length

As the time increase the

percentage change inlength